A freely falling object is dropped from rest, what is its speed after falling 1 second? 2 seconds? 3 seconds? 10 seconds?

A Freely Falling Object Is Dropped From Rest, What Is Its Speed After Falling 1 Second? 2 Seconds? 3

Answers

Answer 1

Answer:

You can use the formula: X= Vinitial.t + \(\frac{1}{2}\) g\(t^{2}\)

where: X: distance, which the question wants.

V initial = Zero

t= 1,2,3,10 sec.

g: is the acceleration due to gravity = 9.8 m/\(s^{2}\)


Related Questions

Fill The Blank? the tangential speed on the outer edge of a rotating carousel is _______.

Answers

The tangential speed on the outer edge of a rotating carousel is dependent on the carousel's rotational speed and the distance from the center of rotation to the outer edge.

It can be calculated using the formula: tangential speed = radius × angular speed

Where the radius is the distance from the center of rotation to the outer edge, and the angular speed is the rate of rotation measured in radians per second.

The carousel's rotational speed of a carousel refers to the rate at which it completes one full revolution, and it is usually measured in units of revolutions per minute (RPM) or radians per second (rad/s). The faster the carousel rotates, the higher the outer edge's tangential speed. The rotational speed of a carousel can be controlled by adjusting the power source that drives it, such as an electric motor.

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What mistake did Kamala make? Gamma rays should have a very high frequency, not a very low frequency. Visible light should have a low frequency and a long wavelength. Infrared light should have a short wavelength, not a long wavelength. Microwaves should have a high frequency and a short wavelength.

Answers

Answer:

The answer is "Option A".

Explanation:

Please find the complete question in the attached file.

Kamala uses Gamma radiation inside this question should be very high, not very low. Electromagnetic radiation is a penetrating type resulting from radioactive nuclear decline. Its radiation is a very high-frequency, radioactive waveform to frequencies greater than \(10^{19} \ Hz\) usually emitted from the radioactive decline.

What mistake did Kamala make? Gamma rays should have a very high frequency, not a very low frequency.

Answer:

A

Explanation:

edge 2022

A toy car has an initial velocity of 5 m/s and experiences a constant acceleration of 2.0 m/s2. How far does the toy car travel before reaching a velocity of 11 m/s? Write your answer to one decimal place.

Answers

Answer:t would be 17 m/s

If we use V2 = V1 + a*t

Sub in 5 for v1

2m/s*2 for a

And

6 for t

That should give you the answer.

help me plsssssssss

help me plsssssssss

Answers

Answer:

It is the first one

Explanation:

they (simple machine) can be defined as the simplest mechanisms that use mechanical advantage (also called leverage) to multiply force like a plow or something.

If a force of 10 N stretches a spring 0.5 m, what is the spring constant?

Answers

Answer:

the spring would be a constant of 10.5 m

4. A sprinter begins from rest and accelerates at the rate of 2 m/s2 for 200 m.
a) What is the sprinter's velocity at the end of the 200 m?
b) How long does it take him to cover it?
c) What is his average velocity?

Answers

Answer:

v=28.28m/s t=14.14s average velocity =2m/s

Explanation:

Starting at rest the initial velocity is 0 substituting that in the first equation of motion v=u+atgives the final velocity but we first have to determine the time using the third equation of motion which is s=ut+1/2at^2 and then do the substitution. Average velocity is the determined by adding the initial and final velocity then divide it by 2

1.A Radio station broadcasts modern song on medium wave 350 Hz every day at ten o’clock in the morning. The velocity of radio wave is 3X108 ms-1. The wavelength of another wave created in water is one percent of the radio wave and the velocity of sound in water is 1450 ms-1.
How many times of the frequency of the radio wave that of the wave created in the water? Analyze mathematically.

Answers

Answer:

\(ans \: = \boxed{{4.8 \times 10}^{ - 4} Hz}\)

Explanation:

\(given \to \\ f_{r} = 350 \: \\ v_{r} = {3 \times 10}^{8} \\ but \to \\ v = f \gamma \to \: \gamma = \frac{v}{f} : hence \to \\ \gamma _{r} = \frac{v_{r}}{f_{r}} = \frac{3 \times 10^{8} }{350} = \boxed{857,142.85714 \: m}\\ therefore \to \\ given \to \\ f_{w} = water \: frequency = \: \boxed{ ?}\: \\ v_{w} = 14 50 \\ but \to \\ v = f \gamma \to \: \gamma = \frac{v}{f} : hence \to \\ \gamma _{w} = \frac{v_{w}}{f_{w}} = \frac{1}{100} \times \gamma _{r} = \frac{1}{100} \times 857,142.85714 \\\gamma _{w} = \boxed{8,571.4285714 \: m} : hence \to \: \\ f_{w} = \frac{v_{w}}{ \gamma _{w}} = \frac{1450}{8,571.4285714} = \boxed{0.1691666667} \\ if \: the \: number \: of \: times = \boxed{ x} \\ f_{r} (x)=f_{w} \\ (x) = \frac{f_{w}}{f_{r}} = \frac{0.1691666667}{350} = 0.0004833333 \\ hence \to \\ the \: frequency \: of \: the \: radio \: wave \: is \to \: \boxed{{4.8 \times 10}^{ - 4} }\: \\ that \: of \: the \: wave \: created \: in \: the \: water.\)

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Please help me

Question 1 . For a sound wave, the pitch is determined by which wave characteristic?

A-frequency
B-amplitude
C-wavelength
D-period

Question 2 - Which of the following waves cannot be transmitted through a vacuum

1-Ultraviolet radiation
2-Microwaves
3-Sound waves
4-Gamma rays

Question 3- Which of the following could be the value of a wavelength that is found in the visible region of the electromagnetic spectrum

A 5 × 10^-9 m
B. 5 × 10^-7 m
C. 5 × 10^-2 m
D. 5 × 10^-5 m


Question 4- Sophie is trying to measure the speed of sound. She stands 24.0 m away from a wall and claps repeatedly, changing the frequency until the echo synchronised with her claps. If she calculates the speed of sound as 325 m • s-1 how long did she wait between claps?

Give your answer in seconds, without units and correct to three significant figures.

Answers

Explanation:

1 For a sound wave, the pitch is determined by which wave characteristic?

A - Frequency

2 Which of the following waves cannot be transmitted through a vacuum?

C - Sound waves

3 Which of the following could be the value of a wavelength that is found in the visible region of the electromagnetic spectrum?

B - 5 × 10^-7 m

4 Sophie is trying to measure the speed of sound. She stands 24.0 m away from a wall and claps repeatedly, changing the frequency until the echo synchronized with her claps. If she calculates the speed of sound as 325 m • s-1 how long did she wait between claps?

The time between her claps and the echo is twice the time it takes for the sound to travel from her to the wall. Therefore, the time between her claps is:

time = distance/speed = 2 x 24.0 m/325 m/s = 0.148 seconds (to three significant figures).

So the answer is 0.148, without units and correct to three significant figures

This 800 kg dragster gets up to 100 miles per hour from rest in 0.8 s.

a. What is the change in momentum of the dragster? (4 pt)
b. What is the average force exerted on the dragster? (4 pt)
c. What exerts that force? (2 pt)

Answers

Answer:

here,

the mass of car , m = 800 kg

the initial speed of car , u = 100 mph

u = 44.7 m/s

time taken , t = 0.8 s

a)

the change in momentum of the car , dP = Pf - Pi

dP = m * 0 - m * u

dP = - 800 * 44.7 kg.m/s

dP = - 3.58 * 10^4 kg.m/s

b)

the average force exerted on the car , F = dP /t

F = - 3.58 * 10^4 /(0.8) N

F = - 4.47 * 10^4 N

c)

this force is exerted by road on the car

Can someone please help

Can someone please help

Answers

99.16 Newtons is the new force of attraction between the particles.

What causes an atoms to attract one another?

The forces that hold atoms together to create molecules and solids are referred to as chemical bonds. The attraction between the electrons of one atom and the nuclei of another atom as a result of this electric force is what is known as a chemical bond.

\(F = (kq1q2)/r^2\)

\(9,916 = (kq1q2)/r^2\)

\(F = (k*(q1/5)*(q2/5))/(2r)^2\)

\(F = (1/100)((kq1*q2)/(r^2))\)

So, the new force of attraction is:

\(F = (1/100)*9,916 = 99.16\)Newtons (rounded to 4 decimal places)

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Which would have more matter: a 1 cm cube of lead or a 1 cm
cube of rubber?

Answers

Answer: 1CM CUBE OF LEAD

Explanation:

6. A student discovers an asteroid with a mass of 0.00041 earth masses orbiting the sun with an orbital
radius of 4.39AU. How long would the asteroid take to orbit the sun?
earth years

Answers

Every 1,580 days (4.33 years), 2004 TL10 completes one circle around the sun. Its distance from the sun orbit from 0.91 AU to 4.39 AU. Considering its brightness and how it reflects light,

Are asteroids circling the sun?

Along with rotating, often rather erratically, the asteroids tumble through their elliptical orbits around the Sun. More than 150 asteroids are known to have a small companion moon (some have two moons).

We orbit the Sun in what way?

A: Due to the way our solar system evolved, the planets of our solar system orbit the Sun in a counterclockwise manner (as viewed from above the Sun's north pole). A cloud of gas and dust gave birth to our Sun, and its byproducts, the solar nebula, later gave birth to the planets.

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The word _____ is defined as either of two points when the sun's rays strike the earth at the equator.

Answers

Answer:

Equinox.

Explanation:

It is Equinox because Equinox is defined as the time when the sun rays passes through the Earth's equator. This happen twice in the year around 21 March and 23 September. It is the time when the center of the sun is directly above the equator.

This normally occur when the Earth axis is either tilted toward or away from the sun which lead to equal amount of daylight and darkness.

a) We produce a diffraction pattern on a viewing screen by means of a long narrow slit illuminated by blue light. Does the pattern expand away from the bright center (the maxima and minima shift away from the center) or contract toward it if we I. switch to yellow light or II. Decrease the slit width? 02 x 02 = 04 Marks

Answers

Answer:

I. The angle θ increases, and the pattern expands away from the bright center

II. The angle θ increases, and the pattern expands away from the bright center

Explanation:

The given information are;

The light used to produce a diffraction pattern = Blue light

The formula for refraction is given as follows;

d × sin(θ) = n·λ

Where;

d = The inter slit distance

θ = The angle to the maxima

n = Number to the integer next fringe

λ = Light wavelength

The wavelength of blue light is between 450 and 495 nanometers

Therefore;

I. When we switch to yellow light

The wavelength of yellow light is between 590 and 560 nanometers, which is an increase in wavelength, given that d, the inter slit distance is held constant, the angle θ increases, and the pattern expands away from the bright center

II. Decrease the slit width

When the slit width is decreased, and the wavelength remains the same, the angle θ increases, and the pattern expands away from the bright center.

if the amount of work done remains constant but occurs over less time how does this affect the amount of power exerted?

Answers

Answer:

The amount of power will be increased.

Explanation:

If the work remains constant but the time is reduced the power increases. Since power is defined as the relationship between work overtime. By means of the following equation, we can see this relationship.

\(P=W/t\)

where:

P = power [Watts]

W = work [J] (units of joules)

t = time [s]

Let's assume with an example the above written.

If we have an electric motor that exerts a work of 950 [J], and the time used is 5 [s], the power is:

\(P = 950/5\\P = 190 [W]\)

Now if we want to accelerate the work done and use 2 seconds for the time, we will have:

\(P=950/2\\P=475 [W]\)

We want to see how maintaining the work constant but reducing the time in which it occurs affects the power. We will see that the power increases.

We define power as the amount of work done per unit of time.

So we can compute power as the quotient between the work done and the time in which it is done.

So, if we reduce the time in which the work is done, then the denominator is smaller, thus, the power will be larger.

This means that maintaining the work constant, and reducing the time in which it is done, increases the amount of power exerted.

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Which of the following statements is false?

Dissolving salt into water is an example of a mixture.

The mass of one piece of paper is the same even after it is ripped in half and the 2 pieces are measured again.

Increasing the temperature of water to a boil is a physical change.

The formation of a precipitate is the only way to see if a chemical change has occurred.

Answers

Answer: the last 1
Explanation: because it is

A toy car with a mass of 8 kg and velocity of 5 m/s to the right collides with a 5.28 kg car moving to the left with a velocity of 1.65 m/s. After the collision, the 8 kg car continues forward with a velocity of 0.5 m/s. What is the new velocity of the 5.28 kg car after the collision?

Answers

This is a case of elastic collision.
The equation is m1v1i+m2v2i=m1v1f+m2v2f
Substituting we get:
(8)(5)+(5.28)(-1.65)=(8)(0.5)+(5.28)(v2f)
V2f=5.168m/s


3. What factors can contribute to an infant's ability to develop sensory competencies?

Answers

Answer:

Explanation:

Here's how to stimulate your baby's senses in age-appropriate ways:

Decorate the nursery with colorful, bold patterns. ...

Play hand games. ...

Use "baby talk." Studies have shown that the sing-song, fluctuating tones mothers use to talk to their babies are important for language development. ...

Hold your baby as much as possible.

20. There is a bell at the top of a tower that is 45 m high. The bell weighs 19 kg. The bell has
energy. Calculate it.

Answers

Explanation:

Find an energy is E =mgh, so E = 45*10*19=8550j

If a skateboarder is moving at 4 meters per second then changes its velocity to 10
meters per second over the course of 10 seconds what is the skateboards acceleration?

Answers

Answer:

i was doing this is it actually 0.6

Explanation:

;D

The acceleration of the skateboard from its initial velocity to the final velocity over the given time is 0.6m/s².

What is Motion?

Motion is simply the change in position of an object over time.

From the First Equation of Motion;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

Initial velocity u = 4m/sFinal velocity v = 10m/sTime elapsed t = 10sAcceleration of the skateboard a = ?

To determine the acceleration of the skateboard, we substitute our given values into the expression above.

v = u + at

10m/s = 4m/s + ( a × 10s)

( a × 10s) = 10m/s - 4m/s

a × 10s = 6m/s

a = 6m/s ÷ 10s

a = 0.6m/s²

Therefore, the acceleration of the skateboard from its initial velocity to the final velocity over the given time is 0.6m/s².

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6. Calculate the potential temperature of air that at pressure 50mb has temperature T=250 K

Answers

Calculate the potential temperature of air at 50mb and 250 K using the formula: potential temperature = temperature * (Reference Pressure / Current Pressure)^(R/Cp).the potential temperature of the air at a pressure of 50mb and a temperature of 250 K is approximately 369.25 K.

To calculate the potential temperature of air at a pressure of 50mb and a temperature of 250 K, you can use the formula for potential temperature:

Potential temperature = Temperature * (Reference Pressure / Current Pressure)^(R/Cp)

In this case, the reference pressure is typically taken as 1000mb, the gas constant for dry air (R) is approximately 287 J/(kg·K), and the specific heat at constant pressure (Cp) is approximately 1005 J/(kg·K).

Plugging in the values, we get:

Potential temperature = 250 K * (1000 mb / 50 mb)^(287/1005)

Simplifying the calculation:

Potential temperature = 250 K * 20^(0.2856)

Using a calculator, we can find that 20^(0.2856) is approximately 1.477.

So, the potential temperature of the air is:

Potential temperature = 250 K * 1.477

Calculating this, we find that the potential temperature of the air is approximately 369.25 K.

Therefore, the potential temperature of the air at a pressure of 50mb and a temperature of 250 K is approximately 369.25 K.

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Waves are caused by which energy

Answers

Answer:

Waves are most commonly caused by wind.

Explanation:

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest.

A leaf falls from a tree. Because the leaf is so light, it will be affected by air
resistance. Taking this into account, what is the acceleration of the leaf as it
falls?
O A. O m/s2
O B. Less than 9.8 m/s2
O C. Exactly 9.8 m/s2
O D. More than 9.8 m/s2​

Answers

Answer:

b

Explanation:

Answer: less than 9.8 m/s

Explanation:

A leaf falls from a tree. Because the leaf is so light, it will be affected by airresistance. Taking

What are MACHOs (massive compact halo objects)?

Answers

MACHOs, or Massive Compact Halo Objects, are a type of dark matter candidate consisting of large, non-luminous celestial bodies.


MACHOs are thought to be made up of baryonic matter (protons, neutrons, and electrons), but they do not emit or reflect enough light to be easily detected.

They are theorized to reside in the halo region surrounding galaxies like the Milky Way.

Examples of MACHOs include black holes, neutron stars, and brown dwarfs. Due to their massive size and gravitational influence, they are considered as potential contributors to the unaccounted mass in the universe, known as dark matter.

Hence, MACHOs are massive, non-luminous celestial bodies that serve as a dark matter candidate, possibly contributing to the unexplained mass in the universe. They are comprised of baryonic matter and can be found in the halo region of galaxies.

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As the wavelength of a wave gets shorter the frequency does what?

As the wavelength of a wave gets shorter the frequency does what?

Answers

The frequency gets lower

Answer:

It gets higher

Explanation:

The shorter it is, the higher the frequency.

A blue lab cart is traveling west on a track when it collides with and sticks to a red lab cart traveling east. The magnitude of the momentum of the blue cart before the collision is 2.0 kilogramdmeters per second, and the magnitude of the momentum of the red before the collision is 3.0 kilogramdmeters per second. The magnitude of the total momentum of the two carts after the collision is?

Answers

The magnitude of the total momentum of the two carts after the collision is 1 kg m/s west.

What is the total momentum of the two carts?

The total momentum of the two carts is calculated by applying the principle of conservation of linear momentum as shown below.

Mathematically, the formula for principle of conservation of linear momentum is given as;

Pf = Pi

where;

Pf is the final momentum of the systemPi is the initial momentum of the system

The magnitude of the momentum of the blue cart before the collision is 2.0 kilogramdmeters per second.

The magnitude of the momentum of the red before the collision is 3.0 kilogramdmeters per second.

The magnitude of the total momentum of the two carts after the collision is calculated as follows;

Pt = P (W) - P ( E )

Pt = 3 kg m/s - 2 kg m/s

Pt = 1 kg m/s

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the displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s − 2 sin t 1 3 cos t, where t is measured in seconds.

Answers

The average velocity or displacement of a particle for the first time interval is Δs / Δt = 6 cm/s.

Solution:

As we know that displacement is calculated in centimeters and the unit of time is second.

The average velocity for the first interval [1,2] is given

Δs / Δt = s (t2) - s (t) / t2 - t1

Δs / Δt = 2sin2  π  + 3cos 2 π -  ( 2sin π + 3cos π ) / 2 - 1

Δs / Δt = 2(0) + 3(1) - 2(0) - 3 (-1) / 1

Δs / Δt = 6 cm/s

Thus the average velocity or displacement of a particle for the first time interval is Δs / Δt = 6 cm/s

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The complete question is:

The displacement of a particle moving back and forth along a line is given by the following equation s(t) = 2sin π t + 3cos π t. Estimate the instantaneous velocity of the particle when t = 1

Calculate the voltage difference in a circuit that has a resistance of 24 Ohms if the current is 0.50A. Use the formula I= V/R.

Answers

Answer:

12V

Explanation:

from the formula, I=V/R

V=IR

V=24x0.50

Voltage difference in a circuit = 12V

a transmission tower is held by three guy wires attached to a pin at a and anchored by bolts at b, c, and d. if the tension in wire ab is 924 lb, determine the vertical force p exerted by the tower on the pin at a.

Answers

The vertical force exerted by the tower on the pin at A is 924 lb by understanding the principles of tension and equilibrium is essential in engineering and designing transmission towers.

The tension in the wire AB, which is 924 lb, is equal to the vertical force exerted by the tower on the pin at A. This is because in a state of equilibrium, the sum of all vertical forces acting on the tower must be balanced. The tension in the wire AB provides the vertical support necessary to counteract the tower's weight and maintain equilibrium.

In this scenario, the tower is held by three guy wires, with AB being one of them. The tension in AB is the only vertical force acting on the pin at A since the other guy wires (BC and BD) are anchored by bolts at points B, C, and D respectively. The tension in the wire BC and BD will have horizontal components that cancel each other out, resulting in no net vertical force on the pin at A.

Therefore, the tension in AB, which is 924 lb, is the vertical force exerted by the tower on the pin at A.

In a system of guy wires supporting a tower, the tension in each wire plays a crucial role in maintaining stability and equilibrium. By distributing the forces properly, the tower can withstand external loads and remain structurally sound.

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How much charge is on each plate of a 3.00-µF capacitor when it is connected to a 16.0-V battery?

Answers

Charge on each plate of 3.00µF capacitor is 48C when it is connected to a 16.0-V battery.

The capacitors capacity to store this electrical charge ( Q ) between its plates is corresponding to the applied voltage, V for a capacitor of known capacitance in Farads. Note that capacitance C is Dependably sure and never negative.The more prominent the applied voltage the more noteworthy will be the charge put away on the plates of the capacitor.

Moreover, the more modest the applied voltage the more modest the charge. Hence, the genuine charge Q on the plates of the capacitor and can be determined as:Capacitance is the deliberate worth of the capacity of a capacitor to store an electric charge. This capacitance esteem likewise relies upon the dielectric consistent of the dielectric material used to isolate the two equal plates. Capacitance is estimated in units of the Farad (F), so named after Michael Faraday.

So,we know that charge on capacitor is equal to=capacitance×Voltage

=>Q=C×V

We have C=3.00-µF ,V=16V

=>Q=3×16

=>Q=48Columb.

Hence,charge on each plate is 48C.

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