Assume the average house price for a house in your neighborhood is $135,000, and the standard deviation is $15000. Find the price range where at least 75% of the houses will sell. a.) Upper price range:_________Units count. No decimals. No commas. b.) Lower price range:__________Units count. No decimals. No commas.

Answer:

use for formula a^2+b^2=c^2 to execture

*" ^ "  means square or to the power of two

Step-by-step explanation:

Option (B) is the correct answer.

A company plans to spend $8,000 in year 2 and $10,000 in year 4. At an interest rate of 10% per year, compounded semiannually. The equation that represents the equivalent annual worth A in years I through 4 is given by option (B).That is;Option (B) represents the equation that represents the equivalent annual worth A in years I through 4.

The formula for equivalent annual worth is given by;A = PW (A/P, i, n) + F(A/F, i, n)where,PW = Present WorthF = Future WorthA/P = Present Worth FactorA/F = Future Worth Factori = interest raten = number of yearsSo,A = 8000(P/A, 10/2,2) + 10000(F/A, 10/2,4)A = 8000(3.1051) + 10000(0.6848)A = 24,840.80 + 6848A = $31,688.80The equation that represents the equivalent annual worth A in years I through 4 is represented by the option (B);A = 8000(P/A, 10.25/2,2) + 10000(F/A, 10.25/2,4).

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The statement "The line that can be drawn through points D and E is contained in plane Y" is true about the points and planes.

From the given information, we have the following conditions:

Vertical plane X intersects horizontal plane Y.

Point D is on the left half of plane Y.

Point F is on the bottom half of plane X.

Point E is on the right half of plane Y.

Point C is above and to the right of the planes.

Let's analyze each statement to determine its validity:

The line that can be drawn through points C and D is contained in plane Y.

This statement is not necessarily true based on the given information. Since point C is above and to the right of the planes, the line connecting C and D may not lie entirely in plane Y.

The line that can be drawn through points D and E is contained in plane Y.

This statement is true. Since point D is on the left half of plane Y and point E is on the right half of plane Y, any line passing through D and E would be contained within plane Y.

The only point that can lie in plane X is point F.

This statement is not necessarily true. While point F is on the bottom half of plane X, there could be other points that lie in plane X as well.

The only points that can lie in plane Y are points D and E.

This statement is not true. While points D and E are mentioned in the given conditions, there could be other points that lie in plane Y as well.

Based on the analysis, we conclude that the statement "The line that can be drawn through points D and E is contained in plane Y" is the only true statement about the points and planes.

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Answer:

hope this helps!

Step-by-step explanation:

The population of Medway, Ohio, is expected to be approximately 3728 in the year 2020.

From the question, we have the following parameters that can be used in our computation:

Initial, a = 4007

Rate = 0.36% per year

The decay function is represented as

y = a(1 - rate)^x

So, we have

y = 4007 * (1 - 0.36%)^x

This gives

y = 4007 * (0.9964)^x

The year 2020 is 20 years from 2000

So, we have

x = 20

Substitute the known values in the above equation, so, we have the following representation

y = 4007 * (0.9964)^20

Evaluate

y = 3728

Hence, the approximate solution is 3728

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The unit rate for each shirt if 24 shirts cost $259.36 as required to be determined is; $10.81.

It follows from the task content that the unit rate is to be determined if 24 shirts cost $259.36.

On this note, it follows that; the unit rate is given by the quotient;

Unit rate = Total cost / No. of units

Unit rate = 259.36 / 24

Unit rate = 10.80667.

Ultimately, the unit rate of the shirts as required is; $10.81.

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In this scenario, we have a uniformly charged thin rod extending along the x-axis from the origin (x = 0) to positive infinity (x = +∞).

The term "uniformly charged" means that the charge is distributed evenly throughout the entire length of the rod.

To analyze this situation, we can consider the following steps: 1. Determine the linear charge density (λ) of the rod. Since the rod is uniformly charged, λ remains constant along its entire length. λ is usually given in units of charge per length (e.g., coulombs per meter).

2. To find the electric field at a particular point along or outside the rod, we can break the rod into infinitesimally small segments (dx) and consider the contribution of the electric field (dE) from each of these segments.

3. Calculate the electric field (dE) produced by each segment at the desired point using Coulomb's equations , considering the linear charge density (λ) and distance between the segment and the point.

4. Integrate the electric field contributions (dE) from all segments along the entire length of the rod (from x = 0 to x = +∞) to find the total electric field (E) at the point of interest.

By following these steps, you can analyze the electric field and related properties of a uniformly charged thin rod extending along the x-axis from x = 0 to x = +∞.

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Answer:

x = 9

Step-by-step explanation:

12^2+x^2 = 15^2

==> x = 9

Answer:

9

Step-by-step explanation:

x = \(\sqrt{c^{2} - a^{2} }\)

x = \(\sqrt{15^{2} - 12^{2} }\)

x = \(\sqrt{225 - 144}\)

x = \(\sqrt{81}\)

x = 9

The confidence interval is approximately (0.0814, 0.1386), meaning that with 98.5% confidence, the true proportion of new cars with manufacturing defects is between 8.14% and 13.86%. Since the cars were randomly selected, this confidence interval provides a reliable estimate of the overall defect rate in the entire population of new cars.

To determine the confidence interval at a significance level of 0.015, we need to calculate the standard error of the proportion and use it to find the margin of error.
First, we calculate the standard error of the proportion using the formula:
SE = sqrt[(p * (1 - p)) / n]
Where p is the proportion of defective cars in the population, which is given as 0.08, n is the sample size, which is 300, and sqrt denotes the square root.
SE = sqrt[(0.08 * (1 - 0.08)) / 300] = 0.019
Next, we find the margin of error by multiplying the standard error by the z-value corresponding to a significance level of 0.015. From a standard normal distribution table, we find that the z-value is -2.17 (since the significance level is on the left tail).
Margin of error = 2.17 * 0.019 = 0.041
Finally, we can construct the confidence interval by adding and subtracting the margin of error from the sample proportion:
CI = (p-hat - ME, p-hat + ME)
CI = (33/300 - 0.041, 33/300 + 0.041)
CI = (0.066, 0.154)
Therefore, we can say with 98.5% confidence that the true proportion of defective cars in the population lies between 0.066 and 0.154.

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Answer:

k = m + 4

Step-by-step explanation:

Therefore, the measure of the area of rhombus EFGH is 252 square units.

A rhombus is a four-sided geometric shape that has the following properties:

All four sides are of equal length.

Opposite sides are parallel to each other.

The angles formed between adjacent sides are equal (i.e., they are all congruent).

The diagonals of a rhombus bisect each other at right angles, meaning they intersect at a 90-degree angle. Additionally, the length of one diagonal is equal to the product of the length of the other diagonal and the sine of one of the angles formed by adjacent sides.

by the question.

\(EK^2 = EG^2/4 + KH^2 (where KH is half the length of FH)EK^2 = 36^2/4 + (14/2)^2EK^2 = 324 + 49EK^2 = 373EK = sqrt(373)\)

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Answer:

(3,2) just use a slope triangle (over 2 up 3) and do it in reverse

Answer:

1/6

Step-by-step explanation:

1- 1/2 = 1/2

1/2- 1/3 = 1/6

The fractional part which left after eat half and then one third of rest is 1/3.

Fraction:

Fraction is mathematical representation of any number that distribute over some numbers

Ex: 3/7 represent 3 is distributed in 7 equally parts.

One friend is eat 1/2 of the dessert

then rest part will be = 1 - 1/2 = 1/2

Now second friend eat one third of 1/2

that is 1/3*1/2 = 1/6 eats

Then the remaining part is

1/2 - 1/6 = 2/6 = 1/3

Hence the final answer is 1/3

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Answer:

And 2 from grand-pa pa

Step-by-step explanation:

Answer: 6 snack bags

Step-by-step explanation:

In rder to know mnay bags destiny ca make, we need a number is a factor of 18 and 12, so that the 18 chocolate candy bars and the 12 cookies can be divided up evenly.

So, if there were 2 bags, thre would be 18÷2=9 chocolate candy bars and 12÷2=6 cookies in a bag. This creates identical snack bags, but isn't the greatest number of bags!

To find the greatest snack bag, we want to find the greatest common factor of 18 and 12

To do so, let's find factors of 18 ans 12

18: 1, 2, 3, 6, 9, 18

12: 1, 2, 3, 4, 6, 12

The greatest common factor of 18 and 12 is 6. in math notation this looks like:

gcf (18, 12) = 6

The greatest number of identical bags can make is 6

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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Answer:

-x^3 + x^2 - 2x - 4

Step-by-step explanation:

You have to subtract

Let o = the polynomial

So you know 2x^3 - x^2 + 4x + 5 - o = x^3 + 2x - 9

Now you do 2x^3 - x^3 = x^3

then you -x^2 + answer = 0

you need to cancel it out

to cancel, you found out that it is x^2

Now you need to make from 4x to 2x.

To do that, you do 4x - 2x and you get 2x

Lastly you need to change -5 to 9. To do that you add -4.

Now since it is subtraction you have to distribute

2x^3 - x^2 + 4x - 5 -(x^3 - x^2 + 2x + 4)

= 2x^3 - x^2 + 4x + 5 - x^3 + x^2 -2x -4

= x^3 -2x + 9

Among the provided functions, the ones that approach positive infinity as x approaches negative infinity are:

- f(x) = 2x^5

- f(x) = 6x^8 + 9x^6 + 32

- f(x) = -x + 8x^4 + 248

To determine which functions approach positive infinity as x approaches negative infinity, we need to analyze the leading terms of the functions. The leading term dominates the behavior of the function as x becomes very large or very small.

Let's examine each function and identify their leading terms:

1. f(x) = 2x^5

The leading term is 2x^5, which has a positive coefficient and the highest power of x.

As x approaches negative infinity, this term becomes very large and positive, indicating that f(x) approaches positive infinity.

2. f(x) = 9x + 100

The leading term is 9x, which has a positive coefficient but a lower power of x compared to the constant term 100.

As x approaches negative infinity, the leading term becomes very large and negative, indicating that f(x) approaches negative infinity, not positive infinity.

3. f(x) = 6x^8 + 9x^6 + 32

The leading term is 6x^8, which has a positive coefficient and the highest power of x.

As x approaches negative infinity, this term becomes very large and positive, indicating that f(x) approaches positive infinity.

4. f(x) = -8x^3 + 11

The leading term is -8x^3, which has a negative coefficient and the highest power of x.

As x approaches negative infinity, this term becomes very large and negative, indicating that f(x) approaches negative infinity, not positive infinity.

5. f(x) = -10x + 5x + 26

Combining like terms, we have f(x) = -5x + 26.

The leading term is -5x, which has a negative coefficient but a lower power of x compared to the constant term 26.

As x approaches negative infinity, the leading term becomes very large and positive, indicating that f(x) approaches negative infinity, not positive infinity.

6. f(x) = -x + 8x^4 + 248

The leading term is 8x^4, which has a positive coefficient and the highest power of x.

As x approaches negative infinity, this term becomes very large and positive, indicating that f(x) approaches positive infinity.

Therefore, the correct choices are:

- f(x) = 2x^5

- f(x) = 6x^8 + 9x^6 + 32

- f(x) = -x + 8x^4 + 248

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Hey there! :)

Answer:

V = 3408 units³

Step-by-step explanation:

Given:

r = 12

h = 71

Volume of a cone: V = 1/3 (bh) where b = πr²

Calculate the area of the base:

A = 12²π

A = 144π units²

Plug this into the formula for the volume of a cone:

V = 1/3 (144π · 71)

V = 1/3 (10224)

V = 3408 units³

Answer:

B . 3408 π  units^3

Step-by-step explanation:

\(h = 71\\r = 12\\V =?\\V = \frac{1}{3} \pi r^2 h\\V = \frac{1}{3} \pi \times 12^2 \times 71\\V = \frac{1}{3} \pi \times 144 \times 71\\V = 3408 \pi -units^3\)

Answer:

Step-by-step explanation:

Step one:

give data

time= 8hours

distance=385mile

speed=?

Step two:

let us solve for the speed

Speed= distance/time

Speed=385/8

speed=48.125miles per hour

Step three:

let's find the time taken to cover 1000mile at the speed of 48.125 mi per hour

speed=distance/time

time=distance/speed

time=1000/48.125

time=20.779hours

approximately 21 hours

Step-by-step explanation:

10x-6x+12=12x-24-8x

4x+12=4x-24

4x-4x≠-24-12

thus,it is erroneous

Answer:

$5155

Step-by-step explanation:

We know

A car salesman earns 5% on the sale of a BMW sold for $103,100.

5% = 0.05

What is his take-home pay that day?

We take

103,100 times 0.05 = $5155

SO he takes home $5155.

Step-by-step explanation:

Looks like we're trying to find out what 5% of 103,100 is. We first need to convert the percent into a decimal and then multiply.

\(5\% = 0.05\)

Now we can multiply

\((0.05)(103100) = 5155\)

Answer:

-24/23 = x

Step-by-step explanation:

Step 1: Write equation

x - 12 = -4(-6x - 3)

Step 2: Solve for x

Distribute -4: x - 12 = 24x + 12

Subtract x on both sides: -12 = 23x + 12

Subtract 12 on both sides: -24 = 23x

Divide both sides by 23: -24/23 = x

The given network consists of several activities with their respective durations in weeks. The activities have dependencies on each other, and the goal is to determine the earliest start time (ES), earliest finish time (EF), latest start time (LS), latest finish time (LF), and total float for each activity.

To determine the ES, EF, LS, LF, and total float for each activity, we can use the forward pass and backward pass techniques in network analysis.

Forward Pass:

Start with the initial node, Activity A, and assign its ES as 0 since it has no predecessors.

Calculate the EF for each activity by adding the duration to its ES.

For Activity A, EF = ES + duration = 0 + 5 = 5.

For Activity B, EF = ES + duration = 0 + 8 = 8.

For Activity C, EF = ES + duration = 5 + 6 = 11.

For Activity D, EF = ES + duration = 8 + 3 = 11.

For Activity E, EF = ES + duration = 11 + 6 = 17.

For Activity F, EF = ES + duration = 17 + 6 = 23.

For Activity G, EF = ES + duration = 17 + 10 = 27.

Backward Pass:

Start with the final node, Activity G, and assign its LF as its EF since it has no successors.

Calculate the LS for each activity by subtracting its duration from its LF.

For Activity G, LS = LF - duration = 27 - 10 = 17.

For Activity F, LS = LF - duration = 23 - 6 = 17.

For Activity E, LS = LF - duration = 17 - 6 = 11.

For Activity D, LS = LF - duration = 11 - 3 = 8.

For Activity C, LS = LF - duration = 11 - 6 = 5.

For Activity B, LS = LF - duration = 8 - 8 = 0.

For Activity A, LS = LF - duration = 5 - 5 = 0.

Total Float:

Calculate the total float for each activity by subtracting its EF from its LF.

For Activity A, Total Float = LF - EF = 0 - 5 = -5.

For Activity B, Total Float = LF - EF = 0 - 8 = -8.

For Activity C, Total Float = LF - EF = 5 - 11 = -6.

For Activity D, Total Float = LF - EF = 8 - 11 = -3.

For Activity E, Total Float = LF - EF = 11 - 17 = -6.

For Activity F, Total Float = LF - EF = 17 - 23 = -6.

For Activity G, Total Float = LF - EF = 17 - 27 = -10.

The negative total float values indicate that the activities are on the critical path and any delay in their completion would result in a delay in the project completion time.

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The area of the Trapezium given in the question is 28ft²

The area of a trapezium is calculated using the relation :

Using the parameters given for our compuation:

height, h = 4

b1 = 9

b2 = 5

Inputting the parameters into our formula :

Area = 4/2(5 + 9)

Area = 2(14)

Area = 28ft²

Therefore, the area of the Trapezium is 28ft²

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Answer:4

Step-by-step explanation:

y=-2x+8

y=x-4

Y equals the same thing so you can do equal values method

-2x+8=x-4

+2x      +2x

__________

8=3x-4

+4     +4

_______

12=3x

_____

3     3

x=4

The value of x that satisfies the equation log(7) + log(x - 4) = 1 is x = 38/7.

To find the value of x in the equation log(7) + log(x - 4) = 1, we can use the properties of logarithms and solve for x algebraically.

First, let's apply the logarithmic property that states

\(log(a) + log(b) = log(a \times b).\)

Therefore, we can rewrite the equation as \(log(7 \times (x - 4)) = 1.\)

Next, we can rewrite the equation in exponential form, as \(10^1 = 7 \times (x - 4).\)

Simplifying this further, we have 10 = 7x - 28.

To isolate x, we can add 28 to both sides of the equation: 10 + 28 = 7x. This gives us 38 = 7x.

Finally, we divide both sides of the equation by 7 to solve for x: x = 38/7.

So, the value of x that satisfies the equation log(7) + log(x - 4) = 1 is x = 38/7.

It's important to note that logarithms are only defined for positive values. Therefore, in this case, x must be greater than 4 in order for the equation to be valid.

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Answer:

12/75 = 4/25

Step-by-step explanation:

Answer: x = -9

Explanation: