Range be R and height be h
\(\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}\)
\(\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}\)
u=initial velocity
theta is angle of projection.
g=acceleration due to gravity
ATQ
\(\\ \sf\longmapsto R=2h\)
\(\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}\)
Cancelling required ones
\(\\ \sf\longmapsto sin^2\theta=sin2\theta\)
sin2O=2sinOcosO
\(\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta \)
\(\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2\)
\(\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2\)
\(\\ \sf\longmapsto tan\theta=2\)
\(\\ \sf\longmapsto \theta=tan^{-1}(2)\)
\(\\ \sf\longmapsto \theta=63.4°\)
Done
Option B is correct
A baseball travels 200 metes in 6 seconds, what is the baseball’s velocity?
Answer:
33.33 m/sec
Explanation:
A baseball travels 200 metes in 6 seconds,
what is the baseball’s velocity?
use the formula: velocity = distance over time
where (d) distance = 200 m
and (t) time = 6 sec.
plugin values into the formula:
v = d / t
= 200 m / 6 sec
= 33.33 m/sec.
therefore, the baseball's velocity is 33.33 m/sec
A person consumes 2 500 kcal/day while expending 3 500 kcal/day. In a month's time, about how much weight would this person lose if the loss were essentially all from body fat? (Body fat has an energy content of about 4 100 kcal per pound.)
Approximately 7.32 pounds, this person would lose wieght if the loss were essentially all from body fat.
A person consuming 2,500 kcal/day and expending 3,500 kcal/day experiences a daily caloric deficit of 1,000 kcal (3,500 - 2,500 = 1,000). Over a month, this deficit accumulates to 30,000 kcal (1,000 x 30 days). Since body fat has an energy content of about 4,100 kcal per pound, we can calculate the weight loss by dividing the total caloric deficit by the energy content of body fat.
Weight loss = Total caloric deficit / Energy content of body fat
Weight loss = 30,000 kcal / 4,100 kcal/pound
Weight loss ≈ 7.32 pounds
In a month's time, this person would lose approximately 7.32 pounds if the loss were essentially all from body fat. It's important to note that weight loss may vary depending on individual factors, and maintaining a healthy, balanced diet alongside regular exercise is crucial for overall well-being.
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what would you want the after life to be like. examples are heaven and hell ,reincarnation ,eternal darkness , reliving your live but different choices or become a ghost,
Answer:
i would want to be a dog or a cat
Explanation:
there just funny
What is the k_{sp} for mn(oh)_2 if the molar solubility of mn(oh)_2 is 3.7 x 10^{-5} m?
The ksp, or solubility product constant, for Mn(OH)2 can be calculated using the molar solubility of Mn(OH)2. The balanced equation for the dissociation of Mn(OH)2 is:
\(Mn(OH)2 ⇌ Mn2+ + 2OH-\)
The molar solubility of Mn(OH)2 is given as 3.7 x 10⁻⁵ M. This means that at equilibrium, the concentration of Mn2+ is also 3.7 x 10⁻⁵ M, while the concentration of OH- is 2 times that, or 7.4 x 10⁻⁵ M.
To calculate the ksp, we need to multiply the concentrations of the ions raised to their stoichiometric coefficients. In this case, the stoichiometric coefficient of Mn2+ is 1, while that of OH- is 2.
ksp = [Mn2+][OH-]²
= (3.7 x 10⁻⁵)(7.4 x 10⁻⁵)²
Calculating this expression gives us the ksp for Mn(OH)2.
ksp = (3.7 x 10⁻⁵)(7.4 x 10⁻⁵)²
To calculate the ksp for Mn(OH)2, we start by considering the balanced equation for its dissociation into ions:
Mn(OH)2 ⇌ Mn2+ + 2OH-. The molar solubility of Mn(OH)2 is given as 3.7 x 10⁻⁵ M.
This means that at equilibrium, the concentration of Mn2+ is also 3.7 x 10⁻⁵ M, while the concentration of OH- is 2 times that, or 7.4 x 10⁻⁵M.
To calculate the ksp, we need to multiply the concentrations of the ions raised to their stoichiometric coefficients. In this case, the stoichiometric coefficient of Mn2+ is 1, while that of OH- is 2. Thus, the ksp can be calculated as follows: ksp = [Mn2+][OH-]²
= (3.7 x 10⁻⁵)(7.4 x 10⁻⁵)².
By evaluating this expression, we can find the solubility product constant for Mn(OH)2.
The ksp for Mn(OH)2, given a molar solubility of 3.7 x 10⁻⁵ M, can be calculated as (3.7 x 10⁻⁵)(7.4 x 10⁻⁵)²
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Take some time to research a utility plant. If there is one in your area, you may even visit it. Otherwise, look up a type of plant that produces energy - such as a nuclear power plant, a hydroelectric plant, or a coal-burning plant. Find out what energy resources are brought into the plant. Then find out what energy and what “waste” is produced by the plant. Describe how the two Laws of Thermodynamics apply to what you find out in your research. Be thorough. You will be using the information you gather to engage in a debate with your class about thermodynamics.
Answer:
bro we cant do this
Explanation:
Answer:
The energy resource brought into a coal power plant is coal.
Found the answer at: https://www.tva.com/energy/our-power-system/coal/how-a-coal-plant-works#:~:text=Coal%2Dfired%20plants%20produce%20electricity,to%20start%20the%20process%20over.
The waste produced by coal power plants is coal ash and the energy produced by coal power plants is electricity.
Answers found at: http://www.groundtruthtrekking.org/Issues/AlaskaCoal/Coal-Ash-Combustion-Wastes.html and https://www.tva.com/energy/our-power-system/coal/how-a-coal-plant-works#:~:text=Coal%2Dfired%20plants%20produce%20electricity,to%20start%20the%20process%20over.
The two laws of thermodynamics apply to what I found out in my research because I know that the entropy increase due to the combustion of conventional fuels is much larger than that resulting from that of nuclear fuels, and is therefore much more dangerous. Also, I know that heat is used to burn coal and create energy.
Found answer at: https://www.encyclopedie-energie.org/en/energy-consumption-and-entropy-release-in-the-biosphere/
Explanation:
Hope this helps, i got an okay score on it but better than nothing i guess lol
. If the electrical force of repulsion between two same amount of charges is 10 N, andthey are 30000 m apart. What is the magnitude of each charge?
Answer:
Explanation:
Given: q₁ = q₂,
F= 10 N,
distance between two charges, r = 30000 m.
We have, \(F = \frac{q_{1} q_{2} }{4\pi Er^{2} }\)
Hence, \(q_{1} q_{2} =F * 4\pi *E *r^{2}\)
E (epsilon) =\(8.85 * 10^{-12} C^{2} /Nm\)
Substituting the values, we have,
\(q_{1} q_{2} = 1 C\)
Hence \(q_{1} = q_{2} = 0.5 C\)
at what time ABC or D is the writer accelerating upwardwhat is the magnitude of the maximum acceleration experienced by the rider
We will have the following:
From the graph we can see that the point at which it is accelerating upward is at point C. [We can see that where the slope of the function is positive the acceleration will be positive]
We determine the maximum magnitude of the acceleration of the rider by using the maximum force, that is:
\(F=m\cdot a\Rightarrow1.20N=a=\frac{1.20N}{m}\)So, the maixmum magnitude of the acceleration will depend on the mass of the rider. Now, since the mass cannot be 0 kg since that would undetermine the expression we know then that the best approximation is:
\(a=\frac{1.20N}{m}\)Where "m" is the mass of the rider in kg. Since we are not given a mass, then the acceleration can only be expressed as the force divided by the mass of the rider.
the pressure in a reciprocating air compressor starts at 14.7 psia. the volune of air in the compressor starts at 5 cubic inches at a temp of 530 degrees rankine. if the piston then compresses the gas to a pressure of 100 psia and its temp increases to 640 dregrees rankine whats the final volume of the air
The final volume of the air in the compressor is approximately 7.981 cubic inches.
