A person is running a temperature of 103°F What is the temperature on the Celsius scale?

The wire's magnetic field lines are circles that are perpendicular to the wire and have their centers on the wire.

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a) Displacement current density  for the capacitor is  113.4 A/m²

b) Rate of change of the electric field is   1.48157826 V/m.s

c) Magnetic field between plates at r of 1.93 cm  is  5.563×10⁻6 Tesla

d) Magnetic field between plates at r of 1.10 cm is  7.833 x 10-7 Tesla

Since we are given the radius of a parallel-plate capacitor which is 4.00 cm( 0.04 m) and the Conduction current = Ic =  0.570 A .we know  the  formula for the Displacement current density is

JD = Id/A, where  Id is the conduction current and A is the area of the capacitor, and A= πr² = π(0.04)²= 0.005024 m². As we know  conduction current has equal displacement between the capacitor plates so  Id = Ic

JD = 0.570/0.005024  = 113.4 A/m²

For the second case, we know the  rate of change of the electric field is:

dE/dt = JD/ε₀ , where JD is the displacement current density and ε₀ is the permittivity of free space (  8.854×10⁻¹² C²/N.m²)

so, dE/dt = 113.4/8.854×10⁻¹² =1.48157826 V/m.s

for the third case, the formula for The induced magnetic field between the plates  will be :

B = (μ₀/2)*JD*r, μ₀ is the permeability of free space(4π×10⁻⁷ T.m/A)and r is the distance from the axis.

B = (4π×10⁻⁷/2)*113.4 *0.01953

B = 5.563× 10⁻⁶ Tesla ,and for the last case, for the radius of 1.10  cm (0.011 m)

B = (μ₀/2)*JD*r

B = (4π×10⁻⁷/2)*113.4 *0.011

B = 7.833 x 10⁻⁷ Tesla

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The wise and economic use of energy sources is the best way of conserving existing energy sources because it ensures that energy sources that are not renewable such as petroleum are effectively managed so that they last for a longer time.

The conservation of resources refers to the various steps ad method employed to ensure that the existing resources are available for a long time and for future generations.

Conservation of energy sources involves effective and efficient use and management of energy sources so that they last longer. One way is the use of renewable energy.

One of the most important ways of the conservation of resources is the process of recycling to ensure that resources are reused.

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Answer:

The kinetic energy is  

= 1250 j

Explanation:

The kinetic energy is

KE = 1/2mv²

The mass is m = 25kg

The velocity is  v = 10ms^1

So,  KE = 12.25.10² = 1250 j

The velocity of the ball at the bottom of the ramp is approximately 8.86 m/s.

To find the velocity of the 4kg ball at the bottom of the 4m high ramp, we can use the conservation of mechanical energy principle. Since the ball starts from rest, its initial potential energy (PE) is converted into kinetic energy (KE) at the bottom of the ramp.

Initial PE = m * g * h
where m = 4kg (mass), g = 9.81 m/s² (acceleration due to gravity), and h = 4m (height)

Initial PE = 4 * 9.81 * 4 = 156.96 J (joules)

At the bottom, the potential energy is converted into kinetic energy:
KE = 0.5 * m * v²
where v is the velocity we want to find.

Since the initial PE = KE at the bottom, we can write:
156.96 J = 0.5 * 4 * v²

Solve for v:
v² = (156.96 / (0.5 * 4))
v² = 78.48
v = √78.48
v ≈ 8.86 m/s

The velocity will be approximately 8.86 m/s.

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Answer:

women... men

Explanation:

Answer:

c. women... men

Explanation:

edge 2021

Explanation:

Science says that youngest rock can be found in between ocean .

So plates should move away from each other to form ocean .

Option C is correct

Where would you find the youngest rock? At the boundary between the

O Pacific and North American plates

O Nazca and South American plates

O African and South American plates ✓

O Indian and Eurasian plates

Answer: depth, shade, fragrance

Explanation:

(i) The velocity of the two blocks after the collision is v0/3 to the right.

