Answer: The evidence described in the given statement, specifically the absence of ocean sediments at the mid-ocean ridge and the thicker sediments moving away from the ridge, supports the concept of sea-floor spreading, which is a key aspect of the plate tectonic theory.
The evidence described in the statement supports the concept of sea-floor spreading, which is a fundamental aspect of the plate tectonic theory. Sea-floor spreading is the process by which new oceanic crust is formed at mid-ocean ridges through the upwelling of molten material from the Earth's mantle, and then moves away from the ridge in opposite directions, creating a continuous process of crustal formation and spreading.
The absence of ocean sediments at the mid-ocean ridge is consistent with sea-floor spreading because the ridge is the site of crustal formation where molten material is constantly welling up and creating new oceanic crust. As the newly formed crust moves away from the ridge, it is relatively young and has not had enough time to accumulate significant amounts of sediment. This is why sediments are absent or thin at the mid-ocean ridge.
On the other hand, as the oceanic crust moves away from the ridge and gets older, it accumulates sediment from various sources, such as weathering of continents and deposition of marine organisms. This is why the sediments get thicker moving away from the ridge, as mentioned in the statement.
This evidence from sediment cores collected by the Deep Sea Drilling Project provides support for the concept of sea-floor spreading, as it confirms the pattern of sediment distribution observed in ocean basins and is consistent with the idea that new crust is constantly forming at mid-ocean ridges and spreading away from them, contributing to the overall movement of tectonic plates on the Earth's surface.
Therefore, the correct answer is A) sea-floor spreading.
Hydropower is the production of electrical energy through the use of
A. gravitational force
B. stored energy
C. water flowing upwards
D. water resistance
Answer:
gravitational force .. .. .
Explanation:
hope it helps^o^An electronic device has a resistance of 20 ohms and a current of 15 A. What is the voltage across the device ?
Question :-
An Electronic Device has a Resistance of 20 Ohm's and a Current of 15 Ampere . What is the Voltage across the Device ?Answer :-
Voltage of the Device is 300 Volt's .\( \rule {180pt}{2pt} \)
Given :-
Resistance = 20 Ohm'sCurrent = 15 AmpereTo Find :-
Voltage = ?Solution :-
As per the provided information in the given question, we have been given that the Resistance of the Device is 20 Ohm's. It's Current is given as 15 Ampere . And, we have been asked to calculate the Voltage .
For calculating the Voltage , we will use the Formula :-
\( \bigstar \: \: \: \boxed {\sf { \: Voltage \: = \: Current \: \times \: Resistance \: }} \)
Therefore , by Substituting the given values in the above Formula :-
\( \Longrightarrow \: \: \: \sf { Voltage \: = \: Current \: \times \: Resistance } \)
\( \Longrightarrow \: \: \: \sf { Voltage \: = \: 15 \: \times \: 20 } \)
\( \Longrightarrow \: \: \: \bf { Voltage \: = \: 300 } \)
Hence :-
Voltage of Device = 300 Volt's .\( \underline {\rule {180pt}{4pt}} \)
Additional Information :-
\( \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} \)
\( \Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance}} \)
\( \Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } \)
Answer:
300 volts
Explanation:
now in this question we have been given our resistance which is 20 ohms and our current which is 15A
using ohm's law
V=IR
where v is voltage, I is current and r is resistance
now substitute,
V=15 x 20
V=300
I hope I helped
assuming the atmospheric pressure to be constant at 101,325 pa, by what amount does the volume of the balloon change?
The volume of the balloon is increased to 2.9 L.
Initial volume of the balloon, V₁ = 0.5 L
Initial temperature of the balloon, T₁ = 20°C = 293 K
Final temperature, T₂ = 150°C = 423 K
According to Charle's law,
V₁/T₁ = V₂/T₂
The final volume,
V₂ = (V₁/T₁)T₂
V₂ = 0.5 x 423/293
V₂ = 2.9 L
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Your question was incomplete, but most probably your question will be:
A balloon has a volume of 0.5 L at 20°C. If the balloon is heated to 150°C, assuming the atmospheric pressure to be constant at 101,325 pa, by what amount does the volume of the balloon change?
Determine the cross-sectional area and length of an aluminum wire if its resistance is 0.1 ohm and its mass is 54 g. (Resistivity of Aluminum=1.7*10^-8 Ohm*m)
An aluminium wire's cross-sectional area is\(A = 3.1 * 10^{-5} m^{2}\), and its length is L = 0.17 m.
The resistance of an aluminum wire is given by the formula:
\(R = \frac{\rho L}{A}\)
Where R = resistance, ρ = resistivity of aluminum, L = length of wire, and A = cross-sectional area of wire.
So that we can solve for A, we can rearrange the equations as follows
\(A =\frac{ \rho L}{R}\)
Plugging in the given values, we have:
\(A =\frac{ (1.7 * 10^{-8} Ohm*m)(L)}{(0.1 Ohm)}\)
Solving for L,
\(L = \frac{(0.1 Ohm)(A)}{(1.7 * 10^{-8} Ohm*m)}\)
We also know that the mass of the aluminum wire is 54 g. The following formula determines a wire's mass:
\(m = \rho AL\)
In order to find A, we can rearrange the equation as follows:
\(A = \frac{m}{(\rho L)}\)
Plugging in the given values, we have:
\(A =\frac{ (54 g)}{((1.7 *10^{-8} Ohm*m)(L))}\\A = 3.1 * 10^{-5} m^{2}\)
Combining the two equations, we obtain:
\(L =\frac{ (54g)(0.1 Ohm)}{((1.7 * 10^{-8} Ohm*m)(A))}\)
L = 0.17 m
Therefore, the cross-sectional area is \(A = 3.1 * 10^{-5} m^{2}\) and L = 0.17 m is the length of an aluminium wire.
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Which two complementary forces keep the sun from blowing itself up?.
The two complementary forces that keep the sun from blowing itself up are gravity and nuclear fusion.
Gravity is the force that exists between any two masses, any two bodies, any two particles. It is the force that attracts a body towards the center of the Earth, or towards any other physical body with mass.
Nuclear fusion is the process by which two atomic nuclei join together to form a heavier nucleus. This process releases energy, as per the famous equation,
E = mc²,
where E is the energy released, m is the mass that gets converted to energy, and c is the speed of light. The sun and other stars release energy through nuclear fusion.
What is the role of gravity in keeping the sun from blowing itself up?Gravity is the force that attracts all the particles of matter together in the sun's core. It keeps the nuclear fuel together and squeezes the matter so tightly that the temperature and pressure in the core are sufficient to make nuclear fusion reactions occur.
What is the role of nuclear fusion in keeping the sun from blowing itself up?The energy released during nuclear fusion reactions in the sun's core is what keeps the sun shining and stable. The outward pressure from the energy released in nuclear fusion is balanced by the inward force of gravity. The sun stays in a stable equilibrium state where these two forces are balanced, preventing it from blowing itself apart.
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a model house that runs completely on renewable energy uses 2 windmills and 3 solar panels. each windmill generates mmm kilowatt-hours (kwh) of energy per year, and each solar panel generates sss kwh per year. which expressions can we use to describe how many kwh of energy the model house will output in 10 years? choose 2 answers: choose 2 answers:
The model house on remote renewable energy will generate (20mmm + 30sss) kilowatt-hours of energy in 10 years.
Given:
Remote Renewable House= 2 windmills + 3 turbines
1 windmill generate mmm kilowatts-hours in a year
Therefore,
2 windmills will generate,
2×mmm=2mmm kwh in a year
In 10 years, 2 windmills will generate
10×2mmm=20mmm
1 solar panel generate sss kilowatt-hour each in 1 year
3 solar panels will generate yearly
3×sss=3sss
In 10 years, 3 solar panels will generate
10×3sss=30sss
Therefore, the total energy generated in the renewable model house is in 10 years
(20mmm+30sss) kwhr
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what would the wind speeds at a be if the hurricane is moving due east at a speed of 40 km/hr and the average wind speed of the hurricane was 215 km/hr?
The wind speed would be 255km/hr if the hurricane is moving east due east at a speed of 40 km/hr and the average wind speed of hurricane was 215 km/hr.
We must determine the localized wind speed at Point A because it is the end of the storm and has the highest velocity.
Speed at point A equals the combined speeds of the hurricane and the forward motion since point A is situated in the same rotational direction as the cyclone.
speed at point A = speed of hurricane + speed of forward
= 215 + 40 = 255km/hr
What does a hurricane mean in simple terms?
A hurricane is defined as a tropical storm with sustained winds of 74 mph or more. A storm's eye typically measures 20 to 30 miles in width and can reach distances of 400 miles. Storms may be dangerous because of their heavy downpours, strong gusts, and storm surges.
Where do storms usually begin?
Near the tropics, in the Caribbean, or in the waters around the Cape Verdean islands of West Africa, hurricanes start to form. Surface water that is relatively warm quickly evaporates before condensing to create clouds in the sky. When moist air rises to the point of saturation, a tropical depression—a kind of meteorological system—is created.
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A 70kg man runs at a pace of 4 m/s and a 50g meteor travels at 2 km/s. Which has the most kinetic energy?.
Answer:
the 70kg man
Explanation:
because he has more weight and is moving faster
suppose that an accelerating car goes from 0 mph to 60.0 mph in five seconds. its velocity is given in the following table, converted from miles per hour to feet per second, so that all time measurements are in seconds. (note: 1 mph is 22/15 ft/sec.) find the average acceleration of the car over each of the first two seconds.
The average acceleration of a car which goes from 0 to 60 mph in first second would be 30 and over 2 seconds is 22.
Since the Average acceleration from \(t + h\) is given
\(A_{vg} =\frac{v(t+h)-v(t)}{h}\) ; \(h\) ≠ \(0\)
The average acceleration for the first second would be
\(a_{avg} = \frac{v(0+1)-v(0)}{1} \\= {v(1)-v(0)\\\\\)
=30-0
=30
The average acceleration over \(2\) seconds is:
\(a_{avg} =\frac{v(1+1)-v(1)}{1} \\=v(2)-v(1)\\\)
= 52-30
=22
What is acceleration?Acceleration is defined as the change in object velocity over time. Acceleration is a vector term and requires both magnitude and direction to define it. Units of acceleration are m/sec², miles/sec², etc.
In a velocity versus time graph, acceleration is the slope of the curve.
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A proton with a kinetic energy of 4.9×10−16 J moves perpendicular to a magnetic field of 0.37 T . Part A What is the radius of its circular path? r=cm Express your answer using two significant figures.
After performing the calculations, the radius of the proton's circular path is approximately 0.18 cm when rounded to two significant figures.
The radius of the circular path followed by a proton moving perpendicular to a magnetic field can be determined using the formula:
r = (m*v) / (q*B)
where r represents the radius, m is the mass of the proton, v is its velocity, q is the charge of the proton, and B is the magnetic field strength.
Given:
Kinetic energy of the proton = 4.9×10^(-16) J
Magnetic field strength = 0.37 T (Tesla)
To find the velocity of the proton, we can use the formula for kinetic energy:
K.E. = (1/2) * m * v^2
Rearranging the equation to solve for v:
v = √((2 * K.E.) / m)
The mass of a proton (m) is approximately 1.67 × 10^(-27) kg, and the charge (q) of a proton is 1.6 × 10^(-19) C.
Now, substituting the given values into the equation for the radius:
r = ((1.67 × 10^(-27) kg) * √((2 * 4.9×10^(-16) J) / (1.6 × 10^(-19) C))) / (0.37 T)
Evaluating this expression gives us the radius of the proton's circular path.
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You are dating rocks by their proportions of parent isotope potassium-40 (half-life 1.25 billion years) and daughter isotope argon-40. Find the age for each of the following.A rock that contains seven times as much argon-40 as potassium-40.Express your answer using three significant figures.
The age of the rock is 3.512 billion years.
What are 3 types of rocks?
1. Igneous rocks
2. Sedimentary rocks
3. Metamorphic rocks
For the first rock, the number of potassium-40 atoms is equal to the number of argon-40 atoms. That can only happen when when one half life cycle has elapsed. Therefore the age of this rock is indeed 1.25×109 years. Now let us calculate the age of the second rock sample. Let us say that the number of potassium-40 at the beginning was N0 and the number of potassium-40 after a particular time t us N. There after 1.25 billion years, N= N0 /2. Now we know the decay constant. This means that every second,5.54×10-10 atoms of potassium-40 decay into argon-40. We can use this decay constant to calculate the time required for the number of argon-40 to be 7 times as much as potassium-40. We want the time required to get the condition N = N0/7. So the correct answer is 3.512 billion years.
Therefore, the age of the rock is 3.512 billion years.
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The age of the rock is approximately 42 million years, calculated using the equation (7/8) = (1 - \(e^{-kt}\) ) with k = ln(2)/1.25 billion years and solving for t.
What is the dating of rock?
The dating of rocks refers to the process of determining the age of rocks or geological events using various techniques, such as radiometric dating, relative dating, and stratigraphy. Radiometric dating involves measuring the ratio of parent and daughter isotopes in a rock, while relative dating involves determining the order of events in geological history. Stratigraphy involves analyzing the layers of sedimentary rocks to determine the relative age of the rocks and the events they represent. These techniques are used by geologists to study the history of the Earth and the processes that have shaped it over time.
The ratio of argon-40 to potassium-40 in a rock can be used to determine the age of the rock based on the half-life of potassium-40. The equation for the decay of potassium-40 to argon-40 is:
K-40 --> Ar-40 + e-
where e- represents an electron and a neutrino.
The half-life of potassium-40 is 1.25 billion years, which means that half of the original amount of potassium-40 will decay to argon-40 in 1.25 billion years. After another 1.25 billion years, half of the remaining potassium-40 will decay, and so on.
If a rock contains seven times as much argon-40 as potassium-40, that means the ratio of argon-40 to potassium-40 is 7:1. We can set up the following equation to solve for the age of the rock:
(7/8) = (1 - \(e^{-kt}\))
where k is the decay constant for potassium-40, t is the age of the rock, and e is the mathematical constant approximately equal to 2.71828.
The decay constant for potassium-40 can be calculated using the following formula:
k = ln(2)/t1/2
where ln represents the natural logarithm and t1/2 is the half-life of potassium-40.
Plugging in the values, we get:
k = ln(2)/1.25 billion years = 0.00055 \(years^{-1}\)
Substituting k into the first equation and solving for t, we get:
t = -ln(7/8)/0.00055 \(years^{-1}\) = 42 million years
Therefore, the age of the rock is approximately 42 million years.
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How fast is the van traveling relative to the ground
Answer:
5238747643782 mph
Explanation:
i assure u it is
Question 10 of 34
Julia walks from the park 6 blocks east of her house to the store 3 blocks
east of her house. The walk takes Julia 5 minutes. What is her average
velocity on this walk?
OA. 0.6 blocks/min east
OB. 1.2 blocks/min
O C. 1.8 blocks/min
OD. 0.6 blocks/min west
Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.
What is displacement?Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.
Displacement is a vector quantity .its unit is m.
The average velocity on this walk will be;
\(\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4 \ block /min\)
Hence option B is correct.
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if the mass of the child and sled is 38 kg , what is the magnitude of the average force you need to apply to stop the sled? use the concepts of impulse and momentum.
The magnitude of the average force is 101.33N.
Here we have to find the magnitude of the average force.
The given data:
Initial velocity(u) = 1.6m/s
Mass of the child and sled = 38 kg
Time taken = 0.60s
Formula to find the impulse:
Impulse = change in momentum
We have final velocity (v) = 0
Ft = m(v - u)
F = m(v-u)/t
F = -38 × 1.6/ 0.6
= -101.33N
Therefore we get an average force is 101.33N.
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What is the value of a in the function’s equation?
A.
3
B.
-2
C.
2
D.
-3
Answer:
Explanation:
What is the value of a in the function's equation?
A. -2
B. -3
C. 3
D. 2
ANSWER: c.
Help please 20 points ? ASAP
Answer:
21: Mass
22: Unbalanced Force
23: Friction
24: Balanced
Explanation:
when astronomers measure the mass of the galaxy triangulum using the brightness method the result they get is much less than when they measure the mass using the orbital method. why?
The discrepancy between the brightness method and the orbital method in measuring the mass of the Triangulum galaxy arises due to the presence of dark matter.
The brightness method calculates a galaxy's mass based on the observed luminosity, assuming that the mass is proportional to the amount of visible light emitted. On the other hand, the orbital method calculates mass by observing the motion of stars and other objects within the galaxy, relying on the gravitational forces acting upon them.
The reason for the discrepancy between the two methods is the presence of dark matter, an invisible substance that does not emit, absorb, or reflect light, but exerts gravitational influence. Since the brightness method only accounts for visible matter, it tends to underestimate the galaxy's mass compared to the orbital method, which considers both visible and dark matter in its calculation.
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If a swimming pool has a circumference of 25.12 m, what is its radius?
ANSWER
4 m
EXPLANATION
The circumference formula is,
\(C=2\pi r\)Where r is the radius of the circle.
Solving for r,
\(r=\frac{C}{2\pi}\)The circumference of the swimming pool is 25.12m. If we use 3.14 for π,
\(r=\frac{25.12m}{2\cdot3.14}=\frac{25.12m}{6.28}=4m\)The radius of the swimming pool is 4 m.
2
A simple circuit contains a battery and a resistor.
Over 3.0 hours, 29 000 C of charge passes through the resistor.
Calculate the current flowing through the circuit during this time.
Give your answer to two significant figures.
Answer:
Approximately \(2.69\; {\rm A}\).
Explanation:
Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:
\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).
Electric current \(I\) is the rate of flow of electric charge.
In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:
\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).
Which is an example of
kinetic energy?
A. An apple falling from a tree
B. A book sitting on a table
C. A plate of hot food
D. A parked car
Answer:
A. an apple falling from a tree
Explanation:
What is reflection very short answer?
When a shaft of light approaches a smooth polished face and the light shaft bounces back, it's called the reflection of light. The incident light shaft which lands upon the face is said to be reflected off the face. The shaft that bounces back is called the reflected shaft.
When light is reflected on a aeroplane face the angle of reflection is equal to the angle of prevalence i.e. θr = θi.
Angle of prevalence is the angle between the incident shaft and the reflecting face.
Angle of reflection
This is the angle between the reflected shaft and the normal shaft on a reflecting face.
Angle of reflection is analogous to angle of prevalence.
Thus, the reflection of light is the shaft that hits the face and reflects back to the atmosphere.
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Use Wien's law and a sunspot temperature of 3800 K to calculate the wavelength of peak thermal emission from a sunspot. Express your answer to three significant figures and include the appropriate units.
The wavelength of peak thermal emission from a sunspot can be calculated using Wien's law and a sunspot temperature of 3800 K.
Wien's Law states that the wavelength of peak thermal emission is inversely proportional to the temperature of the body emitting radiation. It is given by:
λ_max = b/T
where b is the Wien constant, 2.898 x 10^-3 m K, and T is the temperature of the emitting body. Substituting the given values into the equation,λ_max = b/Tλ_max = (2.898 x 10^-3 m K)/(3800 K)λ_max = 7.63 x 10^-7 m
The answer is expressed to three significant figures as 7.63 x 10^-7 m, with units of meters. Therefore, the wavelength of peak thermal emission from a sunspot is 7.63 x 10^-7 m.
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Identify by letters (A-E) in which section the following are found if in an energy curve worksheet A is solid, B is solid to liquid C is liquid, D. Is liquid to gas and E is gas.
1. Solid getting warmer
2. Liquid getting warmer
3. Gas getting warmer
4. Freezing/ Solidifying
5. Melting/ Liquefying
6. Boiling point
7. Boiling (Vaporization)
8. Particles farthest apart
9. Weakest IMF (intramolecular force)
10. Particles are rigid & compressed
1 1. Particles closest together
All particles able to move past each other in fluid motion
Condensation occurs
Strongest IMF
Particle motion is stationary
16- Particles are most chaotic and disordered. Have the most entropy
Respective sections (A-E) in an energy curve worksheet for the given terms: 1) A (solid), 2 )B (solid to liquid), 3) E (gas), 4) B (solid to liquid), 5) B (solid to liquid), 6) C (liquid), 7) D (liquid to gas), 8) E (gas), 9) E (gas), 10) A (solid), 11) A (solid)
The following are the respective sections (A-E) in an energy curve worksheet for the given terms:
1. Solid getting warmer: A (solid).
2. Liquid getting warmer: B (solid to liquid).
3. Gas getting warmer: E (gas).
4. Freezing/ Solidifying: B (solid to liquid).
5. Melting/ Liquefying: B (solid to liquid).
6. Boiling point: C (liquid).
7. Boiling (Vaporization): D (liquid to gas).
8. Particles farthest apart: E (gas).
9. Weakest IMF (intramolecular force): E (gas).
10. Particles are rigid & compressed: A (solid).
11. Particles closest together: A (solid).
All particles able to move past each other in fluid motion: C (liquid).Condensation occurs: D (liquid to gas).Strongest IMF: A (solid).Particle motion is stationary: A (solid).Particles are most chaotic and disordered. Have the most entropy: E (gas).
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What is the multiplier and the liquidity trap and how do they
work?What is the multiplier and the liquidity trap and how do they
work?
The multiplier and the liquidity trap are concepts in economics that relate to the relationship between changes in aggregate demand and the overall level of economic activity.
The multiplier refers to the idea that an initial change in spending, investment, or government expenditure can have a magnified effect on the economy's output.
When there is an increase in spending, for example, households or businesses that receive the additional income will in turn spend some of it, creating a ripple effect of increased demand.
This increase in demand leads to increased production and employment, resulting in further income and spending. The multiplier effect stems from the fact that each round of spending generates additional rounds of spending, amplifying the initial impact on the economy.
On the other hand, the liquidity trap refers to a situation in which monetary policy becomes ineffective in stimulating the economy. It occurs when interest rates are extremely low, close to zero, and individuals and businesses prefer to hold on to cash rather than invest or spend.
In a liquidity trap, people are unwilling to borrow or invest because they expect further deflation or economic instability. Consequently, the central bank's attempts to stimulate the economy through lowering interest rates or increasing the money supply have limited impact since they cannot further incentivize borrowing and spending.
The liquidity trap can be problematic because it hinders the effectiveness of conventional monetary policy tools and limits the ability of the central bank to stimulate economic activity. In such situations, unconventional policies like quantitative easing or fiscal stimulus may be necessary to boost aggregate demand and overcome the liquidity trap.
Overall, the multiplier highlights the potential for a positive feedback loop in the economy, while the liquidity trap demonstrates the challenges faced when monetary policy loses its effectiveness.
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If the total volume of a simple cubic unit cell is 6. 817×10-23 cm3 , what is the volume occupied by particles in unit cell?
0.8521 × 10⁻²³ cm³ is the volume occupied by particles in unit cell. A unit cell refers to the smallest repeating unit in a crystal lattice that can be used to build up the entire crystal structure.
In a simple cubic unit cell, particles occupy only the corners of the cube, and each corner is shared by 8 unit cells. Therefore, the volume occupied by each particle in the unit cell is given by:
Volume of each particle = 1/8 * Volume of the unit cell
Substituting the given value of the volume of the unit cell:
Volume of each particle = 1/8 * 6.817 × 10⁻²³ cm³
Volume of each particle = 0.8521 × 10⁻²³ cm³
Therefore, the volume occupied by each particle in the unit cell is 0.8521 × 10^-23 cm³.
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F= 10k F2 12k F3 = 18k Problems analytical solutions using force components. check graphically 2.9 three members of a truss frame into a steel gusset plate as shown. all forces are concurrent at point o. determine the resultant of the three forces that must be carried by the gusset plate.
The resultant of the three forces that must be carried by the gusset plate is 22.14k
The resultant itself means total or amount. So, it can be said that the resultant force is the total or overall force acting on a system. The resultant force is a vector quantity.
F₁
sin 30° = x₁/10k
x₁ = 10 × sin 30° × k
x₁ = 5k
Similarly:
y₁ = 10k × cos30°
y₁ = 10k × 0.866
y₁ = 8.66k
F₂
The angle at F₂ is 0 degrees θ = 0°
So:
x₂ = -12k
y₂ = 0
F₃
cos 45° = x₃/18k
x₃ = 18 × cos 45° × k
x₃ = 12.728 k
Similarly:
y₃ = 18k × sin 45°
y₃ = 18k × 0.707
y₃ = 12.728 k
Resultant of x:
x = x₁ - x₂ + x₃
x = 5k -12 k + 12.728 k
x = 5.726 k
Resultant of y:
y = y₁ - y₂ + y₃
y = 8.66k - 0k + 12.728 k
y = 21.388k
Resultant F:
F = \(\sqrt{x^2 + y^2}\)
F = \(\sqrt{ 5.726^2 + 21.388^2 }\)
F = \(\sqrt{ 32.787+ 457.446 }\)
F = \(\sqrt{ 490.233 }\)
F = 22.14k
So, the resultant of the three forces is 22.14k
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What name is given to the force on an object caused by Earth's gravitational pull?
Answer:
gravity
Explanation:
Size of the Milky Way The speed of light is about 186,000 miles per second. The Milky Way galaxy has an approximate diameter of 6×10¹⁷ miles. Estimate, to the nearest thousand, the number of years it takes for light to travel across the Milky Way. (Source: C. Ronan, The Natural History of the Universe.)
The time it takes for light to travel across the Milky Way galaxy is approximately 102,000 years (to the nearest thousand)
The speed of light is 186,000 miles per second. The Milky Way galaxy has an approximate diameter of 6 × 10¹⁷ miles. Therefore, we can estimate the time it takes for light to travel across the Milky Way by dividing the distance by the speed of light. Using this formula, we can say that:
Time taken for light to travel across the Milky Way galaxy= 6 × 10¹⁷ miles/186,000 miles per second= 3.23 × 10¹² seconds.1 year has 365.25 days, and each day has 24 hours, each hour has 60 minutes and each minute has 60 seconds.
So the number of seconds in one year = 365.25 days × 24 hours × 60 minutes × 60 seconds= 31,536,000 seconds.
Therefore, we can determine the time it takes for light to travel across the Milky Way in years by dividing the time taken by the number of seconds in a year, as follows:
3.23 × 10¹² seconds/31,536,000 seconds per year= 1.02 × 10⁵ years.
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A rock, of mass 970-g rock is tied securely to the end of a string and whirled in a horizontal circle of radius 1.8-in. 1 Review If the breaking strength of the string is 150 N , what's the minimum angle the string can make with the horizontal? Express your answer using two significant figures. View Available Hint(s) IVO ADD O 2 ? Submit Part B At this minimum angle, what's the rock's speed? Express your answer to two significant figures and include the appropriate units. View Available Hint(s) Value Units Doomoon
Minimum angle: θ ≈ 23.2 degrees | Rock's speed: v ≈ 2.65 m/s
What is the minimum angle the string can make with the horizontal, and what is the rock's speed at that minimum angle?To determine the minimum angle the string can make with the horizontal, we can analyze the forces acting on the rock when it is whirled in a horizontal circle.
Minimum angle:
The tension in the string provides the centripetal force required to keep the rock moving in a circle. The maximum tension the string can withstand before breaking is given as 150 N. At the minimum angle, the tension in the string will be equal to the breaking strength.
The centripetal force is given by the equation: \(F = m * (v^2 / r),\)where F is the force, m is the mass, v is the velocity, and r is the radius of the circle.
At the minimum angle, the tension (F) in the string is equal to the breaking strength, which is 150 N. The mass (m) of the rock is given as 970 g (0.97 kg), and the radius (r) is 1.8 in (0.04572 m). We can solve for the velocity (v).
\(150 N = 0.97 kg * (v^2 / 0.04572 m)v^2 = (150 N * 0.04572 m) / 0.97 kgv^2 = 7.0456 m^2/s^2v = √(7.0456) m/sv ≈ 2.65 m/s\)
Now, we can use trigonometry to find the minimum angle. The tension (150 N) is the vertical component of the tension force, and the horizontal component can be calculated using the angle θ:
Tension (horizontal component) = Tension (vertical component) / tan(θ)
Tension (horizontal component) = 150 N / tan(θ)
Since the tension in the horizontal direction is equal to the centripetal force, we can substitute the centripetal force equation:
\(m * (v^2 / r) = 150 N / tan(θ)\)
Now we can solve for the minimum angle (θ):
\(tan(θ) = (m * v^2) / (r * 150 N)θ = arctan((m * v^2) / (r * 150 N))\)
Substituting the given values, we can calculate the minimum angle.
Rock's speed at the minimum angle:
At the minimum angle, the rock's speed can be calculated using the previously derived velocity value (v).
The rock's speed at the minimum angle is approximately 2.65 m/s.
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pts
You walk 10 meters east, then 5 meters north. What is your displacement?