5) Are the statements below correct? 1. Considering two different ways in the figure to push two identical heavy boxes to move at a constant speed, cases a) and b) are the same strenuous because they have the same kinetic friction. b) 2. If a round object undergoes pure rolling downhill on an inclined plane, the gravitational force exerts zero torque on the object. 3. If a round object undergoes pure rolling downhill on an inclined plane, the friction force tends to de-accelerate the rotational motion of the object. 4. With the presence of kinetic friction, a brick pulled by gravity can no longer slide down an inclined plane at a constant acceleration. 6) Consider a pure-rolling race where two objects are simultaneously released from the top of an inclined plane and roll down to a finish line. For each group below, answer which object will win the race or it will be a tie (I or Il or Tie). 1. I: 100 g solid cylinder with R = 10cm vs II: 200 g solid cylinder with R = 10cm. 2. 1: 100 g solid cylinder with R = 10cm vs II: 100 g solid cylinder with R = 20cm. 3. I: 100 g solid cylinder with R = 10cm vs II: 100 g hollow cylinder with R = 10cm. 4. I: 100 g solid cylinder with R = 10cm vs II: 100 g solid sphere with R = 10cm.

Answer:

Points R(4,1) S(7,3) T(6,4) after translation

R(4-3, 1) S(7-3, 3) T(6-3, 4)

R'(1, 1) S'(4, 3) T'(3, 4)

Points R'(1, 1) S'(4, 3) T'(3, 4) after reflection

R''(1, -3) S''(4, -5) T''(3, -6)

Step-by-step explanation:

Answer:Step-by-step explanation:Points R(4,1) S(7,3) T(6,4) after translation R(4-3, 1) S(7-3, 3) T(6-3, 4) R'(1, 1) S'(4, 3) T'(3, 4) Points R'(1, 1) ...

When we try to convert the value of one kilo meter to feet, the value that we obtain is 3280.8 ft.

We know that there are several units that we could use for calculations. t is often common that we need to convert the units from one unit to the other so that we can be able to carry out calculations. The number that allows us to be able to carry out such a a conversion is what we call the conversion factor for that particular operation.

Given that;

1 foot = 0.0003048 kilo meter

We can see that if we seek to convert a value of One km to feet we would have 3280.8 ft

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The break-even point is 1100 products sold. This means that if the store can sell 1100 products, it will be able to cover its costs and make a profit.

What is average ?

The average is a measure of central tendency that is calculated by adding a set of values together and dividing the sum by the number of values. It is also known as the arithmetic mean. It is a way to represent a typical value of a dataset.

The break-even point is the point at which the cost of the products equals the revenue from the sales of the products. To find the break-even point, we need to set the cost function (C(x) = 550 + 3.00x) equal to the revenue function (R(x) = 5.50x) and solve for x.

C(x) = 550 + 3.00x = R(x) = 5.50x

3.00x = 5.50x - 550

0.50x = 550

x = 1100

So the break-even point is 1100 products sold. This means that if the store can sell 1100 products, it will be able to cover its costs and make a profit.

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The process of dividing a data set into a training, a validation, and an optimal test data set is called data partitioning.

Data partitioning is the process of dividing a dataset into separate subsets that are used for different purposes, such as training a model, validating its performance, and testing it on new data.

The most common way to partition a dataset is into three subsets: a training set, a validation set, and a test set. The training set is used to train a model, the validation set is used to tune the model's hyperparameters and assess its performance during training, and the test set is used to evaluate the final performance of the model on new, unseen data.

Data partitioning helps to prevent overfitting by providing a way to evaluate a model's performance on data that it has not seen during training.

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Answer:

2x + 2

Step-by-step explanation:

Combine all the like terms:

-5x + 7x -12 + 14 = 2x + 2

Answer:

2x + 2

Step-by-step explanation:

(- 5x - 12) + (14 + 7x) ← remove parenthesis

= - 5x - 12 + 14 + 7x ← collect like terms

= (- 5x + 7x) + (- 12 + 14)

= 2x + 2

The magnitude of the sum of these two vectors is approximately 11.791 units.

In this question we have the representations of two vectors on a Cartesian plane, of which we must find the magnitude of the two vectors. There are different methods to find it, we decide to use a vectorial method. First, sum the two vectors:

R(x, y) = A(x, y) + B(x, y)

R(x, y) = 7.70 · (cos 27.8°, sin 27.8°) + 16.3 · (- sin 20°, - cos 20°)

R(x, y) = (6.811, 3.591) + (- 5.574, - 15.317)

R(x, y) = (1.237, - 11.726)

Second, use the Pythagorean theorem:

R = √[1.237² + (- 11.726)²]

R ≈ 11.791

The magnitude of the sum of these two vectors is approximately 11.791 meters.

