1. Suppose we have a 16 bit virtual address space with 64 pages. A virtual address then has _____ bits for the virtual page number and _____ bits for the offset.
2. In address translation with paging, how is the offset of the virtual address modified? a) according to the page table, b) it is zeroed, c) it is not changed. True or false: Fragmentation can occur with paging if the page tables are frequently modified.
3. Suppose we have a 32 bit virtual address space with pages that are 4 KB in size. How many entries will there be in the page table? Yes or no:
4. Can permissions be assigned to different pages in a virtual address space, for example to prohibit writing to certain pages?
Answers
Here is the answer;
A virtual address then has 6 bits for the virtual page number and 10 bits for the offset.In address translation with paging, the offset of the virtual address is not changed. Option C is true. It is false that fragmentation can occur with paging if the page tables are frequently modified. We have a 32 bit virtual address space with pages that are 4 KB in size.Yes, permissions can be assigned to different pages in a virtual address space to prohibit writing to certain pages.Question 1
In a 16-bit virtual address space with 64 pages, each virtual address consists of two parts: the virtual page number and the offset. To determine the number of bits for each, we first need to find out the number of bits required to represent 64 pages.
Since \(2^{6}\) = 64, we need 6 bits for the virtual page number. The remaining bits in the 16-bit address will be used for the offset, so we have 16 - 6 = 10 bits for the offset. Therefore, a virtual address has 6 bits for the virtual page number and 10 bits for the offset.
Question 2
In address translation with paging, the offset of the virtual address is not changed. Option C is right, The virtual page number is used to look up the corresponding physical page number in the page table, and the offset remains the same.
Fragmentation is not an issue with paging, as the page size is fixed and the memory manager can easily manage the allocation of pages. So, the statement given is false.
Question 3
In a 32-bit virtual address space with 4 KB (4096 bytes) pages, we first need to find out the number of bits required to represent the offset. Since \(2^{12}\) = 4096, we need 12 bits for the offset.
The remaining bits in the 32-bit address will be used for the virtual page number, so we have 32 - 12 = 20 bits for the virtual page number. Therefore, there will be \(2^{20}\) = 1,048,576 entries in the page table.
Question 4
Yes, permissions can be assigned to different pages in a virtual address space. This allows the system to control access to certain pages, for example, to prohibit writing to specific pages for security or other purposes.
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Related Questions
An article in Computers \& Electrical Engineering, "Parallel simulation of cellular neural networks" (1996, Vol. 22, pp. 61-84) considered the speed-up of cellular neural networks (CNN) for a parallel general-purpose computing architecture based on six transputers in different areas. The data follow: Round your answers to 3 decimal places. Assume population is approximately normally distributed. (b) Construct a 99.9% two-sided confidence interval on the mean speed-up. ≤μ≤ (c) Construct a 99.9% lower confidence bound on the mean specd-up. ≤μ
Answers
(a) There is enough evidence to support that the mean speed-up is not equal to zero. (b) The 99.9% lower confidence bound on the mean speed-up is 0.911.
The given data is as follows: n = 6, x = 6.6574, s = 0.7761; df = n – 1 = 5
(a) The hypothesis test is as follows:Null hypothesis:H0: μ = 0Alternate hypothesis:H1: μ ≠ 0Since it is a two-tailed test, the level of significance is 0.001/2 = 0.0005 (99.9% two-sided confidence interval).Since n ≤ 30, the t-distribution is used for calculation.The test statistic is given by t = x - μ/ (s/√n)Here, t = 38.8181 (approx)Since the test statistic is greater than the critical value of t = 6.571 (t5, 0.0005), we reject the null hypothesis.Therefore, there is enough evidence to support that the mean speed-up is not equal to zero.
(b) Confidence interval:Here, α = 0.001/2 = 0.0005 and df = n – 1 = 5Using the t-distribution, the confidence interval is given by x ± tα/2,df (s/√n)Substituting the values, we get6.6574 ± 6.965 (0.7761/√6)≤μ≤ 6.6574 ± 5.4381≤μ≤ (1.2193, 12.0955)Therefore, the 99.9% two-sided confidence interval on the mean speed-up is (1.2193, 12.0955).(c) Confidence interval:Here, α = 0.001/2 = 0.0005 and df = n – 1 = 5Using the t-distribution, the confidence interval is given by x + tα,df (s/√n)Substituting the values, we get6.6574 + 8.032 (0.7761/√6)≤μ≤ 6.6574 + 6.2536≤μ≤ (0.911, 12.4034)Therefore, the 99.9% lower confidence bound on the mean speed-up is 0.911.
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Which of these is NOT a safety procedure for lockout/tagout?
A) Inspecting locks and tags for defects
B) Turning off the equipment at the control panel
C) Leaving the equipment on
D) Attaching a safety lock or tag on the energy-isolating device
Answers
Answer:
I would assume c
Explanation:
it just seems like it would not be a safety procedure
Lockout/Tagout would be the idea of properly shutting down a source of energy, draining any surplus energy, and applying mechanisms to that energy source that prevent it from being reactivated, and the further explanation can be defined as follows:
It also called lock & tag is a security method in use in industry and research to guarantee that critical machinery was correctly shut down. It can be restarted until the completion of conservation or recovery operations.Therefore the final answer is "Option C".
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Ill give 100 points to whoever gives me the CORRECT answer. I keep getting syntax errors when I do the "add:" part. Can someone walk me through this code?
Part A One of the biggest benefits of writing code inside functions is that we can reuse the code. We simply call it whenever we need it! Let’s take a look at a calculator program that could be rewritten in a more reusable way with functions. Notice that two floats (decimal numbers, but they can also include integers) are inputted by the user, as an operation that the user would like to do. A series of if statements are used to determine what operation the user has chosen, and then, the answer is printed inside a formatted print statement. num1 = float(input("Enter your first number: ")) num2 = float(input("Enter your second number: ")) operation = input("What operation would you like to do? Type add, subtract, multiply, or divide.") if operation == "add": print(num1, "+", num2,"=", num1 + num2) elif operation == "subtract": print(num1, "-", num2,"=", num1 - num2) elif operation == "multiply": print(num1, "*", num2,"=", num1 * num2) elif operation == "divide": print(num1, "/", num2,"=", num1 / num2) else: print("Not a valid operation.") Your job is to rewrite the program using functions. We have already looked at a function that adds two numbers. Using that as a starting point, we could call the add function from within our program in this way: if operation == “add”: result = add(num1, num2) print(num1, "+", num2,"=",result) Now it’s your turn to do the following: Type all of the original code into a new file in REPL.it. Copy the add function from the unit and paste it at the top of your program. Write 3 additional functions: subtract, multiply, and divide. Pay careful attention to the parameters and return statement. Remember to put the three functions at the top of your Python program before your main code. Rewrite the main code so that your functions are called. Part B There are many different ways that a user could tell us that he or she would like to add two numbers in our calculator program. The user could type “add”, “Add”, “ADD”, or “+”, to name a few possibilities. Of cour
Answers
Answer:
sorry but there is not enough information to complete this
Explanation:
working on rewriting my code so i can paste it here! itll be done in a sec
True or False. Malware that executes damage when a specific condition is met is the definition of a trojan horse
Answers
The statement "Malware that executes damage when a specific condition is met is the definition of a trojan horse" is partially true, as it describes one of the characteristics of a Trojan horse.
A Trojan horse is a type of malware that is designed to disguise itself as a legitimate software or file in order to deceive users into downloading or executing it.
Once installed on the victim's computer, the Trojan horse can perform a variety of malicious actions, such as stealing sensitive data, spying on the user's activities, or damaging the system.
