(1 pointConsider the function f(x) = 3 - 5x on the interval (-6,4) (A) Find the average or mean slope of the function on this intervalle S(4) - [(-6) 4-(-6) (B) By the Mean Value Theorem, we know there exists a c in the open interval (-6, 4) such that l'() is equal to this mean slope. For this problem, there is only one that works. Find it

Answer:

6cm

Step-by-step explanation:

The formula for the surface area of a sphere = 4πr²

From the Question, we are given:

The surface area of a sphere = 144pi square centimeters = 144π cm²

The length of the radius of the sphere, in centimeters is calculated by:

4πr² = 144π

Divide both sides by 4π

4πr²/4π = 144π/4π

r² = 36

Square root both sides

√r² = √36

r = 6cm

Therefore, the length of the radius of the sphere, in centimeters is 6 centimeters.

Answer:

4

Step-by-step explanation:

Answer:

188.5\(cm^2\)

Step-by-step explanation:

The surface area of a cylinder can be found using the equation: \(A=2\pi rh+2\pi r2\).

When we plug in to this equation we get \(2\pi (3)(7) + 2\pi(3^2)\) which equals 188.4955 which can be rounded up to 188.5\(cm^2\)

Answer:

Step-by-step explanation:

Let \(m=x^2-5\)

We want to express the equation \((x^2-5)^2-3x^2+15=-2\) in terms of m.

Given: \((x^2-5)^2-3x^2+15=-2\)

Factorizing the third and fourth term, we obtain:

\((x^2-5)^2-3(x^2-5)=-2\)

Substituting  \(m=x^2-5\), the above equation becomes:

\(m^2-3m=-2\)

Since the options are not given, the equivalent equation is:

\(m^2-3m=-2\)

It could also be written in a rearranged form as:

\(m^2-3m+2=0\)

Answer:

I don't think this question is phrased correctly. The lesser number is the lesser number...  I think this is asking you to find each of the numbers, so I will do that.

Greater number: -19

Lesser number: -28

Step-by-step explanation:

If the greater number minus the lesser number is 9, the greater number is 9 more than the lesser number. I'll use algebra to solve this problem.

Lets set the lesser number as the variable x.

lesser number = x

Because the greater number is 9 more than the lesser number, the greater number is:

x+9

2x+9 = -47

Subtract 9 on both sides to isolate the variable.

2x + 9 - 9 = -47 - 9

2x = -56

x = -28

Because the greater number is 9 greater than the lesser number, add 9 to x to get the greater number.

-28 + 9 = -19

Answer:

5x+120

Step-by-step explanation:

first you add the 2x x and x and x that would get you 5x and then add the 20 and 10 and 80 that would get you 120

Answer:

It's an angle bisector

Step-by-step explanation:

It is between 2 congruent angles therefore bisects those angles

The growth rate of the bacterial colony after 3 hours is 32%, the population of a slowly growing bacterial colony after t hours is given by the function p(t) = 100 + 24t + 2t²

The growth rate of the colony is the rate of change of the population, which is given by the derivative of the function. The derivative of p(t) is p'(t) = 24 + 4t

The growth rate after 3 hours is p'(3) = 24 + 4 * 3 = 32. This means that the population of the colony is increasing by 32% after 3 hours.

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The quadratic equation to find the width of the rectangle by formulating the area and length value is 2w² - w - 91 = 0.

What is area?

An object's area is how much space it takes up in two dimensions. It is the measurement of the quantity of unit squares that completely cover the surface of a closed figure.

The value for the area of the rectangle is given as = 91 in²

Let the width for the rectangle be = w

Then the length of the rectangle is 1 less than twice its width, l = (2w - 1)

The formula for the area of the rectangle is -

Area = length × width

Substitute the values to get the equation for width -

91 = (2w - 1) × w

Use the arithmetic operation of multiplication -

91 = w(2w - 1)

91 = 2w² - w

Rearrange in quadratic form -

2w² - w - 91 = 0

Therefore, the equation is obtained as 2w² - w - 91 = 0.

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Therefore, company A will charge less than company B for any mileage greater than 65 miles.
To help you with your question, I need the specific prices for both companies, as well as any additional information you can provide about the charges.

