Therefore the speed at the ground is 185. 3 m/s.
horizontal speed = 485 km/hr
= 485 * (5/18)
= 134.72m/s
h = 875 m
g = 9.8 m/s^2
a) Using formula,
h = (1/2) gt^2
875 = (9.8/2) t^2
t = 13.36 seconds
b)
D = u * t
D = 131.11 * 13.36
D = 1751.64 m
D = 1.75 km
c) when it lands on the ground
Vx = 131.11 m/s
Vy = gt
= 9.8 * 13.36
= 130.9 m/s
Therefore the speed at ground = [ 131.11^2 + 130.9^2]^(1/2)
= 185. 3 m/s
The pace is the directional speed of an item in motion as a demonstration of its price of alternate in the role as observed from a specific body of reference and as measured via a particular widespread of time (e.g. 60 km/h northbound). speed is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of our bodies.
Velocity is a bodily vector amount; each significance and route are needed to define it. The scalar absolute value (significance) of speed is known as velocity, being a coherent derived unit whose quantity is measured inside the SI (metric device) as meters in step with second (m/s or m⋅s−1). as an example, "5 meters in step with 2d" is a scalar, whereas "5 meters consistent with 2nd east" is a vector. If there is a trade-in velocity, route, or each, then the object is stated to be present process an acceleration.
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A car has a mass of 1000 kg. It is driving to the right.
Draw a free body diagram showing the forces acting on it.
Find it’s weight on Earth.
How do I even draw a body diagram? Please help.
Answer:
Explanation:
What is a free body diagram?
Answer: a force diagram is a graphical illustration used to visualize the applied forces and resulting reactions on a body in a given condition
Drawing a free-body diagram for this problem
Answer: Look at the attached picture, ask me any questions if you are still confused. It is a little messy since I didn't have my pen.
Find its weight on Earth
Answer: The weight is dependent on the mass of the object and the gravitational constant on the planet. The gravitational constant, in this case, is 9.8.
so the weight = mass * gravitational constant = m * g = 1000 * 9.8
= 9800 N
Hope that helps!
Please help me with this assignment!
Answer:
Ice cube, molecules, melting, zero degrees, liquid, faster, temperature, 100 degrees, steam
Answer:
lol you got the answer just need points sorry
Explanation:
A metal that has a mass of 23. 4 g has a heat capacity of 6. 18 J/°C. What is the specific heat of the metal? (hint: what is unit of specific heat?) 4. 15. 3 g of NaNO3 were dissolved in 100. G of water in a calorimeter. The temperature of the water dropped from 25. 00°C to 21. 56°C. Calculate the energy given off. 5. How much heat is required to raise the temperature of 20. 0 g of iron from 26. 00°C to 72. 30°C? The specific heat of iron is 0. 4470 J/g°C
1)The specific heat of the given metal is 0.2641 J/g°C. 2) The energy given off if temperature of the water dropped from 25. 00°C to 21. 56°C in given case is 1413 J. 3) The heat that is required to raise the temperature of 20. 0 g of iron from 26. 00°C to 72. 30°C is 314 J.
1) Specific heat is defined as the amount of heat required to raise the temperature of a substance by one degree Celsius per unit of mass, typically Joules per gram per Celsius. Therefore, the specific heat of the given metal is calculated by using the formula,
Specific heat = Heat capacity/mass
Specific heat = 6.18 J/°C/23.4 g = 0.2641 J/g°C` (rounded to four significant figures)
Hence, the specific heat of the metal is 0.2641 J/g°C.
2) The amount of heat given off is given by the formula,
q = mcΔT
where q is the heat released, m is the mass of water, c is the specific heat of water, and ΔT is the change in temperature.
q = (100.0 g) (4.184 J/g°C) (25.00 - 21.56)°C
`q = 1413 J (rounded to three significant figures)
Thus, the energy given off is 1413 J.
3) The amount of heat required to raise the temperature of the given mass of iron is calculated using the formula,
q = mcΔT
where q is the heat absorbed, m is the mass of the iron, c is the specific heat of iron, and ΔT is the change in temperature.
q = (20.0 g) (0.4470 J/g°C) (72.30 - 26.00)°C
q = 314 J
Thus, the heat required to raise the temperature of 20.0 g of iron from 26.00°C to 72.30°C is 314 J (rounded to three significant figures).
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How much energy is stored in a room 3.0 m by 4.0 m by 2.4 m due to the earth's magnetic field with a strength of 5.0 × 10-5 T? (
The energy stored in the room due to the Earth's magnetic field is approximately 1.44 × 10^(-4) joules (J).
The energy stored in a magnetic field can be calculated using the formula:
Energy (E) = (1/2) * magnetic permeability (μ) * magnetic field strength (B)^2 * volume (V),
where the magnetic permeability (μ) is a constant.
Given:
Length of the room (l) = 3.0 m
Width of the room (w) = 4.0 m
Height of the room (h) = 2.4 m
Magnetic field strength (B) = 5.0 × 10^(-5) T (tesla)
The volume of the room (V) can be calculated by multiplying the length, width, and height:
V = l * w * h
= 3.0 m * 4.0 m * 2.4 m
= 28.8 m³
The magnetic permeability of free space (μ₀) is approximately 4π × 10^(-7) T·m/A.
Now we can substitute the given values into the energy formula:
E = (1/2) * μ₀ * B^2 * V
= (1/2) * (4π × 10^(-7) T·m/A) * (5.0 × 10^(-5) T)^2 * 28.8 m³
≈ 1.44 × 10^(-4) J
Therefore, the energy stored in the room due to the Earth's magnetic field is approximately 1.44 × 10^(-4) joules (J).
The energy stored in the room with dimensions 3.0 m by 4.0 m by 2.4 m due to the Earth's magnetic field with a strength of 5.0 × 10^(-5) T is approximately 1.44 × 10^(-4) joules (J). This calculation is based on the formula for magnetic energy, incorporating the volume of the room and the magnetic field strength.
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You hang an object with a mass of 0.5kg on a spring, and the spring stretches 0.1m. If the stiffness of the spring is 50 N/m, what is the elastic energy stored in the spring?
Answer:
0.25 N-m
Explanation:
PE=0.5kx^2; PE=potential engery, k=stiffness of spring, x=displacement
=0.5(50)(0.1^2)
=0.25 N-m
a scientist studies how the temperature of a baseball affects how far it goes when hit by a bat. what will make this experiment more repeatable?
A scientist is studying how the temperature of a baseball affects how far it goes when hit by a bat. The scientist aims to make the experiment as repeatable as possible by following specific procedures that will allow for consistency and accuracy. The following steps will make the experiment more repeatable:
1. Standardization of the equipment: The scientist must ensure that the equipment used in the experiment is standardized. They should use the same type of bat, ball, and equipment for every trial to make the experiment as repeatable as possible.
2. Standardization of the environment: The scientist must maintain a standard environment for the experiment. The temperature, humidity, and atmospheric pressure must be the same for every trial.
3. Randomization: The scientist should randomly choose the order of trials to eliminate any potential biases.
4. Multiple Trials: The scientist should repeat the experiment multiple times to obtain accurate and consistent results. This will help to identify any anomalies or errors.
5. Record Keeping: The scientist must maintain accurate records of all the data collected from the experiment. They should record the date, time, and temperature of the ball and any other relevant information that can help to repeat the experiment.
6. Data Analysis: The scientist should analyze the data obtained from the experiment using statistical methods to identify any trends or patterns.
By following these steps, the scientist can make the experiment more repeatable and achieve accurate and consistent results.
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5. a canoe accelerates away from shore at 0.45 m/s2. what is the canoe’s velocity after traveling 32 m?
The canoe's velocity after traveling 32 m is 9.4 m/s.
To find the velocity, we can use the formula:
v = u + at,
where v is the final velocity, u is the initial velocity (assumed to be zero as the canoe starts from rest), a is the acceleration, and t is the time.
In this case, the initial velocity u is 0 m/s, the acceleration a is 0.45 m/s², and the distance traveled d is 32 m. We need to find the final velocity v.
We can rearrange the formula as:
v = √(u² + 2ad).
Since u = 0, the formula simplifies to:
v = √(2ad).
Plugging in the values, we get:
v = √(2 × 0.45 m/s² × 32 m) ≈ 9.4 m/s.
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What is the current in a circuit that has a voltage of 1.5v and a resistance of 15?
Answer:
0.1 amps or A
Explanation:
I believe to calculate that you would have to use the formula V = IR and change it to:
I = V/R
I = 1.5/15
I = 0.1 amps or A
ANSWER AND I WILL GIVE YOU POINTS
You exert 500 N down on the earth as you jump into the air. How much force does the earth exert back on you?
Answer:
500 Newton itself
Explanation:
Newton's third law of motion
22. two slits, each 0.80 mm wide, are 2.6 mm apart: when light is shone through them onto a screen how many interference maxima are there between the first diffraction minimum on the left side and the first diffraction minimum on the right side? a 1 b. 3 c.5 d. 7 e.9
Option (D) is the correct answer
Given data: width of each slit, a = 0.80 mm.
distance between the slits, d = 2.6 mm
If the wavelength of light is \lambda then,
2.6 ) = 2 x (0.8) = 6.5 r=2x
x = 7 ( taking the next higher integer of 6.5)
The wavelength of a wave describes how lengthy the wave is. The distance from the "crest" (top) of 1 wave to the crest of the following wave is the wavelength.
Alternately, we can degree from the "trough" (bottom) of 1 wave to the trough of the subsequent wave and get the equal price for the wavelength.
SI unit of wavelength is metre . At the same time as measuring wavelength the multiples or fractions of a metre is also used. Extensively, exponential powers of 10 are used whilst wavelengths are of a huge assets.
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An isolated system can exchange ______ with its surroundings
a. both matter and energy
b. matter but not energy
c. energy but not matter
d. neither matter nor energy
Explanation:
An isolated system cannot exchange any heat, work, or matter with the surroundings, while an open system can exchange energy and matter.
What is the mass of a box that was pushed across the floor with a force of 120N and an acceleration of 30 m/s2?
The answer is the mass of the box is 4 kg. When an external force is applied to an object, it causes the object to accelerate. The amount of acceleration is directly proportional to the applied force, and inversely proportional to the mass of the object.
In other words, the greater the force, the greater the acceleration, and the greater the mass, the less the acceleration.To solve this problem, we are given the force applied and the acceleration of an object, and we need to find the mass of the object. We can use the equation F = ma, where F is the force applied, m is the mass of the object, and a is the acceleration of the object. Substituting the given values, we get:
F = ma
120 N = m × 30 m/s^2
Solving for m, we get:
m = 120 N / 30 m/s^2
m = 4 kg
Therefore, the mass of the box is 4 kg.
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'If you increase the frequency of a sound wave four times, what will happen to its speed?
ОА.
The speed will increase four times.
OB.
The speed will decrease four times.
O c.
The speed will remain the same.
OD
The speed will increase twice.
O E.
The speed will decrease twice.
PLEASE PLEASE PLEASE PLEASE PLEASE HELP!!!!!!!!
A car traveled 88 km in 1.0 hour, 91 km in the next 2.0 hours, and then 76 km in 1.0 hour before reaching its destination. What was the car’s average speed?
Answer:
64 km/h
Explanation:
now assume that the mass of particle 1 is 2m , while the mass of particle 2 remains m . if the collision is elastic, what are the final velocities v1 and v2 of particles 1 and 2?
The collision is elastic, the final velocities v1 and v2 of particles 1 and 2 (v₁, v₂) = [(v/3), (4v/3)] Or (v₁, v₂) = (v, 0)
In elastic collisions, the momentum and kinetic energy is usually conserved.
The momentum before collision = momentum after collision
And
Kinetic energy before collision = Kinetic energy after collision
Momentum of object 1 before collision = (2m)v = 2mv
Momentum of object 2 before collision = (m)(0) = 0
Momentum of object 1 after collision = (2m)(v₁) = 2mv₁
Momentum of object 2 after collision = (m)(v₂) = mv₂
So, we have
2mv = 2mv₁ + mv₂
2v = 2v₁ + v₂
v₂ = 2v - 2v₁ (eqn 1)
Kinetic energy of object 1 before collision = (1/2)(2m)(v²) = mv²
Kinetic energy of object 2 before collision = (1/2)(m)(0²) = 0
Kinetic energy of object 1 after collision = (1/2)(2m)(v₁²) = mv₁²
Kinetic energy of object 2 after collision = (1/2)(m)(v₁²) = (mv₂²/2)
So, we have,
mv² = mv₁² + (mv₂²/2)
v² = v₁² + (v₂²/2)
2v² = 2v₁² + v₂² (eqn 2)
Substitute (v₂ = 2v - 2v₁) from (eqn 1) into (eqn 2)
2v² = 2v₁² + (2v - 2v₁)²
2v² = 2v₁² + 4v² - 8vv₁ + 4v₁²
6v₁² - 8vv₁ + 2v² = 0
6v₁² - 6vv₁ - 2vv₁ + 2v² = 0
6v₁(v₁ - v) - 2v(v₁ - v) = 0
(6v₁ - 2v)(v₁ - v) = 0
6v₁ = 2v or v₁ = v
v₁ = (v/3) or v₁ = v
If v₁ = (v/3)
From (eqn 1)
v₂ = 2v - 2v₁
v₂ = 2v - 2(v/3)
v₂ = 2v - (2v/3)
v₂ = (4v/3)
If v₁ = v,
From eqn 1,
v₂ = 2v - 2v₁
v₂ = 2v - 2v = 0
(v₁, v₂) = [(v/3), (4v/3)]
Or
(v₁, v₂) = (v, 0)
The collision is elastic, what are the final velocities v1 and v2 of particles 1 and 2 (v₁, v₂) = [(v/3), (4v/3)] Or (v₁, v₂) = (v, 0)
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3. Two fans blow at 5 ms^-1 in a easterly direction and 8ms^-1 in a Northerly
direction. What is the total wind speed of both fans combined?
Addition of vectors is done by adding the components of the vectors
The total speed of the fan is approximately 9.43 m/s,
Direction of total wind 58° counterclockwise from the positive x-axis
The reason the value is correct is as follows:
The given parameters are:
The direction at which the fan blowing at 5 m/s is blowing = Easterly
The direction in which the fan blowing 8 m/s is blowing = Northerly
The total speed of the van, |v| ≈ 9.43 m/s
Required:
To find the total wind speed of the fans
Solution:
Taken the easterly direction as the ith component, and the northerly direction as the jth component, the vector representing the speed of the fan is presented as follows
v = 5·i + 8·j
The magnitude of the total wind speed of the fan, |v| = √(5² + 8²) = √(89) ≈ 9.43
The total wind speed of the fan , |v| ≈ 9.43 m/s
The direction of the total speed with respect to the x-axis, θ, is given as follows;
θ = arctan(8/5) ≈ 58°
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World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15m/s2.A) How much horizontal force F must a sprinter of mass 61 kg exert on the starting blocks to produce this acceleration? B) Which body exerts the force that propels the sprinter, the blocks or the sprinter?
Answer:
915N; the blocks;
Explanation:
a) F = ma = 61 * 15 = 915N
b) the sprinter pushes against the block. it is the reaction force of the block on the sprinter that propels the sprinter. therefore the blocks are exerting the force that propels the sprinter.
An unknown element has 5 protons, 5 electrons, and 6 neutrons what is the atomic mass of this element
Answer:
Atomic mass 5
Explanation:
No. protons=Atomic mass
the allowed shapes for orbits under the force of gravity are
a helical compression spring is made of oil-tempered spring steel wire 0.075-in in diameter and has an outside diameter of 0.960 in. the ends are plain and ground, and there are 16 total coils. a) the spring is wound to a free length, which is the largest possible with a solid-safe property. find this free length. b) what is the pitch of this spring? c) what force is needed to compress the spring to its solid length? d) estimate the spring rate. e) will the spring buckle in service?
a) The free length of the spring is 51.84 inches
b) The pitch of this spring 0.06 inches
c) The force is needed to compress the spring to its solid length 277 lb.
d) The spring rate is 230.8 lb/in.
e)The spring buckle in service 758 lb
a) The solid height of the spring can be calculated using the formula:
\(Solid height = Total number of coils x Wire diameter\)
Solid height = 16 x 0.075 = 1.2 inches
The free length of the spring is the sum of the solid height and the length of wire used to make the 16 coils. The length of wire used to make 16 coils is given by:
Length of wire used = π x (Outside diameter + Wire diameter) x Number of coils
Length of wire used = π x (0.960 + 0.075) x 16 = 50.64 inches
Therefore, the free length of the spring is:
Free length = Solid height + Length of wire used
Free length = 1.2 + 50.64 = 51.84 inches
b) The pitch of the spring is the distance between successive coils. It can be calculated using the formula:
Pitch = Outside diameter / Total number of coils
Pitch = 0.960 / 16 = 0.06 inches
c) The force required to compress the spring to its solid length can be calculated using the formula:
\(Force = Spring rate x Distance compressed\)
The distance compressed is the solid height of the spring, which is 1.2 inches. The spring rate can be estimated using the formula:
Spring rate = Gd^4 / 8ND^3
where G is the modulus of rigidity of the material (given), d is the wire diameter, N is the total number of coils, and D is the mean coil diameter (outside diameter minus wire diameter).
Using the given values, we get:
Spring rate = 11.5 x 10^6 psi x 0.075^4 / (8 x 16 x 0.885 x 0.885^3)
Spring rate = 230.8 lb/in
Therefore, the force required to compress the spring to its solid length is:
Force = 230.8 lb/in x 1.2 in = 277 lb
d) The spring rate is 230.8 lb/in.
e) The critical buckling load of the spring can be estimated using the formula:
Critical buckling load = π^2EI / (KL)^2
where E is the modulus of elasticity of the material, I is the second moment of area of the cross-section, K is the effective length factor, and L is the length of the spring. The effective length factor depends on the end conditions of the spring, which are plain and ground in this case.
Assuming a conservative effective length factor of 0.8, we get:
Critical buckling load = π^2 x 30 x 10^6 x 0.000184^4 / (0.8 x 51.84)^2
Critical buckling load = 758 lb
Since the estimated compressive load is well below the critical buckling load, the spring is not expected to buckle in service.
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A gas in a cylinder with a movable piston occupies 50.0 m³ at 50°C. The gas is cooled at constant pressure until the temperature is 10°C. What is the final volume?
10.0 m³
43.80 m³
3.8 m³
13.5 m³
The gas is cooled at constant pressure until the temperature is 10°C, then the final volume after calculating it comes out to be 43.80 m³. hence, the correct option is (B).
To solve this problem, we can use the ideal gas law, which states:
PV = nRT
Where:
P is the pressure
V is the volume
n is the number of moles of gas
R is the ideal gas constant
T is the temperature
In this case, we are given the initial volume (V1 = 50.0 m³), initial temperature (T1 = 50°C), and final temperature (T2 = 10°C). We need to find the final volume (V2).
First, we convert the temperatures to Kelvin since the ideal gas law requires temperature in Kelvin:
T1 = 50°C + 273.15 = 323.15 K
T2 = 10°C + 273.15 = 283.15 K
Since the pressure is constant in this problem, we can simplify the ideal gas law to:
V1/T1 = V2/T2
Now, let's plug in the known values:
50.0 m³ / 323.15 K = V2 / 283.15 K
To solve for V2, we can cross-multiply and then divide:
V2 = (50.0 m³ / 323.15 K) * 283.15 K
V2 = (50.0 m³ * 283.15 K) / 323.15 K
V2 = 14157.5 m³ / 323.15
V2 ≈ 43.82 m³
Therefore, the final volume of the gas is approximately 43.82 m³. The closest option to this value is 43.80 m³.
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The purpose of a starting relay is to _____. a. start an electric motor b. to prevent the motor from starting under heavy loads c. to protect the motor from starting overloads d. to remove the starting winding or component from the circuit
The purpose of a starting relay is to remove the starting winding or component from the circuit (option d).
A starting relay serves to disconnect the starting winding or component in an electric motor circuit once the motor has reached its operational speed.
This action is crucial because the starting winding is designed to provide a higher torque during the initial starting phase but is not meant for continuous operation.
If the starting winding remains in the circuit, it could lead to overheating and potential motor damage.
By removing the starting winding or component from the circuit, the starting relay ensures the safe and effective running of the electric motor. (choice d).
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HELP PLZZZZZZZZ
3. Which of these does not have potential energy?
a. A book resting on the floor
b. A roller coaster at its maximum height
c. A bird flying in the sky
d. A basketball shot in the air
Answer:
a. A book resting on the floor
Explanation:
Potential energy is the energy stored in a object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above/below the zero height.
I run around a circular track, with radius 25m, for 4 and times before stopping. It takes me 16
minutes. (A) What is my speed? (8) What is my velocity?
Answer:
13m/s. is the answer probably but do u have ms gallup too?
7. What is the kinetic energy when the moving cart is 2/3 the way down (height=5 m) when the total mechanical energy is _____________
Please I need someone to help me with this?!
(a) The kinetic energy of the cart when it moves is 2/3 the way down is 1/3mgh.
(b) The total mechanical energy of the cart at the given height of 5 m is 5mg.
Potential energy of the cart
The potential energy of the cart when it is 2/3 way down the given height of 5 m is calculated as follows;
ΔP.E = mghf - mgh₀
ΔP.E = mg(hf - h₀)
ΔP.E = mg(2h/3 - h)
ΔP.E = -¹/₃mgh
Kinetic energy of the cartΔK.E = -ΔP.E
ΔK.E = ¹/₃mgh
Total mechanical energy of the cartM.A = P.E + K.E
M.A = ²/₃mgh + ¹/₃mgh
M.A = mgh
M.A = mg(5)
M.A = 5mg
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CAN SOMEONE DO THIS FOR ME PLEASE CHECK THE COMMENT FOR THE LINK TO THE ASSESSMENT
Answer:
yes.................
which of the following options best describes a solid object
Answer:
Which of the following correctly describes a solid? Explanation: A solid is defined as having a definite shape and definite volume. A liquid is defined as having a definite volume, but not a definite shape.
an object of mass 20kg is lifted to a 25m building. how much potential energy is stored on a mass?(take g=10m/s²)
Answer:
5000J
Explanation:
hope this helps you
if you walk 8km at an average speed of 4km/h, how much time does it take
Answer:
2 hours
Explanation:
0.43 kg What is the weight
Answer: 4.214 N
Explanation: Given Mass = .43kg
Weight = mxa ...........(On earth a= 9.8 m/s2)
so .43X 9.8 = 4.214 N
as SI unit of weight if N
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