Can someone please give me the (Answers) to this? ... please ...

I need help….

In dealing with multicollinearity, a common approach is to examine the Variance Inflation Factor (VIF) for each independent variable. VIF values larger than 10 indicate a potential issue with multicollinearity. When facing multiple independent variables with VIFs greater than 10, choosing the correct course of action is important.

a. It is not always advisable to eliminate the variable with the largest VIF, as it may hold valuable information for the model.b. Eliminating the variable that you think is the least related to the dependent variable can be a reasonable approach, provided that you have a strong rationale for your choice and the remaining variables do not exhibit severe multicollinearity.c. It is not recommended to eliminate all independent variables with VIFs larger than 10 at once, as this could lead to an oversimplified model that may not adequately capture the relationships between variables.d. If you cannot determine which variable is the least related to the dependent variable, eliminating the one with the largest VIF can be a practical approach, but it should be done cautiously, considering the potential impact on the overall model.
In conclusion, when multiple independent variables have VIFs larger than 10, it is important to carefully evaluate the relationships between the variables and the dependent variable to determine the most appropriate course of action, considering both the statistical properties and the underlying subject matter.

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Answer:

(1/3)(9*9*10)=270cm^3 pyramid volume

270/(4*4*4)=4.22cubes

round

5 wax cubes

The perimeter of triangle is 66.24 units.

What is triangle?

In Euclidean geometry, any 3 points, once non-collinear, verify a unique triangle and at the same time, a unique plane

Main body:

according to question :

c = 28

let the vertices be A,B,C

∠A= 30°

by using trigonometric ratios,

BC/ AB = sin30°

AB = C = 28

BC/28 = sin30°

BC = 28*sin30°

BC= 28*(1/2)

BC = 14

similarly

AB /CA = cos 30°

28/CA = √3/2

CA = 28*√3/2

CA = 14/√3

CA = 24.24

Hence , perimeter = AB +BC +CA = 28+14+24.24

                              =66.24 units

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4th term of an AP = 10

11th term exceeds 4th term by 1.

the sum of 20 terms ​

⟹ 11th term = 10 + 11 = 11.

We know that,

nth term of an AP (an) = a + (n - 1)d

Hence,

⟹ a₄ = a + (4 - 1)d

⟹ a + 3d = 10

⟹ a = 10 - 3d -- equation (1)

⟹ a₁₁ = a + (11 - 1)d

Substitute the value of a from equation (1).

⟹ 10 - 3d + 10d = 11

⟹ 7d = 11 - 10

⟹ 7d = 1

⟹ d = 1/7

Substitute the value of d in equation (1).

⟹ a = 10 - 3(1/7)

⟹ a = (70 - 3)/7

⟹ a = 67/7

Now,

Sum of first n terms of an AP (Sn) = n/2 * [ 2a + (n - 1)d ]

⟹ S₂₀ = 20/2 * [ 2(67/7) + (20 - 1)(1/7) ]

⟹ S₂₀ = 10 (134 + 19)/7

⟹ S₂₀ = 1530/7

∴ Sum of first 20 terms of the given AP is 1530/7.

I hope it will help you.

Regards.

Answer:

→ 11(2 + y) + 11y

→ 22 + 11y + 11y = 154

→ 22y + 22 = 154

→ 22y = 154 - 22

→ 22y = 132

→ y = 132/22

→ y = 6

Step-by-step explanation:

Answer:

There is a multiplication error. The payment should be $48 per month.

Step-by-step explanation:

Answer:

There is a multiplication error. The payment should be $48 per month.

Step-by-step explanation:

Answer:

2 and -1/2 since -1/2 is negative the answer is 2

Step-by-step explanation:

I plugged the values into the quadratic formula

The volume of the cone is one-third the volume of the pyramid, the area of the circle is pi/4 the area of the square because the radius of the circle is half the side length of the square.

The volume of the cone is one-third the volume of the pyramid because the cone's base is a sector of the square, and the sector takes up one-third of the square's area.

Volume of a cone: The volume of a cone is equal to (1/3)πr²h, where r is the radius of the base and h is the height of the cone.

Volume of a pyramid: The volume of a pyramid is equal to (1/3)Bh, where B is the area of the base and h is the height of the pyramid.

In the problem, we are told that the area of the circle is pi/4 the area of the square. This means that the radius of the circle is half the side length of the square. We can use this information to find the volume of the cone and the pyramid.

Volume of the cone: The radius of the cone is half the side length of the square, so r = s/2. The height of the cone is h. The area of the base of the cone is (pi)(r²) = (pi)(s²/4). So, the volume of the cone is (1/3)π(s²/4)h = (1/12)πs²h.

Volume of the pyramid: The area of the base of the pyramid is the same as the area of the base of the cone, which is (pi)(s²/4). The height of the pyramid is the same as the height of the cone, which is h. So, the volume of the pyramid is (1/3)π(s²/4)h = (1/12)πs²h.

As you can see, the volume of the cone is equal to one-third the volume of the pyramid.

