A 1.00 x 109 kg object is raised vertically at a
constant velocity of 4.00 m/s by a crane. What
is the power output of the crane?

Answers

Answer 1

Answer:

P = 3.92 10¹⁰ W

Explanation:

The power is data by the expression

         P = W / t

the work of a force is

         W = F. y

the bold ones represent vectors. In this case the displacement is vertical upwards and the vertical forces upwards, therefore the angle is zero and the cos 0 = 1

          W = F y

we substitute

          P = F y / t

          P = F v

as the body rises at constant speed the acceleration is zero and from the equilibrium condition

            F -W = 0

            F = mg

we substitute

           P = m g v

let's calculate

           P 1.00 10⁹ 9.8  4

           P = 3.92 10¹⁰ W


Related Questions

A radio station broadcast at a frequency of 200HZ. If the speed of the wave is 3×10^8ms^-4, calculate the period and wave length of the wave.

Answers

The speed of sound of a wave having frequency 200 Hz in air is 340 m/s.

How can you determine a wave's length?

The following equation can be used to compute wavelength: wavelength = wave velocity/frequency. In most cases, wavelength is measured in meters. Greek letter lambda is used to represent wavelength, so = v/f.

The wavelength, which will also apply to troughs, is the separation between two wave crests. The frequency is measured in cycles per second (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz).

How to calculate length of the wave?

Wavelength = (speed) / (frequency) =

(3 x 10⁸ m/s) / (200HZ) =  340m/s

The speed of radio waves is 3*10^8 m/s, the same as the speed of light.

The speed of sound of a wave having frequency 200 Hz in air is 340 `m//s`.

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I drop a meterstick, and my reaction time is 0.2 seconds. How far does the meterstick travel
before I catch it?

Answers

The distance formula used for a falling object is y = 1/2gt^2 where g is gravity which is 9.80m/s^2 and t is the time it falls ( reaction time).

Y = 1/2(9.8)0.2^2

Y = 0.196

It travels 0.196 meters

The word _____ in contrast,refers to the accumulation of such a borrowing, year after year

Answers

Answer:

Budget

Explanation:

Have good day!!!

You throw a snowball horizontally. It hits a target 2 meters away. You notice that it hit o.9m below where you aimed. With what horizontal velocity did you throw the snowball?

Answers

The snowball travels a horizontal distance x and has height y at time t according to

x = vt

y = 0.9 m - 1/2 gt ²

where g = 9.8 m/s² is the magnitude of the acceleration due to gravity.

Set y = 0 and solve for t :

0 = 0.9 m - 1/2 gt ²

t ² = (1.8 m) / g

t ≈ 0.43 s

The target is 2 m away from where the snowball is thrown, so it was thrown with speed v such that

2 m = v (0.429 s)

v = (2 m) / (0.43 s)

v4.7 m/s

Answer:

About 5

Explanation:

it’s about 5 because of the physical shape

When you view the pendulum’s swing, it shows that at the very top of the swing KE = 0. What does that tell you about the pendulum’s motion at that point?

Answers

it tells you that it has a lot of force

Answer:

Since I couldn't find the other answers to the same question, I wrote the wrong answer to help ya'll get the sample response. So here's from Edge

Explanation:

Sample Response: If KE = 0, the pendulum is not moving. At the top of the swing, the pendulum must stop for a brief moment.

Robert, my neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long. What does he weigh?

Answers

The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

What is a riddle?

A riddle is a statement, question or phrase having a double or veiled meaning, put forth as a puzzle to be solved.

If Robert, your neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long, based on these statements, we can explain the riddle as Robert weighs iron for the fact that he  is a blacksmith, iron is the only thing he weighs the whole day.

Thus, the correct explanation for the riddle is " The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

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At the beginning of a new school term, a student moves a box of books by attaching a rope to the box and pulling with a force of F=84.4 N at an angle of 64 degrees. The acceleration of gravity is 9.8 m per s2. The box of books has a mass of 14 kg and the coefficient of kinetic friction between the bottom of the box and the floor is 0.3. What's the acceleration of the box?

Answers

After solving the equation the acceleration of box is 1.31m/s².

What is acceleration?
The rate at which an object's velocity with respect to time changes is called its acceleration.

