\(\underline{\underline{\large\bf{Given:-}}}\)
\(\red{\leadsto}\:\)\(\sf{Mass \: of \:boy,m_b} \)\(\sf = 50\: kg \)
\(\red{\leadsto}\:\)\(\sf{Mass \: of \: cart,m_c} \)\(\sf = 2\:kg \)
\(\red{\leadsto}\:\)\(\sf{Initial \: velocity \:of \: boy,v_b} \)\(\sf= 20 \: m/s \)
\(\underline{\underline{\large\bf{To \: Find:-}}}\)
\(\orange{\leadsto}\:\)\(\sf{Velocity \: of \:cart \:after \: jumping \: of \:boy,V} \)\(\sf \)
\(\\\)
\(\underline{\underline{\large\bf{Solution:-}}}\\\)
Initially cart is at rest so -
\(\therefore \sf initial \:velocity \: of \:cart,v_c= 0\)
When boy jumps on cart , the boy and cart with their combined mass \(\sf (m_b+m_c)\)starts moving with same velocity, V
By conservation of linear momentum -
\(\begin{gathered}\\ \sf Initial \: Momentum \: of \:system = Final \:momentum \:of \:system \\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf m_bv_b+m_cv_c = (m_b+m_c)V \\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf 50 \times 20+2\times 0 = (50+2)V \\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf 1000 = 52V \\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf 52V= 1000 \\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf V= \frac{1000}{52}\\\end{gathered} \)
\(\begin{gathered}\\\implies\quad \sf V= 19.23 m/s \\\end{gathered} \)
Therefore, Velocity of cart after jumping of boy is 19.23 m/s.
Explanation:
Need to FinD :We have to find combined velocity according to the given condition.\( \red{\frak{Given}} \begin{cases} &\sf {Mass\ of\ the\ body\ A,\ (Boy)\ =\ {\pmb{\sf{50\ kg}}}.} \\ &\sf{Initial\ velocity\ of\ boy\ =\ {\pmb{\sf{20\ m/s}}}.} \\ &\sf{Mass\ of\ the\ body\ B,\ (Cart)\ =\ {\pmb{\sf{2\ kg}}}.} \\ &\sf{Initial\ velocity\ of\ cart\ =\ {\pmb{\sf{0\ m/s}}}.} \end{cases}\)
We know that, we're given with the mass of the boy and cart. Also, we're given the initial velocities of the two the bodies. We are asked to find out the velocity of cart after jumping of boy or just the combined velocity.
In order to find the combined velocity, we are gonna use the concept of Conservation of linear momentum. The formula for this concept is given by,
\( \rightarrow {\underline{\boxed{\red{\sf{m_Au_A\ +\ m_Bu_B\ =\ m_Av_A\ +\ m_Bv_B}}}}} \)
Where,
\( \sf {m_Au_A} \) denotes the mass and the initial velocity of object one \( \sf {m_Bu_B} \) denotes the mass and the initial velocity of object two\( \sf {m_Av_A} \) denotes the mass and the final velocity of object one\( \sf {m_Bu_B} \) denotes the mass and the final velocity of object twoSo, by substituting all the values in the formula, we'll find out the velocity of the cart after jumping of boy.
\(\rule{200}{3}\)
\({\underline{\underline{\blacksquare\ {\red{\pmb{\sf{Finding\ the\ velocity\ of\ the\ cart:}}}}}}} \)
\( \sf \dashrightarrow {m_Au_A\ +\ m_Bu_B\ =\ m_Av_A\ +\ m_Bv_B} \\ \\ \\ \sf \dashrightarrow {50(20)\ +\ 2(0)\ =\ (50\ +\ 2)v} \\ \\ \\ \sf \dashrightarrow {1000\ +\ 0\ =\ 52v} \\ \\ \\ \sf \dashrightarrow {1000\ =\ 52v} \\ \\ \\ \sf \dashrightarrow {\dfrac{\cancel{1000}}{\cancel{52}}\ =\ v} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{v\ =\ 19.23\ ms^{-1}}}}}_{\sf \blue {\tiny{Required\ velocity}}}} \)
∴ Hence, the required velocity of cart after jumping of boy or the combined velocity is 19.23 ms‐¹.
