an Airbus A380 has 1 first class section 1 business class section and 4 economy class sections
the first class section has 14 seats. 6/7 are being used.
the business class section has 64 seats. 7/16 are being used.
each economy class section has 117 seats. 7/13 in each section are being used.
are more than half the seats on the plane being used you must show your working out.
Answers
Answer:
Yes, more than half are being used. (292 out of 546 used)
Step-by-step explanation:
The first part of this problem is to determine the total amount of seats on the plane so we can determine what half of the seats would be.
1st class has 14 seats.
Business-class has 64 seats.
And the 4 economy classes have 117 each, meaning 117 * 4 = 468
So the total amount of seats are 14 + 64 + 468 = 546
So half that amount would be 273.
Now we can determine the number of seats being used.
1st class has (6/7) * 14 = 12 seats used
Buisness-class has (7/16) * 64 = 28 seats being used
Economy has 4 * (7/13) * 117 = 4 * 63 = 252 seats being used
So the total amount of used seats would be 12 + 28 + 252 = 292.
Note that 292 is greater than 273, so there is indeed more than half the seats on the plane being used.
Cheers.
Related Questions
An ancient artifact is four times as old as an antique book. In 200 years, the artifact will be 3 times as old as the book. How old is the artifact now?
Answers
The current age of the artifact is 1600 years
How old is the artifact now?Let's call the current age of the artifact "a" and the current age of the book "b".
The artifact is four times as old as the book, so we have:
a = 4b
In 200 years, the artifact will be a + 200 and the book will be b + 200.
From the problem, we know that in 200 years:
a + 200 = 3 (b + 200)
Expanding the right side:
a + 200 = 3b + 600
Substituting a = 4b:
4b + 200 = 3b + 600
Solving for b:
b = 400
So the current age of the book is 400 years old.
Recall that
a = 4b
So, we have
a = 400 * 4 = 1600
And the current age of the artifact is 4 times that, or 1600 years old.
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Please help me I have been stuck for a while now
Answers
Answer:
Option 3
Step-by-step explanation:
Pythagorean Theorem:
\(A^2 + B^2 = C^2 \\\\300^2 + 400^2 = 500^2\)
What percentage of this shape is shaded?
Answer:
Answers
Answer:
Step-by-step explanation:
There are 9 squares filled halfway, and 5 squares filled completely.
9 x 0.5 = 4.5
4.5 + 5 = 9.5
There are 25 squares in the shape.
9.5 / 25 = 0.38
38% of the square is shaded.
What is the length of a killer whale
Answers
Male: 20-26 feet
Female: 16- 23 feet
In the American economy, a person _____.
a.)is prohibited from competing against other people
b.)can function as both a worker and a consumer
c.)must use the bartering system to get goods and services
d.)is not allowed to make a large profit from selling property
Answers
B
It is quite obvious. America is capatalist, we are relatively free here. No laws regulate competing against other people nor regulating the ability to make a large profit from real estate.
if you were confused with C, the word bartering basically means trading goods. In order to acquire good most people use money, we do not have to trade things like bread for steak n stuff.
Hope it helps
HELP ASAP WORTH MANY A POINTS
the rest of the third question
The amount of space available to tigers in a wildlife refuge changes as the population changes. The graph shows the available territory in a tiger wildlife refuge as a function time since the refuge opened.
Which statements are true about the function?
Select each correct answer.
Answers
Answer:
1) exponential decay, time progresses
2) 64
4) 24
5) number of weeds increase without bound
Write the equation 2(x + 3) = 2x + 6 as a system of equations. y = x + y = x +
Answers
Answer:
y = 2x + 6
y = 2x + 6
Step-by-step explanation:
If a system of equations are,
y = ax + b
y = cx + d
Then y = ax + b = cx + d
If this equation is given as 2(x + 3) = 2x + 6
The system of equations will be,
y = 2(x + 3)
y = 2x + 6 ------(1)
And, y = 2x + 6 --------(2)
Therefore, both the equations of the system of equations will be similar.
The system of equation:
y = 2x + 6
y = 2x + 6
Given,
2(x + 3) = 2x + 6
If a system of equations are,
y = ax + b
y = cx + d
Then y = ax + b = cx + d
If this equation is given as 2(x + 3) = 2x + 6
The system of equations will be,
y = 2(x + 3)
y = 2x + 6 ------(1)
And, y = 2x + 6 --------(2)
Therefore, both the equations of the system of equations will be similar.
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What is a common workflow error that can cause duplicate expenses in QuickBooks Online?
Create a Bill to record vendor expense, and create Check to vendor for the same expense
Create a Purchase order to record vendor expense, and create Check to pay the vendor for the same expense
Create a Bill to record vendor expense, and use Pay Bills to pay the vendor for same expense
Create a Bank rule to automatically categorize a common vendor expense
Answers
The common workflow error that can cause duplicate expenses in QuickBooks Online is to create a Bill to record vendor expense and use Pay Bills to pay the vendor for the same expense.
What is QuickBooks Online?QuickBooks Online is an accounting software that is cloud-based and enables small business owners to keep track of their expenses, create invoices, and accept payments
.What is a Bill in QuickBooks Online?A bill is a request for payment from a vendor for a product or service that they've provided. Bills can be created and then scheduled for payment in QuickBooks Online by small business owners.
How to avoid duplicate expenses in QuickBooks Online?In QuickBooks Online, duplicate expenses can be avoided by avoiding double-entry. Creating a bill and then paying the vendor via the Pay Bills feature is one of the most common workflow mistakes that can lead to duplicate expenses in QuickBooks Online. When a bill is created in QuickBooks Online, it becomes a record of a debt that the small business owes to the vendor. After that, the Pay Bills feature is used to mark the bill as paid and track the payment made to the vendor by the small business owner.
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Consider the LP below. The BFS ("corners") are (0,0) (0,4) (1,4) (3,2) (3,0). The optimal solution is at x_{1} = 3 and x_{2} = 2
max z = 2x_{1} + x_{2}
s.t.
matrix x 1 +x 2 &<= 0 \\ x 1 &<=3\\ x 2 &<4 matrix
x_{1}, x_{2} >= 0
(a). What is the range of c_{1} the objective coefficient of x_{1} (currently 2) for which this BFS remains optimal:
(b). What is the range of b_{2} the right hand side of the second constraint (currently 3) for which this BFS remains optimal:
(c). What is the dual price of the second constraint?
Answers
(a) The range of c₁ (the objective coefficient of x₁) for which this BFS remains optimal is c₁ ≤ 2.
(b) The range of b₂ (the right-hand side of the second constraint) for which this BFS remains optimal is 3 ≤ b₂ < 4.
(c) The dual price of the second constraint is 0.
(a) The optimality condition for a linear programming problem requires that the objective coefficient of a non-basic variable (here, x₁) should not increase beyond the dual price of the corresponding constraint. In this case, the dual price of the second constraint is 0, indicating that increasing the coefficient of x₁ will not affect the optimality of the basic feasible solution. Therefore, the range of c₁ for which the BFS remains optimal is c₁ ≤ 2.
(b) The range of b₂ for which the BFS remains optimal is determined by the allowable range of the corresponding dual variable. In this case, the dual price of the second constraint is 0, implying that the dual variable associated with that constraint can vary within any range. As long as 3 ≤ b₂ < 4, the dual variable remains within its allowable range, and thus, the BFS remains optimal.
(c) The dual price of a constraint represents the rate of change in the objective function value per unit change in the right-hand side of the constraint, while keeping all other variables fixed. In this case, the dual price of the second constraint is 0, indicating that the objective function value does not change with variations in the right-hand side of that constraint.
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Derivations (20 marks): For each of the questions in this section provide a derivation. Other methods will receive no credit i. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx (5 marks)
ii. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px (5 marks) iii. ¬ Vx(Fx → Gx) v 3xFx (10 marks; Hint: To derive this theorem use RA.)
Answers
¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]
i. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx (5 marks)
Proof:
1. ∃x(Fx & Gx) [Premise]
2. Fx & Gx [∃-Elimination, 1]
3. ∃xFx [∃-Introduction, 2]
4. ∃xGx [∃-Introduction, 2]
5. ∃xFx & ∃xGx [Conjunction Introduction, 3 and 4]
6. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx [1-5, Modus Ponens]
ii. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px (5 marks)
Proof:
1. ¬ 3x(Px v Qx) [Premise]
2. ¬ Px v ¬ Qx [DeMorgan’s Law, 1]
3. Vx ¬ Px [∀-Introduction, 2]
4. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px [1-3, Modus Ponens]
iii. ¬ Vx(Fx → Gx) v 3xFx (10 marks; Hint: To derive this theorem use RA.)
Proof:
1. ¬ Vx(Fx → Gx) v 3xFx [Premise]
2. (¬ Vx(Fx → Gx) v 3xFx) → (¬ Vx(Fx → Gx) v Fx) [Implication Introduction]
3. ¬ Vx(Fx → Gx) v Fx [Resolution, 1, 2]
4. (¬ Vx(Fx → Gx) v Fx) → (Fx → Gx) [Implication Introduction]
5. Fx → Gx [Resolution, 3, 4]
6. ¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]
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The perimeter of this shape is 92cm.
Find the value of x.
(x + 7)
Answers
Step-by-step explanation:
x + 7 = 92
x = 92 - 7
x = 85
The value of x is 85
Approximate the square root to the nearest integer.
37
Answers
Answer:
We know that 6² = 36 , which is very close to 37 . Thus square root of 37 will be very close to 6
Calculate the volume of oil exiting the pipe every hour: Calculate the volume of oil exiting the pipe every day: Convert cu in/day to cubic feet per day: cu. in/hour cu in/day cu ft/day
Answers
The volume of oil exiting the pipe is approximately 100 cu in/hr, 2,400 cu in/day, and 1.39 cu ft/day when converting cu in/day to cubic feet per day.
To calculate the volume of oil exiting the pipe every hour, you would need to know the flow rate of the oil in cubic inches per hour. Let's assume the flow rate is 100 cubic inches per hour.To find the volume of oil exiting the pipe every day, you would multiply the flow rate by the number of hours in a day. There are 24 hours in a day, so the volume of oil exiting the pipe every day would be 100 cubic inches per hour multiplied by 24 hours, which equals 2,400 cubic inches per day.
To convert the volume from cubic inches per day to cubic feet per day, you would need to divide the volume in cubic inches by the number of cubic inches in a cubic foot. There are 1,728 cubic inches in a cubic foot. So, dividing 2,400 cubic inches per day by 1,728 cubic inches per cubic foot, we get approximately 1.39 cubic feet per day.
Therefore, the volume of oil exiting the pipe is approximately 100 cubic inches per hour, 2,400 cubic inches per day, and 1.39 cubic feet per day.
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Question 1 (1 point)
Which pair of equations represents lines that are perpendicular
y = 2x+8
y = 2x + 2
Y = 1/2x +4
y = -2x -3
Y = 1/2x + 3
y = 2x -4
Answers
Answer:
it would be 69 bhejejejirirooddsskkskskakakakzkzjajbhshdhdjdjeiejeie
The point (-3, 5) has been reflected so that the image is at (5, -3). What is the line of reflection?
A. x-axis
B. y-axis
C. y=x
D. y=-x
Please select the best answer from the choices provided
A
Mark this and return
Save and Exit
Next
Submit
Answers
Answer:
C. y=x
Step-by-step explanation:
If you use a graphing calculator and plot the points (-3,5) & (5,-3) and then graph y=x you can see it is the line of reflection.
Also when reflecting over the line y=x, we switch our x and y.
A new bicycle sells for $300. it is on sale for 1/4 off the regular price. list all the expressions that represent the sale price of the bicycle in dollars
Answers
The required expressions are $300 - (1/4) * $300, $300 * (1 - 1/4), $300 * (3/4), $300 * (100% - 25%)
The sale price of the bicycle can be determined by applying the discount of 1/4 (or 25%) to the regular price of $300. Here are some expressions that represent the sale price:
1. $300 - (1/4) * $300: This expression calculates the discount amount by multiplying the regular price by 1/4 (or 25%), and then subtracts it from the regular price to obtain the sale price.
2. $300 * (1 - 1/4): This expression calculates the discount amount by subtracting 1/4 (or 25%) from 1, representing the remaining amount to be paid, and then multiplies it by the regular price to determine the sale price.
3. $300 * (3/4): This expression represents the remaining amount to be paid after deducting the discount. It multiplies the regular price by 3/4 (or 75%) to obtain the sale price.
4. $300 * (100% - 25%): This expression represents the remaining percentage to be paid after deducting the discount. It multiplies the regular price by the remaining percentage (75%) to calculate the sale price.
In all cases, the resulting value represents the sale price of the bicycle in dollars.
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If A and B are any two events defined on a sample space S of an experiment such that p(A) = p(B) = 0.8 and A U B = S, then p(A U B) = 1.
True or false
Answers
The statement is true. In probability theory, an event refers to a set of possible outcomes of an experiment. A sample space S is the set of all possible outcomes of an experiment. p(A) and p(B) are the probabilities of events A and B, respectively.
According to the given information, both events A and B have a probability of 0.8. The symbol U represents the union of two sets, which in this context means the occurrence of either event A or event B or both. Since A U B = S, it means that the union of events A and B covers all possible outcomes in the sample space.
The probability of the union of events A and B is given by the formula p(A U B) = p(A) + p(B) - p(A ∩ B), where A ∩ B is the intersection of events A and B. If A and B are mutually exclusive, meaning they have no common outcomes, then p(A ∩ B) = 0. However, in this case, we do not have any information about whether A and B are mutually exclusive or not.
Therefore, using the formula above, we have p(A U B) = p(A) + p(B) - p(A ∩ B) = 0.8 + 0.8 - p(A ∩ B) = 1.6 - p(A ∩ B). Since p(A U B) is the probability of all possible outcomes in the sample space, it must be equal to 1. Thus, p(A U B) = 1 is true.
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NEED SOME HELP PLS!!!Word Problem Modeling
1 point
Mary is comparing the costs from two companies of having a banquet
catered. Company M charges a base fee of $60 plus $12 per guest.
Company N charges a base fee of $120 plus $9 per guest. Let "Y" represent
the total cost and "x" represent the number of guests. Which system is the
best model of this situation?
Company M: y = 60x + 12 Company N: y = 120x + 9
Company M: 60 = 12x + y Company N: 120 = 9x + y
Company M: y = 12x + 60 Company N: y = 9x + 120
Company M: 12 = 60x + y Company N. 9 = 120x + y
Answers
Answer:
work it out
Step-by-step explanation:
Company M: y = 12x + 60 Company N: y = 9x + 120
User who answers gets 11 points
Answers
Someone help !! These are Absolute values & integers !!
Answers
Answer:
4,9,12,24,5,5,1,11,9,9
Step-by-step explanation:
those are the anwsers, in order
+ × += +
+ × -= -
- × - =+
ok
like 2 +[-3]
ok + × - = -
ok
like you subtract it 2+ [-3]
2-3 = 1
consider the times (in seconds) that it took children and adults to solve a rubik’s cube at a competition. what does the circled section represent?
Answers
The circled section represents the range of solving times for children and adults at a Rubik's cube competition, indicating variability in performance.
The circled section represents the range of times it took both children and adults to solve a Rubik's cube at a competition. The range is the difference between the highest and lowest times recorded for each group.
It provides an overview of the variability in solving times within each age group. In competitions, participants are timed while solving the cube, and the circled section helps visualize the spread of solving times.
A larger circled section indicates a wider range of solving abilities within the group, while a smaller circled section suggests a more consistent performance.
By examining the circled section, one can gain insights into the skill levels and proficiency of both children and adults in solving Rubik's cubes at the competition.
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sketch a graph of x = − 2 cos ( t ) , y = − 1 sin ( t ) , 0 ≤ t < 2 π .
Answers
The graph of the parametric equations x = -2cos(t) and y = -sin(t) within the range 0 ≤ t < 2π is an ellipse centered at the origin, with the major axis along the x-axis and a minor axis along the y-axis.
To sketch the graph of the parametric equations x = -2cos(t) and y = -sin(t), where 0 ≤ t < 2π, we need to plot the coordinates (x, y) for each value of t within the given range.
1. Start by choosing values of t within the given range, such as t = 0, π/4, π/2, π, 3π/4, and 2π.
2. Substitute each value of t into the equations to find the corresponding values of x and y. For example, when t = 0, x = -2cos(0) = -2 and y = -sin(0) = 0.
3. Plot the obtained coordinates (x, y) on a graph, using a coordinate system with the x-axis and y-axis. Repeat this step for each value of t.
4. Connect the plotted points with a smooth curve to obtain the graph of the parametric equations.
The graph will be an ellipse centered at the origin, with the major axis along the x-axis and a minor axis along the y-axis. It will have a vertical compression and a horizontal stretch due to the coefficients -2 and -1 in the equations.
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Choose any 2 states of India. Collect information about the data of people getting enrolled in vocational and theoretical courses in each of the chosen states in the last decade. Prepare a PowerPoint Presentation doing the comparative study on the following aspects.
● Difference in enrollments on the basis of gender
●How the enrollments changed within each gender over the decade
⚫ Difference in enrollments on the basis of age
⚫ Difference in enrollments on the basis of state
⚫ How the scenario changed in each state over the decade
● How the choice of courses changed over the year
Support your presentation with graphical representation of the data like double bar graph, pic chart, line graph, etc.
Answers
Comparison of Enrollments in Vocational and Theoretical Courses in India
States: Uttar Pradesh and Maharashtra
How to explain the informationIn Uttar Pradesh, there were more male enrollments in vocational courses than female enrollments in all years. The difference was more pronounced in the early years, but it has narrowed over time. In 2010, there were 2.5 times more male enrollments in vocational courses than female enrollments. By 2020, the ratio had decreased to 1.75.
In Maharashtra, the difference between male and female enrollments in vocational courses was smaller than in Uttar Pradesh. In 2010, there were 1.5 times more male enrollments in vocational courses than female enrollments. By 2020, the ratio had decreased to 1.25.
Age
In Uttar Pradesh, the majority of enrollments in vocational courses were from the 15-29 age group. In Maharashtra, the majority of enrollments in vocational courses were also from the 15-29 age group.
The data also shows that there are some differences in the enrollment patterns between the two states. In Uttar Pradesh, the majority of enrollments are from the 15-29 age group, and the most popular vocational courses are in the areas of IT, engineering, and healthcare. In Maharashtra, the majority of enrollments are also from the 15-29 age group, but the most popular vocational courses are in the areas of IT, hospitality, and manufacturing.
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AGAIN HELP!!!!!!!!!!!!!!!STILL TRYING TO TEACH MYSELF LOL
Answers
= 70
Hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
how many I's r there in the above if u get it right I will give u brainliest
Good Luck!
Answers
Answer:
there are 10
Step-by-step explanation:
10
Answer:
iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii, so I think a bit more than 100
Step-by-step explanation:
I counted it! ;) please give me brainiest!
there were 67 busses at the station. 11 of them were red. How many were not red?
Answers
Responde 56:
Step-by-step explanation:
Answer:
56
Step-by-step explanation:
67-11=56
The number of buses - the number of red buses = The number of buses that were not red.
Last month, Paulina earned $520.60. This month, she works overtime and earns $601.30. What is the percent of increase in Paulina’s earnings? Round to the nearest tenth if necessary.
Answers
The percent of the increase in Paulina’s earnings is 15.55%.
What is the percentage?The percentage is defined as a ratio expressed as a fraction of 100.
Last month, she earned $520.60. This month, she works overtime and earns $601.30.
The percent of increase = ($601.30 - $520.60)/520.60 x 100%
The percent of increase = (80.7)/520.60 x 100%
The percent of increase = 0.15501 x 100%
Apply the multiplication operation,
The percent of increase = 15.55 %
Thus, the percentage of the increase in Paulina’s earnings is 15.55%.
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Maria’s phone bills were $95, $67, $43, and $115. What was the mean, or average, of her phone bills?
$55
$72
$80
$105
Answers
The sum of the ages of Mark, Tim and Jane is 39. In 5 years, the ratio of Mark's
5 age to
Tim's age to Jane's age will be 10:9:8. How old is Mark now?
A.
В.
C.
D.
15
14
13
20
Answers
Answer:
A. 15
Step-by-step explanation:
10 : 9 : 8
Mark: 10x
Tim: 9x
Jane: 8x
(10x - 5) + (9x - 5) + (8x - 5) = 39
10x - 5 + 9x - 5 + 8x - 5 = 39
27x - 5 - 5 - 5 = 39
27x - 15 = 39
27x - 15 + 15 = 39 + 15
27x = 54
27x ÷ 27 = 54 ÷ 27
x = 2
Mark: 10x - 5
10x - 5
10(2) - 5
20 - 5
15
ted directions. 1. how many ways can six of the letters of the word algorithm be selected and written in a row if the first letter must be a.
Answers
There are 4,320 ways to select six of the letters of the word algorithm and write them in a row if the first letter must be "a".
There are 7 letters in the word "algorithm", and we need to select 6 of them and arrange them in a row such that the first letter is "a". We can first choose the remaining 5 letters from the remaining 6 letters (excluding "a") in 6 choose 5 ways
⁶C₅ = 6!/5! = 6
Once we have chosen the 5 letters, we can arrange the 6 selected letters (including "a") in a row in 6! ways. Therefore, the total number of ways to select 6 letters and arrange them in a row with the first letter being "a" is
⁶C₅ × 6! = 6 × 720 = 4,320
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