The mass of the box, g, the acceleration due to gravity, F, the pulling force, μ be the coefficient of kinetic friction between the box and the floor, and f k, the kinetic frictional force, are all to be determined.

Fsin 64° and Fcos64°, respectively, represent the horizontal and vertical parts of the pulling force.

Consider that moving to the right is positive while moving to the left is negative. Take into account that the upward direction is positive, and the downward direction is negative.

Use the force. compute the value of the normal force while maintaining an equilibrium along the vertical direction.

N+Fsin64°- mg=0

N+ [84.4N] sin64°-[14kg] [9.80m/s²]

N=62.07

The results of applying Newton's second law of motion in the horizontal direction are as follows:

F net=ma

F cos64°-f k=ma

Fcos64°-μkN=ma

a= Fcos64°-μk N÷m

= [84.4N] cos640.3] [62.07N] ÷14kg

=1.31m/s²

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How fast would a 106-kg object have to be moving at this height to have zero energy?

Answers

Answer:

This question is inconclusive considering you are not representing either kinetic or potential energy. It would just have to be laying on the ground stagnant to have neither potential or kinetic energy.

Explanation:

Alex tickles his brother by stroking adjacent ________ spots on his skin.

Answers

Answer:

adjacent flat spots on his skin

Answer:

You didn't provide answer choices but I'd assume it's pressure.

Give examples of stochastic and non-stochastic effects of radiation and explain why this information is essential in our field of study

Answers

Stochastic impacts of radiation allude to those that happen arbitrarily and are not reliant upon the portion got. These impacts are related to the likelihood of events and incorporate disease and hereditary changes. Non-stochastic impacts, then again, have a limit, and their seriousness increments with expanding portions.

Models incorporate radiation consumption and intense radiation conditions. Understanding the qualification among stochastic and non-stochastic impacts of radiation is significant in fields like radiation security, atomic medication, and radiobiology.

It assists in setting radiation with dosing limits, creating well-being rules, and carrying out suitable radiation safeguarding measures. By separating these impacts, experts can evaluate and deal with the dangers related to openness to ionizing radiation all the more successfully.

This information guides choices in regard to radiation wellbeing conventions, word-related openness limits, and the improvement of radiation therapy systems in medication.

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In an immersion measurement of an odd-shaped metal object, the weight of the object is found to be 980 N when submerged in water. When it is submerged in a heavier Bromine liquid (density 3100 kg/m3), the object weighs 840 N. What is the volume of this object

Answers

Answer: \(0.00680\ m^3\)

Explanation:

Given

The weight of the object, when submerged in the water is \(980\ N\)

When it is submerged in the bromine liquid, it weighs \(840\ N\)

Suppose,

\(\rho=\text{Density of object}\\\rho_w=\text{Density of water}\\\rho_b=\text{Density of bromine}\\V=\text{Volume of the object}\)

for water,

\(\Rightarrow V(\rho -\rho_w)g=980\quad \ldots(i)\)

For bromine

\(\Rightarrow V(\rho-\rho_b)g=840\quad \ldots(ii)\)

Divide (i) and (ii)

\(\Rightarrow \dfrac{\rho-1000}{\rho-3100}=\dfrac{980}{840}\\\\\Rightarrow 840\rho -840\times 1000=980\rho-980\times 3100\\\\\Rightarrow 140\rho=(3038-840)\cdot 1000\\\\\Rightarrow \rho=15,700\ kg/m^3\)

Put the density value in equation (i)

\(\Rightarrow V(15,700-1000)\cdot 9.8=980\\\\\Rightarrow V=\dfrac{100}{14,700}\\\\\Rightarrow V=0.00680\ m^3\)

Lam Lesson Name: Uncovering Your Personality
m number: 700047RR
Exam Guidelines
Exam Instructions
Question 10 of 20:
Select the best answer for the question.
10. Which characteristic of a turbulent person causes them to always strive for self-improvement, and to never see accomplishing a goal as good enough?
O A. Confident
B. Self-critical
O C. Ignorant
O D. Calm
Mark for review (Will be highlighted on the review page)
ex Previous Question
Next Questin
Review My F

Answers

The correct answer is Self-critical.

Why is self-improvement?

Enhancing strengths, mental health, and even mending relationships benefit self-improvement. Simple actions like reading a book, trying something new, meditating, or even getting up early are some ways to improve oneself. There are so many easy, efficient methods to begin the process of improving oneself.A self-improvement strategy enables you to build the life you want for yourself. It enables you to maintain perspective on your priorities and the things most important to you in life to experience greater meaning and fulfillment.Self-development is taking steps to better yourself, such as by learning new skills or overcoming bad habits. An example of self-development is taking courses at the university to learn new skills and interesting things.

Self-critical:

Self-critical causes them to always strive for self-improvement and never to see accomplishing a goal as good enough.

The characteristic of a turbulent person causes them to always strive for self-improvement and to never see accomplishing a goal as good enough is Self-critical.

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Which of the following is accurate when discussing specific heat? Question 2 options: A) The specific heat of a gas can be measured at constant pressure. B) The specific heat of a gas can be measured at constant volume only. C) Specific heat values for liquids will never vary for different ranges of temperature. D) Specific heat values for solids will never vary for different ranges of temperature.

Answers

The accurate statement when discussing specific heat is  option A) The specific heat of a gas can be measured at constant pressure.

This is because specific heat is the amount of heat energy required to raise the temperature of a substance by a certain amount. For gases, the specific heat can be measured at either constant pressure or constant volume. However, when discussing specific heat in general, it is more commonly measured at constant pressure.

Option B is incorrect because the specific heat of a gas can also be measured at constant volume, not just constant volume only.

Option C is incorrect because specific heat values for liquids can vary for different ranges of temperature. The specific heat of a substance may change with temperature due to variations in molecular interactions and other factors.

Option D is incorrect because specific heat values for solids can also vary for different ranges of temperature. The specific heat of a solid can depend on factors such as crystal structure, impurities, and temperature range.

Therefore, the accurate statement is option A, which states that the specific heat of a gas can be measured at constant pressure.

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A hiker with a skin surface area of 1.3 m² is protected from hypothermia (the cold) by a close-fitting sleeping bag 30 mm thick. If her skin temperature is 34°C and she can safely lose 85 W of heat by conduction through the sleeping bag, what is the lowest outside temperature for which the sleeping bag provides adequate protection? Ignore heat losses due to convection or radiation. Coefficient of thermal conductivity of the sleeping bag = 0.019 Wm¹¹°C-¹ ​

Answers

Answer: The lowest outside temperature for which the sleeping bag provides adequate protection is approximately 89.61°C below the hiker's skin temperature of 34°C.

Explanation:

To find the lowest outside temperature for which the sleeping bag provides adequate protection, we need to determine the rate of heat loss through conduction and compare it to the heat loss the hiker can safely tolerate.

The rate of heat loss through conduction can be calculated using the formula:

Q = (k * A * ΔT) / d

Where:

Q is the rate of heat transfer (in Watts)

k is the coefficient of thermal conductivity (0.019 Wm¹¹°C-¹ in this case)

A is the surface area (1.3 m² in this case)

ΔT is the temperature difference (in this case, the difference between the skin temperature and the outside temperature)

d is the thickness of the sleeping bag (30 mm, which needs to be converted to meters by dividing by 1000)

Let's plug in the values:

Q = (0.019 * 1.3 * ΔT) / (30 / 1000)

The hiker can safely lose 85 W of heat, so we can set up the equation:

85 = (0.019 * 1.3 * ΔT) / (30 / 1000)

To solve for ΔT, we can rearrange the equation:

ΔT = (85 * (30 / 1000)) / (0.019 * 1.3)

ΔT ≈ 89.61°C

How does the atmosphere affect the hydrosphere?

Answers

Answer:

when pure water vapor from the water bodies get absorbed into polluted gases in the atmosphere, acid rain is caused and when this happens in a place where an element of the hydrosphere is located, it is polluted.in such a way hydrosphere is effected

Answer: When a parcel of air in the atmosphere becomes saturated with water, precipitation, such as rain or snow, can fall to Earth's surface.

Explanation:

Human contributions to greenhouse gases in the atmosphere are warming the earth's surface a process which is projected to increase evaporation of surface water and accelerate the hydrologic cycle. In turn, a warmer atmosphere can hold more water vapor.

Someone help me please i need to finish this

Someone help me please i need to finish this

Answers

Answer:

the last option is correct

Explanation:

see I won't explain all the points but will tell you the concept being used.

protons and neutrons are inside the nucleus in an atom while the electrons are outside the nucleus.

the mass number of an atom is equal to the sum of number of electrons and neutrons in an atomatomic number is equal to the number of electrons which is equal to the number of protons in an atom no. of electrons/ protons is always less than that of neutrons and they're almost equal( a large difference ain't obtained between the number of electrons and that of neutrons.

since, the rest of the options are violating the above rules they're incorrect

a) Define the Inverse Square Law and show that the field strength, E of a single charge Q acting on a test charge Q at a distance x from it along its field is given by
(b) A circuit consists of a variable resistor R connected in series with an ammeter and a cell. A voltmeter is connected in parallel across the variable resistor R. the cell is of e.m.f E and internal resistance r. For a certain value of R, the voltmeter reads 4V and the ammeter reads 1A. When R is adjusted, the voltmeter reads 2V and the ammeter reads 2.5A. Draw the circuit diagram and calculate the values of E and r.​

Answers

a. The Inverse Square Law states that the intensity or strength of a physical quantity decreases with the square of the distance from its source.

b. The values of E and r in the given circuit are: E = 4V (e.m.f. of the cell) and r = ∞

How to explain the information

a. In the context of electrostatics, the Inverse Square Law describes the relationship between the electric field strength and the distance from a charged particle.

b. For the first scenario (V = 4V and I = 1A), we have:

4V = 1A * R1,

R1 = 4Ω.

For the second scenario (V = 2V and I = 2.5A), we have:

2V = 2.5A * R2,

R2 = 0.8Ω.

Total resistance in the circuit (when ammeter reads zero current) is given by:

= R1 + R2 + r.

Since the ammeter reads zero current, we have:

E = I * R_total,

4V = 0A * R_total,

R_total = ∞ (infinity).

Therefore, we can conclude that the internal resistance r of the cell is infinite (or very high compared to the resistances in the circuit).

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What day of the year is solar time the same as sidereal time?

Answers

Answer:

I think the answers March 21

Answer:

Once a year, mean solar time and sidereal time will be the same.

A heavy, 6 m long uniform plank has a mass of 30 kg. It is positioned so that 4 m is supported on the deck of a ship and 2 m sticks out over the water. It is held in place only by its own weight. You have a mass of 70 kg and walk the plank past the edge of the ship. How far past the edge do you get before the plank starts to tip, in m

Answers

Answer:

about 1 meter

Explanation:

   

The distance past the edge that the man will get before the plank starts to tip is; 0.4285 m

We are given;

Mass of plank; m = 30 kg

Length of plank; L = 6m

Mass of man; M = 70 kg

Since the plank has 2 supports which are the deck of the ship, then it means that, we can take moments about the right support before the 2m stick out of the plank.

Thus;

Moment of weight of plank about the right support;

τ_p = mg((L/2) - 2)

τ_p = 30 × 9.8((6/2) - 2)

τ_p = 294 N.m

Moment of weight of man about the right support;

τ_m = Mgx

where x is the distance past the edge the man will get before the plank starts to tip.

τ_m = 70 × 9.8x

τ_m = 686x

Now, moment of the board is counterclockwise while that of the man is clockwise. Thus;

τ_m = τ_p

686x = 294

x = 294/686

x = 0.4285 m

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A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C​

Answers

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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What is the main organ of the circulatory system?

veins

arteries

heart

capillaries

Answers

It is the heart

if not im sorry

2
1 point
Cars are safety tested to see how quickly they come to a stop under many conditions. The distance and time of one of these tests is graphed. What is the average
velocity of this car over the first second?
Automobile Brake Test
120
W
0
60
-50 m/s
-100 m/s
-25 m/s
-75 m/s
14
28
30 4.0 10
Q Search
945
6:58 PM
6/5/2025

Answers

The average velocity of the car over the first second is -50 m/s.

The first option is correct.

What is the average velocity of the car over the first second?

Average velocity is the ratio of the displacement to the time interval.

The formula to calculate the average velocity is as follows;

Average velocity = Displacement / Time

where;

Displacement is the change in distance or position in a specified direction.

That is the difference between the final and initial distances.

Considering the graph of the automobile brake test given in the attachment;

displacement over the first second = 50 - 100 m

displacement over the first second = -50 ms

Average velocity = -50 m/ 1 s

Average velocity = -50 m/s

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21 pointCars are safety tested to see how quickly they come to a stop under many conditions. The distance

Why do diving seabirds need to account for the bending of light?
2-3 sentence response.

Answers

Diving seabirds need to account for the bending of light because water has a higher refractive index than air.

When light passes through the air-water interface, it slows down and changes direction, causing the image of an object to appear distorted. This phenomenon is known as refraction. For diving seabirds, the refraction of light can make it challenging to accurately locate their prey when diving, which is essential for their survival.

To account for the bending of light, diving seabirds have evolved specialized eyes that allow them to adjust their focus and perceive images differently than humans. These adaptations enable the birds to see through the distorted image caused by refraction and accurately locate their prey while diving. One adaptation that diving seabirds have is a flattened cornea, which allows them to maintain a sharp focus while diving.

Overall, the ability of diving seabirds to account for the bending of light is essential for their survival, as it enables them to accurately locate and catch their prey while diving in the often murky and challenging conditions of the ocean.

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a) a drone flies 150 m to southwest (directly between south and west), then flies 85 m directly south, and finally flies 550 m in the direction 35 degrees north of east. Use the analytical method to find the resultant displacement of the drone (magnitude and direction)

you can help with a​

a) a drone flies 150 m to southwest (directly between south and west), then flies 85 m directly south,

Answers

The resultant of the displacement is 336.5m

What is resolution of vectors?

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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it is dangerous to stand near the railway leak when train passing by,why?​

Answers

Answer:

Because a person may be pulled in the direction of the moving train. Thereby causing accident

Explanation:

According to Daniel Bernoulli's theorem, he was widely known as a Mathematician. He stated that due to the higher velocity of a moving train, there is higher kinetic energy in terms of volume around it, while the air pressure between the person and the train becomes lower.

As a result, a person near a moving train may be pulled in the direction of the moving train. Thereby causing accidents that may lead to death.

Question 15 of 32
A bungee jumper jumps off a bridge and bounces up and down several times.
She finally comes to rest 30 m below the bridge from which she just jumped.
If her mass is 50 kg and the spring constant of the bungee cord is 10 N/m,
how much energy was lost due to air resistance while she was bouncing?
(Recall that g = 9.8 m/s²)
A. 7330 N
B. 9200 N
C. 10,200 N
D. 8605 N

Answers

C. 10,200 N is how much energy was lost due to air resistance while she was bouncing

How much energy was lost

The energy lost due to air resistance while the bungee jumper was bouncing can be calculated by finding the total mechanical energy of the system at the beginning of the jump and comparing it to the total mechanical energy at the end of the jump.

At the beginning of the jump, the total mechanical energy is given by:

Ei = mgh

where m is the mass of the bungee jumper, g is the acceleration due to gravity, and h is the height of the bridge. Therefore, at the beginning of the jump:

50 x 30 x 10 - 1/2 x 30^2 x 10

= 15000 - 4500

= 10,200 N

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Very large forces are produced in joints when a person jumps from some height to the ground. (a) Calculate the magnitude of the force (in N) produced if a 62.0 kg person jumps from a 0.800 m-high ledge and lands stiffly, compressing joint material 1.50 cm as a result. (Be certain to include the weight of the person.) N (b) In practice the knees bend almost involuntarily to help extend the distance over which you stop. Calculate the magnitude of the force (in N) produced if the stopping distance is 0.300 m. N (c) Compare both forces with the weight of the person.

