A car with mass m travels over a hill with a radius of curvature of r at a speed of 15 m/s. What is the normal force on the car when the car is at the top of the hill?

The acceleration of the car is obtained as 0.298 m/s^2.

We know that the acceleration of the object is the change in the velocity of the object with time. In this case, we can see that we have the fact that a car is on a slope of 10 degree above horizontal. A force of 1000N is applied to the car up the line of the slope. The car has a mass of 500 kg.

Now we can be able to apply a simple formula so that we can be able to obtain the acceleration of the car that is in question here and we have to use the expression;

ma = Fapp - mgsinθ

m = mass of the object

a = acceleration

Fapp = applied force

θ = angle turned

500 * a = 1000 - (500 * 9.8 * sin10)

a = 1000 - (500 * 9.8 * sin10)/500

a = 0.298 m/s^2

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The clear stream appears to be shallower than it really is because of the refraction of light. The light bend at the water surface and and make the surface shallowed to our eyes.

Refraction is a the phenomenon of bending of light when it passes from one transparent medium to the other. The direction of light ray bends at he boundary of the two medium of different densities. For instance, the light bends when it travels from air to water.

The ratio of speed of light in a medium to the speed of light in air is called the refractive index of the medium. As the density of medium increases the speed of light decreases.

When light rays passes to the stream water, it bends downwards and comes to the surface in the bend line. Our eyes does not take the bending in account and we process it as it is coming in a straight direction and we judge the position of objects accordingly.

Therefore, due to refraction, the stream appears shallower than it really is.

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer: false

Explanation: They are measured by cubic ______. ______ is feet, meters, inches, any way to measure

Let's see

\(\\ \rm\Rrightarrow 1metre= 10^2cm\)

\(\\ \rm\Rrightarrow 1m=10^3mm\)

\(\\ \rm\Rrightarrow 1m=10^6\mu m\)

\(\\ \rm\Rrightarrow 1m=10^{-3}km\)

\(\\ \rm\Rrightarrow 1m=10^{9}nm\)

Answer: My bad bro. Just tryna get me some points g

Explanation: tuff

Answer:

Explanation:

D=s*t

D=(20)(45)

D=900m.

hope it helps

Answer:

Explanation:

Given

Maximum height H = 300m

Range (horizontal distance) = 380m

Required

Initial speed U and the angle of the ball when it was launched.​

Range = U√2H/g

380 = U√2(300)/9.8

380 = U√600/9.8

380 = 7.8246U

U = 380/7.8246

U = 48.57m/s

The initial speed is 48.57m/s

b) Using the formula for calculating time of flight;

T = 2Usin theta/g

9 = 2(48.57)sin theta/9.8

9*9.8 = 97.14sin theta

88.2 = 97.14sin theta

88.2/97.14 = sin theta

sin theta = 0.9079

theta = sin^-1(0.9079)

theta = 65.23°

hence the angle when the ball was launched is 65.23°

The correct statement is the water absorbed energy continuously, but the temperature increased only when all of the water was in one phase.

this is explained by the latent heat of fusion. The melting point of ice ( at which ice melts into water) is 0 degree Celcius. This temperature remains constant till all 10 g of ice melts completely and water comes in the same phase of liquid.

The latent heat of fusion, also known as enthalpy of fusion, is defined as the total amount of heat energy supplied to a solid substance to start a change in its physical state from a solid to a liquid state. Given the pressure of the environment is constant.

The correct option is (b).

The given question is incomplete, the complete question is

The image below shows how the temperature of 10 g of ice changes as energy is added. which statement is correct?

(a) The water absorbed energy continuously and temperature increases while water is changing phase.

(b) The water absorbed energy , but the temperature increased only when all of the water was in one phase.

(c) Temperature of the water remained constant.

(d) Temperature always increases.

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Answer:

what

you need to elaborate

Answer: Can you please write question clearly.

Explanation:

Answer:

2v

Explanation:

capacitance is the ratio of charge to voltage

C=q/v

1=2/v

v=2/1

V=2

Answer:

they are right it is a new moon

Explanation:

took the test

Answer:

Height of the ramp

Explanation:

The independent variable is always what the person doing the experiment can change or modify.  So if the question is about whether the height of the ramp with  effect the car, that is indeed what they are changing or modifying in the experiment.

Answer:

The correct answer is - Plantae.

Explanation:

Drosera magnifica is discovered in 2015 for the first time and the characteristics this organism's cell shows are -

- permanent vacuoles

- surrounded by cellulose layer

Vacuoles are present in both Plantae and Animalia kingdom of the eukaryotic organism but in animal cells, there are small and numerous vacuoles present and they are not permanent whereas in plant cells vacuoles are present permanently.

The cell of an animal cell has no surrounding layer other than cell membrane while in the plant cell there is a supporting and protecting layer of cellulose cell wall present.

On the basis of the given characteristics, it is confirmed that the Drosera magnifica belongs to Plantae kingdom.

The potential energy of the mass is 0.0452 J when it is at a distance of

0.0600 m from equilibrium.

How to calculate potential energy?

The potential energy stored in a spring when it is stretched or compressed by a displacement x is given by:

\($PE = \frac{1}{2}kx^2$\)

where k is the spring constant.

In this problem, the spring constant is given as 26.6 N/m, and the displacement of the mass from equilibrium is

\((0.120 m - 0.0600 m) = 0.0600 m.\)

Therefore, the potential energy stored in the spring when the mass is at a distance of 0.0600 m from equilibrium is:

\($PE = \frac{1}{2}kx^2 = \frac{1}{2}(26.6 N/m)(0.0600 m)^2 = 0.0452 J$\)

So the potential energy of the mass is 0.0452 J when it is at a distance of 0.0600 m from equilibrium.

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Answer: 0.0479

Explanation: This answer works for Acellus! :D

hope this helps!

Answer:

a burning piece of converts Chemical energy into Heat(Thermal) and Light energy

Answer:

a

  \(t = 3.798 \  s \)

b

\(S = 67.91 \ m \)

Explanation:

From the question we are told that

The height of the helicopter is \(h= 235 ft\)

The height of the bed of the truck is \(h_b = 3 \ ft\)

The speed of the truck is \(v = 40 \ miles / hour = \frac{40 * 1609.34}{3600} = 17.88 \ m/s\)

Generally the distance between the truck bed and the helicopter is mathematically represented as

\(H = h - h_b\)

=> \(H = 235 -3\)

=> \(H = 232 \ ft \)

Converting to meters

\(H = \frac{ 232}{3.281} = 70.7 \ m \)

Generally the time at which the helicopter should drop the package is mathematically represented as

\(t = \sqrt{\frac{2 * H}{g} }\)

\(t = \sqrt{\frac{2 * 70.7}{9.8} }\)

\(t = 3.798 \ s \)

Generally distance of the helicopter from the drop site at time t = 0 s is

\(S = v * t\)

=>     \(S =  17.88   *  3.798\)

=> \(S = 67.91 \ m \)

Answer:

The Number is concept. It is depending with what you mean by infinity. Some of the numbers include 1 through 2 or infinite. If you work with vector space of tuples with any components could be infinite you just know what typed of infinity work with.

Explanation:

May you have a bless day. And send positive all over the world.

Answer:

8 N

Explanation:

Applying,

(F'+F) = ma............... Equation 1

Where F' = Amhed's force, F = Rashid's force, m = mass of the box, a = acceleration of the box.

From the question,

Given: F = 12 N, m = 4 kg, a = 5 m/s²

Substitute these values into equation 1

(F'+12) = 4×5

(F'+12) = 20

F' = 20-12

F' = 8 N.

Hence Ahmed's force is 8 N

(a) The direction of wave propagation is along the negative z-axis.

(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms.

(c) The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m

Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.

Hence, the direction of wave propagation for the given wave is along the negative z-axis.

To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:

E = c * H,

where c is the speed of light in the medium, which can be approximated as 3 × \(10^{8}\) m/s in free space.

(a) Direction of wave propagation: Along the positive z-axis.

(b) Calculating λ, f, and Er:

Since the electric field (E) is given as E = 50 sin (\(10^{8}\) + 2z) ay V/m, we can see that the angular frequency (ω) is \(10^{8}\) rad/s and the wave number (k) is 2.

The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.

Using the relation c = ω/k, we can solve for λ and f:

λ = 2π/k = 2π/2 = π m (meters)

f = ω/2π = \(10^{8}\)/2π ≈ 1.59 × \(10^{7}\) Hz (Hertz)

To find the wave impedance (Er), we can use the equation Er = E/H:

Er = E/c = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ≈ 0.1667 sin (\(10^{8}\) + 2z) ohms.

(c) The magnetic field (H) can be calculated using the relationship H = E/c:

H = (E/c) = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms. The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

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Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

Changing the green sum of forces arrow involves manipulating applied forces, frictional forces, and normal forces, allowing for adjustments in magnitude and direction through various means.

