A random sample of 10 subjects have weights with a standard deviation of 12.3570 kg. What is the variance of their weights? Be sure to include the appropriase unite with the resill. The variance of the sample data is (Round to four decimal places as needed.)

Answer: x=7

               ab=21

               bc=14

Step-by-step explanation:

ab=3x

bc=2x±7

ac=42

3x±2x±7=42

5x±7=42

5x=42-7

5x=35

to get the value of x you divide 35 by 5x

35÷5x=7

so the value of x is 7

ab=3x

x=7

3x=7×3x

7×3=21

x=7

2x=7×2x

2×7=14

Answer:

I Think so 3 option is the correct answer of this question

Answer:

C is the correct answer. F(x) = -\(x^{3}\)

The proportion of businesses who did not respond = 54.67%

Given : Total businesses = 150

Businesses responded = 68

Businesses did not respond =  150- 68 = 82

The proportion of businesses who did not respond =

82/150 x 100

54.67%

Answer:

5 nights

Step-by-step explanation:

39 divided by 3 = 13

so we divided 65 by 13 hence your answer 5 nights

\( {10}^{2y} = 25\)

\( {(10)}^{y2} = {5}^{2} \)

\( {10}^{y} = 5\)

\( \frac{1}{10 {y} } = \frac{1}{5} \)

\( {10}^{ - y} = \frac{1}{5} \)

answer= option e.

The number of cubes Lucy should add is 8.

In mathematics, an equation is a formula that expresses the equivalency of two expressions, by connecting them with the equals sign = .

Given that, a visage balance has 3 cells on one visage and 11 cells on the other visage.

The equation to represent the situation is 3 c = 11

The result of an equation is the set of all values that, when substituted for unknowns, make an equation true.

Now, c = 11- 3

c = 8

thus, the number of cells Lucy should add is 8.

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Answer:

The first one is - 5 and the other is - 40

The value of the real part of the sum of two complex numbers (6+4i) and (5-i) is 11.

To find the value of the real part of the sum of complex numbers, we add the real parts of the individual numbers. In this case, we have the complex numbers (6+4i) and (5-i). The real part of a complex number is the coefficient of the imaginary unit 'i'.

For the first complex number (6+4i), the real part is 6.

For the second complex number (5-i), the real part is 5.

To find the sum of these complex numbers, we add their real parts separately. Therefore, the sum of the real parts is 6 + 5 = 11.

Hence, the value of the real part of the sum of (6+4i) and (5-i) is 11.

In summary, when adding complex numbers, we can find the real part by adding the real parts of the individual numbers. In this case, the real part of the sum is 11.

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For a randomly selecting one letters from each words, DISCRETE and ALGEBRA, the probability that you choose the same letter is equals to the \( \frac{1}{28}.\).

When we divide the number of events by the possible number of outcomes. It will give the Probability. The value of probability lies between 0 and 1. We have two Words one is DISCRETE and ALGEBRA. One letter is randomly selected from each words. Total numbers of letters in word DISCRETE = 8

Total numbers of letters in word ALGEBRA = 7

We have to determine the probability to choose the same letter. Now, number of same letters in both of the words = 1 ( E)

So, the number of ways to selecting the 'E' letter from DISCRETE word = 2

The number of ways to selecting the 'E' letter from ALGEBRA word = 1

Probability that letter E selected from ALGEBRA word, P( A)\( = \frac{1}{7}\).

Probability that letter E selected from DISCRETE word, P( D) = \( = \frac{2}{8} = \frac{1}{4} \). So, probability that you choose the same letter from both words = P(A) × P(B)

\( = \frac{1}{7} \times \frac{1}{4}\)

\( = \frac{1}{28}\)

Hence, required value is \( \frac{1}{28} \).

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The probability that both balls drawn are white is 4/15.

To find the probability that both balls drawn are white, we need to consider the probabilities of drawing a white ball from each urn and then multiply them together.

The first urn contains 2 white balls and 4 yellow balls. The probability of drawing a white ball from the first urn is 2/6, or simplified, 1/3.

The second urn contains 8 white balls and 2 yellow balls. The probability of drawing a white ball from the second urn is 8/10, or simplified, 4/5.

To find the probability of both events occurring, we multiply the probabilities together:\((1/3) \times (4/5) = 4/15\).

In summary, when drawing a ball at random from each urn, the probability of selecting two white balls is 4/15.

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9514 1404 393

Answer:

  29.4°

Step-by-step explanation:

The equation can be rearranged to give C directly.

  C = arccos((a^2 +b^2 -c^2)/(2ab))

  C = arccos((90^2 +55^2 -50^2)/(2·90·55))

  C = arccos(8625/9900) ≈ 29.4002°

  C ≈ 29.4°

Answer:

thxxxxx ;)

Step-by-step explanation:

Answer:

~You made me smile~

Have a wonderful day!!!!

a) Median will be an appropriate measure for the distribution. b) Mean will be an approprate measure for the distribution.

Here we already have the data available to us. From the data, we can clearly see that

Mode < Mean < Median

Hence this is a negatively skewed distribution.

Therefore the appropriate measure of central tendency for this distribution will be the median. The median will tell us the point at which the frequency is divided by 50%.

Hence we can say that the median will a more appropriate measure.

Now if the data has another aspect of sex included, then the frequency column would be divided into separate columns with each gender identity taking up its own column.

Since now this will become multivariate data, the best measure of central tendency will be Mean.

The difference in the measure of central tendency will depend upon how skewed the data for every sex will be. For example, if in a country, men preferred to be educated over women, then the mean for men will be a lot higher than that of women. On the other hand, the EDUC for women will be a lot lower.

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Answer:

  a.  Larger: 16x +5; Smaller: 4x +5

  b.  Difference: 12x

  c.  Larger: 53; Smaller: 17

Step-by-step explanation:

You want expressions for the perimeter of each triangle, the difference of those, and their value when x=3.

The perimeter is the sum of the side lengths. The expression is simplified by combining like terms.

  Larger: (4x +2) +(7x +7) +(5x -4) = (4+7+5)x +(2+7-4) = 16x +5

  Smaller: (x +3) +(2x -5) +(x +7) = (1+2+1)x +(3-5+7) = 4x +5

The perimeter of the larger triangle is 16x +5; the smaller, 4x +5.

The difference is found by subtracting the smaller from the larger. Like terms can be combined.

  (16x +5) -(4x +5) = (16 -4)x +(5 -5) = 12x

The difference in perimeters is 12x.

When x = 3, the larger triangle perimeter is ...

  16·3 +5 = 48 +5 = 53 . . . . units

and the smaller triangle perimeter is ...

  4·3 +5 = 12 +5 = 17 . . . . units

The perimeters of the larger and smaller triangles are 53 units and 17 units, respectively, when x = 3.

__

Additional comment

There are no values of x that will make the larger triangle be a right triangle. The smaller triangle is a right triangle only for x = 10+√116.5 ≈ 20.794.

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Answer:

0.35 because above all the probs were below 50 meaning that it was hard for them to even score one goal per game

Step-by-step explanation:

The value for a = -2 and b = 0, the absolute minimum of f(x, y) is 0, and the absolute maximum is 2.

In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.

To find the critical points of the function f(x, y) = √(2² - x² - y²) restricted to the boundary of D, we need to consider the condition x² + y² = 2².

Let's solve for x² + y² = 2² and substitute it into the function f(x, y):

x² + y² = 2²

Simplifying, we have:

x² + y² = 4

Substituting this into f(x, y), we get:

f(x, y) = √(2² - x² - y²) = √(4 - x² - y²)

To find the critical points, we need to find where the partial derivatives of f(x, y) equal zero. Since we are restricted to the boundary of D, we can use Lagrange multipliers to consider the constraint x² + y² = 4.

Let's set up the Lagrange multiplier equation:

∇f(x, y) = λ∇g(x, y)

where g(x, y) = x² + y² - 4 and ∇ denotes the gradient.

Calculating the gradients:

∇f(x, y) = <-x/√(4 - x² - y²), -y/√(4 - x² - y²)>

∇g(x, y) = <2x, 2y>

Setting the components equal, we have:

-x/√(4 - x² - y²) = 2xλ

-y/√(4 - x² - y²) = 2yλ

x² + y² = 4

We can simplify the equations by canceling out the x and y terms (assuming they are not zero):

1/√(4 - x² - y²) = 2λ

x² + y² = 4

From the second equation, we know that x² + y² = 4. Substituting this into the first equation, we get:

1/√(4 - 4) = 2λ

1/√0 = 2λ

0 = 2λ

Since λ cannot equal zero, we can conclude that there are no critical points within the interior of D.

However, we need to check the boundary of D for critical points. The boundary is defined as x² + y² = 4.

Let's find the critical points on the boundary:

Substituting x² + y² = 4 into f(x, y):

f(x, y) = √(4 - x² - y²)

To find the absolute minimum and maximum on the boundary, we need to find the extremum points by analyzing the function along the boundary.

Using techniques such as Lagrange multipliers or parameterization, we can find that the absolute minimum occurs at (x, y) = (-2, 0), and the absolute maximum occurs at (x, y) = (2, 0).

Therefore:

a = -2

b = 0

The absolute minimum of f(x, y) is 0, and the absolute maximum is 2.

Please note that this solution assumes that the question is asking for critical points and extrema on the boundary of D, not at corner points. If the question intends to ask for extrema at corner points as well, further analysis would be needed.

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d. Dummy coding. Categorical variables need to be converted into numerical variables to be used in regression analysis. Dummy coding involves creating binary variables for each category of the categorical variable.

For example, if the categorical variable is "color" with categories "red," "green," and "blue," dummy coding would involve creating three binary variables: "red" (0 or 1), "green" (0 or 1), and "blue" (0 or 1). These binary variables can then be used in the regression analysis. In conclusion, to use categorical variables in regression analysis, dummy coding is necessary.


In order to use categorical variables in a regression analysis, they must be converted into numerical values. This process is called dummy coding (also known as one-hot encoding). Dummy coding involves creating new binary variables (0 or 1) for each category of the categorical variable. This allows the regression model to incorporate the categorical data while maintaining its numerical nature.

To use categorical variables in a regression analysis, you must apply dummy coding to convert them into numerical values.

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The equation of the line that is perpendicular to this line and passes through the point (-5, -6) is 5x + 3y + 43 = 0, and the equation of the line that is parallel to this line and passes through the point (-5, -6) is 3x - 5y + 15 = 0.

Given, the equation of the line is y = (3/5)x + 1.

We need to find the equation of the line that is perpendicular to this line and passes through the point (-5, -6) and the equation of the line that is parallel to this line and passes through the point (-5, -6).

Perpendicular line: If two lines are perpendicular to each other, then the product of their slopes is -1. So the slope of the given line = 3/5Therefore, the slope of the line perpendicular to it will be the negative reciprocal of 3/5 Slope of the line perpendicular to it = -5/3

Therefore, the equation of the line perpendicular to it and passes through the point (-5, -6) is given by y - y1 = m(x - x1), where:

(x1, y1) = (-5, -6) and

m = -5/3y + 6 = (-5/3)(x + 5)

Multiplying both sides by 3, we get

3y + 18 = -5x - 25 => 5x + 3y + 43 = 0

The equation of the line perpendicular to it and passes through the point (-5, -6) is 5x + 3y + 43 = 0.

Parallel line: If two lines are parallel to each other, then their slopes are equal.

So the slope of the given line = 3/5

Therefore, the slope of the line parallel to it will be the same. The slope of the line parallel to it = 3/5

Therefore, the equation of the line parallel to it and passes through the point (-5, -6) is given by y - y1 = m(x - x1),

where:

(x1, y1) = (-5, -6) and

m = 3/5y + 6 = (3/5)(x + 5)

Multiplying both sides by 5, we get

5y + 30 = 3x + 15 => 3x - 5y + 15 = 0

The equation of the line parallel to it and passes through the point (-5, -6) is 3x - 5y + 15 = 0.

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The difference between AIC and BIC penalty lies in their approach to model selection.

AIC (Akaike Information Criterion) is a measure of the goodness of fit of a statistical model. It is used to compare different models and select the one that fits the data best. AIC is based on the principle of maximum likelihood, which means it is more focused on finding the model that fits the data best.

On the other hand, BIC (Bayesian Information Criterion) is a criterion for model selection based on the Bayesian approach. It is also used to compare different models, but it takes into account the complexity of the model. BIC tends to favor simpler models, and it is more focused on finding the model that is most likely to be true given the data.

In summary, AIC is more focused on finding the model that fits the data best, while BIC is more focused on finding the model that is most likely to be true given the data.

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Answer:

the answer is b. y = 20x + 30

The absolute threshold is defined as the minimum detectable stimulus or intensity.

The absolute threshold refers to the minimum amount or level of a stimulus that is required for it to be detected or perceived by an individual. It is the point at which a stimulus becomes perceptible or noticeable to a person.

In sensory psychology, the absolute threshold is typically measured in terms of the lowest intensity or magnitude of a stimulus that can be detected accurately by a person at least 50% of the time. It represents the boundary between the absence of perception and the presence of perception.

The absolute threshold can vary depending on the sensory modality being tested. For example, in vision, it may refer to the minimum amount of light required for a person to see an object. In hearing, it may represent the minimum sound intensity needed for an individual to hear a tone.

Several factors can influence the absolute threshold, including individual differences, physiological factors, and the nature of the stimulus itself. Factors such as sensory acuity, attention, fatigue, and background noise can all affect an individual's ability to detect a stimulus.

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She counted the squares instead of using the scale.

The scale, the numbers on the x amd y axis dont fo by ones, they go by sixes

Answer: the secound one

Step-by-step explanation:

Step-by-step explanation:

Again, using similar triangle ratios

7.2 m  is to 2.4 m  

     as   AB is to  12.0 m

7.2 / 2.4  = AB/12.0    Multiply both sides of the equation by 12

12 *   7.2 / 2.4   = AB = 36.0 meters