The weight of the traffic light must be 400 N.
In this scenario, the tension in each rope segment is 200 N, and the resultant force at the midpoint is zero. This means that the vertical components of the tension forces cancel out the weight of the traffic light. Since the weight acts vertically downwards, it must be balanced by the vertical components of the tension forces.
Considering the angle of 10° with the horizontal, we can determine the vertical component of each tension force using trigonometry. The vertical component is given by Tension * sin(angle). In this case, each rope segment has a tension of 200 N, so the vertical component is 200 * sin(10°).
Since there are two rope segments, the total vertical component of the tension forces is 2 * (200 * sin(10°)). To balance the weight of the traffic light, this total vertical component must be equal to the weight. Therefore, the weight of the traffic light is 2 * (200 * sin(10°)), which simplifies to approximately 400 N.
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an ice skater spins with her arms close to her body with a rotational inertia i ii i i, start subscript, i, end subscript and angular speed \omega iω i omega, start subscript, i, end subscript. the ice skater then extends her arms outward and spins with rotational inertia i fi f i, start subscript, f, end subscript. what is her final angular speed \omega fω f omega, start subscript, f, end subscript?
The final angular speed (ωf) is equal to the initial rotational inertia (Ii) multiplied by the initial angular speed (ωi) divided by the final rotational inertia (If).
According to the conservation of angular momentum, the initial angular momentum of the ice skater must be equal to the final angular momentum after extending her arms outward.
The angular momentum (L) is given by the equation:
L = I * ω
where I represents the rotational inertia and ω represents the angular speed.
Given:
Initial rotational inertia (Ii) = Ii
Initial angular speed (ωi) = ωi
Final rotational inertia (If) = If
Using the conservation of angular momentum, we can write:
Ii * ωi = If * ωf
Rearranging the equation to solve for the final angular speed (ωf), we have:
ωf = (Ii * ωi) / If
Therefore, the final angular speed (ωf) is equal to the initial rotational inertia (Ii) multiplied by the initial angular speed (ωi) divided by the final rotational inertia (If).
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Your roof radiates heat away at night. At what net rate does the heat radiate from a 275 m² black roof on a night when the roof temperature is 33°C in the surrounding temperature is 14°C? The emissivity of the roof is 0.900.
We are asked to determine the net rate of radiation of a roof given its area and its emisivity. To do that we will use the following formula:
\(P_{net}=\sigma eA(T_0^4-T^4)\)Where:
\(\begin{gathered} P_{net}=\text{ net rate of radiation} \\ \sigma=\text{ Stefan-Boltzmann's constant} \\ e=\text{ emisivity} \\ A=\text{ area} \\ T_0=\text{ surrounding temperature} \\ T=\text{ temperature of the roof} \end{gathered}\)The Stefan-Boltzmann's constant is given by:
\(\sigma=5.67\times10^{-8}\frac{W}{m^2K^4}\)Now, we need to convert the temperature to Kelvin. To do that we use the following:
\(T_K=T_c+273.15\)Where:
\(\begin{gathered} T_K=\text{ temperature in Kelvin} \\ T_C=\text{ temperature in Celsius} \end{gathered}\)For the 33°C we have:
\(T_k(33)=33+273.15=306.15\)For the 14°C:
\(T_K(14)=14+273.15=287.15\)Now, we substitute the values:
\(P_{net}=(5.67\times10^{-8}\frac{W}{m^2K^4})(0.9)(275m^2)((287.15K)^4-(306.15K)^4)\)Solving the operation:
\(P_{net}=-27870.84W\)Therefore, the net rate of radiation is -27870.84 Watts.
A hockey puck slides across a frozen pond. if ice friction and air resistance are neglected, the force needed to keep the puck sliding at constant velocity is:________
Answer:
Zero
Explanation:
Zero.... Inertia states a body in motion will remain in motion unless acted on by external forces.... no friction forces means it needs no force to keep going
The parent function `f\left(x\right)=\sqrt[3]{x}` is compressed vertically by a factor of `\frac{1}{3}` and then translated 3 units left and 7 units down. What is the transformed function `g\left(x\right)`?
Answer:
The answer is below
Explanation:
Given that f(x) = x√3.
A function can be vertically stretched or compressed by multiplying it by a positive constant. If the constant is greater than 1, it is vertically stretched and if the constant is less than 1 it is vertically compressed.
If a function f(x) = x is compressed or stretched by a constant a, then the new function g(x) = a f(x)
If a function f(x) = x is translated a units down, then the new function g(x) = f(x) - a
If a function f(x) = x is translated a units left, then the new function g(x) = f(x-a)
If f(x) = x√3 is compressed vertically by a factor of 1/3. The new function is
\(f(x)'=x\sqrt{3} *\frac{1}{3} \\\\f(x)'=\frac{x}{3} \sqrt{3}\)
If it is then translated 3 units left and 7 units down, the transformed function g(x) is:
\(g(x)=(\frac{x-3}{3}\sqrt{3} )-7\)
PLS ANSWER FAST WILL GIVE BRAINLEST!!
Answer using mass m= F divided by a
And also kilograms {kg}
A 7.5 N force is applied to a football generating an initial acceleration of 15 m / s2. Calculate the mass of the football.
Answer:
from
force =mass x acceleration
mass = force/acceleration
m = f/a
m = 7.5/15
m=0.5kg
\(\huge\bf{\pink{\underline{\underline{\mathcal{AnSwer࿐}}}}}\)
Given:-acceleration = 1000 m/s²
force = 5000 N
To find:-Mass of the cannonball
Formula to be used:-\(\longrightarrow\) \(\underline{\boxed{\sf mass = \dfrac{force}{acceleration}}}\)
Solution:-:\(\implies\) \(\sf mass = \dfrac{5000}{1000}\)
:\(\implies\) \(\sf mass = 5 kg \)
hence, the required answer is 5kg.
______________________________
In a free body diagram all the forces are depicted as pointing _______ the central box
Answer:
There are three forces acting upon the system - the gravity force (the Earth pulls down on the 15.0 kg of mass), the normal force (the floor pushes up on the system to support its weight), and the applied force (the hand is pushing on the back part of the system).
Explanation:
Answer:
what he said
Explanation:
planimeters have a counter that registers the number of times the wheel revolves as c is traversed. explain how the number of revolutions is converted to the area of r
Planimeters are devices used to measure the area of irregular shapes on a surface. The number of revolutions is converted to the area of r
Area (A) = (C x R^2) / (2π)
The conversion of the number of wheel revolutions to the area of the shape measured by a planimeter is based on the concept of the polar planimeter. A polar planimeter consists of a wheel that rotates as it moves along the boundary of the shape being measured. The wheel's radius is known as R.
When the wheel rotates, it traces a spiral path, and the area of the shape enclosed by this spiral path can be determined using the formula:
Area (A) = (C x R^2) / (2π)
Here, C represents the number of wheel revolutions recorded by the planimeter counter. The formula derives from the concept that the area of a sector of a circle is equal to (1/2) x (radius)^2 x angle (in radians). By integrating the contributions of each sector covered by the wheel revolutions, the total area of the shape can be calculated.
Therefore, by multiplying the number of revolutions (C) by the square of the wheel radius (R^2) and dividing by 2π, the planimeter can accurately convert the rotations into the area of the irregular shape being measured.
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If a 1000 kg car is traveling at 3
meters per second, what is its
kinetic energy?
a sight glass that is full of vapor or liquid may look the same.
The given statement is true. A sight glass is a transparent or translucent window installed in a pipeline or vessel to visually inspect the presence, level, and characteristics of a fluid.
Explanation: When a sight glass is full of vapor, it may appear similar to when it is filled with liquid. This is because both vapor and certain liquids can be transparent or have similar optical properties. In such cases, it can be challenging to distinguish between a sight glass filled with vapor and one filled with liquid by visual observation alone.
To accurately determine whether a sight glass is filled with vapor or liquid, additional information or techniques may be required.
For example, measuring the temperature or pressure of the system, observing any condensation or evaporation occurring in the sight glass, or employing other complementary instruments or indicators can help differentiate between vapor and liquid contents.
