The maximum velocity of a particle on the string is approximately 0.98 m/s.
To find the maximum velocity of a particle on the string, we can use the given tension, linear density, amplitude, and wavelength values.
Given:
- Tension (T) = 55.0 N
- Linear density (μ) = 4.70 g/m = 0.00470 kg/m (converted to kg/m)
- Amplitude (A) = 3.00 cm = 0.03 m (converted to meter)
- Wavelength (λ) = 2.10 m
First, we can find the wave speed (v) using the equation v = √(T/μ):
v = √(55.0 N / 0.00470 kg/m) ≈ 34.66 m/s
Next, we can find the angular frequency (ω) using the equation ω = 2πv/λ:
ω = (2π * 34.66 m/s) / 2.10 m ≈ 32.74 rad/s
Finally, we can find the maximum velocity of a particle on the string (v_max) using the equation v_max = Aω:
v_max = 0.03 m * 32.74 rad/s ≈ 0.98 m/s
So, the maximum velocity of a particle on the string is approximately 0.98 m/s.
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Turning right on a red light is permitted after a stop and when the intersection is clear. which vehicles are permitted to turn right on a red light?
In conclusion, in most cases, motor vehicles are permitted to turn right on a red light after a complete stop and when the intersection is clear. However, it is crucial to consult local traffic laws and regulations to ensure compliance and to be aware of any exceptions or specific requirements that may apply.
According to the given information, turning right on a red light is permitted after a stop and when the intersection is clear. In general, this rule applies to motor vehicles, such as cars, trucks, and motorcycles. However, the specific vehicles permitted to turn right on a red light may vary depending on the jurisdiction and local traffic laws.
To illustrate, let's consider an example where a driver approaches a red traffic light and intends to make a right turn. If the driver comes to a complete stop, checks for oncoming traffic, and ensures there are no pedestrians crossing the intersection, they are generally allowed to proceed with the right turn.
It's important to note that this rule may not apply to all types of vehicles. For instance, large commercial vehicles or buses may have specific regulations or restrictions on turning right on a red light due to their size or potential impact on traffic flow.
In conclusion, in most cases, motor vehicles are permitted to turn right on a red light after a complete stop and when the intersection is clear. However, it is crucial to consult local traffic laws and regulations to ensure compliance and to be aware of any exceptions or specific requirements that may apply.
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why is velocity called vector quantity while speed is a scalar quantity
Answer:
velocity is the rate of change of distance moved with a time in a specific direction. While speed is the rate if distance with time in no specific direction
an orthodontic spring, connected between the upper and lower jaws, is adjusted to provide no force with the mouth open. when the patient closes her mouth, however, the spring compresses by 6.0 mm.
Answer:
0.96 N
Explanation:
a 20,000.0 kg trolley moving at 5.0 m/s collides and couples with a 5000.0 kg trolley which is initially at rest. the final speed of the trolleys is:
Since this is an inelastic collision where both masses stick together (couple with one another) after a collision, the final speed (velocity) of the trolleys is 4 m/s.
Momentum is defined to be p = mv where p is momentum, m is mass, and v is speed/velocity. Therefore, the momentum of a single object is determined by its mass as well as its speed.
Collision, also known as impact, is the sudden and forceful coming together in direct contact of two masses. The sum of the momenta (plural of momentum) before collision is equal to that after collision.
One type of collision is inelastic collision, which is when both masses stick together after a collision and move at a common speed. The equation for inelastic collision is m₁u₁ + m₂u₂ = (m₁ + m₂)v where:
m₁ is mass of 1st object,m₂ is mass of 2nd object,u₁ is initial velocity of m₁,u₂ is initial velocity of m₂, andv is final velocity.Given that m₁ = 20,000 kg, m₂ = 5,000 kg, u₁ = 5 m/s, and u₂ = 0 m/s, the final velocity v is then calculated as follows:
m₁u₁ + m₂u₂ = (m₁ + m₂)v
20,000 · 5 + 5,000 · 0 = (20,000 + 5,000)v
100,000 = 25,000v
100,000/25,000 = 25,000v/25,000
4 = v
v = 4 m/s
We've confirmed that the final speed of the trolleys is equal to 4 m/s.
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At what distance from a 15W point source of electromagnetic waves is the magnetic field amplitude 0.60μT ?
Express your answer to two significant figures and include the appropriate units.
The magnetic field amplitude of the electromagnetic wave from the 15W point source is 0.60 μT at a distance of 2.10 m.
To solve this problem, we can use the equation for the magnetic field amplitude (B) of an electromagnetic wave at a certain distance (r) from the source:
B = (μ0/4π) * (2πf) * (r^-1) * E
where μ0 is the permeability of free space (4π x 10^-7 T·m/A), f is the frequency of the wave, E is the electric field amplitude, and r is the distance from the source.
We are given that the source has a power output of 15W, but we do not know the frequency of the wave or the electric field amplitude. However, we do know that the magnetic field amplitude at a certain distance is 0.60 μT. So we can rearrange the equation to solve for r:
r = (μ0/4π) * (2πf) * (E/B)
We can assume that the frequency of the wave is constant, so we can combine the constants in the equation and substitute the values:
r = (1.26 x 10^-6 m) * (E/B)
We need to find the value of r that makes B = 0.60 μT. Let's assume that E is also constant and solve for r:
r = (1.26 x 10^-6 m) * (E/0.60 x 10^-6 T)
r = 2.10 m.
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difference between mechanical watch and quartz watch
Answer:
Mechanical vs. Quartz Watch Movements
Mechanical watch movements are powered by gears and springs. They're autonomous little machines without the need for electric power sources, whereas quartz watches are powered by batteries that vibrate little crystals.
A quantity that is fully described by magnitude alone is a ___________ quantity. A quantity that is fully described by both magnitude and direction is a ___________ quantity.
Answer:
Scalar quantity
Vector quantity
Explanation:
A scalar quantity is a quantity that is fully described by magnitude alone. Examples include; mass, temperature etc
A vector quantity is described by both magnitude and direction. E.g force, weight etc
State the law of gravity, and explain how this paper airplane investigation
proved Newton's law of gravity.
Based on Newton's law of gravity, the force of attraction on the airplane moving on Earth is directly proportional to the mass of the airplane and inversely proportional to the square of distance the airplane from Earth's surface.
What is Newton's law of universal gravitation?
Newton's law of universal gravitation states that the force of attraction between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects.
Mathematically, this law is written as follows;
Fg = ( G m₁ m₂ ) / ( r² )
where;
G is the universal gravitation constantm₁ is the mass of the first objectm₂ is the mass of the second objectr is the distance between the two objectsFrom Newton's second law of law of motion we will have;
F = mg
mg = ( G m₁ m₂ ) / ( r² )
g = Gm / r²
Every object on Earth surface moves with equal acceleration due to gravity which has a value of 9.8 m/s².
Thus, airplane flying on Earth surface will be affected by gravity and the weight or downward force on the airplane is a function of gravity.
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An object is taken to Mars. It’s mass is 15kg, it’s weight on Mars is 55.5N
What is the gravitational field strength on Mars?
Answer:
Approximately \(3.7\; {\rm N \cdot kg^{-1}}\) (or equivalently, \(3.7\; {\rm m\cdot s^{-2}}\).)
Explanation:
Gravitational field strength measures the force (weight) that the field exerts on object of unit mass (e.g., \(1\; {\rm kg}\).)
Divide the weight of the object by its mass to find the gravitational field strength at the position.
In this question, \(\text{weight} = 55.5\; {\rm N}\) while \(\text{mass} = 15\; {\rm kg}\). Therefore, the gravitational field strength will be:
\(\begin{aligned} & (\text{gravitational field strength}) \\ =\; & \frac{(\text{weight})}{(\text{mass})} \\ =\; & \frac{55.5\; {\rm N}}{15\; {\rm kg}} \\ =\; & 3.7\; {\rm N \cdot kg^{-1}} \end{aligned}\).
4. What are some of the physical factors of the room that
determine how much light actually reaches the working plane?
The physical factors of the room that determine how much light reaches the working plane include the size and placement of windows, the presence of obstructions, and the reflectance of the surfaces.
The amount of light that reaches the working plane in a room is influenced by several physical factors. Firstly, the size and placement of windows play a crucial role. Larger windows allow more natural light to enter the room, while the location of the windows determines the direction and angle of the incoming light. For example, windows facing the south tend to receive more sunlight throughout the day compared to those facing other directions.
Secondly, obstructions in the room can block or diffuse the light. Objects such as furniture, partitions, or screens can cast shadows and obstruct the direct path of light, reducing the amount that reaches the working plane. Additionally, the presence of curtains or blinds can further control the amount of light entering the room.
Lastly, the reflectance of the room's surfaces affects the distribution of light. Light-colored walls, ceilings, and floors reflect more light, helping to distribute it evenly across the space. On the other hand, dark or highly absorbent surfaces can absorb light, resulting in reduced overall brightness.
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when is atmospheric pressure 1x10 to the power of 5 and when is it pgh
Answer:
1 atmospheris pressure is equal to10.33 meter under water
Explanation:
right ??
a 2.0-mm-diameter glass bead is positively charged. the potential difference between a point 2.0 mm from the bead and a point 4.0 mm from the bead is 500 v. what is the charge on the bead?
The glass bead has a 0.001 m radius. The distance between the first and second points from the bead's center is 0.003 and 0.005 meters, respectively.
How big is a circle's radius?The radius of a circular is the distance a circle's center from any point along its perimeter. Usually, "R" or "r" is used to indicate it.
In geometry, what is a radius?A radius is indeed a line segment that has one endpoint in the circle's center and the other terminus on the circumference of the circle. Circle's diameter equals the radius The diameter of a circle is a line segment that has its ends on the circle and passes through its center. Radius x 2 equals the diameter.
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Which of the following has more inertia: (a) a rubber ball and a stone of the same size? (b) a bicycle and a train? (c) a five-rupees coin and a one-rupee coin?
Inertia is the same thing as mass, more or less. Inertia is the tendency of the object to want to stay in place if at rest, or the object's tendency to stay in motion if a force is applied to it. A train's inertia is massive because it takes a lot of force to move such a large mass, or to slow it down. This is in comparison to the other objects (rubber ball, stone, bike, and the coins).
Answer:
Inertia is the measure of the mass of the body. The greater is the mass of the body; the
greater is its inertia and vice-versa.
(a) Mass of a stone is more than the mass of a rubber ball for the same size. Hence, inertia of
the stone is greater than that of a rubber ball.
(b) Mass of a train is more than the mass of a bicycle. Hence, inertia of the train is greater
than that of the bicycle.
(c) Mass of a five rupee coin is more than that of a one-rupee coin. Hence, inertia of the five
rupee coin is greater than that of the one-rupee coin.
which has the greatest inertia
A. Jumbo Jet
B. Bird
C. Car
Answer:C car
Explanation:
how long will you have to wait for the oxygen in the chamber to decrease from 21% to 20%? a) 18 hours b) 9 hours c) 1.8 hours d) 1 hours
You will have to wait 1.8 hours for the oxygen in the chamber to decrease from 21% to 20%
The rate at which the oxygen concentration decreases in the chamber depends on several factors, such as the size of the chamber, the number of people in it, and the ventilation system.
Assuming a standard-sized chamber and normal ventilation, it would take approximately 1.8 hours for the oxygen concentration to decrease from 21% to 20%.
This is because the oxygen concentration in the air we breathe is already quite low (only 21%), so it takes a relatively small amount of time to decrease by 1%.
It is important to monitor oxygen levels in any enclosed space to ensure the safety and well-being of those inside.
Thus, the correct choice is (c) 1.8 hours
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It depends on a few factors, including the size of the chamber, the rate at which oxygen is being used or consumed, and the rate at which fresh air is being introduced into the chamber.
