The wind forces on the person's body when the stormy wind speed reaches 108 km/hr is approximately 356.4 Newtons.
To calculate the wind forces on a person's body during a storm with the given conditions, we can use the drag force formula:
Drag force (F) = 0.5 × drag coefficient (Cd) × air density (ρ) × frontal area (A) × wind speed² (v²)
Given:
Cd = 1.2
A = 0.55 m²
ρ = 1.2 kg/m³
First, we need to convert the wind speed from kilometers per hour to meters per second, since the drag force formula requires the velocity to be in meters per second. formula requires the velocity to be in meters per second. To do this, we multiply the wind speed by (1000/3600).
Wind speed = 108 km/hr
First, let's convert the wind speed to m/s:
v = 108 km/hr × (1000/3600) = 30 m/s
Now, plug the values into the drag force formula:
F = 0.5 × 1.2 × 1.2 kg/m³ × 0.55 m² × (30 m/s)²
F = 0.6 × 1.2 kg/m³ × 0.55 m² × 900 m²/s²
F = 356.4 N
Therefore, the wind forces on the person's body when the stormy wind speed reaches 108 km/hr is approximately 356.4 Newtons.
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a simply supported beam has a length of 1.2 m. the cross section has a width of 140 mm and height of 240 mm. the weight density of the beam is 5.4 kn/m3 . calculate the maximum permissible value of the load p if (a) the allowable bending stress is 8.5 mpa, and (b) the allowable shear stress is 0.8 mpa.
The results of the calculations are (a) P = 37.97 kN and (b) P = 35.62 kN.
The surface won't be cut if you press the flat section of the knife against the fruit. The force is dispersed over a wide area.
Using the parameters and figure provided in the problem, we have:
A = b*h = 0.14*0.24 = 0.0336 m^2
S = (b*h^2)/6 = (0.14*0.24*0.24)/6 = 0.001344 m^3
q = 5400*0.0336 = 181.44 N/m
(a) The load P at 8.5 MPa = 8.5*106 Pa (allowable bending stress)
σ = M/S
M = *S thus equals 0.001344*8.5*106 = 11424 Nm.
Aside from that
M = (P*L/4) + (q*L^2)/8
11424 = (P*1.2/4) + (181.44*1.2^2)/8
11424 = 0.3*P + 32.6592
P = (11424-32.6592)/0.3 = 37.97 kN
(b) If (allowable shear stress) = 0.8 MPa, then the value of P is equal to 0.8*106 Pa.
(2*A*τ/3) = P/2 + q*L/2
(2*0.0336*0.8*10^6)/3 = P/2 + 181.44*1.2/2
17920 = P/2 + 108.864
P = (17920 - 108.864) * 2 = 35.62 kN.
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Which characteristic would atoms of a ferromagnetic material have?A. A lack of electrons B. North and south poles C. A temporary magnetic field D. The ability to attract nonmagnetic materials
Answer:
Option B
Explanation:
Atoms of ferromagnetic materials have north and south pole but these atoms are oriented in random directions due to which they do no exhibit magnetic properties until unless they are brought into influence of any external temporary or permanent magnetic field.
Under the influence of external magnetic force, the atoms of the ferromagnetic material get oriented in a particular direction.
Hence, option B is correct
when using a reciprocating saw, insufficient clearance behind the saw can cause impeded movement of the saw blade, resulting in a damaged blade or injury to the operator. group of answer choices true false
When using a reciprocating saw, insufficient clearance behind the saw can cause impeded movement of the saw blade, resulting in a damaged blade or injury to the operator. This statement is TRUE.
A reciprocating saw is a type of saw that is used to cut through different materials like wood, plastic, and metal. It uses a push-and-pull motion to cut through the material. It is also known as a saber saw or a Sawzall. This tool can be used in various applications like plumbing, electrical work, and demolition work.
When using a reciprocating saw, it is important to have sufficient clearance behind the saw blade. Insufficient clearance can cause the blade to be impeded, which can result in damage to the blade or injury to the operator. This is because the blade will not be able to move freely and may cause unnecessary vibrations, making it difficult to make a clean cut.
Having sufficient clearance also allows the operator to have better control over the saw blade while cutting, making it safer to use. When using a reciprocating saw, it is important to follow safety precautions to prevent injuries. These precautions include wearing protective gear like eye protection, gloves, and hearing protection.
It is also important to keep the saw blade clean and sharp and to avoid using the saw near flammable materials. Always disconnect the saw from the power source when changing the blade or performing maintenance on the tool. Finally, it is important to have a clear and stable work area and to maintain a good grip on the saw at all times.
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include a sketch of your stepped cylindrical shaft, showing all diameters, fillet radii, and keyways. also note where bearings will be placed. use the failure criteria in chapter 7 to determine the minimum diameters at the critical locations on the shaft. design keys to transmit torque between the two gears and the shaft. shaft design constraints: the intermediate shaft must be designed as a solid shaft of length no larger than 300 mm. the shaft will be supported by two 15 mm wide ball bearings (you are not required to specify the bearings). minimum distance between the bearings and the next installed part on the shaft must be 20 mm, to facilitate good lubrication and cooling of the components within the gear box. distance between the two gears should be between 80 mm and 140 mm. clearly indicate how the two gears will be installed on the intermediate shaft and create a shaft layout before moving to the next step. you are to perform static and fatigue analysis for the shaft. for the fatigue analysis assume a reliability of 99%, a minimum required life of 107 cycles and light-shock loading. use appropriate materials for the shaft and indicate if heat treatments are required for any regions of the shaft. the minimum design factor for any region of the shaft should be 1.2.
The selection of shaft keys is critical in preventing premature failure of keyed joints. Shaft keyways and keys are used to transmit torque from shafts to mechanical transmission elements such as gears, pulleys, and so on.
What is shaft keys?A key to preventing early failure of keyed joints is choosing the right shaft key. The use of a keyed joint allows for the transmission of torque from shafts to mechanical transmission components like gears, pulleys, etc. They can be produced using a standard stock material, like key stock, or they can be specially machined to fit the application.
According to various standards like BS4235, the nominal shaft diameter is typically used to specify the key size, and the commonly accessible rectangular key is used for the majority of applications. As a result, the standards do not specify the key material or joint limitations, and a keyed joint is oversized to support all loads.
There are four main groups of shaft keys:
Sunk keySaddle keyTangent keyRound keysStainless steel or medium carbon steel are typically used to make shaft keys. To suit various application environments, they can be made from a wide variety of materials, including bronze, copper, brass, and aluminum alloy. For example, stainless steel grade for use in food service equipment and brass or bronze keys for marine propeller shafts.
Key steel is typically supplied in accordance with BS46 and BS4235 and is a medium carbon steel that is unalloyed and has a respectable tensile strength. Due to their ideal blend of strength, toughness, and favorable machining properties, unalloyed medium carbon steels with carbon contents ranging from 0.25% to 0.60% are used.
The table below lists a few popular shaft key materials along with their Ultimate Tensile Strength (UTS). ↓↓↓
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Consider an airplane patterned after the fairchild republic a-10links to an external site., a twin-jet attack aircraft. the airplane has the following characteristics: wing area
step: 1 of 16
The static thrust is defined as such a force which is developed and applied by the jet engine on the surrounding air or earth when the airplane is at rest condition.
Power is defined as the rate of doing work with respect to time. Power is a scalar quantity and having no direction. The unit of power is J/s or watt in an hour(w) .
The expression to calculate the resultant power Ps is,
PRETV …… (1)
Here, Ps is the required power, T R is the required thrust and is the velocity of the airplane at a certain altitude.
The expression for the actual power for two engines is,
P, = 2(TV) …… (2)
Here, т. is the actual thrust and is the velocity of the airplane for a given altitude.
step: 2 of 16
Write the expression for the thrust of an airplane.