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Communication satellites are often put in a geo-synchronous orbit, meaning they have an orbital period of 24 hours and stay over the same spot above the equator at all times. Given that the Earth has a mass of 5.97 x 1024 kg and a radius of 6.37 x 106 meters, determine the following: a. What is the orbital height of the satellite relative to the surface of the Earth
Answer:
h = 35857 km
Explanation:
A geosynchronous orbit can be defined as circular orbit which lies on the Earth's equatorial plane and follows the direction of the Earth's rotation in a period that's equal to the Earth's rotational period and thereby appearing motionless, at a fixed position in the sky relative to the ground observers.
We are given;
Radius of earth(R) = 6.37 x 10^(6) m
Mass of earth (Me) = 5.97 x 10^(24) kg
Gravitational constant = 6.67 × 10^(-11) m³/kg.s²
The earth has a rotational period of 24 hours per day. This gives in seconds
T = 24 × 60 × 60
T = 86400 s
Let's make the height of the orbit from Earth's surface to be h
Also, let ω be the uniform angular velocity in rad/s with which the satellite rotates in the geosynchronous orbit
Now, equating the centripetal force with the gravitational force gives us;
mω²(R + h) = G•Me•m/(R + h)²
m will cancel out. Also ω can be written as 2π/T
Thus,we now have;
(R + h) = ∛(G•Me•T²/(4π²))
Plugging in the relevant values, we have;
(R + h) = ∛(6.67 × 10^(-11) × 5.97 x 10^(24) × 86400²/(4π²))
(R + h) = 42227 Km
Since R = 6.37 x 10^(6)m = 6370 km
Thus;. h = 42227 - 6370 = 35857 km
Carbon plays an important role in living things. The carbon cycle describes the
storage and exchange of carbon between the Earth's biosphere (living matter),
atmosphere
(air), hydrosphere (water), and geosphere (earth).
a. Explain how the carbon, found in the fossil fuel emissions, impacts each sphere.
Explanation:
The Carbon Cycle and Earth's climate Carbon Dioxide is an atmospheric constituent that plays several vital roles in the environment. It is a greenhouse gas that traps infrared radiation in the atmosphere. it plays a crucial role in the weathering of rocks. it is the carbon source for plants.
what happens as a planet approaches the perihelion of its orbit around the sun?
the planet approaches to it's highest velocity
Since the Sun is not at the center of an elliptical orbit, the planet moves closer towards and further away from the Sun as it orbits.
What happens as a planet approaches the perihelion of its orbit around the sun ?The place where the planet is closest to the Sun is called perihelion. When the planet is furthest away from the Sun, it is at aphelion.
The words "aphelion" and "perihelion" come from the Greek language. In Greek, "helios" mean Sun, "peri" means near, and "apo" means away from.When Earth is at perihelion, it is about 147 million km (91 million miles) from the Sun. When it is at aphelion, it is 152 million km (almost 95 million miles) from the Sun.Learn more about Perihelion here:
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what would be the noontime altitude of the sun at the time of the summer solstice?
At the time of the summer solstice, the noontime altitude of the sun is at its highest point, around 90°.
What is altitude?Altitude is the height above sea level. It is typically measured in either metres or feet. In aviation, altitude can also refer to the vertical distance between an aircraft and a certain reference point on the ground. Altitude can be used to determine the air pressure, temperature, and density of the air. Altitude can also be used to calculate the distance a plane can travel without refueling. Altitude can play an important role in the weather of an area, as air pressure and temperature tend to decrease with altitude. Altitude can also affect the type of vegetation found in an area. In mountain regions, the altitude can have a dramatic effect on the climate, creating distinct areas of vegetation and wildlife. Altitude can also affect the types of crops that can be grown in an area, depending on the air pressure, temperature, and precipitation.
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can you give me an example about radiation
Explanation:
A burning candle emits radiation in the form of heat and light. The Sun emits radiation in the form of light, heat, and particles.
Answer: The energy from the sun is one great example of radiation. The sun emits light in a broad range of wavelengths which all contain energy. These waves are also discussed in the climate section for energy balance. The waves are emitted from the sun and travel through space and hit the earth and other planets.
EXTRA EXAMPLES: heat from a stove burner.
visible light from a candle.
x-rays from an x-ray machine.
alpha particles emitted from the radioactive decay of uranium.
sound waves from your stereo.
microwaves from a microwave oven.
electromagnetic radiation from your cell phone.
Which type of radio broadcast has a greater broadcast range, AM or FM? Explain.
How many grams of aluminum sulfate must be dissolved in 650. mL of water to make 84.0% (m/v) aluminum sulfate solution?
3415.2 grams
Explanation
to solve this we can use a rule of three
Step 1
Let
water= 100-84%= 16%
so,
\(\text{ 16 \%=650 mL}\)for the water , 1 mL = 1 gram , so
\(\text{ 16\% =650 grams}\)now, let represents the mass of the aluminiu, so
\(\text{ 84 \%= x}\)a) the ratio is the same, so we have a proportion
\(\frac{16}{650}=\frac{84}{x}\)Step 2
finally, solve for x
\(\begin{gathered} \frac{16}{650}=\frac{84}{x} \\ \text{cross multiply } \\ 16\cdot x=84\cdot650 \\ 16x=54600 \\ \text{divide both sides by 16} \\ \frac{16x}{16}=\frac{54600}{16} \\ x=3412.5 \end{gathered}\)so, the mass of the aluminum is
3415.2 grams
How fast is 10 km in miles?
Therefore, 10 kilometers is equivalent to approximately 6.21371 miles.
What is distance?Distance is a measure of how far apart two objects or points are, and is commonly defined as the length or magnitude of the shortest path connecting them. Distance can be measured in various units such as meters, kilometers, miles, feet, or yards, depending on the context. In physics, distance is a fundamental concept that plays an important role in describing the position, motion, and interactions of objects in space. It is a scalar quantity that can be positive or zero, but cannot be negative. Distance is also distinct from displacement, which is the change in position of an object over time, and is a vector quantity that can have a direction and magnitude. Distance can be calculated using various techniques, such as using measuring devices like rulers, tape measures, or surveying tools, or using mathematical formulas based on known properties of the objects and the space in which they exist.
Here,
To convert kilometers to miles, you can use the conversion factor of 0.621371.
So to convert 10 kilometers to miles, we multiply 10 by 0.621371:
10 kilometers * 0.621371 = 6.21371 miles
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Consider an airplane flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. Calculate the pressure at this point. Assume incompressible flow. Given: p _1 =7.01×10^4 N/m^2 and rho=0.909kg/m^3 . The pressure at a point on the wing is ×10 ^4 N/m^2
An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\).
To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.
The equation is as follows:
P + 1/2 * ρ * \(V^2\) = constant
where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.
Given:
\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)
ρ = \(0.909 kg/m^3\) (density of the fluid)
\(V_1 = 42 m/s\) (velocity of the airplane)
\(V_2 = 88 m/s\) (velocity at the point on the wing)
To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:
\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\) * ρ * \(V_2^2\)
Substituting the given values:
\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)
Simplifying the equation:
\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)
7.01 × 10^4 + 804.906 = P + 3526.242
\(P + 4329.148 = 7.01 *10^4\)
\(P = 7.01 * 10^4 - 4329.148\)
\(P = 6.96 * 10^4 N/m^2\)
Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)
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Avery sees a UFO out her bedroom window and calls to report it to the police. She says, "The UFO moved 20.0 m east, 10.0 m north, and 30.0 m west before it disappeared." What was the displacement of the UFO while Avery was watching?
Answer:
10^2 + 10^2 = x^2
x = 14.2 m NW
A mass of 100 kg is 100 m away from a mass of 50 kg. Calculate the force of attraction between the masses. Show your work
The force of attraction between the two masses is \(3.335 \times 10^{-8} N\).
The force of attraction between two masses is given by the gravitational force equation, which is expressed as:
\($F = G \cdot \frac{m_1 \cdot m_2}{r^2}$\)
where F is the force of attraction, G is the gravitational constant (\($6.67 \times 10^{-11} , \text{N}\cdot\text{m}^2/\text{kg}^2$\)), \(m_1\)1 and \(m_2\) are the masses of the two objects, and r is the distance between the centers of the two masses.
In this case, \(m_1\) = 100 kg, \(m_2\) = 50 kg, and r = 100 m. Substituting these values into the equation, we get:
\($F = 6.67 \times 10^{-11} , \text{N}\cdot\text{m}^2/\text{kg}^2 \cdot \frac{(100 , \text{kg}) \cdot (50 , \text{kg})}{(100 , \text{m})^2}$\)
\(F = 3.335 \times 10^{-8} N\)
It is worth noting that the force of attraction between the two masses is very small, which is due to the large distance between them. The gravitational force decreases rapidly with distance, so as the distance between the two masses increases, the force of attraction decreases as well.
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a car is driven 1.5 kilometers west in 2 minutes. what is the velocity in m/s?
A student makes a homemade resistor from a graphite pencil 5.00 cm long, where the graphite is 0.05 mm in diameter. The resistivity of the graphite is rho=1.38×10−5Ω/mrho=1.38×10−5Ω/m . The homemade resistor is place in series with a switch, a 10.00-mF uncharged capacitor and a 0.50-V power source. (a) What is the RC time constant of the circuit? (b) What is the potential drop across the pencil 1.00 s after the switch is closed?
Answer:
(a) RC time constant of the circuit is 6.9 × 10⁻⁶ ms
(b) The potential drop across the capacitor 1.00 s after the switch is closed is 0 V
Explanation:
The given parameters are
The length of the graphite pencil, L = 5.00 cm
The diameter of the graphite, D = 0.05 mm
The resistivity of the graphite, ρ = 1.38 × 10⁻⁵ Ω/m
The capacitance of the capacitor, C = 10.0 mF
The voltage of the power source, V = 0.50-V
(a) The RC time constant of the circuit, τ, is given as follows;
τ = R × C
Where;
R = The resistance of the graphite = L × ρ
C = The capacitance of the capacitor
∴ R = 5.00 cm × 1.38 × 10⁻⁵ Ω/m = 6.9 × 10⁻⁷ Ω
RC time constant of the circuit, τ = 6.9 × 10⁻⁷ Ω × 10.0 mF = 6.9 × 10⁻⁶ ms
RC time constant of the circuit, τ = 6.9 × 10⁻⁶ ms
(b) The potential drop after t = 1.00 s is given as follows;
\(i = \dfrac{V}{R} \cdot e^{-\dfrac{t}{R\cdot C} }\)
Where;
I = The current in the circuit
V = The voltage in the circuit = 0.50 V
R = resistance in the circuit = 6.9 × 10⁻⁷ Ω
C = The series capacitance = 10.0 mF
t = The time taken = 1.00 s
Plugging in the variable values, gives;
\(I = \dfrac{0.5}{6.9 \times 10^{-7}} \cdot e^{-\dfrac{1.00}{6.9 \times 10^{-7}\times 10.0 \ mF} } = 0\)
V(1) = I·R = 0 × R = 0
The potential drop across the capacitor 1.00 s after the switch is closed, V(1) = 0 V
A year is the time it takes a planet to complete one orbit. use your data to estimate the year length for each planet. use time units of earth years or earth months. why does it take the outer planets so long to orbit the sun? try to come up with 2 reasons.
The planets of the solar system has the orbiting time.
Mercury- 88 days, Venus-225 days, Earth- 365 days, Mars-687 days, Jupiter- 12 years, Saturn- 29 years, Uranus- 84 years, Neptune- 165 years, Pluto- 248 years.
What is solar system?Solar system consists of all the planets and the most importantly the center of the solar system is Sun.
Sun is the main focus of the solar system. It emits high temperature light rays on the planets which in turn emit lights and be visible.
Outer planets take longer to orbit the sun because the gravitational pull is weaker as shown in the inverse square law.
The outer planets very far away from the Sun, means that they have more distance to cover in their orbit.
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derive from one of the laws of motion the relation between the momentum produced in a body and the force applied on the body
Answer:
The fact that change in moment is equal to force times duration can be derived from Newton's Second Law of Motion (assuming that the net force on the object is constant.)
Explanation:
Let \(m\) denote the mass of an object. Let \(\Delta v\) denote the change in the velocity of this object. The change in momentum of this object will be \(\Delta p = m\, \Delta v\).
Let \(F_{\text{net}}\) denote the net force (resultant force) on the object. Let \(a\) denote the acceleration of this object. By the law of motion, \(F_{\text{net}} = m\, a\), or equivalently, \(a = (F_{\text{net}} / m)\).
Assume that this net force is constant and is exerted on this object over a period of \(\Delta t\). With an acceleration of \(a = (F_{\text{net}} / m)\), the velocity of this object would have changed by:
\(\begin{aligned}\Delta v &= a\, \Delta t \\ &= \left(\frac{F_{\text{net}}}{m}\right)\, (\Delta t) \\ &= \frac{F_{\text{net}}\, \Delta t}{m}\end{aligned}\).
Multiply both sides of this equation by the mass \(m\) of the object to obtain:
\(m\, \Delta v = F_{\text{net}}\, \Delta t\).
Note that \(m\, \Delta v\) is equal to the change in momentum (\(\Delta p = m\, \Delta v\).) Therefore, if the net force \(F_{\text{net}}\) on the object is constant, the change in the momentum \(\Delta p\) over time period \(\Delta t\) will be equal to \(F_{\text{net}}\, \Delta t\) (net impulse on the object.)
a(n) _____ shows the timing of interactions between objects as they occur.
A sequence diagram is a type of UML (Unified Modeling Language) diagram that shows the interactions between objects or components of a system as they occur in a chronological sequence.
It is a graphical representation of the interactions that take place between objects or components of a system, depicting the order of messages that are exchanged between them.
Sequence diagrams are used to visualize the flow of a system's functionality, as well as the communication and collaboration between the various components of the system. They are especially useful in understanding complex systems and identifying areas that may require improvement or optimization. Sequence diagrams are also often used to document and communicate the design of a system to stakeholders or development teams.
In summary, a sequence diagram shows the timing of interactions between objects or components of a system as they occur. It is a valuable tool in understanding and communicating the behavior and functionality of complex systems.
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though its economics question can anybody help me
What type of reproduction occurs when a cell divides to form two new cells?
a. autotrophic b. heterotrophic c. asexual reproduction d. sexual reproduction
Answer:
d. sexual reproduction
Explanation:
A single cell divides to make two cells and these two cells then divide to: we call this process "cell division" and "cell reproduction," and there are two ways cells divide—mitosis and meiosis. This is all part of sexual reproduction.
What happens to the chemical structure of water when it changes state?
A. Water molecules break apart to form individual atoms.
B. Water molecules harden into ice molecules.
C. Water molecules melt into gas molecules.
D. Nothing happens to the chemical structure.
Answer:
c) Water molecules melt into gas molecules.
The chemical structure of water when it changes state - D. Nothing happens to the chemical structure.
Physical state of an object is the condition where substance have different energy content. For instance water is on heating it change into vapor or gaseous phase while cooling (decreasing heat content) causes water to become ice in solid phase. Therefore,
physical states is only in the energy content of the substance.Change in the state or phase of water does not change the chemical property. However, changing phase can alter the speed of the chemical reactions.Thus, the change in physical state do not affect chemical properties, but affects the kinetics of the reactions.
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Which two statements are true for reversible reactions that reach dynamic equilibrium?
The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."
What is dynamic equilibrium?The dynamic equilibrium is defined as a state of a particular system wherein the reversible reaction takes place and ceases modifying the ratio of reactants as well as products.
The chemical reaction is a method for creating novel chemicals with unique features.
The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."
Therefore, the correct answer will be an option (C).
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What happens to the electricity in a strand of
Christmas lights if they are plugged in and not
working?
Answer:
Either all the lights are very old and need new ones or the cable is wet.
Explanation: