An Atwood's machine consists of blocks of masses m1=12.0kg and m2=19.0kg attached by a cord running over a pulley. The pulley is a solid cylinder with mass M=9.20kg and radius r=0.200m the block of mass m2 is allowed to drop, and the core turns the pulley without slipping. If the pulley axis is frictionless, find the linear acceleration of the system and the tension on each string.​

Answers

Answer 1

Answer:

2.60 m/s²

149 N and 137 N

Explanation:

Draw free body diagrams for the blocks and the pulley.

For the first block, there are two forces: m₁g pulling down and T₁ pulling up.

For the second block, there are two forces: m₂g pulling down and T₂ pulling up.

For the pulley, there are two torques: T₁r pulling counterclockwise and T₂r pulling clockwise.

m₁ moves up, so sum the forces in the +y direction:

∑F = ma

T₁ − m₁g = m₁a

m₂ moves down, so sum the forces in the -y direction:

∑F = ma

m₂g − T₂ = m₂a

The pulley rotates clockwise, so sum the torques in the clockwise direction:

∑τ = Iα

T₂r − T₁r = (½ Mr²) (a/r)

T₂ − T₁ = ½ Ma

If we add the first two equations together:

T₁ − m₁g + m₂g − T₂ = m₁a + m₂a

T₁ − T₂ + (m₂ − m₁) g = (m₁ + m₂) a

Substitute:

½ Ma + (m₂ − m₁) g = (m₁ + m₂) a

(m₂ − m₁) g = (m₁ + m₂ − ½ M) a

a = (m₂ − m₁) g / (m₁ + m₂ − ½ M)

Plug in values:

a = (19.0 kg − 12.0 kg) (9.8 m/s²) / (12.0 kg + 19.0 kg − ½ (9.20 kg))

a = 2.60 m/s²

Plug this into the first two equations to find the two tensions.

T₁ = m₁g + m₁a = 148.8 N

T₂ = m₂g − m₂a = 136.8 N

Rounded to three significant figures, the tensions are 149 N and 137 N.

Answer 2

The magnitude of tension force on each strings are 148.8 N and 136.8 N respectively.

Given data:

The mass of blocks are \(m_{1}=12.0 \;\rm kg\)  and  \(m_{2}=19.0 \;\rm kg\).

The mass of solid cylinder is, M = 9.20 kg.

The radius of solid cylinder is, r = 0.200 m.

In the given problem, there are two cases:

For the first block, there are two forces: m₁g pulling down and tension T₁ pulling up. For the second block, there are two forces: m₂g pulling down and tension T₂ pulling up.

For the pulley, there are two torques: T₁r pulling counterclockwise and T₂r pulling clockwise.

m₁ moves up, so sum the forces in the +y direction. Then apply the equilibrium of force condition as,

∑F = ma

T₁ − m₁g = m₁a

Since, m₂ moves down, so sum the forces in the -y direction:

∑F = ma

m₂g − T₂ = m₂a

The pulley rotates clockwise, so sum the torques in the clockwise direction:

∑τ = Iα

T₂r − T₁r = (½ Mr²) (a/r)

T₂ − T₁ = ½ Ma

If we add the first two equations together:

T₁ − m₁g + m₂g − T₂ = m₁a + m₂a

T₁ − T₂ + (m₂ − m₁) g = (m₁ + m₂) a

Substitute:

½ Ma + (m₂ − m₁) g = (m₁ + m₂) a

(m₂ − m₁) g = (m₁ + m₂ − ½ M) a

a = (m₂ − m₁) g / (m₁ + m₂ − ½ M)

Substitute the values:

a = (19.0 kg − 12.0 kg) (9.8 m/s²) / (12.0 kg + 19.0 kg − ½ (9.20 kg))

a = 2.60 m/s²

Plug this into the first two equations to find the two tensions.

T₁ = m₁g + m₁a = 148.8 N

T₂ = m₂g − m₂a = 136.8 N

 

Thus, we can conclude that the magnitude of tension force on each strings are 148.8 N and 136.8 N respectively.

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Related Questions


Mention two ways in which the effects of friction can be minimised

Answers

Answer:

Polishing the rough surface.

Oiling or lubricating with graphite or grease the moving parts of a machine.

Providing all bearings or wheels between the moving parts of a machine or vehicles reduce friction and allow smooth movement as rolling friction is less than sliding friction.

Explanation:

Which material would a magnet attract?
O A. Wood
O B. Cement
O C. Glass
OD. Iron

Answers

The material that the magnet attracts is Iron and hence the ideal solution is option D.

The magnet is the material that produces the magnetic field on its own. The magnetic field is the invisible field but it has the ability to attract other materials. Magnets are made up of ferromagnetic materials.

Ferromagnetic materials are materials that are permanently magnetized due to the unpaired electrons in the materials. Most of the Ferromagnetic materials are metals namely nickel, iron, etc.

When the magnet is brought close to the iron, the electrons in the iron are aligned in the direction of the magnetic field which makes the iron become magnetized. Thus, the attraction takes place between two magnetized objects.

Thus, the ideal solution is option D) Iron.

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a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!​

Answers

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times ​

Answers

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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A pendulum has a length of 2 m and a 30 kg mass hanging on the end. What is the period of the
pendulum?

Answers

Answer:

T = 2.83701481512 seconds

Explanation:

Hi!

The formula that you will want to use to solve this question is:

\(T = 2\pi *\sqrt{\frac{L}{g} }\)

T--> period

L --> length of the pendulum

g --> acceleration due to gravity (9.8m/s^2)

since we know that the mass of the bob at the end of the pendulum does not affect the period of the pendulum, we can go ahead and ignore that bit of information (unless, of course, the weight causes the pendulum to stretch)

so now we can plug in our given info into the formula above and solve!

T = 2*pi * sqrt(2/9.8)

T = 2.83701481512 seconds

*Note*

- I used 3.14 to pi, if you need to use a different value for pi (a longer version, etc) your answer will be slightly different

I hope this helped!

One end of an object has a definite positive charge, which is an instance of _____ or a positive or negative state that reacts to an electric field.

Answers

One end of an object has a definite positive charge, which is an instance of inverse-square or a positive or negative state that reacts to an electric field.

A positive or negative energy is what?

A fundamental characteristic of some of the constituent particles, of which all matter is made, is electric charge.

Electric charges come in two different flavours.

(+) positive charges

adverse charge (-)

A negative charge is present when there are more electrons than protons in an item.

When an atom has more protons than electrons, it has a positive charge.

Protons have a positive charge, whereas electrons have a negative charge.

The coulomb is the unit of charge (C).

Similar charges repel one another.

Similar charges are drawn to one another.

The positive charge produces an electric flux.

The negative charge is the point where electric flux ends.

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Two parallel, vertical, plane mirrors, 38.8 cm apart, face each other. A light source at point P is 30.1 cm from the mirror on the left and 8.7 cm from the mirror on the right.
(a) How many images of point P are formed by the mirrors?
(b) Find the distance from the mirror on the right to the two nearest images behind the mirror.
first nearest image=
second nearest image=
(c) Find the number of reflections of light rays for each of these images.
first nearest image=
second nearest image=

Answers

Answer:

Explanation shown below.

Explanation:

1.The number of images formed by 2 parallel mirrors is an infinite number of images.

2. The characteristics of a plane mirror is such that the object distance equals the image distance.

Hence the object distance is 8.7cm from the right; the image formed would be 8.7cm behind the mirror.

Now a second image is going to be formed by the left mirror which is going to have an image distance of 30.1cm behind the mirror.

Now this image would be reflected on the right side to form a new image which is going to be seen as 38.8 +30.1 = 68.9cm behind the right Mirror .

Hence the shortest distances are 8.7cm and 68.9cm

3. The number of reflections is infinite for both cases.

The volume of 1 kg of helium in a piston–cylinder device is initially 5 m3. Now helium is compressed to 2 m3 while its pressure is maintained constant at 174 kPa. Determine the initial and final temperatures of helium as well as the work required to compress it, in kJ. The gas constant of helium is given to be R = 2.0769 kJ/kg·K. (Round the temperatures to one decimal place and the work required to the nearest whole number.)

Answers

Answer:

T₁ = 418.9 k = 145.9° C

T₂ = 167.6 k = - 105.4° C

W = - 522 KJ

Here negative sign indicates that work is being done on the gas.

Explanation:

For the temperature of Helium, we use the general gas equation:

PV = mRT

For initial state:

PV₁ = mRT₁    (Constant Pressure)

where,

P = constant pressure = 174 KPa

V₁ = Initial Volume = 5 m³

m = mass = 1 kg

R = Gas Constant of Helium = 2.0769 KJ/kg.k

T₁ = initial temperature of helium = ?

Therefore,

(174 KPa)(5 m³) = (1 kg)(2.0769 KJ/kg.k)T₁

T₁ = (870 KJ)/(2.0769 KJ/k)

T₁ = 418.9 k = 145.9° C

For final state:

PV₂ = mRT₂    (Constant Pressure)

where,

P = constant pressure = 174 KPa

V₂ = Final Volume = 2 m³

m = mass = 1 kg

R = Gas Constant of Helium = 2.0769 KJ/kg.k

T₂ = Final temperature of helium = ?

Therefore,

(174 KPa)(2 m³) = (1 kg)(2.0769 KJ/kg.k)T₂

T₂ = (348 KJ)/(2.0769 KJ/k)

T₂ = 167.6 k = - 105.4° C

The work done on a gas in a constant pressure process (isobaric) is given as:

W = P(V₂ - V₁)

W = (174 KPa)(5 m³ - 2 m³)

W = - 522 KJ

Here negative sign indicates that work is being done on the gas.

Which of the following bounces light in another direction?
a) Sunglasses
b) lamp
c) mirror
d) prism​

Answers

Answer:

I do believe the answer is D. prism

Answer:

Explanation:

either all of the above or D <3

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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how do you mountaineers reduce the effects of changes in atmospheric pressure?

Answers

Essentially belly breathing with forceful exhale, the pressure breath helps to improve gas exchange across the alveoli by increasing the pressure of the lungs . The pressure breaths helps to combat the effects caused by decreasing atmospheric pressure as climbers gain altitude

What observations can the geologist make by working outdoors instead of in a lab?

Answers

Answer:

Geology is the study of the Earth that involves the process at Earth, materials of which it is made, and its history.

Geologists combine both laboratory and field data to illustrate the results of their research. Some observations that can the geologist make by working outdoors instead of in a lab are as follows:

Understanding and exploring the earth's surface closely using geophysical tools.Collecting samples by own and make some interpretations at the same time.Observation of the  landscapesClose observation of outcrops

Can someone help me find F2

Can someone help me find F2

Answers

The net electric force on particle q₂ is determined as -9.86 N.

What is the net force of particle q₂?

The net force of particle q₂ is determined by applying Coulomb's law of electrostatic force.

The electric force between particle q₁ and q₂ is the repulsive force and the magnitude is calculated as;

F₁₂ = kq₁q₂ / r²

where;

K is the Coulomb's constantq₁ is the magnitude of charge 1q₂ is the magnitude of charge 2r is the distance between charge 1 and charge 2

F₁₂ = -(9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶) / (0.25²)

F₁₂ = -14.4 N

The electric force between particle q₃ and q₂ is the attractive force and the magnitude is calculated as;

F₂₃ = kq₃q₂ / r²

F₂₃ = (9 x 10⁹ x 5.9 x 10⁻⁶ x 7.7 x 10⁻⁶) / (0.3²)

F₂₃ = + 4.54 N

The net force on the particle q₂ is calculated as;

F (net) = F₁₂ + F₂₃

F (net) = -14.4 + 4.54

F (net) = -9.86 N

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In your business plan, the target market section should clearly identify_____market(s).
A. Both your primary and secondary
B. primary
C. demographic
D. secondary

Answers

In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.

The function s(t)s(t) describes the position of a particle moving along a coordinate line, where ss is in feet and tt is in seconds. (a) Find the velocity and acceleration functions. (b) Find the position, velocity, specd, and acceleration at time t

Answers

Answer:

Explanation:

From the given information:

Let's assume that the missing function is:

s(t) = t³ - 6t², t ≥ 0

From part (b), we are to find the given  required terms when time t = 2

So; from the function s(t) =  t³ - 6t², t ≥ 0

\(velocity \ v(t) \ = \dfrac{d}{dt}s(t)\)

\(velocity \ v(t) \ = \dfrac{d}{dt}(t^3 - 6t^2)\)

\(velocity \ v(t) \ = 3t^2 - 12t\)

\(acceleration a(t) = \dfrac{d}{dt}*v(t)\)

\(acceleration a(t) = \dfrac{d}{dt}(3t^2 - 12 t)\)

\(acceleration\ a(t) = 6t - 12\)

At time t = 2

The position; S(2) = (2)² - 6(2)²

S(2) = 8 - 6(4)

S(2) = 8 - 24

S(2) = - 16 ft

v(2) = 3(2)² - 12 (2)

v(2) = 3(4) - 24

v(2) = 12 - 24

v(2) = - 12 ft/s

speed = |v(2)|

|v(2)|  = |(-12)|

|v(2)| = 12 ft/s

acceleration = 6t - 12

acceleration = 6(2) - 12

acceleration =  12 - 12

acceleration =  0 ft/s²

consider the picture below illustrating three different regions of earth (the northernhemisphere, the southern hemisphere, and the equatorial region) at two different times ofthe year, six months apart.\\\\\\< sunlight-e?sunsunlight >~.::".,\\\\\\note: this drawing is not to scale. in fact you could fit more than 11,000 earths between the sun and earth.12) which location( s) (a-f) correspond( s) with summer in the northern hemisphere?explain your reasoning.

Answers

Location F is significant because it demonstrates that there are winters inside the southern hemisphere but that Antarctica has long, dark days and nights.when the winter season in the Hemisphere is in effect

What time of year do you think it is down south?

Seasons are a result of the tilt of the Earth's axis; winter occurs when one hemisphere is pointed toward the sun.The beginning of winter is marked by various cultural definitions, some of which base their dates on the weather.In the Southern Quarter, it's indeed summer when it is winter inside the Northern Hemisphere, and conversely.

What time of year do the northern & southern hemispheres experience?

As a result, the first day of spring, summer, autumn, and winter in temperate regions of the northern hemisphere is March 1.In the temperate zone of the southern hemisphere, spring officially starts on 1 September, winter on 1 December, and fall on 1 March.

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A system has two possible energy states, E0 and E1 (with E1 > E0). If the difference between these energy states grows (E0 and E1 get further apart while the temperature stays constant), then the ratio of the number of particles in state E0 over the number of particles in state E1 will:__________

Answers

Answer:

The number of particles in state E0 over the number of particles in state E1  will reduce

Explanation:

E0 represents the ground level state when all the particles have same energy level.

E1 represents excited state in which only a few particle reaches

E0 and E1 get further apart  means that the energy difference between the two level increases.

Thus, the number of particles in state E0 over the number of particles in state E1  will reduce.

A student practicing for a cross country meet runs 250 m in 30 s. What is the average speed

Answers

Answer:8.3m/sec 30 sec,

Explanation:

A student practicing for a track meet, ran 250 m in 30 sec. a. What was her average speed? 250 m = 8.3 m/sec 30 sec.

A 3.0-kg block moves up a 40° incline with constant speed under the action of a 26-N force acting up and parallel to the incline. What magnitude force must act up and parallel to the incline for the block to move down the incline at constant velocity?

Answers

Explanation:

Sooooo, first,

Constant Speed means that the body isn't accelerating.

a= 0

Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.

The force that pulls the body downwards is given by,

F = mgsin40°

F= 18.898N

P -(F+Fr) = ma, but, a= 0

P = F + Fr

Fr = 26-18.898

= 7.102N

If the block must move down the incline, Q and Fr will act in the same direction.

Q + Fr = F

Q = 11.796N

Which statement accurately describes the motion of the object in the graph above over 10 seconds?

The object moves forward at 1 cm/s, stops, and then continues at the same velocity.
The object moves forward at 1 cm/s, stops, and then increases velocity to 2 cm/s.
The object is at rest for 4 seconds and then moves forward for 4 seconds at 1 cm/s.
The object is at rest for 3 seconds and then decreases velocity to 1 cm/s for 3 seconds.

Which statement accurately describes the motion of the object in the graph above over 10 seconds? The

Answers

B. The object moves forward at 1 cm/s, stops, and then increases velocity to 2 cm/s.

Velocity of the object between 0 to 3 s

Velocity = change in position / change in time

Velocity = (3 cm - 0 cm)/(3 s - 0 s)

Velocity = 1 cm/s

The displacement of the object between 3 seconds to 6 seconds is zero (0).

Velocity of the object between 6 to 10 s

Velocity = (11 cm - 3 cm)/(10 s - 6s)

Velocity = 2 cm/s

Thus, the object moves forward at 1 cm/s, stops, and then increases velocity to 2 cm/s.

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Answer:

B

Explanation:

Which statement accurately describes the motion of the object in the graph above over 10 seconds? The

Which circuit best describes the kind of circuit that is created when the electrical charge flows from one point to another in a single closed path?
A. Closed circuit
B. Charged circuit
C. Parallel circuit
D. Series circuit

Answers

Answer:b

Explanation:

The belief that race indicates certain traits and capacities and that one's own race is superior is called __________.
A.
ageism
B.
sexism
C.
racism
D.
feminism

Answers

Answer:Racism

Explanation:

Racism
Explanation: it’s the only answer that has to do with race

A gas is contained in a cylinder with a frictionless moveable piston at a pressure of 2.7 * 105 pascals and a volume of 0.04 cubic meters. What is the work done by the gaseous system if the volume is increased to 0.12 cubic meters ?

Answers

The work done by the gaseous system if the volume is increased to 0.12 cubic meters is given as 21,600 joules

How to solve for the workdone

To find the work done by the gas, we can use the formula:

W = PΔV

where W is the work done, P is the pressure of the gas, and ΔV is the change in volume.

At the initial state, the pressure is P = 2.7 × 10^5 Pa and the volume is V1 = 0.04 m^3. At the final state, the volume is V2 = 0.12 m^3.

The change in volume is ΔV = V2 - V1 = 0.12 m^3 - 0.04 m^3 = 0.08 m^3.

Substituting these values into the formula, we get:

W = PΔV = (2.7 × 10^5 Pa) × (0.08 m^3) = 21,600 J

Therefore, the work done by the gaseous system is 21,600 joules (J).

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Answer:

4.6x10^4 joules

Explanation:

A gas is contained in a cylinder with a frictionless moveable piston at a pressure of 2.7 * 105 pascals

a particle weighing 250N accelerates from 8.5m/s when a force of 125N acts on it. Find the velocity after 5.5sec​

Answers

The velocity of the particle after 5.5 seconds is 11.25 m/s.

To find the velocity of the particle after 5.5 seconds, we can use the equation of motion:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

Given:

u = 8.5 m/s (initial velocity)

a = F/m = 125 N / 250 N = 0.5 m/\(s^2\) (acceleration)

t = 5.5 sec (time)

substitute the values:

v = 8.5 m/s + (0.5 m/\(s^2\))(5.5 sec)

v = 8.5 m/s + 2.75 m/s

v = 11.25 m/s

Therefore, the velocity of the particle after 5.5 seconds is 11.25 m/s.

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An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)

Answers

An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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what is the current definition of intelligence?

Answers

Answer:

the ability to learn, emotional knowledge, creativity, and adaptation to meet the demands of the environment effectively

A block is launched with initial speed 2.2 m/s up a 35° frictionless ramp
How far up the ramp does it slide?

Answers

When a block is launched with initial speed 2.2 m/s up a 35° frictionless ramp then ramp slides up to 0.43m.

What is work energy theorem?

The work-energy theorem explains that net work done by the forces on an object is equal to change in its kinetic energy.

We can also say that work done on a body is equal to the net change in its energy.

Given angle = 35°

initial speed = 2.2m/s

Applying work - energy theorem,

Wgravity = KE

-m *g *sin ∅ * S =1/2* (0- 2.2²)

-9.81*sin 35° *S= 1/2 *(0- 2.2² )

S= 0.43m

Ramp slides up to 0.43m.

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A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current running from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]

Answers

Answer:

Explanation:

Force on a current carrying wire in a magnetic field

= B i L where B is magnetic field , i is current and L is length of the wire .

Putting in the given values in the question

force on a current carrying wire in a magnetic field  = .001 T x i x .5 m

5 x 10⁻⁴ i  N .

weight of the wire = .050 kg x 9.8 m/s²

= .49 N .

For equilibrium

5 x 10⁻⁴ i  = .49

i = 980 A .

A well-coated structure is defined as A) 95% or better B) 90% or better C) 99% or better D) 93% or better

Answers

Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

Learn more about the UV radiation refer: brainly.com/question/13849635

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

A horizontal string tied at both ends is vibrating in its fundamental mode. The traveling waves have speed v, frequency f, amplitude A, and wavelength λ.
A) Calculate the maximum transverse velocity of the point located at x=λ/2.
Express your answer in terms of the variables v, f, A, λ, and appropriate constants. vmax =
B) Calculate the maximum transverse acceleration of the point located at x=λ/2.
Express your answer in terms of the variables v, f, A, λ, and appropriate constants. amax =
C) What is the amplitude of the motion at the point located at x=λ/2?
Express your answer in terms of the variables v, f, A, λ, and appropriate constants.
ASW = D) How much time does it take the string to go from its largest upward displacement to its largest downward displacement at the point located at x=λ/2?
Express your answer in terms of the variables v, f, A, λ, and appropriate constants. t =

Answers

A) The maximum transverse velocity of the point located at x=λ/2 is given by vmax = 2πfA.

B) The maximum transverse acceleration of the point located at x=λ/2 is given by amax = (2πf)^2A.

C) The amplitude of the motion at the point located at x=λ/2 is half the amplitude of the entire wave, so the amplitude at this point is A/2.

D) The time it takes for the string to go from its largest upward displacement to its largest downward displacement at the point located at x=λ/2 is given by t = 1/f.
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