An object has 7N upwards, and on the same side 6N upwards. It also has 10N down and in the same direction 6N down. What is the Net Force and Describe the motion of the object.

Answer:12

Explanation:

Answer Multiply the acceleration by time to obtain the velocity change: velocity change = 6.95 * 4 = 27.8 m/s . Since the initial velocity was zero, the final velocity is equal to the change of speed.

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v, start subscript, a, v, g, end subscript, equals, start fraction, delta, x, divided by, t, end fraction, equals, start fraction, minus, 4, start text, space, m, end text, divided by, 5, start text, space, s, end text, end fraction, equals, minus, 0, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction

The minus sign indicates the average velocity is also toward the rear of the plane.

The average velocity of an object does not tell us anything about what happens to it between the starting point and ending point, however. For example, we cannot tell from average velocity whether the airplane passenger stops momentarily or backs up before he goes to the back of the plane. To get more details, we must consider smaller segments of the trip over smaller time intervals. For instance, in the figure below, we see that the total trip displacement,

Answer:

bdjdiosfjigjdigjtrht <3

Explanation:

Answer:

1,110,114.6 J

Explanation:

The height is 1857m, the mass is 61 kg, and the accelaration is 9.8 m/s^2. Plug in the equation GPE=h*m*a and you get 1,110,114.6.

h= height

m= mass

a= accelaration

GPE= gravitational potential energy

If you are at the grand canyon standing at the edge of a ledge 1857 meters high you have a mass of 61 kilograms, then your gravitational potential energy at the edge of the cliff would be 1111247.37 Joules.

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As total mechanical energy is the sum of all the kinetic as well as potential energy stored in the system.

ME = KE + PE

The total gravitational potential energy at the edge of the cliff would be

PE = m × g × h

PE =61 × 9.81 × 1857

PE =1111247.37 Joules

Thus, the total gravitational potential energy at the edge of the cliff would be  1111247.37 Joules.

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The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The speeds of light in the water will be 2.25×10⁸ m/sec.

The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The difference in density is the cause of the bending.

Refraction is a term that is used to describe the phenomenon of refraction."The change in direction of a wave traveling through one medium to another is known as refraction."

The following data are given in the problem;

C is the Speed of light in a vacuum =3×10⁸ m/sec.

n is an index of refraction for water = 1.333

v is the speed of light in the water=?

The index of refraction is the ratio of the speed of light in a vacuum to the speed of light in water. By the formula of the index of refraction.

\(\rm n=\frac{C}{V} \\\\ \rm V=\frac{C}{n}\\\\ \rm V=\frac{3\times10^8}{1.333}\\\\\ \rm V=225056264.1\;m/sec.\\\\\rm V=2.25\times10^8\;m/sec.\)

Hence the speed of light in the water will be 2.25×10⁸ m/sec.

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The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The speeds of light in the water will be 2.25×10⁸ m/sec.

The phenomenon bending of a wave as it crosses from one medium to another is said to be refraction. The difference in density is the cause of the bending.

Refraction is a term that is used to describe the phenomenon of refraction."The change in direction of a wave traveling through one medium to another is known as refraction."

The following data are given in the problem;

C is the Speed of light in a vacuum =3×10⁸ m/sec.

n is an index of refraction for water = 1.333

v is the speed of light in the water=?

The index of refraction is the ratio of the speed of light in a vacuum to the speed of light in water. By the formula of the index of refraction.

\(n=\dfrac{c}{v}\)

\(V=\dfrac{c}{n}\)

\(V=\dfrac{3\times10^8}{1.333}\)

\(V=2.25\times 10^8 m/s\)

Hence the speed of light in the water will be 2.25×10⁸ m/sec.

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Answer:

when the ray passes from ice to perspex it must approach the normal

Explanation:

This is an exercise in refraction of light, the process is governed by the expression

      n₁ sin θ₁ = n₂ sin θ₂

where we use index 1 for the incident medium and subscript 2 for the scattered medium.

In our case, medium 1 is ice with the lowest refractive index.

           sin θ₁ = n₂ / n₁   sin θ₂

To fulfill this equation, if the ray travels through the medium 1 ice with an angle θ₁, the angle in the medium 2 perspex must be smaller so that the sine is smaller, so when the ray passes from ice to perspex it must approach the normal

The  answer is that the statement is true only if the two forces are acting in the same direction. If the two forces are acting in opposite directions, then they cannot be combined into a single resultant force.

When two forces act on a body in the same direction, they can be combined into a single resultant force by simply adding their magnitudes. This is because the direction of the resultant force will be the same as the direction of the two forces.

However, when two forces act on a body in opposite directions, they cannot be simply added together. Instead, they will cancel each other out and create a net force of zero. In this case, the two forces cannot be combined into a single resultant force.

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Answer:

Yes. If a car travels in a circular path with constant speed, its motion is called uniform circular motion

Explanation:

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Brain-list it or support me at my U-Tube channel " ZK SOFT&GAMING " I will be thankful

Answer:

:)

Explanation:

Answer:

\(N_P = 40\ N_S\)

To reduce the output voltage to 6v in transformers if the input voltage is 240v​, we need to have 40 times as many turns in the primary coil as there are in the secondary coil.

Explanation:

The change in voltage of a transformer depends upon the turns ratio of the transformer between secondary and primary coil. Following formula can be used to determine the turns ratio in this case:

\(\frac{N_P}{N_S} = \frac{V_P}{V_S} \\\\\)

where,

\(N_P\) = No. of turns in the primary coil

\(N_S\) = No. of turns in the secondary coil

\(V_P\) = voltage in the primary coil = 240 V

\(V_S\) = voltage in the secondary coil = 6 V

Therefore,

\(\frac{N_P}{N_S} = \frac{240\ V}{6\ V} \\\\N_P = 40\ N_S\)

To reduce the output voltage to 6v in transformers if the input voltage is 240v​, we need to have 40 times as many turns in the primary coil as there are in the secondary coil.

Answer:

They walked for 10.025 minutes or 601.5 seconds

Explanation:

\({ \rm{velocity = \frac{ \triangle displacement}{time} }} \\ \\ { \rm{time = \frac{displacemet}{velocity} }} \\ \\ { \rm{time = \frac{800}{1.33} }} \\ \\ { \rm{time = 601.5 \: seconds}}\)

Answer:

B. man with a beard

Explanation:

it is not a genetic mutation because it is completely natural and common unlike the other options.

Answer:

di ko alam eh sorey

Explanation:

di ako maalam sa ganyan

Answer:

The amount of gravitational force INCREASES as the distance between two objects increases; thus, an astronauts weight DECREASES as she or he moves away from earth into space.

hope this helped.

Answer:

Element

Explanation:

The Number 1 which is Ca is a calcium element that is taking part in the chemical combination.

An element is a substance made up of one kind of atom.

Calcium is an element belong to the alkali earth metals. These group of elements are found on the second group of the periodic table.

a) To find the acceleration of the masses and the tension in the string, we need to consider the forces acting on the system.

1. Forces on m1 (block on the ramp):

The component of the weight acting parallel to the incline is \(\displaystyle\sf mg_{1}\sin(20°)\), and the component perpendicular to the incline is \(\displaystyle\sf mg_{1}\cos(20°)\).

The normal force \(\displaystyle\sf N_{1}\) is equal in magnitude and opposite in direction to the perpendicular component of the weight, so \(\displaystyle\sf N_{1}=mg_{1}\cos(20°)\).

The frictional force \(\displaystyle\sf f\) is given by \(\displaystyle\sf f=\mu N_{1}\), where \(\displaystyle\sf \mu\) is the coefficient of kinetic friction.

The net force acting on m1 is the force parallel to the incline, which is the difference between the weight component and the frictional force:

\(\displaystyle\sf F_{\text{{net}}}=(mg_{1}\sin(20°))-f\).

Using Newton's second law \(\displaystyle\sf F_{\text{{net}}}=m_{1}a\), where \(\displaystyle\sf a\) is the acceleration of the masses, we can find the acceleration:

\(\displaystyle\sf m_{1}a=(mg_{1}\sin(20°))-f\).

Now, let's consider the forces acting on m2 (hanging block):

Since the two blocks are connected by the string, the tension in the string is the same for both blocks, so \(\displaystyle\sf T\) is the tension in the string.

Using Newton's second law for m2, we have:

\(\displaystyle\sf m_{2}g_{2}-T=m_{2}a\).

Now we have two equations with two unknowns (a and T). Solving these equations simultaneously will give us the values for acceleration and tension.

b) To find the maximum value of m2 that will not make m1 slide up the incline, we need to consider the forces and the maximum static friction.

When m1 is at the verge of sliding up the incline, the force of static friction \(\displaystyle\sf f_{\text{{static}}}\) is at its maximum and is given by \(\displaystyle\sf f_{\text{{static}}}=\mu_{\text{{static}}}N_{1}\), where \(\displaystyle\sf \mu_{\text{{static}}}\) is the coefficient of static friction.

The force of static friction \(\displaystyle\sf f_{\text{{static}}}\) must be equal to or greater than the component of the weight of m1 parallel to the incline, which is \(\displaystyle\sf mg_{1}\sin(20°)\).

