Are true or false grocery bags considered low density polyethylene compounds?

The number of moles of the excess reactant that is left over is 0.37 moles

The excess reactant refers to the reactant that is present in a greater quantity than what is required for complete reaction with the other reactant(s). The other reactant is referred to as the limiting reactant.

Number of moles of P = 2.5 moles

Number of moles of bromine = 3.20 moles

We have that the stoichiometry gives that;

2 moles of P reacts with 3 moles of bromine

2.5 moles of P reacts with  2.5 * 3/2

= 3.75 moles

Hence bromine is the limiting reactant

If 2 moles of P reacts with 3 moles of bromine

x moles of P reacts with  3.20 moles of bromine

x = 2.13 moles

Moles of excess reactant left = 2.50 - 2.13 moles

= 0.37 moles

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The standard voltage generated by the hydrogen fuel cell in acidic solution is 1.23 V, expressed to three significant figures.

To calculate the standard voltage generated by a hydrogen fuel cell in acidic solution, you need to consider the standard reduction potentials of the half-reactions involved.

In a hydrogen fuel cell, the overall reaction can be represented as:
2H₂ (g) + O₂ (g) → 2H₂O (l)

This reaction can be broken down into two half-reactions:
1. Oxidation of hydrogen (anode): 2H₂ (g) → 4H⁺ (aq) + 4e⁻
2. Reduction of oxygen (cathode): O₂ (g) + 4H⁺ (aq) + 4e⁻ → 2H₂O (l)

Now, you can use the standard reduction potentials (E°) found in Appendix E:
E°(H₂/H⁺) = 0 V (by definition)
E°(O₂/H₂O) = +1.23 V

To find the standard voltage (E°) for the overall reaction, we can use the equation:
E°(cell) = E°(cathode) - E°(anode)
E°(cell) = (+1.23 V) - (0 V) = +1.23 V

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Answer:

12g

Explanation:

The following equation is given in this question:

2H2 + O2 → 2H2O

According to this balanced chemical equation, 2 moles of hydrogen gas is used to produce 2 moles of water molecule.

Hence, if 12 grams of hydrogen is used, 12 × 2/2 = 24/2

= 12 grams of H2O will be produced.

Answer:

b) Increase

Explanation:

Species that are able to adapt to a new environment experience an increase in population in their new environment. Because they are able to adapt to their new surroundings and utilize the new materials and experiences they have, they thrive and their population experiences an increase.

The molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.

The molar mass of a substance can be calculated by dividing the mass of the substance by its number of moles.

However, the number of moles of the gas in this question needs to be calculated first using the ideal gas law equation:

PV = nRT

Where;

1.04 × 0.854 = n × 0.0821 × 302

0.888 = 24.79n

n = 0.888/24.79

n = 0.036mol

Molar mass of gas = 3.82g/0.036mol

Molar mass = 106.66g/mol

Therefore, the molar mass of the gas that has a mass of 3.82 g and occupies a volume of 0.854 L is 106.66g/mol.

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Answer:

12:35

Try it this way. egst11245

Answer:

A is mixture

B and C are compund

D and E are elements

F is also mixture

The difference in degrees Fahrenheit between the maximum expected temperatures by the end of the century between the lower and higher emissions scenarios can vary depending on various factors and assumptions.

However, in general, the lower emissions scenario is expected to result in a lower increase in global temperatures compared to the higher emissions scenario.

This means that the maximum expected temperature rise by the end of the century under the lower emissions scenario would be lower than that of the higher emissions scenario.

The specific temperature difference would depend on the specific projections and models used, but it highlights the significant impact that emissions reductions can have on mitigating future temperature increases.

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Answer:

has a magnetic field surrounding it

Explanation:

The compound that is composed of calcium and chlorine is CaCl₂

To know which of the compound that contains calcium and chlorine, we must know the symbol of calcium and chlorine. This is shown below:

Calcium is a group 2 element with atomic number of 20 and a symbol of Ca

Chlorine is a group 17 element with atomic number of 17 and a symbol of Cl

With the above information, we can determine the compound that contains calcium and chlorine as follow:

The compound that contains calcium and chlorine must have Ca and Cl in it.

Thus, the compound that contains calcium and chlorine is CaCl₂

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Using Heat flow equation,

The final temperature of the mixed water is equal to 46.15°C .

This requires considering heat transfer between hot and cool substances, and hot substances transfer to cool substances. We expect the result to be closer to 27.3°C than 71°C.

Therefore, we need to use the heat flow equation, q = plus/minus m×c×∆T

= plus/minus m×c×| final temp. - initial temp.|

q > 0 when heat is absorbed and q<0 when heat is emitted. So, q<0 for hot water and q>0 for cold water. So, the following applies: q warm + q cold=0

i.e. there is energy conservation for an ideal closed system.

Assuming that the specific heat capacity, c does not vary significantly between 27.3°C and 71.2°C

q (hot substance) = - m×c×∆T

= -(75g )(4.284 J/g°C) |final temp. - 71.2°C| = - (75 )(4.284 )(71.3°C - final temp. ) (because for hotter body final temp. <71.2°C)

q (cold substance) = m×c×∆T

= (100g)(4.284 J/g°C) |final temp. - 27.3°C|

An ideal closed system we have,

q(hot body ) = − q(cold body )

=> - (75g )(4.284 J/g°C)(71.3°C - final temp )

= - (100g)(4.284 J/g°C) (final temp. - 27.3°C)

=> (75 )(4.284 )(71.3°C - final temp.)

= (100)(4.284) (final temp. - 27.3°C)

=> 100g( final temp. - 27.3°C) = 75g(71.3°C - final temp.)

=> final temp. (100 + 75 ) = 2730°C + 5347.5°C

=> 175 final temp. = 8077.5°C

=> final temperature = 46.15 °C

Hence ,final temperature is 46.15°C .

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The amount of heat absorbed by the water is 1606.6 J (383.99 Calories )

Initial temperature (T₁) = 21.5 °C

Final temperature (T₂) = 28.1 °C

ΔT = T₂ – T₁

ΔT = 28.1 – 21.5

Mass of water (M) = 58.18 g

Change in temperature (ΔT) = 6.6 °C

Specific heat capacity of water (C) = 4.184 J/gºC

Q = MCΔT

Q = 58.18 × 4.184 × 6.6

Divide by 4.184 to express in Calories

Q = 1606.6 / 4.184

Therefore, the amount of heat absorbed by the water is 1606.6 J (383.99 Calories )

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Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

Identify

[Given] 10.1 g Ne

[Solve] atoms Ne

Step 2: Identify Conversions

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

Answer: Anything that does not have an affect of the earth surface changing it in any way

Explanation: No options were provided

Answer:

Limiting reactant: lead(II) nitrate (Pb(NO3)2).

Mass of sodium nitrate (NaNO3) = 12.92 g.

Explanation:

What is given?

Mass of lead (II) nitrate (Pb(NO3)2) = 25 g.

Mass of sodium iodide (NaI) = 30 g.

Molar mass of Pb(NO3)2 = 331 g/mol.

Molar mass of NaI = 150 g/mol.

Molar mass of sodium nitrate (NaNO3) = 85 g/mol.

Step-by-step solution:

First, let's state the balanced chemical equation. Lead (II) nitrate (Pb(NO3)2) reacts with sodium iodide (NaI) in a double-replacement reaction to produce sodium nitrate (NaNO3), and PbI2:

Now, let's calculate the number of moles of each reactant using its molar mass. The conversion from grams to moles for Pb(NO3)2 will look like this:

And for NaI:

The next step is to see how many moles of NaNO3 are being produced. We're going to need the chemical equation: let's start with Pb(NO3)2. 1 mol of Pb(NO3)2 reacted produces 2 moles of NaNO3, so we will obtain:

And now, let's see that 2 moles of NaI reacted produce 2 moles of NaNO3, so the molar ratio between these compounds is 1:1, which means that 0.20 moles of NaI reacted will produce 0.20 moles of NaNO3 too:

Based on these calculations, you can note that the limiting reactant would be Pb(NO3)2 because this compound imposes the limit because is being consumed first, it is producing the maximum amount of NaNO3 that we can produce in this reaction.

The final step is to calculate the mass of NaNO3 that is being produced. Remember as Pb(NO3)2 is the limiting reactant and it produces 0.152 moles of NaNO3, we use this data to find the mass of NaNO3 using its given molar mass too, like this:

The answer is that the limiting reactant is lead (II) nitrate (Pb(NO3)2) and we're producing 12.92 g of sodium nitrate (NaNO3).

Answer:

Display behavior or engaging in physical combats with other males

Explanation:

The behavior that both territorial and used for courtship is engaging in physical combats with other males because the male display and engage in physical combats with other males in order to attracts females as their mating partner or for courtship and also the male do this so as to secure their territories from Intruders and others taking over their own found territories. This normally occur in male lizards. The male like lizards have variants color on their skin, they display to attracts females and also to secure their territory.

Answer:

0.41 and 0.02 moles Au

Explanation:

Moles:

81 grams (2.6 troy oz):

mole Au = 81g/(196.97 g/mole) = 0.41 moles Au

4.0g (0.13 oz):

mole Au = 4.0g/(196.97 g/mole) = 0.020 moles Au

Therefore, approximately 108.736 kJ of heat is absorbed in the process of making 0.769 mol of CF₄ from the given reaction.

To determine the amount of heat absorbed in the process of making 0.769 mol of CF₄ (carbon tetrafluoride) from the given reaction, we need to use the molar enthalpy change (∆H°) provided.

The reaction is:

C (s) + 2 F₂ (g) → CF₄ (g)

The molar enthalpy change (∆H°) for the reaction is 141.3 kJ/mol.

We can use stoichiometry to calculate the heat absorbed for the given amount of CF₄.

From the balanced equation, we can see that 1 mol of C (s) reacts to form 1 mol of CF₄. Therefore, the heat absorbed for the reaction of 1 mol of CF₄ is 141.3 kJ.

Now, to calculate the heat absorbed for 0.769 mol of CF₄, we can use a proportion:

(0.769 mol CF₄) / (1 mol CF₄) = x / (141.3 kJ)

Solving for x, we find:

x = (0.769 mol CF₄) × (141.3 kJ / 1 mol CF₄)

x ≈ 108.736 kJ

Therefore, approximately 108.736 kJ of heat is absorbed in the process of making 0.769 mol of CF₄ from the given reaction.

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Answer:

it have been already balanced

2H2 + O2 = 2H2O.

size and shape. only the appearance of the paper will have changed, but is reversible.

Lewis proposed that the eight valence electrons in inert gas atoms make them chemically inert.

A gas is said to be inert if it does not readily react chemically with other substances and does not afterwards produce chemical compounds. The noble gases, also known as the inert gases in the past, frequently do not react with numerous things.

Typically, inert gases are employed to stop unintended chemical reactions from deteriorating a sample. With the oxygen and moisture in the air, these unfavorable chemical processes frequently involve oxidation and hydrolysis.

Several of the noble gases can be made to respond when particular conditions are met, hence the phrase "inert gas" is context-dependent. Due to its large natural abundance (78.3% N2, 1% Ar in air) and cheap relative cost, purified argon gas is the most often utilized inert gas.

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The correct answer is: 1.8 moles Fe and 2.7 moles CO2.

In the balanced chemical equation, Fe2O3 + CO → Fe + CO2, the stoichiometric coefficients indicate the mole ratio between the reactants and products. According to the coefficients, 1 mole of Fe2O3 reacts with 3 moles of CO to produce 2 moles of Fe and 3 moles of CO2.

Given that 1.8 moles of Fe2O3 and 2.7 moles of CO are provided, we can determine the number of moles of each product formed. From the mole ratio, 1 mole of Fe2O3 requires 3 moles of CO, so 1.8 moles of Fe2O3 will react with (1.8 moles × 3 moles CO / 1 mole Fe2O3) = 5.4 moles of CO. Therefore, the remaining 2.7 moles of CO will not react fully and will be in excess.

Using the mole ratio, 1 mole of Fe2O3 produces 2 moles of Fe. Since 1.8 moles of Fe2O3 are consumed, the number of moles of Fe produced is (1.8 moles × 2 moles Fe / 1 mole Fe2O3) = 3.6 moles Fe.

Similarly, 1 mole of Fe2O3 produces 3 moles of CO2. Thus, the number of moles of CO2 formed is (1.8 moles × 3 moles CO2 / 1 mole Fe2O3) = 5.4 moles CO2.

Hence, the correct answer is 1.8 moles Fe and 2.7 moles CO2.

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Answer:

When 20.0 grams of aluminum and 30.0 grams of chlorine are reacted according to the above equation, the chlorine is the limiting reactant and the maximum yield of aluminum chloride is 0.28 moles or 37.33 grams.

As a result, when two objects are close together and have enormous masses, their gravitational attraction is strongest.

According to Newton's law of universal gravitation, any two bodies in the universe are attracted to one another by a force that is inversely proportional to the square of the distance between them and a direct relationship between their mass products In other words, every particle of matter in the cosmos is attracted to every other particle by a force that is inversely proportional to the square of the distance between them and proportionate to their masses. Sir Issac Newton created the law in 1687.

According to their masses and separation, two objects will gravitationally pull one another.

The attractive force between two objects (F) is determined by Newton's law of universal gravitation and is equal to G times the product of their masses (m1m2) divided by the square of their distance

(r2), or F = Gm1m² / r2².

As a result, when two objects are close together and have enormous masses, their gravitational attraction is strongest.

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Answer: B.

Explanation:

Trust me already took the quiz on it its B.

Answer:

Yes its B

Explanation:

The mass of ammonia that can be produced from the reaction of 74.2 g of N₂ and 14.0 moles of H₂ is 90.1 g.

The mole ratio of the reaction for the production of ammonia is obtained from the balanced equation of the reaction as follows:

Equation of the reaction: N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

The mole ratio of the reactants nitrogen and hydrogen is 1 : 3

Moles of nitrogen in 74.2 g of nitrogen = 74.2/28

Moles of nitrogen in 74.2 g of nitrogen = 2.65 moles

Moles of hydrogen present = 14.0 moles

The limiting reactant is nitrogen

Mole ratio of nitrogen to ammonia is 1 : 2

Mass of ammonia produced = 2.65 * 2 * 17 g

Mass of ammonia produced =  90.1 g

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