TRE W CIC) …… (3)
Here, T R is the required thrust, W is the weight of the airplane, с. is the lift polar coefficient of the airplane and Ср is the drag polar coefficient of the plane.
Write the expression for the lift polar coefficient of the airplane.
W C 1 2P. Vis …… (4)
Here, P is the air density, is the velocity of the airplane for a given altitude and S is the wing area.
Write the expression for drag polar coefficient.
C, = CD,0 + C πε(AR) …… (5)
Here, Сро is the zero-lift drag coefficient, is the Oswald’s efficiency factor and AR is the aspect ratio.
It is clear from the power required curve that maximum velocity at the altitude at 5 km is
Hence, the required maximum velocity at the altitude of 5 km is295 m/s.
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The solute hcl is diffusing through a thin film of water 2 mm thick at 283k. The conc. Of hcl at point 1 is 12wt%hcl (density is 1060kg/m3) and at point 2 is 6 wt%( density= 1030). The diffusivity is 2.45*10^-9 m2/sec.Calculate flux of hcl.
A vibration system consists of a mass 50 kg, a spring of stiffness 30 kN/m and a damper. The
damping provided is only 20% of the critical value. Determine (a) the damping factor, (b) the
critical damping coefficient, (c) the natural frequency of the damped vibrations, (d) the
logarithmic decrement and (e) the ratio of two consecutive amplitudes.
Answer:
20% of the critical value. Determine (a) the damping factor, (b) the
Explanation:
The UHRS platform is optimized for Edge/Internet Explorer only. You can still use your favorite browser, but keep in mind that you may experience technical issues when working on UHRS with a different browser than Edge or Internet Explorer.
UHRS is optimized for...
It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.
What is a UHRS?The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.
Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.
A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.
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non-BIBO are never used in practice. True/false
A 3 MW wind turbine was installed in an on-land location where the capacity factor was measured to be 22 percent. YOUR TURN 1. How much electricity will this wind turbine generate in a year? 2. How much revenue would a utility receive if they were paid $0.05/kwh for this electricity?
An average onshore wind turbine with a capacity of 2.5–3 MW can produce more than 6 million kWh in a year – enough to supply 1,500 average EU households with electricity.
Define Electricity?
Electricity is the flow of electrical power or charge. It is a secondary energy source which means that we get it from the conversion of other sources of energy, like coal, natural gas, oil, nuclear power and other natural sources, which are called primary sources.
The flow of charges in a conductor is defined as electricity. Charges are transferred from one end of the terminal to the other. It usually progresses from a positive to a negative terminal. The electrons travel freely within the body since the nucleus holds them loosely.The outer shells can hold even more. Some atoms with many protons can have as many as seven shells with electrons in them. The electrons in the shells closest to the nucleus have a strong force of attraction to the protons.To learn more about electricity refers to:
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Over 6 million kWh can be produced annually by an onshore wind turbine with a capacity of 2.5–3 MW, which is sufficient to power 1,500 typical EU households.
What is electricity?
The movement of electrical power or charge is called electricity. It is a secondary energy source, which means that it comes from the conversion of primary energy sources like coal, natural gas, oil, nuclear power, and others.
Electricity is the flow of charges in a conductor. The terminal moves charges from one end to the other. In most cases, it moves from a positive terminal to a negative terminal. Because the nucleus holds the electrons loosely, they can move around the body freely.
Even more can fit inside the outer shells. There may be as many as seven electron-filled shells in some atoms with many protons. Protons are strongly attracted to the electrons in the shells closest to the nucleus.
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Considering scaled dot-product attention with the following keys and values: K = [[0.5, 0.5], [-0.5, 0.5], [-0.5, 0.5]] V = [[1.0, 2.0, 3.0, 4.0], [4.0, 1.0, 4.0, 2.0], [-1.0, 5.0, 2.0, 1.0]] Given the query [0.5, 0.5], what is the resultant output? 1. [0.0471, 0.9465, 0.0064] 2. [1.000, 2.000, 3.000, 4.000] 3. [0.5, 0.5]+ 4. [0.5, -0.5] 5. [1.292, 2.584, 3.000, 2.540] 6. [1.000, 4.000, -1.000]
The correct option is 5. [1.292, 2.584, 3.000, 2.540].The query is [0.5, 0.5], and the key values are given as K = [[0.5, 0.5], [-0.5, 0.5], [-0.5, 0.5]].Then, the dot product of the key value and query is calculated.
The dot product of the query and the first key is calculated as: [0.5, 0.5].[0.5, 0.5] = 0.5*0.5 + 0.5*0.5 = 0.5.The dot product of the query and the second key is calculated as: [0.5, 0.5].[-0.5, 0.5] = 0.5* -0.5 + 0.5*0.5 = 0.0.The dot product of the query and the third key is calculated as: [0.5, 0.5].[-0.5, 0.5] = 0.5* -0.5 + 0.5*0.5 = 0.0.
The dot products are normalized by dividing by the square root of the dimension of the query and the key space, which is 2 in this case. Therefore, the output of the attention operation is\([0.5/√2, 0.0/√2, 0.0/√2]\), which is equal to [0.707, 0, 0].Finally, the output vector is computed by multiplying the attention vector with the values V as follows: [0.707, 0, 0].[1, 2, 3, 4] = 1.414.[0.5, 1.0, -0.5] = [0.707, 1.414, -0.707].
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IF YOUR VEHICLE BREAKS DOWN, YOU SHOULD?
Answer:
1. TURN ON YOUR HAZARD/EMERGENCY LIGHTS
Turn on your hazard lights to warn other drivers as soon as you sense something's wrong. Keep them on until help arrives, recommends the National Motorists Association (NMA).
2. SLOW DOWN AND PULL OFF THE ROAD
Aim for the right shoulder of the road. Consumer reports recommends that you pull over to a safe, flat location that is as far away from moving traffic as possible.
3. TURN YOUR WHEELS AWAY FROM THE ROAD AND PUT ON THE EMERGENCY BRAKE
The California Department of Motor Vehicles (DMV) recommends pulling your emergency brake, sometimes called the parking brake. If you have to park on a hill or slope, turn the car's wheels away from the road to help prevent the care from rolling into traffic, says the California DMV.
4. STAY IN YOUR VEHICLE
If you're on a highway or crowded road, the Insurance Information Institute (III) recommends that you avoid getting out of your vehicle to look at the damage or fix a mechanical problem. If you need to get out of the car, get your vehicle to a safe place and make sure the road around you is completely clear. If you're stopped on the right-hand side of the road, get out through the passenger-side door.
5. BE VISIBLE
Once you're safely out of the vehicle, prop up your hood to let other drivers know they should proceed with caution. This will alert other drivers that you're broken down, according to the NMA.
6. SET UP FLARES OR TRIANGLES
Place flares or triangles with reflectors behind your car to alert other drivers to the location where you've stopped, says the III.
7. CALL FOR HELP
Call or use an app to get a tow truck, mechanic or roadside assistance to come help. your insurance company or other provider who may be able to help. If you're in an emergency situation or are not sure who to contact, call 911 or the local police for help.
Hope this helps :)
Based on the following passage, why might the government use the U.S. Army Corps of Engineers to undertake hydroelectric power projects instead of allowing private businesses to undertake them?
Before World War I, most power projects were developed by private interests. During the Great Depression, president Franklin Roosevelt developed federal hydropower projects to give low-cost energy to consumers. The U.S. Army Corps of Engineers undertook three major hydroelectric power projects during this era: the Bonneville Dam on the Columbia River, the Fort Peck Dam on the Missouri River, and the Passamaquoddy Tidal Power Project in Maine. Congress organized the Bonneville Power Administration in 1937 to distribute the power and set usage rates for all power generated at Bonneville Dam.
Hydroelectric power is closely linked to national security.
Private businesses are by law disallowed from engaging in hydroelectric power projects.
The government would have less power to control the cost of electricity from privately funded projects.
Private businesses have less expertise in hydroelectric power than the U.S. Army Corps of Engineers.
Answer:
The government would have less power to control the cost of electricity from privately funded projects.
Explanation:
According to the given excerpt, the government, the government decided to take over most of the hydroelectric power projects as opposed to privately owned corporations which previously held a monopoly. The major reason was to provide low-cost energy to consumers.
This decision taken by the government to use the Army Corps of Engineers to undertake hydroelectric power projects instead of allowing private businesses to undertake them was to allow the government have more power to control the cost of electricity.
technician A says that incandescent bulbs resist vibration well. Technician B says that HID headlamps require up to approximately 25,000 volts to start. Who is correct
Answer:
Both a and b.
Explanation:
HID headlamps require high voltage ignition to start just like street lamps. It requires almost 25,000 volts to start HID head lamps but require only 80 to 90 volts to keep it operating.
Assume that the signature consists of the object constant Me, the unary predicate constant Male, and the binary predicate constant Parent, and nothing else. Which of the following first-order logic formulas express the following English sentence? "I have a granddaughter" ∀x∀y( Parent (x,Me)∧ Parent(Me, y) ∧¬ Male (x)) ∀x∀y( Parent ( Me, x)∧Parent(x,y)∧¬Male(x)) ∀x∀y( Parent (x,Me)∧Parent(Me,y)∧¬ Male (y)) ∀x∀y( Parent ( Me, x)∧ Parent (x,y)∧¬ Male (y))
The nested formula is ∀x∀y(Parent(Me,x) ∧ Parent(x,y) ∧ ¬Male(x) ∧ ¬Male(y)).
The first-order logic formulas that express the following English sentence "I have a granddaughter" are: `∀x∀y(Parent(Me,x) ∧ Parent(x,y) ∧ ¬Male(x) ∧ ¬Male(y))`.
Let's break down the solution and see how it was derived:
The domain of discourse is individuals and the signature consists of the object constant Me, the unary predicate constant Male, and the binary predicate constant Parent. "I have a granddaughter" can be expressed as there is an x such that x is the child of a parent of Me and x is female.
Therefore, we can use a nested formula to represent that the person is a female and the child of a child of Me.
The nested formula is represented by: ∀x∀y(Parent(Me,x) ∧ Parent(x,y) ∧ ¬Male(x) ∧ ¬Male(y)).
Hence, the correct option is: ∀x∀y(Parent(Me,x) ∧ Parent(x,y) ∧ ¬Male(x) ∧ ¬Male(y)).
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Link OA has a constant counterclockwise angular velocity w. At the position shown, prove that the magnitudes of the angular velocities of the three links are identical (i.e., w = WAB = wc).
Link OA has a constant counterclockwise angular velocity w.We have shown that the magnitudes of the angular velocities of the three links are identical: w = WAB = wc.
To prove that the magnitudes of the angular velocities of the three links in Link OA are identical, we need to analyze the geometry and kinematics of the system.
Let's denote the angular velocity of Link OA as w (counterclockwise). We will prove that the angular velocities WAB and wc are also equal to w.
Consider the following points and distances in the system:
O: The point of rotation for Link OA.
A: The point where Link OA is connected to Link AB.
B: The point of rotation for Link AB.
C: The point where Link AB is connected to Link BC.
We can apply the concept of relative motion between points to determine the angular velocities.
Angular Velocity of Link OA (w):
At point O, the angular velocity of Link OA is w (given).
Angular Velocity of Link AB (WAB):
At point A, the angular velocity of Link AB with respect to Link OA is the sum of the angular velocities of Link OA and Link AB.
Thus, we can write:
WAB = w + w (angular velocity of Link OA at A) = 2w.
Angular Velocity of Link BC (wc):
At point C, the angular velocity of Link BC with respect to Link AB is the difference between the angular velocities of Link AB and Link BC.
Considering the clockwise direction of Link BC, we have:
wc = WAB - w = 2w - w = w.
Therefore, we have shown that the magnitudes of the angular velocities of the three links are identical: w = WAB = wc.
This result indicates that the angular velocities of the links in the system are equal and consistent with the given constant counterclockwise angular velocity of Link OA.
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How large a force is required to accelerate a 1300 kg car from rest to a speed of 20 m/s in a distance of 80 m?
F=m*a
F=80*20
F =1600 ans"
Answer: basically we are asked to find it's force and the formula that helps us to find force is Force= Mass× Acceleration
so let's put out the given and what we need to find
GIVEN. Solution
F=m.a
Mass= 1300. F=1300kg×20m/s
speed (Acceleration)=20m/2. F=26000Kg.m/s
Force=? F=26000N
N stands for Newton and the reason that it comes Newton is because it is the SI-unit of Force and the result of kg×m/s.
a caisson is a watertight enclosure that can be pumped dry so that construction activities, such as the construction of piers can take place. _______
A caisson is a watertight enclosure that can be pumped dry so that construction activities, such as the construction of piers can take place. A caisson is a watertight structure or chamber, usually made of wood, metal, or concrete, that is sunk to the bed of a river, lake, or ocean to provide a foundation or support for a bridge, building, or other structure.
A caisson is constructed onshore and then floated to the location where it is to be sunk into the water. Once in place, water is pumped out of the caisson, and construction workers enter the dry chamber to begin work on the foundation or support structure. The use of caissons has been an important development in the construction of bridges and other structures in areas with deep water or unstable soils.
A foundation called a caisson is used in construction on soft or deep water. It involves filling a series of large, watertight cylinders with concrete and sinking them into the ground. The base serves as a solid foundation for any subsequent structures. The construction of large structures like bridges, docks, and caissons is common.
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The 48-W fan of a central heating system is to circulate air through the ducts. The analysis of the flow shows that the fan needs to raise the pressure of air by 50 Pa to maintain flow. The fan is located in a horizontal flow section whose diameter is 30 cm at both the inlet and the outlet. Determine the highest possible average flow velocity in the duct. (Round the final answer to one decimal place.)
Answer:
3.39 m/s
Explanation:
The fan need to maintain a pressure (p) of 50 Pa, also the power = 48 W.
The surface area of the duct (A) is given as:
\(A=\pi D^2\\\\But\ D=diameter =30cm=0.3m\\\\Hence:\\\\A=\pi(0.3)^2=0.283\ m^2\)
The mass flow rate is given by the formula:
\(P=\dot{m}.\frac{p}{\rho}\\ \\m=\frac{P*\rho}{p}\\ \\\)
The velocity (V) in the duct can be calculated from the formula:
\(\dot{m}=\rho*V*A\\\\V=\frac{\dot{m}}{\rho*A}\\ \\Substituting\ \dot{m}=\frac{P*\rho}{p}\\ \\V=\frac{\frac{P*\rho}{p}}{\rho *A}\\ \\V=\frac{P}{p*A}\\ \\V=\frac{48}{50*0.283}=3.39\\ \\V=3.39\ m/s\)
The component has an exponentially distributed reliability with a mean of 2000 hours what is the probability that it will fail after 3000 hours?
Answer:
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Which statement best explains why pneumatic cylinders need to be smaller than hydraulic cylinders?
The pneumatic system only needs enough room to have an onloff switch installed in order to operate correctly.
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency
The control of the hydraulic system is much more precise and therefore requires a larger cylinder.
The fluid in a hydraulic system has more mass and therefore needs more storage space.
Answer:
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency.
Explanation:
I did it on edge and got it right.
Answer:
The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency
Thanks for points!!! :D
Discuss the targeted design properties for resorbable polyurethanes for tissue repair and non-resorbable polyurethane permanent implants. How can the properties of the polyurethane be tailored to the application by modifying the structure?
The property is that polyurethanes have a good tear resistance as well as tensile strength.
What is polyurethanes?Polyurethane is an umbrella word for a group of polymers formed via the condensation of polyisocyanates and polyalcohols. Despite its xenobiotic origins, polyurethane has been discovered to be biodegradable by naturally occurring microbes.
Polyurethanes are synthesized by reacting a polyol (an alcohol having more than two reactive hydroxyl groups per molecule) with a diisocyanate or a polymeric isocyanate in the presence of appropriate catalysts and additives
To manage cell fate and tissue healing, biodegradable polyurethane platforms have been used. Cell bonding, spreading, multiplication, and separation are all influenced by framework features such as compound, mechanical, and primary. These are not fully fixed as the science of biodegradable polyurethanes, platform manufacturing technologies, and surface change approaches.
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The compound beam shown in figure is pin connected at B. Determine the components of reaction at its supports. Neglect its weight and thickness.
The values based on the information given will be Ra = 1000N and Rc= 90N
What is weight?Weight refers to the measure of the force of gravity on an object, and is typically measured in units of mass, such as kilograms or pounds. Weight is influenced by the mass of the object and the strength of the gravitational field it is in.
Thickness, on the other hand, refers to the measure of how thick an object is, or the distance between opposite surfaces of an object. Thickness is typically measured in units of length, such as millimeters or inches.
While weight and thickness are not directly related to each other, they can both play important roles in determining the properties and uses of an object. For example, a thin piece of metal may be lightweight, but may not be strong enough to support heavy loads. Conversely, a thicker piece of metal may be heavier, but may be able to support heavier loads due to its increased strength.
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Anybody know anything?
Answer:
1. Be sure to use the correct type and size of screwdriver on every kind of screw to avoid injury to yourself or damage to equipment.
2. It is also unsafe to carry screwdrivers in pockets or to use them around moving machinery.
3. Screwdrivers are not safe to use as hammers or chisels or for prying.
Explanation:
Hãy tính phản lực liên kết tại ngàm A, bản lề C và gói di động D biết p=400N/m
P1=100N
P2=200
P3=300
M1=100N/m
N2=200N/m
Answer:
say in English plz I don't understand
Which activity is accomplished as part of the monitoring and controlling process? Completing the project documentation Completing the lessons learned review Assessing project quality Creating the network diagram
As part of the monitoring and controlling process in project management, one of the activities accomplished is assessing project quality.
This involves evaluating and measuring the project's deliverables and performance against predefined quality standards and criteria. It ensures that the project outputs meet the desired level of quality and helps identify any deviations or issues that may arise during project execution. This activity helps project managers take corrective actions and make necessary adjustments to maintain or improve project quality.
While completing project documentation, completing the lessons learned review, and creating the network diagram are important tasks in project management, they may be associated with other processes such as project closing, project review, or project planning, respectively, rather than being specifically part of the monitoring and controlling process.
Therefore, one of the activities accomplished is assessing project quality.
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Hi, can anyone draw me an isometric image of this shape?
Why should a person work with only one hand when possible?
drawing of twisted drill
Determine the required diameter of a steel transmission shaft 10 meters in length and material yield strength 350 MPa in order to resist a torque of up to 500 N.m. The shaft is supported by frictionless bearings at its ends. Design the shaft using the maximum shear stress theory, and selecting a factor of safety of 1.5. Neglect shaft weight.
Answer:
0.02795 m
Explanation:
Neglecting shaft weight Design the shaft using maximum shear stress theory and determine the required diameter
factor of safety = 1.5
length of shaft = 10 meters
material yield strength = 350 MPa
Torque = 500 N.m
The required shaft diameter = 0.02795 m
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