Answers

Answer:

a)   F = 3.3 10⁴ N,  b)  F = 2.2 10³ N,  c) force when rigid is 15 times greater than when bending the knees

Explanation:

For this exercise we can use the relationship between work and the variation of kinetic energy

          K₀ = ½ m v²

the final kinetic energy is zero because the person is stationary

          W = (∑ F) x

          W = W x - F w

the weight is in the same direction of the displacement therefore the work is positive and the force applied, by the floor, is in the opposite direction to the displacement, consequently the work is negative

we substitute

          ( W-  F ) x = 0-K₀

           F = W + K₀ /x  

          F = mg + \(\frac{1}{2} \frac{mv^2 }{2x}\)  

          F = m ( g+  \(\frac{v^2 }{2x }\)  )

 

Let's use kinematics to find the velocity of the person when reaching the floor

           v² = v₀² - 2g (y + y₀)

the initial velocity is true and when reaching the ground y = 0

          v² = -2 g (0-yo)

           

we calculate

          v = \(\sqrt{2 ] 9.8 \ 0.800}\)

          v = - 3.96  m/s

the direction of this velocity is vertical down

let's calculate

a) x = 1.50 cm = 0.0150 m

           F = 62.0 (3.96² / 2 0.0150 + 9.8)

           F = 3.3 10⁴ N

b) x = 30 cm = 0.30 m

           F = 62.0 (3.96² / 2 0.30 + 9.8)

           F = 2.2 10³ N

c) to compare the force let's look for the relationship between the two

           \(\frac{F_{rigid} }{ F_{flexible} }\) = 3.3 10⁴ / 2.2 10³

           \frac{F_{rigid}  }{ F_{flexible} } = 15

therefore see that the force when rigid is 15 times greater than when bending the knees

name three characteristics of sound​

Answers

Loudness, pitch, and timbre

A weather balloon is floating at a constant height above the earth when it releases a pack of instruments. If the pack hits the ground with a velocity of –73.5 m/s, how far did the pack fall?

a 7.45 m
b -7.45 m
c 275 m
d - 275 m

Answers

Answer:

c 275 m

Explanation:

Given parameters:

Final velocity  = 73.5m/s

Unknown:

Height of fall  = ?

Solution:

Since the body is falling from rest, U = 0 or initial velocity is 0m/s. Then we use one of the kinematics equation to solve this problem.

           V²   = U²  + 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

           73.5²   = 0²  +  (2 x 9.8 x h)

         5402.25 = 19.6h

                h = 275.6m

The density of water is about 1 gram per milliliter. A milliliter is a cubic centimeter (i.e., cm3 ). A red blood cell has a density similar to water and is shaped like a one micrometer thick disk with a diameter of about 10 micrometers. About what is the mass in grams of a red blood

Answers

Answer:

The mass in grams of a red blood cell is about 7.85 ×  10⁻¹¹ grams

Explanation:

To find the mass in grams of a red blood cell,

From,

\(Density = \frac{Mass}{Volume}\)

Then,

\(Mass = Density \times Volume\)

From the question,

Density of a red blood cell is similar to that of water

Density of water = 1 g/mL = 1 g/ cm³

Then, Density of a red blood cell = 1 g/cm³

Now, we will find the volume a red blood cell.

From the question,  

A red blood cell is shaped like a one micrometer thick disk with a diameter of about 10 micrometers

Since the shape is like that of a thick disc, we can determine the volume by using the formula for volume of a cylinder.

Hence,

Volume of a red blood cell = \(\pi r^{2}h\)

Where \(\pi\) Is a constant (Take \(\pi\) = 3.14)

\(r\) is the radius

and \(h\) is the thickness

Diameter of a red blood cell = 10 micrometers

Then, radius of a red blood cell = 10/2 micrometers = 5 micrometers

\(r\) = 5 micrometers = 5 × 10⁻⁶ meters

and \(h\) = 1 micrometer = 1 × 10⁻⁶ meters

Hence,

Volume of a red blood cell = 3.14 × (5 × 10⁻⁶)² × 1 × 10⁻⁶

∴ Volume of a red blood cell = 7.85 × 10⁻¹⁷ cubic meter (m³)

Convert this to cubic centimeter

(NOTE: 1 cubic meter = 1000000 cubic centimeter)

Hence,

Volume of a red blood cell = 7.85 ×  10⁻¹¹ cubic centimeter (cm³)

Now, for the mass

\(Mass = Density \times Volume\)

Density of a red blood cell = 1 g/cm³

Volume of a red blood cell = 7.85 ×  10⁻¹¹ cubic centimeter (cm³)

Then,

Mass = 1 g/cm³ ×  7.85 ×  10⁻¹¹ cm³

Mass = 7.85 ×  10⁻¹¹ g

Hence, the mass in grams of a red blood cell is about 7.85 ×  10⁻¹¹ grams

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