30 g of copper pellets are removed from a 300°c oven and immediately dropped into 100 ml of water at 20°c in an insu- lated cup. what will the new water temperature be?

Answers

Answer 1

The new water temperature after dropping the copper pellets into the water will be approximately 28.3°C.

To find the new water temperature, we can use the formula Q = mcΔT, where Q is the heat transfer, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. For this problem, we need to consider the heat exchange between the copper pellets and water.

Copper specific heat capacity: 385 J/kg°C
Water specific heat capacity: 4,186 J/kg°C

First, convert the mass of copper pellets to kg:
30 g = 0.03 kg

Next, calculate the heat transfer for the copper pellets as they cool down:
Q_copper = m_copper * c_copper * ΔT_copper
Q_copper = 0.03 kg * 385 J/kg°C * (T_final - 300°C)

Now, calculate the heat transfer for the water as it heats up:
Q_water = m_water * c_water * ΔT_water
100 ml of water = 0.1 kg (assuming 1 g/ml density)
Q_water = 0.1 kg * 4,186 J/kg°C * (T_final - 20°C)

Since the heat transfer between copper and water is equal (Q_copper = Q_water):
0.03 kg * 385 J/kg°C * (T_final - 300°C) = 0.1 kg * 4,186 J/kg°C * (T_final - 20°C)

Now, solve for T_final:
T_final ≈ 28.3°C

So, the new water temperature will be approximately 28.3°C.

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Related Questions

A converging mirror with a focal length of 7cm is held 4cm from your face. Determine the image location?

Answers

The image is approximately 9.33 cm away from the mirror, on the object's side.

To determine the image location formed by a converging mirror, we can use the mirror equation:

1/f = 1/d_o + 1/d_i

where:

f is the focal length of the mirror,

d_o is the object distance (distance of the object from the mirror), and

d_i is the image distance (distance of the image from the mirror).

In this case, the focal length (f) is given as 7 cm, and the object distance (d_o) is 4 cm.

Plugging in the values into the mirror equation:

1/7 = 1/4 + 1/d_i

To find the image distance (d_i), we can solve for it:

1/d_i = 1/7 - 1/4

1/d_i = (4 - 7) / (4 * 7)

1/d_i = -3 / 28

Taking the reciprocal of both sides:

d_i = 28 / -3

d_i ≈ -9.33 cm

The negative sign indicates that the image formed by the converging mirror is virtual and located on the same side as the object.

Therefore, the image is approximately 9.33 cm away from the mirror, on the object's side.

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7. What force is required to accelerate a 100 kg car to 4 m/s27 F=ma
O A. 25N
B. 104N
C. 400N

Answers

Answer:

is the formula is F=MA so

F=100kg×4m/s=400n

so the answer is 400n

When my phone is plugged into a 120 Volt outlet, it takes 20 minutes to fully charge it with 32kJ of energy.
How much current if flowing through the charging cord?
A) 0.13 Amps
B) 0.22 Amps
C) 0.33 Amps
D) 0.64 Amps
E) 13 Amps
F) 22 Amps
G) 33 Amps
H) 64 Amps

There is only one answer, please help!​

Answers

The Current flowing in the charger is 0.22 Amps.

Energy consumed

The energy consumed by the phone is calculated using the following relationship.

E = IVt

where;

I is the current flowingV is the voltaget is the time

Current flowing in the charger

The Current flowing in the charger is calculated as follows;

\(I = \frac{E}{Vt} \\\\I = \frac{32,000}{120 \times (20 \times 60 )} \\\\I = 0.22 \ Amps\)

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What is the wavelength of a wave that has a frequency of 841 Hz if the speed of the wave is 457 m/s?

Answers

Answer:

The answer is 0.54 m

Explanation:

The wavelength of a wave can be found by using the formula

\( \lambda = \frac{c}{f} \\ \)

where

c is the velocity

f is the frequency

So we have

\( \lambda = \frac{457}{841} \\ = 0.543400713...\)

We have the final answer as

0.54 m

Hope this helps you

this is a continuation of the previous question. assume that capacitor c2 is chosen as 200 nf. what is the maximum value of capacitance c1( in nf)

Answers

The maximum value of capacitance C1, when capacitor C2 is chosen as 200 nF, is not constrained or limited, and it can be any value greater than or equal to zero in nanofarads (nF).

To determine the maximum value of capacitance (C1) when capacitor C2 is chosen as 200 nF, we need to consider the total equivalent capacitance in the circuit.

The given circuit diagram is not provided in the question, so I'll provide a general approach based on the assumption that capacitors C1 and C2 are connected in parallel.

When capacitors are connected in parallel, the total equivalent capacitance (C_eq) is calculated by summing the individual capacitance values:

C_eq = C1 + C2

Since C2 is given as 200 nF, we can express the equation as:

C_eq = C1 + 200 nF

However, the maximum value of C1 is not specified in the question. If we assume that there are no other constraints or limitations, we can simply state that the maximum value of C1 can be any value greater than or equal to zero.

Therefore, the maximum value of capacitance C1, when capacitor C2 is chosen as 200 nF, is not constrained or limited, and it can be any value greater than or equal to zero in nanofarads (nF).

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please help me!!!!!!!! it's due soon!!!!!!!!!!!!! NO LINK!!!!!!!!!

please help me!!!!!!!! it's due soon!!!!!!!!!!!!! NO LINK!!!!!!!!!

Answers

.75(m/s)^2


Use this picture
If you know the two on the bottom you multiply them but if you only know the top and one on the bottom you divide
please help me!!!!!!!! it's due soon!!!!!!!!!!!!! NO LINK!!!!!!!!!

A uniform rod with mass 6M and length 2L is rotating freely around an axis.
(1)
(2)
A) What is the angular velocity at position 1?
B) What is the velocity of the center of mass at position 2, given the angle theta relative to position 1?

Answers

(1) The angular velocity at position 1 of a uniform rod rotating freely around an axis can be determined.

(2) The velocity of the center of mass at position 2.

(1) To determine the angular velocity at position 1, we need to consider the conservation of angular momentum. Since the rod is rotating freely, there are no external torques acting on it.

The initial angular momentum is zero, and at position 1, the angular momentum is given by L = Iω, where I is the moment of inertia of the rod and ω is the angular velocity. By substituting the values of mass and length of the rod into the formula for moment of inertia, we can solve for ω.

(2) To calculate the velocity of the center of mass at position 2, relative to position 1 and at an angle theta, we can use the concept of angular velocity and linear velocity. The linear velocity of the center of mass is given by v = ωr, where ω is the angular velocity and r is the distance between the center of mass and the axis of rotation. By considering the given angle theta and the length of the rod, we can determine the distance r.

Substituting the value of ω calculated in part (1) into the formula, we can find the velocity of the center of mass at position 2, relative to position 1 and at angle theta.

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the elastic cords used for bungee jumping are designed to endure large strains. consider a bungee cord that stretches to a maximum length 3.51 times the original length. there are different ways to report this extensional deformation.

Answers

The ratio of (ε true/ε engr) = (1.2556/2.51) = 0.5002

So, the engineering strain is around 0.5002 bit wrong from the value of the true strain. This calculated value of difference is known as the extensional deformation.

For finding out the Engineering strain,

Engineering strain is a unit used to describe how much a material deforms when subjected to a specific force. It is equal to the amount of deformation divided by the material's initial length in the direction of the applied force.

⇒ε(engineering) = ΔL/L₀

⇒Lₓ= final length = 3.51 L₀

⇒L₀ = original length = L₀

⇒ΔL = Lₓ- L₀

        = 3.51 L₀ - L₀

        = 2.51 L₀

⇒ε(engineering) = ΔL/L₀

                            = (2.51L₀)/L₀  

                            = 2.51

For finding out the True Strain,

Deformation is measured by True Strain. It can be calculated by integrating the strain across short time intervals and adding them up. Hence,

⇒ε(true) = In (Lₓ/L₀)

⇒Lₓ = 3.51L₀

⇒L₀ = L₀

⇒ε(true) = In (Lₓ/L₀)

              = In (3.51L₀/L₀)

              = In 3.51

              = 1.2556

So, dividing both the values, we get

(ε true/ε engr) = (1.2556/2.51) = 0.5002

The complete question is as follows:

The elastic cords used for bungee jumping are designed to endure large strains. Consider a bungee cord that stretches to a maximum length 3.51 times the original length. There are different ways to report this extensional deformation. Calculate how wrong' the engineering strain is compared to the true strain by evaluating the ratio: ε true/ε engr

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Which of the following scenarios would result in an increase of kinetic
energy?*

A) An object at rest at a height of 10 meters
B) A car accelerating from 10 m/s to 20 m/s
C) A car coming to a stop

Answers

B) car accelerating from 10 to 20

Answer:

B) A car accelerating from 10 m/s to 20 m/s

Explanation:

I explained this yesterday.

help me with Physics. please


On Saturn, the acceleration due to gravity is 11.08 m/s². On Venus, the acceleration due to gravity is 8.87 m/s². For an alien traveling to both planets, which answer is true?