To change the green sum of forces arrow, you can employ the following three strategies:

Adjusting Applied Forces: By modifying the magnitude or direction of the applied forces, you can alter the green sum of forces arrow. If the applied forces are increased or directed in a different way, the green sum of forces arrow will change accordingly. For instance, increasing the magnitude of a pushing force will result in a larger green sum of forces arrow in that direction.

Modifying Frictional Forces: Frictional forces play a crucial role in determining the green sum of forces. By changing the coefficient of friction or applying lubricants, you can affect the magnitude of frictional forces acting on an object. Reducing friction will decrease the green sum of forces arrow, while increasing friction will have the opposite effect.

Varying Normal Forces: The green sum of forces arrow can be influenced by adjusting the normal forces acting on an object. Normal forces are perpendicular to the surface and counteract the weight of an object. By changing the angle or surface on which an object rests, you can modify the normal forces. This alteration will subsequently impact the green sum of forces arrow.

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Answer:The electrical current through the wires itself causes the home wiring to heat up. This is because as the electrons flow they come across the resistive forces of the medium's material, releasing energy that is expended in the form of heat energy

Explanation:

Answer: At such high frequencies it is very difficult for a sound wave to propagate efficiently; indeed, above a frequency of about 1.25 × 1013 hertz it is impossible for longitudinal waves to propagate at all, even in a liquid or a solid

a. Va-Vb= 0 volts

The two are perpendicular and therefore would have a difference of zero

b. Vc-Vb= -Ed

We already know V=Ed and in this case d is negative

c. -2.736 volts

(-7.2)*(.38)= -2.736

Plug in what was given for E and d into the equation for b

The problem is about the relation between electric field and potential difference. They both are related according to:

Vb -Va = - ∫ E× dl

The solution is:

a) V(B) - V(A)  = 0

c) V(C) - V(B) =  2.74 (V)

a) The segment AB is perpendicular to the lines of the electric field, then the point product is zero and V(B) - V(A) = 0

b) The segment CB is parallel to the lines of the electric field, and it is uniform, the:

V(C) - V(B) = - ∫₀⁰°³⁸ E × dl = E× d |₀⁰°³⁸ = - (7.2)×(0.38) = - 2.74 (V)

So the expression for the potential difference between point C and point B in terms of E and d is:

V(C) - V(B) = - ( E×d)

And finally     V(C) - V(B) =  2.74 (V)

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Answer:

Explanation:

Velocity measuring by m/s ,speed measuring by m/s,acceleration measuring by m/s² and velocity is vector physical quantity and speed is scalar physical quantity

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

The force applied to the system is equal to  203.703 N

Distance = 162cm to m = 162/1000 = 0.162m

Work done = 33J

Work can be calculated with the equation:

Work = Force × Distance.

Making Force the subject of the formula we have

Force = Work/Distance

Force = 33/0.162

Force = 203.703 N

The joule (J) or Newton meter (N m) is the SI unit for work. One joule is the amount of work done when one Newton of force moves an object one meter.

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Answer:

v = 60 m/s

final velocity after 20 seconds depends on how long it continues to accelerate after 20 seconds. Also we do not know the direction to complete the velocity requirements of a scalar value and direction component.

Explanation:

If we assume that the acceleration is constant

d = ½at² = ½(Δv/t)t² = ½Δvt = ½(v - 0)t = ½vt

v = 2d/t

v = 2(600)/20 = 60m/s

The gravitational potential energy (PE) of an object can be calculated using the formula:

PE = mgh

Where:

PE is the gravitational potential energy

m is the mass of the object

g is the acceleration due to gravity

h is the height or distance above the reference point (usually the ground)

In this case, you provided the weight of the object, which is 24 N. The weight of an object is the force due to gravity acting on it, and it can be calculated using the formula:

Weight = mg

Where:

Weight is the force due to gravity

m is the mass of the object

g is the acceleration due to gravity

Since you haven't provided the mass of the object, we can find it by rearranging the weight formula:

m = Weight / g

Now, we can calculate the mass of the object:

m = 24 N / 9.8 m/s² ≈ 2.45 kg

Now we have the mass (m = 2.45 kg), the height (h = 3.2 m), and the acceleration due to gravity (g ≈ 9.8 m/s²). Plugging these values into the formula for gravitational potential energy:

PE = mgh

= 2.45 kg × 9.8 m/s² × 3.2 m

≈ 76.736 J

Therefore, the gravitational potential energy of the object at a height of 3.2 m from the ground is approximately 76.736 joules (J).

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