a) Sequence diagram: Visualizes the chronological flow of messages and interactions between objects. b) Collaboration diagram: Illustrates the structural relationships between objects and their interactions. c) Main differences: Sequence diagrams focus on message flow, while collaboration diagrams emphasize object relationships.
a) Sequence Diagram:
A sequence diagram visualizes the interactions and order of messages between different objects or components in a system. Based on the given specification, here's a sequence diagram representing the interactions between John, the Thunderbird email application, and the email server:
lua
Copy code
John Thunderbird Email Server
| | |
|------- Get Messages ----->| |
| |------- Send Unsent Emails ---->|
| |<----- Response (Unsent) -------|
| |------- Check New Emails ------->|
| |<----- Response (No New) -------|
| |<----- Response (New Emails) ---|
| |------- Download Emails -------->|
| |<----- Response (Downloaded) ---|
| | |
b) Collaboration Diagram:
A collaboration diagram, also known as a communication diagram, illustrates the relationships and interactions between objects or components in a system. Based on the given specification, here's a collaboration diagram representing the collaboration between John, the Thunderbird email application, and the email server:
sql
Copy code
+-------------+
| John |
+-------------+
|
| Get Messages
|
+------------------+
| Thunderbird App |
+------------------+
|
| Send Unsent Emails
|
+----------------+
| Email Server |
+----------------+
|
| Response (Unsent)
|
+------------------+
| Thunderbird App |
+------------------+
|
| Check New Emails
|
+----------------+
| Email Server |
+----------------+
|
| Response (No New)
|
+------------------+
| Thunderbird App |
+------------------+
|
| Response (New Emails)
|
+----------------+
| Email Server |
+----------------+
|
| Download Emails
|
+------------------+
| Thunderbird App |
+------------------+
|
| Response (Downloaded)
|
c) Differences between Sequence and Collaboration Diagrams:
Representation: In a sequence diagram, interactions between objects are shown in a linear manner, emphasizing the chronological order of messages exchanged. On the other hand, a collaboration diagram focuses on the structural organization of objects and highlights the relationships and interactions between them.
Message Flow: In a sequence diagram, the flow of messages is represented vertically, indicating the sender and receiver of each message. In a collaboration diagram, the messages flow horizontally, emphasizing the collaboration between objects.
Level of Detail: Sequence diagrams provide a detailed view of the interactions between objects, including the order of messages and any possible return messages. Collaboration diagrams focus more on the relationships and collaborations between objects, providing a higher-level overview.
Object Focus: Sequence diagrams typically emphasize the behavior of individual objects, showcasing their interactions. Collaboration diagrams, on the other hand, highlight the collaboration between multiple objects to achieve a specific goal.
Based on the sequence and collaboration diagrams drawn above, the main difference is the visual representation and emphasis on message flow in a sequence diagram, whereas a collaboration diagram focuses on the structural organization and collaboration between objects.
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Create a decision matrix that can be used to decide the changes that could be implemented in the design of an automobile, and explain how an engineer might find it useful.
Answer:
An engineer using a decision matrix to determine which one of his/her solution ideas meets the established criteria and constraints.
Why are there few effective HCI standards?
Answer:
There are few effective Human Computer Interaction (HCI) standards because for one, standards are more suitable for hardware than software because they are relatively unstable. ... Some software product standards have been in place long before any formal standard documents were published.
Can space debris take out a whole state
Two sides and the included angle of triangle were measured as under
A = 757.64 +0.045 m
B = 946.70+ 0.055 m
C = 54°18+25"
Based on the calculations, the area of this triangle is equal to 290,136.87 m².
Given the following data:
Side A = 757.64 +0.045 m.Side B = 946.70+ 0.055 m.Angle, C = 54°18'25"How to calculate the area of this triangle?Mathematically, the area of a triangle can be calculated by using this formula:
Area = 1/2 × b × h
Where:
b is the base area.h is the height.In this scenario, the area of this triangle is given by:
Area = 1/2 × a × b × sinC
Substituting the given parameters into the formula, we have:
Area = 1/2 × 757.64 × 946.70 × sin(54°18'25")
Area = 580,273.74/2
Area = 290,136.87 m².
