An object has a density of 9.22 g/cm³. What is the mass of 20.21 cm³ of this substance?

(a) Polytetrafluoroethylene has a repeat unit of (-CF2-CF2-)n, where n is the number of repeat units in the polymer chain. The molecular weight of each repeat unit is 100.01 g/mol, and since there are n repeat units, the molecular weight of the polymer is 100.01n g/mol.

(b) Poly(methyl methacrylate) has a repeat unit of (-CH2-C(CH3)-COO-)n, where n is the number of repeat units in the polymer chain. The molecular weight of each repeat unit is 100.12 g/mol, and since there are n repeat units, the molecular weight of the polymer is 100.12n g/mol.

(c) Nylon 6,6 has a repeat unit of (-NH-(CH2)6-NH-CO-(CH2)4-CO-)n, where n is the number of repeat units in the polymer chain. The molecular weight of each repeat unit is 226.32 g/mol, and since there are n repeat units, the molecular weight of the polymer is 226.32n g/mol.

(d) Poly(ethylene terephthalate) has a repeat unit of (-CO-C6H4-CO-O-CH2-CH2-O-)n, where n is the number of repeat units in the polymer chain. The molecular weight of each repeat unit is 192.17 g/mol, and since there are n repeat units, the molecular weight of the polymer is 192.17n g/mol.


(a) Polytetrafluoroethylene (PTFE): The repeat unit is -CF2-. Its molecular weight is (12.01 g/mol for C) + (2 x 19.00 g/mol for F) = 50.01 g/mol.

(b) Poly(methyl methacrylate) (PMMA): The repeat unit is -C(CH3)(COOCH3)CH2-. Its molecular weight is (5 x 12.01 g/mol for C) + (3 x 16.00 g/mol for O) + (8 x 1.01 g/mol for H) = 100.12 g/mol.

(c) Nylon 6,6: The repeat unit is -[NH(CH2)6NHCO(CH2)4CO]-. Its molecular weight is (12 x 12.01 g/mol for C) + (2 x 14.01 g/mol for N) + (22 x 1.01 g/mol for H) + (2 x 16.00 g/mol for O) = 226.32 g/mol.

(d) Poly(ethylene terephthalate) (PET): The repeat unit is -[OCH2CH2OCO(C6H4)CO]-. Its molecular weight is (10 x 12.01 g/mol for C) + (8 x 1.01 g/mol for H) + (4 x 16.00 g/mol for O) = 192.18 g/mol.

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The mass of 3.012 x 10^24 Ca2+ ions is approximately 20.03 g.

Molar mass is defined as the ratio between the mass and the amount of substance of any sample of said compound.

To find the mass of a specific number of ions, we can use the molar mass of the ions.

Given:

Ca2+ ion has a molar mass of 40.08 g/mol

Number of Ca2+ ions = 3.012 x 10^24

First, let's convert the number of ions to moles:

moles = (3.012 x 10^24 ions) / (6.022 x 10^23 ions/mol)

moles = 0.5012 mol

Next, let's multiply the number of moles by the molar mass to get the mass in grams:

mass (g) = moles * molar mass (g/mol)

mass (g) = 0.5012 * 40.08 g/mol

mass (g) = 20.03 g

Therefore,The mass of 3.012 x 10^24 Ca2+ ions is approximately 20.03 g.

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Answer: It will expand to fill the room.

Explanation:

Gases will expand or compact to fill the available space.

The formula unit of a salt that is not correct is \(Ca_{2} O\) in option C.

A salt is almost always made up of a metal and a nonmetal element. The salts as we know them are mostly ionic in nature and they are known to be able to dissolve in solution when they are put into solution.

We know that the salt that they meant to show in option C is calcium oxide and the foregoing can not be the correct formula since both the calcium and the oxygen ions are divalent. The correct formula of the salt would be CaO.

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Some environmental problems human population growth poses are:

Maintainable resource management: Executing maintainable hones to oversee assets viably and minimize squander. This incorporates receiving renewable vitality sources, advancing water preservation, and practicing mindful farming and ranger service.

Preservation and conservation of ecosystems: Ensuring and reestablishing normal habitats, building up ensured ranges, and advancing economical land-use hones to protect biodiversity and avoid environment misfortune.

Education and awareness: Advancing natural instruction and mindfulness to cultivate economical ways of life and behavior alter. Teaching people around the affect of their choices on the environment can lead to more maintainable utilization designs.

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Answer:

The suns position would change from human perspective because of the rotation of the earth around its axis. So your shadow would look differently. Explanation: The sun will move where it is at because the earth moves around the sun.

Explanation:

The size of the shadow changes as the sun changes its position.

The position of sun in the sky would change the direction of our shadow if we were to stand in the same place all day because the sun moves with the passage of time. The sun rises in the east so at that time our shadow is formed towards the west side and start decreasing when the sun reaches high in the sky.

When the sun reaches at the top of our head, then no shadow is formed and when the sun set occurs the length of the shadow again decreases so we can say that the size of the shadow changes as the sun changes its position.

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Answer:

See explanation

Explanation:

The formation of isomers is common to octahedral complexes. Isomers are different compounds with the same molecular formula but different structural formulas. Isomers have different atom to atom connections. Werner's complexes can display; polymerization, ionization, linkage, geometric and optical isomerism among others.

Isomers of coordination compounds are not easily recognizable and not easily separable in the laboratory.

The geometric, linkage and ionization isomers of the complex given in the question are shown below.

Only coniferous trees have thin, waxy, needle-like leaves that drop throughout the year and help to retain water.

Coniferous trees are evergreen trees that produce cones.

In addition, they produce waxy and needle-like leaves that help them conserve water by limiting the evapotranspiration rate as a result of reduced surface area.

Examples of conifers include pine trees and spruces.

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Answer:coniferous trees

Explanation:

Answer:

Explanation:

When you use electricity to charge your car, you can integrate renewable resources like solar into the fueling process. Without solar, your electric vehicle is still effectively running off of fossil fuels – it's just the fossil fuels utilized at the power plant and not within your engine.

Fossil fuels include substances like natural gas, coal, and oil. It is possible for electric cars to run on these fossil fuels. Fossil fuels like coal are burnt up to generate electricity. So when cars run on electricity, they are indirectly tapping into fossil fuels.

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CaBr2 is an ionic bond. This is because the calcium gives up an electron to each of the chlorine atoms resulting in the calcium becoming Ca2+ ions...

The value of the equilibrium constant, Kc, for this reaction is approximately 0.43 L/mol.

The balanced chemical equation for the reaction between ethanol and acid to form ester is:

CH₃CH₂OH + RCOOH ⇌ CH₃COOC₂H₅ + H₂O

where R represents the organic acid group.

From the given information, the initial concentration of ethanol and acid in the flask is 1.00 mol/L and 2.00 mol/L, respectively. At equilibrium, the concentration of ester is 0.86 mol/L.

The equilibrium constant expression for the reaction is:

Kc = [CH₃COOC₂H₅][H₂O]/[CH₃CH₂OH][RCOOH]

where the square brackets represent the molar concentrations of the respective species at equilibrium.

Substituting the given values, we get:

Kc = (0.86 mol/L) / (1.00 mol/L x 2.00 mol/L) = 0.43 L/mol

Therefore, the value of the equilibrium constant, Kc, is 0.43 L/mol.

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The saturation pressure of every gas in the entire volume, if somehow the gases being allowed to mix, is 2.5 atm.

In comparison to other forms of matter, like solids and liquids, vapors have a lower density. Particles have a great deal of kinetic energy yet aren't very attracted to one another, thus there is a lot of unoccupied space between them. A sampling of matter that assumes the shape of the bottle it is stored in and develops a consistent density on the inside of the container is referred to as a gas.

Pressure = 2.10 atm

Temperature = T K

Volume = 712 mL

= 0.712 L (1 mL = 0.001 L)

PV=nRT,

2.10 atm × 0.712 L = n × 0.0821 L.atm/K.mol × T K

n = 19.2232 / T moles

For Container B :

Pressure = 4.80 atm

Temperature = T

Volume = 134 mL

= 0.134 L (1 mL = 0.001 L)

= 4.80 atm × 0.134 L = n × 0.0821 L.atm/K.mol × 298 K

= n = 6.3435 / T moles

Total moles = 19.2132 / T moles + 6.3435 / T moles

= 25.5567 /T moles

Total Volume = 712 + 134 mL = 846 mL = 0.846 L

P × 0.846 L = 25.5567 /T × 0.0821 L.atm/K.mol × T

Total P = 2.5 atm

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No, the source is not usable. It is barely usable taking into account it's half life.

The period of time it takes for one-half of a radioactive isotope to decay is known as the half-life. An individual radioactive isotope's half-life is unaffected by environmental factors and is independent of the isotope's starting concentration. A substance's activity is a thermodynamic characteristic connected to its chemical potential. Chemical potentials are less practical to employ than activities, which are more closely tied to concentration measurements like partial pressures and mole fractions.

The activity is

\(\frac{dN}{dt} =\) λN

Therefore

N= \(N_{o} 2^{-\frac{t}{T_{0.5} } }\)

The amount of elapsed time since the source was created is roughly 2.5 years. Thus, we expect the current activity to be after calculating and using values,

=  3600 .

The source is barely usable.

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When we multiply a reaction by 2, we double the stoichiometric coefficients of the reactants and products.

However, the standard reduction potential (E°red) is an intensive property and remains unchanged. E°red represents the potential of a single mole of electrons transferred in the redox reaction. By doubling the reaction, we effectively double the number of moles of electrons transferred, but the potential per mole of electrons remains the same. Therefore, we do not multiply E°red by 2. It is important to note that E°red values are specific to individual half-reactions and do not depend on the overall balanced equation or the reaction stoichiometry.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{6.76 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{6.76}{6.02} \\ = 1.22923...\)

We have the final answer as

Hope this helps you

Answer:

C

Explanation:

Adding another Li will balance the equation

2LiNO3 + CaBr2 → Ca(NO3)2 + 2LiBr

Answer:

A. Convert the 200 mol of water to kilograms of water.

Explanation:

To find the molality of 10mol of NaCl in 200mol of water, convert the 200mol of water to kilograms of water.

Molality is one of the several ways of measuring concentration of a solute in a solvent;

 Molality  = \(\frac{number of moles of solute}{mass of solvent}\)

Answer:

so u can put on hot sauce to spice it up

and give it to ur teacher

It's fruitfull to add some more information and some acquired knowledge...

Hope it is helpful !

Metals :-

Group 1A - Alkali metals ( highly reactive metals)

Non-metals :-

Group 17 - Halogens ( highly reactive non-metals )

Following represents the number of Molecules of the type indicated is present as a reactant or product of the chemical reaction shown is the coefficient of the species

The number of atoms, molecules, or formula units of a reactant or product in a balanced chemical equation is the coefficient of that species then the mole ratio of two substances in a chemical reaction is the ratio of their coefficients in the balanced chemical equation and the this numbers are called as coefficient and they tell how many of each molecule are participate in the reaction

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To solve this problem, we could use the Boyle's law since there's a sample of ideal gas and temperature is constant.

Boyle's law tells us that:

Replacing the values of the problem:

The new volume V equals 5.6L.

Approximately 9 x 10^24 electrons pass through the bulb in 2 hours.

To find the number of electrons that pass through the bulb, we need to calculate the charge that flows through it. The charge of an electron is 1.6 x 10^-19 coulombs. To find the total charge that passes through the bulb, we multiply the current (0.40 A) by the time (2 h) and convert the time into seconds.

0.40 A * 2 h * (3600 s/h) = 14400 C

Now that we have the total charge that passes through the bulb, we can calculate the number of electrons by dividing the charge by the charge of an electron:

14400 C / (1.6 x 10^-19 C) = 9 x 10^24 electrons

So, approximately 9 x 10^24 electrons pass through the bulb in 2 hours. To express the answer to two significant figures, we round the answer to 9 x 10^24 to 9 x 10^22 electrons.

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Narrative form or storytelling is used to convey events, experiences, or information. In a narrative form, a single atom of Nitrogen, in the form of Nitrogen gas (N2) travels through different pools. The description of each pool it passes through as a source or a sink is given below:

In the atmosphere:Nitrogen gas is the most abundant gas in the atmosphere, it comprises about 78% of the earth's atmosphere. It is a component of many organic and inorganic compounds in the atmosphere.In the biosphere:Nitrogen-fixing bacteria or lightning can convert nitrogen gas into ammonia. This ammonia can be converted into nitrite and then nitrate through nitrification. This nitrate can be taken up by plants and utilized to make proteins and other molecules that are important for life.

Animals that consume these plants get the nitrogen that they need to build their own proteins. When an organism dies, decomposers like bacteria break down the proteins and return the nitrogen back to the soil in the form of ammonia and other organic compounds.In the atmosphere:Denitrification is the process that converts nitrate to nitrogen gas, which is then released into the atmosphere. This can be done by anaerobic bacteria and other microbes that live in soils and other places where there is little or no oxygen. Human activities that influence the movement of Nitrogen:Humans have a significant impact on the movement of nitrogen in the environment. One of the ways in which they do this is through the use of fertilizers, which contain high levels of nitrogen. These fertilizers can be washed into rivers and streams, where they can cause eutrophication.

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Answer:

If it is a pure substance is it an element or a compound? Blood is a mixture since it is made up of many different compounds and substances. Blood is a homogenous mixture since you cannot see the individual components and the components are uniformly distributed.

Explanation:

Answer(s):

Template: reactants ⇒ products

1. \(Ag+KNO_3\) ⇒ \(AgNO_3 + K\)

2. \(Zn+AgNO_3\) ⇒ \(Zn(NO_3)_2 + Ag\)

3. \(Al + H_2SO_4\) ⇒ \(Al_2(SO_4)_3 + H_2\)

4. \(Cl_2+KI\) ⇒ \(HCl + I_2\)

5. \(Li + H_2O\) ⇒ \(LiOH + H_2\)

6. \(Cu + FeSO_4\) ⇒ \(CuSO_4 + Fe\)

7. \(Na + H_2O\) ⇒ \(NaOH + H_2\)

8. \(Fe+Pb(NO_3)_2\) ⇒ \(Fe(NO_3)_2 + Pb\)

9. \(Cu+H_2O\) ⇒ \(CuO + H_2\)

10. \(Cu+Al_2(SO_4)_3\) ⇒ \(CuSO_4 + Al\)

11. \(Al + Pb(NO_3)_2\) ⇒ \(Al(NO_3)_3 + Pb\)

What is a chemical equation?

A chemical equation consists of the chemical formulas of the reactants (on the left) and the products (on the right). The two are separated by an arrow symbol (“→” usually read aloud as “yields”). Each individual substance's chemical formula is separated from others by a plus sign.

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*: (=' :') this

•.. (,('')('') helped :)

(a) The potential of hydrogen (pH) before any KOH has been added is 0.872. (b) The pH after 0.0180 L KOH has been added is 1.326. (c) The pH after 0.0360 L KOH has been added is 1.610. (d) The pH after 0.0540 L KOH has been added is 7.0.

(a) Before any KOH has been added, the pH of the hydroiodic acid solution can be calculated using the equation pH = -log[H+], where [H+] is the hydrogen ion concentration.

Since HI is a strong acid, it will dissociate completely in water to form H+ and I-. Therefore, [H+] = 0.134 M, and the pH is calculated as pH = -log(0.134) = 0.872.

(b) After 0.0180 L KOH has been added, the reaction between the acid and the base will produce water and potassium iodide (KI). The number of moles of KOH added can be calculated as follows:

moles of KOH = molarity of KOH x volume of KOH

moles of KOH = 0.268 M x 0.0180 L

moles of KOH = 0.004824

Since KOH is a strong base, it will dissociate completely in water to form K+ and OH-. The number of moles of OH- added is the same as the number of moles of KOH, which is 0.004824 moles.

The number of moles of H+ that react with the OH- can be calculated from the balanced equation:

HI + KOH → KI + H2O

1 mole of HI reacts with 1 mole of KOH to form 1 mole of water. Therefore, the number of moles of H+ that react with the OH- is also 0.004824 moles.

The new concentration of H+ can be calculated from the number of moles of H+ and the new volume of the solution:

moles of H+ = moles of HI - moles of OH-

moles of H+ = 0.134 M x 0.0720 L - 0.004824 moles

moles of H+ = 0.008688

new volume = 0.0720 L + 0.0180 L = 0.0900 L

[H+] = moles of H+ / new volume

[H+] = 0.008688 / 0.0900

[H+] = 0.09653 M

The pH can be calculated as pH = -log(0.09653) = 1.326.

(c) After 0.0360 L KOH has been added, the calculation is similar to part (b), but with a different volume of KOH added. The number of moles of KOH added is:

moles of KOH = 0.268 M x 0.0360 L

moles of KOH = 0.009648

The number of moles of OH- and H+ that react with each other are still the same as in part (b), which is 0.004824 moles.

The new volume of the solution is:

new volume = 0.0720 L + 0.0360 L = 0.1080 L

[H+] = moles of H+ / new volume

[H+] = 0.008688 / 0.1080

[H+] = 0.08044 M

The pH can be calculated as pH = -log(0.08044) = 1.610.

(d) After 0.0540 L of KOH has been added:

At this point, a total of 0.0540 L of KOH has been added to the solution, which is equal to 0.268 M x 0.0540 L = 0.0145 moles of KOH.

To determine the concentration of H+ ions remaining in the solution, we need to subtract the moles of KOH added from the initial moles of H+ ions in the solution.

Initial moles of H+ ions = 0.134 M x 0.0720 L = 0.00967 moles

Moles of H+ ions remaining = 0.00967 - 0.0145 = -0.00483

Since the moles of H+ ions remaining are negative, it means that all the H+ ions have been neutralized by the added KOH.

The solution is now a solution of KI (potassium iodide). Since KI is a salt of a strong acid (HI) and a strong base (KOH), it will not undergo hydrolysis, and its solution will be neutral.

Therefore, the pH at this point is 7.0.

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Answer:

Yes a proton affects the mass of an atom.

815 mL of this solution contains 570.5 mL of water and 244.5 mL of alcohol, respectively.

We are given a solution of alcohol that is 30.0% (v/v). This indicates that there is 30.0 mL of alcohol in 100 mL of solution.

The volume of alcohol In the 815 mL solution must now be calculated.

As 30.0 mL of alcohol is present in 100 mL of solution.

Therefore, a solution of 815 mL  \(\frac{815}{100} *30.0 = 244.5mL\) of alcohol.

Alcohol, therefore, has a capacity of 244.5 mL.

We must now determine the water’s volume.

\(The volume of water = Volume of the solution - Volume of alcohol\)

Water volume = 815 mL – 244.5 mL

Water volume = 570.5 mL

As a result, the water’s volume is 570.5 mL.

Thus, there are 570.5 mL of water and 244.5 mL of alcohol, respectively, in 815 mL of this solution.

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Answer:

220g of CO2

Explanation:

Step 1:

The balanced equation for the reaction.

2C5H11OH + 15O2 —> 10CO2 + 12H2O

Step 2:

Determination of the number of mole of CO2 produced by burning 1 mole of C5H11OH.

From the balanced equation above,

2 moles of C5H11OH produced 10 moles CO2.

Therefore, 1 mole of C5H11OH will produce = (1 x 10)/2 = 5 moles of CO2.

Therefore, 5 moles of CO2 is produced from the reaction.

Step 3:

Conversion of 5 moles of CO2 to grams.

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Number of mole of CO2 = 5 moles

Mass of CO2 =...?

Mass = mole x molar mass

Mass of CO2 = 5 x 44

Mass of CO2 = 220g.

Therefore, 220g of CO2 were obtained from the reaction.

Answer:

Complete combustion takes place in the presence of a sufficient amount of oxygen while an incomplete combustion reaction takes place when there is an insufficient amount of oxygen supply.

The equation for incomplete combustion of propane is: 2 C3H8 + 9 O2 → 4 CO2 + 2 CO + 8 H2O + Heat. If not enough oxygen is present for complete combustion, incomplete combustion occurs. The result of incomplete combustion is, once again, water vapour, carbon dioxide and heat.