To solve for the mileages at which company A will charge less than company B, we can set up the following inequality:
A < B
where A is the cost of renting from company A and B is the cost of renting from company B. We can plug in the given information to get:
x ≤ A
x > B = y + 40z
where x is the number of miles driven, y is the initial fee for company B, and z is the additional cost per mile for company B.
Now we can substitute the given values to get:
x ≤ A
x > y + 40z
For company A, the cost is a flat rate with unlimited mileage, so A is just the cost listed for one day of rental. Let's say that cost is $100.
For company B, the initial fee is $50 and the additional cost per mile is $0.25. So:
y = 50
z = 0.25
Now we can plug in these values and solve for x:
x ≤ 100
x > 50 + 40(0.25)
x > 65
Therefore, company A will charge less than company B for any mileage greater than 65 miles.
To help you with your question, I need the specific prices for both companies, as well as any additional information you can provide about the charges.

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The expression that is equivalent to the expression given as (52 • 34)3 is 5^4 • 3^12

The expression is given as:

(52 • 34)3

Rewrite properly as:

(5^2 • 3^4)^3

Expand the expression

(5^2)^2 • (3^4)^3

Evaluate the products of the exponents

(5^4) • (3^12)

Remove the brackets

5^4 • 3^12

Hence, the expression that is equivalent to the expression given as (52 • 34)3 is 5^4 • 3^12

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Answer:

its 5^6 x 3^12

There are 5 * 5 = 25 possible arrangements. Some examples include aa, bb, cc, dd, ee, ab, ac, ad, ae, ba, bb, bc, bd, be, and so on.

a. Choosing 2 objects at a time without repetition and with order counting: The ordered arrangements of 5 objects (a, b, c, d, e) taken 2 at a time without repetition and with order counting are: ab, ac, ad, ae,

ba, bc, bd, be,

ca, cb, cd, ce,

da, db, dc, de,

ea, eb, ec, ed.

b. Choosing 2 objects at a time without repetition and without order counting: The unordered arrangements of 5 objects (a, b, c, d, e) taken 2 at a time without repetition and without order counting are: ab, ac, ad, ae,

bc, bd, be,

cd, ce,

de.

c.Choosing 2 objects at a time with repetition: In this case, we can choose any of the 5 objects for the first position, and any of the 5 objects (including repetition) for the second position.

Therefore, there are 5 * 5 = 25 possible arrangements. Some examples include aa, bb, cc, dd, ee, ab, ac, ad, ae, ba, bb, bc, bd, be, and so on.

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According to the information, we can infer that the number of ounces of water, x, that Will could have put in each cup is 8 ounces.

Will initially had a cooler filled with 144 ounces of water. After using 16 ounces to fill his water bottle, there were 144 - 16 = 128 ounces of water remaining in the cooler.

Will then took out 16 plastic cups for his teammates. Since the same amount of water was put in each cup, the remaining amount of water, 128 ounces, needs to be divided equally among the cups.

Dividing 128 ounces by 16 cups gives us 8 ounces of water for each cup.

So, Will could have put 8 ounces of water in each cup.

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Answer:

20+15x

Step-by-step explanation:

because we start with 20 and every year 15 kids join we multiply 15 by x years with 20 kids so we get 20+15x

=====================================================

Explanation:

Laura starts off with a balance of $606.40

This balance is in effect for x days, where x is some positive whole number between 1 and 30.

For the remaining 30-x days, her balance is 606.40-55.25 = 551.15 dollars after making the payment of $55.25

Here's a table to keep track of everything so far

\(\begin{array}{|c|c|c|} \cline{1-3}& A & B\\ \cline{1-3}\text{Interval} & \text{Num Days} & \text{Balance}\\ \cline{1-3}\text{June 1st to June x} & x & 606.40\\ \cline{1-3}\text{June x+1 to June 30th} & 30-x & 551.15\\ \cline{1-3}\end{array}\)

where "Num Days" is shorthand for "number of days".

What we do is multiply the A and B column to form column C like this

\(\begin{array}{|c|c|c|c|} \cline{1-4}& A & B & C\\ \cline{1-4}\text{Interval} & \text{Num Days} & \text{Balance} & \text{A*B}\\ \cline{1-4}\text{June 1st to June x} & x & 606.40 & 606.40x\\ \cline{1-4}\text{June x+1 to June 30th} & 30-x & 551.15 & 551.15(30-x)\\ \cline{1-4}\end{array}\)

Add up the stuff in column C

606.40x+551.15(30-x)

Then divide by 30 to compute the average daily balance

\(\frac{606.40x+551.15(30-x)}{30}\)

