A 0.1 M solution of a chemical substance has a pH of 9. What is the chemical substance?
a strong acid.
a strong base.
a weak acid.
a weak base.
not dissociated into ions in water.

Answer:4

Explanation: I know because I got it right

Statement that gives description as regards energy and bonding changes between atoms such as fluorine become a molecule of fluorine is : 4:Energy is released as a bond is formed.

Therefore, option 4, is correct.

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The difference in electrochemical potential between two electrodes of an electrochemical cell is called as the cell potential.

The potential difference or voltage that exists between two electrodes in an electrochemical cell when no current is flowing through the cell is called the cell potential. Cell potential, also known as electromotive force (emf), is a measure of the driving force that drives a chemical reaction in an electrochemical cell forward.

The potential difference between the anode and cathode of an electrochemical cell is a quantitative measurement of the cell's capacity to generate electrical energy. The cell potential is usually measured in volts (V), and its sign is determined by the direction in which the electrons flow through the cell. When electrons flow spontaneously from the anode to the cathode, the cell potential is positive, whereas if electrons are forced to flow from the cathode to the anode, the cell potential is negative.

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The definite integral of f(x) da is 22.

let's calculate the area of the triangle. The base of the triangle is 2 units long, and the height is 4 units. Therefore, the area of the triangle is:

A_triangle = (1/2) * base * height
          = (1/2) * 2 * 4
          = 4 square units

Next, let's calculate the area of the trapezoid. The bases of the trapezoid are 2 units and 4 units long, and the height is 6 units. Therefore, the area of the trapezoid is:

A_trapezoid = (1/2) * (base1 + base2) * height
           = (1/2) * (2 + 4) * 6
           = 18 square units

Finally, we can add the areas of the triangle and the trapezoid to get the total area:

A_total = A_triangle + A_trapezoid
       = 4 + 18
       = 22 square units

Therefore, the definite integral of f(x) da is 22.

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The formula of sodium hydrogen phosphate is Na₂HPO₄.

3.2 moles of Na₂HPO₄ contains 6.40 moles of Sodium atoms.

Two mole of sodium, one moles of hydrogen, one mole of phosphate, and four moles of oxygen make up one mole of sodium hydrogen phosphate, or Na₂HPO₄.

Given;

1 mole of Na₂HPO₄ contains 2 moles of Sodium  

3.2 moles of Na₂HPO₄ will contain =?

= 3.2 moles x 2  

= 6.40 moles  

Therefore;  

3.2 moles of Na₂HPO₄ contains 6.40 moles of Sodium atoms.

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Answer:

The volume of 9.0 M copper (II) sulfate stock solution needed to prepare 3.0 L of a 5.0 M solution is 1.667 L

Explanation:

Dilution is a process by which the concentration of a solute in solution is reduced by adding more solvent.

In other words, dilution is the procedure followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.

In a dilution the amount of solute does not vary. What varies in a dilution is the volume of the solvent: as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

The equation used in this case is:

Ci * Vi = Cf * Vf

where

Ci: initial concentration

Vi: initial volume

Cf: final concentration

Vf: final volume

In this case:

Ci: 9 M

Vi: ?

Cf: 5 M

Vf: 3 L

the de Broglie wavelength of the electron moving at a velocity of 3. 0 × 107 m/s is 2.4×10∧-11nm

lambda = h/mv

The de Broglie wavelength is defined as follows: lambda = h/mv, wherein the greek letter lambda represents the wavelength, h is Planck's consistent, m is the particle's mass and v is its pace. One may also explicit mv as the particle's momentum

according to wave-particle duality, the De Broglie wavelength is a wavelength manifested in all the gadgets in quantum mechanics which determines the chance density of locating the item at a given factor of the configuration area. The de Broglie wavelength of a particle is inversely proportional to its momentum

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Answer:

NaO2SO3 -> Na2SO4 + O2

Explanation:

The reaction of NaCl (sodium chloride) and Oxone (potassium peroxymonosulfate) is described by the following chemical equations:

The first step in the reaction is to dissociate oxone into its component ions:

Oxone (potassium peroxymonosulfate) -> K+ (potassium ion) + O2SO3- (peroxymonosulfate ion)

The peroxymonosulfate ion (O2SO3-) then oxidizes the sodium chloride (NaCl) to produce sodium peroxymonosulfate (NaO2SO3) and chlorine gas (Cl2):

NaCl + O2SO3-  -> NaO2SO3 + Cl2

The sodium peroxymonosulfate (NaO2SO3) then decomposes into sodium sulfate (Na2SO4) and oxygen gas (O2):

NaO2SO3 ) -> Na2SO4  + O2.#SPJ4

.

The term "atomic theory" is used instead of "atomic hypothesis" because it signifies the evolution and acceptance of the concept over time.

While Democritus initially proposed the idea of atoms in 400 BCE, it was merely a hypothesis without substantial experimental evidence. Over centuries, scientific investigations and advancements led to a deeper understanding of atomic structure and behavior.

The term "atomic theory" acknowledges that the concept of atoms has undergone refinement and modification based on experimental evidence and theoretical developments.

It recognizes that the understanding of atoms has evolved from a speculative hypothesis to a well-established scientific theory supported by extensive experimental observations, mathematical models, and empirical data.

The term "theory" conveys the comprehensive and validated nature of our understanding of atoms, encompassing their complex structures and behavior.

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Therefore, 0.2062 mol of NO can be produced from 3.3 g of O2. In order to determine the number of moles of NO that can be produced from 3.3 g of O2.

2NO + O2 → 2NO2 From the balanced equation, we can see that the stoichiometric ratio between O2 and NO is 1:2. This means that for every one mole of O2 that reacts, two moles of NO are produced.

To calculate the number of moles of O2 present in 3.3 g, we need to use the molar mass of O2, which is 32.00 g/mol:

moles of O2 = mass of O2 / molar mass of O2

moles of O2 = 3.3 g / 32.00 g/mol

moles of O2 = 0.1031 mol

Now, we can use the stoichiometric ratio to determine the number of moles of NO produced:

moles of NO = 2 x moles of O2

moles of NO = 2 x 0.1031 mol

moles of NO = 0.2062 mol

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The half life of the isotope is 60 minutes.

The term half life refers to the time taken for an isotope to decay to half of its original amount. In order to find the half life of the isotope, we can use the formula;

N/No =(1/2)^t/t1/2

Where;

N = mass of the isotope at time t

t = time taken

t1/2 = half life of the isotope

No = mass of the isotope originally present

Hence;

17/32 = (1/2)^60/t1/2

(0.5)^1 = (0.5)^60/t1/2

1 = 60/t1/2

t1/2 = 60 minutes

The half life of the isotope is 60 minutes.

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The height of a ramp does not directly determine the strength of the frictional force between a book and an object.

The strength of the frictional force between a book and an object is not directly influenced by the height of a ramp. The nature of the surfaces in contact, the force forcing the surfaces together (normal force), and the coefficient of friction are some of the variables that affect the frictional force between two surfaces.

The coefficient of friction between the book and the object plays a major role in determining the strength of the frictional force.

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Answer:

Cu

Explanation:

yes the taste of acid is sour

Explanation:

the acid increase the hydrogen concentration, which provides more ions for the tongue. Because the tongue gains ions, it registers the flavor as sour.

Here is the structure of alpha-ketoglutarate

     O

     ||

H3N--C--CH2--C--COO-

     |

  COOH

To draw the structure of alpha-ketoglutarate by glutamate dehydrogenase and being a precursor to the urea cycle, follow these steps:

1. Start with the backbone structure of a 5-carbon molecule, arranged in a linear chain.

2. At the first carbon (C1), attach a carboxyl group (COOH). Due to the pH of 7, the carboxyl group will lose a proton, forming a carboxylate ion (COO-).

3. At the second carbon (C2), attach a carbonyl group (C=O).

4. At the third carbon (C3) and fourth carbon (C4), attach hydrogen atoms.

5. At the fifth carbon (C5), attach another carboxyl group (COOH). Again, due to the pH of 7, this carboxyl group will lose a proton, forming a carboxylate ion (COO-).

