8. A weight lifter lifts a set of weights a vertical distance of 2 m. If a constant net force of 350 N is exerted on the weights, what is the net work done on the weights? Please show full working out ( not in words)​

Answer:

yes  I feel you-

Explanation:

Answer:

same bro hard times out here

The total drag force acting on a sphere with a diameter of 12 cm and exposed to airflow at 1 atm and 5°C is therefore measured to be 5.2 N. Therefore, the friction drag coefficient is 0.0115.

When determining whether a flow pattern is laminar or turbulent while passing through a pipe, Reynolds number, a dimensionless quantity, is used. The relationship between inertial and viscous forces is what determines the Reynolds number. Friction is caused by surface irregularity, according to observations made at the microscopic level. Variety of Friction Friction can be divided into two categories, which are as follows: internal rubbing

Cdf = 0.2*0.3/5.2

Cdf = 0.06/5.2

Cdf = 0.0115

when 5.2/0.3 = 0.2

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These waves are traveling at the same speed.  The wave with the highest frequency is option C, "A wave frequency with line crossing in the middle."

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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In terms of size, our technology is not enough to "see" the entire universe, what we know based on the Cosmic microwave background and other observations is that the universe started from a compressed state and start to expand.

This expansion gives the idea of an endless universe. The reality is that the continued expansion makes impossible to determine the end of it, due to it expanding faster than we cover the distance to see the end.

In reality we are not sure if there is any "end" or if the universe conect like in a sphere with out an "end". It would be very difficult to know it thanks to the expansion and its speed.

The Big Bang is more a theory that explains what happened after t milliseconds. Talks about this expansion, not the origin of it, but explains how the energy was concentrated and started to expand until the light was capable to escape from this mass. This first image is the cosmic microwave background.

ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

Impulse = Change in momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass × velocity

In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.

Therefore, the change in momentum is given by:

Change in momentum = (mass × final velocity) - (mass × initial velocity)

Change in momentum = mass × (final velocity - initial velocity)

Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))

Change in momentum = 0.14 kg × (49 m/s + 32 m/s)

Change in momentum = 0.14 kg × 81 m/s

Change in momentum = 11.34 kg·m/s

So, the impulse imparted on the baseball is 11.34 kg·m/s.

The magnitude of the force acting at point O is determined as 240 N.

The magnitude of the force at point O is calculated by applying the principles of moment as shown below.

sum of the clockwise moment = sum of the anticlockwise moment

F₀(2 m + 2m + 2m) = 260 N (2m + 2 m ) +  200 N ( 2 m )

where;

6F₀ = 260 (4) + 200(2)

6F₀ = 1,440

F₀ = 1440 / 6

F₀ = 240 N

Thus, the magnitude of the force acting at point O is determined as 240 N.

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A. Centripetal force acting on the two stars is the reason why the two stars will not crash into one another

B. The mass of each stars, given they maintain a constant distance of 8×10¹⁰ m is 7.68×10²⁷ Kg

A. Why don't the two stars crash into one another?

Centripetal force is the force that acts to keep an object moving in a circle. Since the two stars undergoes revolution, this means they rotate in a circle. Thus, centripetal force is acting on them.

Therefore, we can say that the two stars will not crash into one another due to the centripetal force

B. How do I determine the mass of each stars?

We can obtain the mass of each stars as illustrated below:

F = GM₁M₂ / r²

Note: They rotate mid-way. Thus distance apart (r) = 2r

F = GM₁M₂ / (2r)²

F = GM₁M₂ / 4r²

Also, centripetal force is given as:

F = mv² / r

Thus, we have:

mv² / r = GM₁M₂ / 4r²

But

v = 2πr / T

v² = (2πr / T)² = 4π²r² / T²

M₁ = M₂ = m

Thus, we have

m4π²r² / rT² = Gmm / 4r²

4π²r / T² = Gm / 4r²

Cross multiply

mGT² = 4r² × 4π²r

mGT² = 16π²r³

Divide both sides by GT²

m = 16π²r³ / GT²

From the question given, we have:

m = 16π²r³ / GT²

m = [16 × 3.14² × (8×10¹⁰)³] / [6.67×10¯¹¹ × (3.97×10⁸)²]

m = 7.68×10²⁷ Kg

Thus, the mass of each stars is 7.68×10²⁷ Kg

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Answer:

2, 3, 4, 1

Explanation:

geosphere, hydrosphere, biosphere, and atmosphere

Answer:

Lithosphere hydrosphere biosphere atmosphere

Explanation:

So yea mark me brainliest

Answer:

Option C. ⁰₊₁e

Explanation:

From the question given above, the following data were obtained:

¹⁵₈O —> ¹⁵₇N + __

Let the unknown be ʸₓM

Thus, the equation becomes

¹⁵₈O —> ¹⁵₇N + ʸₓM

Next, we shall determine x, y and M. This can be obtained as follow:

8 = 7 + x

Collect like terms

8 – 7 = x

1 = x

x = 1

15 = 15 + y

Collect like terms

15 – 15 = y

0 = y

y = 0

ʸₓM => ⁰₁M => ⁰₊₁e

Therefore,

¹⁵₈O —> ¹⁵₇N + ʸₓM

¹⁵₈O —> ¹⁵₇N + ⁰₊₁e

Answer: it is c

Explanation:

i took the t.e.s.t

Answer:

f. 500N

Explanation:

The force exerted by the wagon on the horse is 500N directed in the opposite path .

This is premised on the Newton's third law of motion which states that "action and reaction forces are equal and opposite in direction".

So, as the action force of 500N is used by the horse to drag the wagon, the wagon also exerts an oppositely directed force of 500N on the horse.

This way, the acceleration can continue.

In the experiment, place a ringing alarm clock inside a vacuum chamber, and observe that when the chamber is evacuated, the sound from the alarm clock cannot be heard, illustrating that sound does not travel through a vacuum.

To illustrate that sound requires a medium for its propagation and does not travel through a vacuum, you can perform the following experiment:

Take two identical bells or sound-producing devices and place them in separate chambers, one in a vacuum chamber and the other in a chamber filled with air.

Ensure that both chambers are isolated from external noise sources.

Activate the sound-producing devices simultaneously, creating sound waves in both chambers.

Observe and listen for the sound produced in each chamber.

In the chamber filled with air, you will hear the sound clearly, as air molecules transmit the sound waves, allowing them to propagate and reach our ears.

However, in the vacuum chamber, you will not hear any sound because there is no medium (such as air) for the sound waves to travel through. Without molecules to transmit the vibrations, the sound cannot reach our ears.

This experiment demonstrates that sound requires a medium, such as air or other substances, to propagate and be perceived by our ears. In a vacuum, where there is an absence of molecules, sound cannot travel.

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Given data:

* The final velocity of the ball is 0m/s.

* The acceleration of the ball is,

* The time taken by the ball is 8 s.

Solution:

By the kinematics equation, the initial velocity of the ball in terms of the final velocity, acceleration, and the time taken is,

where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken,

Substituting the known values,

Thus, the initial velocity of the ball is 3.2 m/s.

Hence, option D is the correct answer.

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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The new force is obtained as 228 N since the product of the masses is directly proportional to the force.

From the Newton law of universal gravitation, we can see that the gravitational force that exists between two masses is directly proportional to the product of the masses and inversely proportional to the distance between the masses.

Where the distance between the masses, remain the same, we can see that the new force would be three times the initial force since the the force and the mass are directly proportional.

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The correct values for heat and work for the piston are;

Q = +42 J, W = -50 J

Option C

We must note that the work that has been done by the piston can be obtained by the formula that we know and that formula states that;

w = PdV

w = work that have been done

P = pressure

dV = change in the volume

As such we would have that the work done is;

w =  1.0 × 10^5 Pa (0.0002 -  0.0007)

w = -50 J

This is the work that has been done but the heat was absorbed hence it is positive.