A. On Venus, the alien would have less mass because the gravity is lower on Venus than on Earth.

B. On Venus, the alien would have more mass because the gravity is lower on Venus than on Earth.

C. On Saturn, the alien would weigh than on Earth because the gravity is higher on Saturn than on Earth.

D. On Saturn, the alien would weight less than on Earth because the gravity is higher on Saturn than on Earth.

help me with Physics. pleaseOn Saturn, the acceleration due to gravity is 11.08 m/s. On Venus, the acceleration

Answers

Considering the difference between mass and weight, On Saturn, the alien would weigh higher than on Earth because the gravity is higher on Saturn than on Earth.

Difference between mass and weight

Mass is the amount of matter that a body contains. That is, mass is a measure of the amount of matter that the body possesses.

Weight is the action exerted by the force of gravity on the body; that is, it is a measure of the force that is caused on said body by the gravitational field. The weight is calculated by:

P= m×g

where

P = weight, in Newtons (N)m = mass, in kilograms (kg)g = gravitational constant, in (m/s²)

The mass of an object will always be the same, no matter where it is located. Instead, the weight of the object will vary according to the force of gravity acting on it.

Statement correct

Considering the difference between mass and weight, the definition of weight, and that gravity on Earth has a value of 9.8 m/s², the correct answer is option C.) On Saturn, the alien would weigh higher than on Earth because the gravity is higher on Saturn than on Earth.

This can be seen in the expression for the weight calculation. Since the mass is the same both on Earth and on Saturn, if the gravity of the latter is greater, the product of mass with gravity must be greater.

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) now you will start taking data with the magnetometer. select the magnetometer sensor and start recording data. un-check the bx and bz boxes so that only the by trace is being displayed on the chart. stand several feet away from anything metallic or magnetic and point the y-axis of the iolab in different directions (forward, backward, up, down, left, right, etc) and find the orientation of your iolab for which its measurement of by has the biggest value. what does this tell you about the direction of the earths magnetic field in your location?

Answers

It shows that the orientation of the iolab that gives the largest "by" reading corresponds to the direction of the Earth's magnetic field in your location.

How to explain the information

A magnetometer is a device that measures magnetic fields. It can be used to detect the Earth's magnetic field, which is generated by the motion of molten iron in the Earth's core. The Earth's magnetic field is a vector field, which means that it has both magnitude and direction.

When you stand several feet away from anything metallic or magnetic and point the y-axis of the iolab in different directions, you are essentially changing the orientation of the magnetometer sensor relative to the Earth's magnetic field. The sensor measures the strength of the magnetic field component in the direction of the sensor. In this case, you are only measuring the "by" component of the magnetic field, which is the component of the field that is perpendicular to the surface of the Earth.

By finding the orientation of the iolab for which its measurement of "by" has the biggest value, you are essentially finding the direction of the Earth's magnetic field in your location. The direction of the Earth's magnetic field at any point on the Earth's surface is not constant, and it varies with location. However, in general, the direction of the Earth's magnetic field at any point on the Earth's surface is roughly parallel to the surface of the Earth and points towards the geographic North Pole.

Therefore, the orientation of the iolab that gives the largest "by" reading corresponds to the direction of the Earth's magnetic field in your location.

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) now you will start taking data with the magnetometer. select the magnetometer sensor and start recording