However, in general, it is likely that the decrease from 21% to 20% would happen relatively slowly, and could take several hours or even days to occur. Therefore, the most likely answer to this question is either a) 18 hours or b) 9 hours, as these are the options that represent long time periods. It is important to note that if someone is in an oxygen chamber and the oxygen level drops significantly, it could potentially be dangerous or even life-threatening, so it is important to monitor oxygen levels carefully and take appropriate precautions to ensure that everyone in the chamber remains safe and healthy. To determine how long it will take for the oxygen concentration in a chamber to decrease from 21% to 20%, we would need additional information such as the size of the chamber, the rate of oxygen consumption or displacement, and any potential sources of oxygen replenishment.
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-
J SLC
2SCC
A football player throws a football with a force of 50 N. The ball travels 12 min 3 seconds and
hits a water bucket with a force of 25 N. This causes the bucket to moves a distance of 4
meters in just 2 seconds
Answer:
DO NOT DOWNLOAD THAT LINK, IT WILL SCAM YOU!
Explanation:
Explanation:
hola si me puede dar la respuesta
the drag force from air resistance is given by F= pACv2/2. where p is the density of air, A is the cross-sectional area (assume to be a circle), C is the drag coefficient based on shape and v is the speed. You may guess that larger raindrops may have a larger terminal speed, but let's see if this is true. Assume a spherical raindrop of radius r and density p.. I) Derive an expression for the terminal speed of the raindrop in terms of r, C, g. pw and p. (where p, is the density of air that is in the drag force expression). Mass cannot be in your expression. il) From your expression, if you double the radius, what happens to the terminal speed?
The terminal speed of a raindrop is proportional to the square of the radius.
If the radius is doubled, the terminal speed will quadruple.
The terminal speed of a raindrop is the speed at which the drag force from air resistance balances the force of gravity. The drag force is given by F = pACv^2/2, where p is the density of air, A is the cross-sectional area, C is the drag coefficient, and v is the speed.
The cross-sectional area of a spherical raindrop is A = πr^2, where r is the radius of the raindrop.
The force of gravity is given by F = mg, where m is the mass of the raindrop and g is the acceleration due to gravity.
For a raindrop to reach its terminal speed, the drag force must equal the force of gravity. This means that pACv^2/2 = mg.
Solving for v, we get v = (2mg)/(pCπr^2).
The terminal speed is proportional to the square of the radius. This means that if the radius is doubled, the terminal speed will quadruple.
v = (2mg)/(pCπr^2)
If r = 2r, then v = (2mg)/(pCπ(2r)^2) = 4 * (2mg)/(pCπr^2) = 4v
Therefore, the terminal speed will quadruple.
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Antireflection coatings can be used on the inner surfaces of eyeglasses to reduce the reflection of stray light into the eye, thus reducing eyestrain.PART A) A 90-nm-thick coating is applied to the lens. What must be the coating's index of refraction to be most effective at 480 nm?
To minimize reflection at the surface, the coating's index of refraction should be equal to the square root of the product of the indices of refraction of the lens and the surrounding medium.
Assuming the lens is made of glass, with an index of refraction of approximately 1.5, and the surrounding medium is air, with an index of refraction of approximately 1, the index of refraction for the coating can be found as follows: n_coating = sqrt(n_lens * n_air), n_coating = sqrt(1.5 * 1), n_coating = sqrt(1.5), n_coating ≈ 1.22. Therefore, for a 90-nm-thick coating to be most effective at reducing reflection at a wavelength of 480 nm, its index of refraction should be approximately 1.22. This will allow the coating to reduce the reflection of stray light into the eye and reduce eyestrain.
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A video recorder is loaded with a tape which plays for 180 minutes.
The length of the tape is 260 m.
(a) (i) Calculate the speed of the tape, in metres per minute.
The speed of the tape, in metres per minute is 1.44 meter per minute
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
With the above formula, we can obtain the speed of the tape. Details below
How to determine the speed of the tapeThe following data were obtained from the question:
Distance = 260 mTime = 180 minutesSpeed =?The speed of the tape can be obtained as illustrated below:
Speed = distance / time
Speed = 260 / 180
Speed = 1.44 meter per minute
Thus, the speed of the tape is 1.44 meter per minute
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What is the temperature of an incandescent lamp filament
Answer:
about 5000 °F
Explanation:
Co-efficient of volume expansion of
aluminium
The coefficient of volume expansion of a material is a measure of how much its volume changes with a change in temperature. For aluminium, the coefficient of volume expansion is approximately \(7.1 \times 10^{-5}\) per degree Celsius (\(K^{-1}\)).
For aluminium, the coefficient of volume expansion is approximately \(23.1 \times 10^{-6}\) per degree Celsius. This means that for every degree Celsius increase in temperature, the volume of aluminium will increase by approximately 23.1 parts per million (ppm).
This coefficient of volume expansion is an important property of aluminium, as it affects its behaviour in a variety of applications. For example, in the aerospace industry, aluminium is used extensively in the construction of aircraft because of its low weight and high strength-to-weight ratio. However, as the temperature of the aircraft changes during flight, the volume of the aluminium components will also change, potentially affecting the structural integrity of the aircraft.
Understanding the coefficient of volume expansion is therefore essential for engineers and designers working with aluminium in a variety of fields, from aerospace to construction to electronics.
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A student fires a cannonball vertically upwards with a speed of 22.0m/s from a height of 40.0m. On the descent, the cannonball misses the building and lands on the ground. Determine all unknowns and answer the following questions. Neglect drag and horizontal motion of the cannonball.What was the cannonball's maximum height (measured from the ground)? With what speed did the cannonball strike the ground? What was the cannonball's total flight time?
We are given that an object is launched with an initial height and we are asked to determine its maximum height. To do that we will determine first the time it takes the object to reach the maximum height which is given by the following formula:
\(t=\sqrt[]{\frac{2v_0}{g}}\)Where:
\(\begin{gathered} t=\text{ time for maximum height} \\ v_0=\text{ initial velocity} \\ g=\text{ acceleration of gravity} \end{gathered}\)Replacing the values we get:
\(t=\sqrt[]{\frac{2(22\frac{m}{s})}{9.8\frac{m}{s^2}}}\)Solving the operations we get:
\(t=2.12s\)Now, to determine the height associated with this time we will use the following formula:
\(h=h_0+v_0t-\frac{1}{2}gt^2\)Where:
\(h_0=\text{ initial height}\)In this case, the initial height is 40 meters. Replacing the known values:
\(h=40m+(22\frac{m}{s})(2.12s)-\frac{1}{2}(9.8\frac{m}{s^2})(2.12s)^2\)Solving the operations:
\(h=64.61m\)Therefore, the maximum height the ball reaches measured from the ground is 64.61 meters.
Now we are asked to determine the final velocity of the object. To do that, we will use the following formula:
\(2gh=v^2_f-v^2_0\)Where:
\(\begin{gathered} h=\text{ }initial\text{ height} \\ v_f=\text{ final velocity} \end{gathered}\)Now we solve for the final velocity first by adding the square of the initial velocity:
\(2gh+v^2_0=v^2_f\)Now we take the square root to both sides:
\(\sqrt{2gh+v^2_0}=v^{}_f\)Replacing the known values:
\(\sqrt[]{2(9.8\frac{m}{s^2})(40m)+(22\frac{m}{s})^2}=v_f\)Solving the operations:
\(35.6\frac{m}{s}=v_f\)Therefore, the final velocity is 35.6 meters per second directed towards the ground.
Now we are required to determine the time the object stays in the air. To do that we will use the following formula:
\(v_f=v_0-gt\)We will solve for "t" first by subtracting the initial velocity from both sides:
\(v_f-v_0=-gt\)Now we divide both sides by the acceleration of gravity with the negative sign:
\(\frac{v_f-v_0}{-g}=t\)Now we replace the values, but we need to have into account that since the final velocity is directed towards the ground its sign is negative:
\(\frac{-35.6\frac{m}{s}-22\frac{m}{s}}{-9.8\frac{m}{s}}=t\)Solving the operations:
\(5.87s=t\)Therefore, the cannonball's total time is 5.87 seconds.
three charged particles are placed at the corners of an equilateral triangle that has edge length 2.0 cmcm. one particle has charge 4.5 ncnc and a second has charge 9.0 ncnc.
The magnitude of the electric field at the position of the third particle is 2.52 x 10⁶ N/C, causing it to remain stationary.
How are charges distributed on an equilateral triangle?Assuming the third particle has a charge of 0, we can use Coulomb's law to find the magnitude of the electric field at the third particle's position due to the other two charges:
E = k * (q1 / r1² + q2 / r2²)
where k is the Coulomb constant, q1 and q2 are the charges of the first two particles, and r1 and r2 are the distances from the third particle to the first two particles.
Since the triangle is equilateral, the distances from the third particle to the first two particles are both 2.0 cm. Plugging in the values:
E = (8.99 x 10⁻⁹ N*m²/C²) * (4.5 x 10⁻⁹ C / (0.02 m)² + 9.0 x 10⁻⁹ C / (0.02 m)²)
E = 2.52 x 10⁶ N/C
So the magnitude of the electric field at the third particle's position is 2.52 x 10⁶ N/C. Since the third particle has a charge of 0, there is no force on it and it will remain stationary.
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The ability of a metal to react with air and water is a
property.
O chemical, physical, respectively
O physical, chemical, respectively
o physical, physical, respectively
O chemical, chemical, respectively
\(\bold{{Answer}}\)
O physical, chemical, respectively
please buddy correct me if im wrong
The ability of a metal to react with air and water is a chemical, chemical, respectively property
What is a chemical change?A chemical change occur when the substance's composition is changed or when bonds are broken and new ones are forms a chemical change occur .
When a metal burn in air or react with air it form metal oxide and when metal react with water it forms oxides or hydroxides and release hydrogen gas . In both the cases change in composition is taking place . hence , bot are chemical reactions
correct answer is O chemical, chemical, respectively
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the period of oscillation of a spring and mass system is 0.54 seconds and the amplitude is 4.900 cm. what is the magnitude of acceleration at the point of maximum extension of the spring
Simple harmonic motion is defined as a motion in which the restoring force is directly proportional to the displacement of the body from its mean position.
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a spring of force constant 120N/m is acted upon by a constant force of 240N . calculate the elastic potential energy stored in the spring
Answer:
240 J
Explanation:
240 N will compress the spring 2 meters ( 240 N / 120 N/m = 2 m)
EPE = 1/2 k x^2 = 1/2 (120 N/m) ( 2 m)^2 =240 J
The elastic potential energy stored in the spring is 240 joule.
What is potential energy?
Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.
Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has more potential energy as they become further apart.
Force constant: k = 120N/m.
Applied force: F = 240 N.
Hence, compression in length = F/k = 240/120 m = 2 m.
The elastic potential energy stored in the spring = kx²/2
= 120 × 2²/2 joule
= 240 joule.
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how come if you jump in a train you will land in the same spot but if you jump on top of the train you won't? i tried to make it make sense.
Answer:
Well, it has to do something with the force of the train. It's pulling you, a force of gravity
However jumping off results in a different sort of energy, the train know is moving farther away as you jump down. So you end up in a different place
Explanation:
Describe binary fission with amoeba.
find the value of x in this figure
Answer:
x=50
Explanation:
Answer:
vertically opposite angles are equal
Explanation:
so
2x+30=3x-20
2x-3x= -20-30
-1x= -50
so x is 50
as minus gets cancelled both sides.
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Waldo gets stopped by the police, and the police officer tells Waldo that she caught him on radar doing 50 miles per hour in a 40 miles per hour zone. Waldo responds, "No way! I was traveling 50 miles per hour. I sat at home for 1 hour and then drove for 1 hour before you stopped me. I traveled 50 miles total in that second hour. So, my speed was 25 miles per hour. That's well under the speed limit." Waldo is wrong, per speeding laws, and does receive a speeding ticket. Explain how Waldo came up with a speed of 25 miles per hour.