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Lets set up the equation:

p + w = 327  -- equation 1

p - w = 289 -- equation 2

equation 1 + equation 2

2p = 616

p = 308

Thus the plane flies at 308 mph without the wind.

Hope that helps!

The word "bookkeeper" contains 10 letters in total, with the following breakdown:

'o' appears 2 times

'k' appears 2 times

'e' appears 3 times

'b' appears 1 time

'p' appears 1 time

'r' appears 1 time

To calculate the number of distinct permutations, we can apply the concept of permutations with repetition. The formula is:

N! / (n1! * n2! * n3! * ... * nk!)

Where:

N is the total number of objects (letters in this case)

n1, n2, n3, ..., nk are the frequencies of each letter (repetitions)

Plugging in the values, we have:

10! / (2! * 2! * 3! * 1! * 1! * 1!)

Simplifying further:

10! / (4 * 6 * 1 * 1)

Calculating:

(10 * 9 * 8 * 7 * 6!) / (4 * 6)

= (10 * 9 * 8 * 7) / 4

= 10 * 9 * 8 * 7 / 4

= 10 * 9 * 2 * 7

= 1,260

Therefore, there are 1,260 distinct permutations that can be formed using the letters of the word "bookkeeper."

There are 3,628,800 distinct permutations of the letters in the word "bookkeeper." The word "bookkeeper" has 10 letters in total. By calculating the number of distinct permutations, we can determine the different ways these letters can be arranged.

To find the number of distinct permutations of the word "bookkeeper," we need to consider that it has repeating letters. In this case, we have:

- 1 'b'

- 2 'o's

- 3 'k's

- 2 'e's

- 1 'p'

- 1 'r'

The total number of distinct permutations can be calculated using the formula for permutations of objects with repetition.

The formula is:

n!/ (n1! * n2! * n3! * ... * nk!)

Where n is the total number of objects and n1, n2, n3, ..., nk are the number of repetitions for each distinct object.

Applying this formula to the word "bookkeeper," we get:

10! / (1! * 2! * 3! * 2! * 1! * 1!)

Calculating this expression, we find that there are 3,628,800 distinct permutations of the letters in the word "bookkeeper." Each of these permutations represents a unique arrangement of the letters.

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The estimated distance between the park and your school is 5 miles.

Here,

To estimate the distance between the park and your school, we can use the Pythagorean theorem, as the distance forms a right-angled triangle with the school, apartment, and park as its vertices.

Let's label the points as follows:

S = School

A = Apartment

P = Park

Given:

School (S) is 4 miles east and 1 mile south of the apartment (A).

Park (P) is 3 miles east and 4 miles south of the apartment (A).

Now, we have two right-angled triangles:

The triangle formed by S, A, and P. This is the triangle for which we want to estimate the distance between the school and the park.

The triangle formed by A, S, and P.

Since both triangles share the side AS (4 miles east), we can use the Pythagorean theorem for the triangle ASP to find the distance between the school and the park.

The Pythagorean theorem states that for a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, let's represent the distance between the school and the park as d (the hypotenuse), and the other two sides as 3 miles (east) and 4 miles (south).

Using the Pythagorean theorem:

\(d^2 = 3^2 + 4^2\\d^2 = 9 + 16\\d^2 = 25\\\)

Now, take the square root of both sides to find d:

d = √25

d = 5

So, the estimated distance between the park and your school is 5 miles.

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Exponential model representing the amount of Iodine-125 remaining in the tumor after t days is f(t) = 0.5 *\(e^{-0.0115t}\) and number grams of Iodine-125 after 60 days is 0.2507 grams

Given:

A tumor is injected with 0.5 grams of Iodine-125, which has a decay rate of 1.15% per day.

The formula for exponential decay is f(t)=a*e^kt where a is the original amount of the substance, k is the decay rate and t is the time elapsed. You are given the decay rate of 1.15% or -0.0115. For this problem t is left as is since we are creating a function of time.

f(t) = 0.5 *\(e^{-0.0115t}\)

After 60 days

= 0.5 * \(e^{-0.0115*60}\)

= 0.5*e^-0.69

= 0.5*0.50157

f(t) = 0.2507 grams

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If 32,000,000 acres in Texas are cropland and 40 percent of that cropland is considered highly erodible, then 12,800,000 acres are highly erodible.

To calculate this, you simply need to find the percentage of the total cropland that is highly erodible. In this case, 40 percent of the 32,000,000 acres of cropland in Texas is considered highly erodible. To find this amount, you can multiply the total acres of cropland (32,000,000) by the percentage (40 percent, or 0.4 as a decimal). The calculation is as follows:

32,000,000 acres * 0.4 = 12,800,000 acres

Therefore, 12,800,000 acres of the total cropland in Texas are highly erodible. This information is important for understanding the potential impacts of soil erosion on agricultural productivity and developing effective conservation measures to protect valuable land resources.

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So the final expression is: (change in y/y) = n (change in a/a).

We can start by taking the natural logarithm of both sides of the equation:

ln(y) = ln(aⁿ)

Using the rule that ln(aⁿ) = n ln(a), we can simplify this to:

ln(y) = n ln(a)

Next, we can take the derivative of both sides with respect to a:

d/d(a) ln(y) = d/d(a) (n ln(a))

Using the chain rule, we can simplify the right-hand side to:

d/d(a) ln(y) = n (1/a)

Now, we can multiply both sides by a/y:

a/y * d/d(a) y = n(a/y) * (1/a)

Simplifying, we get:

dy/y = n da/a

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Step-by-step explanation:

2 1/3

=2*3+1/3

=7/3

Answer:

28 cm and 12 cm

Step-by-step explanation:

I didn't use math for this one I just used logic lol

Multiply 7 by 4 and 3 by 4, you get 28 and 12, 28+12=40

The total possible ways of arranging 30 students in two groups of sizes 4 and 6 respectively are 6309453150, which is obtained by using the prerequisite knowledge of combinations.

What is the combination?

A combination is a mathematical procedure that deduces the number of feasible selections in a collection of articles in which the order of the selection does not matter. In combinations, you can choose any items in any order. Its formula is given by C(n,r) = n! / (n - r)! r!)

Calculation of the total possible ways of arranging two focus groups of students with sizes 4 and 6 respectively

Given a group of 30 students

Two focus groups are to be arranged in sizes 4 and 6 respectively

Total number of possible ways to arrange the two focus groups = C(30,4) × C(26,6)

Using the formula for combination, we get,

T.F.O = [30! / (26! 4!)] × [26! / (20! 6!)]

T.F.O = 27405 × 230230

         = 6309453150

Hence, the required possible ways to arrange two groups are given by 6309453150.

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Answer:

-44

Step-by-step explanation:

Answer:

use a calculator that should help u so much

Answer:

C!

Step-by-step explanation:

Answer:

9.99  +  1.29n  ≤ 50

Step-by-step explanation:

Answer:

55 ÷ 11 +5 × 19 × 2 =195

If you take turns in filling each gap then at one point you can get the answers.

Brainliest pls if it is correct! And hope it helps!

Answer:

42 i think

Step-by-step explanation:

Answer:

42

Step-by-step explanation:

ΔPSE + GPST

(7 x 2) / 2 + (5 x 7) = 7 + 35 = 42

The number 713.49 is already written in standard form.

Standard form, also known as standard notation or scientific notation, is a way of writing numbers using digits and decimal places. In standard form, a number is written with one digit to the left of the decimal point and the remaining digits to the right of the decimal point.

For example, the number 7,134.9 would be written in standard form as 7,134.9. The number 713.49 is already written in this format, so there is no need to convert it to standard form.

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x/2, which is a contradiction. So, the statement is true.Let x = 1,

then x² + x + 41 = 43

which is a prime.

If we take x = 2,

then x² + x + 41 = 47

which is also a prime. But,

when x = 40,

then x² + x + 41 = 1681

which is not a prime.

So, the statement is false.

b) ∀x∃y(x + y = 0). For every x,

there exists y = -x,

such that x + y =

x - x = 0.

So, the statement is true.

c) Let x = 2,

y = 1.

Then x > 1 and y > 0,

but  \(y^x = 1^2\)

= 1 ≤ x.

So, the statement is false.

d) Let a = 6,

b = 3,

c = 4.

Then a divides bc, but a does not divide b or a does not divide c. So, the statement is false.

e) Let a = 2,

b = 5,

c = 3, and

d = 1.

Then a divides (b-c) and a divides (c-d), but a does not divide (b-d). So, the statement is false.

f) x² - x ≥ 0 can be written as x(x-1) ≥ 0. If x > 1,

then both x and x-1 are positive and hence their product is positive.

If 0 ≤ x < 1, then x is positive and x-1 is negative, so their product is negative.

But, the statement is true only for positive real numbers. So, the statement is true.

g) Subtracting x+1 on both sides, 2x - (x+1) > 0 or x > 1. So,

the statement is true only for x > 1.

h) For any positive real number x, choose y = x/2.

Then for any positive real number z, yz ≥ z.

So, the statement is true.

i) For any positive real number x,

choose y = x/2.

Then if y < x, 0 < x-y < x.

If y > x,

then y > x/2 > x-x/2

= x/2,

which is a contradiction. So, the statement is true.

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The value of q in the question is q>-12/15

In mathematics, an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions

The given inequality is 5(p−3q)<12

Opening the bracket we have

5p - 15q < 12

The solution can only be gotten if we assume p = 0

the substitute p=0 in the inequality to have

-15q < 12

dividing both sides by -15 to have

-15q/-15 < 12/-15

therefore q > 12/-15

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Answer:

\(\displaystyle h'(0) = -5\)

Step-by-step explanation:

We are given the function:

\(\displaystyle h(x) = 3f(x) -2g(x) - 5\cos x - 3\)

And that f'(0) = 3 and g'(0) = 7.

And we want to determine the value of h'(0).

Find h'(x). We can take the derivative of both sides:

\(\displaystyle h'(x) = \frac{d}{dx}\left[ 3f(x) - 2g(x) - 5\cos x - 3\right]\)

Expand and simplify:

\(\begin{aligned}\displaystyle h'(x) & = \frac{d}{dx}\left[ 3f(x) - 2g(x) - 5\cos x - 3\right] \\ \\ & = \frac{d}{dx}[3f(x)] + \frac{d}{dx}[-2g(x)] + \frac{d}{dx}[-5\cos x] + \frac{d}{dx}[-3]\\ \\ & = 3f'(x) -2g'(x) +5\sin x\end{aligned}\)

Therefore:

\(\displaystyle h'(0) = 3f'(0) -2 g'(0) + 5 \sin (0)\)

Substitute and evaluate:

\(\displaystyle \begin{aligned} h'(0) & = 3(3) - 2(7) + 5(0) \\ \\ & = (9) - (14) + (0) \\ \\ & = -5\end{aligned}\)

In conclusion:

\(\displaystyle h'(0) = -5\)

Step-by-step explanation:

92  is worth  70%

92 * .72    + 100 * .30 = 94.4 score

 If   "A"   is 93 or above....it looks like you got one !

       Therefore, Your Grade is Now:  94.4%

       Calculate the percentage of the summative grade:

       0.30  *  100   =  30

        1  -  0.30  = 0.70

        0.70  *  92  =  64.4

        64.4  +  30  =  94.4

        Therefore, Your Grade is Now:  94.4%

I hope this helps!

Answer:

On the coordnite grid the y axis use rise over run

You go up 1 spaces and go across 3 spaces

If you still dont get it use algebra calculator sit.e

Step-by-step explanation

The required percentage yield for the reaction when theoretical yield and actual yield are given is calculated to be 85.5 %.  

The maximum mass that can be generated when a particular reaction occurs is referred to as theoretical yield.

Theoretical yield is given as mt = 9.23 g

The actual amount of product recovered is given as ma = 7.89 g

We must comprehend that in order to calculate the reaction's percent yield, we must divide the total amount of product recovered by the utmost amount that can be recovered. If we multiply by 100%, we can represent this fraction as a percentage.

Percentage yield = ma/mt × 100 = 7.89/9.23 × 100 = 85.5 %

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The slope of the tangent to the curve r = 4-9 cos θ at the value θ = 7/2 is approximately -8.00.

To find the slope of the tangent to the curve r = 4-9 cos θ at the value θ = 7/2, we first need to find the derivative of the polar function r(θ):

r(θ) = 4-9 cos θ

Taking the derivative with respect to θ, we get:

dr/dθ = 9 sin θ

Now we can find the slope of the tangent at θ = 7/2 by plugging in the value of θ into the derivative:

m = dr/dθ (θ = 7/2)

m = 9 sin (7/2)

m ≈ -8.00

Therefore, the slope of the tangent to the curve r = 4-9 cos θ at the value θ = 7/2 is approximately -8.00.

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Answer:

number lines of x>4 and x<-1 respectively

Step-by-step explanation: