At t=0 a grinding wheel has an angular velocity of 21. 0 rad/s. It has a constant angular acceleration of 26. 0 rad/s2 until a circuit breaker trips at time t = 2. 10 s. From then on, it turns through an angle 438 rad as it coasts to a stop at constant angular acceleration. Through what total angle did the wheel turn between t=0 and the time it stopped?

Answer:

atlanta

Explanation:

just took the test

The reference point in this scenario is Atlanta.

The can be described as the starting point of the entire journey.

From the given statements the family started the journey from Atlanta and then traveled to Baltimore.

Atlanta is the start point (reference point) while Baltimore is the destination (finishing point).

Thus, the reference point in this scenario is Atlanta.

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Answer:

get some

get some ⛽⛽⛽⛽⛽

pour the ⛽ on the module,

get that on itttttt and booooooommmm

Explanation:

Answer:

B. The law of conservation of energy

Explanation:

The law of conservation of energy states that energy can neither be created or destroyed which means that a perpetual motion machine, which creates its own power and energy, cannot be true since energy cannot be created.

Electric Current:

Electric current is the flow of charge through a given circuit per unit time. Electric current is one of the components needed to calculate the electric power that a device needs to operate and do work. Electric current is measured in amperes (A), which is equal to:

            1A = 1 C/ s

Recall that the coulomb (C) is the unit for charge while the second (s) is the unit for time

Given: I = 3.5

A is the current

Δt =30 s is the time interval

                     A =ΔQ/ΔT

Net charge = 100C

Electricity is produced when an electric current runs through a circuit.

How does electric current work?

A current of electricity is a steady flow of electrons. When electrons move from one place to another, round a circuit, they carry electrical energy from place to place like marching ants carrying leaves. Instead of carrying leaves, electrons carry a tiny amount of electric charge.

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Answer:

false gravity is not considered matter

To make a galvanometer into an ammeter, connect a low resistance in parallel

Define resistor.

A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.

The obstruction to current flow in an electrical circuit is measured by resistance. Ohms are used to measure resistance. The current in each resistor is the same in a series circuit since the first resistor's output current feeds into the second resistor's input. All of the resistor leads on one side of the resistors are connected together in a parallel circuit, as are all of the leads on the other side.

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Answer:

A Peak

B Period

C 1/2 Period

D Trough

E Period

F 1/2 Period

Explanation:

Science

For the given charge the magnitude of electric field at 1 m is  4 times the electric field at 2 m.

Electric charge can create magnetic field as well electric fields.

According to the given question a charge is given and we need to find electric field at 2 different positions that is at 1 m and 2 m.

Electric field at 1 m is E1   E1 = Kq/r₁²

E1 = Kq / 1²

E1 = Kq -------- 1

Electric field at 2 m is E2 , E2 = Kq/ r₂²

E2 = Kq / 2²

E2 = Kq / 4 ---------- 2

After comparing E1 and E2 from the above equation 1 and 2

E1 = 4 E2

Thus electric field at 1 m is  4 times the electric field at 2 m.

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The above question is incomplete. Check complete question below:

The magnitude of the electric field 1 m away from the positive charge is _________ the magnitude of the electric field 2 m away .

1. equal to

2. one-quarter

3. four times

4. two times

5. one-half

Explanation:

what is the answer

The producer's surplus at a unit price of $1000 is approximately $313.35.

To find the producer's surplus at a unit price of $1000, we need to determine the supply function and integrate it from the quantity produced to the quantity at which the price equals $1000.

The given equation is p = 500e^(0.5q), where p is the price and q is the quantity produced.

To find the supply function, we can solve the equation for q in terms of p:

p = 500e^(0.5q)

Dividing both sides by 500:

e^(0.5q) = p/500

Taking the natural logarithm of both sides:

ln(e^(0.5q)) = ln(p/500)

0.5q = ln(p/500)

Simplifying:

q = 2ln(p/500)

Now, we want to find the producer's surplus at a unit price of $1000, so we need to calculate the surplus between the quantity produced and the quantity at which the price equals $1000.

Let's substitute p = $1000 into the equation:

q = 2ln(1000/500)

q = 2ln(2)

q ≈ 1.386

Now, to calculate the producer's surplus, we need to integrate the supply function from the quantity produced (0) to q ≈ 1.386:

Producer's Surplus = ∫[0 to 1.386] (500e^(0.5q) - 1000) dq

Performing the integration:

Producer's Surplus = [1000e^(0.5q) - 2000q] evaluated from 0 to 1.386

Producer's Surplus ≈ [1000e^(0.5(1.386)) - 2000(1.386)] - [1000e^(0.5(0)) - 2000(0)]

Producer's Surplus ≈ [1000e^(0.693) - 2772.72] - [1000 - 0]

Producer's Surplus ≈ 313.35

Therefore, the producer's surplus at a unit price of $1000 is approximately $313.35.

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A magnetic field can deflect an electron beam, but it cannot do any work on the beam because the force exerted by the magnetic field is always perpendicular to the velocity of the electrons.

The force exerted by a magnetic field on a moving charge is given by the Lorentz force law:

F = q(v × B)

where:

F is the force on the charge

q is the charge of the particle

v is the velocity of the particle

B is the magnetic field

The cross product (×) means that the force is perpendicular to both the velocity and the magnetic field. This means that the force does not do any work on the electrons, because work is defined as the product of force and distance.

In other words, the force of the magnetic field does not cause the electrons to move along the direction of the force, so it does not do any work on them.

Additional Information:

The fact that a magnetic field can deflect an electron beam but not do any work on the beam is used in many applications, such as televisions and electron microscopes.

In a television, the magnetic field is used to deflect the electron beam so that it can scan across the screen, creating the image. In an electron microscope, the magnetic field is used to deflect the electron beam so that it can be focused on a small area, allowing for high-resolution images.

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The final volume of the gas, work done, and the thermal energy transferred  is mathematically given as

vf=0,0623m^2

W=-4.03KJ

Q=-4.03KJ

Generally, the equation for the ideal gas   is mathematically given as

Pv=nRT

Therefore

vf=nRT/P

vf=2*8.314330/1*1.01*10^3

vf=0,0623m^2

In conclusion

vi=nRT/Pi

vi=0.1175m^3

w=pdv

w=2*8.314*330in()0.0623/0.117

W=-4.03KJ

Where

Q=W

Q=-4.03KJ

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It is important to note that the debate between scientific realism and antirealism is ongoing and complex, with various nuances and perspectives within each position. Different philosophers of science and scientists may hold different views on the nature of scientific terms and their relationship to reality.

According to a scientific realist perspective, scientific terms for unobservable phenomena such as "atom" and "black hole" are seen as referring to entities that truly exist in reality. Scientific realists believe that scientific theories and concepts accurately capture aspects of the world, including unobservable entities and phenomena. They argue that scientific theories provide the best explanation of the natural world and aim to describe the underlying structure and mechanisms of reality.

On the other hand, scientific antirealists hold a different view. They argue that scientific terms that refer to unobservable phenomena do not necessarily correspond to something that exists independently in reality. Antirealists often emphasize the instrumentalist view of science, which suggests that scientific theories are simply tools or frameworks that help us organize and predict observable phenomena, without making claims about the ultimate nature of reality.

Antirealists may argue that scientific theories are subject to revision and change over time as new evidence emerges, suggesting that the terms used to describe unobservable phenomena are not fixed and may not have a one-to-one correspondence with actual entities in reality. They may also highlight the role of social and cultural factors in shaping scientific knowledge, suggesting that scientific terms are influenced by human conventions and interpretations.

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Answer:

its false

Explanation:

because Longitudinal waves are in which particles of the medium move directio ni. parallel to the energy transport.

I think this is ur answer

Answer:

increases   increases   decreases

Explanation:

For an object falling from a height

Answer:

One gram atom of any substance contains one Avogadro number of atoms. Therefore, the number of atoms of U-235 present in 235 g of the substance = Avogadro Number = 6.02×10^23 atoms

The number of U-235 atoms present in 1 g of the substance = (6.02×10^23/235) atoms=2.56×10^21 atoms

Energy released in one atom fissioning = 200 MeV= 200 MeV × 1.6 × 10^-6 erg/MeV= 3.2 ×10^-4 erg/atom.

Energy released in the fission of all the atoms contained in 1g of Uranium-235 fissioning = (2.56×10^21 atom)×(3.2×10^-4 erg/atom)=8.19 ×10^17 erg

Now

1 kWh = 1000 Watt hour = 1000×( 10^7 erg/s)×3600s = 3.6 ×10^13 erg/kWh

So energy in kWh released in fission of 1 g of U-235 = (8.19× 10^17 erg)÷(3.6×10^13 erg/kWh) = 2.55 ×10⁴ kWh.

Added on 19th February, 2019.

The energy consumption of an average home in India in a month is between 300–500 kWh in the metropolitan cities. Let us take it at 400 kWh. So one gram of nuclear fuel (uranium) would be able to meet the energy requirements of a town of about 6000 for a month.

The energy in a fissile material is highly concentrated, compared to other types of fuels like wood, coal, diesel etc. So nuclear powered submarines can remain below water for very long periods of time, as they do not need to surface for getting fuel.

Explanation:

Energy in kWh released in fission of 1 g of U-235 is 2.55 ×10⁴ kWh.

One gram atom of any substance contains one Avogadro number of atoms. Therefore, the number of atoms of U-235 present in 235 g of the substance = Avogadro Number = 6.02×10^23 atoms

The number of U-235 atoms present in 1 g of the substance = (6.02×10^23/235) atoms=2.56×10^21 atoms

Energy released in one atom fissioning = 200 MeV= 200 MeV × 1.6 × \(10^{-6}\) erg/MeV= 3.2 ×\(10^{-4}\) erg/atom.

The energy released in the fission of all the atoms contained in 1g of Uranium-235 fissioning = (2.56×\(10^{21}\) atom)×(3.2×\(10^{-4}\) erg/atom) = 8.19 ×\(10^{17}\) erg

1000 Watt hour = 1000×( \(10^{7}\) erg/s)×3600s = 3.6 ×10^13 erg/kWh

So the energy in kWh released in fission of 1 g of U-235 = 2.55 ×10⁴ kWh.

Fission takes place when a neutron slams into a bigger atom, forcing it to excite and break up into smaller atoms—additionally referred to as fission products. Extra neutrons are also launched that may initiate a sequence reaction. whilst each atom splits, a high-quality amount of electricity is released.

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Answer:

The president is permitted to veto specific legislative acts, but Congress has ... and judicial appointments and on the approval for ratification of treaties. ... State shall have the Qualifications requisite for Electors of the most numerous Branch of the State Legislature. ... No Bill of Attainder or ex post facto Law shall be passed.

Explanation:

The answer is no. Hope this helps

The ball is moving at approximately 0.29 m/s after being released from the spring. Rounded to two decimal places, the final answer is 0.29 m/s

The potential energy stored in the compressed spring is given by:

\(U = (1/2) * k * x^2\)

where k is the spring constant, x is the compression distance, and U is the potential energy.

In this case, k = 26 N/m and x = 0.12 m. Substituting these values into the above equation, we get:

\(U = (1/2) * (26 N/m) * (0.12 m)^2U = 0.045 N*m = 0.045 J\)

The potential energy stored in the spring is converted into kinetic energy when the ball is released. The kinetic energy of an object with mass m moving at velocity v is given by:

At the instant of release, all the potential energy is converted to kinetic energy. Therefore, we can equate the two energies and solve for v:

K = U

\((1/2) * m * v^2 = 0.045 Jv^2 = (2 * 0.045 J) / mv^2 = (2 * 0.045 J) / 0.52 kgv^2 = 0.0865 m^2/s^2\)

Taking the square root of both sides gives us:

V= 0.294 m/s

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Answer:

Distance 50m

final velocity 20ms^-1

\(s = ut + \frac{1}{2} a {t}^{2} \\ = 0 \times t + \frac{1}{2} \times 4 \times {5}^{2} = 50m\)

\(v = u + at \\ v = 0 + 4 \times 5 \\ v = 20ms^{ - 1} \)

About 4.5 mol of water will be created when the platinum-based engine is run continuously at 300 K for an hour with 0.5 atm of H2 and 0.5 atm of O2 injected for each reaction.

For fuel cell engines' electrodes, platinum is a requirement. It acts as an electrocatalyst to speed up the electrochemical reactions needed to induce H2 to release electrons and form H2 ions when it is placed on porous electrodes.

Platinum is particularly well suited as a fuel cell catalyst because it makes it possible for the hydrogen and oxygen reactions to occur at an ideal rate and because it is stable enough to withstand both the intense electrical current density and the complex chemical environment found inside a fuel cell. This allows platinum to function effectively over an extended period of time.

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It depends on what direction you are running in, if it's forward, you'll have to keep to accelerating forward to keep running.

If you stop accelerating forward, you wouldn't be able to move forward.

H=132.3m and U=29.4ms−1 are height and velocity respectively.

What is motion?

Motion is a change in position of an object over time. It occurs when an object moves from one point to another. Motion can be described in terms of displacement, distance, speed, velocity, and acceleration. Motion can also be described using Newton's laws of motion which state that an object in motion will remain in motion unless acted upon by an external force. Motion also describes the motion of particles in a fluid or gas, as well as the motion of waves in a medium. Motion is an essential part of the physical world and is essential for understanding the fundamental laws of nature.

Motion in a straight line

Let,

u = Initial velocity of stone

H = Maximum height attained by the stone

v = final velocity at maximum height = 0

t = time taken to attain maximum height = 3s

a=−g= acceleration due to gravity

a. We know that,

V=u+at

0=u−g×3

U=3g=3×9.8ms−2

U=29.4ms−1

b. From the equations of motion, we know that,

S=ut+ ½ a t2

H=29.4×3+½ * 9.8 *32

H=88.2+44.1

H=132.3m

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Answer:

1 m/s so number 2 is the right one

Explanation:

so when it is at rest it still has some of the left over energy so it would be at 1 m/s

Answer:

Yes, it would be enough.

Explanation:

The volume of the tank (cylinder tank) is given by the following equation:

\(V_{initial}=\pi (\frac{D}{2})^{2}h\)

Where:

D is the diameter of the tank

h is the height of the tank

Now, the engineer makes a tank 1.26 times as big in heigh and 1.41 times as large with respect to diameter, then the new volume of this tank will be:

\(V_{new}=\pi (\frac{1.41D}{2})^{2}1.26h\)    

\(V_{new}=1.41^2*1.26\pi (\frac{D}{2})^{2}h\)

\(V_{new}=2.51\pi (\frac{D}{2})^{2}h\)

in terms of the initial volume:

\(V_{new}=2.51V_{initial}\)

Which means that the volume of the water could be doubled.

I hope it helps you!

Answer: 4 times as much

Explanation:

(A) This box glides, then slides up to 4.74 m before stopping . (B) The friction coefficient at the point of halting is 0.537. (C) The box would have slid 101.25 meters before coming to a stop if the coefficient of friction had stayed unchanged.

To solve this problem, we can use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:

Net work = ΔK.E.

We can break the motion of the box into two parts: before and after the rough section. Before the rough section, the box is moving with a constant velocity, so the net work done on it is zero. After the rough section, the box slows down and comes to a stop, so the net work done on it is equal to its initial kinetic energy:

Net work = -K.E.

(A) To find how far the box slides before stopping, we need to find the distance over which the box is acted upon by the increasing frictional force. Let's call this distance x.

W (friction) = ∫₀ˣ F f(x') dx'

here,

F f(x') is frictional force at a distance x' from point P.

Since the coefficient of friction increases linearly with distance, we can express F f(x') as:

F f(x') = μ₀ + (μ f - μ₀) * (x'/x f)

here,

μ₀ is initial coefficient of friction at point P,

μ f is final coefficient of friction at distance x f = 12.5 m, and

x' ranges from 0 to x.

Reserving expression of F f(x') into the integral for W (friction):-

W (friction) = μ₀ * x + (μ f - μ₀) * (x²/2x f)

Express initial kinetic energy as:-

K.E. = (1/2) * m * v²

here,

m is mass of the box and

v is its initial velocity of 4.50 m/s.

Setting the net work equal to the change in kinetic energy:-

= μ₀ * x + (μ f - μ₀) * (x²/2x f)

= (1/2) * m * v²

= x² - 2x f * [(μ f - μ₀)/μ₀] * x - 2x f * (K.E./(μ₀ * m))  

= 0

Putting given values of μ₀, μ f, x f, m, and v:-

x = 4.74 m

Therefore, the box slides for a distance of 4.74 m before coming to a stop.

(B) To find the coefficient of friction at the stopping point, we can use the same equation we derived earlier for W (friction) and solve for μ f:-

= W (friction)

= μ₀ * x + (μ f - μ₀) * (x²/2x f)

= -K.E.

= μ f

= (2 * K.E. + μ₀ * x * (μ f - μ₀)/x f) / x²

Putting given values of K.E., μ₀, μ f, x f, and x:-

μ f = 0.537

Therefore, the coefficient of friction at the stopping point is 0.537.

(C)  If the coefficient of friction remained constant at μ₀ = 0.1000, then we can simplify the equation we derived for x by setting μ f = μ₀:

= μ₀ * x + (μ₀ - μ₀) * (x²/2x f)

= (1/2) * m * v²

Simplifying the second term:-

μ₀ * x = (1/2) * m * v²

Solving for x:-

x = (m * v²) / [2 * μ₀ * W (friction)]

here,

W (friction) is work done by friction.

To find W (friction), we can integrate the frictional force over the entire distance traveled by the box:-

= W (friction)

= ∫₀ˣ F f(x') dx'

here,

F f(x') is constant frictional force of μ₀.

Reserving this expression for W friction into the equation for x:-

x = (m * v²) / (2 * μ₀ * F f * x)

here,

F f is constant frictional force of μ₀.

Simplifying:-

x = (m * v²) / (2 * μ₀ * F f)

Putting given values of m, v, μ₀, and F f:-

x = 101.25 m

Therefore, if the coefficient of friction had remained constant at μ₀ = 0.1000, the box would have slid for a distance of 101.25 m before coming to a stop.

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Answer:

in the opposite direction of the force

Answer:

The force applied moves the object in the direction of the force. Suppose if the force is applied to the moving object in that case object moves in the direction of the stronger force. Thus, according to the given question the applied force moves the object in its direction.

that means it's the 2nd option( in the opposite direction of the force