Learning Goal: To understand that centripetal acceleration is the acceleration that causes motion in a circle. Acceleration is the time derivative of velocity. Because velocity is a vector, it can change in two ways: the length (magnitude) can change and/or the direction can change. The latter type of change has a special name, the centripetal acceleration. In this problem we consider a mass moving in a circle of radius R with angular velocity ω, r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^] =Rcos(ωt)i^+Rsin(ωt)j^. The main point of the problem is to compute the acceleration using geometric arguments. (Figure 1) Part A What is the velocity of the mass at a time t? You can work this out geometrically with the help of the hints, or by differentiating the expression for r⃗ (t) given in the introduction. (Figure 2) Express this velocity in terms of R, ω, t, and the unit vectors i^ and j^. V⃗ (t) = Part Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it crosses the positive x axis, an instant that corresponds to t=0. [Notice that when t=0, r⃗ (t=0)=Ri^. ] For the remainder of this problem, assume that the time t is measured from the moment you start timing the motion. Then the time − t refers to the moment a time t before you start your stopwatch. Part B What is the velocity of the mass at a time − t? Express this velocity in terms of R, ω, t, and the unit vectors i^ and j^. V⃗ (−t) = SubmitMy AnswersGive Up Part C What is the average acceleration of the mass during the time interval from − t to t? (Figure 3) Express this acceleration in terms of R, ω, t, and the unit vectors i^ and j^.

Answers

Part A :The position of the particle in vector form is given by\(r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^]\)where R is the radius of the circle and ω is the angular velocity.The velocity of the particle is given by taking the derivative of the position vector with respect to time.

Taking derivative with respect to time on both side we get \(v⃗ (t)=d/dt R[cos(ωt)i^+sin(ωt)j^]= R[-in(ωt)ωi^+cos(ωt)ωj^]=ωR[-sin(ωt)i^+cos(ωt)j^]v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\)Thus the velocity of the mass at a time t is given by \(v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\).

Part B :

We have to find the velocity at time -t. The velocity of the particle is given by taking the derivative of the position vector with respect to time. Thus the velocity of the mass at a time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)

\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)Part C :

The average acceleration of the particle can be computed using the formulaa = \(Δv/Δt\)The velocity at time t is given by\(v⃗ (t) = ωR[-sin(ωt)i^+cos(ωt)j^]\)

The velocity at time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)

\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)The change in velocity over the interval from -t to t is therefore

\(Δv = v(t) - v(-t) = 2ωR[sin(ωt)i^ + cos(ωt)j^]\)

The time interval over which this change occurs is\(Δt = 2t\)Thus the average acceleration of the particle is given by a = \(Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)

\(a = Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)

The acceleration can be expressed in terms of R, ω, t, and the unit vectors \(i^ and j^\) as \(a = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\).

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The conventional system of signs that indicate relative durations of long and short sounds is called.

Answers

Musical notation is the term used to describe the common system of signs used to denote the relative duration of long and short sounds.

What is a musical notation?

Music notation, often known as musical notation, is any technique used to graphically express audibly perceived music performed with instruments or sung by a human voice using written, printed, or other symbol-based representations. This includes notation for periods of silence like rests.

Throughout history, many civilizations have used different types of notation, and the knowledge of early musical notation is generally sparse. Different musical genres and cultural groups employ various methods of music notation, even during the same time period, such as the 2010s. For instance, while sheet music with staves and note-heads is the most popular method for professional classical musicians, the Nashville Number System is the main method used by professional country music session musicians.

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overall the human leverage system is built for speed and range of movement at the expense of force generation. true false

Answers

The statement is true that overall the human leverage system is built for speed and range of movement at the expense of force generation.

What does the human body's lever system entail?

The bodily pieces that act as levers to enable human movement are bones, ligaments, and muscles. To put it more simply, a joint—where two or more bones come together and form the axis (or fulcrum), and the muscles that crossed the joint exert the force sufficient to move a weight or resistance.

The human arm is what kind of a lever?

There are hundreds of third-class levers in the human body. The arm serves as one of the most set of features for this. To exercising those powers held in the hand, the elbow serves as the fulcrum, the biceps brachii as the effort, and the forearm as the beam.

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Below is a nuclear equation. What number should go in the place marked (i)?

Below is a nuclear equation. What number should go in the place marked (i)?

Answers

The nuclear reaction becomes:

U₉₂²³⁸ → Th₉₀²³⁴+ α⁴₂

Thus, here (i) 234 and (ii) 90

What is alpha-decay?

Uranium-238 decays to thorium-234 via alpha decay. (The numbers after the chemical names indicate the number of protons and neutrons.) Uranium-238 loses two protons and two neutrons in this process, forming the isotope thorium-234.

Reactors based on thorium are safer since the reaction is simple to stop and does not need to be carried out under intense pressure. When compared to uranium reactors, thorium reactors produce significantly less waste, and the waste produced is far less radioactive and far shorter in duration.

Now, here (i) 234 and (ii) 90

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Answer:

(i) 234 and (ii) 90

a 11 kg block slides up a hill to a height of 6.4 m. if 432 j of thermal energy are generated, how fast was the block going at the bottom of the hill?

Answers

The block was going 8.12 m/s at the bottom of the hill.

To find this, we can use the conservation of energy equation:
Initial kinetic energy + initial potential energy + work done by non-conservative forces = final kinetic energy + final potential energy

In this case, the initial potential energy is 0 (since the block is at the bottom of the hill), the final kinetic energy is 0 (since the block comes to a stop at the top of the hill), and the work done by non-conservative forces is -432 J (since this is the amount of thermal energy generated).

So the equation becomes:
Initial kinetic energy + 0 + (-432 J) = 0 + final potential energy

We can find the final potential energy by using the equation for gravitational potential energy:
PE = mgh
= (11 kg)(9.8 m/s^2)(6.4 m)
= 696.96 J

So now we can plug this into the conservation of energy equation:
Initial kinetic energy + 0 + (-432 J) = 0 + 696.96 J

Solving for the initial kinetic energy:
Initial kinetic energy = 1128.96 J

And finally, we can use the equation for kinetic energy to find the initial velocity of the block:
KE = 0.5mv^2
1128.96 J = 0.5(11 kg)v^2

Solving for v:
v = 8.12 m/s

So the block was going 8.12 m/s at the bottom of the hill.

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One important concept in quantum mechanics is known as the correspondence principle. This idea states that as the energy increases, the behavior of a quantum mechanical system must approach the classical limit. For the particle in a box, the energy goes as the square of the quantum number, meaning that the spacing between adjacent levels increases with increasing n.

Show that the correspondence principle holds for the particle in a box by considering the ratio of the spacing between adjacent levels to the energy of the lower state.

Answers

The correspondence principle holds for the particle in a box, as the ratio of the spacing between adjacent levels to the energy of the lower state approaches zero with increasing energy.

In the particle in a box system, the energy levels are given by the equation:

\(E = (n^2 * h^2)/(8 * m * L^2)\)

where n is the quantum number, h is the Planck's constant, m is the mass of the particle, and L is the length of the box.

To examine the correspondence principle, let's consider the spacing between adjacent energy levels. The difference in energy between two adjacent levels can be calculated by subtracting the energy of one level from the energy of the next level:

ΔE = E(n+1) - E(n)

\(= [(n+1)^2 * h^2)/(8 * m * L^2)] - [(n^2 * h^2)/(8 * m * L^2)]\)

\(= [2n + 1] * (h^2/(8 * m * L^2))\)

Now, let's calculate the ratio of the spacing between adjacent levels to the energy of the lower state:

Δ\(E/E(n) = ([2n + 1] * (h^2/(8 * m * L^2))) / [(n^2 * h^2)/(8 * m * L^2)]\)

\(= (2n + 1) / n^2\)

As n increases, the spacing between adjacent levels (ΔE) will increase. However, the ratio ΔE/E(n) can be simplified to \((2/n) + (1/n^2),\)which approaches zero as n increases. This means that as the energy increases (as n increases), the ratio ΔE/E(n) approaches zero, indicating that the behavior of the particle in a box system converges to the classical limit.

Therefore, we have shown that the correspondence principle holds for the particle in a box, as the ratio of the spacing between adjacent levels to the energy of the lower state approaches zero with increasing energy.

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verify that is an eigenfunction of ~p and l :op with the appropriate eigenvalues.

Answers

The given function needs to be operated on by the momentum operator (~p) and the angular momentum operator (l:op) to verify if it is an eigenfunction of both operators with the appropriate eigenvalues.

When a function is an eigenfunction of an operator, it means that applying the operator to the function results in the same function multiplied by a constant (the eigenvalue).

By following the steps above and verifying that the momentum and angular momentum operators result in the eigenfunction multiplied by their respective eigenvalues, you can confirm that the function is an eigenfunction of both operators.

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Tap the point on this graph where the ball has the greatest Kinetic Energy if it were to move from Point A to G. Target Image

Answers

I don't understand the question

Answer:

As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy, at E. 19.

Explanation:

A yoyo can be approximated as a solid cylinder of mass m, radius R and thickness d. Two identical such yoyos have their strings tied together and are wound so that the two yoyos are touching each other. These stuck together yoyos are ejected into deep space far from any other objects. Shortly after being ejected, the center of mass of the yoyos have an initial velocity ū as indicated in the diagram. At this instant, the stuck together yoyos are rotating about the center of mass counterclockwise with an angular speed Wil. As the yoyos fly through space the strings unwind so that at some later time all of the string has unwound from each yoyo. At this time, the velocity of the center of mass is ū and the distance between the center of the yoyos is d. Determine the unknown angular velocity (magnitude and direction) of the center of mass for the tied together yoyos. You can neglect the mass of the string and you can assume that the yoyos are tied to the string so that the string is not slipping on the axle of the yoyo

Answers

Answer:

I don't understand what your asking

Explanation:

I really don't know

1)A 25 kg air compressor is dragged up a rough incline from r⃗ 1=(1.3ı^+1.3ȷ^)m to r⃗ 2=(8.3ı^+2.6ȷ^)m, where the y-axis is vertical. How much work does gravity do on the compressor during this displacement?
2)A 25 kg box sliding to the left across a horizontal surface is brought to a halt in a distance of 55 cm by a horizontal rope pulling to the right with 16 N tension.How much work is done by tension?How much work is done by gravity?

Answers

As for the work done by gravity, in this case, it is zero because the box is sliding horizontally on a horizontal surface, and gravity does not do any work in this direction. Therefore, the total work done by tension is 8.8 Joules.

What is the work done by gravity?

To calculate the work done by gravity on the air compressor during its displacement up the incline, we need to determine the change in gravitational potential energy.

The gravitational potential energy (PE) of an object is given by the equation  \(PE = mgh\), where m is the mass of the object, g is the acceleration due to gravity, and h is the change in height.

Given:

Mass of the air compressor, \(m = 25 kg\)

Acceleration due to gravity, \(g = 9.8 m/s^2\)  (assuming Earth's gravity)

Initial position, \(r⃗ = (1.3ı^ + 1.3ȷ^) m\)

Final position, r⃗\(2 = (8.3ı^ + 2.6ȷ^) m\)

Change in height, h = Final y-coordinate - Initial y-coordinate \(= y2 - y1 = 2.6 m - 1.3 m = 1.3 m\)

Therefore, the work done by gravity on the air compressor is:

\(W = \Delta PE = mgΔh = 25 kg * 9.8 m/s^2 * 1.3 m = 318.5 J\) (rounded to one decimal place)

So, the work done by gravity on the air compressor during its displacement up the incline is approximately 318.5 Joules.

The work done by tension can be calculated using the equation \(W = Fd\), where F is the force applied and d is the displacement.

Given:

Tension force,  \(F = 16 N\) (in the opposite direction of displacement)

Displacement, \(d = 55 cm = 0.55 m\)

Therefore, the work done by tension is:

\(W = Fd = 16 N \times 0.55 m = 8.8 J\)

Therefore, As for the work done by gravity, in this case, it is zero because the box is sliding horizontally on a horizontal surface, and gravity does not do any work in this direction.  the work done by tension is  \(8.8\) Joules.

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PLEASE ONLY A B C OR D || During an experiment, your teacher gives you two objects: tissue paper and a balloon. You observe that the tissue paper repels the balloon. What does this most likely tell you about the charges of the two objects?

a.Both objects have negative charges.
b.The tissue has a positive charge, and the balloon has a negative charge.
c. The tissue has a negative charge, and the balloon has a positive charge.
d.The objects have no interactive with each other.

Answers

c. The tissue has a negative charge, and the balloon has a positive charge.

The balloon is repelled by the tissue paper, why?

Due to the opposing charges of both things, the tissue paper repels the balloon. In this instance, it is likely that the balloon has a positive charge whereas the tissue paper has a negative charge. While like charges repel one another, opposite charges attract.

The balloon is repelled by the tissue paper, so what can we assume about the charges of the two items from this observation?

The fact that the balloon is repelled by the tissue paper leads us to conclude that both items have opposing charges. The tissue paper has a negative charge, but the balloon is most likely to have a positive charge.

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600-nm light is incident on a diffraction grating with a ruling separation of 1. 7 10–6 m. the second order line occurs at a diffraction angle of:_____.

Answers

The diffraction angle is 20.66 degrees.

To find the answer, we have to know about the Bragg's law.

How to find the diffraction angle?We have expression of Bragg's law as,

                         \(2dsin\theta=n \lambda\)

where; d is the separation of the rulings, \(\theta\) is the diffraction angle, n is the order of diffraction and lambda is the wavelength.

