The given circuit is shown below:Given circuitThe current, I, is given as follows:
\($$I = \frac{V_{1} - V_{2}}{3 \Omega}$$Using KCL at node B:$$\frac{V_{1} - V_{B}}{2 \Omega} + \frac{V_{1} - V_{2}}{3 \Omega}\)
\(= 0$$$$\frac{V_{1} - V_{B}}{2} + \frac{V_{1} - V_{2}}{3}\)
\(= 0$$$$\frac{3V_{1} - 3V_{B} + 2V_{1} - 2V_{2}}{6}\)
\(= 0$$$$5V_{1} - 5V_{B} + 3V_{1} - 3V_{2}\)
\(= 0$$\)Rearranging the above equation:
\($$5V_{1} - 5V_{B} = 3V_{2} - 3V_{1}$$$$10V_{1} - 10V_{B}\)
\(= 6V_{2} - 6V_{1}$$$$16V_{1} - 10V_{B} - 6V_{2}\)
\(= 0$$Using KCL at node C:$$\frac{V_{B} - V_{C}}{4 \Omega} - \frac{V_{C}}{5 \Omega}\)
\(= 0$$$$\frac{V_{B} - V_{C}}{4} - \frac{V_{C}}{5}\)
\(= 0$$$$5V_{B} - 5V_{C} - 4V_{C}\)
\(= 0$$$$5V_{B}\)
\(= 9V_{C}$$Substituting the above equation in (2):$$16V_{1} - 10 \cdot \frac{9}{5}V_{B} - 6V_{2}\)
\(= 0$$$$16V_{1} - 18V_{B} - 6V_{2} = 0$$$$8V_{1} - 9V_{B} - 3V_{2}\)
\(= 0$$\)We know that the voltage across the 5 Ω resistor is given by:
\($$V_{C} = -4I$$$$V_{C}\)
\(= -4\frac{V_{1} - V_{2}}{3}$$Substituting in (3):$$8V_{1} - 9V_{B} - 3V_{2}\)
\(= 0$$$$8V_{1} - 9V_{B} - 3\cdot-4\frac{V_{1} - V_{C}}{3} = 0$$$$8V_{1} - 9V_{B} + 4V_{1} - 4V_{C} = 0$$$$12V_{1} - 9V_{B} - 4V_{C} = 0$$$$4V_{C}\)
\(= 3V_{B} - 4V_{1}$$$$4\left(-4\frac{V_{1} - V_{2}}{3}\right) = 3V_{B} - 4V_{1}$$$$-\frac{16}{3}V_{1} + \frac{16}{3}V_{2} = 3V_{B} - 4V_{1}$$$$-\frac{4}{3}V_{1} + \frac{16}{3}V_{2} = 3V_{B}$$$$-4V_{1} + 16V_{2}\)
\(= 9V_{B}$$\)We have obtained three equations from KCL at node B, KCL at node C and the voltage across the 5 Ω resistor. We can solve these equations simultaneously to obtain the unknown node voltages.'
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In a single component of an electromagnetic plane wave, what is the relative orientation of the vector directions of the electric field, the magnetic field, and the propagation direction?
a. The electric and magnetic fields are parallel to each other and are both parallel to the propagation direction.
b. The electric and magnetic fields are parallel to each other and are both perpendicular to the propagation direction.
c. The electric field direction, magnetic field direction, and propagation direction can be oriented independent of one another and in any direction.
d. The electric and magnetic fields are perpendicular to each other and are both parallel to the propagation direction.
e. The electric and magnetic fields are perpendicular to each other and are both perpendicular to the propagation direction.
The correct answer is option d. In a single component of an electromagnetic plane wave, the electric and magnetic fields are perpendicular to each other and are both parallel to the propagation direction.
This means that the magnetic field is oriented perpendicular to the electric field and the direction of wave propagation is perpendicular to both the electric and magnetic fields. This relationship is known as the right-hand rule, where if you curl the fingers of your right hand in the direction of the electric field, then the direction of your thumb represents the direction of the magnetic field, and the direction of your palm represents the direction of wave propagation. The electric and magnetic fields are perpendicular to one another and to the direction of propagation in a single component of an electromagnetic plane wave. Transverse wave propagation is this process. The maximum and minimum values of the electric and magnetic field vectors occur at the same time and place because they are in phase with one another. One of the essential properties of electromagnetic waves is this relative orientation.
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15. true or false convection drives movement of the tectonic plates which does not involve subduction.
The given statement "convection drives movement of the tectonic plates which does not involve subduction" is false because tectonic plate movement caused by mantle convection involves subduction.
Convection plays a crucial role in driving the movement of tectonic plates, which includes subduction. The Earth's mantle is divided into several convection cells that transfer heat and matter from the interior of the Earth towards the surface.
As the hotter material rises towards the surface, it displaces colder and denser material, which sinks back down into the interior. This convection cycle causes the movement of tectonic plates, as the plates are essentially riding on top of the flowing mantle.
Subduction occurs when one tectonic plate is forced beneath another due to differences in density and temperature. This process is driven by the movement of the plates themselves, which in turn is driven by the underlying convection currents in the mantle.
In summary, the movement of tectonic plates is driven by convection currents in the mantle, and subduction is one of the important processes involved in this movement.
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Is mechanical energy the result of both kinetic and potential energy?
Answer:
Yes
Explanation:
Because putting them together would make a type of energy making the answer yes
all millisecond pulsars are now, or once were, members of binary-star systems.
a. true
b. false
All millisecond pulsars are now, or once were, members of binary-star systems. This statement is option a. true
Millisecond pulsars are now, or once were, members of binary-star systems. They are highly-magnetized, fast-spinning neutron stars formed through the transfer of mass from a companion star in a binary system. This transfer of mass leads to an increase in the pulsar's rotation speed, resulting in very rapid rotation periods, typically in the range of milliseconds.
Highly magnetised neutron stars known as pulsars produce electromagnetic radiation beams along their magnetic axes as they rotate. They were initially believed to be artificial signals from extraterrestrial intelligence when they were first found in 1967 by Jocelyn Bell Burnell and Antony Hewish. Pulsars can rotate up to several hundred times per second and release radiation at a variety of wavelengths, including radio waves and gamma rays. A number of astrophysical phenomena, including the behaviour of matter under extreme circumstances, the workings of gravity, and the makeup of the Milky Way galaxy, can be studied using the radiation emitted by pulsars.
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What property of light waves makes it possible to use waves to transmit information between a space shuttle and NASA mission control centers on the ground?
Answer:
Explanation: Because it was able to exhibit an electromagnetic property hence, it is transverse meaning that
each wave is perpendicular to the direction of propagation.
And recall that an Electromagnetic waves can travel through a vacuum.
A 19.0 mH inductor is connected across an AC generator that produces a peak voltage of 9.40 V. You may want to review (Page 914) .
The answer is 95.5mA.
The current amplitude I is given by I=V
L /X
L =ω d
L=2πf d
L. Since the circuit contains only the inductor and a sinusoidal generator, V L=ε m
Therefore,I= X LV L= 2πf dLεm =2π(1.0∗10 3Hz)(50.0∗10 −3H)30.0V =0.0955A=95.5mA.
What is an AC generator?An alternating current generator (AC generator) is a mechanism that transforms mechanical energy into electrical energy. Mechanical energy is supplied to the AC Generator by steam turbines, gas turbines, and combustion engines.
Faraday's law of electromagnetic induction, which says that electromotive force - EMF or voltage - is created in a current-carrying wire that cuts a uniform magnetic field, is the basis for AC generators. This may be accomplished by rotating either a conducting coil in a static magnetic field or the magnetic field that contains the stationary conductor. It is preferable to keep the coil fixed since it is easier to pull induced alternating current from a stationary armature coil than from a moving armature coil.
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Potentially dangerous confined spaces, such as tanks, silos, and manholes, are purposely designed with:
Potentially dangerous confined spaces, are purposely designed with permit system.
Confined spacesConfined spaces are those areas that are enclosed sue to the fact that serious injuries may occur if precautions are not taken.
The features that makes a space confined are:
when there is limited opening for both entry and exit,There is limited time to always spend in the areaThe Space is Large Enough for You to Enter and Conduct Work.Examples of confined spaces include: tanks, silos, and manholes.
Since precautions needs to be taken, a permit system needs to be made available to ensure the safety of the individual entering the confined space.
This system includes the following measures:
rules to prevent unauthorized entry.Hazards that have been identified and evaluated before employee entry.The means, procedures, and practices necessary for safe permit space entry operations.Learn more about confined spaces here:
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i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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What have you learnt from subsidence modeling with MODFLOW SUB?
There are several things that we can learn from subsidence modeling with MODFLOW-SUB. Some of them are listed below: 1. Impact of groundwater pumping on subsidence, 2. Effect of aquifer properties on subsidence, 3. Planning of groundwater management strategies
MODFLOW-SUB is a subsidence model of the MODFLOW family. MODFLOW is a modeling software that simulates the groundwater flow by numerically solving the partial differential equations. MODFLOW-SUB incorporates the subsidence deformation in the groundwater flow simulations. It is used to simulate the interaction of groundwater flow with subsurface deformation in regions with significant subsidence.
1. Impact of groundwater pumping on subsidence: MODFLOW-SUB can be used to model the impact of groundwater pumping on subsidence. It can help in predicting the subsidence caused due to the change in the groundwater level.
2. Effect of aquifer properties on subsidence: The subsidence caused by groundwater pumping depends on various factors such as the compressibility of the soil, the hydraulic conductivity of the aquifer, the porosity of the soil, etc. MODFLOW-SUB can help in understanding the effect of these properties on subsidence.
3. Planning of groundwater management strategies: MODFLOW-SUB can be used to plan groundwater management strategies that can help in reducing subsidence. It can help in optimizing the pumping rates, the location of the wells, and the time of pumping to reduce subsidence.
Evaluation of subsidence risk: MODFLOW-SUB can be used to evaluate the subsidence risk in a region. It can help in identifying the areas that are more prone to subsidence due to groundwater pumping.
Validation of subsidence models: MODFLOW-SUB can be used to validate the subsidence models. It can help in comparing the results obtained from the subsidence models with the actual subsidence data. This can help in improving the accuracy of the subsidence models.
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By how many times will the kinetic energy of a body increases if its speed is trippled? Show by calculation.
Answer:
6 times
Explanation:
How are frequency, wavelength, and energy related? Choose all that apply.
Explanation:
The energy of a wave is given by :
\(E=\dfrac{hc}{\lambda}\)
Where
h is Planck's constant
c is the speed of light
\(\lambda\) is wavelength
Energy is inversely proportional to wavelength. Also, the relation between frequency and wavelength is inverse.
If the frequency is high, the wavelength will be shorter.
Hence, the correct options are :
Higher frequencies have shorter wavelengths.
Shorter wavelengths have lower energy.
Lower frequencies have lower energy.
A power cable carries a 100 A current. At what distance from the wire is the magnetic field equal to that of earth, 5.00 x 10^-5 T?
Answer:
0.4 m
Explanation:
The magnetic field strength is given by the formula ...
B = (μ₀I)/(2πr)
where I is the current in the wire in amperes, and r is the distance from the wire in meters. The value of μ₀ is 4π×10^-7. We want to find r for B = 5×10^-5. This gives ...
5×10^-5 = (4π×10^-7)(100)/(2πr)
r = 2×10^-5/(5×10^-5) = 0.4
At a distance of 0.4 meters from the wire, the magnetic field is equal to that of Earth.
is there any possibility to make 100% efficient system
Answer:
yes
Explanation:
its awesome
is ignoring drag when calculating a projectile’s motion an error
It is important to consider the effect of drag when calculating the motion of a projectile, especially in situations where it can have a significant impact on the object's trajectory.
Ignoring drag when calculating a projectile's motion can be an error depending on the situation. In some cases, such as short-range projectile motion at low speeds, the effects of drag can be negligible and ignoring it would not result in a significant error. However, in other cases such as long-range projectile motion at high speeds, drag can have a significant impact on the trajectory and ignoring it would result in a large error.
Additionally, if the goal of the calculation is to achieve a high degree of accuracy, such as in scientific experiments or engineering designs, ignoring drag would not be acceptable. In these cases, the effects of drag must be taken into account in order to make accurate predictions and ensure the safety and reliability of the design.
Overall, whether or not ignoring drag is an error depends on the specific situation and the level of accuracy required in the calculations.
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If scientists could bore though Earth's interior, what change would they most likely notice as they passed from the lithosphere to the asthenosphere?
Answer:
It gets hotter and hotter and it would start to be a liquid lava
Explanation:
gas particles can change to solid particles if the temperature
Gas particles can change to solid particles if the temperature decreases.
The state of matter of a substance is determined by its temperature and pressure. When the temperature of a gas decreases, its particles lose kinetic energy and slow down. This decrease in kinetic energy leads to a decrease in the average speed of gas particles.
As the temperature continues to decrease, the particles lose energy and move closer together. At a certain temperature known as the condensation point or the freezing point, the gas particles no longer have enough energy to overcome the intermolecular forces holding them together.
At this point, the gas undergoes a phase transition and changes into a solid. The process of gas turning into a solid is called condensation or freezing, depending on the specific substance.
During condensation, the gas particles arrange themselves in a more orderly and structured manner, forming a solid. The transition from gas to solid involves the release of energy, known as heat of fusion.
In summary, when the temperature of a gas decreases below its condensation or freezing point, the gas particles lose energy, slow down, and eventually come together to form a solid.
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Explain Sound level intensity with mathematical steps?
Answer:
sound intensity is explained by the following formula I= P/A where I= sound intensity(W/m²),P=power(W),A= area(m²) I hope this helps good luck!
Answer:
In a quiet forest, you can sometimes hear a single leaf fall to the ground. After settling into bed, you may hear your blood pulsing through your ears. But when a passing motorist has his stereo turned up, you cannot even hear what the person next to you in your car is saying. We are all very familiar with the loudness of sounds and aware that they are related to how energetically the source is vibrating. In cartoons depicting a screaming person (or an animal making a loud noise), the cartoonist often shows an open mouth with a vibrating uvula, the hanging tissue at the back of the mouth, to suggest a loud sound coming from the throat Figure 2. High noise exposure is hazardous to hearing, and it is common for musicians to have hearing losses that are sufficiently severe that they interfere with the musicians’ abilities to perform. The relevant physical quantity is sound intensity, a concept that is valid for all sounds whether or not they are in the audible range.
Intensity is defined to be the power per unit area carried by a wave. Power is the rate at which energy is transferred by the wave. In equation form, intensity I is I=PAI=PA, where P is the power through an area A. The SI unit for I is W/m2. The intensity of a sound wave is related to its amplitude squared by the following relationship:
\(\displaystyle{I}=\frac{\left(\Delta{p}\right)^2}{2\rho{v}_{\text{w}}}\\\).
Here Δp is the pressure variation or pressure amplitude (half the difference between the maximum and minimum pressure in the sound wave) in units of pascals (Pa) or N/m2. (We are using a lower case p for pressure to distinguish it from power, denoted by P above.) The energy (as kinetic energy mv22mv22) of an oscillating element of air due to a traveling sound wave is proportional to its amplitude squared. In this equation, ρ is the density of the material in which the sound wave travels, in units of kg/m3, and vw is the speed of sound in the medium, in units of m/s. The pressure variation is proportional to the amplitude of the oscillation, and so I varies as (Δp)2 (Figure 2). This relationship is consistent with the fact that the sound wave is produced by some vibration; the greater its pressure amplitude, the more the air is compressed in the sound it creates
Sound intensity levels are quoted in decibels (dB) much more often than sound intensities in watts per meter squared. Decibels are the unit of choice in the scientific literature as well as in the popular media. The reasons for this choice of units are related to how we perceive sounds. How our ears perceive sound can be more accurately described by the logarithm of the intensity rather than directly to the intensity. The sound intensity level β in decibels of a sound having an intensity I in watts per meter squared is defined to be β(dB)=10log10(II0)β(dB)=10log10(II0), where I0 = 10−12 W/m2 is a reference intensity. In particular, I0 is the lowest or threshold intensity of sound a person with normal hearing can perceive at a frequency of 1000 Hz. Sound intensity level is not the same as intensity. Because β is defined in terms of a ratio, it is a unitless quantity telling you the level of the sound relative to a fixed standard (10−12 W/m2, in this case). The units of decibels (dB) are used to indicate this ratio is multiplied by 10 in its definition. The bel, upon which the decibel is based, is named for Alexander Graham Bell, the inventor of the telephone.
Table 1. Sound Intensity Levels and IntensitiesSound .
3. what are the heat transfer mechanisms involved during heat transfer in a liquid-to-liquid heat exchanger from the hot to the cold fluid?
The heat transfer mechanisms in a liquid-to-liquid heat exchanger from the hot to the cold fluid include conduction, convection, and radiation. Conduction and convection are the primary mechanisms, while radiation plays a minor role.
The heat transfer mechanisms involved during heat transfer in a liquid-to-liquid heat exchanger from the hot to the cold fluid are conduction, convection, and in some cases, radiation.
1. Conduction: This is the process of heat transfer through direct contact between the hot and cold fluids. The heat moves from the hot fluid to the cold fluid through the solid walls of the heat exchanger.
2. Convection: This mechanism occurs due to the movement of fluids in the heat exchanger. The hot fluid transfers heat to the solid walls of the heat exchanger, and the cold fluid receives the heat from the walls as it flows. The movement of fluids enhances the heat transfer rate.
3. Radiation: Although less significant in liquid-to-liquid heat exchangers, radiation is the transfer of heat through electromagnetic waves. The heat is emitted from the hot fluid and absorbed by the cold fluid without the need for direct contact or fluid movement.
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Cane Company manufactures two products called Alpha and Beta that sell for $240 and $162, respectively. Each product uses only one type of raw material that costs $5 per pound. The company has the capacity to annually produce 131,000 units of each product. Its average cost per unit for each product at this level of activity are given below:
Alpha Beta
Direct materials $ 35 $ 15
Direct labor 48 23
Variable manufacturing overhead 27 25
Traceable fixed manufacturing overhead 35 38
Variable selling expenses 32 28
Common fixed expenses 35 30
Total cost per unit $ 212 $ 159
The company considers its traceable fixed manufacturing overhead to be avoidable, whereas its common fixed expenses are unavoidable and have been allocated to products based on sales dollars.
8. Assume that Cane normally produces and sells 80,000 Betas and 100,000 Alphas per year. If Cane discontinues the Beta product line, its sales representatives could increase sales of Alpha by 13,000 units. What is the financial advantage (disadvantage) of discontinuing the Beta product line?
9. Assume that Cane expects to produce and sell 100,000 Alphas during the current year. A supplier has offered to manufacture and deliver 100,000 Alphas to Cane for a price of $160 per unit. What is the financial advantage (disadvantage) of buying 100,000 units from the supplier instead of making those units?
10. Assume that Cane expects to produce and sell 75,000 Alphas during the current year. A supplier has offered to manufacture and deliver 75,000 Alphas to Cane for a price of $160 per unit. What is the financial advantage (disadvantage) of buying 75,000 units from the supplier instead of making those units?
The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000. The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.
To calculate the financial advantage or disadvantage of discontinuing the Beta product line, we need to compare the costs and revenues associated with the current situation and the proposed scenario.
Currently, the company produces and sells 80,000 Betas and 100,000 Alphas. If the Beta product line is discontinued, the sales representatives can increase Alpha sales by 13,000 units.
In the current situation:
Revenue from Beta sales = 80,000 units × $162 = $12,960,000
Revenue from Alpha sales = 100,000 units × $240 = $24,000,000
Total revenue = $12,960,000 + $24,000,000 = $36,960,000
In the proposed scenario:
Increased Alpha sales = 113,000 units × $240 = $27,120,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Revenue in proposed scenario - Revenue in current situation
Financial Advantage = $27,120,000 - $36,960,000 = -$9,840,000
The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000.
To determine the financial advantage or disadvantage of buying 100,000 units from the supplier instead of making them, we need to compare the costs of production with the purchase cost from the supplier.
Cost of producing 100,000 Alphas:
Direct materials cost = 100,000 units × $35 = $3,500,000
Direct labor cost = 100,000 units × $48 = $4,800,000
Variable manufacturing overhead = 100,000 units × $27 = $2,700,000
Traceable fixed manufacturing overhead = 100,000 units × $35 = $3,500,000
Variable selling expenses = 100,000 units × $32 = $3,200,000
Common fixed expenses = 100,000 units × $30 = $3,000,000
Total cost of producing 100,000 units = $3,500,000 + $4,800,000 + $2,700,000 + $3,500,000 + $3,200,000 + $3,000,000 = $20,700,000
Cost of buying 100,000 units from the supplier = 100,000 units × $160 = $16,000,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Cost of producing - Cost of buying
Financial Advantage = $20,700,000 - $16,000,000 = $4,700,000
The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.
Similarly, to determine the financial advantage or disadvantage of buying 75,000 units from the supplier instead of making them, we follow the same calculations as in question 9, but with the quantities adjusted accordingly.
Cost of producing 75,000 Alphas:
Direct materials cost = 75,000 units × $35 = $2,625,000
Direct labor cost = 75,000 units × $48 = $3,600,000
Variable manufacturing overhead = 75,000 units × $27 = $2,025,000
Traceable fixed manufacturing overhead = 75,000 units × $35 = $2,625,000
Variable selling expenses = 75,000 units × $32 = $2,400,000
Common fixed expenses = 75,000 units × $30 = $2,250,000
Total cost of producing 75,000 units = $2,625,000 + $3,600,000 + $2,025,000 + $2,625,000 + $2,400,000 + $2,250,000 = $15,525,000
Cost of buying 75,000 units from the supplier = 75,000 units × $160 = $12,000,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Cost of producing - Cost of buying
Financial Advantage = $15,525,000 - $12,000,000 = $3,525,000
The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.
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A 103-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is μk = 0.702. (a) What is the magnitude of the frictional force? (b) If the player comes to rest after 1.02 s, what is his initial speed?
A 103-kg baseball player slides into second base. The magnitude of frictional force will be 708.598 N and his initial speed will be 7.017 m/s
Elaborating:m = 103 kg
μk = 0.702
f = μk N
= μk mg
= 0.702 × 103 ×9.8
= 708.5988 N
b . μ mg = ma
a = μg
= 6.8796 m / s ²
vf = o m/s
vi= ?
t = 1.02 s
vf = vi + at
0 = vi - 6.8796 × 1.02
vi = 7.01719 m / s
How exactly does frictional force function?The tiny bumps push against each other when two surfaces slide over one another. On a surface, friction exerts a force in the opposite direction of its motion. Rubbing can be decreased by the utilization of ointments
SignificanceRubbing can pump the brakes and prevent fixed things from moving. In a world without friction, more things would slide around, it would be hard to keep clothes and shoes on, and it would be very hard for people or cars to move or change direction.
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in the rock cycle, if any type of rock is broken down into little pieces, it changes into
Answer:
soil
Explanation:
it changes to different type of soil......................................
you put a test charge of 2e near two other particles. particle a has a charge of -2e and is 0.0200 m north of the test charge. particle b has a charge of 3e and is 0.0200 m east of the test charge. the magnitude of the net electrostatic force on the test charge in newtons is:
Since F₁ is directed towards the south and F₂ is directed towards the east, we can use the Pythagorean theorem to find the magnitude of the net force:
F = √(F₁² + F₂²)
The magnitude of the net electrostatic force on the test charge in newtons is given by the formula: F= k(q1q2)/r²
where k is Coulomb's constant, q1 is the charge on particle a, q2 is the charge on particle b, and r is the distance between the test charge and the other two charges.
Using the given values, we can find the magnitude of the net electrostatic force on the test charge as follows: F₁
= k(2e)(-2e)/(0.0200m)²F₂
= k(2e)(3e)/(0.0200m)²
The net force is obtained by taking the vector sum of F₁ and F₂.
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Two identical thin rectangular sheets have dimensions 0.30 m × 0.50 m. They are both set to rotation by the same torque, but the first one rotates about an axis which lies on its 0.30 m side, while the second one rotates about an axis which lies on its 0.50 m side (Fig. 1). The first sheet reaches its final angular velocity in 8.0 s, starting from rest. How long will it take the second sheet to reach the same angular velocity, also starting from rest.
Therefore, it will take the second sheet approximately 4.63 s to reach the same angular velocity.
What is the starting velocity and final velocity formula?With a few calculations and some fundamental conceptual understanding, one can easily determine the ultimate velocity. By dividing the amount of time it took the object to move a certain distance by the overall distance, one can calculate the object's initial velocity.
For a thin rectangular sheet rotating about a plane perpendicular to one of its edges, the moment of inertia is given by:
\(I = (1/12)M(L^2 + W^2)\)
Since both sheets have the same torque causing them to rotate, the torque is the same for both sheets. The first sheet's moment of inertia is:
\(I1 = (1/12)M(0.3^2 + 0.5^2) = 0.0125M\)
The angular acceleration for the first sheet is:
α1 = τ/I1
ω1 = α1t1
Solving for α1, we get:
α1 = ω1/t1
Substituting this into the equation for angular acceleration and solving for ω1, we get:
ω1 = (τ/I1)t1
Similarly, for the second sheet, the moment of inertia is:
\(I2 = (1/12)M(0.5^2 + 0.3^2) = 0.0125M\)
The angular acceleration for the second sheet is:
α2 = τ/I2
ω2 = α2t2
Substituting in the equation for angular acceleration and solving for t2, we get:
t2 = ω2/α2
To find ω2, we can use the fact that the torque is the same for both sheets:
τ = I1α1 = I2α2
Substituting in the expressions for I1, I2, α1, and α2, we get:
\(τ = (1/12)M(0.3^2 + 0.5^2)(ω1/t1) = (1/12)M(0.5^2 + 0.3^2)(ω2/t2)\)
Canceling out the mass and torque, and solving for ω2, we get:
\(ω2 = (0.3^2 + 0.5^2)/(0.5^2 + 0.3^2)(ω1)t1\)
Substituting this into the equation for t2, we get:
\(t2 = (0.5^2 + 0.3^2)/(0.3^2 + 0.5^2)(t1)\)
Plugging in the values for t1 (8.0 s), we get:
\(t2 = (0.5^2 + 0.3^2)/(0.3^2 + 0.5^2)(8.0 s)\)
≈ 4.63 s
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someone pls review my work
In astronomy, Johannes Kepler published his three laws about planetary motion. It is one of the most important things in astronomy. So Kepler gives three laws about planetary motion.
What is motion?Motion is a physical term in physics. If a particle of mass m and affected by some force F then it change its position in many different way. That is the motion of the object. It is a vector quantity.
What is Kepler's three laws?In astronomy, Johannes Kepler published his three laws about planetary motion between 1609 and 1619. This shows about motion describe the orbits of planets around the Sun. So the three motions are shown following,
First law: Every planet in solar system that moves in a elliptical orbits where the sun always in the center of the motion.
Second law: Every planet covers the same amount of distance in a constant time no matter where the orbit of the planet placed. That means the velocity of every planet is not same. It varies along with the orbit. But every time the change of area is constant.
Third law: The orbital period of the planet is proportional with the cube of the semi major axis of the planet. It can be shown mathematically,
p²∝a³
Where we know,
p= The orbital period of the planet.
a= the semi major axis of the planet.
From the discussion we can easily shown that there are three laws of Kepler about planetary motion.
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a vibrating diaphragm sets up strong vibrations at the mouth of a horizontal tube containing air and a small amount of fine powder. the powder becomes arranged in piles i cm apart, and the speed of sound in air is 330 meters
the wavelength of this sound in air is:
(the answer is 2cm howd we get hereeee)
A sound is moving through the atmosphere at a velocity of 343 ms-1. The sound wave has a wavelength of 0.1 cm.
Sound in the air is what kind of wave?Longitudinal waves are what make up sound. Compressions and rarefactions are also present in longitudinal waves when they pass through any given medium. When particles travel in close proximity to one another, compression occurs, creating areas of intense pressure.
What is the air wavelength formula?As with all waves, the relationship between the speed of sound (vw), its frequency (f), and its wavelength () is provided by vw=f. vw=(331m/s)T273K describes how the sound's velocity in the air relates to air temperature T. For any and all frequencies and wavelengths, vw is constant.
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A solid cylinder with a mass of 2. 53 kg and a
radius of 0. 026 m starts from rest at a height
of 2. 70 m and rolls down a 46. 8
◦
slope. What is the translational speed of the cylinder when it leaves the incline? The acceleration of gravity is 9. 81 m/s
2. Answer in units of m/s
The translational speed of the cylinder when it leaves the incline is 3.28 m/s.
To solve this problem, we need to use the conservation of energy principle, which states that the initial potential energy of the cylinder is equal to its final kinetic energy plus any remaining potential energy.
The initial potential energy of the cylinder is given by:
U_i = mgh
where m is the mass of the cylinder, g is the acceleration due to gravity, and h is the height of the incline. Substituting the given values, we get:
U_i = (2.53 kg)(9.81 m/s^2)(2.70 m) = 68.9 J
The final kinetic energy of the cylinder is given by:
K_f = (1/2)mv^2
where v is the translational speed of the cylinder when it leaves the incline. We also know that the cylinder will have rotational kinetic energy due to its rolling motion, given by:
K_rot = (1/2)Iω^2
where I is the moment of inertia of the cylinder and ω is its angular velocity. For a solid cylinder rolling without slipping, the moment of inertia is given by:
I = (1/2)mr^2
and the angular velocity is related to the translational speed by:
ω = v/r
Substituting these equations and simplifying, we get:
K_f + K_rot = (1/2)mv^2 + (1/4)mv^2
K_f + K_rot = (3/4)mv^2
Now, let's calculate the final potential energy of the cylinder. At the bottom of the incline, the cylinder will have a height of zero, so its potential energy will be:
U_f = mgh_cos(θ)
where θ is the angle of the incline. Substituting the given values, we get:
U_f = (2.53 kg)(9.81 m/s^2)(2.70 m)cos(46.8°) = 29.3 J
Using the conservation of energy principle, we can equate the initial potential energy to the final kinetic energy plus the final potential energy:
U_i = K_f + K_rot + U_f
Substituting the equations we derived earlier and simplifying, we get:
68.9 J = (3/4)mv^2 + 29.3 J
Solving for v, we get:
v = sqrt[(4/3)(68.9 J - 29.3 J)/m] = 3.28 m/s
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3) The atomic mass of beryllium is about 9 times the atomic mass of a proton. If a beryllium ion (singly ionized) and a proton are given the same kinetic energy (by accelerating them through the same potential difference) then sent into a uniform magnetic field, what will be the size of the circle made by the beryllium ion compared to the size of the circle made by the proton? 4 A) 3 times the size B) 9 times the size C) 1/3 the size D) 1/9 the size
The size of the circle made by the beryllium ion will be 1/3 the size of the circle made by the proton.
The size of the circle made by a charged particle moving in a uniform magnetic field is determined by its mass, charge, and kinetic energy. In this scenario, the beryllium ion (singly ionized) and the proton have the same kinetic energy, but the beryllium ion has a greater atomic mass.
The centripetal force acting on a charged particle moving in a magnetic field is given by the equation:
F = (mv^2) / r
Where m is the mass of the particle, v is its velocity, and r is the radius of the circle.
Since both the beryllium ion and the proton have the same kinetic energy, their velocities will be equal. However, the mass of the beryllium ion is 9 times that of the proton.
As the centripetal force is determined by the mass of the particle, the beryllium ion will experience a smaller centripetal force compared to the proton. Therefore, the radius of the circle made by the beryllium ion will be smaller, making it 1/3 the size of the circle made by the proton.
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A guitar string vibrates with an unknown frequency. If the the guitar string is played along with a 440 Hz tuning fork, a beat frequency of 5 Hz is heard. What are the possible frequencies the guitar string could be vibrating at?
This question involves the concept of the beat frequency.
The possible frequencies of the guitar string could be "445 Hz" (or) "435 Hz".
Beat FrequencyWhen two sounds with a very minor difference in their frequency are played, they produce a frequency equal to the absolute value of the difference between their frequencies. This frequency is known as beat frequency.
\(f_b=|f_1-f_2|\)
where,
\(f_b\\\) = beat frequency = 5 Hzf₁ = frequency of first guitar string = 440 Hzf₂ = possible frequencies of other string = ?Therefore,
5 Hz = |440 Hz - f₂|
f₂ = 440 Hz ± 5 Hz
f₂ = 445 Hz (OR) 435 Hz
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Compare the values for index of refraction of glass for each trial (values in last column) Is there good agreement between them? Would you conclude that index of refraction is constant for & given medium? Compare your calculated nz with the given index of refraction, nglass. Do they agree? Explain why it does or doesn't"
The calculated average n2 does not agree with the given index of refraction, indicating a potential discrepancy that may be attributed to experimental limitations or errors.
To analyze the agreement between the values for the index of refraction (n2) of glass in each trial, we can observe the trend and variation in the data. From the table, it appears that the values for n2 increase as the angles θ1 and θ2 increase. However, it is difficult to determine the level of agreement between the values without further statistical analysis or calculation of uncertainties.
The conclusion regarding whether the index of refraction is constant for a given medium depends on the level of agreement observed. If the values for n2 in each trial are close to each other and do not deviate significantly, it suggests good agreement and supports the hypothesis of a constant index of refraction.
On the other hand, if there is significant variation and inconsistency among the values, it indicates that the index of refraction may not be constant for the given medium.
To determine the average value of n2 from the provided results, we can calculate the mean of the n2 values:
Average n2 = (1.46 + 1.61 + 1.73 + 1.96 + 2.08 + 2.13) / 6 ≈ 1.85
Comparing the calculated average n2 (1.85) with the given index of refraction of the glass (1.50), we can see that they do not agree. The calculated average n2 is higher than the given value of 1.50. This suggests that there might be some systematic error or uncertainties in the measurements or calculations.
The difference between the calculated and given values could be due to factors such as experimental errors, instrumental limitations, or other sources of uncertainty in the measurement process.
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Complete question is:
Calculate sinθ1, sinθ2 and n2 for each of your results and add them to table 1. Keep your results to 2 or 3 significant figures.
Compare the values for index of refraction of glass for each trial (values in last column). Is there good agreement between them? Would you conclude that index of refraction is a constant for a given medium?
Determine the average value of n2 from your results.
Compare your calculated n2 with the given index of refraction of the glass (1.50). Do they agree? Explain why it does or doesn’t.
Is this statement true or false? The plates of the earth’s crust may also contribute to maintaining upper mantle convection. True false.
True. The statement is true. The movement of tectonic plates on the Earth's surface can indeed contribute to maintaining upper mantle convection. The convection currents in the mantle are responsible for the movement of the plates, as the heat from the deeper parts of the mantle rises, moves towards the surface, and then sinks back down after cooling.
This convective motion of the mantle material drives the movement of the tectonic plates, which can cause various geological phenomena such as earthquakes, volcanic activity, and the formation of mountain ranges. Thus, the plates of the Earth's crust play a significant role in maintaining and influencing the convection processes in the upper mantle.
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