a) The general form of Newton's Law of cooling is: T(t) = Ta +(T(0) – Tale-ke where T is the temperature at any time, t in minutes. Ta is the surrounding ambient temperature in °C and k is the cooling con- stant. Consider a cup of coffee at an initial temperature, T(0) of 80°C placed into the open air at 15°C. After 5 minutes the coffee cools to 65°C. Using these initial conditions: i) Calculate the cooling constant, k. ii) What will be the temperature of the coffee after exactly 13 minutes? iii) How long will it take for the coffee to reach 25°C?

Answer: I believe it to be D.

Momentum is never created or destroyed. It's conserved. The total amount after a collision is the same as it was before the collision.

In this scenario, the total is 10 kg-m/s before the collision, so it's going to be 10 kg-m/s after.

Ball 2 has 4 kg-m/s, so Ball 1 has the other 6 kg-m/s of momentum.

Yes, force can be expressed in units of pounds and newtons.

Force is an effect of the mass of object to accelerate in particular direction and can be expressed in the unit of pounds according to the FPS system of units. Newton is also a unit to express the force. SI unit of force is the newton and symbol is N.

Convert weight measured in pounds to equivalent in Newtons. In the formula for the determination of mass based on weight, mass is measured in Newtons. Weight is measured in Kilograms, and acceleration of gravity on Earth is measured as 9.8 meters per second squared and these are metric system unit measurements.

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The starling burns approximately 4,658 grams or 4.7 kilograms of fat during its flight.

To calculate the amount of fat that the starling burns, we need to use the equation that relates energy expenditure to the amount of fat burned. This equation states that for every gram of fat burned, the body expends 9 kcal of energy.
First, we need to convert the time from hours to seconds. 1.8 hours is equal to 6,480 seconds.
Next, we can use the formula for distance, speed, and time:
distance = speed x time
The distance that the starling travels is:
distance = 11 m/s x 6,480 s
distance = 71,280 meters
Now, we need to calculate the energy expended by the starling during this flight:
energy expended = force x distance
force = mass x acceleration
We know the acceleration is zero, since the starling is flying at a constant speed. So, force is simply the weight of the starling.
weight of the starling = mass x gravity
Assuming the starling weighs 60 grams, its weight is:
weight = 60 g x 9.81 m/s^2
weight = 588.6 g m/s^2
Therefore, the force on the starling is 588.6 g m/s^2.
energy expended = force x distance
energy expended = 588.6 g m/s^2 x 71,280 m
energy expended = 41,932,608 g m^2/s^2 or 41,932,608 joules
Finally, we can use the energy expenditure equation to calculate the amount of fat burned:
energy expenditure = amount of fat burned x 9 kcal/g
41,932,608 joules = amount of fat burned x 9 kcal/g
amount of fat burned = 4,658 grams
Therefore, the starling burns approximately 4,658 grams or 4.7 kilograms of fat during its flight.

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In order to calculate the velocity of a sound wave, you need to use the formula: velocity = wavelength × frequency.

In this case, you have a wavelength of 5 meters and a frequency of 1000 cycles per second (Hz). Using the given information, you can calculate the velocity of the sound wave by multiplying the wavelength (5 meters) and the frequency (1000 Hz). This gives you a velocity of 5,000 meters per second.

To find the velocity of the sound wave, we can use the formula:
Velocity = Wavelength x Frequency, we are given the wavelength as 5 meters and the frequency as 1000 cycles per second.                            Therefore: Velocity = 5 meters x 1000 cycles/second
Velocity = 5000 meters/second
So the velocity of the sound wave is 5000 meters per second.

In summary, a sound wave with a wavelength of 5 meters and a frequency of 1000 Hz has a velocity of 5,000 meters per second.

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The cost of method because the source's pace procedures the velocity of sound transferring to the proper will be 1/2fs.

When each movements withinside the same route with same velocity n' = n, i.e. there can be no Doppler impact because of the truth relative motion amongst deliver and listener is zero.

The motion of the observer will adjust the frequency of the measured sound from a table certain deliver: An observer moving in the direction of the deliver measures a higher frequency. An observer moving a ways from the deliver measures a lower frequency.

The Doppler impact is an alteration withinside the determined frequency of a legitimate due to motion of each the deliver or the observer. The actual trade in frequency is called the Doppler shift.

It will cause an increase in frequency heard thru an observer at the same time as the deliver is moving withinside the direction of the observer and a decrease in frequency heard thru an observer at the same time as the deliver is moving a ways from the observer. The doppler impact can be determined at the same time as an ambulance with a siren on procedures and passes an observer.

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We are given a series circuit with two resistors and a voltage source. Since the resistor are in series this means that the total resistance is the sum of both resistances. Applying Ohm's law we get

Where:

V is voltage, I is current and R1 and R2 are the resistance of the radio and the variable resistance respectively.

Now we solve for the variable resistance, R2, first by dividing both sides by I:

Now we subtract R1 to both sides:

Replacing the values:

Solving the operations:

Therefore, the resistance needed is 135 Ohms.

Answer: true

Explanation:

For the designing of differential amplifier following were found out :

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

To design the differential amplifier according to the given specifications, we will follow these steps:

Step 1: Calculate the small-signal gain (Av)

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Step 4: Calculate the tail current (Itail) based on the specified Iss

Step 5: Determine the resistance (R) value

Step 6: Calculate the width (Wp) of the PMOS transistor

Step 7: Calculate the width (Wn) of the NMOS transistors

Now let's go through each step in detail.

Step 1: Calculate the small-signal gain (Av)

Given: Av = 10, VOP = VON = 3.5V

Av = (vop - von) / (vip - vin)

10 = (3.5 - 3.5) / (0.1)

10 = 0 / 0.1

Since the numerator is zero, the small-signal gain is zero.

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Given: unCox = 400 μA/V², Vtn = 0.8V, n = 0.02 V^(-1), L = 0.2 μm

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

ro = 1 / (lambda * unCox * (W/L))

We need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vgs = Vin - Vbias) should be zero to operate the transistors in the saturation region.

For the NMOS transistors:

Vgs = 0 (since Vin = Vbias)

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

  = 2 * 400 μA/V² * (W/L) * (0 - 0.8)

  = -640 * (W/L) μA/V

ro = 1 / (lambda * unCox * (W/L))

  = 1 / (0.02 V^(-1) * 400 μA/V² * (W/L))

  = 1 / (8 * (W/L)) kΩ

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Given: upCox = 200 μA/V², Vtp = -0.8V, p = 0.04 V^(-1), L = 0.2 μm

Similarly, for the PMOS transistors, we need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vsg = Vbias - Vin) should be zero to operate the transistors in the saturation region.

For the PMOS transistors:

Vsg = 0 (since Vin = Vbias)

gm = 2 * upCox * (W/L) * (Vtp - Vsg)

  = 2 * 200 μA/V² * (W/L) * (-0.8 - 0)

  = -320 * (W/L) μA/V

ro = 1 / (lambda * upCox * (W/L))

  = 1 / (0.04 V^(-1) * 200 μA/V² *

  = 1 / (5 * (W/L)) kΩ

Step 4: Calculate the tail current (Itail) based on the specified Iss

Given: Iss = 2 mA

Itail = Iss / 2

= 2 mA / 2

= 1 mA

Step 5: Determine the resistance (R) value

Given: Vs = 0.3 V, VDD = 5 V

We can calculate the resistance (R) value using Ohm's Law:

Vs = Itail * R

0.3 V = 1 mA * R

R = 0.3 kΩ

Step 6: Calculate the width (Wp) of the PMOS transistor

To calculate Wp, we'll use the equation for the tail current:

Itail = 2 * upCox * (Wp/L) * (VDD - Vtp)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5 V + 0.8 V)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5.8 V)^2

Solving for Wp:

Wp = (1 mA * 0.2 μm) / (2 * 200 μA/V² * (5.8 V)^2)

Wp = 0.01 μm / (2 * 200 μA/V² * 33.64 V^2)

Wp ≈ 0.0075 μm

Step 7: Calculate the width (Wn) of the NMOS transistors

Given: Wn = 4 * Wp

Wn = 4 * 0.0075 μm

Wn = 0.03 μm

So, the design parameters for the differential amplifier are as follows:

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

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The birdman needs to soar 86.43m in the air to hit the bucket.

The ball's diameter, d, and the amount of time, t, it takes to cross the photogate can both be used to calculate the beginning horizontal velocity. Vo = d/t, then.

Time of motion of the birdman

The duration of the birdman's motion is the amount of time it takes for him to soar to his highest point.

R = Vₓt

where;

R is the birdman's motion's range or his horizontal distance.

Time of motion is t.

The horizontal speed is Vx.

t = R/Vₓ

t = 147/ 35

t = 4.2 seconds

Maximum height the missile has climbed

h = ¹/₂gt²

where;

The birdman's height is measured in h.

Gravitational acceleration, or g,

h = ¹/₂(9.8)(4.2)²

h = 86.43 m

The birdman must therefore fly to a height of 86.43m in order to hit the bucket.

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Answer:

True all waves that go up must come down

I feel like the follow the rule of gravity:everything that goes up must come d5

Answer:

remains constant.

Explanation:

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If difference of time is 1s .

As acceleration remains constant .

Velocity of objects would increase in constant manner.

So distance remains same/constant until the first ball hits the ground.

Answer:

it is 45

Explanation:

element z are isotopes because number of netron are different and number of protons are same

The duration, frequency, and intensity are increased in an exercise program during the progression phase.

A program's progression phase is a key time for developing strength, flexibility, and endurance. In order to keep the body challenged and encourage new adaptations, the duration, frequency, and intensity of the workouts are increased during this phase. People can prevent hitting a plateau and advance towards their fitness objectives by progressively increasing the demands placed on their bodies. To prevent injury or overtraining, it's crucial to approach this phase cautiously and to gradually and carefully increase these factors. An effective progression plan can assist people in achieving their fitness objectives, whether they are to increase their overall health and wellness, lose weight, or gain muscle.
In an exercise program, duration, frequency, and intensity are typically increased during the "progression" phase. This phase focuses on gradually increasing the workload to improve physical fitness and adapt to the exercise routine.

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Oxygen

hope this helps:)

Answer:

Explanation:

the cells need oxygen for metabolism, which also creates carbon dioxide as a waste product. The red blood cells then pick up the carbon dioxide and transport it back to the lung. There we exhale it when we breathe out. Red blood cells can also pick up or release hydrogen and nitrogen.

Answer:

pretty sure its d

Explanation:

The efficiency of the engine is 16%.

The efficiency of the engine is given by,

η = W/Q

η = (W₁ + W₂ + W₃ + W₄)/(Q₁ + Q₂ + Q₃ + Q₄)

Since, the steps 2 and 4 are held at constant volume, the work done in these steps will be zero. Also, the heat enters into the system only during the steps 1 and 4.

So, the efficiency,

η = (W₁ + W₃)/(Q₁ + Q₄)

In step 1

The work done in isothermal expansion,

W₁ = nRT ln(V₂/V₁)

During isothermal expansion, there is no change in internal energy. So, the heat energy,

Q₁ = W₁ = nRT ln(V₂/V₁)

In step 3

Work done in isothermal compression,

W₃ = nRT₂ ln(V₄/V₃)

In step 4

The heat entering into the system,

Q₄ = CvΔT = Cv(T₁ - T₂)

Therefore, efficiency,

η = [nRT₁ ln(1.88) + nRT₂ ln(1/1.88)]/[nRT₁ ln(1.88) + Cv(T₁ - T₂)]

η = (280 - 151)/[280 + (21/8.314 ln(1.88)) (280 - 151)

η = 0.16

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The distance travelled by the player( recoil ) in the time the puck reach the goal is 0.025m.

Mass of the player;

Mass of puck;

Since they were both at rest initially

Initial velocity of player;

Initial velocity of puck;

Velocity of player after the hit;

Velocity of puck after the hit;

Distance to the goal;

Using conservation of linear momentum:

Now, Since they were both at rest initially

We substitute in our values to find the velocity of the player after the hit ( recoil velocity )

{ The negative sign shows that the velocity of both the player and the puck are in opposite direction }

Hence, recoil velocity of the player is 0.075m/s

Now, we determine the time taken for the puck to trach the goal using the relation between distance, velocity and time .

Time = Distance / Velocity

We substitute our values into the expression

Hence, the time taken for the puck to reach the goal is 0.3333 seconds.

Next, we determine the distance travelled by the player( recoil ) in the time the puck reach the goal using the relation between distance, velocity and time .

Time = Distance / Velocity

We substitute in our values

Therefore, the distance travelled by the player( recoil ) in the time the puck reach the goal is 0.025m.

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The wavelength most strongly reflected at the center of the outer surface of a soap bubble with a thickness of 113 nm would be the one that satisfies the condition for constructive interference, given by 2nλ = 2t, where n is the refractive index of the bubble and t is the thickness.

When white light illuminates the soap bubble, different wavelengths of light will interact with the bubble's outer surface. These waves will interfere constructively or destructively depending on their phase relationships. For constructive interference to occur, the path length difference between the reflected wave and the incident wave must be an integer multiple of the wavelength.

In the case of a soap bubble, the reflected wave undergoes a phase change of 180 degrees due to the reflection at the outer surface. This means that the path length difference between the reflected and incident waves is equal to twice the thickness of the bubble.

Therefore, the condition for constructive interference is given by 2nλ = 2t, where n is the refractive index of the bubble and t is the thickness. Rearranging the equation, we find that the wavelength λ is equal to t/n.

Substituting the values, with t = 113 nm and assuming a refractive index for the soap bubble, we can calculate the wavelength.

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The moment of inertia about the rotation axis for the given playground toy, with two children sitting opposite each other, is approximately 145.35 kg·m².

To determine the moment of inertia about the rotation axis for the given playground toy, we need to consider the contributions from the seats and the two children.

Given:

Mass of each seat = 6.4 kg

Length of the rods (r) = 1.5 m

Mass of the first child (m₁)= 16 kg

Mass of the second child (m₂) = 23 kg

The moment of inertia of each seat can be calculated using the formula for the moment of inertia of a point mass about an axis:

\(I_{seat} = m_{seat times} r^2\)

For each seat, the moment of inertia is:

\(I_{seat} = 6.4 kg times (1.5 m)^2= 14.4 kg\cdot m^2\)

Now, to calculate the moment of inertia contributed by the children, we need to consider that the children are located opposite each other. Assuming the axis of rotation passes through the center of mass of the children-seats system, the moment of inertia for each child is:

\(I_{child} = m_{child times} r^2\)

For the first child (m₁):

\(I_1 = 16 kg times (1.5 m)^2 = 36 kgm^2\)

For the second child (m₂):

\(I_2 = 23 kg times (1.5 m)^2 = 51.75 kgm^2\)

Finally, we can calculate the total moment of inertia by summing the contributions from the seats and the children:

Total moment of inertia =\(4 times I_{seat} + I_1 + I_2\)

= \(4 times (14.4 kgm^2) + 36 kgm^2 + 51.75 kgm^2\)

= \(57.6 kgm^2 + 36 kgm^2 + 51.75 kgm^2\)

= \(145.35 kgm^2\)

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Answer:

Osteologists are trained to read and translate a bone's story.

Explanation:

This rare skill provides information that helps us better understand ancient cultures, solve mysteries, and learn about animals. Being an Osteologist means you have a variety of job opportunities.

Answer:

You can use a block and an inclined plane (just a tilted board)

Place the block on the plane and gradually increase the angle the plane makes with the horizontal.

Static friction will keep the block in place (no sliding) until the angle between the plane and the horizontal is large enough. The block will now slide but is still under the influence of kinetic friction. Thus static friction is greater than sliding friction.

Answer:

??

Explanation:

Answer:

A

Explanation:

Positive slope lines have a left to right ascent. A negative slope is present on lines that descend from left to right. Consequently, a diagonal line with a positive slope (/) would be to the right. Thus, option A is correct.

The height difference between two tile corners that is on the diagonal. A hidden value is used to determine if a tile can be seeded on, passed by a cart, or have the corner of the pavement tile lowered.

When two variables have a positive slope, it means that they are positively correlated; that is, when x rises, y rises as well, and when x falls, y falls as well.

A line on a line graph that has a positive slope rises as the line advances from left to right.

Be aware that a line's positive slope causes it to slope upward from left to right. Remember that a line with a negative slope descends from left to right. Keep in mind that a line has no slope when it is horizontal.

Therefore, positively sloping diagonal general shape of the graph line.

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Answer:

2m/s

Explanation:

10m / 5 s

Simplify and divide.

2 m / 1 s

Answer:

The speed would be 2

Explanation:

The principal quantum number is the number of shells of an atom. So it can only be positive integers. So the correct answer is option D.

Quantum numbers are the numbers which represent the position and energy of an electron in an atom. There are four quantum numbers.

So principal quantum number can have positive integer as values. So option D is correct.

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