To determine the final volume of the air in the compressor, we can use the ideal gas law, which states that the pressure times the volume divided by the temperature is equal to a constant.
Given:
Initial pressure (P1) = 14.7 psia
Initial volume (V1) = 5 cubic inches
Initial temperature (T1) = 530 degrees Rankine
Final pressure (P2) = 100 psia
Final temperature (T2) = 640 degrees Rankine
Using the ideal gas law equation: P1 * V1 / T1 = P2 * V2 / T2
We can rearrange the equation to solve for the final volume (V2):
V2 = (P1 * V1 * T2) / (P2 * T1)
Substituting the given values into the equation:
V2 = (14.7 psia * 5 cubic inches * 640 degrees Rankine) / (100 psia * 530 degrees Rankine)
Calculating the value:
V2 ≈ 7.981 cubic inches
Therefore, the final volume of the air in the compressor is approximately 7.981 cubic inches.
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Which Case clause will be true whenever the value of the selector in a Select Case blockis greater than or equal to 7?A. Case Is >7B. Case Is = 8C
The correct case clause would be A. Case Is >7.
In a Select Case block, the case clauses are used to check different conditions against a selector value. The selector value is compared with each case clause, and the first matching case clause is executed.
To determine which case clause will be true when the selector value is greater than or equal to 7, we need to consider the available options:
A. Case Is >7: This case clause will be true when the selector value is greater than 7.
B. Case Is = 8: This case clause will be true only when the selector value is exactly 8.
Since we are interested in finding the case clause that matches when the selector value is greater than or equal to 7, option A (Case Is >7) is the correct choice. It covers all values greater than 7, including 8 and any other number greater than 8.
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Part (A) A light, rigid rod of length
ℓ = 1. 00 m
joins two particles, with masses
m1 = 4. 00 kg
m2 = 3. 00 kg
at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod. Determine the angular momentum of the system about the origin when the speed of each particle is 6. 40 m/s.
I got the answer to be 22. 4 with a +z direction.
Part (B) What would be the new angular momentum of the system (in kg · m2/s) if each of the masses were instead a solid sphere 10. 5 cm in diameter?
I'm not sure how this changes the equation. All my attempts are incorrect so far
In Part A, the angular momentum of the system about the origin can be calculated using the formula:
L = r × p, where r is the position vector from the origin to the center of mass of the system, and p is the linear momentum of the system. In this case, since the system is rotating in the xy-plane about the origin, the angular momentum is in the +z direction. The position vector r is perpendicular to the plane of rotation and has a magnitude of ℓ/2. The linear momentum of each particle is mvi, where vi is the speed of the particle. Using this information, we can calculate the angular momentum of the system as: L = (ℓ/2) × (m1v1 - m2v2). Substituting the given values, we get: L = (1/2) × (4.00 kg × 6.40 m/s - 3.00 kg × 6.40 m/s) = 22.4 kg·m^2/s. In Part B, we need to find the new angular momentum of the system if each of the masses were instead a solid sphere 10.5 cm in diameter. In this case, we can assume that the spheres rotate about their own center of mass. The moment of inertia of each sphere can be calculated using the formula for the moment of inertia of a solid sphere: I = (2/5) × mr^2, where m is the mass of the sphere and r is the radius of the sphere. Substituting the given values, we get: I = (2/5) × (m/4π) × (10.5/200)^2, where m = 4.00 kg for one sphere and m = 3.00 kg for the other sphere. The total moment of inertia of the system can be found by adding the moments of inertia of the two spheres. We can then use the formula for the angular momentum of a rotating object: L = Iω, where ω is the angular velocity of the system. However, we do not have enough information to find the angular velocity ω. Therefore, we cannot find the new angular momentum of the system with the given information.
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A wave has a frequency of 450 Hz and a wavelength of 0.52 m. What is the speed of the wave?
Answer:
Explanation:
ave speed is always (frequency) x (wavelength)
Speed = (450 /sec) x (0.52 m)
= 234 m/sec .
Height can be calculated from GPE by
O.5mv^2
O PE/gh
O PE/mg
O mgh
Height can be calculated from GPE by mgh.
What is GPE?Gravitational energy or gravitational potential energy is the potential energy that a massive object has due to gravity relative to another massive object. It is the potential energy associated with the gravitational field that is released when objects fall towards each other. Gravitational potential energy depends on several things: it depends on the mass of the object, the gravitational acceleration of the object due to the ground, and the displacement of the object from the ground. Gravitational potential energy is measured in joules (J).
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A 250 kg cannon containing a cannonball is initially at rest. If the cannon shoots the 20 kg cannonball at 15 m/s, what is the magnitude of the recoil velocity of the cannon?
Answer:
hhgyujhkhgjghhjhhghjkhlhjkghghgh
Explanation:
Which of the following describes the correct order of energy conversions necessary to form electricity from solar panels?
Solar Heat Kinetic → Electric
Solar- Kinetic Heat → Electric
Solar 1 Heat → Electric
O Solar ->Electric
Answer:
hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9
Students perform an experiment in which they drop two eggs with equal mass from a balcony. in the first trial, the egg hits the ground and breaks. in the second trial, the egg hits a foam cushion and does not break or bounce. what conclusions about impulse can the students make? the impulse was greater in the first experiment because the egg broke. the impulse was greater in the second experiment because the egg did not break. the impulse was the same in both experiments because the egg came to a stop. the impulse cannot be determined without the mass and velocity of the eggs.
The impulse was greater in the first experiment because the egg broke.
What is impulse?The term impulse is defined a the product of the force and time. We know that the impulse is high when a large force acts for a short time.
From the experiment if the students, we can conclude that the impulse was greater in the first experiment because the egg broke.
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Answer:
The impulse was the same in both experiments because the egg came to a stop.
Explanation:
test
How is water vapour different from a mixture of hydrogen and oxygen atoms?
Answer: in water vapor hydrogen atoms are bonded to oxygen atoms. In a mixture of hydrogen and oxygen hydrogen atoms are bonded to hydrogen atoms and oxygen atoms are bonded to oxygen atoms.
Explanation:
An 8 000-kg aluminum flagpole 100-m long i heated by the un from a temperature of 10°C to 20°C. Find the work done (in J) by the aluminum if the linear expanion coefficient i 24 ´ 10-6 (°C)-1. (The denity of aluminum i 2. 7 ´ 103 kg/m3 and 1 atm = 1. 0 ´ 105 N/m2
The work done by the aluminum in 216 Joules.
The ratio of the increase in length to the original length for each degree increase in temperature is called the coefficient of linear expansion. The coefficient of linear thermal expansion describes the change in the length of a material as a function of temperature. A distinction is made between the average thermal coefficient of expansion and the physical coefficient of linear expansion.
calculation:-
Work done = msT2 -T1
= 8000000 g × 2 × 1/000000 ( 20- 10)
= 600
density = 2.7
work done per unit = 600/2.7
= 216 jolues
The volume expansion coefficient is three times the linear expansion coefficient. Heating an object changes its dimensions. It depends on your body type. Expansion can be done in length in which case it is called linear expansion. Heating a square wafer causes expansion in two planes lengthwise and widthwise. We call this range dilation.
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a jet was going 100 m/s. over a distance of 200m, the jet accelerated up to a speed of 150 m/s. how long did this take?
It took jet 1.6 seconds to accelerate from 100 m/s to 150 m/s over the distance of 200m.
What is Acceleration?Acceleration is defined as the rate of change of velocity (v) with respect to time. Mathematically, the instantaneous measurement of acceleration is given by-
a = dv/dt
Given is a jet moving at 100 m/s such that it accelerated to a speed of 150 m/s over the distance of 200m. From this, we can write -
Initial velocity [u] = 100 m/s
Final velocity [v] = 150 m/s
Distance covered [d] = 200m
Using the third equation of motion -
v² - u² = 2aS
150 x 150 - 100 x 100 = 2 x a x 200
250 x 50 = 400a
a = (250 x 50)/400
a = 31.25 m/s²
Using first law of motion -
v = u + at
150 = 100 + 31.25t
t = 50/31.25
t = 1.6 seconds
Therefore, it took jet 1.6 seconds to accelerate from 100 m/s to 150 m/s over the distance of 200m.
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Liquid ammonia flows through a pipe at a mass flow rate of 100
kg/s .
If the cross-sectional area of the pipe is 0.01
m^2, determine the flow rate of momentum through the
pipe.
The momentum flow rate through the pipe carrying liquid ammonia is 1 × \(10^6\) kg·m/s.
The flow rate of momentum (Ṁ) through the pipe can be calculated by multiplying the mass flow rate (ṁ) by the velocity (v). The speed can be determined using the equation v = ṁ / (ρA), where ρ is the density of the liquid ammonia and A is the pipe's cross-sectional area.
Given:
ṁ = 100 kg/s
A = 0.01 m²
Assuming the density (ρ) of liquid ammonia is 700 kg/m³, we can calculate the velocity (v):
v = ṁ / (ρA)
v = 100 kg/s / (700 kg/m³ × 0.01 m²)
v = 10000 m/s
Now, we can calculate the flow rate of momentum (Ṁ):
Ṁ = ṁv
Ṁ = 100 kg/s × 10000 m/s
Ṁ = 1 × \(10^6\) kg·m/s
Therefore, the momentum flow rate through the pipe is 1 × \(10^6\) kg·m/s.
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An experiment was set up to investigate the cooling of water in two flasks. One flasks was painted shiny white. The other was painted Matt black. The starting temperature of the hot water poured into both flasks was 80 degrees. Explain what other quantity had to be kept the same in both flasks to make the experiment fair.
Answer:
add add more hot water in the flask painted shiny white while less of it in the one painted Matt black
Explanation:
Let's name the flasks A and B respectively
flask A due to the nature of its exterior will tend to reflect heat from the environment thus will need more hot water while flask B since it painted in Matt black the heat will be absorbed from the environment thus will require less hot water
a 1000 kg car comes to a stop without skidding. the car's brakes do 50,000 j of work to stop the car. how much kinetic energy did the car have when the brakes were initially applied?
The kinetic energy of an object is the energy it possesses due to its motion. In this problem, the car comes to a stop without skidding, meaning that all of its initial kinetic energy is dissipated as work done by the brakes.
The work done by the brakes is given as 50,000 J, and we know that work is equal to the change in kinetic energy. Therefore, the initial kinetic energy of the car is also 50,000 J. This means that the car was moving with a significant amount of energy before the brakes were applied, which highlights the importance of braking systems in ensuring safety on the road.
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if the kinetic energy of a particle is tripled, by what factor has its speed increased?
Answer:
KE1 = 1/2 m v1^2
KE2 = 3 KE1 = 3 * 1/2 m v1^2 = 1/2 m v2*2
3 v1^2 = v2*2
v2 = 3^1/2 v1
What is the atomic number the atom shown?
A. 3
B. 13
C. 14
D. 27
Answer:
13
Explanation:
Brainlest pls
Answer:
B-13
Explanation:
The protons listed in the atom are 13, and the protons are the same number as the atomic number.
what 3 things are produced as a result of the fusion of two atoms
Answer:
Electron, proton and neutron
Explanation:
In each and every atom they are consist of electron, proton and neutron.
The development of fusion energy has not been successful so far because of the high temperatures needed for fusion to occur. It’s not clear when we will have the technology to accomplish this. Do you think the government should continue to fund fusion research? Give your reasons.
Government should continue to fund fusion energy research because:
it potentially will produce large amounts of energyscientific research could discover more feasible methods of fusion energy productionit is a very clean form of energyWhat is fusion energy?Fusion energy is the energy produced from fusion reactions.
Fusion reactions are a type of nuclear reaction in which small atomic nucleus are fused together to produce larger atomic nucleus with the release of large amounts of energy.
The Sun produces its energy from fusion reactions between hydrogen atoms to produce helium nucleus. This reaction takes place at very high temperatures.
It is important that the government continue to fund fusion energy research because:
it potentially will produce large amounts of energymore scientific research could discover alternative cheaper methods of fusion it is a very clean form of energyIn conclusion, the continuous government funding will make it possible to finally discover cheaper and more feasible ways to produce fusion energy.
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3. Ryan is driving a car at 22 m/s when he sees a child standing in the road. He takes 0.83 s to
react, then steps on the brakes and slows down at 7.11 m/s². How far does the car travel
before it stops?
Answer:
S1 = V0 t - 1/2 a t^2 to stop moving car
t = 22m/s / 7.11 m/s^2 = 3.09 sec to decelerate moving car
S1 = 22 * 3.09 - 1/2 ^ 7.11 * 3.09^2 = 34.0 m to decelerate car
22 m/s * .83 s = 18.3 m distance traveled due to reaction time
S = (34.0 + 18.3) m = 52.3 m or about 172 ft
2. A golfer wishes to chip a shot into the hole 50 m away on flat level ground. If the ball flies to a
maximum height of 25 m, what speed must it have initially to reach the hole?
The speed the golf which is in projectile motion must have initially to reach the hole is 31.321 m/s.
What is projectile?A projectile is any object which is thrown into the space upon which the only acting force is the gravitational force. The primary force which is acting on a projectile is only gravity. This does not necessarily mean that other forces do not act on the object, just that their effect is minimal compared to the gravity.
A golfer wishes to chip a shot into the hole, which is 50 meters away on the flat level ground. If the ball flies to a maximum height of 25 meters.
The angle with which the ball flies,
tan θ = 25 m/ (50m/2)
tan θ = 1
θ = 45°
If u is the initial speed, the maximum height of the ball will be:
H = u² sin²θ / 2g
By putting the values, we get
25 = u² sin²45 / (2 × 9.81)
u = 31.321 m/s
Thus, the initial speed is 31.321 m/s.
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a typical person has a surface area of about 2m^2 and a layer of fat about 1cm thick (it can vary from 0.5 cm to 1.5 cm) . estimate the rate of heat loss in watts for someone who is lightly dressed sitting in a comfortable room with a temperature of 20 c
The energy output is 714 Watts is loss.
According to the thermal conductivity equation, the rate of heat loss H is given by:
H=\swhere,
K is the heat conductivity coefficient.
A is for Area of Cross Section.
H = Heat loss rate
Temperature differential between the two sides of the body in the given situation: x-Thickness of the material 71 -1
T = 37°C, or body temperature, and 12°C, or room temperature
initial instance.
A=2m x=0.01 m
H=174watt
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To determine
the force of an object what two measurements
are multiplied?
Answer:
Mass and acceleration
Using the conductor sizing guide, what conductor ampacity is needed for a 10-horsepower, 230-volt, single-phase motor: a.50 A
b.60 A
c.62.5 A
d.87.5 A
The correct conductor ampacity for a 10-horsepower, 230-volt, single-phase motor is option c. 62.5 A.
The ampacity of a conductor is a measure of the maximum amount of electrical current that can flow through it safely. The ampacity required for a motor is based on the size of the motor and the voltage of the electrical system. There are standard methods for determining the minimum ampacity for a given motor and voltage, such as the National Electric Code (NEC) and the American National Standards Institute (ANSI). The NEC and ANSI both state that the minimum ampacity for a 10-horsepower, 230-volt, single-phase motor is 62.5 amperes. It's important to note that using a conductor with ampacity lower than the recommended one may cause the motor to overheat and fail, leading to damage or even fire hazard.
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