That average daily balance is plugged into this formula

\(\text{F} = \frac{\text{ADB}*\text{APR}*\text{n}}{365}\)

where

We are given the following

Plug in \(\text{ADB} = \frac{606.40x+515.15(30-x)}{30}\) and solve for x

So,

\(\text{F} = \frac{\text{ADB}*\text{APR}*\text{n}}{365}\\\\5.71 = \frac{\frac{606.40x+551.15(30-x)}{30}*0.1204*30}{365}\\\\5.71 = \frac{(606.40x+551.15(30-x))*0.1204}{365}\\\\5.71*365 = (606.40x+551.15(30-x))*0.1204\\\\2,084.15 = 606.40*0.1204x+551.15*0.1204(30-x)\\\\2,084.15 = 73.01056x+66.35846(30-x)\\\\\)

\(2,084.15 = 73.01056x+1,990.7538-66.35846x\\\\2,084.15 = 6.6521x+1,990.7538\\\\2,084.15-1,990.7538 = 6.6521x\\\\93.3962 = 6.6521x\\\\6.6521x = 93.3962\\\\x = 93.3962/6.6521\\\\x = 14.0401076351829\\\\\)

That value is approximate.

When rounding to the nearest whole number, we get x = 14.

Therefore, from June 1st to June 14th, Laura has a balance of $606.40

From June 15th to June 30th, she has a balance of $551.15

--------------------------

Checking the answer:

Here's the updated table with x replaced with 14. So x+1 = 14+1 = 15

\(\begin{array}{|c|c|c|c|} \cline{1-4}& \text{A} & \text{B} & \text{C}\\ \cline{1-4}\text{Interval} & \text{Num Days} & \text{Balance} & \text{A*B}\\ \cline{1-4}\text{June 1st to June 14th} & 14 & 606.40 & 8489.60\\ \cline{1-4}\text{June 15th to June 30th} & 16 & 551.15 & 8818.40\\ \cline{1-4}\end{array}\)

Adding everything in column C gets us

8489.60+8818.40 = 17,308

Divide that over 30 days

(17,308)/30 = 576.93

Her average daily balance for the month of June is $576.93

Plug that into the formula mentioned to get the finance charge.

\(\text{F} = \frac{\text{ADB}*\text{APR}*\text{n}}{365}\\\\\text{F} = \frac{576.93*0.1204*30}{365}\\\\\text{F} = \frac{2,083.87116}{365}\\\\\text{F} = 5.7092\\\\\text{F} = 5.71\)

We get the correct finance charge of $5.71, so the answer has been confirmed.

Answer:

i got it right on test⬇️

Answer:

A scatter plot can show a positive relationship, a negative relationship, or no relationship. If the points on the scatter plot seem to form a line that slants up from left to right, there is a positive relationship or positive correlation between the variables.

Answer:

\(\dfrac{ 450 \sin ( 140 ) }{ \sin ( 28 ) }\)

= 616.127679049

"B"

Step-by-step explanation:

THIS IS MS NEISES PLEASE SEE ME AFTER CLASS

THIS IS MS NEISES I AM REALLY MS NEISES

Answer:

The slope is 0

Line is y= -4

Step-by-step explanation:

The probability that a high school student chosen at random is in 11th grade or volunteers is 0.61 or 61%. This was obtained by adding the probabilities of being in 11th grade and volunteering and subtracting the probability of being both.

To find the probability that a student chosen at random is in 11th grade or volunteers, we need to add the probabilities of the two events.

The number of students who volunteered is 306, and the total number of students is 600, so the probability of a student chosen at random volunteering is

P(volunteer) = 306/600 = 0.51

The number of students in 11th grade is 167, and the total number of students is 600, so the probability of a student chosen at random being in 11th grade is

P(11th grade) = 167/600 = 0.28

To find the probability that a student chosen at random is in 11th grade or volunteers, we add these probabilities

P(11th grade or volunteer) = P(11th grade) + P(volunteer) - P(11th grade and volunteer)

We need to subtract the probability of a student being both in 11th grade and volunteering because we have already counted them once in each of the probabilities above. From the table, we can see that the number of students who are in 11th grade and volunteered is 110, so

P(11th grade and volunteer) = 110/600 = 0.18

Substituting the values, we get

P(11th grade or volunteer) = 0.28 + 0.51 - 0.18 = 0.61

Therefore, the probability that a student chosen at random is in 11th grade or volunteers is 0.61 or 61%.

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Step-by-step explanation:

Conversion between Miles and Kilometer:

1 mile = 1.609km.

