A galvanic cell is powered by the following redox reaction:

2IO₃⁻ (aq) + 12H⁺ (aq) + 10Cu⁺ (aq) → I₂ (s) + 6H₂O (I) + 10Cu²⁺ (aq)

Answer the following questions about this cell.
1. Write a balanced equation for the half-reaction that takes place at the cathode.
2.Write a balanced equation for the half-reaction that takes place at the anode.
3.Calculate the cell voltage under standard conditions. Round your answer to 2 decimal places.

Answers

Answer 1

Half-reaction at the cathode:

part 1.

The half-reaction at the cathode is the reduction of Cu2+ ions to Cu+ ions:

10Cu2+ (aq) + 2e- → 10Cu+ (aq)

part 2.

Half-reaction at the anode:

The half-reaction at the anode is the oxidation of IO3- ions to I2:

2IO3- (aq) → I2 (s) + 6e-

part 3.

The cell voltage under standard conditions is  -0.20 V.

What is cell voltage?

The difference in the electrical potential between two electrodes is described as the cell voltage.

The cell voltage under standard conditions is equal to the difference between the standard reduction potentials of the half-reactions:

Ecell = E°cathode - E°anode

Ecell = 0.34 V - (+0.54 V)

Ecell = -0.20 V

Rounding off to 2 decimal places:

Ecell = -0.20 V

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Related Questions

On the basis of the information above, a buffer with a pH = 9 can best be made by using

A pure NaH2PO4

B H3PO4 + H2PO4–

C H2PO4– + PO42–

D H2PO4– + HPO42–

E HPO42– + PO43

Answers

Answer:

D H2PO4– + HPO42–

Explanation:

The acid dissociation constant for \(\mathbf{H_3PO_4 , H_2PO^{-}_4 , HPO_4^{2-}}\) are \(\mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \ 5\times 10^{-13}}\) respectively.

\(\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}\)

\(\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}\)

\(\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}\)

The reason while option D is the best answer is that, the value of pKa for both

\(\mathbf{H_2PO^{-}_4 ,\ \& \ HPO_4^{2-}}\) lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.

Using Henderson-Hasselbach equation:

\(\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}\)

The compounds that are used for the formulation of the pH 9 buffer are \(\rm H_2PO_4^-\;and\;HPO_4^+\). Thus, option D is correct.

The buffers are the solutions of acids and base of appropriate pH, that are able to limit the change in pH in the reaction mixture.

Which compound is used for pH 9 buffer?

The buffer pH is adjusted with the compounds that has been able to add base or acid to the solution.

For the formulation of buffer of specific pH, the acid and base solutions are required.

The compounds that are used for the formulation of the pH 9 buffer are \(\rm H_2PO_4^-\;and\;HPO_4^+\), as they are able to provide acid and base to the solution.

Thus, option D is correct.

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what is the characteristics of tropical air mass

Answers

Answer:

Explanation:

Continental tropical air masses are extremely hot and dry. Arctic, Antarctic, and polar air masses are cold. The qualities of arctic air are developed over ice and snow-covered ground. Arctic air is deeply cold, colder than polar air masses.

is a one time explanation of one observation a hypothesis and a scientific theory 100 points

Answers

One time explanation of one observation is a hypothesis.

Whenever, an assumption is made juts by observation and without proper testing then that is referred as an hypothesis.

For example- If my friend is late, so I might assume that he or she must have been stuck in traffic. So, this assumption is not tested yet and is made based on my observation. So, this is a hypothesis.

Whenever, a conclusion is given after several experiments and testing after observing something in science is referred as scientific theory.

For example- Atomic theory given by Dalton was based on several experiments. However, theories can also be proved wrong as Dalton's theory was proved wrong later on my JJ Thomson.

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48 grams of MgCl2 is dissolved in 500g of water, DENSITY OF
WATER = 1 kg/1L. What is the MOLALITY of this solution? Please
show your steps.
mol
kg
m =
or
m = mol = kg
Step1: given information:
solute=
(UNIT=
Solvent =
(UNIT =
)
)

Answers

The molality of the solution is 1.080 mol/kg of a 48 grams of MgCl2 is dissolved in 500g of water, density of water = 1 kg/1L.

How to calculate molality?

Taking the moles of solute and dividing it by the kilograms of solvent yields the molality of a solution.

Molality is calculated as follows: kg of solvent/kg of solute

500 g, or 0.500 kg, is the mass of the solvent.

MgCl2 molecular weight divided by its mass gives the amount of moles.