(ii) The minimum initial velocity required for the two blocks to make it to the top of the hill is √(2h).

(iii) The impulse delivered to the 2m block in the elastic collision is 2Vf/v0 times greater than in the totally inelastic collision.

(iv) In an inelastic collision, the required velocity v0 would be between the values obtained in (i) and (ii), and the impulse for a given v0 would be between the values obtained in (iii) and (ii).

(i) In an elastic collision, both momentum and kinetic energy are conserved. Initially, the block of mass m has momentum m * v0 to the right, and the block of mass 2m is at rest, so its momentum is zero.

When the blocks collide and stick together, the total momentum after the collision must be zero since they move as a single object. Let's denote the final velocity of the combined blocks as Vf.

Using the principle of conservation of momentum:

m * v0 + 0 = (m + 2m) * Vf

v0 = 3Vf

Therefore, the final velocity of the combined blocks after the collision is v0/3 to the right.

(ii) To determine the minimum initial velocity v0 required for the two blocks to make it to the top of the hill, we need to consider the conservation of mechanical energy.

The initial mechanical energy is given by the sum of the potential energy of the block of mass 2m at the top of the hill and the kinetic energy of the block of mass m:

E_initial = m * v0^2/2 + 2m * g * h

Since the collision is totally inelastic, the final velocity after the collision will be v0/3 (as found in part (i)). At the top of the hill, the final mechanical energy is given by the potential energy of the combined blocks:

E_final = (3m) * g * h

For the blocks to make it to the top of the hill, the initial mechanical energy must be equal to or greater than the final mechanical energy. Therefore:

m * v0^2/2 + 2m * g * h ≥ (3m) * g * h

Simplifying and canceling the m and g terms:

v0^2/2 + 2 * h ≥ 3 * h

v0^2/2 ≥ h

The minimum initial velocity v0 occurs when v0^2/2 = h:

v0^2/2 = h

v0 = √(2h)

Therefore, the minimum initial velocity required for the two blocks to make it to the top of the hill is √(2h).

(iii) In an elastic collision (Problem 1), the impulse delivered to the 2m block is equal to the change in its momentum. The magnitude of the impulse can be calculated as:

Impulse_elastic = Δp_elastic = m * (2Vf) - 0

Impulse_elastic = 2m * Vf

In a totally inelastic collision (This Problem), the two blocks stick together and move as a single object after the collision. The impulse delivered to the combined blocks is equal to the change in momentum of the system. The magnitude of the impulse can be calculated as:

Impulse_inelastic = Δp_inelastic = (3m) * (v0/3) - 0

Impulse_inelastic = m * v0

To compare the impulses, we divide the magnitude of the impulse delivered in the elastic collision by the magnitude of the impulse delivered in the totally inelastic collision:

Impulse_elastic / Impulse_inelastic = (2m * Vf) / (m * v0)

Impulse_elastic / Impulse_inelastic = 2Vf / v0

Therefore, for a given initial velocity v0, the impulse delivered to the 2m block in the elastic collision (Problem 1) is 2Vf / v0 times greater than the impulse delivered in the totally inelastic collision (This Problem).

(iv) If the collision were inelastic but not totally inelastic, the required velocity v0 would be between the values obtained in parts (i) and (ii). The impulse delivered for a given v0 would also be between the values obtained in parts (iii) and (ii).

In an inelastic collision, where the objects stick together, the final velocity after the collision is less than the initial velocity. As the collision becomes more inelastic (approaching totally inelastic), the final velocity approaches zero.

Therefore, the required velocity v0 for an inelastic collision would be greater than in a totally inelastic collision and less than in an elastic collision.

The complete question is:

A block of mass m moves with speed v0 rightward. A block of mass 2m begins at rest atop a hill of height h and slides down leftward. The two collide elastically at the foot of the hill. Assume no friction throughout.

In this problem, the same scenario is the same as in problem (1), except that, instead of colliding elastically, the blocks stick together when they collide at the bottom of the hill.

(i) What is the velocity of the two after the collision?

(ii) What is the minimum initial velocity v0 such that the two make it to the top of the hill?

(iii) For a given initial velocity v0, how many times greater is the impulse delivered to the 2m block by the elastic collision (Problem 1) versus the totally inelastic collision (This Problem)?

(iv) If the collision were inelastic, but not totally inelastic, how would the required velocity v0 compare to those found for 1(iii) and 2(ii)? How would the impulse for a given v0 compare? Justify your answers.

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Answer:

Rusting!

Explanation:

Rusting is a chemical reaction because it is the process of oxidation of a metal.  

Answer:

rusting

Explanation:

Answer:

•Helps to maintain va proper pH in the body which supports cell function.

•Carries electrolytes such as sodium and potassium to our muscles.

The magnitude of the force F experienced by a charge q that moves in a direction perpendicular to a magnetic field B with a speed v is given by:

Isolate B from the equation:

Replace F=22.394N, q=0.049C and v=272.4m/s to find the strength of the magnetic field:

Therefore, the magnetic field strength is approximately 1.7T.

When the distance between them is suddenly increased by a factor of 2. the new electrostatic force will be 2 N.

We need to know about electrostatic force to solve this problem. The electrostatic force is a force caused by two charges separated at a distance. It can be determined as

F = k . Q1 . Q2 / r²

where F is force, k is coulomb's constant (9 x 10⁹ Nm²/C²), Q is charge and r is radius.

From the question above, we know that

F1 = 8 N

r1 = r m

r2 = 2r1 = 2r

For this question, we can apply the ratio of initial and final force

F1 / F2 = k . Q . Q / r1² / k . Q . Q / r2²

F1 / F2 = r2² / r1²

F1 / F2 = (2r)² / r²

F1 / F2 = 4r² / r²

F1 / F2 = 4

F2 = 1/4 . 8

F2 = 2 N

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Answer:

the answer would be 'd'

Explanation:

im really good at this stuff

The unique use of gamma radiation is Killing bacteria. The correct option is D.

Gamma radiation is a type of electromagnetic radiation that is highly energetic and has no mass or charge. It is the most penetrating form of radiation and is often emitted during radioactive decay or nuclear reactions. Gamma rays have the shortest wavelengths and highest frequencies in the electromagnetic spectrum, ranging from about 0.1 nanometers to 10 picometers in wavelength. They can cause ionization in matter, meaning they can knock electrons out of atoms or molecules, making them highly damaging to living tissue. Gamma radiation is commonly used in medical imaging and cancer treatment, as well as in industrial applications for sterilization and food preservation.

Here in the Question,

Option A. Detection of thyroid cancer: Gamma radiation is used in medical imaging techniques such as PET scans and SPECT scans to diagnose cancerous conditions, but it is not unique to the detection of thyroid cancer.

Option B. CT scanners: Gamma radiation is not used in CT (computed tomography) scanners. CT scanners use a series of X-rays to produce detailed images of the inside of the body.

Option C. Smoke detectors: Smoke detectors use a small amount of radioactive material, typically americium-241, to ionize air particles and detect the presence of smoke. While gamma radiation is a type of ionizing radiation, smoke detectors do not use gamma radiation specifically.

Option D. Killing bacteria: Gamma radiation is used in the food industry to kill bacteria and sterilize food products, such as spices, meat, and poultry. This is a unique use of gamma radiation, as it relies on its ability to destroy microorganisms at high doses while leaving no residual radiation.

Therefore, The correct answer is option D i.e Killing bacteria.

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The process that water redeposit into a lake in the form of rain is precipitation.

Water runoff occurs when there is more water than land can absorb.

The water flows across the surface of the land and into nearby creeks, streams, or lakes.

Runoff can come from both natural processes and human activity.

When rain falls to the earth from clouds and runs downhill into rivers and lakes.

During evaporation, the water turns from liquid into gas, and moves from oceans and lakes into the atmosphere where it forms clouds.

Precipitation is any liquid (rain) or frozen water that forms in the atmosphere and falls back to the Earth, for example it could fall on land or into lakes and rivers.

Thus,  the process that water redeposit into a lake in the form of rain is precipitation.

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we need to consider the wave speed equation and the relationship between tension, linear mass density, and wave speed.

Therefore, the difference in speed of a wave traveling from one wire to the other is approximately 7.52 m/s

The wave speed (v) on a string is given by the equation:

v = √(T/μ)

where T is the tension in the string and μ is the linear mass density of the string.

For the first wire with linear mass density M₁ = 0.45 kg/m and tension

T = 300 N, the wave speed v₁ is given by:

v₁ = √(T/M₁)

Similarly, for the second wire with linear mass density M₂ = 0.27 kg/m and tension T = 300 N, the wave speed v₂ is given by:

v₂ = √(T/M₂)

To calculate the difference in speed between the two wires, we subtract the smaller wave speed from the larger wave speed:

Δv = |v₁ - v₂| = |√(T/M₁) - √(T/M₂)|

Substituting the given values:

Δv = |√(300/0.45) - √(300/0.27)|

Δv = |√(666.67) - √(1111.11)|

Δv = |25.81 - 33.33|

Δv ≈ 7.52 m/s

Therefore, the difference in speed of a wave traveling from one wire to the other is approximately 7.52 m/s.

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The correct answer is option B. It travels up and down. Transverse waves are characterized by the fact that they cause particles in the medium to move perpendicular to the direction of wave propagation.

Transverse waves are a type of wave that causes the particles of the medium to move up and down or side to side as the wave passes through them.

The other options are not right because:

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Water at 0°C will contract when warmed a little.

Water at 4°C will expand when warmed a little.

Water at 6°C will also expand when warmed a little.

The density of water changes with temperature, which affects its volume. To determine whether water will expand or contract when warmed, we need to consider the relationship between temperature and density.

Water is unique in that it reaches its maximum density at approximately 4°C. This means that as water cools from 4°C to lower temperatures, it contracts and becomes denser. On the other hand, as water warms from 4°C, it expands and becomes less dense.

At 0°C:

The water is already at its maximum density, so any further increase in temperature will cause it to expand and become less dense. Therefore, water at 0°C will contract when warmed a little.

At 4°C:

Since water reaches its maximum density at this temperature, any slight increase in temperature will cause it to expand and become less dense. Therefore, water at 4°C will expand when warmed a little.

At 6°C:

Water is still below its maximum density at this temperature. Therefore, any warming, even if it's just a little, will cause it to expand and become less dense. Hence, water at 6°C will also expand when warmed a little.

Water at 0°C will contract, water at 4°C will expand, and water at 6°C will also expand when warmed a little.
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Answer: 220 °C = 428 °F

Explanation:

220 degrees Celsius is approximately equal to 428 degrees Fahrenheit.

Celsius (°C) and Fahrenheit (°F) are two different temperature scales used to measure temperature. The Celsius scale is widely used in most countries around the world, while the Fahrenheit scale is primarily used in the United States and a few other countries.

To convert Celsius to Fahrenheit, the following formula is used :

°F = (°C × 9/5) + 32

Let's apply this formula to convert 220 degrees Celsius to Fahrenheit:

°F = (220 × 9/5) + 32

°F = (220 × 1.8) + 32

°F = 396 + 32

°F = 428

Therefore, 220 degrees Celsius is approximately equal to 428 degrees Fahrenheit.

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Answer is given below :

Explanation:

Answer:

The answer is that he tested seed color and shape that same time

Explanation:

Answer:

It has several other objects in its orbit, though few are as massive as itself."

answer:

u =11

Explanation:

brackets were inserted in the 1st step,to make it simpler as multiplication is done first, before addition.

hope this helps:))

The magnitude of the second charge is 3.01 x 10⁻⁵C.

The second charge is positive.

The magnitude of the second charge is determined by applying Coulomb's law of electrostatic force as shown below.

F = kq₁q₂/r²

where;

Substitute the given parameters, and solve for the magnitude of the second charge as shown below.

q₂ = Fr²/kq₁

q₂ = (65 x 0.5²) / (9 x 10⁹ x 6 x 10⁻⁵)

q₂ = 3.01 x 10⁻⁵C

Thus, the magnitude of the second charge is 3.01 x 10⁻⁵C. Also, since the force is attractive, the second charge must be positive.

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Answer:

Explanation:

Work done = Force * Displacement

There is no displacement vertical so only the horizontal part of force did work.

The horizontal force = Force * cos(angle with floor)

Work done = 40*cos(40°)*2

= 61.28 J

As cos(65°) is less than cos(40°), work done will be less at 65°.

True or false: Below the wave base there is no wave action (from surface waves).  

Wave action refers to the movement of water caused by the transfer of energy from wind or other sources. Surface waves, which are waves that travel along the surface of the water, have a wave base which is the point at which the wave starts to become noticeable to the eye.

Below the wave base, there may still be some water movement due to internal waves or subsurface currents, but the surface of the water will be relatively calm and there will be no visible wave action. These internal waves and currents are caused by the movement of water within the ocean or other bodies of water and are not directly related to wind or other external sources of energy.

In summary, true or false: below the wave base there is no wave action (from surface waves).  

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The effective value of g, the acceleration of gravity, at 6700m , above the Earth's surface is 9.79 m/s².

Given:

G=gravitational constant = 6.67x10⁻¹¹ m³/(kg.s²)

M=the Earth's mass = 5.97x10²⁴ kg

r=  Earth's radius = 6371 km  +6700m

r=6371000m+6700m

r=6377700m

For gravitation we use following:

F=GmM/r^2

which on further derivation gives

ma=GmM/r^2 , which results in

a=GM/r^2

Now putting the values in a=GM/r^2

a=6.67x10⁻¹¹ m³/(kg.s²)*5.97x10²⁴ kg/6377700^2

a=9.79 m/s²

Hence, The effective value of g, the acceleration of gravity, at 6700m , above the Earth's surface is 9.79 m/s².

then at 7000km i.e. 7000000m

All will be same except r= 6371000m+7000000m

r=13371000m and

r^2 =1.78*10^14.

putting values

a=6.67x10⁻¹¹ m³/(kg.s²)*5.97x10²⁴ kg/1.78*10^14.

a=2.23*10^28 m/s.

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The displacement from Rhonda's car to her campsite 257 m, 34.4° north of west.

Most campgrounds have picnic tables, a place to park your car, and a place to pitch your tent. Bathrooms and taps are often shared. One of the joys of camping is the lack of outdoor gear. But it's also nice to have a comfortable, convenient and cozy campsite. A tent is a small shelter for sleeping while camping.

Camps are areas with tents campfires and surroundings. There are many types of camping but the main methods of camping are backpacking auto-camping and glamping. These top three camping styles have options for every level of camper. Front country camping is also called auto camping because you can drive to the campground. These campsites usually have running water and modern washrooms.

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Answer:

d. Is indicated when a magnetometer measures intervals of magnetism that are weaker than expected

Explanation:

Magnetic field intensity is measured with a magnetometer on the surface of the Earth. Areas in which the magnetic field strength is lower or more than average are known as areas with magnetic anomalies, which may be due to  the presence of rocks that have a different magnetic characteristics

Where the magnetic anomaly is negative, it is indicative of a magnetic field strength reading that is lower than average magnetic field which is generally obtainable

Therefore, the correct option is indicated when a magnetometer measures intervals of magnetism that are weaker than expected