A company finds that if it charges e dollars for a cell phone, it can expect to sell 1,000 - 2x phones. The company
uses the function - defined by r(t) = < (1,000 – 22) to model the expected revenue, in dollars, from selling cell
phones at dollars each.
Use graphing technology to graph the function r. At what price should the company sell their phones to get the
maximum revenue? Explain your reasoning.

The domain of a function {(x, y): x and y are real and 2x + 5y ≠ x}

The domain of a function represents the set of all possible input values for which the function is defined. In this case, the function is defined as z = (8x - y)/(2x + 5y - x).

To determine the domain, we need to consider any restrictions on the variables x and y. Looking at the given options, we can see that the correct answer is {(x, y): x and y are real and 2x + 5y - x ≠ 0}.

The expression 2x + 5y - x represents the denominator of the fraction in the function.

The denominator cannot be equal to zero, as division by zero is undefined.

Therefore, the domain excludes any values of x and y that make the denominator zero.

The given option {(x, y): x and y are real and 2x + 5y - x ≠ 0} captures this restriction and represents the correct domain for the function.

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The value of Steve's portfolio before the announcement was $52.15.

Let's denote the original value of Steve's portfolio before the announcement as "P".

The drop in the stock price is given as 6.75%, which means the stock price decreased by 6.75% from the original value.

To calculate the original value (P), we can use the following equation:

P - 6.75% of P = $48.62

P - (6.75/100) x P = $48.62

P - 0.0675P = $48.62

0.9325P = $48.62

P = $48.62 / 0.9325

P ≈ $52.15

Therefore, the value of Steve's portfolio before the announcement was $52.15.

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Answer:

364×180=65,520 baskets

Step-by-step explanation:

since its a leap year(4days as shown in the document)

2nd question:

365×180=65,700 baskets

since its not a leap year

if u dont know leap years end with an even number which is 364 and non leap years end with odd number which is 365.

Answer:

hello :

Step-by-step explanation:

x(x+3)(x+3)=0  means : x=0 or x+3=0 or x+3=0

x=0 or x=-3 or x=3

6000FT, is the shortest length of fence that the rancher can use.

Area is the total amount of space that an object's shape or a flat (2-D) surface occupy.

Create a square on paper by using a pencil. Two dimensions make it up. A shape's area on paper is the space it takes up.

Imagine that your square is made up of smaller unit squares.

The area of a figure is equal to the number of unit squares required to completely cover the surface area of a particular 2-D shape. Square cms, square feet, square inches, square meters, etc. are a few common units for measuring area.

To get the area of the square figures presented below, draw unit squares with 1-centimeter sides. Therefore, the shape will be measured.

According to our question-

Let the rectangular field's length be x.

rectangle field width = y

square feet of a rectangular field's area

Because length is always positive, it is always positive.

Once more, discriminate with respect to x

replace x=1500

Therefore, at x=1 500, fencing is minimal.

Change x to 1 500.

the rectangular field is 1500 feet long.

rectangle field's width is 1000 feet.

Replace the values

shortest used fence length =6000ft

Hence, 6000FT, is the shortest length of fence that the rancher can use.

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Answer:

it's the third one. x=47/3

Step-by-step explanation:

if needed in decimal form: 15.666

mixed number form: 15 2/3

Answer:

16

Step-by-step explanation:

separate into 4 triangles. 2x1= 2

triangle area formula= 1/2 l x w

3x4=12 12+4 is 16

Answer: 129.9

Step-by-step explanation:

tan 30 = 75/x

x = 75/tan 30

x = 129.9

Sheba's initial horizontal velocity (Vx) is approximately 7.81 m/s, and her initial vertical velocity (Vy) is approximately 4.09 m/s.

To analyze Sheba's motion during dock diving, we can break down her initial velocity into horizontal and vertical components.

Given an initial speed of 8.72 m/s and an angle of 28 degrees, we can calculate the horizontal and vertical velocities using trigonometry.

The horizontal velocity (Vx) can be found using the cosine function:

Vx = V * cos(angle)

Vx = 8.72 m/s * cos(28 degrees)

Vx ≈ 7.81 m/s

The vertical velocity (Vy) can be determined using the sine function:

Vy = V * sin(angle)

Vy = 8.72 m/s * sin(28 degrees)

Vy ≈ 4.09 m/s

So, Sheba's initial horizontal velocity (Vx) is approximately 7.81 m/s, and her initial vertical velocity (Vy) is approximately 4.09 m/s.

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The algorithm given in the question is essentially generating a sequence of random variables with a Bernoulli distribution with parameter p, where each random variable takes the value 1 with probability p and 0 with probability 1-p. The number X returned by the function X(p) is simply the sum of these Bernoulli random variables over 600 trials.

To determine the distribution of X(0.4), we need to find a continuous random variable that approximates its distribution the best. Since the sum of independent Bernoulli random variables follows a binomial distribution, we can use the normal approximation to the binomial distribution to find an appropriate continuous approximation.

The mean and variance of the binomial distribution are np and np(1-p), respectively. For p=0.4 and n=600, we have np=240 and np(1-p)=144. Therefore, we can approximate the distribution of X(0.4) using a normal distribution with mean 240 and standard deviation sqrt(144) = 12.

Therefore, the best continuous random variable that approximates the distribution of X(0.4) is Normal(240,12), which is one of the options given in the question. The other options, Poisson(240), Poisson(360), and Exponential(L), do not provide a good approximation for the distribution of X(0.4). Therefore, the answer is Normal(240,12).

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Answer:

Step-by-step explanation:

(-3 -5)/(0 - 4) = -8/-4 = 2

y - 5 = 2(x - 4)

y - 5 = 2x - 8

y = 2x - 3

answer is C

Answer:

deededededededededede

Step-by-step explanation:

dedededededededede

Answer:

5x+2

Step-by-step explanation:

6x-x=5x and 5-3=2

so 5x+2 is the answer.

Given:

Correct answer is

Final options are:

The first term should be positive.

She did not distribute the -4 properly.

Answer:

After Multiplying them.

we get 0 as an answer.

You can substitute any vector v to find its image under the transformation t.

By multiplying the transformation by the vector, we can determine the image of a given vector under the linear transformation t. Let's call the given vectors v1, v2, and v3, as well as the images that correspond to them, t(v1), t(v2), and t(v3), respectively.

Given:

t(1, 1, 1) = (2, 0, -1) t(0, -1, 2) = (-2, 5, -1) t(1, 0, 1) = (1, 1, 0) Using the information provided, we can construct a system of equations:

This system of equations can be represented as: x1(1, 1) + x2(0, -1, 2) + x3(1, 0, 1) = (2, 0, -1) y1(1, 1) + y2(0, -1, 2) + y3(1, 0, 1) = (-2, 5, -1) z1(1, 1) + z2(0, -1, 2) + z3(1, 0, 1) = (1, 1, 0)

| 1 0 1 | | x1 0 1 | | 2 0 -1 | | 1 -1 0 | = |-2 5 -1 | | 1 2 1 | | x3 2 1 | | 1 1 0 | We can use matrix inversion to solve this system. The matrix on the left will be referred to as A, and the matrix on the right will be referred to as B. A * X = B In order to determine X, we can multiply both sides of the equation by the inverse of A:

We have: A1 * A = A1 * B because A1 * A is the identity matrix.

Now that we know the inverse of A, we can find X by multiplying it by B: X = A * B.

We can use matrix row operations to reduce A to the identity matrix and keep track of the row operations performed to apply the same operations to the identity matrix. A = | 1 0 1 | | 1 -1 0 | | 1 2 1 |

| 1 0 1 | | 1 0 1 | | 1 -1 0 | | 1 2 1 | | 0 0 1 | | 0 0 1 | | 0 0 1 | | 0 0 1 | | 0 0 1 | | 0 0 1 | | 0 0 1 | | 0 0 1 | | 0 0 1 | The matrix A has been reduced to the identity matrix. As a result, A1 is:

A1 = | 1 0 0 | | 0 0 1 | Now, we can find X by multiplying A1 by B:

A * B = | 1 0 0 | | 2 0 -1 | | 0 0 1 | | 1 0 0 | = | 2 0 -1 | | 2 5 -1 | | 1 1 0 | The system of equations' solution reads as follows:

X = | 2 0 - 1 |

|-2 5 - 1 |

| 1 1 0 |

The picture of any vector under the direct change t can be gotten by increasing the vector by the grid X:

Any vector v can now be used to find its image under the transformation t if t(v) = X * v.

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The statement "P implies Q" is false under the following conditions: a) P is true and Q is false, and d) P is false and Q is true.

The statement "P implies Q" can be expressed as "if P, then Q." It is a conditional statement where P is the antecedent (the condition) and Q is the consequent (the result).

To determine when the statement is false, we need to identify cases where P is true but Q is false, or when P is false but Q is true.