Thus, the diffraction angle can be found by substituting values in the equation.

                     \(sin\theta=\frac{n\lambda}{2d} =\frac{2*600*10^{-9}}{2*1.7*10^{-6}} \\\\sin\theta=0.352\\\\\theta=sin^{-1}(0.352)=20.66 degree\)

Thus, we can conclude that, the diffraction angle is 20.66 degrees.

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Match the definition with the appropriate word.
temperature
part of internal energy that can be
transferred
heat
measure of the average kinetic energy of a
substance
thermal energy
total potential and kinetic energies of the
particles in a substance
internal energy
thermal energy that flows from one
substance to another

Answers

Answer:

Temperature: measure of the average kinetic energy of a substance

Internal energy: total potential and kinetic energies of the particles in a substance

Heat: thermal energy that flows from one substance to another

Thermal energy: part of internal energy that can be transferred

Explanation:

Proof for correct answers on edge :)

Match the definition with the appropriate word.temperaturepart of internal energy that can betransferredheatmeasure

what does the values 0.5 for the wave

Answers

Answer:

1 mm = 0.1 mV; 5 mm = 0.5 mV (or between 2 dark horizontal lines); 10 mm = 1.0 mV. Heart rate ... QRS complex is a series of wave forms following P wave.

Explanation:

Hoped I helped

This is for Earth Space Science

One of the major events that contributed to Snowball Earth was the series of large volcanic eruptions that occurred 700 million years ago in what is now Canada. These eruptions caused ⎽⎽⎽(blank)⎽⎽⎽⎽⎽ particles to get trapped in the atmosphere. The particles blocked incoming solar radiation, which had a strong ⎽⎽⎽(blank)⎽⎽⎽ effect on the planet.
1. carbon dioxide; warming
2. sulfur gas; warming
3. sulfur gas; cooling
4. carbon dioxide; cooling

Answers

The words that complete the blanks are; carbon dioxide; warming. Option 1

What is volcanic eruption?

The term volcanic eruption has to do with a situation in which molten magma suddenly bursts out of the earth and may solidify to give rise to the emergence of rocks. We know that rocks are the solid parts of the earth hat may occur above or below the earth's crust. During a large volcanic event. It is common that carbon dioxide is evolved into the atmosphere.

To complete the sentence; One of the major events that contributed to Snowball Earth was the series of large volcanic eruptions that occurred 700 million years ago in what is now Canada. These eruptions caused carbon dioxide particles to get trapped in the atmosphere. The particles blocked incoming solar radiation, which had a strong  warming effect on the planet.

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A 20N bucket is accelerated upward out of a well, by a rope with a force of 75N. What is the acceleration of the bucket

Answers

Answer:

36.76m/s²

Explanation:

Given

Weight of the bucket = 20N

Mass = Weight/acceleration due to gravity

Mass = 20/9.8

Mass = 2.04kg

Applied force = 75N

Get the acceleration

According to Newton's second law:

F = ma

a = F/m

a = 75/2.04

a = 36.76m/s²

Hence the acceleration of the bucket is 36.76m/s²

A car moving at a speed of 20m/s has a kinetic energy of 300,000 J what’s the cars mass

Answers

Answer:

1500 kg

Explanation:

The mass of the car can be found by using the formula

\(m = \frac{2k}{ {v}^{2} } \\ \)

From the question we have

\(m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ \)

We have the final answer as

1500 kg

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The dimensions of a room are 16.40 m long, 4.5 m wide and 3.26 m high. What is the volume of the room in cubic meters? Express your answer in scientific notation

Answers

Answer:

\(V=2.4\times 10^2\ \text{m}^3\)

Explanation:

Given that,

The dimensions of a room are 16.40 m long, 4.5 m wide and 3.26 m high.

We need to find the volume of the room.

The room in the shape of cuboid whose volume is given by :

\(V=L\times B\times H\)

L,B,H are length, breadth and height of the room

So,

\(V=16.4\times 4.5\times 3.26\\\\V=240.588\ \text{m}^3\\\\\text{In scientific notation}\\\\V=2.4\times 10^2\ \text{m}^3\)

Hence, the volume of the room is \(2.4\times 10^2\ \text{m}^3\)

How many minutes are in 2 1
4 hours?​

Answers

Answer:

If you are meaning to say 214 the answer is 12840 minutes

Explanation:

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