Answer:
0.6
Step-by-step explanation:
0.551567
You look at the hundredth value to see if you can find it up to the tenth.
If it's at least between 5-9 then round anything below between1-5 you can not found.
Answer:
0.6
Step-by-step explanation:
in a class of 18 students, 5 have a cat and 9 have a dog. there are 6 students who do not have a cat or a dog. what is the probability that a student chosen randomly from the class does not have a cat?
The probability that the randomly selected student does not have a cat is 13/18.
What is probability?The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true.
An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.
So, we know that is a total of 18 students.
5 have cats
9 have dogs
6 do not have a cat and a dog
Probability formula: P(E) = Favourable events/Total events
The probability that the student does not have a cat:
P(E) = Favourable events/Total events
P(E) = 18-5/18
P(E) = 13/18
Therefore, the probability that the randomly selected student does not have a cat is 13/18.
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Which expression is equivalent to (10+7r-r2)+(-6r2-18+5r)
Answer:
8−72+12−8
Step-by-step explanation:
a controlled experiment has one or more test variables (also called independent, or manipulated, variables) and one or more outcomes (also called dependent, or responding, variables). identify the test and responding variables in part 1 of the investigation.
The test variable in part 1 of the investigation is the type of fertilizer used, while the responding variable is the growth rate of the plants.
In part 1 of the investigation, the experiment aims to study the effect of different fertilizers on plant growth. The test variable, or the independent variable, is the type of fertilizer being used. The researcher would manipulate this variable by selecting and applying different types of fertilizers to the plants. The responding variable, or the dependent variable, is the growth rate of the plants.
This variable is expected to change in response to the manipulation of the test variable. The researcher would measure and observe the growth rate of the plants in order to determine the impact of the different fertilizers on their development.
By identifying and controlling the test and responding variables, the experiment allows for a systematic analysis of the relationship between the fertilizer type and plant growth, providing valuable insights for agricultural practices or gardening.
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a + 4 = 11 Cant figure this one out
Answer:
a = 7
Step-by-step explanation:
a+4 = 11
Subtract 4 from each side
a+4-4 = 11-4
a = 7
Use the function below (whose parameters qualify it as a STC function) to answer the questions.
"STC "=" 6 "+"9 Q - 3" "Q" ^2 +" (1/3)" "Q" ^3
a) Total fixed cost is $_________
b) Obtain the AFC function from (a) and write it here __________________
c) Obtain the AVC function contained in the STC function and write the AVC function here _________________________
d) Write here the MC function __________________________
e) Find the value which AFC approaches as Q gets very large. Also write a sentence or two explaining what this implies for fixed costs per unit (AFC) as production quantities get ever larger.
f) Find the value of Q at which AVC is a minimum.
g) Is productive efficiency at the value in (f) greatest or least?
h) Demonstrate that the value of SMC equals the value of AVC at the value of Q where AVC is a minimum. Hint: The level of Q you found in (f) is where AVC is a minimum. If you plug this level of Q into AVC (see c) and also into MC (see d) the two outcomes should be the same if SMC crosses AVC at this level of Q.
i) Why does the derivative of Short Run Total Cost (STC) equal the derivative of Total Variable Cost (TVC)? Stated another way, why does dSTC/dQ = dTVC/dQ? Explain in a couple of sentences.
j. Find the value of Q where increasing returns ceases and diminishing returns begins. Hint: Diminishing returns begins at the level of Q where MC is a minimum
Total fixed cost is $6. The value of AFC is $6 / Q. Productive efficiency is greatest at Q = 4.5. Diminishing returns begin when Q = 3. The total fixed cost (TFC) does not change because it is fixed.
a) Total fixed cost is $6
b) We can obtain the average fixed cost function (AFC) from the total fixed cost (TFC) by dividing it by output (Q) as follows: AFC = TFC / Q. So, the value of AFC is $6 / Q.
c) The AVC function is calculated by dividing total variable cost (TVC) by output (Q).
STC = TFC + TVC6 + 9Q - 3Q2 + (1/3)Q3TVC = 9Q - 3Q2 + (1/3)Q3AVC = TVC / QAVC = (9Q - 3Q2 + (1/3)Q3) / QAVC = 9 - 3Q + (1/3)Q2
d) The MC function is derived by taking the first derivative of the STC function with respect to output (Q). The derivative of the STC function is: MC = dSTC / dQMC = 9 - 6Q + Q2
e) As Q approaches infinity, the denominator of AFC becomes larger and larger. So, AFC approaches zero as Q gets very large. This implies that fixed costs per unit decrease as production quantities get larger.
f) We can find the value of Q at which AVC is a minimum by taking the first derivative of the AVC function and setting it equal to zero. The first derivative of AVC is: AVC = 9 - 3Q + (1/3)Q2
dAVC / dQ = -3 + (2/3)Q= 0
Q = 4.5
g) Productive efficiency is greatest when AVC is at its minimum. Therefore, productive efficiency is greatest at Q = 4.5.
h) We can demonstrate that the value of SMC equals the value of AVC at the value of Q where AVC is a minimum by plugging Q = 4.5 into both the AVC and MC functions. AVC = 9 - 3(4.5) + (1/3)(4.5)2AVC = 7.125MC = 9 - 6(4.5) + 4.52MC = 7.125
Since SMC = MC, we can conclude that SMC equals AVC at the value of Q where AVC is a minimum.
i) In the short run, the total fixed cost (TFC) does not change because it is fixed. Therefore, the derivative of the STC function with respect to output (Q) is equal to the derivative of the TVC function with respect to output (Q). This means that dSTC / dQ = dTVC / dQ.
j) Increasing returns to scale cease when the marginal cost (MC) is equal to average total cost (ATC). Diminishing returns to scale begins when MC exceeds ATC. ATC is calculated by dividing the total cost (TC) by output (Q). TC is calculated by adding total fixed cost (TFC) and total variable cost (TVC).
ATC = TC / QATC = (6 + 9Q - 3Q2 + (1/3)Q3) / Q
Now, we can find the level of Q where increasing returns to scale cease by calculating the first derivative of ATC and setting it equal to zero.
ATC = (6 + 9Q - 3Q2 + (1/3)Q3) / QdATC / dQ = (6 - 6Q + Q2) / Q2= 0
Q = 3
Now, we can calculate the marginal cost function and find the level of Q where diminishing returns begins. We know that diminishing returns begin where the marginal cost is at its minimum.
MC = 9 - 6Q + Q2MC = 9 - 6(3) + 32MC = 3
So, diminishing returns begin when Q = 3.
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how many minutes will it take for a plane altitude to change by -5,400 meters
Answer:
I believe it will be 5 minutes for it to reach that.
Please help‼️ domain and range‼️
The domain and the range of the function are (-∝, ∝) and (0, ∝), respectively
Calculating the domain and range of the graph?From the question, we have the following parameters that can be used in our computation:
The graph
The above graph is an exponential function
The rule of an function is that
The domain is the set of all real values
In this case, the domain is (-∝, ∝)
For the range, we have
Range = (0, ∝)
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What is the quotient of 513 divided by 19
Answer:
The number 513 is called the numerator or dividend, and the number 19 is called the denominator or divisor.
The quotient of 513 and 19, the ratio of 513 and 19, as well as the fraction of 513 and 19 all mean (almost) the same: 513 divided by 19, often written as 513/19.
Step-by-step explanation:
Answer:
27
Step-by-step explanation:
First you set up the equation of your quotient. Then divide it by 19, like so 513÷19 lastly you solve the answer that the math you calculated.
find the reciprocal of 3
Given: m∠B = 46°; m∠C = 45°; m∠R = 46°; m∠T = 89° Prove: △ABC ~ △TRS Triangles A B C and T R S are shown. Angles A B C and T R S are 46 degrees. Angle B C A is 45 degrees. Angle R T S is 89 degrees. Melissa believes that the AA similarity theorem can prove that the triangles are similar. Which fact would be necessary in the proof? △ABC is an acute triangle. △TRS is larger than △ABC. The sum of the measures of the interior angles of a triangle is 180°. The sum of the side lengths of two sides of a triangle is greater than the third side length.
Answer:
C) The sum of the measures of the interior angles of a triangle is 180°.
Step-by-step explanation:
I got it correct on edge
The fact to prove ΔABC and ΔTRS are similar is The sum of the measures of the interior angles of a triangle is 180, option third is correct.
What is the similarity law for triangles?It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have two triangles shown in the picture.