48 g / 95.2 g m o l 1 equals the quantity of moles of magnesium chloride.

0.504 moles of MgCl2 are present in one mole.

Molality is calculated as 0.504moles per kilogram.

Molality is equal to 1.080 mol k g 1.

As stated in the definition, molality is the "total moles of a solute contained in a kilogram of a solvent." The terms "molality" and "molal concentration" are synonymous. It is a measurement of a solvent.

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Which of Newton's Laws of Motion is called the Law of Inertia?

Question 1 options:

1st


3rd


2nd pls help

Answers

The Newton's first (1st) Law of Motion is called the Law of Inertia.

What is Newton's first law of motion?

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless it is acted upon by an external force.

This law (Newton's first law of motion) is called the law of inertia because it depends on mass of the object.

Inertia is the measure of reluctance of an object to move or resist motion when a force is applied to it.

The more massive an object is, the more inertia it will possess because it will exert a greater resistive force to prevent motion.

Basically, the Newton's first law of motion is all about the difficulty to stop an object in motion or get an object at rest to start moving on its own. The resistive force of the object to prevent motion can be overcame when an external force is applied to the object.

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Name three sources of atmospheric carbon dioxide.

Answers

Answer:

Natural sources include decomposition, ocean release and respiration. Human sources come from activities like cement production, deforestation as well as the burning of fossil fuels like coal, oil and natural gas.

A Sample of an Organic Compound Contain
0.624 Carbon, 0.065 hydrogen, 0·028 oxygen
(a) what is the Emperical formuler of the Compound.
(b) If the relative molecular mass of the Compound Is 1940 what is the moleculer
formular of the compound (C=12₁ H=1

N = 14,0= 16)​

Answers

(a) The empirical formula of the compound is \(C_{29}H_ {36}O\)

(b) The molecular formula of the compound is approximately \(C_{8}H_{118}O_{3}\)

To determine the empirical formula of the organic compound, we need to find the simplest whole-number ratio of the elements present.

(a) The given percentages of carbon, hydrogen, and oxygen can be converted into moles by dividing them by their respective atomic masses:

Carbon: 0.624 g / 12.01 g/mol = 0.052 mol

Hydrogen: 0.065 g / 1.008 g/mol = 0.064 mol

Oxygen: 0.028 g / 16.00 g/mol = 0.0018 mol

Next, we divide each of the mole values by the smallest mole value (0.0018 mol in this case) to obtain the mole ratio:

Carbon: 0.052 mol / 0.0018 mol ≈ 29

Hydrogen: 0.064 mol / 0.0018 mol ≈ 36

Oxygen: 0.0018 mol / 0.0018 mol = 1

Therefore, the empirical formula of the compound is \(C_{29}H_ {36}O\)

(b) To find the molecular formula, we need the relative molecular mass of the compound, which is given as 1940 g/mol. The empirical formula mass can be calculated by summing the atomic masses in the empirical formula:

Empirical formula mass: (29 × 12.01 g/mol) + (36 × 1.008 g/mol) + (1 × 16.00 g/mol) = 588.94 g/mol

To find the multiplier, we divide the relative molecular mass by the empirical formula mass:

Multiplier: 1940 g/mol / 588.94 g/mol ≈ 3.29

Rounding to the nearest whole number, the molecular formula of the compound is approximately 3 times the empirical formula, resulting in \(C_{8}H_{118}O_{3}\).

In summary, the empirical formula of the compound is\(C_{29}H_ {36}O\), and the molecular formula is approximately \(C_{8}H_{118}O_{3}\).

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Rank the following dienes in order of increasing reactivity in a Diels-Alder reaction, listing the least reactive first.(A) l < lll < ll(B) l < ll < lll(c) lll < l < ll(d) ll < l < lll

Answers

l < ll < lll  is the following dienes in order of increasing reactivity in a Diels-Alder reaction, listing the least reactive first.

What is reactivity ?

An atom's or molecule's potential to interact chemically with another atom, molecule, or compound. Chemical reactivity is the ability or willingness of a substance to undergo a reaction. Energy can be released when the substance reacts with another substance or with itself.

What is reaction ?

The transformation of one or more reactants into one or more new products is referred to as a chemical reaction. Substances are made of chemical constituents or compounds. The transformation of one or more reactants into one or more new products is referred to as a chemical reaction. Substances are made of chemical constituents or compounds.

s-cis dienes react faster than s-trans diene toward diels alder reaction

Since

ll is s-cis diene and is rigid molecule therefore will always be in this orientation hence reace fastest .

lll is s- trans form and is rigid molecule with no free rotation ,hence can never attain

s-cis form hence will be least reactice towards diels alder reaction .

l is aliphatic hence free rotation around single bond so , beacuse of this free rotation can cause two alkens to come in s-cis form to give faster diels alder but will take some time to come in s cis form hence its reactivity will be lesser than ll which is already in s-cis form.

Therefore,  l < ll < lll  is the following dienes in order of increasing reactivity in a Diels-Alder reaction, listing the least reactive first.

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A 0.150 M solution chloride in water is best prepared ina) a volumetric pipetb) a volumetric flaskc) a beakerd) an Erlenmeyer flask

Answers

To prepare sich solution, we would have to have a good measure of the solution added and of the final volume.

We may use a volumetric pipet to prepare it, but we won't prepare in a pipet, we would use it to measure something we would add.

A beaker or an Erlenmeyer flask don't have a good precision for volume measure, so they are bad to prepare the solution.

So, the best is to prepare in a volumetric flask, because its volumetric meaures is very precise.

A sailor on a trans-Pacific solo voyage notices one day that if he puts 375. mL of fresh water into a plastic cup fresh water weighing 15.0 g, the cup floats in the seawater around his boat with the fresh water inside the cup at exactly the same level as the seawater outside the cup.

Required:
Calculate the amount of salt dissolved in each liter of seawater.

Answers

Answer:

Amount of salt dissolved in each liter of seawater = 40 g

Explanation:

According to Archimedes principle, a body will float in a fluid if the upthrust experienced by a body is equal to the to the weight of the body.

Also, the volume of seawater displaced equals the volume of freshwater in the cup.

From the above principle, since the freshwater and cup floats in the seawater, their combined weight equals the upthrust.

Therefore, mass of equal volume of displaced seawater = mass of freshwater + mass of cup

Mass of freshwater = density of freshwater * volume

density of freshwater = 1 g/mL; volume = 375 mL

mass of freshwater = 375 mL * 1 g/mL = 375 g

mass of seawater = 375 + 15 = 390 g

mass of salt in 375 mL seawater = mass of seawater - mass of freshwater

mass of salt = (390 - 375) g = 15 g

Since 15 g of salt are dissolved in 375 mL seawater, mass of salt in 1 L of seawater =(1000 mL/ 375) * 15g = 40 g

Therefore, amount of salt dissolved in each liter of seawater = 40 g

What does it mean to interpret data?

Answers

Answer:

Data interpretation is the process of reviewing data through some predefined processes which will help assign some meaning to the data and arrive at a relevant conclusion. It involves taking the result of data analysis, making inferences on the relations studied, and using them to conclude

Explanation:

hope this helps! :)

A pure substance is a single kind of matter. A(n) _________
is made up of two or more substances that are together in the same place, but each substance keeps its own properties.

Answers

A pure substance is indeed a single kind of matter with a uniform and definite composition. In contrast, a mixture is made up of two or more substances that are together in the same place, but each substance maintains its own properties.

Mixtures can be classified as either homogeneous or heterogeneous. A homogeneous mixture has a uniform composition throughout, meaning its components are evenly distributed and not easily distinguishable. Examples include solutions, such as saltwater or air.

On the other hand, a heterogeneous mixture has an uneven distribution of its components, and its individual substances can be easily identified. Examples include sand and water, or oil and water.

One key distinction between a pure substance and a mixture is that a pure substance has a fixed composition, while the composition of a mixture can vary. This means that mixtures can be separated into their individual components through physical processes like filtration, evaporation, or distillation, without undergoing any chemical changes.

In summary, a pure substance is a single type of matter with a definite and uniform composition, while a mixture consists of two or more substances that are combined in the same place, but each substance retains its individual properties. Mixtures can be homogeneous or heterogeneous and can be separated into their components through physical methods.

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In the laboratory, open-toed shoes and shorts:
a. Are potentially dangerous and should not be worn.
b. Are OK if the weather is hot.
c. Are all right if you are wearing a lab coat
d. Are OK if they are in style.

Answers

Answer:

a. Are potentially dangerous and should not be worn.

A 6.2-L balloon at 55˚C and 615mm Hg is taken to the top of Mt. Everest (-35˚C and 400- mmHg). What is the size of the balloon?

Answers

Explanation:

wish I could help but I'm lost

Answer: 6.788

Explanation: Water expands 9% when frozen and if the baloon is filled with all 6.2-L then its just 9% of 6.2 which is 0.588 then add it toghether unless your asking something else becuase im not smart and I can't even divided. :p

A student planned to make copper sulfate crystals from excess copper oxide and dilute sulfuric acid.
The equation for the reaction is:
CuO(s) + H,SO (aq) -, CuSO (aq) + H20(1)
This is the method used.
1. Add 25 cm° of dilute sulfuric acid to a conical flask.
2. Gently warm the dilute sulfuric acid.
3. Add excess copper oxide to the dilute sulfuric acid.
4. Stir the mixture.
5. Heat to evaporate all the water from the mixture.
Suggest two improvements to the method
Explain why each improvement is needed.

A student plans a method to prepare pure crystals of copper sulfate.
The student's method is:
1. Add one spatula of calcium carbonate to dilute hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a Bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
Explain the improvements the student should make to the method so that pure crystals of copper sulfate are produced.

A student planned to make copper sulfate crystals from excess copper oxide and dilute sulfuric acid.The

Answers

The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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(a) 0.50 mol of NaCl dissolved in 0.30 L of solution

Answers

Answer:

Explanation:

To find the concentration of a solution, we need to divide the number of moles of solute by the volume of the solution in liters.

In this case, we have 0.50 mol of NaCl dissolved in 0.30 L of solution. Therefore, the concentration of the solution can be calculated as:

Concentration = moles of solute / volume of solution

Concentration = 0.50 mol / 0.30 L

Concentration = 1.67 mol/L

Therefore, the concentration of the solution is 1.67 mol/L.

List the 2 pKa's for H2SO4

Answers

No pKa1 because it is strong acid, pKa2 = 1.99

What type of wave travels quickly through solid, liquid, and gas?

A. primary
B. Secondary
C. Love
D. Rayleigh

Answers

Answer: sound waves

Explanation: Of the three mediums (gas, liquid, and solid) sound waves travel the slowest through gases, faster through liquids, and fastest through solid

We wish to determine the mass of Mg required to react completely with 250mL of 1.0 M HCI. HCI reacts with Mg according to the equation below.
2HCl(aq) + Mg(s) → MgCl₂(aq) + H₂(g)
How many moles of HCI are present in 250. mL of 1.0 M HCl?

Answers

There are 0.25 moles of HCl present in 250 mL of 1.0 M HCl.

We have to calculate the number of moles of HCl present in some mL of 1.0M HCl.  A mole is defined as the amount of substance in a system that contains as many elementary entities as there are atoms in 0.012 kg of carbon 12. We represent mole by the symbol 'mol'. Now, we will see how to calculate the number of moles.

We can calculate the number of moles of a substance using the following expression;

Molarity = no of moles of an element/volume

According to this question, we were given 250. mL of 1.0 M HCl. The number of moles will be calculated by the formula as follows;

no of moles of HCl = 0.250L × 1.0M

no of moles of HCl = 0.250 moles.

Therefore, 0.25 moles are present in 250 mL of 1.0 M HCl.

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Use your trendline equation to determine the gas pressure at 200 K and 400 K. (notice the temperature units) How many times greater is the pressure at 400 K in comparison to 200 K? Is this what you’d expect? Why?

Answers

Answer:

The pressure will be twice the initial pressure

Explanation:

Gay-Lussac's law states that the pressure of a gas is directely proportional to absolute temperature under constant volume. That is because vibrations of a gas increase when temperature increases, increasing the pressure of the gas.

That means if the temperature of a gas is doubled, the pressure will be twice the initial pressure.

Prepare one solution that has 0.12 M of FeCl3 and 0.40 M of HCl with the reagents 3 M HCl and Solid FeCL3 * 6H20. Provide the calculations and protocol to make the solution in a lab.

Answers

To prepare a 0.12 M solution of FeCl₃, the amount of solid FeCl₃ to be dissolved in a given volume of solvent will be 9.72 grams.

Given,

Molarity of FeCl₃ (M)= 0.12 M

The molecular weight (m) of FeCl₃ is  = 162 gm

The volume of the solution (V) to be prepared is =500 ml

The amount of FeCl₃ to be dissolved to make a 0.12 M solution is= x

So,

MV= x ÷ m × 1000

0.12× 500 = x ÷ 162 × 1000

x = 60 × 162 ÷ 1000

x= 9.72 gm

So 9.72 grams of FeCl₃ is dissolved to make 500 ml of 0.12 M solution.

