A ________ can be best understood as data in motion, moving from one place in a system to another. A. Process B. Data flow C. Data store D. Data source

Answer: 0.28 A

Explanation:

Answer:

93km/h

Explanation:

because 31multiplied by 2 Is equal to 2

It takes 2 seconds for the charge to pass a point in the wire. The result is obtained by using the formula for an electric current equation.

Electric current is a flow of charged particles per unit of time. It can be expressed as

I = Q/t

Where

A light bulb has

Find the time taken!

We use the formula above to find t.

I = Q/t

0.835 = 1.67/t

t = 1.67/0.835

t = 2 s

Hence, the time needed to for the charge to pass a point in the wire is 2 seconds.

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Answer:

a) Metres (m)

b) Kilogram (kg)

c) litres (l)

Answer:

Yes your correct.

Explanation:

In the drag race between Alison and Kevin, Alison wins by 1 second.Let's denote the total distance of the race as "d" and the constant accelerations of Alison and Kevin as "a" and "b," respectively. Since both drivers start from a standing position, their initial velocities are zero.

According to the given information, Alison covers the last 1/4 of the distance in 3 seconds, while Kevin covers the last 1/3 of the distance in 4 seconds.

Let's calculate the time it takes for Alison to cover the last 1/4 of the distance:

Since the distance covered is 1/4 of the total distance, we can write:

1/4 * d = (1/2) * a * (3^2)

d = 9a/2

Similarly, for Kevin, the time it takes to cover the last 1/3 of the distance is:

1/3 * d = (1/2) * b * (4^2)

d = 8b/3

Since both expressions represent the same total distance, we can equate them:

9a/2 = 8b/3

Simplifying the equation, we find:

27a = 16b

From this equation, we can see that Alison's acceleration is greater than Kevin's. Therefore, Alison reaches the finish line before Kevin, winning the race.

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Answer:

A

Explanation:

and that is a very strange question in physics ...

it actually depends on what state you are in.

California for example requires all to stop unconditionally, I think. while in many other states it is the rule, if the 4-lane road is separating both driving direction by a barrier or raised intermediate area, you don't have to stop when going in the opposite direction.

so, it is either A or D depending on your state.

B and C never apply.

Answer:

Question

A school bus in the oncoming lane of a 4-lane road is flashing. You should:

\(====================================\)

ANSWER

A. Stop until the flashing red lights turn off.

\(====================================\)

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(ʘᴗʘ✿)

Answer:

Question

A school bus in the oncoming lane of a 4-lane road is flashing. You should:

\(====================================\)

ANSWER

A. Stop until the flashing red lights turn off.

\(====================================\)

#CarryOnLearning

(ʘᴗʘ✿)

Answer:

answer is 1000 N

formula used-

F= m x (v-u/t)

mark this as brainliest!

Answer:

C

becuase its where a wave (light etc) goes through a narrow area or across an edge of an area

The acceleration due to gravity on the surface of the Moon is only 17% of that on the surface of the Earth. If a person can throw a heavy ball 10.0 m vertically upward on Earth, how high could she throw it on the Moon if she gives it the same starting speed.

On Earth, the acceleration due to gravity is 9.8 m/s².On the Moon, the acceleration due to gravity is 1/6 of the Earth's acceleration due to gravity.On the Moon, the acceleration due to gravity is:

9.8 m/s² × (1/6) = 1.63 m/s².

The distance (height) that the ball could be thrown on the moon if given the same starting speed as that on the Earth, can be obtained using the kinematic equation:

v² = u² + 2gs

Where:

v = final velocity

u = initial velocity

g = acceleration due to gravity

s = displacement

Since the ball is being thrown vertically upward, the final velocity is 0 m/s (at maximum height).

Hence, v = 0 m/s.

u = ? (initial velocity is unknown)

g = 1.63 m/s²

s = ? (to be calculated)

Using the kinematic equation,

we have:0² = u² + 2 × 1.63 × ss

= u²/ (2 × 1.63)

Height (s) = (u²/3.26) m.

We know that the ball could be thrown 10.0 m vertically upward on Earth when given the same starting speed. This can be used to obtain the initial speed (u) of the ball.

u² = 2 × 9.8 × 10.0u²

= 196u

= √196u

= 14 m/s.

Therefore,Height

(s) = (u²/3.26) m

= (14²/3.26) m

= 60.9 m (approximately).

Therefore, the heavy ball could be thrown 60.9 m vertically upward on the Moon if given the same starting speed.

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Answer:

Answer:

Cheetos, takis, and doritos

Explanation:

Fruit bars

Explanation:

they ate healthy and tasty. they have them at costco

Averaged over a year in the central United States, radiation from the sun transfers about 200 W to each square meter of earth's surface, and the amount of solar energy that falls on a house each second is 20,000 W.

It is calculated by multiplying the area of the house by the average amount of solar radiation, and here the area of the house is 10 meters by 10 meters; the calculation is the below.

A = 10 m x 10 m = 100 \(m^2\)

P = A x 200 W/\(m^2\)

P= 100 \(m^2\) x 200 W/\(m^2\)= 20,000 W

Hence, averaged over a year in the central United States, radiation from the sun transfers about 200 W to each square meter of earth's surface, and the amount of solar energy that falls on a house each second is 20,000 W.

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Answer:

F = 7.7 [N]

Explanation:

In order to solve this problem, we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

m = mass = 3.5 [kg]

a = acceleration = 2.2 [m/s^2]

F = (3.5*2.2) = 7.7 [N]

An appropriate value for the resistance in parallel with the smoothing capacitor would be 1.59 kΩ.

To ensure good tracking of the AM envelope, the resistance in parallel with the smoothing capacitor should be low enough to discharge the capacitor quickly during the troughs of the modulated signal, but high enough to avoid discharging it too quickly during the peaks of the signal.

The time constant (τ) of the RC circuit formed by the smoothing capacitor and the parallel resistance is given by the formula:

τ = RC

where R is the resistance and C is the capacitance.

To determine an appropriate value for the resistance, we need to calculate the time constant and compare it to the period of the modulated signal.

The period of a 500 kHz signal is T = 1/f = 2 μs. The modulating signal has a bandwidth of 5 kHz, which means its period is 200 μs.

Assuming a small signal approximation, we can use the formula for the time constant to calculate an appropriate value for the resistance:

τ = 20 nF × R = T/2π = 31.8 ns

Solving for R, we get:

R = τ/C = 31.8 ns / 20 nF = 1.59 kΩ

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Complete question is:

The input signal into an envelope detector is an am signal of carrier frequency 500 khz. the envelope detector employs a smoothing capacitor of 20 nf. the modulating signal has a bandwidth of 5 khz. specify an appropriate value for the resistance in parallel with the smoothing capacitor for a good tracking of the am envelope.

When several resistors with different values are connected in parallel, the equivalent resistance is lower than the value of the smallest resistor.

When several resistors with different values are connected in parallel, the equivalent resistance is always less than the smallest individual resistor value.

This occurs because the total current in the circuit is divided among the parallel resistors, leading to a lower effective resistance.

To calculate the equivalent resistance in a parallel circuit, use the formula: 1/Req = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn, where Req is the equivalent resistance, and R1, R2, R3, etc. are the individual resistor values.

In summary, the equivalent resistance in a parallel connection of resistors is smaller than any of the individual resistors, and this is due to the distribution of current among the parallel resistors

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Answer:

true

Explanation:

Dahil ito ay isang uri na laro na

Parang larong may target for you to win

Answer:

A) T1 = 566 k = 293°C

B) T2 = 1132 k = 859°C

Explanation:

A)

The average kinetic energy of the molecules of an ideal gas is givwn by the formula:

K.E = (3/2)KT

where,

K.E = Average Kinetic Energy

K = Boltzman Constant

T = Absolute Temperature

At 10°C:

K.E = K10

T = 10°C + 273 = 283 K

Therefore,

K10 = (3/2)(K)(283)

FOR TWICE VALUE OF K10:

T = T1

Therefore,

2 K10 = (3/2)(K)(T1)

using the value of K10:

2(3/2)(K)(283) = (3/2)(K)(T1)

T1 = 566 k = 293°C

B)

The average kinetic energy of the molecules of an ideal gas is given by the formula:

K.E = (3/2)KT

but K.E is also given by:

K.E = (1/2)(m)(vrms)²

Therefore,

(3/2)KT = (1/2)(m)(vrms)²

vrms = √(3KT/m)

where,

vrms = Root Mean Square Velocity of Molecule

K = Boltzman Constant

T = Absolute Temperature

m = mass

At

T = 10°C + 273 = 283 K

vrms = √[3K(283)/m]

FOR TWICE VALUE OF vrms:

T = T2

Therefore,

2 vrms = √(3KT2/m)

using the value of vrms:

2√[3K(283)/m] = √(3KT2/m)

2√283 = √T2

Squaring on both sides:

(4)(283) = T2

T2 = 1132 k = 859°C

A) The temperature at which the average kinetic energy will have a value of 2K10 is; T1 = 293 °C

B) The temperature at which the molecules have twice the rms speed, 2vrms is; T2 = 859 °C

A) We are given;

Initial temperature; T = 10°C = 283 K

Initial kinetic energy; KE = K10

Final kinetic energy; KE1 = 2K10

Now,formula for average kinetic energy of the molecules of an ideal gas is given as;

KE = (3/2)kT

Where;

k is Boltzmann constant

T is temperature

We are told that in the second case, KE = 2K10. Thus;

2K10 = (3/2)kT1

K10 = ¾kT1 - - - (eq 2)

In the first instance, we have;

K10 = (3/2)kT - - - (eq 1)

Put (3/2)kT for K10 in eq 2 to get;

(3/2)kT = ¾kT1

k will cancel out to get;

(3/2)T = ¾T1

Make T1 the subject to get;

T1 = 2T

Thus;

T1 = 2 × 283

T1 = 566 K

Converting to °C gives;

T1 = 293 °C

B) We want to find the temperature T2 (in degrees Celsius) at which the molecules will have twice the rms speed, 2v_rms.

Formula for kinetic energy is also;

KE = ½mv²

Thus;

½m(v_rms)² = (3/2)kT

v_rms = √(3kT/m) - - - (eq 1)

When rms speed is 2v_rms, we have;

½m(2v_rms)² = (3/2)kT2

v_rms = √(¾kT2/m) - - - (eq 2)

Thus;

√(3kT/m) = √(¾kT2/m)

Square both sides to get;

(3kT/m) = (¾kT2/m)

4T = T2

T2 = 283 × 4

T2 = 1132 K

Converting to °C gives;

T2 = 859 °C

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Explanation:

In other to avoid a situation where their differences, pride, and personalities caused them to compete and publicly insult one another instead of working together they need to respectfully consider the viewpoints of each other, as well as assign individual roles that should be respected.

Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

Answer:

It will roll 9 meters in 3 seconds

Explanation:

3 m/s times 3 is 9

Thanks for warning me.

I'll be careful to stay out of its way.

Do you have a question to ask ?

The time needed for the hammer to reach the surface of the Earth is 3.54 s.

The time of motion is calculated as follows;

t = √(2h/g)

where;

t = √(2 x 10 / 1.6)

t = 3.54 s

Thus, the time needed for the hammer to reach the surface of the Earth is 3.54 s.

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All human cells contain mitochondria, which function as the cell's main "power generator" by transforming energy from food into a form the cell can use. Mitochondria are found in the cytoplasm of all human cells.

How do a generator and a mitochondria compare?

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Explanation:

We Know That

POTENTIAL ENERGY= MASS*g*HEIGHT

When the objects are lifted to same height then the object with heavier mass would have the highest potential energy

.

The length of the x-component of the vector is approximately 48.55 units.

To find the length of the x-component of the vector, we need to use trigonometry.

We can use the angle and the magnitude (length) of the vector to find the x-component using the formula:

x-component = magnitude x cos(angle)

Plugging in the values given, we get:

x-component = 52 units x cos(21⁰)

x-component = 52 units x 0.9336

Multiplying these two numbers, we get:

x-component ≈ 48.55 units

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Answer: Therefore, the instantaneous speed is only the answer, because, the detector can only detect the instantaneous speed but not the average speed.

Explanation:

Action-reaction pairs are forces that operate on separate objects in opposing directions and at identical magnitudes. Never do they affect the same thing. We learn that forces are interactions from Newton's third law.

When two bodies contact, they exert an equal and opposite force on one another in accordance with Newton's third rule of motion. Action-reaction forces are made up of these forces.

Think about how a baseball bat and a ball interact, for instance. The bat forces the ball to the right while the baseball forces the bat to the left. The action-reaction force pair is made up of these two forces acting on two separate objects together.

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Answer:

It is 52° below the celestial equator.

Explanation:

The declination is the angle in degrees measured north (+) or south (-) of the an imaginary line called the celestial equator.

The celestial equator is a projection of the earth's equator on the celestial sphere. imaginary

The star named Canopus has a declination of approximately –52°.

Since the angle is negative, this shows that it is south or below the celestial equator and at 52° south of the celestial equator.

Thus, the star named Caponus is 52° below the celestial equator.

Answer:

the answer is 'it is 52° below the celestial equator.' :))

Explanation:

its the correct answer on the quizz,,, good luck!! :3

In a circuit consisting of several resistors connected in series, the statement that is true is that the current flowing through each of them is the same. It is impossible to determine the power dissipated on each of them without knowing the actual magnitudes of the resistors.

When resistors are connected in series, the current flowing through the circuit is constant throughout. This means that the same amount of current passes through each resistor in the series.

This is a fundamental property of a series circuit, where the current encounters each resistor in succession. Therefore, the statement that the current flowing through each of the resistors is the same is true.

On the other hand, the power dissipated on each resistor depends not only on the current but also on the magnitude of the resistors themselves.

The power dissipated on a resistor can be calculated using the formula P = I²R, where P is the power, I is the current, and R is the resistance. Since the resistors in series may have different resistance values, it is impossible to determine the power dissipated on each resistor without knowing their individual resistances.

Therefore, the statement that the power dissipated on each of the resistors is the same is false. The power dissipated will vary depending on the individual resistance values.

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Answer:

A

Explanation: