A function f: (a,b)R satisfies a Holder condition of order if >0 and for some positive constant C and all x,y(a,b) wehave|f(x)f(y)|C|xy|(a) Prove that an -Holder function

we have shown that for any arbitrary x, y (a, b), the inequality |f(x) - f(y)| C|x - y|^ holds for some positive constant C, which proves that f is an -Holder function.To prove that an -Holder function satisfies the given condition, we need to show that for some positive constant C and all x, y (a, b), we have |f(x) - f(y)| C|x - y|^.Let's assume that f is an -Holder function, where > 0. This means there exists a positive constant C such that for all x, y (a, b), we have |f(x) - f(y)| C|x - y|^.We want to prove that this inequality holds for any arbitrary x, y (a, b).Consider any x, y (a, b). Without loss of generality, assume x > y (if x y, the proof is similar by interchanging the roles of x and y).We have:|f(x) - f(y)| C|x - y|^.Dividing both sides by |x - y| gives:[tex]|f(x) - f(y)| / |x - y| \leq C|x - y|^{(\alpha -1)}.[/tex]Since > 0, - 1 > -1. Therefore, we can write - 1 = , where > -1.Now, let's consider the function g(t) = |f(t) - f(y)| / |t - y|. This function is well-defined for all t y since dividing by |t - y| ensures that t y.We can rewrite the above inequality as:[tex]g(x) \leq C|x - y|^\beta[/tex].Since > -1, we know that |x - y| > 0 for all x, y (a, b).Now, let's consider the limit of g(t) as t approaches y. Since f is continuous, we have:lim(ty) f(t) = f(y).Similarly, we have:lim(ty) |t - y| = 0.Therefore, taking the limit as t approaches y on both sides of the inequality [tex]g(x) \leq C|x - y|^\beta[/tex], we get:lim(ty) g(t) C lim(ty) |t - y|^.Simplifying, we have:[tex]|f(y) - f(y)| / |y - y|\leq C |y - y|^{\beta }[/tex],0 0.Since the right-hand side of the inequality is zero, the left-hand side must also be zero, which implies:0 0.This inequality holds for any y (a, b).To know more about function visit:brainly.com/question/30721594#SPJ11

Mathematics High School

A function f: (a,b)→R satisfies a Holder condition of order α if
α >0 and for some positive constant C and all x,y∈(a,b) we
have|f(x)−f(y)|≤C|x−y|α
(a) Prove that an α-Holder function

Answers

Answer 1

we have shown that for any arbitrary x, y ∈ (a, b), the inequality |f(x) - f(y)| ≤ C|x - y|^α holds for some positive constant C, which proves that f is an α-Holder function.

To prove that an α-Holder function satisfies the given condition, we need to show that for some positive constant C and all x, y ∈ (a, b), we have |f(x) - f(y)| ≤ C|x - y|^α.

Let's assume that f is an α-Holder function, where α > 0. This means there exists a positive constant C such that for all x, y ∈ (a, b), we have |f(x) - f(y)| ≤ C|x - y|^α.

We want to prove that this inequality holds for any arbitrary x, y ∈ (a, b).

Consider any x, y ∈ (a, b). Without loss of generality, assume x > y (if x ≤ y, the proof is similar by interchanging the roles of x and y).

We have:

|f(x) - f(y)| ≤ C|x - y|^α.

Dividing both sides by |x - y| gives:

$|f(x) - f(y)| / |x - y| \leq C|x - y|^{(\alpha -1)}.$

Since α > 0, α - 1 > -1. Therefore, we can write α - 1 = β, where β > -1.

Now, let's consider the function g(t) = |f(t) - f(y)| / |t - y|. This function is well-defined for all t ≠ y since dividing by |t - y| ensures that t ≠ y.

We can rewrite the above inequality as:

$g(x) \leq C|x - y|^\beta$.

Since β > -1, we know that |x - y| > 0 for all x, y ∈ (a, b).

Now, let's consider the limit of g(t) as t approaches y. Since f is continuous, we have:

lim(t→y) f(t) = f(y).

Similarly, we have:

lim(t→y) |t - y| = 0.

Therefore, taking the limit as t approaches y on both sides of the inequality $g(x) \leq C|x - y|^\beta$, we get:

lim(t→y) g(t) ≤ C lim(t→y) |t - y|^β.

Simplifying, we have:

$|f(y) - f(y)| / |y - y|\leq C |y - y|^{\beta }$,

0 ≤ 0.

Since the right-hand side of the inequality is zero, the left-hand side must also be zero, which implies:

0 ≤ 0.

This inequality holds for any y ∈ (a, b).

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Related Questions

the alexander family and the chen family each used their sprinklers last summer. the water output rate for the alexander family's sprinkler was 30l per hour. the water output rate for the chen family's sprinkler was 40l per hour. the families used their sprinklers for a combined total of 65 hours, resulting in a total water output of 2250l. how long was each sprinkler used?

Answers

The Alexander family used their sprinkler for 35 hours, and the Chen family used their sprinkler for 30 hours.

To find out how long each sprinkler was used, we can set up a system of equations. Let's say the Alexander family used their sprinkler for x hours, and the Chen family used their sprinkler for y hours.

From the given information, we know that the water output rate for the Alexander family's sprinkler is 30 liters per hour. Therefore, the total water output from their sprinkler is 30x liters.

Similarly, the water output rate for the Chen family's sprinkler is 40 liters per hour, resulting in a total water output of 40y liters.

Since the combined total water output from both sprinklers is 2250 liters, we can set up the equation 30x + 40y = 2250.

We also know that the families used their sprinklers for a combined total of 65 hours, so we can set up the equation x + y = 65.

Now we can solve this system of equations to find the values of x and y, which represent the number of hours each sprinkler was used.

By solving the equation we get,

The Alexander family used their sprinkler for 35 hours, and the Chen family used their sprinkler for 30 hours.

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What is the height of the cone if its volune is 8,138.88 feet CUBED? Use 3.14 for pi. (Radius of base of cone is 12 ft)

Answers

Answer:

h = 54 feet

Step-by-step explanation:

The equation for the volume of a cone is V = $\frac{1}{3}$ × π × r² × h.

You have the volume, which is 8,138.88, and the radius of the base, which is 12.

V = 8,138.88

h = 12

π = 3.14

When you plug everything you know into the equation, you get:

V = $\frac{1}{3}$ × 3.14 × r² × h.

8,138.88 = $\frac{1}{3}$ × 3.14 × (12)² × h

After you multiply everything on the right side, you come out with:

8,138.88 = 150.72 × h

To find h, you can divide each side by 150.72.

8,138.88 ÷ 150.72 = 54 feet!

If P(A) = 0.58, P(B) = 0.44, and P(A ? B) = 0.25, then P(A ? B) = a. 0.11. b. 0.77. c. 0.39. d. 1.02.

Answers

The probability of either A or B occurring (or both) is 0.11. The correct answer is A.

We know that:

P(A) = 0.58

P(B) = 0.44

P(A ∩ B) = 0.25

We can use the formula:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

to find P(A ∪ B), which is the probability of either A or B occurring (or both). Substituting the given values, we get:

P(A ∪ B) = 0.58 + 0.44 - 0.25

= 0.77

We also know that:

P(A ∩ B) = P(A) + P(B) - P(A ∪ B)

Substituting the values we know, we get:

0.25 = 0.58 + 0.44 - P(A ∪ B)

Solving for P(A ∪ B), we get:

P(A ∪ B) = 0.58 + 0.44 - 0.25

= 0.77

Therefore, we have:

P(A ∩ B) = 0.25

P(A ∪ B) = 0.77

Using the formula:

P(A ∩ B) = P(A) + P(B) - P(A ∪ B)

we can find P(A ∩ B) as:

0.25 = 0.58 + 0.44 - 0.77 - P(A ∩ B)

Solving for P(A ∩ B), we get:

P(A ∩ B) = 0.11

Therefore, the answer is (a) 0.11.

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The temperature drops an average of 1 degree celsius for every 100 meters that a hot air ballon rises. If the temperature is 25 degrees celsius on the ground, what is the approximate temperature 1200 meters above ground.

Answers

The required temperature at the height of 1200 meters is 13 degree Celcius.

Given that,
Temperature drops an average of 1 degree celsius for every 100 meters that a hot air balloon rises.
The temperature is 25 degrees celsius on the ground.
The approximate temperature is 1200 meters above the ground is to be determined.

What are functions?

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

The expression of for temperature drops an average of 1-degree celsius for every 100 meters that a hot air balloon rises.
Let x be the height in meters and y be the temperature in degrees celcius
y = -x/100 + 25
For temperature 1200 meters above ground
x = 1200
y = -1200/100 + 25
y = -12 + 25
y = 13

Thus, the required temperature at the height of 1200 meters is 13 degrees Celcius.

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A line passes through the point (4, -6) and has a slope of -2. Which is the equation of the line?
O y=-x-3
O y--RX-6
O y=-3x-
O y=-x-
o ya
-

Answers

Answer:

The posted photo says the slope is -(3/4). I'll use that, instead of -2 as written in the question.

Step-by-step explanation:

The slope-intercept form of a straight line equation is y = mx+b, where m is the slope and b the y-intercept (the value of y when x=0).

With a slope of -(3/4), we can write: y = -(3/4)x + b.

To find b, use the given point (4,-6):

y = -(3/4)x + b

-6 = -(3/4)(4) + b for (4,-6)

-6 = -3 + b

b = -3

The line is y = -(3/4)x - 3

The first option.

helpppppppppppppp make your answer clear please ( no links)

Answers

The answer is: 312 (Squared)

Step-by-step explanation:

(2×6 is 12. 12×2 is 24. Top and Bottom)

(12×6 is 72. 72×4 is 288. Both sides+Front and back)

(Adding those up would be: 288+24 = 312)

brittany has a black skirt, a violet skirt, a white skirt, and a red skirt. she has a yellow top, a pink top, and a green top. she wants to wear a skirt and a top. what are all the possible outcomes? how many possible outcomes are in the sample space?

Answers

There are a total of 12 possible outcomes in the sample space.

The possible outcomes of Brittany wearing a skirt and a top can be determined by considering all the combinations of skirts and tops.

Skirts: Black, Violet, White, Red

Tops: Yellow, Pink, Green

The possible outcomes are as follows:

Black skirt and yellow top

Black skirt and pink top

Black skirt and green top

Violet skirt and yellow top

Violet skirt and pink top

Violet skirt and green top

White skirt and yellow top

White skirt and pink top

White skirt and green top

Red skirt and yellow top

Red skirt and pink top

Red skirt and green top

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A grocer makes a graph of how many bananas are sold at different stores on Tuesday.

How many total bananas did the stores sell on tuesday?

Answers

Answer:

Step-by-step explanation:

Total of banana

symbols=4.5+6+3+2.5=16

total bananas=16×6=96

When you use a timer, you need to define a class that implements the ____ interface.
TimerListener
TimerActionListener
ActionListener
StartTimerListener

Answers

When you use a timer, you need to define a class that implements the ActionListener interface.

Here's a step-by-step explanation:

STEP 1: Create a class.
STEP 2: Implement the ActionListener interface in your class.
STEP 3: Define the actionPerformed() method, which will be called when the timer triggers an event.
STEP 4: Create an instance of the Timer class and pass in the required parameters, such as delay and your ActionListener.
STEP 5: Start the timer using the start() method.

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What is the inverse of y = x2 + 16

Answers

y=x2-16
I’m not sure if I’m right or not

Answer:

$ {y}^{ - 1} = \sqrt{x - 16} $

Step-by-step explanation:

To find the inverse of this function, we make "x" the subject of the equation .$y = {x}^{2} + 16 \\ {x}^{2} = y - 16 \\ x = \sqrt{y - 16} $then we interchange "y" and "x" .$hence \: the \: inverse \: is \\ {y}^{ - 1} = \sqrt{x - 16} $

Express each of the following recurring decimals as a rational number first one 0. 5 second 10. 3 third 10. 34

Answers

Recurring decimal: 0.5

The recurring decimal 0.5 can be expressed as a rational number, which is 1/2.

Recurring decimal: 10.3 The recurring decimal 10.3 can be expressed as a rational number, which is 103/10.

Recurring decimal: 10.34

The recurring decimal 10.34 can be expressed as a rational number, which is 1034/100.

Recurring decimal: 0.5

A recurring decimal is a decimal representation of a fraction where one or more digits repeat indefinitely. In the case of 0.5, it can be rewritten as 1/2. This is because 0.5 is equivalent to the fraction 1/2, where the numerator is 1 and the denominator is 2. Therefore, the rational representation of 0.5 is 1/2.

Recurring decimal: 10.3

Explanation: To convert 10.3 to a rational number, we can consider it as a mixed fraction. The integer part is 10, and the decimal part is 0.3. Since 0.3 is equivalent to the fraction 3/10, we can combine it with the integer part to get 10 3/10. This can be further simplified to an improper fraction as 103/10. Therefore, the rational representation of 10.3 is 103/10.

Recurring decimal: 10.34

Explanation: Similar to the previous case, we can consider 10.34 as a mixed fraction. The integer part is 10, and the decimal part is 0.34. The fraction equivalent of 0.34 is 34/100. Combining the integer part and the fraction, we get 10 34/100. This can be simplified to 10 17/50. Finally, we can express it as an improper fraction, which is 1034/100. Therefore, the rational representation of 10.34 is 1034/100.

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as you consider the various factors involved in starting a group, what is the most important factor you have to judge?

Answers

As you consider the various factors involved in starting a group, the most important factor you have to judge is the group's purpose or goal.

Step 1: Identify the group's purpose or goal - This is crucial because it will guide all other decisions, including membership criteria, communication methods, and meeting schedules.

Step 2: Assess the needs and resources of potential members - This will help you understand their motivations and ensure the group can support their needs while accomplishing its goal.

Step 3: Establish clear membership criteria and expectations - This will ensure that everyone in the group is on the same page and committed to the same goals.

Step 4: Choose an appropriate communication method - This will facilitate smooth and efficient communication among group members.

Step 5: Develop a meeting schedule that works for all members - Regular meetings help keep the group on track and provide opportunities for collaboration and feedback.

By focusing on the group's purpose or goal, you can create a solid foundation for a successful and productive group.

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A baseball diamond has the shape of a square 90 feet on each side.
The pitcher's mound is 60.5 feet from home plate on the segment
joining home plate and second base. Find the distance from the
pitcher's mound to second base to the nearest tenth of a foot. Show work

Answers

The distance from the pitcher's mound to second base is 63.7 feet.

How to calculate the distance?

Call the distance from the pitcher's mound to first base "x".

x² =60.5² +90²-2(60.5)(90)cos45°

x² =3660.25+8100-10,890(0.70710678)

x² = 11,760.25-7700.392

x²=4059.858

take the square root of both sides

x=63.717015

x=63.7 feet

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3/7+2/7=
5/7
5/24
2/3
1/7

Answers

Answer:

$ \frac{5}{7} = 0.71$

Step-by-step explanation:

$1. \: \frac{3 + 2}{7} \\ 2. \: \frac{5}{7} = 0.71$

On a number line ,4.1 would be located. choose all answers that make a true statement.

A. To the right of 4.5

B. between 5 and 6

C. to the left of 4.19

D. To the left of 4.4
Help me plz

Answers

Answer:

Step-by-step explanation:

D. To the left of 4.4.

The lower the number, the more left it will be, the higher the number, the more right it will be.

What is the formula for the volume of a cylinder? (Use the word Pi instead of the symbol)

Answers

Answer:

pi x radius x 2 x height of the cylinder.

Multiply both sides of the equation by the same expression: ×(a−d)=×(−bc) The resulting equation is: c=

Answers

The resulting equation is c = -b(a - d).

To multiply both sides of the equation ×(a−d)=×(−bc) by the same expression, we apply the distributive property. This allows us to multiply each term on both sides of the equation by the expression ×.

Starting with the left side of the equation:

×(a−d) simplifies to ×a - ×d.

Next, we move to the right side of the equation:

×(−bc) simplifies to -b×c.

Now, we have the equation ×a - ×d = -b×c.

To find the resulting equation in terms of c, we can divide both sides of the equation by -b. This gives us:

(×a - ×d) / -b = c.

Simplifying further, we have:

c = -b(a - d).

Therefore, the resulting equation is c = -b(a - d).

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2 A customer applied for a loan for $15,000 to buy a motorcycle. The customer qualified for different loan options. Which loan option would allow the customer to pay the least amount of interest? (A A 3-year loan with an 7% annual simple interest rate B A 4-year loan with a 5% annual simple interest rate CA 5-year loan with a 4.5% annual simple interest rate A 6-year loan with a 3.7% annual simple interest rate

Answers

From the calculations, the best loan option is

A. 3-year loan with a 7% annual simple interest rate

How to find a better loan option

To determine which loan option would allow the customer to pay the least amount of interest, we need to compare the amount of interest charged by each loan option.

For the 3-year loan with a 7% annual simple interest rate,

the interest charged would be $15,000 x 7% x 3 = $2,550.

For the 4-year loan with a 5% annual simple interest rate,

the interest charged would be $15,000 x 5% x 4 = $3,000.

For the 5-year loan with a 4.5% annual simple interest rate,

the interest charged would be $15,000 x 4.5% x 5 = $3,375.

For the 6-year loan with a 3.7% annual simple interest rate,

the interest charged would be $15,000 x 3.7% x 6 = $3,870.

From the calculations, it is clear that the 3-year loan with a 7% annual simple interest rate would result in the least amount of interest charged, with $2,550.

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blank ÷ 3/7= 7/15.

Answers

Answer:

1 4/45

Step-by-step explanation:

You've decided to take
3
33 steps and randomly choose left or right as the direction each time.
Which of these tables lists all possible outcomes of your random walk? (Each row represents one outcome.)
Choose all answers that apply:
Choose all answers that apply:
(Choice A) Table A
A
Table A
(Choice B) Table B
B
Table B
Table A:
First Second Third
Left Left Left
Left Left Right
Left Right Left
Left Right Right
Right Left Left
Right Left Right
Right Right Left
Right Right Right
Table B:
First Second Third
Right Right Right
Left Right Right
Right Left Right
Left Left Right
Right Right Left
Left Right Left
Right Left Left
Left Left Left
Report a problem

Answers

Both tables represent valid sample spaces for the given random walk scenario.

The tables A and B provided represent different sample spaces for the random walk with three steps, where the direction can be randomly chosen as either left or right at each step.

Table A:

- First row: The outcomes for each step are Left, Left, Left.

- Second row: The outcomes for each step are Left, Left, Right.

- Third row: The outcomes for each step are Left, Right, Left.

- Fourth row: The outcomes for each step are Left, Right, Right.

- Fifth row: The outcomes for each step are Right, Left, Left.

- Sixth row: The outcomes for each step are Right, Left, Right.

- Seventh row: The outcomes for each step are Right, Right, Left.

- Eighth row: The outcomes for each step are Right, Right, Right.

Table B:

- First row: The outcomes for each step are Right, Left, Right.

- Second row: The outcomes for each step are Right, Right, Left.

- Third row: The outcomes for each step are Right, Right, Right.

- Fourth row: The outcomes for each step are Right, Left, Left.

- Fifth row: The outcomes for each step are Right, Right, Left.

- Sixth row: The outcomes for each step are Left, Left, Left.

- Seventh row: The outcomes for each step are Left, Left, Left.

- Eighth row: The outcomes for each step are Left, Left, Left.

Both tables provide all possible outcomes for the random walk with three steps and randomly choosing left or right at each step.

However, Table A and Table B have different sequences of outcomes for each row. Therefore, both tables represent valid sample spaces for the given random walk scenario.

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The probable question may be:

"You've decided to take 3 steps and randomly choose left or right as the direction each time. Which of these tables lists all possible outcomes of your random walk? (Each row represents one outcome.) Choose all answers that apply:

Sample spaces for compound

TABLE A:-

First= Left,Left,Left,Left,Right,Right,Right,Right.

Second= Left,Left,Right,Right,Left,Left,Right,Right.

Third= Left,Right,Left,Right,Left,Right,Left.

TABLE B:-

First= Right,Left,Right,Left,Right,Left,Right,Left.

Second= Right,Right,Left,Left,Right,Right,Left,Left.

Third= Right,Right,Right,Right,Left,Left,Left,Left.

You have a standard deck of 52 cards. Find the probability of drawing one card, then drawing another without replacement.
A) You draw an even-numbered card and then a face card.
B) Both cards you drew are "4" or higher (if aces are considered low cards and face cards are nonnumerical)
C) You drew a black face card and then a black "5".

Answers

Assuming that the all the cards have the same probability of being drawn we get:

A) P = 0.07B) P = 0.21C) P = 0.001

How to find the probabilities?

We have a deck of 52 cards.

A) The probability of drawing an even-numbered card is given by the quotient between the number of even-numbered cards and the total number of cards.

On the 52 card deck, there are 16 even cards (2, 4, 6, 8 for each type), so the probability is:

p = 16/52

Then the probability of drawing a face card is given in the same way, notice that now there are 51 cards in the deck and 12 face cards, so we get:

q = 12/51

The joint probability is the product of these two:

P = (16/52)*(12/51) = 0.07

b) Both cards are 4 or larger.

There are 6 cards equal or larger than 4 for each type, so the probability for the first card is:

p = 24/52

For the second card, there is one card less in the deck (and one card less that is equal or larger than 4) so the probability is:

q = 23/51

The joint probability is:

P = (24/52)*(23/51) = 0.21

C) There are 6 black face cards, so the probability first is:

p = 6/52

Then there are 2 black cards with the number 5, so the probability is:

q = 2/51

The joint probability is:

P = (6/52)*(2/51) = 0.001

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Consider the standard normal curve. Answer parts (a) and (b). 2(a). Round your answers to 3 decimal places. Find 13th percentile: Find 80th percentile: Find Q, Find Q3

Answers

The standard normal curve can be described as a bell-shaped curve or Gaussian distribution. It is used to model a variety of phenomena in many fields, including physics, finance, and engineering. Its mean is zero, and its standard deviation is one.

The standard normal curve is symmetrical about the mean and is characterized by the empirical rule. The majority of the population is distributed within one, two, and three standard deviations from the mean (68%, 95%, and 99.7%, respectively).

Part a)13th percentile can be calculated using the standard normal distribution tables. From the tables, the value of z when the area under the curve to the left of z is 0.13 is -1.04. Therefore, the 13th percentile is -1.04. 80th percentile can be calculated in the same way as 13th percentile.

The value of z when the area under the curve to the left of z is 0.8 is 0.84. Therefore, the 80th percentile is 0.84.Part b)The values of Q and Q3 cannot be obtained from the standard normal curve since the standard normal curve is not used to study a particular set of data.

It is used to model phenomena with a normal distribution with a mean of zero and a standard deviation of one. Instead, the quartiles can be calculated using the empirical rule in conjunction with the normal distribution tables.

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A rectangular storage container without a lid is to have a volume of 10 m3. The length of its base is twice the width. Material for the base costs $5 per square meter. Material for the sides costs $3 per square meter. Let w denote the width of the base.Find a function in the variable w giving the cost C (in dollars) of constructing the box.

Answers

The cost of constructing the box will be = $81.77

Since the question gives us information about the rectangle,

so the area of the rectangle is shown by,

Area = 2 x (length + width)

So we have the area as,

Area = 2(lh + wh) +lw

(since the area per square meter is also given so we added l x w)

Since the cost of the base is = $5 per square meter and the cost of the sides is = $3 per square meter, so area in terms of the cost function,

⇒ C = 3 x 2(lh + wh) + 5 x l x w

⇒ C = 6(lh + wh) +5lw ---------equation 1

According to the question, the length of the rectangular container is twice that of the width of the container,

⇒ l = 2w

Substituting the new value of l in equation 1,

⇒ C = 6(2wh + wh) + 10 $w^{2}$

⇒ C = 18wh + 10 $w^{2}$ ---------- equation 2

To calculate the volume of the rectangle,

V = length x width x height ( lwh )

substituting v = 10 and 2w = l,

2$w^{2}$h = 10

h = $\frac{5}{w^{2} }$

Substitute the value of h in equation 2,

⇒ C = 18w x $\frac{5}{w^{2} }$ + 10$w^{2}$

⇒ C = $\frac{90}{w}$ + 10$w^{2}$ --------- equation 3

Differentiating the above equation we get,

⇒ C* = - $\frac{90}{w^{2} }$ + 20w

⇒ 20w = $\frac{90}{w^{2} }$

Multiply both sides by $w^{3}$

⇒ $20w^{3}$ = 90

⇒ $w^{3}$ = 4.5

w = 1.65

Put the value of w in equation 3,

⇒ C = $\frac{90}{1.65}$ + 10 x $1.65^{2}$

⇒ C = 81.77

Therefore, The cost of constructing the box will be = $81.77

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I need help with my Alg 2 work.
Help quickly if possible.
Thanks.

Answers

Positive value of a vertically stretches the graph of f when a > 1 or shrinks the graph of f when a < 1. h translates the graph of f to the left when h < 0 or right when h > 0.

What are some examples of how exponential functions are employed in mathematics and in real life?

Several real-world scenarios use exponential functions, including population increase, compound interest, radioactive decay, and the spread of diseases. For instance, an exponential function may be used to simulate the expansion of a bacterial population, with the rate of increase being proportional to the population size. Similarly, compound interest, which applies the rate of interest to the principal sum across a number of periods, can be represented by an exponential function.

Positive value of a vertically stretches the graph of f when a > 1 or shrinks the graph of f when a < 1. h translates the graph of f to the left when h < 0 or right when h > 0 and k translates the graph of f up when k > 0 and down when k < 0.

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4-1/4 help please guys

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Answer:

Step-by-step explanation:

3.75

What numbers are NOT possible products for 28 X 15

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Any number beside 420

What is the area of a square with one side length of 5x³

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Answer:

The area of square is 25x⁶.

Step-by-step explanation:

Given:

Side of square: 5x³Area of square: s²

Work:

=> (5x³)²=> 5x³ × 5x³=> 25x³⁺³=> 25x⁶

Hence, the area of square is 25x⁶.

Hoped this helped.

$BrainiacUser1357$

50 to 60 as a fraction in simplest form

Answers

Answer:

5/6

Step-by-step explanation:

50/60 in simplest form is 5/6

You would divide both sides by 10

The simplified expression of the expression 50 to 60 is 5/6

How to simplify the expression

From the question, we have the following parameters that can be used in our computation:

50 to 60

Express as equation

50 to 60 = 50/60

Divide 50 by 60

So, we have the following representation

50 to 60 = 5/6

Using the above as a guide, we have the following:

The expression cannot be further simplified

Hence, the simplified expression is 5/6

Answers

Answer:

g(x)=x+1 or g(x)=-x-1

Step-by-step explanation:

f of g(x)=f(g(x))=$x^{2} +2x+1$, and f(x) =$x^{2}$, so

$(g(x))^{2}$=$x^{2} +2x+1$=$(x+1)^{2}$

g(x)=x+1 or g(x)=-(x+1)=-x-1

Identify a CSS3 2D transformation function that resizes an object by a factor of x horizontally.
a. scaleY(y)
b. rotate(angleY)
c. translateY(offY)
d. skewY(angleY)

Answers

The correct answer is not listed among the given options. None of the listed options is a CSS3 2D transformation function that resizes an object by a factor of x horizontally.

Here are brief explanations of the given options:

a. scaleY(y) - This function scales an object vertically by a factor of y.

b. rotate(angleY) - This function rotates an object around the y-axis by the specified angle.

c. translateY(offY) - This function translates an object vertically by the specified offset.

d. skewY(angleY) - This function skews an object along the y-axis by the specified angle.

To resize an object horizontally by a factor of x, you can use the scaleX(x) function. This function scales an object horizontally by a factor of x.

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A function f: (a,b)→R satisfies a Holder condition of order α if α >0 and for some positive constant C and all x,y∈(a,b) we have|f(x)−f(y)|≤C|x−y|α (a) Prove that an α-Holder function

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A function f: (a,b)→R satisfies a Holder condition of order α if
α >0 and for some positive constant C and all x,y∈(a,b) we
have|f(x)−f(y)|≤C|x−y|α
(a) Prove that an α-Holder function