For preparing 0.4 M HCl from 4M HCL:

If we need to make 500 ml of solution with 0.4M of HCL, then we use the formula:

M₁V₁= M₂V₂

0.4 × 500= 4 × x

x= 50 ml

So 50 ml of 4M HCL is taken to make 0.4 M HCL.

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Which part of the brain is affected by a smell, a song, or a photograph?
A. the primitive brain
B. the right brain
C. the outer brain
D. the emotional brain

Answers

The right brain part of the brain is affected by a smell, a song, or a photograph.

What is Right Brain?

The right brain is more intuitive and visually oriented. It is occasionally referred to as the analog brain. It thinks less logically and with more creativity. According to out-of-date research by Sperry, the right brain aids in creativity.

Which part of brain deals with photograph?

Posterior parietal cortex of the parietal lobe of the brain mainly deals with the photographs.

Which part of brain deals with Smell?

The olfactory bulb, a structure in the front of the brain, processes smells before sending data to other regions of the body's central nervous system.

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The right brain part of the brain is affected by a smell, a song, or a photograph.

What is Right Brain?

The right brain is more intuitive and visually oriented. It is occasionally referred to as the analog brain. It thinks less logically and with more creativity. According to out-of-date research by Sperry, the right brain aids in creativity.

Which part of brain deals with photograph?

Posterior parietal cortex of the parietal lobe of the brain mainly deals with the photographs.

Which part of brain deals with Smell?

The olfactory bulb, a structure in the front of the brain, processes smells before sending data to other regions of the body's central nervous system.

what are all the ways that a substance can change state?

Answers

Explanation:

hdhehdbrhdns dhdjdjdhrjs dhfirjr rudjdbe dbdud d

Answer:

Matter can change from one state to another if heated or cooled. If ice (a solid) is heated it changes to water (a liquid). This change is called MELTING. If water is heated, it changes to steam (a gas).

Explanation:

How do I know if something is an acid so I can avoid eating it?

Answers

Answer:

i feel like it will have an acid smell

Calculate how much heat is absorbed by a sample that weighs 12 kilograms, has a specific heat of 0.231 kg/CJ, and is heated from 45 K to 80 K.
PLEASE ANSWER 20 POINTS

Answers

Answer:

97 J

Explanation:

Step 1: Given data

Mass of the sample (m): 12 kgSpecific heat capacity (c): 0.231 J/kg.°C (this can also be expressed as 0.231 J/kg.K)Initial temperature: 45 KFinal temperature: 80 K

Step 2: Calculate the temperature change

ΔT = 80 K - 45 K = 35 K

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.231 J/kg.K × 12 kg × 35 K = 97 J

Besides solubility, state two other physical properties that are different for salt and sand.​

Answers

Answer:Electrical Conductivity,soluble

Explanation:

Salt is a non-magnetic solid and is soluble in water. Sand is a non-magnetic solid and is insoluble in water.

Electrical Conductivity: Salt is an electrolyte and conducts electricity when dissolved in water or in a molten state. This is because salt dissociates into ions (Na+ and Cl-) that can carry electric current. In contrast, sand is a covalent compound and does not conduct electricity, as it does not dissociate into ions in the same way as salt. Sand is considered an insulator in terms of electrical conductivity.

atomic radius(size)______ from left to right across a period on the periodic table

Answers

Answer:

Decreases

Explanation:

How much heat will be released if 0.5901 mol of NH₃ are mixed with 0.20 mol of O₂ in the following chemical reaction?

Answers

Answer:

heyy y boii

Explanation:

(01.04 LC)
What phase of matter has particles that are held together but can flow past each
other and takes the shape of a container, filling it from the bottom up? (3 points)
1) Gas
2) Liquid
3) Plasma
4) Solid

Answers

the answer is liquid ! hope this helped :)

Consider the following reaction PCl3+Cl2 = PCl5. If the per cent yield is 66.3%, what mass of PCl5 is formed when 61.3g of Cl2 reacts with PCl3?

Answers

According to percent yield and stoichiometry, the mass of PCl₅  formed when 61.3 g of Cl₂ reacts with PCl₃ is 180.04 g when 61.3 g of Cl₂ reacts with PCl₃.

What is percent yield?

Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.

In the given example,as 70.90 g chlorine gives 208.24 g  PCl₅  then according to stoichiometry,61.3 g of chlorine will give 61.3×208.24/70.90=180.04 g.

Thus, 180.04 g PCl₅ is formed when 61.3 g of Cl₂ reacts with PCl₃.

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