So we have:

\(\displaystyle\sf f_{\text{{static}}}=\mu_{\text{{static}}}N_{1}\geq mg_{1}\sin(20°)\).

Using the expression for \(\displaystyle\sf N_{1}\) from part a, we can substitute and solve for the maximum value of m2.

Answer:

KE = 1/2 M V^2

V = (2 KE / M)^1/2 = (2 * 40 / .1)^1/2 = 28.3 m/s

Answer:

The correct answer is "625,000 J".

Explanation:

The given values are:

Mass,

m = 2,000 kg

Speed,

v = 25 m/sec

As we know,

⇒  \(Kinetic \ energy=\frac{1}{2} (mass \times speed^2)\)

Or,

⇒  \(K.E=\frac{1}{2}(mv^2)\)

On substituting the values, we get

⇒          \(=\frac{1}{2}(2,000\times 25^2)\)

⇒          \(=1000\times 625\)

⇒          \(=625,000 \ J\)              

To heat a 1200 sq ft house with natural gas, we spend a total of $14.40 per day.

How much it costs to heat a 1200 sq ft house with natural gas relies on a number of things, such as where the house is, how well it heats, and how much natural gas costs in that area.

Sources. says that the cost per square foot for natural gas with 40 BTU is $0.00049836 per square foot per hour. If our house is 1200 square feet, we multiply this cost by 1200 and get $0.60 per hour to heat it. That means that to heat a 1200 sq ft house with natural gas, we spend a total of $14.40 per day.

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Answer:

In a series circuit, the equivalent resistance is the algebraic sum of the resistances. The current through the circuit can be found from Ohm's law and is equal to the voltage divided by the equivalent resistance. The potential drop across each resistor can be found using Ohm's law.

Answer:

A simplified model that depicts how light behaves as it reflects off mirrors and goes through lenses, in which light is depicted as a straight line or ray that indicates the direction in which the light wave travels. Light must enter your eyes from the thing in order for you to view it.

The energy of a photon of x-ray radiation with a frequency of \(4.43*10^{18} s^-1\) is \(2.93*10^{-10} J\).

The energy of a photon is directly proportional to its frequency, as given by the formula E = hf, where E is energy, h is Planck's constant, and f is frequency. To calculate the energy of a photon of x-ray radiation with a frequency of \(4.43*10^{18} s^{-1}\), we can substitute the given values in the formula to get:

\(E = hf = (6.626*10^{-34} Js) * (4.43*10^{18} s^{-1}) = 2.9310^{-10} J\)

Therefore, the energy of a photon of x-ray radiation with a frequency of \(4.43*10^{18} s^{-1}\) is \(2.93*10^{-10} J\).

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Answer:

We have that Assuming No air resistance,the initial horizontal velocity of the cannonball is

From the question we are told that

A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s

Generally the equation for the horizontal velocity  is mathematically given as

Therefore

Therefore Assuming No air resistance,the initial horizontal velocity of the cannonball is For more information on this visit

Explanation:

In the simulation, the brightness of the white arrows represents the strength of the electric field at each point. It does not indicate the poles of the electric field or whether the field is negative or positive.

In the given simulation, the brightness of the white arrows represents the strength of the electric field at each point. The electric field is a vector field that describes the influence of electric charges on other charges or objects in the surrounding space. It has both magnitude and direction. By assigning different brightness levels to the white arrows, the simulation visualizes the relative strength of the electric field at different points.

The strength of the electric field at a particular location is determined by the magnitude of the charge(s) present in the simulation and the distance from the charge(s). A stronger electric field corresponds to a higher density of electric field lines in the vicinity of a charge. Therefore, in the simulation, brighter white arrows indicate regions with a higher electric field strength, while dimmer white arrows represent regions with a weaker electric field.

It's important to note that the brightness of the arrows in the simulation does not provide information about the poles of the electric field or whether the field is negative or positive. The electric field does not have distinct poles like magnets do. Instead, the electric field lines indicate the direction a positive test charge would experience when placed in the field. The arrows in the simulation simply point in the direction of the electric field at each point, without distinguishing between positive or negative charges.

Therefore, the brightness of the white arrows exclusively represents the strength of the electric field, providing a visual representation of the intensity of the field at different locations within the simulation.

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The Scientific Method Review name is HOMER and it stands for :

Observations and inquiries are a part of the scientific method. Based on these findings, scientists generate hypotheses, which are followed by controlled experiments for data collection and analysis. They can make judgments and formulate questions for future scientific research using this data.

The abbreviation HOMER is intended to cover all of the actions that should be taken while doing a scientific method review. The first step is to formulate a hypothesis.

The second step is to operationalize this theory and see whether it is viable. The results of this research must next be evaluated after being measured. The test should then be repeated, the findings revised, and a report should be written.

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The velocity with which the rock initially kicked if the cliff is 5 m high and the rock lands 7m from the base of the cliff is 6.93 m / s

s = ut + 1 / 2 at²

s = Distance

u = Initial velocity

t = Time

a = Acceleration

In vertical motion,

s = 5 m

u = 0

a = 9.8 m / s²

5 = 0 + ( 1 / 2 * 9.8 * t² )

t² = 1.02

t = 1.01 s

In horizontal motion,

s = 7 m

a = 0 ( Since velocity is constant )

7 = 1.01 u + 0

u = 7 / 1.01

u = 6.93 m / s

Therefore, the velocity with which the rock initially kicked is 6.93 m / s

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Answer:

Homo- means the same or uniform.

Explanation:

https://courses.lumenlearning.com/cheminter/chapter/homogenous-and-heterogenous-mixtures/

The dot product is 25, the angle is \(\theta = cos^{-1} \frac{25}{\sqrt{35} \times \sqrt{21}}\), the cross product is 1i + (-6)j + (-7)k, and the area of the parallelogram spanned by vectors A and B is \(\sqrt{86}\).

Given,

A = 5i + 3j + k

B = 4i + j + 2k

i. Dot Product (A · B):

The dot product of two vectors A and B is given by the sum of the products of their corresponding components.

\(A.B = (A_x \times B_x) + (A_y \times B_y) + (A_z \times B_z)\\A.B = (5 \times 4) + (3 \times 1) + (1 \times 2) \\= 20 + 3 + 2 \\= 25\)

ii. Angle between vectors A and B:

The angle between two vectors A and B can be calculated using the dot product and the magnitudes of the vectors.

\(cos\theta = (A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} ((A.B) / (|A| \times |B|))\\A = \sqrt{(5^2 + 3^2 + 1^2)} =\\ \sqrt{35}\\B = \sqrt{(4^2 + 1^2 + 2^2)} \\= \sqrt{21}cos\theta = \frac{(A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} \frac{25}{\sqrt{35} \times \sqrt{21}}}\)

iv. Cross Product (A × B):

The cross product of two vectors A and B is a vector that is perpendicular to both A and B and its magnitude is equal to the area of the parallelogram spanned by A and B.

\(A\times B = (A_y \timesB_z - A_z \timesB_y)i + (A_z \timesB_x - A_x \timesB_z)j + (A_x \times B_y - A_y \times B_x)k\\A\times B = ((3 \times 2) - (1 \times 1))i + ((1 \times 4) - (5 \times 2))j + ((5 \times 1) - (3 \times 4))k\\= 1i + (-6)j + (-7)k\)

Area of the parallelogram spanned by vectors A and B:

The magnitude of the cross product A × B gives us the area of the parallelogram spanned by A and B.

Area = |A × B|

Area of the parallelogram spanned by vectors A and B:

Area = |A × B| =

\(\sqrt{(1^2 + (-6)^2 + (-7)^2}\\\sqrt{1+36+49\\\\\sqrt{86}\)

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The time plane needs to take off is 12 sec if the plane accelerates from rest at a constant rate of 5.00ms² along a runway that is 1800m long.

We can use the kinematic equation that relates the final velocity, initial velocity, acceleration, and time to solve this problem:

\(v_f\) = \(v_i\) + at

where:

\(v_f\) = final velocity of the plane (takeoff velocity)

\(v_i\) = initial velocity of the plane (0 m/s)

a = acceleration of the plane (5.00 m/s²)

t = time needed to take off

We also know that the plane takes off when it reaches the end of the runway, so we can use another kinematic equation that relates the distance, initial velocity, acceleration, and time:

d = \(v_i\)t + 0.5a × t²

where:

d = distance traveled by plane (1800 m)

We can solve the first equation for t:

t = (\(v_f\) - \(v_i\)) / a

Since the initial velocity is 0 m/s, this simplifies to:

t = \(v_f\) / a

Substituting this expression for t into the second equation, we get:

d = 0.5a(\(v_f\)/a)²

Simplifying this expression:

d = 0.5 × \(v_f\)² / a

Multiplying both sides by 2/a:

d × 2/a = \(v_f\)² / a

Taking the square root of both sides:

\(v_f\) = √(2ad)

Now we can substitute the values we know and solve for \(v_f\):

\(v_f\) = √(2 × 5.00 m/s² × 1800 m) = 60.0 m/s

Finally, we can use the first kinematic equation to solve for t:

t = \(v_f\) / a = 60.0 m/s / 5.00 m/s² = 12.0 s

Therefore, it will take the plane 12.0 seconds to take off.

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