One of the key features of a Trojan horse is that it often remains inactive until a specific trigger or condition is met. For example, a Trojan horse might be programmed to activate itself on a certain date or time, or when the user performs a specific action, such as opening a file or visiting a certain website. This makes it difficult for users to detect or remove the Trojan horse before it causes harm.
However, it is worth noting that not all malware that waits for a specific condition to occur is a Trojan horse. There are other types of malware, such as viruses and worms, that can also be programmed to execute specific actions based on certain triggers. Therefore, while the statement is partially true, it is not a definitive definition of a Trojan horse.
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Potential Energy and Kinetic Energy both mean "energy in motion" True or False
Answers
Answer:
false
Explanation:
pretty sure energy in motion is only for kinetic energy
Answer:
False
Explanation:
I'm pretty sure potential energy is there when something isn't moving and kinetic energy is when something is in motion
When you create an ordered list, numbers will be automatically inserted in front of your text. A. True B. False
Answers
False. Depending on the particular formatting of the ordered list used, numbers or letters will be automatically put before the text when you create an ordered list.
Is it true that an ordered list always begins with number one?The default starting point is "1". The first item on an ordered list appears at the top by default. The appearance of a list item is determined by this characteristic.
Do ordered and unordered lists not differ from one another? False or true?A list of elements in no particular order, where the order is irrelevant, is created using an unordered list (). The elements in this list will by default be denoted by bullets. whereas a list of items is created using an ordered list ()
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A surrogate key is appropriate when the primary key of a table contains a lengthy text field (T/F)
Answers
True. A surrogate key is appropriate when the primary key of a table contains a long text field.
A surrogate key is a system-generated unique identifier that is used as the primary key of a table instead of a natural key, such as a lengthy text field.
The primary key of a table should ideally be a natural key that uniquely identifies each record in the table based on its inherent characteristics, such as a person's social security number or a product's serial number.
Using a surrogate key is appropriate when there is no suitable natural key available, or when the natural key is not reliable or efficient. For example, in a table with a lengthy text field as its primary key, a surrogate key could be introduced to simplify indexing and querying.
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A variable of type unsigned short stores a value of 0. If the variable value is incremented, what exception will occur?A. No exception.B. Underflow.C. Overflow.A variable of type unsigned char stores a value of 255. If the variable value is incremented, what exception will occur?A. No exception.B. Overflow.C. UnderflowA variable of type unsigned int stores a value of 4,294,967,295 If the variable value is decremented what exception will occur?A. No exception.B. Overflow.C. Underflow.
Answers
There are different kinds of variable. The answers are below;
If the variable value is incremented, therefore, No exception will occur. If the variable value is incremented, An Overflow will occur If the variable value is decremented no exception will occur.What is Underflow?Underflow is a known to be a process or exception that happens if a number calculation is too small to be shown by the CPU or memory.
what causes a overflow is the Adding to a variable when its value is at the upper end of the datatype range.
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Alice and Bob want to split a log cake between the two of them. The log cake is n centimeters long and they want to make one slice with the left part going to Alice and the right part going to Bob. Both Alice and Bob have different values for dif- ferent parts of the cake. In particular, if the slice is made at the i-th centimeter of the cake, Alice receives a value A[i] for the first i centimeters of the cake and Bob receives a value B[i] for the remaining n - i centimeters of the cake. Alice and Bob receives strictly higher values for larger cuts of the cake: A[0] B[1]... > B[n]. Ideally, they would like to cut the cake fairly, at a loca- tion i such that A[i] = B[i], if it exists. Such a location is said to be envy-free. When A = [1,4,6,10] and B = [20, 10,6,4] then 2 is the envy-free location, since A[2] = B[2] = 6. Your task is to design a divide and conquer algorithm that returns an envy-free location if it exists and otherwise, to report that no such location exists. For full marks, your algorithm should run in O(logn) time. Remember to: a) Describe your algorithm in plain English. b) Prove the correctness of your algorithm. c) Analyze the time complexity of your algorithm. 4
Answers
a) Algorithm Description:
Check if the lengths of arrays A and B are the same. If not, return that no envy-free location exists.
Define a helper function findEnvyFree that takes the start and end indices of the subarray to be considered.
Calculate the mid index as (start + end) // 2.
Check if A[mid] = B[mid]. If true, return mid as the envy-free location.
If A[mid] < B[mid], it means the envy-free location is on the right half of the subarray. Recursively call findEnvyFree with the subarray starting from mid+1 to end.
If A[mid] > B[mid], it means the envy-free location is on the left half of the subarray. Recursively call findEnvyFree with the subarray starting from start to mid-1.
If no envy-free location is found in either half, return that no envy-free location exists.
b) Correctness Proof:
The algorithm uses a divide and conquer approach to search for the envy-free location in the given arrays A and B.
By dividing the arrays into halves and recursively searching, it narrows down the search space until either an envy-free location is found or it is determined that no envy-free location exists.
The correctness of the algorithm can be proven by observing the following:
At each step, the algorithm compares the values at the mid-index of A and B.
If A[mid] = B[mid], it means an envy-free location is found, and the algorithm returns the mid index.
If A[mid] < B[mid], it means the envy-free location is on the right half of the subarray, so the algorithm recursively searches the right half.
If A[mid] > B[mid], it means the envy-free location is on the left half of the subarray, so the algorithm recursively searches the left half.
The algorithm continues dividing the subarrays until it finds an envy-free location or determines that no envy-free location exists.
Since the algorithm considers both halves of the subarray at each step, it covers all possible locations and ensures that if an envy-free location exists, it will be found.
c) Time Complexity Analysis:
The algorithm follows a divide-and-conquer approach, dividing the problem into halves at each step.
The time complexity of the algorithm can be analyzed as follows:
At each step, the algorithm reduces the search space by half.
Therefore, the number of recursive steps required to find the envy-free location is O(log n),
where n is the length of the input arrays A and B.
At each step, the algorithm performs constant-time operations to calculate the mid-index and compare values.
Hence, the overall time complexity of the algorithm is O(log n).
The algorithm achieves the required O(log n) time complexity by dividing the problem into smaller subproblems and efficiently searching for the envy-free location in a balanced manner.
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The algorithm for the envy-free location is a modified binary search algorithm in which we will be searching for a midpoint i such that A[i] equals B[i].Here is how the algorithm works:
Step 1: Check if A[n-1] ≤ B[0]. If this is true, then return n-1 as the envy-free location. If this is false, move to step 2.
Step 2: Define two pointers, low = 0 and high = n-1. Define a variable mid = (low+high)/2.
Step 3: Check if A[mid] = B[mid]. If this is true, then return mid as the envy-free location. If this is false, move to step 4.
Step 4: If A[mid] < B[mid], then set low = mid. If A[mid] > B[mid], then set high = mid. Recalculate mid using mid = (low+high)/2. Repeat step 3 and 4 until either A[mid] = B[mid] or low = mid = high, in which case we report that no envy-free location exists. We now prove the correctness of this algorithm.
Consider the following facts:
The envy-free location exists if and only if there is an i such that A[i] ≤ B[i+1] (i.e. the left part of the cut for Alice has a value less than or equal to the right part of the cut for Bob). If we cannot find such an i, then the envy-free location does not exist. Proof of Step 1: If A[n-1] ≤ B[0], then the envy-free location is n-1. This is because Alice would be happy with the entire cake, and so would Bob. Therefore, the cut is envy-free.
Proof of Step 3: If A[mid] = B[mid], then mid is the envy-free location. This is because the left part of the cut for Alice (from 0 to mid) has the same value as the right part of the cut for Bob (from mid+1 to n-1). Therefore, the cut is envy-free.
Proof of Step 4: If A[mid] < B[mid], then the envy-free location must be to the right of mid. This is because if we make a cut to the left of mid, then the left part of the cut for Alice would have a lower value than the right part of the cut for Bob, and so neither of them would be happy. If we make a cut to the right of mid, then the left part of the cut for Alice would have a higher value than the right part of the cut for Bob, and so Bob would not be happy. Similarly, if A[mid] > B[mid], then the envy-free location must be to the left of mid. This is because if we make a cut to the right of mid, then the right part of the cut for Bob would have a lower value than the left part of the cut for Alice, and so neither of them would be happy.
If we make a cut to the left of mid, then the right part of the cut for Bob would have a higher value than the left part of the cut for Alice, and so Alice would not be happy. Therefore, the algorithm is correct. The time complexity of the algorithm is O(log n). This is because we are performing a binary search on an array of length n. At each iteration, the size of the array is divided in half. Therefore, the number of iterations required to find the envy-free location is log n.
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make a story that ends in ´ I have never found such a kind person ever since´
Answers
Lol I know this isn’t that good , but you can change it up or add stuff.
A ___ is an online collaborative event that may include such features as chat, slideshows, and PowerPoint presentations.
Answers
An Online collaboration or meeting is an online collaborative event that may include such features as, slideshows, and PowerPoint presentations.
What is an online collaborative?Online collaboration is a term that connote the using the internet and online tools to work together.
This is done with the use of a computer system instead of sitting in a physical office space. Note that online collaboration helps employees to work together from different locations and devices by the use of virtual work environments and also some shared online work spaces.
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Binary equivalent of hexadecimal number (C90)16 is
Answers
Answer:
Hexadecimal to Binary
c9016 = 1100100100002.
Explanation:
Type in a number in either binary, hex or decimal form. Select binary, hex or decimal output then calculate the number.
50 POINTS
in Java
A palindrome is a word, phrase, or sequence that reads the same backward as forward, e.g., madam or nurses run.
In this program, ask the user to input some text and print out whether or not that text is a palindrome.
Create the Boolean method isPalindrome which determines if a String is a palindrome, which means it is the same forwards and backwards. It should return a boolean of whether or not it was a palindrome.
Create the method reverse which reverses a String and returns a new reversed String to be checked by isPalindrome.
Both methods should have the signature shown in the starter code.
Sample output:
Type in your text:
madam
Your word is a palindrome!
OR
Type in your text:
hello
Not a palindrome :(
Answers
import java.util.Scanner;
public class JavaApplication52 {
public static String reverse(String word){
String newWord = "";
for (int i = (word.length()-1); i >= 0; i--){
newWord += word.charAt(i);
}
return newWord;
}
public static boolean isPalindrome(String word){
if (word.equals(reverse(word))){
return true;
}
else{
return false;
}
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Type in your text:");
String text = scan.nextLine();
if (isPalindrome(text) == true){
System.out.println("Your word is a palindrome!");
}
else{
System.out.println("Not a palindrome :(");
}
}
}
I hope this works!
(B) PStudio File Edit Code View Plots Session Build Debug Profile Took Help - Addins. (3) Untitled1* 60 makecov × 49 #Create and execute an R function to generate a covariance matrix. 50 rho <−0.5 51n<−5 52 - makecov <- function (rho,n){ 53 m< matrix ( nrow =n,nco⌉=n)I H we are returning a matrix of 54m<− ifelse(row (m)==col(m),1, rho ) 55 return (m) 56−3 57m= makecov (rho,n) 58 m 53.43 In makecov(rho, n) = Console Terminal × Background Jobs x
Answers
The code provided is incomplete and contains some syntax errors. Here is the corrected version of the code:
R
makecov <- function(rho, n) {
m <- matrix(nrow = n, ncol = n)
for (i in 1:n) {
for (j in 1:n) {
if (i == j) {
m[i, j] <- 1
} else {
m[i, j] <- rho
}
}
}
return(m)
}
rho <- -0.5
n <- 5
m <- makecov(rho, n)
m
This code defines a function makecov that takes two arguments rho and n to generate a covariance matrix. The function creates an n x n matrix m and sets the diagonal elements to 1 and the off-diagonal elements to rho. Finally, it returns the generated covariance matrix m.
The code then assigns values to rho and n variables and calls the makecov function with these values. The resulting covariance matrix m is printed to the console.
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(PLEASE HELP!! I'll award brainiest!!)
Which feature in Windows allows you to install patches to ensure your operating system is secure?
Repair
System
Update
Toolbar
Answers
Answer:
Repair
help me by marking as brainliest....
An operating system (OS) is the software that handles all of the other application programs in a computer after being loaded into the machine by a boot program. The correct option is A.
What is an operating system?An operating system (OS) is the software that handles all of the other application programs in a computer after being loaded into the machine by a boot program. The application programs interact with the operating system by requesting services via a predefined application program interface (API).
The feature in Windows that allows you to install patches to ensure your operating system is secure is the Repair feature.
Hence, the correct option is A.
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write a function that counts how many times a substring occurs in a string:
Answers
Certainly! Here's an example of a function in Python that counts how many times a substring occurs in a string:
python
Copy code
def count_substring_occurrences(string, substring):
count = 0
start = 0
while True:
index = string.find(substring, start)
if index == -1:
break
count += 1
start = index + 1
return count
You can use this function by providing the string and substring arguments. It will return the number of occurrences of the substring within the string. For example:
python
Copy code
string = "Hello, hello, hello"
substring = "hello"
occurrences = count_substring_occurrences(string, substring)
print(occurrences) # Output: 3
The function uses the find() method to search for the substring within the string and keeps track of the count using a while loop. It starts searching from the previous found index + 1 to find all occurrences in the string.
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Lets do a who know me better! 5 questions! if you get 4\5 you get brainliest or a 3\5 but anything below u dont get it!
How old am I?
Do I like Summer or Winter?
Whats my name? (You guys should get this.)
What grade am I in? (Its between 4th and 8th).
How many siblings do I have? ( its between 2 and 5)
Good Luck!
Answers
Answer:your 13
you enjoy winter but still like summer
Skylar
either 7 or 8th
3 siblings
Explanation:
a server within your organization has suffered six hardware failures in the past year. it management personnel have valued the server at $4,000, and each failure resulted in a 10 percent loss. what is the ale?
Answers
The annualized loss expectancy (ALE) for a server that has suffered six hardware failures in the past year, resulting in a 10 percent loss each time and with a value of $4,000, can be calculated as follows:
ALE = (Number of failures) * (Loss per failure) * (Value of asset)
= 6 * (10/100) * $4,000
= $240
This means that the ALE for the server is $240 per year.
What is Annualized loss expectancy (ALE)?
The ALE is a measure of the expected loss or cost associated with an asset or risk over a given period of time, and can be used to help organizations make informed decisions about how to allocate resources and manage risks.
In this case, the high number of hardware failures and resulting losses suggest that the server may be unreliable and may require additional maintenance or replacement to reduce the risk of further failures and losses.
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We never ………. TV in the morning.
Answers
Answer:
watch................
which cellular technology is compromised of hspa and ev-do to provide higher data speeds than previous cellular data protocols?
Answers
The cellular technology that is compromised of HSPA and EV-DO to provide higher data speeds than previous cellular data protocols is called HSPA+ and EV-DO Rev A. Cellular technology refers to the various technologies and standards used for mobile telecommunication.
HSPA, which stands for High-Speed Packet Access, is a 3G (third generation) cellular technology that provides faster data speeds than previous 2G technologies. It uses a combination of Time Division Multiplexing (TDM) and Code Division Multiple Access (CDMA) to increase data transmission rates. HSPA is an evolution of WCDMA (Wideband Code Division Multiple Access), which is the technology used in 3G networks. HSPA+ is an enhanced version of HSPA, which provides even faster data speeds.
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Use the drop-down menu to correctly identify the numbering system.
This numbering system uses 8 symbols:
This numbering system uses 0 and 1:
This numbering system uses 16 symbols:
This numbering system uses 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9:
This numbering system uses 2 symbols:
This numbering system uses 10 symbols:
This numbering system uses numbers and letters:
This numbering system uses 0, 1, 2, 3, 5, 6, and 7:
Answers
This numbering system uses 8 symbols: octal number
This numbering system uses 0 and 1: binary number
This numbering system uses 16 symbols: hexadecimal
This numbering system uses 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9: decimal number system
This numbering system uses 2 symbols: binary number system
This numbering system uses 10 symbols: decimal number system
This numbering system uses numbers and letters: hexadecimal number system
This numbering system uses 0, 1, 2, 3, 5, 6, and 7: octal number system
This numbering system uses 8 symbols is octal number and that of 0 and 1 is binary number.
What is numbering system?Other are:
The numbering system that uses 16 symbols: hexadecimal.The numbering system that uses 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9: decimal.The numbering system that uses 2 symbols: binary.The numbering system that uses 10 symbols: decimal.The numbering system that uses numbers and letters: hexadecimal.This numbering system uses 0, 1, 2, 3, 5, 6, and 7: octal.The numbering system is known to be often used in computer.
Conclusively, it is known to be a kind of systematic process for depicting or showing numbers through the use of a specific set of symbols such as the ones given above.
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Fundamental of Computer Science
Prompt:
What is a class that you believe you could learn just as well in an online class as an in
person class? What is a class that you think you need to have in person if you want to learn
and pass the course? How are these subjects different? What factors contributed to your
decision?
Answers
Answer:
Coding and Hardware Hacking
Explanation:
You can learn coding just as well through a online class or even on the internet through yo*tube than an in person class whereas it would be alot easier learning hardware hacking in person because you are given the opportunity to ask and can be corrected for small mistakes due to the task being manual. Coding can be learnt online independently if needed although so can hardware hacking but having a teacher to correct you and teach you handy tricks from their experience will get you further in that sense.
Heya party people just bneeed help!
The repetition of a function or process in a computer program. Iterations of functions are common in computer programming, since they allow multiple blocks of data to be processed in sequence. This is typically done using a "while loop" or "for loop." These loops will repeat a process until a certain number or case is reached.
Variable
Boolean Logic
Iterate
Function
Answers
The process that is typically done using a "while loop" or "for loop and the loops repeating a process until a certain number or case is reached is C. Iterate
What is repetition?The process of looping or repeating sections of a computer program is known as repetition in computer programming. There are various types of loops. The most fundamental is where a set of instructions is repeated a predetermined number of times. Another type of loop continues to repeat until a certain condition is met.
Iteration is the repetition of a process to produce a series of results. Each iteration of the process is a single repetition of the process, and the outcome of each iteration serves as the starting point for the next iteration. Iteration is a common feature of algorithms in mathematics and computer science.
A loop is a section of code that is executed multiple times. Iteration refers to the process of running the code segment once. One iteration is the execution of a loop once.
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What is a graphic unit
Answers
Answer:
If you mean a graphic processing unit:
A graphics processing unit is a specialized, electronic circuit designed to rapidly manipulate and alter memory to accelerate the creation of images in a frame buffer intended for output to a display device.
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A colored border,with ____________, appears around a cell where changes are made in a shared worksheet .
a) a dot in the upper left-hand corner
b) a dot in the lower-hand corner
c) a cross in the upper left-hand corner
d) a cross in the upper right-hand corner
Answers
A colored border, with a cross in the upper left-hand corner, appears around a cell where changes are made in a shared worksheet . (Option
What is a Shared Worksheet?A shared worksheet is a Microsoft Excel file that can be accessed and edited by multiple users simultaneously.
Thus, the border is an indication that the cell has been changed, and the cross in the upper left-hand corner represents the user who made the change. Other users who are currently viewing the shared worksheet will see the colored border and cross to indicate that changes have been made. This feature helps to facilitate collaboration and prevent conflicting changes in shared worksheets.