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Answer:

A) X-rays

Explanation:

Airport security screenings use X-rays because they can penetrate through bags to see objects that are located within that are obscured through normal view.

X- rays are used to  test  body in airports. Low energy waves are used to screen baggages and human body. Thus option A is correct.

Electromagnetic spectrum is the arrangement of radiations in the order of decreasing wavelength or increasing energy and frequency. The order is radio waves, microwaves, infrared, visible, ultraviolet, x-rays and gamma rays.

x -rays are highly energetic short waves which can be easily penetrate through a body. X-ray is used in different diagnostic techniques. X-rays easily penetrate through  tissues and provide the scanned images of internal parts.

In airport security screening x-rays are used to screen baggages and human bodies. High energetic waves are causing serious health risks. Hence, lower energy x-rays are used in testing.

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The pitch of a note is the same as its frequency.

Remember that te timbre depends on the shape and other properties of the vibrating object. The loudness is related to the amplitude of the wave, and the wavelength of sound is inversely proportional to the frequency.

On the other hand, the frequency of the sound of a string is proportional to the square root of the tension in the string. Then, if the tension increases (if the string is tightened), the frequency will also increase (and if the frequency increases, the wavelength decreases).

Therefore, the parameter that increases when a string of a stringed instrument is tightened, is the pitch.

Therefore, the answer is:

The graph of the velocity and the time  can be shown by option D.

We know that the movement of an object as it is falling under gravity would have a constant acceleration. The constant acceleration means that the velocity of the object is also held a constant.

We now have to look at the graphs as we have them here. The graph as it has been shown has the the velocity on the vertical axis and it has the time on the horizontal axis. The gradient of the slope is what we would refers to as the acceleration of the body.

We also need to recall that the acceleration has to be a constant since tje tow object would have to reach the ground at the same time if they are released from the same height at the same time.

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Answer:

Explanation:

Potential energy increases because the train moves against the magnetic force.

According to Newtons third law of motion when one object exerts a force on a second object, then true statement about the force is option (D) They are equal in magnitude and opposite in direction

Newton's third law of motion states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on a second object, the second object exerts an equal and opposite force on the first object. This law applies to any two objects that interact with each other, and the forces they exert on each other always have the same magnitude but act in opposite directions.

To understand this law, let's consider an example of a person pushing a wall. When a person pushes a wall, the person exerts a force on the wall, but the wall also exerts an equal and opposite force on the person. The force that the wall exerts on the person is equal magnitude but opposite in direction to the force that the person exerts on the wall. As a result, the person feels a force pushing back on them, which is why they cannot push the wall over.

Therefore, the correct option is (D) They are equal in magnitude and opposite in direction

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Answer:

Explanation:

To find the net electric flux through a closed surface, we need to apply Gauss's law:

Phi_E = Q_enclosed / epsilon_0

where Phi_E is the electric flux, Q_enclosed is the net charge enclosed by the closed surface, and epsilon_0 is the electric constant.

Let's consider a spherical closed surface of radius R enclosing the charges. We can divide the surface into two regions: inside and outside the sphere.

For the charges inside the sphere, the net charge enclosed is:

Q_enclosed = +1.00 nC - 3.00 nC = -2.00 nC

Therefore, the electric flux through the inner surface of the sphere is:

Phi_E_inside = Q_enclosed / epsilon_0 = (-2.00 nC) / epsilon_0

For the charge outside the sphere, the net charge enclosed is:

Q_enclosed = +2.00 nC

Therefore, the electric flux through the outer surface of the sphere is:

Phi_E_outside = Q_enclosed / epsilon_0 = (2.00 nC) / epsilon_0

The net electric flux through the closed surface is the sum of the electric flux through the inner and outer surfaces:

Phi_E_net = Phi_E_inside + Phi_E_outside = (-2.00 nC) / epsilon_0 + (2.00 nC) / epsilon_0

= 0

Therefore, the net electric flux through the closed surface is zero. This means that the total amount of electric field lines entering the surface is equal to the total amount of electric field lines leaving the surface. This result is consistent with Gauss's law, which states that the net electric flux through a closed surface is proportional to the net charge enclosed by the surface. In this case, since the net charge enclosed is zero, the net electric flux is also zero.

