Apply concepts why can light travel trough outer space but sound cannot?

Complete Question:

The momentum of an object is determined to be 7.2 × 10-3 kg⋅m/s. Express this quantity as provided or use any equivalent unit. (Note: 1 kg = 1000 g).

Answer:

7.2 gm/s.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

\( Momentum = mass * velocity \)

Given the following data;

Momentum = 7.2 * 10^-3 kgm/s

1 kg = 1000 g

Substituting the unit in kilograms with grams, we have;

Momentum = 7.2 * 10^-3 * 1000 gm/s

Momentum = 7.2 gm/s.

Scientific investigation asks about a cause-and-effect relationship between two variables. Thus, the correct answer is (a).

Scientific investigation is intended to create a hypothesis and demonstrate its validity or lack thereof. Experiments must be conducted in order to test these hypotheses, and these experiments are planned in accordance with the discovery of a cause-and-effect relationship between the two variables under scientific investigation. In these experiments, the "cause" is variable upto various degrees, and the "effect" of the variance is noted. The experimental design, which will try to manipulate the causes to see how these manipulations impact the second variable, will thus be guided by knowledge of the cause-and-effect connection.

Observations are frequently the first step in a scientific investigation.

An observation is something that is discovered using the senses of humans or tools and measurement technologies that support the senses of humans. Important scientific discoveries may result from unintentional observations.

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Answer:

5km/h

Explanation:

distance divided by total time

The first line in the Lyman series, corresponding to the transition from an excited state to the ground state in hydrogen, is in the ultraviolet (UV) range with a wavelength of approximately 121.48 nm.

The Lyman series refers to a set of spectral lines in the emission spectrum of hydrogen. The first line in the Lyman series corresponds to the transition from an excited state to the ground state in the hydrogen atom. To calculate the wavelength of this line, we can use the Rydberg formula:

1/λ = R_H * (1/n_f² - 1/n_i²)

where λ is the wavelength of the spectral line, R_H is the Rydberg constant for hydrogen (approximately 1.097 × 10⁷ m⁻¹), n_f is the final energy level (which is the ground state, n_f = 1), and n_i is the initial energy level (corresponding to the excited state).

Since we want to determine if the first line in the Lyman series is ultraviolet (UV) radiation, we need to check if the calculated wavelength falls within the UV range (typically defined as wavelengths between 10 nm and 400 nm).

Let's assume that the initial energy level is n_i = 2 (corresponding to the transition from the second energy level to the ground state). Plugging the values into the Rydberg formula, we get:

1/λ = 1.097 × 10⁷ m⁻¹ * (1/1² - 1/2²)

= 1.097 × 10⁷ m⁻¹ * (1 - 1/4)

= 1.097 × 10⁷ m⁻¹ * (3/4)

= 8.2275 × 10⁶ m⁻¹

To convert this value to nanometers (nm), we can use the conversion factor 1 m = 10⁹ nm:

λ = 1/(8.2275 × 10⁶ m⁻¹)

= 1.2148 × 10⁻⁷ m

= 121.48 nm

Hence, Since the calculated wavelength of the first line in the Lyman series is approximately 121.48 nm, we can conclude that it falls within the ultraviolet (UV) range.

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Answer:

Solid objects will deform when adequate loads are applied to them; if the material is elastic, the object will return to its initial shape and size after removal. This is in contrast to plasticity, in which the object fails to do so and instead remains in its deformed state.

Explanation:

Answer:

It is false

Explanation:

because when it like a rolling ball it can deform no matter what unlesss you throw it at the ground really hard then it breaks but a soft or sometimes metal yeah it can deform but not all things solid deform.

Answer:

b. an electric current is used to turn the pointer of a galvanometer

Explanation:

well , galvanometer is an important device which is used to detect an electric current through a conductor or circuit.

something special about it is that it can detect very minute current too

Answer:

b

Explanation:

Answer:

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass. Mass is the measure of the amount of matter in a body. ... Weight usually is denoted by W. Weight is mass multiplied by the acceleration of gravity.

Answer:

mass is present in the substance and weight is the force exerted by gravity

In the case of a 9.0-cm-long spring attached to the ceiling, the spring constant is 207.1. The spring can be stretched to a height of 15 cm by hanging a 1.9 kilogram mass from it.

The "spring constant," or "k," is a quantity that effectively indicates how "stiff" a spring is. It is represented by the letter "k." A greater value of k indicates that more pressure is necessary t extend it a given distance than would be necessary to stretch a spring with a lower stiffness a similar distance.

F = mg

k = ( 1.9) (9.81) = 18.639N

F/x =18.639 /0.09 =207.1.  N/meter

F = -kx. The spring constant, k, is a proportional constant. It gauges how firm the spring is. When a spring is compressed or extended to a length that differs by an amount x out of its equilibrium length, it produces a force F = -kx that pushes it back towards its equilibrium position.

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The correct question is

A 9.0-cm-long spring is attached to the ceiling. when a 1.9 kg mass is hung from it, the spring stretches to a length of 15 cm . you may want to review ( pages 219 - 221) . part a what is the spring constant k?

Answer:

if you cut a bar of gold over and over it would result to an atom.

because an atom is the smallest particle of an element that can exist.

I hope this helps

Given data,

Mass of the bus is m = 9800 kg,

Speed of the bus is v = 40 mph,

Converting speed of the bus in m/s, {1 miles per hour = 0.447 meter per second}

v = 40*0.447

v = 17.88

Calculating momentum of the bus,

Answer:

A thermistor is an electrical device, a thermally sensitive semiconductor resistor, whose resistance changes in response to temperature. Thermistors are made in a variety of ways including thin films (SiC).

Explanation:

hope it helps

Answer:

d

Explanation:

Answer:

D. A snowball grows as more snow sticks to it.

Explanation:

When a star is born, it’s fairly small. However, the stars gravitational pull brings more things (for lack of better term) into it therefore increases it’s size as a snowball would as more things (again, no better term) stick to it.

Hope this helps, it was a pleasure to make your acquaintance.

The engine of an aircraft propeller delivers an amount of power 171 hp to the propeller at a rotational velocity of 2410 rev/min. This is a false statement.

Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.

With out knowing mass of the propeller, it can't be concluded about its  rotational velocity - no mater how much power is applied on it.

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To determine the initial speed of the car before it ran out of gasoline, we can use the principles of projectile motion and energy conservation.

Given:

Distance traveled before the car stops (d) = 141 m

Angle of the incline (θ) = 10.0°

Acceleration due to gravity (g) = 9.8 m/s²

We can break down the motion into horizontal and vertical components.

In the horizontal direction:

The car experiences no horizontal acceleration since it is coasting. Therefore, the horizontal component of velocity (Vx) remains constant throughout the motion.

In the vertical direction:

The car experiences vertical acceleration due to gravity. The initial vertical component of velocity (Vy0) can be determined using the following equation:

Vy0 = V0 * sin(θ)

where V0 is the initial speed of the car.

We can now use the horizontal and vertical motion equations to find V0.

In the horizontal direction:

d = Vx * t

In the vertical direction:

d = (1/2) * g * t²

Since the time (t) is the same in both equations, we can equate the two expressions for d:

Vx * t = (1/2) * g * t²

Vx = (1/2) * g * t

Using the equation for Vy0:

Vy0 = V0 * sin(θ)

Now we can substitute the expressions for Vx and Vy0 to solve for V0:

V0 * sin(θ) = (1/2) * g * t

V0 = (1/2) * g * t / sin(θ)

We know that sin(θ) = sin(10.0°) and we can calculate the time (t) using the equation for d in the horizontal direction:

t = d / Vx

t = 141 m / Vx

Substituting this value of t into the expression for V0:

V0 = (1/2) * g * (141 m / Vx) / sin(10.0°)

Now we need to determine Vx. Since the car is coasting, the horizontal component of velocity (Vx) remains constant, and we assume it is equal to the initial speed (V0).

Substituting Vx = V0:

V0 = (1/2) * g * (141 m / V0) / sin(10.0°)

To solve for V0, we can simplify the equation:

2 * V0 * sin(10.0°) = g * (141 m / V0)

2 * V0² * sin(10.0°) = g * 141 m

V0² = (g * 141 m) / (2 * sin(10.0°))

V0 = √((g * 141 m) / (2 * sin(10.0°)))

Now we can plug in the values to calculate V0:

V0 = √((9.8 m/s² * 141 m) / (2 * sin(10.0°)))

V0 ≈ 17.8 m/s

Therefore, the initial speed of the car before it ran out of gasoline was approximately 17.8 m/s.

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One crucial assertion—that this gas is ideal—must be made in order to overcome this problem. The ideal gas equation, which is written as PV = nRT, can then be used. The ratio of T and P is equal to some constant at a constant volume and number of moles of the gas. The constant remains unchanged under a different set of circumstances.

T1/P1 = T2/P2 P2 = T2 x P1 / T1, where P2 is equal to 311 K (1 atm) / 273 K P2, or 1.14 atm.

As a result, the pressure rose to 1.14 atm as a result of the temperature increase from 273 K to 311 K at a constant volume.

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the force required of the quadriceps to maintain the leg in a horizontal position is 896 N.

In order to maintain the leg in a horizontal position, the force exerted by the quadriceps must be equal and opposite to the force exerted by the weight on the ankle.

To determine the force required of the quadriceps, we can use the principles of torque and moment arm.

First, we need to calculate the moment arm of the weight. The moment arm is the perpendicular distance between the weight and the joint center.

The moment arm of the weight = 28 cm

Next, we need to calculate the moment arm of the quadriceps. The moment arm of the quadriceps is the perpendicular distance between the line of action of the quadriceps force and the joint center.

We know that the quadriceps tendon attaches to the tibia at a 30 degree angle 5 cm from the joint center. Using trigonometry, we can calculate the moment arm of the quadriceps:

Sin 30 = opposite/hypotenuse
Opposite = Sin 30 x hypotenuse
Opposite = 0.5 x 5
Opposite = 2.5 cm

Therefore, the moment arm of the quadriceps = 2.5 cm

Now we can use the equation for torque:

Torque = force x moment arm

We know that the torque of the weight = torque of the quadriceps (since the leg is in equilibrium).

Torque of the weight = 80 N x 0.28 m = 22.4 Nm

Torque of the quadriceps = force x 0.025 m (converting 2.5 cm to meters)

Setting the torques equal to each other and solving for force:

Force x 0.025 m = 22.4 Nm

Force = 22.4 Nm / 0.025 m

Force = 896 N

Therefore, the force required of the quadriceps to maintain the leg in a horizontal position is 896 N.

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The ratio of (ε true/ε engr) = (1.2556/2.51) = 0.5002

So, the engineering strain is around 0.5002 bit wrong from the value of the true strain. This calculated value of difference is known as the extensional deformation.

For finding out the Engineering strain,

Engineering strain is a unit used to describe how much a material deforms when subjected to a specific force. It is equal to the amount of deformation divided by the material's initial length in the direction of the applied force.

⇒ε(engineering) = ΔL/L₀

⇒Lₓ= final length = 3.51 L₀

⇒L₀ = original length = L₀

⇒ΔL = Lₓ- L₀

        = 3.51 L₀ - L₀

        = 2.51 L₀

⇒ε(engineering) = ΔL/L₀

                            = (2.51L₀)/L₀  

                            = 2.51

For finding out the True Strain,

Deformation is measured by True Strain. It can be calculated by integrating the strain across short time intervals and adding them up. Hence,

⇒ε(true) = In (Lₓ/L₀)

⇒Lₓ = 3.51L₀

⇒L₀ = L₀

⇒ε(true) = In (Lₓ/L₀)

              = In (3.51L₀/L₀)

              = In 3.51

              = 1.2556

So, dividing both the values, we get

(ε true/ε engr) = (1.2556/2.51) = 0.5002

The complete question is as follows:

The elastic cords used for bungee jumping are designed to endure large strains. Consider a bungee cord that stretches to a maximum length 3.51 times the original length. There are different ways to report this extensional deformation. Calculate how wrong' the engineering strain is compared to the true strain by evaluating the ratio: ε true/ε engr

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Answer:

Explanation:

a) Using the equation of motion

S = ut + 1/2gt²

S is the distance of fall

g is the acceleration due to gravity

t is the time taken

Given S = 12.0m, g = 9.81m/s^2, un= 0m/s

12 = 0+1/2(9.81)t²

12 = 4.905t²²²

t² = 12/4.905

t² = 2.446

t = √2.446

t = 1.56secs

b) To determine how fast is the frog falling at this point, we need to calculate the speed of the frog. Using the equaton v = u+gt

v = 0+9.81(1.56)

v = 15.34m/s

Hence the frog is falling at the rate of 15.34m/s

From Coulomb's law, the sets of charges of +2 C and -2 C, and +2 C and +2 C are experiencing the strongest forces, both with a magnitude of 36 N.

The strength of the electrostatic force between two charges depends on the magnitudes of the charges and the distance between them, as given by Coulomb's law. The larger the magnitude of the charges and the smaller the distance between them, the stronger the force.

A fundamental characteristic of matter called charge describes how it interacts with magnetic and electric fields. It is commonly measured in coulombs (C), can be positive or negative, and can also be zero.

Protons and electrons are examples of subatomic particles that have electric charge.

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Answer:

C.increased use of fossil fuels

We should place the crimson cloud on ethene (\(C2H4\)) to represent the nucleophile and the blue cloud on hydrogen chloride (\(HCl\)) to represent the electrophile.

In the given response among ethene (\(C2H4\)) and hydrogen chloride (\(HCl\)), the nucleophile and electrophile may be identified as follows:

Nucleophile (pink cloud): The nucleophile is the electron-wealthy species that donates electron pairs. In this situation, ethene (\(C2H4\)) can act because the nucleophile because it has a π bond among the carbon atoms, which includes a high electron density.

Electrophile (blue cloud): The electrophile is the electron-poor species that accept electron pairs. In this situation, hydrogen chloride (\(HCl\)) can act as the electrophile because the hydrogen atom is in part wonderful (δ+) and may accept a couple of electrons.

So, you should place the crimson cloud on ethene (\(C2H4\)) to represent the nucleophile and the blue cloud on hydrogen chloride (HCl) to represent the electrophile.

Note: The response between ethene and hydrogen chloride generally involves the addition of \(HCl\) across the double bond of ethene to shape a chloroethane product.

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The correct question is:

"Identify the relevant nucleophilic and electrophilic parts of the reaction by placing the corresponding clouds on them. HOME THEORY MEDIA MISSION In front of you are ethene and a hydrogen chloride molecule. Identify the nucleophile and electrophile by placing the reactive center 'clouds' in the correct positions. 1. Pick up one of the clouds - the nucleophile (red) or the electrophile (blue). 2. Place the nucleophile (red) or electrophile (blue) cloud on the correct part of the reactants. 3. Repeat for the other cloud. 4. Press Check on the holo-table to check if vou are right. Chark H ? H H. | -H CI H E Nu SS: 3738 philic and ction by placing them. church"

There are three main types of galaxies: spiral, elliptical, and irregular. Each has distinguishing characteristics that set them apart from one another.

Spiral galaxies are characterized by their rotating disk-like structure with spiral arms. They have a central bulge composed of older stars, surrounded by a flat disk containing younger stars, gas, and dust. Spiral galaxies can be further classified into barred and unbarred, with barred spirals having a central bar structure.

Elliptical galaxies are more spherical or elliptical in shape, and they consist mainly of older stars with little gas and dust. These galaxies have a smooth, featureless appearance and can vary in size from dwarf ellipticals to giant ellipticals. They do not exhibit spiral arms or a central bar like spiral galaxies do.

Irregular galaxies do not fit into the spiral or elliptical categories due to their chaotic shape and structure. These galaxies are rich in gas and dust, and often contain regions of active star formation. Irregular galaxies may be influenced by gravitational interactions with nearby galaxies or have experienced a collision or merger event.

In summary, spiral galaxies are known for their rotating disk and spiral arms, elliptical galaxies for their smooth, featureless appearance, and irregular galaxies for their chaotic structure and active star formation.

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Explanation:

mass(m)=20kg

velocity(v)=d/t=2.67

k.e=?

now,

k.e=1/2mv^2

=1/2*20*(2.67)^2

=71J

Answer:

Explanation:kE =10kg(7.3m²/s²)

=73J

Consequently, by using the orbital velocity law to calculate the stars' orbits at various distances from galactic center,

The Solar System's home galaxy, known as the Milky Way, takes its name from how it looks in the night sky from Earth: as a hazy band of light made consisting of stars which are too near to one another to be viewed separately. One of the many billions of galaxies in the cosmos is the Milky Way galaxy. The universe is a large region of space that houses everything that has ever existed.

The Milky Way, which houses the Solar System and Earth, and the Andromeda Galaxy are anticipated to collide in roughly 4.5 billion years. This galactic collision will take between the two largest galaxies in the Local Group.

Therefore, we may estimate how much of the galaxy's mass is contained inside each radius by applying its orbital velocity laws to a orbits of stars at various distances from galactic center. Overall distribution of a mass mostly in Milky Way can then be determined by plotting the galaxy's mass as just a function of radius.

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Answer:

7.5x10-^8m

Explanation:

the formulae is v=fh ,where f is frequency

h is wavelength

hence wavelength=v/f

since the speed of light is 3x10^8

then the wavelength =3 x 10^8/4 x 10^15

=7.5x10^-8m

If wind is blowing at 20 miles per hour in the direction N30W (30 degrees left of y axis), the express for velocity as a vector v in terms of i and j is  v = v = -10 i + 10√3 j

In this figure it seen that,

v(x) = v sin30 = v/2

v(y) = v cos30 =√3/2 v

where v is velocity of the wind which is 20 miles per hr.

v(x) = 20× sin30 = 20/2 = 10

v(y) = 20× cos30 =√3/2×20 = 10√3

in the vector form it ca be written as,

v = -10 i + 10√3 j

there is negative sign cause it is on negative x axis.

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Answer:

longer

Explanation:

The relationship between the solar day and sidereal is as follows:

The length of the sidereal day is

= (Solar day) (solar year ÷ solar year +  1 day)

As it can be seen that the day i.e. solar its length would be greater as compared with the sidereal day.

In the case when the earn orbited the sun in 9 months rather than 12 so here the sidereal day would be the similar but the solar day would be longer as compared with the original one

Answer: The table that would organize and summarize the class data on pH levels of the different soil types is found in the attachment below.

Explanation: As an A+ student, I love to help people on brainly in my free time! If this answer helped you, please click the heart, click the crown to give brainliest and give a 5 star rating! I'd appreciate it if you did at least one of those <3 Have a great day.

Answer:

My arms are doing a negative work

Explanation:

When you set something on the ground, the displacement of the object set towards the ground is in the downward direction. which means that, in this case, there is a downward displacement.

As the object is set on the ground, the force exerted by the arms on the object acts in the upward direction.

Summarily, direction of force is upwards while the direction of displacement is downwards.

Since the force and displacement act in opposite direction, a negative work is said to be done.

Countries limited trade, investment, and aid to South Africa.

During the era of apartheid in South Africa, which lasted from 1948 to 1994, the South African government implemented a system of institutionalized racial segregation and discrimination.

The policy of apartheid denied basic human rights and freedoms to the non-white population, particularly black South Africans. In response to this unjust system, many countries, including the United States and other nations, implemented economic sanctions against South Africa.

Economic sanctions are measures taken by countries or international bodies to exert pressure on a government or regime by limiting or restricting trade, investment, and financial aid.

In the case of apartheid South Africa, these economic sanctions were aimed at isolating the South African government and encouraging them to dismantle the apartheid system.

By limiting trade, investment, and aid to South Africa, countries sought to economically isolate the apartheid regime and show their disapproval of its discriminatory policies. The goal was to create economic pressure and encourage the South African government to change its stance on apartheid and work towards ending the system.

It is important to note that international organizations and world leaders also played significant roles in the fight against apartheid. However, the specific statements mentioned in the options provided do not accurately reflect their actions during that time.

Overall, the primary approach taken by countries was to limit trade, investment, and aid to South Africa as a means to pressure the government and contribute to the eventual dismantling of apartheid.

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