Your resulting structure of alpha-ketoglutarate will have the following formula:

     O

     ||

H3N--C--CH2--C--COO-

     |

  COOH

This structure is generated in the reaction catalyzed by glutamate dehydrogenase and serves as a precursor to the urea cycle.

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Renal failure is the new diagnosis that the provider would prompt to discontinue a PRN order for magnesium hydroxide.

Renal failure is a special condition where the person is unable to manage the function of the kidney organ.

The magnesium hydroxide may cause renal failure because this salt must be eliminated by the kidney and therefore it may trigger health complications.

In conclusion, renal failure is the new diagnosis that the provider would prompt to discontinue a PRN order for magnesium hydroxide.

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Answer:

Pressure and volume

The mean free path increases with both increasing temperature (option a) and decreasing pressure (option d).

The mean free path refers to the average distance a molecule or particle travels before colliding with another. The mean free path increases with a decrease in the number of collisions, which can be influenced by factors such as temperature and pressure. Specifically, increasing temperature leads to an increase in the speed of particles, reducing the frequency of collisions and increasing the mean free path.

On the other hand, decreasing temperature leads to slower particle speeds and a higher frequency of collisions, decreasing the mean free path. Similarly, decreasing pressure reduces the number of particles in a given space, reducing the frequency of collisions and increasing the mean free path, while increasing pressure has the opposite effect and reduces the mean free path. Therefore, the mean free path increases with increasing temperature and decreasing pressure. Answer( option a and d)

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1) The theoretical yield is 18.02 g

2) The percent yield is 67%

3) The percent yield is  55.8 %

The balanced reaction equation is;

N2 + 3H2 ----> 2NH3

Number of moles of N2 = 15g/28 g/mol = 0.53 moles

If 1 moles of N2 produced 2 moles of NH3

0.53 moles of N2 will produce 0.53 * 2/1

= 1.06 moles

Theoretical yield = 1.06 moles * 17 g/mol

= 18.02 g

The percent yield = 12.1/18.02 * 100/1

= 67%

The percent yield = 19.8 g/35.5 g * 100/1

= 55.8 % as shown

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(i) The air/fuel ratio by mass is approximately 0.0487 kg air / kg fuel.

(ii) The rate of heat loss from the combustion chamber is approximately 0.0349 kW.

To solve the given problem, we need to determine the air/fuel ratio by mass and the rate of heat loss from the combustion chamber. Let's calculate each of these values step by step:

(i) Air/Fuel Ratio by Mass:

To calculate the air/fuel ratio by mass, we need to determine the mass flow rates of air and fuel entering the combustion chamber.

Given:

Flow rate of fuel (benzene): 0.05 kg/min

To find the mass flow rate of air, we need to determine the stoichiometric ratio between air and fuel. The balanced equation for the combustion of benzene (C₆H₆) is:

C₆H₆ + (15/2)O₂ → 6CO₂ + 3H₂O

From the balanced equation, we can see that 1 mole of C₆H₆ reacts with (15/2) moles of O₂. Therefore, the stoichiometric ratio of air to fuel is:

(15/2) * (32 kg O₂ / 1 mole O₂) / (78 kg C₆H₆ / 1 mole C₆H₆) = 20.51 kg air / kg fuel

The air/fuel ratio by mass is the inverse of the stoichiometric ratio:

1 / (20.51 kg air / kg fuel) = 0.0487 kg fuel / kg air

Therefore, the air/fuel ratio by mass is approximately 0.0487 kg air / kg fuel.

(ii) Rate of Heat Loss from the Combustion Chamber:

To determine the rate of heat loss, we can use the energy balance equation for the combustion chamber. The energy balance equation is:

Q_in - Q_out - W_out = ΔE_system

where:

Q_in = Heat input from fuel combustion

Q_out = Heat loss from the combustion chamber

W_out = Work output from the combustion chamber

ΔE_system = Change in internal energy of the combustion chamber

In this case, the process is steady flow and constant pressure, so there is no work output (W_out). Additionally, we can assume that there is no change in internal energy (ΔE_system ≈ 0) since the temperature difference is relatively small.

Therefore, the energy balance equation simplifies to:

Q_in - Q_out = 0

This means that the heat input from fuel combustion is equal to the heat loss from the combustion chamber.

To calculate the rate of heat loss, we need to determine the heat input from fuel combustion. The heat of combustion for benzene (C₆H₆) is -3267 kJ/mol.

Given:

Flow rate of fuel (benzene): 0.05 kg/min

Heat of combustion of benzene: -3267 kJ/mol

First, we need to convert the flow rate of fuel to moles per minute. The molar mass of benzene (C₆H₆) is:

(6 * 12 kg/mol) + (6 * 1 kg/mol) = 78 kg/mol

The moles of benzene consumed per minute is:

(0.05 kg / min) / (78 kg/mol) = 0.000641 mol / min

The heat input from fuel combustion is:

Heat input = moles of fuel * heat of combustion

= 0.000641 mol / min * (-3267 kJ/mol)

= -2.095 kJ/min

Since the heat input and heat loss are equal (Q_in = Q_out), the rate of heat loss from the combustion chamber is 2.095 kJ/min (or 0.0349 kW).

Therefore, the rate of heat loss from the combustion chamber is approximately 0.0349 kW.

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Answer:

the earth and moon rotate around the sun, therefore on sides facing the sun while the other is facing the moon

Answer:

I believe this is facilitated diffusion which is a type of passive transport, meaning no energy is required. If it is, the molecules should be moving to an area of high concentration to an area of lower concentration.

It could be a type of active transport where energy is required. But it doesn't look like it is.

If in doubt, you should click the start cell transport to watch the molecules move (if that feature works). If there are many molecules outside the cell moving inside the cell where there are few molecules, the answer is option 1.

If there are few molecules inside the cell moving outside the cell where there are many molecules, the answer is option 2.

Answer:

we need a picture in order to help you. if you add a picture or text of what you want an answer to I can help!

Answer:

tell me how you want

this done?

Explanation:

Answer: A. 27.43 kPa

Explanation:

Use the formula: PV/T = PV/T →

P(.776) / (298) = (32.6)(.664) / (303) →

.0026P = .07144 →

P = 27.43 kPa :)

Answer:

1. Insulin

2. Keratin

Explanation:

Proteins are one of the four biological molecules found in living systems. They are polymeric molecules made up of monomeric units called AMINO ACIDS. Proteins perform a wide variety of functions in the body ranging from enzymatic functions to structural roles.

Two examples of proteins found in the body are keratin, insulin. Keratin is a structural protein located in the skin, hair and nails while insulin is an enzymatic protein that aids in digestion.

The balanced half-reactions are: Oxidation half-reaction: 4Co → 4Co2+ + 8e-Reduction half-reaction: O2 + 2e- → 2O2 -

Given equation: 3O2+4Co⟶2Co2O3Using the symbol e− for an electron. The redox reaction can be broken down into two half-reactions. The reduction half-reaction is the one in which a species gains electrons and the oxidation half-reaction is the one in which a species loses electrons. The half-reactions are as follows: Reduction Half-reaction Half-reaction equation: O2 + 2e- → 2O2 -Oxidation number of oxygen in O2=0 and in O2^-= -1Charge on the left side = 0Charge on the right side = 2 x (-1) = -2Thus, 2 electrons are added to the left side to balance the charge, making the half-reaction:O2 + 2e- → 2O2 -Oxidation Half-reaction Half-reaction equation: 4Co → 4Co2+ + 8e-Oxidation number of cobalt in Co=0 and in Co2+ =+2Charge on the left side = 0Charge on the right side = 4 x (+2) + 8 x (-1) = -4Thus, 8 electrons are added to the right side to balance the charge, making the half-reaction:4Co → 4Co2+ + 8e-Thus, the balanced half-reactions are: Oxidation half-reaction: 4Co → 4Co2+ + 8e-Reduction half-reaction: O2 + 2e- → 2O2 -

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