A 3.0-kg sphere was moving at 25 m/s when it hit another object. This caused all KE to be converted into thermal energy. What was the increase in thermal energy?

I have been stuck on this problem for two hours. please help

Answer:

Convection currents

Explanation:

As hot air cools it sinks back to the surface of the earth, where it gets warmed by the ocean only to rise again. This is called a convection current. Convection currents are defined as room air rising and cold air sinking

~Hope this helps

~Bre

Answer:

0.000001

Explanation:

Went to google converter.

Answer:

The plate moves a distance of 2,100 kilometers in 100 million years. The question requires units of centimeters. Convert the distance using 1 km = 100,000 cm:

To find speed, divide distance by time. The time it takes the plate to move 210,000,000 centimeters is 100 million years:

So, the African plate moves by approximately 2.1 centimeters per year.

Explanation:

Answer:

Explanation:

ln(A) = ln(A₀) - kt

Answer:

1. Mechanical wave

2. Longitudinal wave

3. The cochlea

4. The diagram is not attached so far

5. the wavelength decreases.

6. slowest through gases, faster through liquids, and fastest through solids. or simply solids>liquids>gases

Explanation:

Greetings!!

1. Waves in water and sound waves in air are two examples of mechanical waves. Mechanical waves are caused by a disturbance or vibration in matter, whether solid, gas, liquid, or plasma.

2. Sound is a longitudinal wave.

3. The cochlea is filled with a fluid that moves in response to the vibrations from the oval window. As the fluid moves, 25,000 nerve endings are set into motion. These nerve endings transform the vibrations into electrical impulses that then travel along the eighth cranial nerve (auditory nerve) to the brain.

4.

5. As the frequency increases, the wavelength decreases.

6. The Speed of Sound: Sound travels at different speeds depending on what it is traveling through. Of the three mediums (gas, liquid, and solid) sound waves travel the slowest through gases, faster through liquids, and fastest through solids.

Hope it helps!!!!

Answer:

directly proportional to the square of its speed.

Explanation:

;)

Answer:

headlight of vehicles use less energy and gives light to very limited area hence electricity can be conserved by doing this

Answer:

The elevator is stationary

Answer:

Wm = 97.2 [N]

Explanation:

We must make it clear that mass and weight are two different terms, the mass is always preserved that is to say this will never vary regardless of the location of the object. While weight is defined as the product of mass by gravitational acceleration.

W = m*g

where:

m = mass = 60 [kg]

g = gravity acceleration = 10 [m/s²]

But in order to calculate the weight of the body on the moon, we must know the gravitational acceleration of the moon. Performing a search of this value on the internet, we find that the moon's gravity is.

gm = 1.62 [m/s²]

Wm = 60*1.62

Wm = 97.2 [N]

a. The two cars are moving at the same speed at t = 3.88 seconds.

b. The two autos are moving at a speed of 4.18 cm/s at that moment.

c. The cars pass each other at time t = 1.05 s and t = 2.54 s, respectively.

d. At t = 1.05 seconds, the first car is located at 12.15 cm, and the second car is located at 16.55 cm. At t = 2.54 seconds, the first car is located at 10.69 cm, and the second car is located at 17.39 cm.

What is the speed of the two cars?

The speed of the cars is derived using the formula for linear velocity.

The velocity of the first car is calculated as follows:

v = v₀ + at

where;

The velocity of the second car can be calculated as:

v = v₀

where;

v₀ is the initial velocity since there is no acceleration.

We equate the two velocities of the two cars and solve for time:

-4.40 + 2.70t = 6.10

2.70t = 10.50

t = 3.88 seconds

b. To find the speeds of the cars at time t, we can substitute t = 3.88 seconds in the velocity equation for the first car:

For the first car:

v = -4.40 + 2.70 * 3.88

v = 4.18 cm/s

c. Solving for the time when the positions of the cars are equal allows us to determine when they pass one another.

The position of the first car will be:

x = x₀ + v₀t + 1/2 at²

where x₀ is the initial position.

The position of the second car will be:

x = x₀ + v₀t

equating the two positions equal and solving for time:

13.5 - 4.40t + 1/2 * 2.70t² = 10.5 + 6.10t

1.35t² + 1.70t + 3.00 = 0

Solving the quadratic equation, we get two times:

t = 1.05 s and t = 2.54 s

d. We can re-insert the time values into the position equation for each car to determine where the automobiles were at the times indicated in (c).

For t = 1.05 seconds:

First car:

x = 13.5 - 4.40 * 1.05 + 1/2 * 2.70 * 1.05²

x = 12.15 cm

Second car:

x = 10.5 + 6.10 * 1.05

x = 16.55 cm

For t = 2.54 seconds:

First car:

x = 13.5 - 4.40 * 2.54 + 1/2 * 2.70 * 2.54²

x = 10.69 cm

Second car:

x = 10.5 + 6.10 * 2.54

x = 17.39 cm

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Answer:

Friction

Explanation:

Friction is wasted energy in the form of heat and or destruction.....this is why combustion engines have oil lubriction ====>  reduce friction and wear

Answer:

its air

give me thanks

Answer:

Air

Explanation:

give me a thanks its 100% right

The image of the water tower and the houses is in the attachment.

Answer: (a) P = 245kPa;

(b) P = 173.5 kPa

Explanation: Gauge pressure is the pressure relative to the atmospheric pressure and it is only dependent of the height of the liquid in the container.

The pressure is calculated as: P = hρg

where

ρ is the density of the liquid, in this case, water, which is ρ = 1000kg/m³;

When it is full the reservoir contains 5.25×10⁵ kg. So, knowing the density, you know the volume:

ρ = \(\frac{m}{V}\)

V = ρ/m

V = \(\frac{5.25.10^{5}}{10^{3}}\)

V = 525 m³

To know the height of the spherical reservoir, its diameter is needed and to determine it, find the radius:

V = \(\frac{4}{3}.\pi.r^{3}\)

\(r = \sqrt[3]{ \frac{3}{4\pi } .V}\)

r = \(\sqrt[3]{\frac{525.3}{4\pi } }\)

r = 5.005 m

diameter = 2*r = 10.01m

(a) Height for House A:

h = 15 + 10.01

h = 25.01

P = hρg

P = 25.01.10³.9.8

P = 245.10³ Pa or 245kPa

(b) h = 25 - 7.3

h = 17.71

P = hρg

P = 17.71.1000.9.8

P = 173.5.10³ Pa or 173.5 kPa

The gauge pressure at house A, and B, is the measurement of pressure

relative to the pressure of the atmosphere.

Reasons:

Question parameters;

Mass of water in the tower, m = 5.25 × 10⁵ kg

Shape of the reservoir = Spherical

Height of the bottom of the reservoir above the main ground level = 15.0 m

Height of the house A above the ground = 0

Height of the house B above the ground = 7.30 m

(a) Required:

The gauge pressure at house A

Solution:

The density of the water, ρ ≈ 997 kg/m³

\(\mathrm{Volume \ of \ water \ in \ the \ tank,} \ V = \dfrac{5.2 \times 10^5 \, kg}{997 \, kg/m^3} \approx 526.58 \, m^3\)

Volume of water in the filled tank = Volume of the tank ≈ 526.28 m³

\(\mathrm{Volume \ or \ a \ sphere, } V = \dfrac{4}{3} \cdot \pi \cdot r^3\)

Therefore;

\(\mathrm{Volume \ or \ the \ spherical \ tank} = \dfrac{4}{3} \cdot \pi \cdot r^3 \approx 526.28\)

Which gives;

\(r = \sqrt[3]{\dfrac{526.58}{\pi} \times \dfrac{3}{4} } \approx 5\)

The diameter of the tank = The height of the tank, h = 2 × r

∴ h = 2 × 5 m = 10 m

The gauge pressure is the pressure above the prevailing atmospheric

pressure;

Therefore;

The gauge pressure at house A, \(P_{gA}\) = 997 × 9.81 × (10 + 15) = 244514.25

The gauge pressure at house A, \(P_{gA}\) = 244514.25 N/m² ≈ 244.5 kPa

(b) Required:

Gauge pressure at house B

At house B, we have;

Gauge pressure at house B, \(P_{gB}\) = 997 × 9.81 × (10 + 15 - 7.3) = 173116.089

The gauge pressure at house B = 173116.089 N/m² ≈ 173.116 kPa

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During an earthquake, it is important to take appropriate steps to ensure safety

(i) When you are in the classroom

Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.

Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.

Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.

(ii) When you are out of danger:

Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.

Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.

Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.

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Answer:

17.15 m/s.

Explanation:

The following data were obtained from the question:

Maximum height (h) = 15 m

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = –9.8 m/s² (since the ball is going again gravity)

Initial velocity (u) =.?

The initial velocity with which the baseball pitcher threw the ball can be obtained as follow:

v² = u² + 2gh

0² = u² + (2 × –9.8 × 15)

0 = u² + (–294)

0 = u² – 294

Collect like terms

0 + 294 = u²

294 = u²

Take the square root of both side

u = √294

u = 17.15 m/s

Therefore, the baseball pitcher threw the ball with an initial velocity of 17.15 m/s

Answer:

3.78 m on the left side of the seesaw

Explanation:

The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:

(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r

Solve for r, and you get 3.78 on the left side.

Hope this helps!

Answer:

25N/s or 25kg*m/s^2

Explanation:

It is written wrong because the unit of momentum is kgm/s^2 or N/s

Answer:

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

Explanation:

We must remember in this case that change in the potential energy is entirely represented by the change in the gravitational potential energy. From Work-Energy Theorem and definition of work we get that:

\(U_{g}= m\cdot g\cdot \Delta y\)

Where:

\(U_{g}\) - Gravitational potential energy, measured in Joules.

\(m\) - Mass, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(\Delta y\) - Change in vertical height, measured in meters.

This work is the energy needed to counteract effects of gravity at given vertical displacement.

If we know that \(m = 0.5\,kg\), \(g = 9.807\,\frac{m}{s^{2}}\) and \(\Delta y = 0.07\,m\), the change in the potential energy of the mass as it goes up the incline is:

\(U_{g} = (0.5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.07\,m)\)

\(U_{g} = 0.343\,J\)

The change in potential energy of the mass as it goes up the incline is 0.343 joules.

The change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

We know that

Potential energy = m*g*h

Here m means the mass = 0.5 kg

g means the gravity = 9.8

And, the h means the height  = 7cm = 0.07m

So, the change in the potential energy should be

=0.5*9.8*0.07

=0.343 J

hence, we can conclude that the  change in the potential energy (in Joules) of the mass as it goes up the incline is 0.343 J.

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Answer:

stress,depression and anxiety by improving self esteem.

Answer:

4

Explanation:

The tension in the tie cord is 67.09 N and the acceleration of the boxes is -1.087 m/s² (approx).

Given,Mass of two boxes, m = 45kg Friction coefficient, µ = 0.15Angle, θ = 30°.

We have to find the tension in the tie cord and the acceleration of the boxes.The free-body diagram of the two boxes is given below:

The two forces acting on each box are Tension force and friction force. And also, each box is under the effect of its weight and both boxes are connected by a tie cord.To calculate the tension in the tie cord, we have to consider the free-body diagram of both the boxes together.

From the free-body diagram of the two boxes together, we get the following equation:

((2mg - T)*sin θ) - (2µmg cos θ) = (2m*a)

Where,m = 45kg

g = 9.8m/s²

θ = 30°

µ = 0.15

a = Acceleration

T = Tension force

We know that the tension force in the tie cord is common for both the boxes.

We can write the above equation in terms of T as below:

T = (2m*g*sin θ - 2µ*m*g*cos θ - 2m*a) / 2

Now we will calculate the acceleration of the boxes.

From the above equation, we get the following equation:

a = (2m*g*sin θ - 2µ*m*g*cos θ - T) / 2m

Substitute the given values in the above equation, we get:

a = (2 * 45 * 9.8 * sin 30 - 2 * 0.15 * 45 * 9.8 * cos 30 - T) / (2 * 45)a = (86.24 - 117.27 - T) / 90a = (-31.03 - T) / 90.

The above equation gives the acceleration of the boxes in terms of tension in the tie cord T.

Substitute the above equation in the equation we got for tension T, we get:

T = (2 * 45 * 9.8 * sin 30 - 2 * 0.15 * 45 * 9.8 * cos 30 - 90 * a) / 2T = (86.24 - 117.27 - 90a) / 2T = (-31.03 - 90a) / 2.

Now we have the tension in the tie cord and the acceleration of the boxes.

The tension in the tie cord is T = (-31.03 - 90a) / 2, and the acceleration of the boxes is a = (-31.03 - T) / 90.

Let's calculate both of them,

T = (-31.03 - 90a) / 2 = (-31.03 - 90(-0.524)) / 2 = 67.09 N (approx)

The tension in the tie cord is 67.09 N (approx)

The acceleration of the boxes is

a = (-31.03 - T) / 90 = (-31.03 - 67.09) / 90 = -1.087 m/s² (approx).

Therefore, the tension in the tie cord is 67.09 N and the acceleration of the boxes is -1.087 m/s² (approx).

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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According to the question the distance between the object A and the image 1₂ is 6 cm.

Distance is the measure of how far apart two objects, points, or locations are from one another. Distance can be measured in linear units such as feet, meters, or kilometers, or angular units such as degrees. The concept of distance is a fundamental concept in mathematics, physics, and other sciences. Distance is used to calculate the speed and velocity of objects, as well as the force of gravity between two objects.

The distance between the object A and the image 1₂ can be calculated using the mirror equation.

Mirror equation: 1/d₁ + 1/d₂ = 1/f

Where d₁ is the object distance, d₂ is the image distance, and f is the focal length of the mirror.

In this case, d₁ = 12 cm, d₂ = ? and f = 8 cm.

Substituting these values into the equation gives us:

1/12 + 1/d₂ = 1/8

Rearranging the equation gives us:

1/d₂ = 1/8 – 1/12

Plugging in the values gives us:

1/d₂ = 1/8 – 1/12 = 1/6

Solving for d₂ gives us:

d₂ = 6 cm

Therefore, the distance between the object A and the image 1₂ is 6 cm.

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The energy that it needs to reach the maximum speed is 7583.4 Cal

In Physics, we know that the work done is the product of the force and the distance moved. However, work can be converted to energy since the both have the same dimensions. We define energy in physics as the ability or the capacity to do work.

Given these information, we know that the work done in moving the cheetah as it accelerates from the bottom to the top of the mountain is equal to the kinetic energy of the cheetah thus we can write;

W = KE = 1/2 mv^2

W= 0.5 * 62.0-kg * ( 32.0 m/s)^2

W = 31744 J

Given that;

1 calories = 4.186 J

x calories = 31744 J

x = 7583.4 Cal

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Answer:

D

Explaination:

I got it right on the quiz

Answer:

The answer is D. cobalt! :)

The final velocity of a truck is 74.0 ft/s, if it accelerates at a range of 3.00 ft/\(s^2\) from an initial velocity of 5.00 ft/s, then it will take the truck 23.67 seconds to attain its final velocity of 74.0 ft/s.

v = u + at

Here, v =the final velocity, u =the initial velocity, a =the acceleration, and t =the time taken.

Substituting the given values, one can get,

74.0 ft/s = 5.00 ft/s + 3.00 ft/\(s^2\) × t

Solving for t, one gets,

t = (74.0 ft/s - 5.00 ft/s) / (3.00 ft/\(s^2\)) = 23.67 s (that is  23.67 seconds is needed to attain final velocity of 74.0 ft/s)

Hence, a truck needs 23.67 seconds time to attain its final velocity of 74.0 ft/s and this is the final velocity.

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Cheese is made of casein protein, which is originally made from milk and is high in protein. The texture of the cheese is determined by the quality of the milk, so cow's milk cheese differs from goat's milk cheese.

Diary products are made from milk, such as cheese, curd, yogurt, etc., but all of them have different nutrients. The quality of these dairy products depend upon the quality of the milk, as some milking animals have a higher concentration of fats in their milk than other animals. These dairy products are used in different industrial sectors, such as for making ice cream, chocolate, and different food products.

Hence, cheese is made up of casein proteins that are present in the milk.

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a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

The heat required to chill 116 g of water from 85°C to 15°C is 33,242.08 J. (or 33.24 kJ).

The moving of minuscule particles known as atoms, molecules, or ions in solids, liquids, and gases produces heat energy. The amount of heat required to cool a substance can be calculated using the formula:

Q = m × C × ΔT

where Q is the heat absorbed or released (in joules), m is the mass of the substance (in grams), C is the specific heat capacity of the substance (in joules per gram per degree Celsius), and ΔT is the change in temperature (in degrees Celsius).

For water, the specific heat capacity is 4.184 J/g°C.

Using this formula, we can calculate the amount of heat released when cooling 116 g of water from 85°C to 15°C as:

Q = m × C × ΔT

Q = 116 g × 4.184 J/g°C × (85°C - 15°C)

Q = 116 g × 4.184 J/g°C × 70°C

Q = 33,242.08 J

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