a solenoid has a diameter of 11 cm and a length of 218 cm. it carries a current of 5.7 a, and the field at the center is 3.1 × 10-3 t. a) how many total turns of wire are there in this solenoid?

If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspeed will Increase and true altitude will increase.

This refers to the vertical elevation of  a body and is the measurement of the height above the sea or ground level. An airplane's altitude is directly proportional to the airspeed as long as the power is constant.

This means that increase in airspeed will lead to an increase in altitude and vie versa. This is the reason why as it runs fast, it can be observed that it begins to elevate.

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Answer:

Explanation:

The momentum of an object can be found by using the formula

From the question

mass = 200 kg

velocity / speed = 8m/s

We have

momentum = 200 × 8

We have the final answer as

Hope this helps you

Answer:

1) 50 seconds 2) 100°C

Explanation:

(Follows formula of Power=Energy/Time)

1) 500W x X = 2000J/kg°C x .25kg x 50°C

X = 50 seconds.

2) 2000W x 300s = 1000J/kg°C x 2kg x X

X = 300

Initial temperature => 400°C-300°C = 100°C

It will take 0.82sec to reach the edge of the table if the system is free to move. If mB=1.0 kg, 99 kg mA must be used if the system's acceleration is to be kept above 1/100 g.

(a) mA = 11 kg

mB = 7 kg

T = mA mB g / (mA+mB) = 77*9.8 / 18 = 41.92 N is the formula for cord tension.

In the case of mA, we have T = mA*a

acceleration of mA, a = T / mA = 41.92 / 11 = 3.81 m/s²

For mB, we have mB*a = mB*g - T a = (mB*g - T) / mB

                                  a = (7*9.8 - 41.92) / 7 = 3.81 m/s²

(b) Initial velocity of mA, u = 0

The distance traveled by mA, s = 1.3 m

We have,

\(s = u t + (1/2) a t^2\\ s = at^2 / 2\\ t = (2s / a)^(1/2) = (2*1.3 / 3.81) (1/2) = 0.82 sec\)

(c) mB = 1 kg

The system's acceleration, a = g/100

The system's acceleration is given by the formula a = mB*g / (mA+mB).

mA = [mB*g / a] - mB = [ 1*9.8*100/9.8 ] - 1 = 99 kg

Acceleration is the rate at which velocity changes with respect to time. It is a vector quantity whose magnitude denotes the amount of change in velocity per unit of time.

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The energy of X-rays emitted by an element depends on its atomic number, and the strongest peak in the X-ray spectrum can help determine the atomic number of the metal. In this case, the strongest peak is observed for X-rays with an energy of 66 keV. This energy corresponds to the K-alpha emission line, which is produced when an electron transitions from the L shell to the K shell, resulting in the release of 66 keV of energy.

The energy of the K-alpha line is related to the atomic number of the element through Moseley's law, which states that the square root of the energy of the K-alpha line is proportional to the atomic number of the element. Using this law, we can calculate the atomic number of the metal as:
Atomic number = (Energy of K-alpha line / Rydberg constant)^2, where the Rydberg constant is 13.6 eV.
Substituting the given energy of 66 keV into the equation, we get:
Atomic number = (66,000 eV / 13.6 eV)^2
Atomic number = 164.7
Therefore, the atomic number of the unknown metal is approximately 165.

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Sydney McLaughlin's average speed during the 400-meter hurdles race was 7.77 m/s.

The average speed of Sydney McLaughlin during the 400-meter hurdles race is calculated as follows;

Average speed = distance / time

The distance is 400 meters, and the time is 51.46 seconds.

The average speed of Sydney McLaughlin during the 400-meter hurdles race is calculated as;

Average speed = 400 / 51.46

Average speed = 7.77 m/s

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The path along which an object moves, which might be a straight line or might be curved, is referred to as the object’s trajectory.

This is defined as the path that an object follows when in motion and it varies according to various factors such as the forces acting on the object and so on.

A trajectory in this case could either be straight line or curved and is also referred to as the path an object travels in space.

This is therefore the reason why it was chosen in this scenario as the most appropriate choice.

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To measure the intensity of the light at different locations when a laser is pointed at a 45-degree angle, you will need to use a light intensity measuring device, such as a lux meter or a spectrometer.

Begin by placing the measuring device at the first location and pointing the laser at a 45-degree angle towards it. Take a reading of the intensity of the light at that location and record the result.

                               Then, move the measuring device to the next location and repeat the process, taking a reading of the intensity of the light at each new location. Repeat this process until you have measured the intensity of the light at all desired locations.

                                  Be sure to note the distance between the laser and the measuring device, as this can affect the accuracy of the readings. The data collected can then be used to create a graph or chart detailing the variation in light intensity across different locations.

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Answer:

Average speed = 60km/hr

Explanation:

Given the following data;

Time = 2.5 hrs

Distance = 150km

To find the average speed;

Average speed = distance/time

Substituting into the equation, we have

Average speed = 150/2.5

Average speed = 60km/hr

Answer:

True

Explanation:

The correct option is D. 3690s They can hare afford to nap if he does not want to lose the race.

The hare can afford to sleep for no longer than 370 seconds, or 6 minutes and 10 seconds, if he wants to win the race. 370 seconds is the answer

In the 7 seconds that the hare runs, he covers a distance of:

d_hare = v_hare x t_hare = 15 m/s x 7 s = 105 m

The hare is currently 895 meters from the finish line,

or 1000 meters - 105 meters.

The tortoise will keep moving toward the finish line and eventually cross it, winning the race, if the hare takes a nap.

The tortoise must travel the remaining distance from its current location to the finish line in the following amount of time:

t_tortoise = (1000 m - 105 m) / 0.27 m/s = 3204.63 s

Therefore, the hare can only nap for a maximum of:

t_max = t_tortoise - t_hare = 3204.63 s - 7 s = 3197.63 s ≈370s

Hence, if the hare wants to win the race, he can afford to sleep for no more than 370 seconds, or 6 minutes and 10 seconds. The response is (b) 370 seconds.

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If an object is accelerated by a force of 100 N and then a second force of 100 N in the opposite direction is applied to the object, the object will continue to move at a constant velocity in the direction of the original force.

When the two forces are equal and opposite, they cancel each other out, resulting in a net force of zero on the object. This means that the object is no longer accelerating, and is instead moving at a constant velocity in the direction of the original force. This constant velocity is known as the terminal velocity of the object, and is determined by the balance of forces acting on the object.

In summary, if two forces of equal magnitude but opposite direction act on an object, the object will continue to move at a constant velocity in the direction of the original force, with a net force of zero.

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The displacement of 20 miles is the straight-line distance in the Southwest direction from the starting point whereas the distance of 70 m is the total distance along the path of travel.

Distance is the actual distance that a body travels. Additionally known as path length. As an illustration, the path length for an object going from point O to point A will be distance OA = 30 m. It is a scalar quantity, the distance.

Displacement is the change in an object's position in relation to a reference frame. It is a vector quantity with both magnitude and direction.

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Answer:

Explanation:

Pressure can be defined as the force per unit area hence there is an inverse relationship between pressure exerted by a substance and the area of that substance. For instance,

(1) if a bag of sand if filled with sand and an individual steps on this bag. The feet of he individual will form no shape/displace little sand sideways in the bag. But if the same quantity of sand is poured in a bigger bag (larger area) and the same individual stands on the bag, the feet of the individual will "sink" (decreased pressure from the bag) displacing some sand sideways.

(2) The straps of a bag are made wide (and not slim) so that the bag can exert lesser pressure on the shoulders when the same quantity of load is carried by the bag than if the straps were made narrow/slim.

Answer:

C) Dew Point

Explanation:

The dew point is the temperature at which air is saturated with water vapor, which is the gaseous state of water. When air has reached the dew-point temperature at a particular pressure, the water vapor in the air is in equilibrium with liquid water.

dew point

Explanation: mark me as brainlest

Answer:

2.04m

Explanation:

PE=mgh

h= PE/mg

h= 40/2(9.82)

h=40/19.64

h=2.04

Answer:

\(20m\)

Explanation:

Formula to find the potential energy is,

Potential Energy = mgh

Here,

m = mass

g = gravitational field

h = height

According to the question, we have to find the height.

Usually, we get g is \(10ms^{-2}\)

Let us solve for the answer now.

\(P.E. =mgh\\40J =2kg*10ms^{-2} *h\\40 = 20h\\\frac{40}{20}= \frac{20h}{20} \\20m=h\)

Hope this helps you.

Let me know if you have any other questions :-)

The electric field at the point (-5.0cm, -5.0cm) due to the +12nC charge at the origin is E = (1.77 x 10^6 N/C) i + (1.77 x 10^6 N/C) j

The electric field at a point (x1, y1) due to a point charge q located at the origin is given by

E = k×q / r^2

where k is the Coulomb constant (9 x 10^9 N m^2/C^2), and r is the distance from the charge q to the point (x1, y1).

In this case, q = +12nC = 12 x 10^-9 C, and r = sqrt(x1^2 + y1^2) = sqrt((-5.0cm)^2 + (-5.0cm)^2) = 7.07 cm = 0.0707 m.

Substituting the values into the formula, we get:

E = (9 x 10^9 N m^2/C^2) × (12 x 10^-9 C) / (0.0707 m)^2

= 2.53 x 10^6 N/C

To express the electric field in component form, we need to find the x and y components of the vector. Since the charge is located at the origin, the electric field vector will point directly towards the point (x1, y1). We can find the angles that the vector makes with the x and y axes using trigonometry

theta_x = atan(x1 / y1) = atan(-5.0cm / -5.0cm) = 45 degrees

theta_y = atan(y1 / x1) = atan(-5.0cm / -5.0cm) = 45 degrees

Then, we can find the x and y components using

Ex = E ×cos(theta_x) = (2.53 x 10^6 N/C) × cos(45 degrees) = 1.77 x 10^6 N/C

Ey = E ×cos(theta_y) = (2.53 x 10^6 N/C) × cos(45 degrees) = 1.77 x 10^6 N/C

Therefore, the electric field at the point (-5.0cm, -5.0cm) is

E = (1.77 x 10^6 N/C) i + (1.77 x 10^6 N/C) j

where i and j are unit vectors in the x and y directions, respectively.

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Answer:

It’s stratosphere

Explanation:

Most ozone is found in a region of Earth’s atmosphere between 10 and 20 miles above Earth’s surface. This temperature zone of the atmosphere is known as the stratosphere.

Ozone is an allotrope of oxygen. It is blue in color and it is found in Earth's atmosphere. It protects the Earth from ultraviolet rays from the Sun.

The ozone subcaste is centered at an altitude between 10-15 country miles (15-25 km). Close to 90% of the ozone found in the atmosphere is in the stratosphere. Ozone that is found in this region is about 10 parts per million by volume (ppmv) to the troposphere's 0.04 ppmv.

Therefore, we have determined that Most ozone is found in a region of Earth’s atmosphere between 10 and 20 miles above Earth’s surface. This temperature zone of the atmosphere is known as the stratosphere.

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Given that the direction sailboat is north and the distance traveled is d = 10 km

The direction of the wind is southeast and the force is

The sailboat travels the distance in time, t = 1 h

We have to find the work done by the wind and wind's power.

The diagram is shown below

The work done by the wind will be

The power of the wind will be

Answer:

well they make the siren go beacaus eyou are doing somthing wrong so what were you thinking

Explanation:

Answer:

Decreasing the distance between the two objects affect the gravitational force by strengthening it.

Explanation:

Gravity is stronger when the distance is shorter.

To start in motion an object sitting at rest on a horizontal surface, the horizontal force applied must be greater than the static friction force present.

This static friction force is the force that holds the object in place, and is equal to the coefficient of static friction multiplied by the normal force.

Therefore, if an object has a static friction coefficient of 0.2 and a normal force of 10 Newtons, then the minimum horizontal force required to start in motion the object is 2 Newtons.

The static friction is the force that opposes the initiation of motion between two surfaces in contact that are at rest relative to each other. The magnitude of the static friction force depends on the nature of the surfaces in contact and the force pressing them together.

Once the applied force exceeds the static friction force, the object will begin to move, and kinetic friction will take over.

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1. They have evolved their leaves into spikes for minimum water loss through transpiration.

2. They have a waxy layer for minimum water loss.

3. They have thick walls for minimum water loss.

4. They can take water from atmosphere.

5. They change the photo energy from Sun into an intermediate stage and store it, so that they can make food even in night.

Answer:

F = - K X

X = .4314 m       compression of spring

F  = 55.71 N/m * .4314 m = 24.03 N      force to compress spring

E = 1/2 K X^2       energy of compressed spring

E = 1/2 55.71 N / m * (.4314 m)^2 = 5.184 Joules energy of spring    

1/2 M V^2 = E      energy imparted to ball

V = (2 E / M)^1/2 = 3.25 m/s     max speed of ball

M g H = 1/2 M V^2     calculate height of ball after release

H = E / (M g)      height above spring

H = 5.184 / (.98 * 9.80) = .540 m     height to which ball rises

.540 + .4314 = .972 m      height above compression point

The speed of sound in air at 30°C will be approximately 349.3 m/s.

we can use the given equation to calculate the speed of sound in air at 30°C.

The equation is:

v = 331 m/s + (0.61 m/s) (t/1°C)

where:

v = speed of sound

t = temperature in °C

We need to calculate the speed of sound at 30°C, so we can substitute t = 30°C in the above equation:

v = 331 m/s + (0.61 m/s) (30°C/1°C)

v = 331 m/s + (0.61 m/s) (30)

v = 331 m/s + 18.3 m/s

v = 349.3 m/s

Therefore, the speed of sound in air at 30°C is approximately 349.3 m/s.

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Answer:

d = 493.72 m

Explanation:

Given that,

Initial velocity of the train, u = 80 km/h = 22.22 m/s

Acceleration of the train, a = -0.5 m/s² (negative as it slows down)

Finally brakes are applied, v = 0

We need to find the distance the train travels. Let the distance be d. Using third equation of kinematics to find it.

\(v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(22.22)^2}{2\times (-0.5)}\\\\d=493.72\ m\)

So, the required distance is equal to 493.72 m.

In order to reach the maximum height of 2 meters, Kangaroo should jump with an initial speed of 6.26 m/s.

The three equations of motion are -

first law → v = u +at

second law → S = ut + 1/2 at²

Third law → v² - u² = 2aS

Given is a kangaroo who jumped 2 meters high.

Assume that the kangaroo jumped with an initial velocity of 'u' m/s.

The maximum height achieved is 2 meters.

Acceleration due to gravity will be -9.8 m/s²

At maximum height, the velocity will be zero. Therefore, the final velocity 'v' will be zero. Using third law →

v² - u² = 2aS

- u² = - 2gS  

u² = 2gS

u² = 2 x 9.8 x 2

u² = 39.2

u = 6.26 m/s

Therefore, in order to reach the maximum height of 2 meters, Kangaroo should jump with an initial speed of 6.26 m/s.

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