A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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Can anyone help me with this question please
I’ll mark as brainliest
No links.
the transverse Wave which is Answer:2
Answer:
1
Explanation:
amplitude is the maximum distance from the rest of the particles. amplitude is thus measured from the rest position to the peak of a crest or of a trough.
as seen below, graph 1 has an amplitude of 1 while both graph 2 and 3 has an amplitude of 2.
the momentum of an object is increased by a factor of 4 in magnitude. by what factor is its kinetic energy changed? (assume no change in the mass of the object.)
When the momentum of an object is increased by a factor of 4 in magnitude, the kinetic energy of the object is changed by a factor of 16. Here option A is the correct answer.
The kinetic energy of an object is given by the equation KE = (1/2)mv², where m represents the mass of the object and v represents its velocity.
The momentum of an object is defined as p = mv, where p represents the momentum, m is the mass, and v is the velocity.
If the momentum of an object is increased by a factor of 4 in magnitude, it means the new momentum is 4 times larger than the original momentum. Mathematically, we can write this as p' = 4p, where p' is the new momentum and p is the original momentum.
Since p = mv, we can substitute this into the equation above to obtain p' = 4mv.
Now, let's consider the kinetic energy. The original kinetic energy is KE = (1/2)mv², and the new kinetic energy is KE' = (1/2)m(v')², where v' is the new velocity.
We know that p' = 4mv, so we can rewrite it as 4mv = m(v').
Dividing both sides of the equation by m, we get 4v = v'.
Now, substituting this into the equation for kinetic energy, we have KE' = (1/2)m(4v)².
Simplifying the equation, we have KE' = (1/2)m(16v²).
Notice that v² appears in both the original and new kinetic energy equations. Since the mass (m) is the same for both cases, we can cancel it out.
Therefore, the ratio of the new kinetic energy to the original kinetic energy is (1/2)(16v²)/(1/2)(v²) = 16.
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Complete question:
The momentum of an object is increased by a factor of 4 in magnitude. By what factor is its kinetic energy changed?(a) 16 (b) 8 (c) 4 (d) 2(e) 1
we calibrated the gaussmeter before using it to measure the magnetic field and it should be calibrated every time before usage. without doing so, the data will likely deviate slightly from the expected values. can you think of the reason why the calibration should be done before every measurement?
For our delicate measurement equipment to continue to operate accurately, gaussmeter calibration is necessary. In order to achieve this, we compare the instrument to one with a standard or greater accuracy. Then, if there is a deviation from the actual reading, we find it and fix it.
How is a magnetic field calibrated?By delivering a reverse field to the magnet that is strong enough to bring the output (of flux) down to a reasonable level, magnetic calibration is accomplished.
Using a Tesla or Gauss metre, one may determine the intensity of a magnet's magnetic field. Many people who utilise magnets today possess their own Gauss metres and decide what magnetic field strengths are acceptable. The magnet analyzer will measure the magnetic field strength for multi-polar magnets.
The Hall Effect in semiconductors is the basis for how a digital Gauss metre functions. A voltage is created at a right angle to the current route when a semiconductor with current flowing in one direction is introduced perpendicular to a magnetic field.
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The table shows the specific heat capacities of various substances. Which substance requires the least energy to heat it by 1°C?
Silver is the best conductor of heat and will require the least amount of energy to heat it by 1⁰C.
What is specific heat capacity?
The specific heat capacity of an object is the quantity of heat require to raise a unit mass of the substance by 1 kelvin.
The specific heat of the given substances;
Water = 4186 J/kg⁰C
Copper = 385 J/kg⁰C
Concrete = 850 J/kg⁰C
Iron = 450 J/kg⁰C
Silver = 233 J/kg⁰C
Air = 1005 J/kg⁰C
The material that will require the least energy to heat it by 1 ⁰C is a material with the highest thermal conductivity and least specific heat capacity.
Thus, silver is the best conductor of heat and will require the least amount of energy to heat it by 1⁰C.
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fill in the blanks (grade8 physics)
Answer:
infra-red
molecules
vacuum
ionizing (?)
transmission
redirected
absorbed
emission
dark
emitter
reflectors
deflect
which of the following is a correct example of an action reaction pair?
A. You push the ball with your foot and the ball pushes the air.
B. When you jump, you push down on the ground and the ground pushes up on you.
C. A swimmer pushes the water with his legs and pulls the water with his arms.
D. The tires on a car push against the road and the front of the car pishes against the wind.
Answer:
its either d or a
Explanation:
imma say d looks pretty right though
Mr. Krabs created a secret ingredient for breath mint that he thinks will "cure" the bad breath people
get from eating crabby patties at the Krusty Krab. He asked 100 customers with a history of bad breath
to try his new breath mint. He had fifty customers (Group A) eat a breath mint after they finished
eating a crabby patty. The other fifty (Group B) also received a breath mint after they finished the
sandwich, however, it was just a regular breath mint and did not have the secret ingredient. Both
breath mint that would cure their bad breath. Two hours
groups were told that they were getting the
after eating the crabby patties, thirty customers in Group A and ten customers in Group B reported
having better breath than they normally had after eating crabby patties.
2. What is the independent variable?
3. What is the dependent variable?
4. What should Mr. Krabs' conclusion be?
5. Why do you think 10 people in group B reported fresher breath?
The answers to the following questions are 1. Group B, 2. secret ingredient, 3. bad breath, 4. not effective cent percent, 5. the placebo effect.
1. The group of people who received the normal mint which does not contain Mr. krab's secret ingredient for breath mint is the control group. So, Group B of people are in the control group.
2. Independent variable in the one for which the research is being conducted. So in this case the secret ingredient in the breath mint is the independent variable.
3. Dependent variable is the one that affects the result of the research. So, the bad breath, in this case, is the dependernt variable.
4. The Group A of fifty people received the secret ingredient in breath mint; 30 people it reported better breath. Therefore the mint that has a secret ingredient is successful in reducing the amount of bad breaths in the individual but does not appear to be effective cent percent.
5. The 10 people in group B may have reported fresher breath due to the 'placebo' effect. It is the effect where the physical or mental health of the individual appears to improve after a fake, dummy, or sample treatment is given to him/her.
Therefore, 1. Group B, 2. secret ingredient, 3. bad breath, 4. not effective cent percent, 5. the placebo effect.
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Suppose that you have been chosen for a space mission to a distant planet. Due to the length of time you'll be away from Earth you must carry out physical activity every day. On earth your, strength and conditioning trainer has determined you must do 90 minutes of exercise every day. If the vehicle is travelling at 0.80 c how much time, according to a timer on the space vehicle should you be active to meet your physical activity requirement?
Answer:
I should be active for 15 hours to meet the physical activity requirement.
Explanation:
Since time dilates in moving objects, we use the formula t = t₀/√(1 - β²) where t = time in space vehicle, t₀ = time on earth = 9 hours and β = v/c where v = speed of space vehicle = 0.8c.
So, t = t₀/√(1 - β²)
t = 9/√(1 - (v/c)²)
= 9/√(1 - (0.8c/c)²)
= 9/√(1 - (0.8)²)
= 9/√(1 - (0.64)
= 9/√0.36
= 9/0.6
= 15 hr
So, according to a timer on the space vehicle, I should be active for 15 hours to meet the physical activity requirement.
What types of changes in motion cause acceleration?
Answer:
Change in velocity and direction over a specific period of time.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate the acceleration of an object.
Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
\(a = \frac{v - u}{t}\)
Where,
a is acceleration measured in \(ms^{-2}\)
v and u is final and initial velocity respectively, measured in \(ms^{-1}\)
t is time measured in seconds.
Hence, the types of changes in motion that cause acceleration is a change in velocity and direction over a specific period of time.
the phenomenon of a light ray bending as it passes through materials of different density is called
The phenomenon of a light ray bending as it passes through materials of different density is called refraction.
Refraction is the bending of light as it passes from one medium to another with a different density. This occurs because the speed of light changes as it enters a new medium, causing the light to change direction. The amount of bending depends on the angle of incidence and the difference in density between the two media. Refraction is responsible for a variety of optical effects, including the magnification of images by lenses and the splitting of white light into its component colors by a prism.
The phenomenon of a light ray bending as it passes through materials of different density is called refraction.
Refraction occurs when a light ray passes from one medium (e.g., air) into another medium (e.g., water or glass) with a different density. This change in density causes the light to change speed, which in turn causes the light to change direction or "bend." The degree to which the light bends depends on the refractive indices of the two media and the angle at which the light enters the new medium.
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This is probaly the first and only real question ive asked and will ask but can someone help me plzzz!
Answer:
open the dictionary/glossary. it will give you the definitions of the words there.
Explanation:
Answer:
i think it goes like this
Explanation:
A train whistle is heard at 330 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and the sound of the whistle is then 320 Hz.Part AWhat is the speed of the train before slowing down?Part BWhat is the speed of the train after slowing down?
Let at velocity v the frequency is 330 Hz.
At velocity v/2 the frequency is 320 Hz.
Using Doppler effect,
\(f_1=f_o\frac{v_s}{v_s-v}\)\(f_2=f_o\frac{v_s}{v_s-\frac{v}{2}}\)Dividing the equations,
\(\begin{gathered} \frac{f_1}{f_2}=\frac{f_o(\frac{v_s}{v_s-v})}{f_o(\frac{v_s}{v_s-\frac{v}{2}_{}_{}})_{}_{}} \\ \Rightarrow v=v_s\frac{(\frac{f_1}{f_2}-1)}{(\frac{f_1}{f_2}-\frac{1}{2})} \end{gathered}\)Putting the values we have,
\(\begin{gathered} v=\frac{20.17m}{s} \\ \frac{v}{2}=10.08\text{ m/s} \end{gathered}\)Thus, the speed of the train before slowing down is 20.17 m/s
The speed of the train after slowing down is 10.08 m/s
What is a joule?
1 foot/lb
1 meter per second squared
1 meter
1 N-m
Answer:
Input Output
1 ft-lb 12 in-lb
1 in-lb 0.113 Nm
1 Nm 0.7376 ft-lb
1 in-lb 0.0833 ft-lb
1 ft-lb 1.3558179 Nm
1 in-lb 15.999999461875 in-oz
1 Nm 8.850746106833 in-lb
1 l-atm 101.325 J
1 Nm 3.72506E-7 hph
1 J 1 Nm
Explanation:
please mark as briliant
Answer:
1N-m
Explanation:
teacher just taught this an hour ago for my class
emily pulls upward on her briefcase to support it as she stands at the bus stop, waiting for the bus to arrive.
For zero work ,either force acts perpendicular to displacement so emily pulls upward on her briefcase to support it as she stands at the bus stop, waiting for the bus to arrive is Zero work.
When force and displacement are perpendicular to one another or when neither of them is present, the work performed is referred to as zero work. For instance, when we hold an object and walk, the force acts downward while the displacement acts forward. A straightforward illustration of zero work is when you stand still while holding a bag in your hands. In order to counteract the gravitational force acting on the bag, you exert a force with your hands, but since the bag is not moved, neither gravity nor your force have any effect. When we carry an object while walking, displacement always moves the object forward rather than downward.
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how much power is used for machine does 28J of work and 7 seconds
Answer:
3N
Explanation:
Tessa uses a toy slingshot to launch a tennis ball across the park for her dog to fetch. For her first launch, she
uses 100 N of force. Her second launch uses 200 N of force, and her third launch uses 300 N. Which launch had
the greatest acceleration of the tennis ball?
Answer:
See the explanation below.
Explanation:
To solve this problem we must apply Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration and this force can be calculated by means of the following equation.
F = m*a
where:
F = force [N] (units of Newtons)
m = mass [kg]
a = acceleration [m/s²]
The mass of the tennis ball will always be the same therefore it will never change.
Now clearing a:
\(a=\frac{F}{m}\)
If the mass of the ball remains the same:
\(a = \frac{100}{m} ; a = \frac{200}{m};a =\frac{300}{m}\)
We see that for a force of 300 [N], the acceleration exerted on the ball must be greater. Therefore with the force of 300 [N] the greatest acceleration is achieved.
Describe a type of force actung at a distance where the force is not gravitational
Answer:
Explanation:
One example of a force acting at a distance that is not gravitational is the electromagnetic force. The electromagnetic force is responsible for the interaction between electrically charged particles, such as protons and electrons. This force can attract or repel particles depending on their charges, and it can act over long distances. For example, the electromagnetic force is responsible for the attraction between the positively charged nucleus and negatively charged electrons in an atom, as well as the interaction between magnets.
What claim can you make about the relationship between energy and mass?
If the radius of an electron's orbit around a nucleus doubles but the wavelength remains unchanged, what happens to the number of electron wavelengths that can fit in the orbit?
Answer:
Number of electron wavelength will Double
Explanation:
let the radius = r and wavelength = λ
when R doubles and λ ( wavelength ) remains the same
The number of electron electron wavelengths will double as well
Using Bohr's angular momentum quantization to show this
attached below
2. Using the same list of living things show how they could be classified into three groups.
Group 1 ________
Group 2 ________
Group 3 _________
Using the same list, show how they could be classified into four groups.
Group 1 ________
Group 2 ________
Group 3 _________
Group 4 __________
Please someone help as soon as possible.
and for this assignment group has have a different name while you are using these words in the picture.
oh almost forgot part 1 of this in the picture also.
Answer:
Also, you could do this for the groups:
Group 1- creatures with scales
Group 2- creatures with fur
Group 3- creatures with feathers
For 4 groups you could possible do:
Group 1- no legs
Group 2- 2 legs with wings
Group 3- 2 legs without wings
Group 4- 4 legs
an electric field has a strength of 10.0 N/C at a distance of 1.00m from an unknown charge. At what distance from the charge does the electric field strength equal 2.50 N/C?
Answer:
r = 1.999m
Explanation:
E = kq/r²
10 = 9*10^9*q/1²
q = 10/9*10^9
q = 1.11*10^-9
then at what distance
r² = kq/E
r² = 9*10^9*1.11*10^-9/2.5
r² = 9.99/2.5
r² = 3.996
r = √3.996
r = 1.999m
What is the Sl unit for momentum?
O kg• m
O kg
O kg• m
O kg
2
m
Explanation:
The S. I. unit of momentum is Kg. m/sechope it helps you
Either funding for nuclear fusion will be cut or if significantly high temperatures are achieved in the laboratory, nuclear fusion will become a reality. Either the supply of hydrogen fuel is limited, or if nuclear fusion becomes a reality, the world's energy problems will be solved. Funding for nuclear fusion will not be cut. Furthermore, the supply of hydrogen fuel is not limited. Therefore, if sufficiently high temperatures are achieved in the laboratory, the world's energy problems will be solved. (C,H,R, S, E)
1. C∨(H>R)
2. S∨(R>E)
3∼C
4∼S /H>E
if sufficiently high temperatures (R) are achieved in the laboratory, nuclear fusion (S) becomes a reality, and as a result, the world's energy problems (E) will be solved.
How do we explain?C= Funding for nuclear fusion will be cut.
H = Supply of hydrogen fuel is limited.
R = Sufficiently high temperatures are achieved in the laboratory.
S = Nuclear fusion becomes a reality.
E = World's energy problems are solved.
We then represent the statements as:
C ∨ (H > R) (Either funding for nuclear fusion will be cut or if the supply of hydrogen fuel is limited, sufficiently high temperatures will be achieved in the laboratory.)S ∨ (R > E) (Either nuclear fusion becomes a reality or if sufficiently high temperatures are achieved in the laboratory, the world's energy problems will be solved.)C (Funding for nuclear fusion will not be cut.)S / H > E (Nuclear fusion will not become a reality, or if the supply of hydrogen fuel is limited, the world's energy problems will be solved.)Learn more about Nuclear fusion at:
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A ray of light is incident at an angle of 39.4◦ on the surface of a piece of crown glass whose index of refraction is 1.52 . What is the angle of refraction? Answer in units of ◦.
Answer:
The angle of refraction is \(\sf 74.7 \textdegree\)
Explanation:
In this example we can use Snell's law to evaluate the angle of refraction.
\(\sf n_1 \sf \sin \theta_1 \sf = n_2 \sin \theta_2\)
Where
\(\sf n_1\) is the is the index of refraction of the first medium (incident index)
\(\sf n_2\) is the is the index of refraction of the second medium (refracted index)
\(\sf \theta_1\) is the angle of incidence
\(\sf \theta_1\) is the angle of refraction
I am assuming the ray of light travels from air to glass.
Numerical Evaluation
In this example we are given
\(\sf n_1=1.52\)
\(\sf \theta_1=39.4 \textdegree\)
The refractive index of air is 1.000293. So we can say
\(\sf n_2=1.000293\)
Substituting our values into the equation yields
\(\sf 1.52 \cdot \sin 39.4=\sf 1.000293\cdot \sin \theta_2\)
Lets solve for \(\theta_2\).
\(\dfrac{\sf 1.52 \cdot \sin39.4}{1.000293} =sin\ \theta_2\\\)
\(\dfrac{\sf 0.96479038}{1.000293} =sin\ \theta_2\\\)
\(\sf 0.96450777=sin\ \theta_2\\\)
\(\sf \arcsin \left(0.96450777\right)=\theta_2\)
\(74.68922535=\theta_2\)
Rounding to the nearest tenth leaves us with
\(\theta_2 =74.7\)
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What is the term that is used to describe the
material through which a wave travels?
a. Matter
b. Medium
C. Substance
d. None of the above
B. A wave travels through medium. Hope this helped!
Calculate the displacement and acceleration of a vibration velocity signal of 10 mm/s at a frequency of 159.2 hz
The displacement of the vibration velocity signal is 0.0628 mm and the acceleration is 9963.15 mm/s².
To calculate the displacement and acceleration of a vibration velocity signal, we need to use the formula:
Displacement (in mm) = Velocity (in mm/s) / Frequency (in Hz)
Acceleration (in mm/s²) = Velocity (in mm/s) * 2 * π * Frequency (in Hz)
Given that the velocity is 10 mm/s and the frequency is 159.2 Hz, we can calculate the displacement and acceleration as follows:
Displacement = 10 mm/s / 159.2 Hz = 0.0628 mm
Acceleration = 10 mm/s * 2 * π * 159.2 Hz = 9963.15 mm/s²
It is important to note that displacement refers to the distance from the equilibrium position, while acceleration measures the rate of change of velocity. These calculations help us understand the characteristics of the vibration and can be used in various applications such as analyzing the behavior of mechanical systems or designing vibration control measures.
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A simple compound microscope with an overall magnification of -750 has an objective that magnifies by -250.
What is the maginication of the eyepiece?
The magnification of the eyepiece in the compound microscope is 3.
To find the magnification of the eyepiece in the compound microscope, we can use the formula for overall magnification:
Overall magnification = Objective magnification × Eyepiece magnification
Given that the overall magnification is -750 and the objective magnification is -250, we can rearrange the formula to solve for the eyepiece magnification:
Eyepiece magnification = Overall magnification / Objective magnification
Eyepiece magnification = -750 / -250
Eyepiece magnification = 3
Therefore, the magnification of the eyepiece in the compound microscope is 3.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
To know more about damping ratios, refer here:
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1. What is the velocity of a go-kart with a mass
of 25 kg and 50 J of kinetic energy?
Answer:
Explanation:
The formula for KE is
\(KE=\frac{1}{2}mv^2\) which makes solving our problem for velocity super easy. We will rewrite the formula in terms of v to get:
\(v=\sqrt{\frac{2KE}{m} }\) and filling in:
\(v=\sqrt{\frac{2(50)}{25} }\) so
v = 2 m/s to the correct number of sig fig's