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Answer:

A.

Step-by-step explanation:

it’s A because it has addition (sum) and it has multiplication (product)

Answer:

bule is in the spot of green in the sixth place of box 5

Step-by-step explanation:

Using variable concepts, of dependent and independent variables, it is found that the dependent variable is the amount of sales dollars earned.

In this problem, the manager believes that the amount of sales dollars earned is a function of the number of contacts that the salesperson makes, hence:

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Answer:y=(7/2)-(3/2)x

Step-by-step explanation:

3x+2y-7=0

3x+2y=7

2y=7-3x

y=(7/2)-(3/2)x

Answer:

area = 8.75 ft²

Step-by-step explanation:

area = 1/2bh

area = 1/2(7)(2.5) = 8.75 ft²

Answer:

4number is the answer

sin30

if the tangent line to y = f ( x ) at ( 6 , 2 ) passes through the point ( 0 , 1 ) , then f(6) = 2 and f'(6) = 1/6.

To find f(6), we can use the fact that the tangent line to y = f(x) at (6, 2) passes through the point (0, 1). The equation of a line can be written as y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

Since the line passes through (6, 2) and (0, 1), we can substitute these values into the equation to get:

2 - 1 = m(6 - 0)

1 = 6m

Solving for m, we find m = 1/6.

Since the slope of the tangent line is equal to the derivative of f(x) at x = 6, we have f'(6) = 1/6.

Now, to find f(6), we can integrate f'(x) with respect to x:

f(x) = ∫(f'(x))dx = ∫(1/6)dx = (1/6)x + C

To find the value of C, we can substitute the point (6, 2) into the equation:

2 = (1/6)(6) + C

2 = 1 + C

C = 1

Therefore, f(x) = (1/6)x + 1.

Substituting x = 6 into the equation, we get:

f(6) = (1/6)(6) + 1 = 2.

So, f(6) = 2 and f'(6) = 1/6.

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All possible values of b are 13.05 and 4.95. Hence, the correct answer is b = 13.05, 4.95.

Given that the distance between (b, 6) and (9, 6) is 4.5 units. We need to find all possible values of b.To find all possible values of b, we need to use the distance formula which is given by; Distance formula = √(x2−x1)2+(y2−y1)2We know the coordinates of (b, 6) and (9, 6). Let's plug them into the formula. Distance between (b, 6) and (9, 6) is 4.5 units.4.5 = √((9 − b)2 + (6 − 6)2)Simplify and solve for b.16.25 = (9 − b)2(9 − b)2 = 16.25√(9 − b) = ±√16.25(9 − b) = ±4.05b1 = 9 + 4.05 = 13.05b2 = 9 − 4.05 = 4.95Therefore, all possible values of b are 13.05 and 4.95. Hence, the correct answer is b = 13.05, 4.95.

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The difference quotient of \(f(x) = x^2 - 6x + 5\) is is 2x - 6 + h.

To find the difference quotient for the function \(f(x) = x^2 - 6x + 5\), we need to evaluate

(f(x + h) - f(x)) / h, where h is not equal to 0.

First, let's find f(x + h):

\(f(x + h) = (x + h)^2 - 6(x + h) + 5\)

\(= x^2 + 2hx + h^2 - 6x - 6h + 5\)

\(= x^2 - 6x + 5 + 2hx - 6h + h^2\)

Now, we can substitute the values of f(x + h) and f(x) into the difference quotient:

\((f(x + h) - f(x)) / h = ((x^2 - 6x + 5 + 2hx - 6h + h^2) - (x^2 - 6x + 5)) / h\)

= (2hx - 6h + h^2) / h

= 2x - 6 + h

Therefore, the difference quotient of \(f(x) = x^2 - 6x + 5\) is 2x - 6 + h.

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Yes, they can speed up the run time by using a heuristic to output a playlist that is not optimal, but close enough.

A phase of the programming lifecycle is runtime. It is the period of time when a programme is simultaneously being executed by all external instructions required for proper operation. Some of these extraneous commands are built into programming languages and are known as runtime environments or runtime systems. The environment in which a programme or application is run is known as the runtime environment.

Programs may access all the features they want and operate independently of operating systems thanks to runtime environments, which is one of their main advantages. The runtime process is well-understood by most users of computer programmes, but it is crucial to software engineers because if flaws are identified in the code, the programme will throw runtime errors.

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(a) The bird watcher's displacement is approximately 3.34 km.

(b) The bird watcher's average velocity is approximately 2.61 km/h in a direction 46.9 degrees north of east.

To determine the bird watcher's displacement, we need to find the straight-line distance from the starting point to the ending point. This can be calculated by treating the east and south components as negative and the north of west component as positive. Using vector addition, we can find the resultant vector which represents the displacement. The magnitude of the resultant vector gives us the displacement, which is approximately 3.34 km.

To find the average velocity, we divide the displacement by the time taken. The direction of the average velocity can be found by calculating the angle with respect to the positive x-axis. By using trigonometry, we can determine the angle to be approximately 46.9 degrees north of east. The magnitude of the average velocity is the displacement divided by the time, giving us approximately 2.61 km/h.

Therefore, the bird watcher's displacement is approximately 3.34 km, and their average velocity is approximately 2.61 km/h in a direction 46.9 degrees north of east.

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Answer:

  72

Step-by-step explanation:

The two right triangles are congruent by the HA congruence theorem, so corresponding sides have the same length.

  QR = QT

  3p = p +48 . . . . . . substitute the given measure expressions

  2p = 48 . . . . . . . subtract p

  p = 24 . . . . . . . divide by 2

  QT = p +48 = 24 +48 . . . . . use the value of p in the expression for QT

  QT = 72

Answer:

- 9 + 12x

Step-by-step explanation:

- 3(3 - 4x) ← multiply each term in the parenthesis by - 3

= - 9 + 12x

The probability that no births will occur today is 0.1353 (approximately) found by using the Poisson distribution.

Given that the number of births in a local hospital follows a Poisson distribution and averages λ per day.

To find the probability that no births will occur today, we can use the formula of Poisson distribution.

Poisson distribution is given by

P(X = x) = e-λλx / x!,

where

P(X = x) is the probability of having x successes in a specific interval of time,

λ is the mean number of successes per unit time, e is the Euler’s number, which is approximately equal to 2.71828,

x is the number of successes we want to find, and

x! is the factorial of x (i.e. x! = x × (x - 1) × (x - 2) × ... × 3 × 2 × 1).

Here, the mean number of successes per day (λ) is

λ = 2

So, the probability that no births will occur today is

P(X = 0) = e-λλ0 / 0!

= e-2× 20 / 1

= e-2

= 0.1353 (approximately)

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\( \sin(a) = \frac{opposite}{hypotenuse \\ } \\ \\ \sin(a) = \frac{5}{8} \\ \\ a = \sin {}^{ - 1} ( \frac{5}{8} ) \\ \)

measure of A is approximately equal to 39°

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Answer:

a^2=5^2+8^2

a^2=25+64

a^2=89

a=9.43398

9.43 to the nearest hundred

Step-by-step explanation:

we use the pythagorus theorem because our triangle is right angled

a^2=b^2+c^2

19 Step-by-step explanation:

Answer:

3.45 sqft

Step-by-step explanation:

Calculate all the areas individually, the 3 lateral sides are the same and using the formula for area we have 1/2 base times height. The height is 2 ft and the base is 1 ft so the area of one of the lateral sides is 1 ft.

There are three lateral sides so you multiply 1 by 3 to get 3.

The base is done the same way. It's base is 1 ft and it's height is 0.9ft so the area is 0.45.

3 + 0.45 = 3.45

The surface area is 3.45 sqft.

I could be wrong but the formula and process is the same, calculate the sides individually using the base height formula for area.

The probability that the first card drawn is a queen or the last card drawn is a queen is approximately 0.1538 or 15.38%.

The probability of drawing a queen as the first card is 4/52 or 1/13, since there are 4 queens in the deck and 52 total cards. The probability of drawing a queen as the last card is also 4/52 or 1/13, since the deck is well-shuffled and without replacement, so the probability of drawing a queen does not change.

However, if a queen is drawn as the first card, there are only 51 cards left in the deck and 3 queens remaining, so the probability of drawing a queen as the last card would be 3/51 or 1/17. Similarly, if a queen is not drawn as the first card, there would be 4 queens remaining in the deck of 51 cards, making the probability of drawing a queen as the last card 4/51.

To calculate the overall probability of drawing a queen as the first card or the last card, we can add the probabilities of each scenario: (1/13) + [(12/13) x (4/51)] + [(12/13) x (47/51) x (1/13)] = 0.1538, or approximately 15.38%.

Therefore, the probability that the first card drawn is a queen or the last card drawn is a queen is approximately 0.1538 or 15.38%

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Answer:    

18 large shirts

2 small shirts

Step-by-step explanation:

trial and error my boi

The expected number of times that a cyan napkin would be drawn if she performs the experiment a total of 189 times is given as follows:

A. 60.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

The total number of trials is given as follows:

7 + 20 + 11 + 3 + 22 = 63.

Hence the probability of drawing a cyan napkin is given as follows:

p = 20/63.

Meaning that the expected number of times that a cyan napkin would be drawn if she performs the experiment a total of 189 times is obtained as follows:

E(X) = 189 x 20/63

E(X) = 60.

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The statement is

1) T - This statement is true. The derivative of a sum is the sum of the derivatives.
2) T - This statement is true. The derivative of a product is the sum of the derivatives of the factors multiplied by each other.
3) T - This statement is true. The derivative of a composite function is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function.
4) T - This statement is true.
5) T - This statement is true.
6) F - This statement is false. The derivative of e^x is e^x, not e^(x+1).
7) T - This statement is true. The derivative of a constant is zero.

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