Answer:

\(74.31\ \text{N}\)

\(16.59^{\circ}\)

Explanation:

P = 50 N

Q = 30 N

\(\theta\) = Angle between the vectors = \(45^{\circ}\)

Resultant is given by

\(R=\sqrt{P^2+Q^2+2PQ\cos\theta}\\\Rightarrow R=\sqrt{50^2+30^2+2\times 50\times 30\times \cos45^{\circ}}\\\Rightarrow R=74.31\ \text{N}\)

Angle of resultant

\(\phi=\tan^{-1}\dfrac{Q\sin\theta}{P+Q\cos\theta}\\\Rightarrow \phi=\tan^{-1}\dfrac{30\times \sin45^{\circ}}{50+30\cos45^{\circ}}\\\Rightarrow \phi=16.59^{\circ}\)

Magnitude of the resultant is \(74.31\ \text{N}\)

Direction of the resultant is \(16.59^{\circ}\)

Answer:

11,000 kg

(a) 11.2 m/s

(b) 1.6 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)

132,000 kg km/h = 22,000 kg km/h + m (10 km/h)

110,000 kg km/h = m (10 km/h)

m = 11,000 kg

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)

-mv + 10mv = m v₁ + 2m v₂

9mv = m (v₁ + 2 v₂)

9v = v₁ + 2 v₂

Since the collision is elastic, kinetic energy is also conserved.

½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²

m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²

mv² + 50mv² = m v₁² + 2m v₂²

51mv² = m (v₁² + 2 v₂²)

51v² = v₁² + 2 v₂²

We know v = 1.60 m/s.  So the two equations are:

14.4 = v₁ + 2 v₂

130.56 = v₁² + 2 v₂²

Solve the system of equations using substitution.

130.56 = (14.4 − 2 v₂)² + 2 v₂²

130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²

0 = 6 v₂² − 57.6 v₂ + 76.8

0 = v₂² − 9.6 v₂ + 12.8

v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)

v₂ = 1.6 or 8

If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.

If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.

We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision.  Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.

Answer:

KE = 3456 J

Explanation:

Answer:

The total displacement is 5 km North (answer B)

Explanation:

Recall that displacement is defined by the vector formula:

Displacement = Final position - initial position

Which corresponds to a vector with its tail at the starting point, and the arrow at the final position. This gives a vector pointing North, and of length 5 km.

This agrees with answer labeled B.

Answer:

conductor

Explanation:

Its easier for electricty to flow through a conductor as it has free electrons

Answer: The acceleration results if a net force of 4F acts on a mass of 6m is 2/3a.

Explanation:

Force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is:

F= mass( kg) × acceleration( m/ s²)

Acceleration is defined as the rate at which the velocity of an object changes. From the formula of force given above it can be determined by making it the subject of formula. Therefore acceleration= Force/ mass.

From the question,

Force= 4F

Mass= 6m

Therefore acceleration= F/m

= 4/6

Acceleration= 2/3a

The required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.

Given data:

The magnitude of net force is, 4F.

The value of mass is, 6m.

Apply the Newton's second law which says that force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is

F = ma

a = F/m ..........................................(1)

here, a is the acceleration.

Solving as when the force becomes 4F and mass becomes 6m.

\((4F) = (6m) \times a'\\\\a '= \dfrac{4F}{6m}\\\\a '= \dfrac{2}{3}a\)

Thus, the required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.

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From the calculations, the speed of the jogger is calculated as 4.7 m/s.

The term speed refers to the ratio of distance covered to time taken. In this case we know that;

steps per minute  = 200 steps per minute.

1 stride length = 140 cm

Distance covered in 200 strides = 200 * 140 = 28000 cm or 280 m

time taken = 1 minute or 60 seconds

Speed of the jogger = 280 m/60 seconds = 4.7 m/s

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