Next, we would determine the probable error of the area by using this formula:
\(PE_A = \pm k \sqrt{PE} \\\\PE_A = \pm \frac{1}{2} \times sinC \sqrt{(aPE_b)^2 + (bPE_a)^2 } \\\\PE_A = \pm \frac{1}{2} \times sin(54^{\circ}18'25") \times \sqrt{(757.64 \times 0.045)^2 + (946.70 \times 0.055)^2 } \\\\PE_A = \pm 0.4045 \times \sqrt{1,162.39 +2,711.12}\\\\PE_A = \pm 0.4045 \times \sqrt{3,873.51}\\\\PE_A = \pm 0.4045 \times 62.2375\\\\PE_A = \pm25.1751 \;m^2\)
Therefore, probable error of the area is equal to ±25.1751 m².
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Complete Question:
Two sides and the included angle of a triangle were measured and the probable error of each value were computed as follows:
A = 757.64 +0.045 m
B = 946.70+ 0.055 m
C = 54°18'25"
Determine the area of the triangle and the probable error of the area.
A stall occurs when the smooth airflow over the unmanned airplane`s wing is disrupted, and the lift degenerates rapidly. This is caused when the wing
A stall happens when the smooth airflow over the unmanned airplane`s wing is disrupted, and the lift degenerates rapidly. This is caused when the wing "exceeds its critical angle of attack."
The angle of attack refers to the angle at which the airplane's wing meets the air that is flowing over it. When an airplane actually is taking off, it is lifting the nose up into the air. And, if that nose continues to rise ultimately it reaches a point where the air is not able to smoothly flow over the wing, causing the airplane to drop. And, this is the point when the airplane exceeds its critical angle of attack.
Exceeding the critical angle of attack is known to be a stall. This has no concern with the engine stalling, it just concerns with the wings not producing enough lift to keep the airplane in the air.
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Two cylindrical rods, AC made of aluminum and CD made of steel, are joined at C and restrained by rigid supports at A and D. It is given that Ea = 10. 4 × 106 psi, Es = 29 × 106 psi, and P = 26 kips. Determine
(a) the reactions at A and D, and
(b) the deflection of point C
Answer:
The figure below shows the free body diagram of the beam.
Free Body Diagram
Write the compatibility equation,
Δ
A
B
+
Δ
B
C
+
Δ
C
D
=
0
⋯
⋯
(
I
)
Here,
Δ
A
B
is the deflection in AB rod,
Δ
B
C
is the deflection in BC rod and
Δ
C
D
is the deflection in the rod CD.
The deflection
Δ
A
B
is,
Δ
A
B
=
4
(
R
A
)
(
a
)
π
d
2
a
E
a
Here,
R
A
is the reaction at point A.
The deflection ${\Delta _{BC}$ is,
Δ
A
B
=
4
(
R
A
−
F
B
)
(
b
)
π
d
2
a
E
a
The deflection ${\Delta _{CD}$ is,
Δ
A
B
=
4
(
R
A
−
F
B
−
F
C
)
(
b
)
π
d
2
s
E
s
Substitute all the values in the equation (I).
4
(
R
A
)
(
8
i
n
)
π
(
9
8
i
n
)
2
(
10.4
M
s
i
)
+
4
(
R
A
−
18
k
i
p
s
)
(
10
i
n
)
π
(
9
8
i
n
)
2
(
10.4
M
s
i
)
+
4
(
R
A
−
18
k
i
p
s
−
14
k
i
p
s
)
(
10
i
n
)
π
(
13
8
i
n
)
2
29
M
s
i
=
0
(
R
A
)
(
0.8
)
(
9
8
i
n
)
2
+
(
R
A
−
18
k
i
p
s
)
(
9
8
i
n
)
2
=
−
(
R
A
−
18
k
i
p
s
−
14
k
i
p
s
)
(
13
8
i
n
)
2
29
10.4
R
A
=
11.917
k
i
p
s
Equate the horizontal forces,
R
A
+
R
B
=
F
B
+
F
C
Substitute all the values in the above equation.
