Where do the carbons and hydrogens go on this structure below?

5.6 moles

Given the decomposition of hydrazine to produce ammonia and nitrogen expressed as:

The balanced form of the equation is expressed as:

According to stochiometry, 3 moles of N₂H₄ produce 4 moles of NH₃, since there are 4.2 moles of N₂H₄ that react, the number of moles of NH₃ that will be produced is given as:

Hence the moles of NH₃ that form when 4.2 moles of N₂H₄ completely reacts is 5.6moles

According to the information, we can infer that a 19.2-pound child would need to take approximately 2.49 tablets of 250.0 mg ampicillin per day.

To calculate the number of tablets the child needs to take, we first need to convert the weight of the child from pounds to kilograms. Since there are 2.20 pounds in 1 kg, we divide 19.2 pounds by 2.20 to get the weight in kilograms, which is approximately 8.73 kg.

Next, we calculate the daily dose of ampicillin for the child by multiplying the weight in kilograms by the recommended dosage of 115 mg/kg.

Since the available tablet size is 250.0 mg, we divide the total daily dose by the tablet size to find out how many tablets the child needs to take per day.

According to the above, we can infer that since we can't have a fraction of a tablet, we round the result to the nearest whole number. Therefore, a 19.2-pound child would need to take approximately 2.49 tablets (rounded to 2) of 250.0 mg ampicillin per day.

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The process's entropy change has the sign  ΔSsys > 0

The entropy of an isolated system never decreases, according to the Second Law of Thermodynamics.

This means that for a process to be spontaneous, the entropy of the system must increase.

This is the theory used in this question to predict the sign of the entropy change for the dissolution process.

In the given  question ,

This is an example of a dissolution process, which is an endothermic process because energy is required to break the strong ionic bonds of the solid.

Therefore, the entropy of the system increases as the molecules become more disordered, leading to a positive entropy change, ΔSsys > 0.

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Answer:

A .    \(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)

B.   \(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)

C.  The system is at steady state but not at equilibrium

Explanation:

Given that:

The volumetric flow rate of the water = 15 gallons per minute

The diameter of the pipe that leaves the pump is 1 inch.

A. The objective here is  to determine how much work flow is done by the water as it leaves the pump and enters the pipe

The work flow that is said to be done can  be expressed by the relation :

W = P × V

where;

P = pressure

V = volume

Also the given outlet pressure is the gauge pressure

The pressure in the pump P  is can now be expressed by the relation:

\(P_{absolute} = P_{guage} + P_{atmospheric}\)

\(P_{absolute}\) =  10 psig + 14.7 psig

\(P_{absolute}\) =  24.7 psig

W =  P × V

W =  24.7 psig  ×  15 gal/min

\(W = (24.7 \ psig * \dfrac{\frac{lb_f}{in^2}}{psig}) * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})\)

\(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)

Thus ; the rate of flow of work is said to be done by the water at \(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)

B.

Given that :

The water returns to the pool through an opening that is 1.5 inches in diameter.

where the pressure is 1 atm.

Then ; the rate of work done  by the water as it leaves the pipe and enter the pool is as follows:

W =  P × V

W = 1 atm  ×  15 gal/min

\(W = 1 \ atm * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})\)

\(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)

Thus ; the rate of flow of work done by the water leaving the pipe and enters into the pool is  at \(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)

C.

We can consider the system to be at steady state due to the fact that; the data given for the flow rate and pressure doesn't reflect upon the change in time in the space between the pump and the pool.

On the other-hand the integral factor why the system is not at equilibrium is that :

the pressure leaving the pipe is different from that of the water at the surface of the pool as stated in the question.

Answer:  

  The speed of an object is the distance the object travels in one unit of time. To calculate the speed of an object, divide the distance the object travels by the amount of time it takes to travel that distance.   Explanation:

Answer: SPEED is the distance traveled during a specific unit of time.

Explanation: I got it right! Have a good day guys :>

The mass of a single atom of carbon is 1.9 x 10-²³ g/atom (option A).

An atom is the smallest possible amount of matter which still retains its identity as a chemical element, now known to consist of a nucleus surrounded by electrons.

According to this question, the mass of a mole of carbon atoms is 12.011 grams.

1 mole of carbon atom = 12g

1 mole of a carbon atoms = 6.022 × 10²³ atoms

Hence, mass of 6.022 × 10²³ atoms of carbon = 12g

Mass of 1 atom of carbon = 12 ÷ 6.022 ×10²³ = 1.9 × 10-²³ g/atom.

Therefore, 1.9 × 10-²³ g/atom is the mass of a single atom of carbon.

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The net ionic equation of the reaction is:

A net ionic equation is an equation which shows only the ions that are involved in the formation of a product in the reaction as well as the product of the reaction alone. Spectator ions are omitted.

The net ionic equation of the reaction is given below:

Pb²⁺aq) + 2 I(aq) → PbI2(s)

In conclusion, a net ionic equation does not show spectator ions.

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Answer: B

Explanation:

Answer:

Yes this is true

Explanation:

Answer:

i have the same question for chemistry, do you have the answer?

Explanation:

Answer:26.9

Explanation:

1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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Answer:

Matter is anything that has mass and takes up space.  Matter can change form through physical and chemical changes, but through any of these changes, matter is conserved. The same amount of matter exists before and after the change none is created or destroyed. This concept is called the Law of Conservation of Mass.

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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The binding energy per nucleon for the ¹⁹F nucleon is equal to 7.786 MeV/nucleon.

Binding energy can be defined as the minimum quantity of energy that is required to remove the particle from the system. Nuclear binding energy can be described as the energy required to dismantle a nucleus of an atom into free neutrons and protons.

The binding energy will be determined from the mass defect. Mass defect is calculated from the difference between the mass observed and the expected combined mass.

Given the mass of the ¹⁹F = 18.9984 a.m.u.

The mass defect for the ¹⁹F can be calculated as:

Δm = \((M _n +M_p) - M_F\)

\(\triangle m =( 9\times 1.0078 + 10 \times 1.0087 )- 18.9984\)

\(\triangle m =0.1588 \;a.m.u.\)

The binding energy for the fluorine can be calculated as:

E = Δmc²

E = 0.1588 × 931.5

E = 147.92 MeV

The binding energy per nucleon of ¹⁹F can be calculated as:

B.E.N. = 147.92/18.9984 = 7.786 MeV per nucleon

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Answer:

A Brønsted-Lowry acid is a substance which donates protons to other substances. (option c.)

Explanation:

For Brønsted-Lowry acids, are the ones that donates protons and bases, the ones that accepts H⁺ from others compounds.

In this reaction:

NH₃  +  HCl → NH₄Cl

The hydrocloridic acid donates the proton to ammonia to make ammonium chloride. So the HCl, is a Brønsted-Lowry acid while the ammonia is a base.

There are cases, like water that behaves as acid and base.

These compounds are called amphoteric because it can donate H⁺ or OH⁻ at the same time.

H₂O ⇄  H⁺  +  OH⁻

Please mark this answer brainliest!!!

Answer:

Explanation:

55647 for b

Explanation:

the answer is C marbles hope you find it helpful

Answer:

Metals are lustrous, malleable, ductile, good conductors of heat and electricity. Other properties include: State: Metals are solids at room temperature with the exception of mercury, which is liquid at room temperature (Gallium is liquid on hot days).

Among the alkaline earth metals, beryllium (Be) has the fewest number of occupied electron shells.

The alkaline earth metals are a group of chemical elements in the periodic table that include beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra).

Among the alkaline earth metals, beryllium (Be) has the fewest number of occupied electron shells. Beryllium has an electron configuration of 1s2 2s2, meaning it has only two occupied electron shells: the first shell, which can hold up to two electrons, and the second shell, which can hold up to eight electrons. In contrast, the other alkaline earth metals have at least three occupied electron shells. For example, magnesium has an electron configuration of 1s2 2s2 2p6 3s2, meaning it has three occupied electron shells.

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Answer:

Ethylene glycol is a syrupy liquid at room temperature whereas polyethylene glycol is a solid material. The main difference between ethylene glycol and polyethylene glycol is that ethylene glycol has a fixed value for molecular weight whereas polyethylene glycol has no fixed value for molecular weight.

Answer:

monosaccharides and glycosidic, I think

Explanation:

Answer:

pasagottt po plss

Explanation:

edi wow

The piece of evidence that best identifies the type of reaction as nuclear or chemical is: Chemical, because a new substance is formed. Option 4

In this scenario, the observation that a new substance is formed is a key characteristic of a chemical reaction. Chemical reactions involve the rearrangement of atoms to form different substances with distinct properties. The formation of a new substance indicates a chemical change has occurred.

The other pieces of evidence listed do not necessarily point to a nuclear reaction:

Chemical, because energy is released during the reaction: Energy can be released in both nuclear and chemical reactions, so this observation alone is not sufficient to determine the type of reaction.

Nuclear, because energy is released during the reaction: While energy can be released in nuclear reactions, it is not exclusive to them. Chemical reactions can also release energy, such as in exothermic reactions.

Nuclear, because the mass decreased after the reaction: This observation suggests a change in mass, which could be indicative of a nuclear reaction. However, it is important to consider that chemical reactions can also involve changes in mass, such as the formation of gases or dissolution of a solid.

Overall, the most conclusive evidence to identify the type of reaction is the formation of a new substance, which aligns with a chemical reaction.

Option 4

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8.01 mol MgO

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Unbalanced] Mg + O₂ → MgO

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 8.01 moles Mg

[Solve] moles MgO

Step 2: Identify Conversions

[RxN] 2 mol Mg → 2 mol MgO

Step 3: Stoich

The heat absorbed by the solution is 386.9 cal.

First, we need to calculate the heat absorbed by the solution using the formula:

q = m × c × ΔT

Where q is the heat absorbed, m is the mass of the solution, c is the specific heat constant, and ΔT is the change in temperature.

m = 45.4 g

c = 1 cal/g oC

ΔT = 31.5 oC - 23.0 oC = 8.5 oC

Substituting the values in the formula, we get:

q = 45.4 g × 1 cal/g oC × 8.5 oC

q = 386.9 cal

Therefore, the heat absorbed by the solution is 386.9 cal.

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First, we need to write out the balanced chemical equation for the reaction: 4 KO2 + 2 CO2 → 2 K2CO3 + 3 O2

From the equation, we can see that 4 moles of KO2 react with 2 moles of CO2 to produce 3 moles of O2. Therefore, we need to convert the given masses of KO2 and CO2 into moles:

moles of KO2 = 2.61 g / molar mass of KO2 = 2.61 g / 71.10 g/mol = 0.0367 mol
moles of CO2 = 4.46 g / molar mass of CO2 = 4.46 g / 44.01 g/mol = 0.1013 mol

Next, we need to determine the limiting reagent (the reactant that will be completely consumed in the reaction) by comparing the mole ratios of KO2 and CO2 in the balanced equation. The ratio of moles of KO2 to moles of CO2 is:
0.0367 mol KO2 / 4 mol KO2 per 2 mol CO2 = 0.0184 mol CO2

Since this ratio is less than the actual number of moles of CO2 we have (0.1013 mol), CO2 is in excess and KO2 is the limiting reagent.

Using the mole ratio from the balanced equation, we can calculate the number of moles of O2 produced:

moles of O2 = 3 mol O2 per 4 mol KO2 × 0.0367 mol KO2 = 0.0275 mol O2

Finally, we can convert the moles of O2 to grams:

mass of O2 = moles of O2 × molar mass of O2 = 0.0275 mol × 32.00 g/mol = 0.88 g
Therefore, 2.61 g of KO2 and 4.46 g of CO2 would produce 0.88 g of O2.

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\(pH=-\log[H^{+}]\\\\\implies [H^{+}] =10^{-pH}=10^{-2.47}=0.0034~M\)

Answer:

78.7

Explanation:

The number has 4 significant figures: 7,8 6 and 5.

To round off to 3 significant figures, the target digit is the third significant figure in the number.The determining digit is the fourth significant figure in the number; it is 5 hence the target digit will go up by 1 and any digits to the right of it will be rounded down to 0.

The concentration of cobalt(II) ions in the final solution is 0.2069 M and the concentration of hydroxide ions is 3.25x\(10^{-8}\) M.

What is Solution?

A solution is a homogeneous mixture of two or more substances, where one substance (solute) is dissolved in another substance (solvent). The solute can be a solid, liquid or gas and is present in smaller amounts, while the solvent is present in larger amounts.

The balanced chemical equation for the reaction between cobalt(II) nitrate and sodium hydroxide is:

Co(NO3)2 + 2NaOH → Co(OH)2 + 2NaNO3

From the equation, we can see that the ratio of cobalt(II) nitrate to cobalt(II) hydroxide is 1:1. Therefore, the concentration of cobalt(II) ions in the final solution will be equal to the concentration of cobalt(II) nitrate before mixing.

Before mixing, the amount of cobalt(II) nitrate present in the solution is:

0.418 mol/L x 0.437 L = 0.182566 mol

The volume of the final solution is the sum of the volumes of the two solutions:

V = 0.437 L + 0.445 L = 0.882 L

The amount of cobalt(II) ions present in the final solution is therefore:

n = 0.182566 mol

The concentration of cobalt(II) ions in the final solution is:

[Co2+] = n/V = 0.182566 mol/0.882 L = 0.2069 M

Now we can calculate the Ksp of cobalt(II) hydroxide using the concentration of cobalt(II) ions and the given solubility product constant:

Ksp = \([Co2+][OH-]^{2}\) =\((0.2069 M)(x)^{2}\)

where x is the concentration of hydroxide ions, which we can assume to be equal to the concentration of sodium hydroxide since sodium ions and nitrate ions are spectator ions and do not participate in the reaction.

Solving for x, we get:

x = sqrt(Ksp/[Co2+]) = sqrt(5.92x10^-15/0.2069) = 3.25x\(10^{-8}\) M

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