Angle B = 46 degrees
Angle C = 45 degrees
Angle A = 180 - 45 - 46 = 89 degrees
Angle R = 46 degrees
Angle S = 180 - 46 - 89 = 45 degrees
Angle T = 89 degrees
Thus, the fact to prove ΔABC and ΔTRS are similar is The sum of the measures of the interior angles of a triangle is 180, option third is correct.
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The first five terms of an arithmetic sequence are 4, 10, 16, 22, and 28. Which function f(x) could be used to describe the xth term of the sequence?(1 point)
f(x)=−6x−2
f(x)=6x+4
f(x)=6x−2
f(x)=−6x+4
Answer:
The answer is f(x)=6x-2
Step-by-step explanation:
I took the quiz so I know that the answer is right.
What is the area of a regular pentagon with a side of 15 cm?
Answer:
hello.
• Area: 387.11cm²
•A (side)= 15 cm.
hope this helps.
PLEASE HELP MEEEEEEE
Answer:
3/4 and in decimal it's 0.75
Step-by-step explanation:
The measure of an angle is 64.9°. What is the measure of its supplementary angle?
When designing questionnaire Overcoming measurement errors can be reduced by
all the following except
O a. The use of a linear rating scale with only the extreme categories labelled.
O b. Positioning difficult and important questions at the beginning and end of the questionnaire.
O c. The Use of many answer scale categories.
O d. Positioning easy and
When designing a questionnaire, overcoming measurement errors can be reduced by various strategies. However, one of the options listed does not contribute to reducing measurement errors. The option that does not help in reducing measurement errors is: c. The use of many answer scale categories.
Measurement errors in questionnaires can arise due to various factors, such as respondent bias, response inconsistency, and ambiguous or confusing question wording. To minimize these errors, researchers employ different techniques. Let's examine the options:
a. The use of a linear rating scale with only the extreme categories labeled: This technique helps by simplifying the rating scale and providing clear reference points, which can enhance response accuracy.
b. Positioning difficult and important questions at the beginning and end of the questionnaire: This strategy is known as primacy and recency effects. Placing challenging and significant questions at the start and end can improve response quality as respondents are more focused and attentive during those sections.
c. The use of many answer scale categories: This option, contrary to the others, does not help in reducing measurement errors. Having numerous answer scale categories can increase respondent confusion, lead to midpoint bias, and result in inconsistent or inaccurate responses.
d. Positioning easy and straightforward questions in the questionnaire: This technique aims to create a smooth flow and encourage respondents to answer confidently. By placing easier questions strategically, respondents may feel more comfortable and provide accurate responses.
In summary, all the provided options contribute to reducing measurement errors except for option c, the use of many answer scale categories.
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Frank is 6 years older than his brother Joe. The sum of their ages is 38. How old is Joe AND Frank?
Answer:
Joe is 16, Frank is 22
Step-by-step explanation:
To find the solution to this problem, we first divide 38 by two.
38 / 2 = 19.
Then, we subtract 6 from 19 and have 19 and 13. Obviously, 19 is 6 more than 13 (19 - 13 = 6). Now, we need to make sure our number on the left is always 6 more than the number on the right. 19 + 3 = 22, 13 + 3 = 16. Since Frank is older than Joe by 6 years, we get 22 and 16 as their ages.
number 7 please
7. Determine the approximate location of a GPS receiver if it has been determined that: (4 mark) - Station 1 (at 74, 41) is \( 44 \mathrm{~km} \) away. - Station \( 2( \) at 0,43\( ) \) is \( 38 \math
If Station 1 (at 74, 41) is 44 km away and Station 2( at 0,43 ) is 38 km away. The required approximate location of the GPS receiver is (42, 10).
The location of the GPS receiver can be determined with the help of trilateration. Trilateration is a process of determining absolute or relative locations of points by measurement of distances, using the geometry of circles, spheres, or triangles. If three stations (or more) are in known locations, with a known distance from the point of interest, we can determine the position of the GPS receiver with the help of trilateration.
It can be determined by the following method:
1: Plot the given stations on a coordinate plane. Stations are:
Station 1: (74, 41)
Station 2: (0, 43)
2: Calculate the distance of the GPS receiver from each station using the distance formula.
Distance Formula: The distance formula is used to find the distance between two points in the coordinate plane. The distance between points (x1,y1) and (x2,y2) is given by
d = √[(x2 - x1)² + (y2 - y1)²]
Station 1: Distance from station 1 = 44 kmSo, d1 = 44 km
Station 2: Distance from station 2 = 38 kmSo, d2 = 38 km
3: Plot the given distances as the circle on the coordinate plane.
Circle 1: Centred at (74, 41) with a radius of 44 km.
Circle 2: Centred at (0, 43) with a radius of 38 km.
4: The intersection of two circles. Circle 1 and Circle 2 intersect at point P (approx) (42, 10). So, the approximate location of the GPS receiver is (42, 10).
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Dev’ car currently ha 18 gallon of ga in the tank. He ue about 0. 04 gallon for every mile he drive. Dev want to go on a car trip over the weekend and have at leat 2 gallon of ga left in hi tank to get to work on Monday. What i the olution of the inequality that determine how far Dev can travel over the weekend? (Example 2) Let x repreent the number of mile Dev travel
The solution of the inequality that determines how far Dev can travel over the weekend is -
x ≤ 400 miles.
What is a expression? What is a mathematical equation? What is Equation Modelling?A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
We have Dave who is planning a car trip for weekend.
Assume that [x] represents the number of miles Dev can travel.
We can write the inequality as -
18 - 0.04x ≤ 2
0.04x ≤ 16
x ≤ 400 miles
Therefore, the solution of the inequality that determines how far Dev can travel over the weekend is -
x ≤ 400 miles.
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whats the slope of (8,18) and (16,24)
Answer:
6/8
Step-by-step explanation:
I answered this math question on edge and 100%.
q. jenny can walk 4 miles in (m 3) minutes. at that pace, how many miles can she walk in 15 minutes?
If she moves at a speed of 1.33 miles per minute while walking 4 miles in 3 minutes, she can cover 20 miles in 15 minutes.
What is division?A number is divided in division, which is a straightforward procedure. The simplest way to conceptualize it is as a set of objects being distributed among a set of individuals, as in the example given above. In mathematics, division is the process of dividing a number into equal parts and calculating the maximum number of equal parts that may be formed. For instance, dividing 15 by 3 results in the division of 15 into 3 groups of 5 each.
Here,
In 3 minutes, she walk 4 miles,
speed=distance/time
=4/3 miles/minute
distance=speed*time
=4/3*15
=20 miles
She can walk 20 miles in 15 minutes if she walks 4 miles in 3 minutes with a speed of 1.33 miles/minute.
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Can u guys PLEASE answer this question ASAP.
THIS IS EXTREMELY URGENT
Answer:its upside down sir
Step-by-step explanation:
what is meant by derivative
Answer:
its basically just rate of change or slope. with derivatoves you can find the slope of a tangent line which is a line that touches the curve at a point.
A confectionery company mixes three types of toffees to form one kilogram " toffee packs. the pack is sold at rs. 17. the three types of toffees cost rs.20, rs. 10, rs. 5 per kg. resp. the mixture must contain atleast 300 gms of first type. also weight of first two types must be at least be equal to weight of third type. find the optimal mix for maximum profit.answer
The maximum profit is 6 and it is obtained when we mix 0.6 kg of type A, 0 kg of type B, and 0.4 kg of type C.
The optimal mix for the maximum profit can be found as follows:
The company mixes three types of toffees, A, B, and C. Let the weights of type A, B, and C be a, b, and c kg, respectively. Let us assume that we are making 1kg of toffee pack. Therefore, the weight of type C should be 1 - (a + b) kg. Also, the mixture must contain at least 300 gms of type A i.e a >= 0.3 kg
Also, the weight of the first two types (A and B) must be at least equal to the weight of type C, i.e a + b >= c. This condition can also be written as a + b - c >= 0
Let us now calculate the total cost of making 1kg of toffee pack.
Cost = 20a + 10b + 5c
If the pack is sold at Rs. 17, then the profit per 1kg of toffee pack is by
Profit = Selling Price - Cost = 17 - (20a + 10b + 5c)
Now we have the following linear programming problem:
Maximize P = 17 - (20a + 10b + 5c)
Subject to constraints: a + b + c = 1 (since we are making 1kg of toffee pack)
a >= 0.3a + b - c >= 0a, b, c >= 0
We can use the simplex method to solve this linear programming problem. However, to save time, we can solve it graphically. The feasible region is as follows:
We can see that the corner points of the feasible region are: (0.3, 0, 0.7), (0.6, 0, 0.4), (0, 0.5, 0.5), and (0, 1, 0).
Let us calculate the profit at each of these corner points. For example, at the point (0.3, 0, 0.7), we have a = 0.3, b = 0, and c = 0.7. Therefore, the profit is
P = 17 - (20(0.3) + 10(0) + 5(0.7)) = 3.5
Similarly, we can calculate the profit at the other corner points as well. The corner point (0.3, 0, 0.7) gives a profit of 3.5
Corner point (0.6, 0, 0.4) result in a profit of 6
Corner point (0, 0.5, 0.5) results in a profit of 5
Corner point (0, 1, 0) gives a profit of 3
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Solve for the volume of this irregular polygon. Show your work
16 cm
16 cm
5 cm
6 cm
24 cm???? HELP
Answer:
36,864
Step-by-step explantion:
[Part A] Which is the ratio for sin A, written as a fraction in simplest form?
The ratio for sin A, written as a fraction in simplest form, is 3 / (2√3).
The sine function is a mathematical function that takes an angle as its input and returns the ratio of the length of the side opposite to the angle to the length of the hypotenuse in a right triangle
In a right triangle, the sine of an angle A is defined as the ratio of the length of the side opposite to angle A to the length of the hypotenuse. Therefore, we have:
sin A = Opposite / Hypotenuse
Substituting the given values, we get
sin A = CB / AB = 8√3 / 16 = √3 / 2
To simplify this fraction further, we can multiply both the numerator and denominator by √3:
sin A = (√3 / 2) × (√3 / √3) = 3 / (2√3)
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The given question is incomplete, the complete question is:
Which is the ratio for sin A, written as a fraction in simplest form?
I need help with my Alg 2 work.
Help quickly if possible.
Thanks.
Positive value of a vertically stretches the graph of f when a > 1 or shrinks the graph of f when a < 1. h translates the graph of f to the left when h < 0 or right when h > 0.
What are some examples of how exponential functions are employed in mathematics and in real life?Several real-world scenarios use exponential functions, including population increase, compound interest, radioactive decay, and the spread of diseases. For instance, an exponential function may be used to simulate the expansion of a bacterial population, with the rate of increase being proportional to the population size. Similarly, compound interest, which applies the rate of interest to the principal sum across a number of periods, can be represented by an exponential function.
Positive value of a vertically stretches the graph of f when a > 1 or shrinks the graph of f when a < 1. h translates the graph of f to the left when h < 0 or right when h > 0 and k translates the graph of f up when k > 0 and down when k < 0.
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secA+tanA-1/tanA-sec+1 = cosA/1-sinA
Subtract to find the value of 15(2/3-2/5)
Answer:
\(4\)
Step-by-step explanation:
Simplify the expression
I will give an excellent vote and a brainliest!
Answer:
Median = 15
Range = 9
25th percentile = 14
75th percentile = 17
Interquartile range = 3
Step-by-step explanation:
=>The median in a box-and-whisker plot is indicated by the vertical line that divides the box into two.
The median in the box plot above is 15
=>The range is the difference between the highest value and the lowest value. The lowest value is indicated at our left, where the whisker starts from (11), while the highest value in the data set is indicated at our far right where the other whisker ends (20).
Range = 20 - 11 = 9
=>25th percentile is same as lower quartile, which is indicated on the box plot at the begining of the rectangular box from our left = 14
=>75th percentile is same as upper quartile, which is located at the end of the rectangular box to our right = 17
=>Interquartile range = 75th percentile - 25th percentile = 17 - 14 = 3
three points t, u, and v on the number line have coordinates t, u, and v, respectively. is point t between points u and v ?
We can determine coordinates if point t is between points u and v by checking if u < t < v or v < t < u.
To determine if point t is between points u and v, we need to compare their coordinates. If u < v, then point t is between points u and v if and only if u < t < v. On the other hand, if v < u, then point t is between points u and v if and only if v < t < u.
Whether or not point t is between points u and v depends on the relationship between the coordinates of u and v. If u < v, t must fall between them, and if v < u, t must also fall between them.
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