11.917
k
i
p
s
+
R
B
=
18
k
i
p
s
+
14
k
i
p
s
R
B
=
20.083
k
i
p
s
Thus the reaction at point A is
11.917
k
i
p
s
and reaction at B is
20.083
k
i
p
s
.
(b)
The deflection at point C is,
Δ
C
=
4
(
R
B
)
(
b
)
π
d
2
s
E
s
Substitute all the values in the above equation.
Δ
C
=
4
(
20.083
k
i
p
s
(
1000
l
b
1
k
i
p
s
)
)
(
10
i
n
)
π
(
13
8
i
n
)
2
29
M
s
i
(
10
6
l
b
/
i
n
2
1
M
s
i
)
=
3.33
×
10
−
3
i
n
what substance does light travel through before putting water in the cup
The Mars roving-laboratory parachute, a 55-ft-diameter disk-gap-band chute with a measured drag coefficient of 1.12. Mars has very low density, about 2.9E-5 slug/ft3, and its gravity is only 38% of earth gravity. If the mass of payload and chute is 2700 kg, estimate the terminal fall velocity of the parachute. Round the final answer to three decimal places.
The parachute's terminal fall velocity is V = 73.561 m/s if the combined mass of the cargo and chute is 2700 kg.
Convert D = 55ft= 16.8m
and Y = 29 E - 5 sluglift 3 = 0. 015 Kg / m³
At terminal velocity, the chute dray balances the parachute weight.
w = mass.gravity=mg = 2700 x 0 38 x 9.81
W = 10065.06 N
W = c.d.p/2V² X π/4 D²
10065. 06 = ( 1.12 ) x ( 0.015 ) V2 x TI x ( 16. 8 )?
10065.06 = 1.86 V 2
V = 73.561 m/s
Weight affects speed going down the , but mass affects speed going out of the . When friction is the same, heavier cars move farther because they have more momentum.
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What relates a landscape architect's knowledge of design to the landscape architect's knowledge of law and government?
Answer:
The landscape architect uses knowledge of legal requirements to inform design choices.
Explanation:
The landscape architect doesn’t only draw on knowledge of law and government to design grounds for public buildings, but will draw on that knowledge quite often on many projects. The landscape architect’s knowledge of design is not purely intuitive but is a product of study and might involve research. The landscape architect’s knowledge of law and government, however, does come into play in making design choices that are consistent with the law and government regulations.
Crank OA rotates with uniform angular velocity 0 4 rad/s along counterclockwise. Take OA= r= 0.5
m,AB2r,and BC 2r.For the instant, 45,OA is horizontal and AB is vertical.
determine the angular velocity and angular acceleration of BC.
Using the correlation for the second virial coefficient (Pitzer correlation), find the molar volume of acetylene vapour at 247.1 K and 13.5 bar, giving your answer to the nearest cm3/mol. The critical temperature is 308.3 K and the critical pressure of acetylene is 61.39 bar. Take R = 8.314 J/mol-K and the acentric factor for acetylene is 0.187.
The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.
Explanation:
The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.
Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.
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If C1= 20 micro farad and CW= 10 micro farad are connected in series in a simple electric circuit,then find the total capacitance
The total capacitance of the given electric circuit is 30 microfarad.
Define capacitance.
The ability of a physical thing or equipment to store electric charge is known as capacitance. The capacitance is quantified by the ratio of those values, which represents the change in charge in response to a variation in electric potential.
When an earthed conductor is moved close to a conductor, its capacitance increases, which is how capacitors operate. The capacitor, therefore, contains two parallel plates that are spaced apart by a certain amount of gap and oriented in opposing directions. The formula C=Q/V is used to determine a capacitor's capacitance based on its charge, Q, and its voltage, V.
Solution Explained:
Given, C1 = 20microfarad and CW = 10 microfarad
Since they are in series,
Total capacitance = C1 + CW = 20 + 10 = 30microfarad
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what is geometrical shape? list them and describe any two of them with sketch
Explanation:
Geometric Shapes can be defined as figure or area closed by a boundary which is created by combining the specific amount of curves, points, and lines.
Choose two other elements from the periodic table that you predict should react to form something like table salt
Please pleassssss helppp
I give branlistttttt
I need help with this problem
Answer:
good question but i cant solve
which type of refrigerant cylinder is gray on the bottom and yellow on the top?
The type of refrigerant cylinder that is gray on the bottom and yellow on the top is commonly known as a "One-Step" cylinder.
These cylinders are designed for use with R-410A refrigerant, which is commonly used in newer air conditioning and heat pump systems. The gray color at the bottom of the cylinder indicates that it is designed for use with liquid refrigerant, while the yellow color at the top indicates that it is designed for use with vapor refrigerant. This helps to prevent accidental mixing of the two forms of refrigerant, which could lead to dangerous situations. One-Step cylinders typically have a capacity of 25 pounds of refrigerant and are made of steel to ensure durability and safety.
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Assuming the validity of Raoult’s law, do the following calculations for the benzene(1)/toluene(2) system:
(a) Given x1 = 0. 33 and T = 100°C, find y1 and P.
(b) Given y1 = 0. 33 and T = 100°C, find x1 and P.
(c) Given x1 = 0. 33 and P = 120 kPa, find y1 and T.
(d) Given y1 = 0. 33 and P = 120 kPa, find x1 and T.
(e) Given T = 105°C and P = 120 kPa, find x1 and y1.
(f) For part (e), if the overall mole fraction of benzene is z1 = 0. 33, what molar fraction of the two-phase system is vapor?
(g) Why is Raoult’s law likely to be an excellent VLE model for this system at the
stated (or computed) conditions
Answer:
a) Using Raoult's law, y1 = x1P1sat/P and P = P1sat*x1/y1, where P1sat is the vapor pressure of pure benzene at the given temperature. Assuming ideal behavior, P1sat at 100°C is 101.3 kPa, so y1 = (0.33)(101.3 kPa)/(1 atm) = 33.5 kPa and P = (101.3 kPa)(0.33)/(0.33) = 101.3 kPa.
(b) Using Raoult's law, x1 = y1P/P1sat. Substituting as before, x1 = (33.5 kPa)(101.3 kPa)/(1 atm) = 3430 ppm and P = (101.3 kPa)(0.33)/(0.33) = 101.3 kPa.
(c) Using Raoult's law, y1 = x1P1sat/P and T = T1sat*y1/(x1P1sat), where T1sat is the boiling point of pure benzene at the given pressure. Assuming ideal behavior, T1sat at 120 kPa is 104.4°C, so y1 = (0.33)(101.3 kPa)/(120 kPa) = 0.28 and T = (104.4°C)(0.28)/(0.33) = 89.0°C.
(d) Using Raoult's law, x1 = y1P/P1sat and T = T1sat*y1/(x1P1sat). Substituting as before, x1 = (33.5 kPa)(120 kPa)/(101.3 kPa) = 39.7% and T = (104.4°C)(0.33)/(0.28) = 123°C.
(e) Using Raoult's law, x1 = P1sat1/(P1sat1 + P1sat2) and y1 = P1sat1*x1/P. Substituting as before, x1 = 0.497 and y1 = 0.415.
(f) The vapor mole fraction is given by y1 = z1*x1/(x1 + (1 - x1)*K), where K is the equilibrium constant for the system. Assuming ideal behavior, K = P2sat/P1sat = 1.3,
Explanation:
hope this helps!
please i want to paraphrase this paragraph please helppppppppp don't skip!!!!!!
Which type of work is a textile engineer most likely to do?
A.
manufacture chemical products to use in medications
B.
manufacture cloth from raw materials through an industrial process
C.
design large-scale manufactured structures, such as buildings and bridges
D.
design automated industrial machines and the computer systems that control them
Answer:
B because as a textile engineer, your job is to help design and create fabric, including the equipment and materials needed for fabrication.
Is the impedance of the capacitor purely reactive, and how does it compare to the nominal value of the ideal capacitor? Why or why not is it purely reactive?
In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.
What is the impedance of an ideal capacitor?An perfect capacitor has an infinite resistance. For all frequencies and capacitance levels, the reactance of a perfect capacitor, and consequently its impedance, is negative.A capacitor that has no resistance and therefore doesn't lose any energy while it's operating is the ideal capacitor. It just possesses capacitance. There is no dielectric loss in a perfect capacitor. High temperature stability characterizes the ideal capacitor.As capacitance and frequency increase, capacitive reactance falls. Impedance is the complete opposition that reactance and resistance give.Similar to inductors, the ideal capacitor is a totally reactive device with no resistive (power dissipative) effects whatsoever. Of course, nothing is so flawless in the actual world. Capacitors, however, have the advantage of often being more pure reactive componentsTo learn more about Ideal capacitor refer to:
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Dust,dirt, or metal chips can pose a potential what kind of injury risk in a shop
Answer:
Dust, dirt, or metal chips can pose a potential eye injury risk in a shop.
Explanation:
Consider a receiver with noise power −160 dBm within the signal bandwidth of interest. Assume a simplified path loss model with d0 = 1 m, K obtained from the free space path loss formula with omnidirectional antenna and fc = 1 GHz and gamma = 4. For a transmit power of Pt = 10 mW, find the maximum distance between the transmitter and receiver such that the received signal-to-noise power ratio is 20 dB
As a result, 22.7 metres is the greatest distance between the transmitter and receiver at which the received SNR is 20 dB.
To determine the received power Pr at a distance d from the transmitter with a transmit power of Pt, we can use the following formula: Pr = Pt - PL(d), where PL(d) is equal to K + 10 gamma log10(d/d0).
The following formula can be used to determine the farthest distance dmax at which the received signal-to-noise power ratio (SNR) is 20 dB:
Pr / N0 = SNR
SNR being equal to 20 dB, the formula becomes:
Pr=SNR*N0 = 10
(SNR/10) * N0
In the equation above, we may substitute the equations for Pr and PL(d) to obtain:
Pt-K-Gamma*Log10(d/d0) = 10(SNR/10)*N0
When we solve for d, we obtain: d = d0 * 10
(10 * gamma) / ((Pt - K - SNR * 10 * log10(N0) - 10 * gamma * log10(d0)))
d = 1 * 10^
(10 mW - 20.8 - (-160) - 10*4*log10(1)) / (10*4) = 22.7 metres
As a result, 22.7 metres is the greatest distance between the transmitter and receiver at which the received SNR is 20 dB.
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In a certain chemical plant, a closed tank contains ethyl alcohol to a depth of 71 ft. Air at a pressure of 17 psi fills the gap at the top of the tank. Determine the pressure at a closed valve attached to the tank 10 ft above its bottom.
Answer:
the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
Explanation:
Given that;
depth 1 = 71 ft
depth 2 = 10 ft
pressure p = 17 psi = 2448 lb/ft²
depth h = 71 ft - 10 ft = 61 ft
we know that;
p = P_air + yh
where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )
so we substitute;
p = 2448 + ( 49.3 × 61 )
= 2448 + 3007.3
= 5455.3 lb/ft³
= 37.88 psi
Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
Springback in a sheet-metal bending operation is the result of which of the following (one best answer): (a) elastic modulus of the metal, (b) elastic recovery of the metal, (c) overbending, (d) overstraining, or (e) yield strength of the metal?
Springback in sheet-metal bending refers to the tendency of the metal to return to its original shape after being bent. This phenomenon occurs due to the elastic properties of the metal. In sheet-metal bending, the metal is subjected to plastic deformation, and this causes changes in the internal structure of the material. When the load is removed, the metal will tend to spring back to its original shape.
Option A is correct
The main factor responsible for springback is the elastic recovery of the metal, which refers to the ability of the material to regain its original shape after being deformed. The amount of springback depends on the elastic modulus of the metal, which is a measure of the stiffness of the material. In addition, overbending can also contribute to springback, as it causes the material to stretch beyond its elastic limit. Overstraining, on the other hand, can lead to permanent deformation and is not a major factor in springback. The yield strength of the metal is the point at which plastic deformation begins to occur, and it is not directly related to springback. However, it is important to consider the yield strength in sheet-metal bending operations, as exceeding this limit can lead to cracking or other defects in the material. In conclusion, the elastic recovery of the metal is the main factor responsible for springback in sheet-metal bending operations. Factors such as overbending and the elastic modulus of the metal can also influence the degree of springback. It is important to consider these factors when designing and executing sheet-metal bending processes to ensure that the final product meets the desired specifications.For such more question on deformation
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Springback is a common issue in sheet metal bending operations. It occurs when the metal tries to return to its original shape due to elastic recovery after being bent.
This can result in a deviation from the intended shape, which is undesirable. The elastic modulus, yield strength, overbending, and overstraining are all factors that affect the amount of springback, but the primary cause is the elastic recovery of the metal. This is because the metal undergoes plastic deformation during bending, which changes its shape permanently.
However, when the bending force is removed, the metal attempts to regain its original shape due to its elastic properties. To minimize springback, techniques such as overbending and bottoming can be used to account for the elastic recovery of the metal.
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4. "ABC constriction Inc." company becomes the lowest in the bed process to get a $21
million construction project for "Northern Inc.". Now “ABC construction Inc." planning to
make a formal contract agreement with the "Northern Inc.". What are the main elements of
this agreement to consider it as a legal contract? Explain.
Answer is given below
Explanation:
Agreement is a official contract. It is written form or even in orally form. The Agreement can be written in formal or informal terms or we can use purely verbal language.
Agreement made between two or more party that allow the court to decide.
The main 6 elements are:
1. Offer
2. acceptance
3. consideration
4. intention to create legal relation
5. certainty
6. capacity
1. The first elements of the contract herein are ABC Sanctions Inc., without the offer, as it is not valid under the Contract Act 1950, Contract Act.
2. Once the offer is made in the contract, acceptance must take place. The agreement must be approved by Northern Inc. When Northern Inc is clear with the offer, it will accept it once the terms and conditions of the agreement are clear.
3. Contrarification is the most important aspect of a contract, when considering a contract, the other person will give something in return. It is considered an exchange between ABC Construction Inc and Northern Inc.
4. It is necessary to have these elements in the contract. Contract law 1950 is one of the requirements of a valid contract, although there is silence about the need for a legal relationship.
5. Another important aspect of the contract is of course. The Contract Agreement sets out the terms and conditions that must be clearly understood by both ABC Contracts Inc and Northern Inc.
6. The ability of a contract to have a legal capacity on either side of the contract is more than eighteen years, since the age of 18 years is specified as the age at which the contract is entered into.
Jamal is demonstrating howto build a game in scratch to several of his friends. for the purpose of his demonstration, he wants the backdrop to continuously keep changing. what type of loop will he need to create in order to do this?
a control loop
b master loop
c forever loop
d motion loop
A type of loop which Jamal will need to create in order to make the backdrop to continuously keep changing is: C. forever loop.
What is a forever loop?A forever loop can be defined as a type of loop which comprises a sequence of instructions that are written to run continuously or endlessly, until the simulation is quitted by an end user.
This ultimately implies that, a forever loop should be created by Jamal to make the backdrop to continuously keep changing.
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Answer: C
Explanation:
To any of you who are also taking Game Design, I have respect for you.
An automobile having a mass of 1100 kg initially moves along a level highway at 120 km/h relative to the highway. It then climbs a hill whose crest is 80 m above the level highway and parks at a rest area located there. Use a reference with kinetic and potential energy each equal to zero for the stationary highway before the hill. Let g = 9.81 m/s^2.
For the automobile, determine its change in kinetic energy and its change in potential energy, both in kJ. For the automobile, determine its change in kinetic energy, in kJ.
a. -8594
b. -663.1
c. -6.63x10^5
d. 663.1
Answer:
\(-6111.11\ \text{kJ}\)
\(863.28\ \text{kJ}\)
Explanation:
m = Mass of automobile = 1100 kg
v = Velocity of car = 120 km/h = \(\dfrac{120}{3.6}\ \text{m/s}\)
h = Height of hill = 80 m
g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)
Change in kinetic energy
\(KE=\dfrac{1}{2}m(u^2-v^2)\\\Rightarrow KE=\dfrac{1}{2}\times 1100\times (0-(\dfrac{120}{3.6})^2)\\\Rightarrow KE=-611111.11\ \text{J}\)
Change in kinetic energy is \(-6111.11\ \text{kJ}\)
Change in potential energy is given by
\(PE=mgh\\\Rightarrow PE=1100\times 9.81\times 80\\\Rightarrow PE=863280\ \text{J}\)
The change in potential energy is \(863.28\ \text{kJ}\).
Suppose that out of 500 lottery tickets sold, 200pay off at least the cost of the ticket. Now supposethat you buy 5 tickets. Find the probability that youwill win back at least the cost of 3 tickets.
The probability that one will win back at least the cost of three tickets is approximately 0.31744. This is solved using Binomial Distribution Model.
What is the Binomial Distribution Model?
The Binomial Distribution Model is a mathematical model of probability that allows one to decipher the probability of success of a group of possibilities within a range of specifically repeated processes.
What is the calculation for the above?Given that non-losing tickets (n) is: 5
Tickets gotten with non-losing probability p = 2/5 = 0.4
Note that probability here is given as:
Pr [X ≥ 3] = \(\sum_{x=3}^{5}.\)\(\binom{n}{x}\) pˣ (1-p)ⁿ⁻ˣ
→ \(\sum_{x=3}^{5}.\)\(\binom{n}{x}\) (0.4)ˣ (0.6)⁵⁻ˣ
= 992/3125
= 0.31744
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1. Looking at the case study provided under the Companion Material section, what is the main problem that is addressed in this case study? Maintenance workers painted over the pipes. Engineers lost all of their work because of the flood. The water pipes broke and flooded the space center. There was no paperwork for the maintenance work done on the pipes.
Incomplete question. However, I provided information that could assist you in identifying the main problem or issue addressed in any case study.
Explanation:
First, note that a case study is simply a learning aid that allows one to learn from a real-life scenario.
To determine the main problems of a case study one needs to:
Read the case as many times as possible to become familiar with the message been expressed. For example, by highlighting or underlining the most important facts it can help you to discover the main problem or issue. Check for any facts provided in the case study, by so doing you can identify the most important problems.Thus, by taking these few steps you may be able to determine the main problem in that case study.
What needs to be done before joining a fitting and pipe using socket fusion?
Before joining a fitting and pipe using socket fusion, it is important to ensure that both the fitting and pipe are clean and free from any debris or contaminants. Additionally, the correct size fitting and pipe must be used to ensure a proper fit.
Socket fusion is a method of joining plastic pipes and fittings together by heating the material and then pressing the heated ends together to form a strong bond. Before the socket fusion process begins, it is important to prepare both the fitting and pipe by ensuring they are clean and free from any debris or contaminants.
This can be achieved by using a specialized cleaning tool or wiping the surfaces with a clean cloth. Additionally, it is crucial to use the correct size fitting and pipe to ensure a proper fit and prevent any leaks or issues in the future. Proper preparation of the materials is crucial to ensuring a successful socket fusion joint.
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