100 miles = 1.609km * 100 = 160.9km,

160.9km - 100km = 60.9km.

Hence the 2 places that are 100 miles apart is 60.9km further away than the places that are 100km apart.

The frequencies for this problem are given as follows:

The total number of people in this problem is given as follows:

13.

Out of 13 people, 3 have zero TV's, hence the frequency A is given as follows:

A = 3/13.

Out of 13 people, 6 have one TV, hence the frequency B is given as follows:

B = 6/13.

Out of 13 people, 3 have two TV's, hence the frequency C is given as follows:

C = 3/13.

Out of 13 people, 1 have three TV's, hence the frequency D is given as follows:

D = 1/13.

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Answer:

58.43%

Step-by-step explanation:

The first thing we must do is calculate the probability of when both are equal, that is, take out two cookies of the same type, since we can calculate that they are not equal by means of their complement:

The probability that they are equal is:

P (plain, plain) = (12/20) (11/19)

= 132/380

P (chocolate, chocolate) = (5/20) (4/19)

 = 20/380

P (currant, currant) = (3/20) (2/19)

= 6/380

The final probability would be the sum of these:

P (equal) = 132/380 + 20/380 + 6/380

P (equal) = 158/380

P (equal) = 0.4157

The probability that they are different is the opposite of the probability that they are equal, that is, the complement. Therefore, the probability that they are different is:

P (different) = 1 - 0.4157

P (different) = 0.5843

In other words, the probability would be 58.43%

The minutes it will take for the tank to be 3/5 full is 720 minutes.

A fraction is a non-integer that is made up of a numerator and a denominator. The numerator is the number above and the denominator is the number below. An example of a fraction is 3/5.

The first step is to determine how many gallons the tank would have when it is 3/5 full. To determine this value, multiply the volume of the tank by 3/5.

Gallons when the tank is 3/5 full = 3/5 x  48,000 = 28,800

Now, divide the speed of the water by the gallons in the tank when it is 3/5 full.

28,800 / 40 = 720 minutes

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the code is referencing a tree data structure and has an instance variable called "root" that holds the root node of the tree.

The statement "stack" itself does not provide enough context to determine its purpose or the expected output. It could be a reference to a specific method or operation involving a stack data structure, but without further information, it is not possible to determine the specific behavior or output of the code.

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Answer:

A. 6

Step-by-step explanation:

\(10x \degree + 30 \degree = 90 \degree \\(complementary \:angles) \\\\ 10x \degree = 90 \degree - 30 \degree\\ \\ 10x \degree = 60 \degree \\ \\ 10x = 60 \\ \\ x = \frac{60}{10} \\ \\ x = 6\)

Answer:

If a researcher cannot gain access to a target population, snowball sampling procedures can assist in locating subjects. In regard to sampling procedures, if a researcher wants to be able to generalize results to the total population of interest, then a purposeful sampling technique is the best approach.

Answer:

Non-probability sampling

Step-by-step explanation:

Non-probability sampling is a method of selecting units from a population using a subjective  method.

The comparison of the expressions is 7 + 3² -2  * 5 ÷ 4 - 1 * 2 > (¾+ ⅛) ÷ ⅛ - 2²

From the question, we have the following parameters that can be used in our computation:

7 + 3^2-2x5÷4-1x2 and (¾+ ⅛) ÷ ⅛ - 2^2

Express the exponents properly

This gives

7 + 3² -2  * 5 ÷ 4 - 1 * 2 and (¾+ ⅛) ÷ ⅛ - 2²

Evaluate the exponents

So, we have the following representation

7 + 9 - 2 * 5 ÷ 4 - 1 * 2 and (¾+ ⅛) ÷ ⅛ - 4

Evaluate the expressions in brackets

So, we have the following representation

7 + 9 - 2 * 5 ÷ 4 - 1 * 2 and 7/8 ÷ ⅛ - 4

Solve the products and quotients

7 + 9 - 2.5 - 2 and 7 - 4

So, we have

11.5 and 3

11.5 is greater than 3

So, we have

11.5 > 3

Rewrite as

7 + 3² -2  * 5 ÷ 4 - 1 * 2 > (¾+ ⅛) ÷ ⅛ - 2²

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Answer:

sqrt(241) or about 15.52 rounded

Step-by-step explanation:

a^2+b^2=c^2

4^2+15^2=c^2

16+225=c^2

241=c^2

sqrt(241)=c