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URGENT! REALLY URGENT! I NEED HELP CREATING A JAVASCRIPT GRAPHICS CODE THAT FULFILLS ALL THESE REQUIREMENTS!
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In the program for the game, we have a garden scene represented by a green background and a black rectangular border. The cartoon character is a yellow circle with two black eyes, a smiling face, and arcs for the body. The character is drawn in the center of the screen.
How to explain the informationThe game uses Pygame library to handle the graphics and game loop. The garden is drawn using the draw_garden function, and the cartoon character is drawn using the draw_cartoon_character function.
The game loop continuously updates the scene by redrawing the garden and the cartoon character. It also handles user input events and ensures a smooth frame rate. The game exits when the user closes the window.
This example includes appropriate use of variables, a function definition (draw_garden and draw_cartoon_character), and a loop (the main game loop). Additionally, it meets the requirement of using the entire width and height of the canvas, uses a background based on the screen size, and includes shapes (circles, rectangles, arcs) that are used appropriately in the context of the game.
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Create a C++ program that will accept five (5) numbers using the cin function and display the numbers on different lines with a comma after each number.
Answers
Answer:
code:
#include<iostream>
using namespace std;
int main()
{
//declare an array of size 5
int array[5];
cout<<"Enter the numbers"<<endl;
//applying the for loop
for(int i=0;i<5;i++)
{
//taking the input from user
cin>>array[i];
}
cout<<"The Entered numbers are : "<<endl;
for(int i=0;i<5;i++)
{
//displaying the output
cout<<array[i]<<", "<<endl;
}
return 0;
}
Explanation:
First of all you will declare an array of size 5
then you are going to apply the for loop logic where you will take input from the user
again you will apply the for loop to print the entered numbers on screen
#include <iostream>
int store[5];
int main() {
for(int i=0;i<5;i++) {
std::cin>>store[i];
}
for(auto& p:store) {
std::cout << p << ",\n";
}
return 0;
}
What will be assigned to the variable s_string after the following code executes? special = '1357 country ln.' s_string = special[ :4] '7' 5 '1357' '7 country ln.'
Answers
Answer:
1357
Explanation:
s_string = special[ :4]
"[:4]" means the first character up to the third character
A free software license allows users to
Answers
Answer:
C. use, alter, and distribute the software as desired.
Explanation:
A software can be defined as a computer program or application that comprises of sets of code for performing specific tasks on the system
A free software license allows users to use, alter, and distribute the software as desired.
You are the IT administrator for a small corporate network. You are configuring Windows Update on the Office2 workstation in Office 2.
In this lab, your task is to complete the following:
Set the active hours of the workstation to 6:00 a.m. to 11:00 p.m.
Configure Windows Update to install updates semi-annually.
Allow other Microsoft products to update when I update Windows.
Defer the update to 90 days.
Set security improvements to 0 days.
Set Pause Updates to Off.
Answers
Since you are the IT administrator for a small corporate network. You are configuring Windows Update on the Office2 workstation in Office, the way to complete the task is given below:
How do you Finish the lab work?To do so:
Right-click Start and choose Settings.Increase the window's size for simpler viewing.To update and secure, click.Choose Change active hours under Update Settings.Decide on 6:00 a.m. as the Start time.Place a check in the box.Decide on 11:00 p.m. as the End time.Place a check in the box.Choose Save.Choose Advanced choices.When updating Windows, check the box labeled Give me updates for other Microsoft products.Select Semi-Annual Channel in the drop-down menu for "Choose when updates are installed."Choose 90 from the drop-down selection for the deferred update.Choose 0 from the drop-down menu for the postponed security upgrades.Turn off Pause Updates.Lastly, one can say that a system administrator who is also said to be sysadmin, or admin, is seen as a person who is in charge of maintaining, configuring, and ensuring the smooth operation of computer systems, particularly those that serve multiple users and can do the above task.
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