Option a) states that both P and Q are true. In this case, the statement "P implies Q" holds true because if P is true, then Q is true.

Option b) states that both P and Q are false. In this case, the statement "P implies Q" is considered true because the antecedent (P) is false.

Option c) states that P is true and Q is false. Under this condition, the statement "P implies Q" is false because when P is true, but Q is false, the implication does not hold.

Option d) states that P is false and Q is true. In this case, the statement "P implies Q" is true because the antecedent (P) is false.

Therefore, the conditions under which the statement "P implies Q" is false are a) P is true and Q is false, and d) P is false and Q is true.

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(a)We know that fx(x,y) = k(x + y) and let Fy(y) be the marginal distribution of Y.

Then, we have Fy(y) = P(Y ≤ y)

Fx,y(x,y) = P(Y ≤ y)P(X ≤ x|Y = y)

Fx(x,y) = P(X ≤ x|Y = y)Fx(x,y)dx

Now, P(X ≤ x|Y = y) = P(X ≤ x, Y = y)/P(Y = y) = Fx,y(x,y)/Fy(y)

Fy(y) = ∫0^1

Fx,y(x,y)dx = ∫0^1k(x+y)dx= ky + ky/2= 3ky/2fy(y) = d

Fy(y)/dy= 3k/2, 0 < y < 1

(b) For 0 < x < 1, we haveFx,y(x,y) = k(x + y)Fy(y) = ∫0^1Fx,y(x,y)dx = ∫0^1k(x+y)dx = k/2 + ky/2 = (k/2)(1 + y)P(Y > X[x]) = ∫xp(y > x)dx= ∫x^11/2(1+y)dy= x + (x^2)/4, 0 < x < 1

(c) We have P(Y > X) = ∫0^1P(Y > X[x])fx(x)dx= ∫0^11/2(k/2)(1 + x)k(x + 1)dx= (3k^2)/8

(d) E[Y|X = x] = ∫0^1yfx|Y(x,y)dy/∫0^1fx|Y(x,y)dy= ∫0^1yk(x+y)dy/∫0^1k(x+y)dy= (kx + 1)/2

E[YX = x] = ∫0^1E[Y|X = x]fx(x)dx= ∫0^1[(kx + 1)/2]k(x + 1)dx= (5k)/8

E[YX = x] = 5/8.

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To reduce the third-order ordinary differential equation y - y" - 4y + 4y = 0 into a companion system of linear equations, we introduce new variables u and v:

Let u = y,

v = y',

w = y".

Taking the derivatives of u, v, and w with respect to the independent variable (let's denote it as x), we have:

du/dx = y' = v,

dv/dx = y" = w,

dw/dx = y"'.

Now we can rewrite the given differential equation in terms of u, v, and w:

u - w - 4u + 4u = 0.

Simplifying the equation, we get:

-3u - w = 0.

This equation can be expressed as a system of first-order linear differential equations as follows:

du/dx = v,

dv/dx = w,

dw/dx = -3u - w.

Now we have a companion system of linear equations:

du/dx = v,

dv/dx = w,

dw/dx = -3u - w.

To solve this system completely, we need to find the solutions for u, v, and w. By solving the system of differential equations, we can obtain the solutions for u(x), v(x), and w(x), which will correspond to the solutions for y(x), y'(x), and y"(x), respectively.

The exact solutions for this system of differential equations depend on the initial conditions or boundary conditions that are given. By applying appropriate initial conditions, we can determine the specific solution to the system.

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Filling in the missing expenditure values in the table is as follows:

May                      June        July            August        Sept.       Total  Average        

$640.00           $710.00    $700.00     $685.00    $705.00  3,440    688.00          

$1,178.50       $1,091.80   $1,207.70    $1,187.80  $1,245.90 5,911.70 1,182.34

$1,789.75       $1,741.36   $1,707.85    $1,751.63    $1,811.75 8,802.34 1,760.47

$2,311.75       $2,210.91   $2,371.85  $2,553.67  $2,412.91 11,861.09 2,372.22

$112.11                $97.13      $106.45       $121.85   $220.02 $545.45 $109.09

$23,687.12 $19,871.03 $20,056.90 $24,510.30 19,892.25 $108,017.60 $21,603.52

The missing expenditure values can be determined using the mathematical operation of addition and subtraction.

The total values are computed using addition.  Some of the total values are computed based on the averages, which are multiplied by 5.

The average refers to the quotient of the total values divided by 5.

September:

a. Average = $109.09

Total = $545.45 ($109.09 x 5)

September 'a' = $220.02 ($545.45 - $97.13 - $106.45 - $121.85)

September:

Average = $21,603.52

Total = $108,017.60 ($21,603.52 x 5)

September 'a' = $19,892.25 ($108,017.60 - $23,687.12 - $19,871.03 - $20,056.90 - $24,510.30)

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 May                      June        July            August        Sept.    Total   Average        

$640.00           $710.00      $700.00     $685.00    $705.00    a.              b.

$1,178.50       $1,091.80     $1,207.70    $1,187.80  $1,245.90    a.              b.

$1,789.75       $1,741.36     $1,707.85    $1,751.63    $1,811.75    a.              b.

$2,311.75       $2,210.91     $2,371.85  $2,553.67  $2,412.91     a.              b.

$112.11                $97.13        $106.45       $121.85   a.                 b.       $109.09

$23,687.12 $19,871.03 $20,056.90 $24,510.30   a.                 b.  $21,603.52

True, Alyssa is learning to drive and is paying close attention to the road conditions, other vehicles on the road, and traffic signs and signals. This focus is a quality of hers.

What is Focus during the Drive?

It means to concentrate only on driving during the time of driving to avoid accidents etc. Yeah when she is driving the car she must focus intently on car and on nothing else because she is a beginner. When people get experience in driving cars they use mobile phones etc kind of things easily during driving but beginners have to be careful a lot regarding this. Its very very good if she is also focusing road signs like zebra crossing and where traffic signals are there it would help her in great way

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Answer:

Step-by-step explanation:

Equation are true:

C.

(3⁴)·(3⁵) = 3⁽⁴⁺⁵⁾ = 3⁹

D.

\(( 8^6 = \frac{1}{8^{-6}} )\)

Answer:

C and D

Step-by-step explanation:

Steps for C:

Step 1: Combine exponent terms on left side
\(4+5=9\)

Leave the base the same.

\(3^9=3^9\)

\(True\)

Steps for D:

Step 1: Simplify left side

\(\frac{1}{8^{-6} }=\frac{1/1}{262144} =262144\)

Step 2: Simplify right side

\(8^6=262144\)

\(262144=262144\)

\(True\)

Hope this helps :)

Below is the answer

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Answer:

---------------------------------

Add 10% to the given price.

a) The normal price is £210, then 10% of it is £21.

Hence new price is:

b) The normal price is £48, then 10% of it is £4.80.

Hence new price is:

The ascending order of the given numbers is  2×\(10^{-4}\) <0.004< 4×\(10^{-2}\) < 0.042 < 0.24

The first number = 0.24

The second number = 4×\(10^{-2}\)

The second number is the form of scientific notation. To compare the numbers, all the numbers should be in same form. So we have to convert the scientific notation to the decimal form

4×\(10^{-2}\) = 0.04

The third number = 0.042

Third number is decimal form

The fourth number = 2×\(10^{-4}\)

Convert the scientific notation to the decimal form

2×\(10^{-4}\) = 0.0002

The fifth number = 0.004

The order of the numbers from least to greatest

= 2×\(10^{-4}\) <0.004< 4×\(10^{-2}\) < 0.042 < 0.24

Hence, the order of the given numbers from least to greatest is 2×\(10^{-4}\) <0.004< 4×\(10^{-2}\) < 0.042 < 0.24

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Answer:

the answer is 2119

Step-by-step explanation:

1+1=1

F; T; T; T; F; T; F; F;T; T. The rate of exchange between certain future dollars and current dollars is known as the forward exchange rate, not the pure rate of interest.

This statement accurately describes the concept of an investment, including the factors that compensate the investor. A dollar received today is worth more than the same dollar received in the future due to the time value of money. The three components mentioned (nominal interest rate, inflation premium, and risk premium) are indeed the components of the required rate of return. Financial intermediaries are not specifically related to primary capital markets. They facilitate transactions between savers and borrowers but may operate in various markets. Diversification with foreign securities can indeed help reduce portfolio risk by spreading exposure to different markets.

The total domestic return on German bonds is not the return experienced by a U.S. investor, as it would include exchange rate effects. A negative exchange rate effect for Japanese bonds would mean that the domestic rate of return is lower than the U.S. dollar return, not greater. The gifting phase and the spending phase can indeed be concurrent, such as when gifts are given for specific expenses. Long-term, high-priority goals often include working towards financial independence as a key objective.

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