The mean is the best measure οf center, and it equals 7.3.
Given that a line plot displays the number of roses purchased per day at a grocery store.
We need to find the mean,
So,
Mean = 6+6+7+7+8+8+8+9+9+10+1 / 11 = 7.3
Hence, the mean is the best measure οf center, and it equals 7.3.
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If you go twice as fast, will your stopping distance increase by: A. Two times. B. Three times. C. Four times. D. Five times
If you go twice as fast, your stopping distance will increase by four times (option C).
This relationship is based on the laws of physics and the principles of motion.
When an object is in motion, its stopping distance is influenced by its initial speed, reaction time, and braking capabilities. The stopping distance consists of two components: the thinking distance (the distance traveled during the reaction time) and the braking distance (the distance needed to bring the object to a complete stop).
According to the laws of physics, the braking distance is directly proportional to the square of the initial speed. This means that if you double your speed, the braking distance will increase by a factor of four. In other words, going twice as fast will require four times the distance to come to a stop.
It is important to note that this relationship assumes other factors, such as road conditions and braking efficiency, remain constant. However, in real-world scenarios, these factors may vary and can affect the stopping distance to some extent.
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a manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 411.0 gram setting. it is believed that the machine is underfilling the bags. a 35 bag sample had a mean of 406.0 grams. a level of significance of 0.05 will be used. state the hypotheses. assume the standard deviation is known to be 25.0.
Using a 35-bag sample with a mean of 406.0 grams, a known standard deviation of 25.0 grams, and a level of significance of 0.05, you can perform a one-tailed Z-test to determine whether to reject or fail to reject the null hypothesis.
To test if the potato chip manufacturer's bag filling machine is working correctly at the 411.0-gram setting, we will state the hypotheses using the given terms.
Null Hypothesis (H0): The machine fills bags correctly, with a mean weight of 411.0 grams (µ = 411.0 grams)
Alternative Hypothesis (H1): The machine is underfilling bags, with a mean weight less than 411.0 grams (µ < 411.0 grams)
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Ethan decides that he wants to crawl to class. The two classes are 40
feet apart. Passing period lasts 240 seconds. What would Ethan's
average speed be if he took all 240 seconds?
Answer:
1/6 feet/second
Step-by-step explanation:
The total feet traveled would be 40 feet. The seconds would be 240 giving 40/240 feet/second. Simplify this by dividing 40 by 240 giving an answer of 1/6. This makes the average speed 1/6 feet/second. Alternatly it would be 10 feet/minute
Richard had 180 total minutes to do
homework, mow the grass, and walk the dog.
He spent 3(x + 4) minutes mowing the
grass.
He spent (x + 3) minutes working on
homework
He walked the dog for x minutes.
How many minutes did Richard spend
mowing the grass?
If QP bisects ZDQL, m/DQP = 5x - 7, and m/PQL = 11 + 2x, determine
the measure of ZDQL.
m₂DQL =
When QP bisects DQL, then the angles DQP and angle PQL is 23°.
Given that,
In the picture we can see the diagram,
The QL line is there and the QD line.
QP line bisect the angles DQL
The angle DQP is 5x-7
The angle PQL is 11+2x
We have to find the x value and the angles DQP and PQL.
We know,
From the bisection we can say the angle are equal to each other
The angle DQP=The angle PQL
5x-7=11+2x
5x-2x=11+7
3x=18
x=18/3
x=6
Substitute x value in angles DQP and angle PQL.
The angle DQP=5x-7=5(6)-7=30-7=23°
The angle PQL=11+2x=11+2(6)=11+12=23°.
Therefore, the angles DQP and angle PQL is 23°.
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please please help me
Answer:
A
Step-by-step explanation:
e.g 10×1 = 10
10 + 8 = 18
10 × 2 = 20
20 + 8 = 28
Answer:
I believe the answer is A
Step-by-step explanation:
slope for this equation is \(m = \frac{y2-y1}{x2-x1}\)
so picking some coordinates (1,18) and (1.5,23)
= \(\frac{23-18}{1.5-1}\)
= 10
slope is 10 which is closes to A
7. If 294 J of heat is transferred to a 10.0 g sample of silver at 25 ºC, what is the
final temperature of the silver? Specific heat capacity of silver is 0.235 J/gºC.
Answer:
T~final is 150.11 C
Step-by-step explanation:
To solve this we need this specific heat equation:
Q=mc(T~final - T~initial) that is the difference of final temperature minus initial temperature.
We are given:
Q = 294 J
m = 10 g
c = 0.235 J/gC
T~initial = 25 C
Plug the values in to the equation
294 J = 10 g * 0.235 J/gC * T(difference)
294 J = 2.35 J/C * T(difference)
Divide both sides by 2.35 J/C
294 J / 2.35 J/C = T(difference)
T(difference) = 125.11 C
If the initial temperature was 25 C then then
T~final = 25 C + 125.11 C or 150.11 C
Solve the 1-dimensional heat equation problem. əzu ди ət u (0,t) u (x,0) 2 Əx2 u (5,t) = 0, for t > 0 f (x) = -4 sin (TX) + 3 sin (27x), for 0 < x < 5
To solve the given 1-dimensional heat equation problem, we can use the method of separation of variables. The problem is defined as follows:
Partial Differential Equation (PDE): ∂u/∂t = α^2 ∂^2u/∂x^2, for t > 0 and 0 < x < 5.
Boundary conditions:
1. u(0, t) = 0
2. u(5, t) = 0
Initial condition: u(x, 0) = f(x) = -4 sin(Tx) + 3 sin(27x), for 0 < x < 5.
To solve this problem, perform the following steps:
1. Assume a solution in the form u(x, t) = X(x)T(t).
2. Substitute this solution into the PDE and separate the variables.
3. Solve the resulting ordinary differential equations (ODEs) for X(x) and T(t) subject to the given boundary conditions.
4. Obtain the general solution by summing the product of the separated solutions X_n(x)T_n(t) with appropriate coefficients.
5. Determine the coefficients by applying the initial condition and using Fourier series representation.
Since the problem is well-posed, a unique solution exists.
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What is the maximum number of terms in a polynomial of degree 10?
Answer: 11
Step-by-step explanation:
The maximum number of terms in a polynomial of degree 10 is 11.
A polynomial of degree n is a mathematical expression consisting of one or more terms, where each term is a product of a constant coefficient and one or more variables raised to non-negative integer powers, and the highest power of the variables in any term is n. The degree of a polynomial is the highest power of its variables.
A polynomial of degree 10 has the form:
f(x) = a₁₀x¹⁰ + a₉x⁹ + a₈x⁸ + a₇x⁷ + a₆x⁶ + a₅x⁵ + a₄x⁴ + a₃x³ + a₂x² + a₁x¹ + a₀
Where a₀, a₁, a₂, a₃, a₄, a₅, a₆, a₇, a₈, a₉, and a₁₀ are constants, and a₁₀ ≠ 0.
The polynomial has at most 11 terms.
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Find a Cartesian equation for the curve.
r^2 cos(2θ)=16
Identify the curve. line circle limaçon hyperbola ellipse
The Cartesian equation for the curve r^2 cos(2θ) = 16 can be determined using the relation between cartesian and polar coordinates.
The relation between cartesian and polar coordinates is
x = r cos(θ)
y = r sin(θ)
First, note that r^2 = x^2 + y^2.
Now, we need to find cos(2θ). Using the double-angle formula, we have:
cos(2θ) = 2cos^2(θ) - 1 = 2(x^2/r^2) - 1
Now, substitute r^2 and cos(2θ) into the original equation:
(x^2 + y^2) (2(x^2/(x^2 + y^2)) - 1) = 16
Simplify the equation:
2x^2 - (x^2 + y^2) = 16
x^2 - y^2 = 16
Now we have the Cartesian equation for the curve:
x^2 - y^2 = 16.
This equation represents a hyperbola, as it has the general form of a hyperbola equation
(A^2 - B^2 = C^2, where A, B, and C are constants).
So, the Cartesian equation for the curve r^2 cos(2θ) = 16 is x^2 - y^2 = 16, and the curve is a hyperbola.
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Determine whether the differential equation (2x² − 2xy + 3) dx + (7y² − x² + 2) dy = 0 is exact. If it is exact, find the solution. The differential equation Choose one exact because Choose one ▾ Choose one Choose one
The general solution is (2/3)x³ - xy² + 3x + C1(y) + (7/3)y³ - xy² + 2y + C2(x).
To determine whether the given differential equation is exact, we need to check if the partial derivatives of the equation with respect to x and y are equal.
Given differential equation: (2x² − 2xy + 3) dx + (7y² − x² + 2) dy = 0
Taking the partial derivative with respect to x:
∂/∂x(2x² − 2xy + 3) = 4x - 2y
Taking the partial derivative with respect to y:
∂/∂y(7y² − x² + 2) = 14y - 0 = 14y
Since the mixed partial derivative (∂²/∂x∂y) is not equal to the difference between the two partial derivatives (∂/∂y(4x - 2y) - ∂/∂x(14y)), the given differential equation is not exact.
To proceed, we can check if the equation can be made exact by multiplying an integrating factor.
Dividing both sides of the equation by (4x - 2y), we get:
[(2x² − 2xy + 3)/(4x - 2y)] dx + [(7y² − x² + 2)/(4x - 2y)] dy = 0
Comparing this with the form M(x, y) dx + N(x, y) dy = 0, we have:
M(x, y) = (2x² − 2xy + 3)/(4x - 2y)
N(x, y) = (7y² − x² + 2)/(4x - 2y)
To find the integrating factor (μ), we can use the formula:
μ = e^(∫(∂M/∂y - ∂N/∂x) dx)
Calculating the values:
∂M/∂y = (-2x + 2)/(4x - 2y)
∂N/∂x = (-2x + 7)/(4x - 2y)
∂M/∂y - ∂N/∂x = [(-2x + 2)/(4x - 2y)] - [(-2x + 7)/(4x - 2y)]
= (-2x + 2 + 2x - 7)/(4x - 2y)
= (-5)/(4x - 2y)
∫(-5)/(4x - 2y) dx = -5ln|4x - 2y|
Therefore, the integrating factor (μ) is μ = e^(-5ln|4x - 2y|) = 1/(|4x - 2y|^5).
Now, multiply the entire equation by the integrating factor:
1/(|4x - 2y|^5) [(2x² − 2xy + 3) dx + (7y² − x² + 2) dy] = 0
Simplifying the equation, we get:
(2x² − 2xy + 3)/(|4x - 2y|^5) dx + (7y² − x² + 2)/(|4x - 2y|^5) dy = 0
Now, we need to check if this new equation is exact.
Taking the partial derivatives with respect to x and y, we find that they are equal.
Since the equation is now exact, we can find the solution by integrating the equation.
Integrating (2x² − 2xy + 3)/(|4x - 2y|^5) with respect to x,
and integrating (7y² − x² + 2)/(|4x - 2y|^5) with respect to y.
To integrate the given differential equation with respect to x and y, we treat it as a function of two variables and integrate each term separately.
Integrating with respect to x:
∫ (2x² - 2xy + 3) dx = (2/3)x³ - xy² + 3x + C1(y)
Integrating with respect to y:
∫ (7y² - x² + 2) dy = (7/3)y³ - xy² + 2y + C2(x)
Where C1(y) and C2(x) are arbitrary functions of y and x, respectively.
Combining the results, we have the general solution:
(2/3)x³ - xy² + 3x + C1(y) + (7/3)y³ - xy² + 2y + C2(x) = C
Where C is the constant of integration.
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Find the constant of proportionality k in the equation y = 24x
Answer:
The value of k is 24
Step-by-step explanation:
y = 24x
The equation for a direct variation is
y = kx
The constant of proportionality is k
y = 24x
The value of k is 24
how to solve equations with fractions and variables in the denominator
To solve equations with fractions and variables in the denominator, we need to eliminate it by moving it to the other side. To do this, we multiply both sides of the equation by the term in the denominator. This will cancel out the fraction and leave us with a simpler equation to solve.
For example, suppose we have the equation (3 + x) / x = 2. To get rid of the fraction, we multiply both sides by x. This gives us: x * (3 + x) / x = x * 2. The x in the numerator and denominator cancel out, leaving us with:
3 + x = 2x. Now we can solve for x by subtracting x from both sides: 3 = x
This is the solution of the equation.
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Trigonometry for anyone who’s bored
Answer:
x= 68.19°
Step-by-step explanation:
you can use inverse of cos(x)
\(cos^{-1}\)(\(\frac{2}{5}\)) =68.19°
∴ x=68.19°
Answer:
we can find the value of x using cos.
cos=adjacent side/hypotenuse
\(cos(x)=2/5\\\)
Using inverse cos, we can find the value of x
\(cos^-1(2/5)=66.42182152\\x=66\)
(Rounded)
Step-by-step explanation:
browns books are 2 for $11 and noble books are 5 for $31 who’s is cheaper
Therefore , the solution of the given problem of unitary method comes out to be Browns books are less expensive than Noble books at $5.50 each.
What is unitary method ?Take the lengths of this minute subsection and split the sum by two to complete a task using a unitary variable technique. The unit technique, in a nutshell, removes a wanted item both from the specific sets and color subsets. For instance, 40 pencils will cost Rs/kg ($1.01). It's possible that one country will have total influence over the approach taken to accomplish this. Almost every living creature has a distinctive quality. There are unanswered questions and changes (mathematics, algebra).
Here,
We must ascertain the price per book for each retailer in order to evaluate the costs of Browns and Noble books.
Two of Brown's books cost $11, so each volume costs $5.50 (11/2 = 5.50).
Five novels from Barnes & Noble cost $31, making each book $6.20 (31/5 = 6.20).
Browns books are less expensive than Noble books, which cost $6.20 per volume, at $5.50 each.
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Which expression is equivalent to the expression below? startfraction m 3 over m squared minus 16 endfraction divided by startfraction m squared minus 9 over m 4 endfraction startfraction 1 over (m 4) (m 3) endfraction startfraction 1 over (m minus 4) (m minus 3) endfraction startfraction m minus 4 over m minus 3 endfraction startfraction m 3 over m 4 endfraction
The equivalent expression of the product expression \(\frac{m^3}{m^2 - 16} \div \frac{m^2 - 9}{m^4}\) is \(\frac{m^7}{(m - 4)(m + 4)(m - 3)(m + 4)}\)
How to determine the equivalent expression?The expression is given as:
\(\frac{m^3}{m^2 - 16} \div \frac{m^2 - 9}{m^4}\)
Rewrite the expression as a product
\(\frac{m^3}{m^2 - 16} * \frac{m^4}{m^2 - 9}\)
Evaluate the product
\(\frac{m^7}{(m^2 - 16)(m^2 - 9)}\)
Rewrite the denominator as a difference of two squares
\(\frac{m^7}{(m - 4)(m + 4)(m - 3)(m + 4)}\)
Hence, the equivalent expression of the product expression \(\frac{m^3}{m^2 - 16} \div \frac{m^2 - 9}{m^4}\) is \(\frac{m^7}{(m - 4)(m + 4)(m - 3)(m + 4)}\)
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Answer the question below!!!!!!!!!!!!!!
a. The total of the three cards is 12. 36
b. The number that should replace the question mark is 1.36
What is the mean of values?The mean of a given set of data is defined as the average of the values.
The formula for the mean of a set of data is given as;
Mean = sum of the data/number of data
From the information given, we have that;
Mean = 5
The data = 8 + 3 + x
Substitute the values, we have;
5 = 8 + 3 + x/3
cross multiply the values, we have;
15 = 11x
Divide both sides by the coefficient, we have;
x = 1. 36
The total of these cards = 8 + 3 + 1.36 = 12. 36
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Determine the three-decimal digit approximation of the number √34.
Using a calculator, it can be found that
\(\sqrt{34}=5.83095189...\)Rounding to three decimal places,
\(\Rightarrow\sqrt{34}\approx5.831\)The rounded answer is 5.831let’s consider the population of current fiu students. if we had access to panthersoft’s database we have data for every single fiu student. what will the set of all fiu students be ?
The set of all FIU students would be the entire population of FIU students, which includes every individual who is currently enrolled as a student at Florida International University.
This would include undergraduate and graduate students, full-time and part-time students, and students of all majors and programs. The set would be a complete representation of the entire FIU student body, including all of its characteristics and attributes.
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Scale factor: 1 in = 2 ft
actual T−Rex foot length = 8 ft
model T−Rex foot length = in
The model T-Rex foot length is 48 inches.
Given the scale factor of 1 inch = 2 feet, we can determine the model T-Rex foot length based on the actual T-Rex foot length of 8 feet.
To convert the actual T-Rex foot length of 8 feet to inches, we multiply it by the conversion factor of 12 inches per foot:
8 feet * 12 inches/foot = 96 inches.
Now, using the scale factor of 1 inch = 2 feet, we can determine the model T-Rex foot length in inches by dividing the actual length in inches by the scale factor:
96 inches / 2 = 48 inches.
Therefore, the model T-Rex foot length is 48 inches. The scale factor allows us to represent the larger actual length of 8 feet in a scaled-down model length of 48 inches. This scaling enables us to accurately represent the proportions and dimensions of the T-Rex foot in a more manageable size.
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!!PLS HELP ASAP!!30 POINTS!!
Divide using synthetic division
\(x^4-3x^3-7x+1\)÷\(x+2\)
The quotient and remainder are x³ -5x² + 10x - 17 and 55.
What is Synthetic division?
When the divisor is a linear factor, synthetic division is a technique used to carry out the division operation on polynomials.
Here, (x+2) is a linear factor which indicates that synthetic division can be applied.
So, we will divide the x^4 - 3x^3 - 7x + 1 by x+2.
(refer the attached solution)
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this is kinda complex ngl could any high schoolers help me? this is the problem.
Solve for
a
aa.
Give an exact answer.
3
+
0.5
(
4
a
+
8
)
=
9
−
2
a
3+0.5(4a+8)=9−2a. A= ?
Answer:
a = 1/2
Step-by-step explanation:
You want the solution to 3 +0.5(4a +8) = 9 −2a.
SolutionIt usually works well to start by simplifying the equation. That is, you eliminate parentheses, combine like terms.
3 +0.5(4a) +0.5(8) = 9 -2a
3 + 2a +4 = 9 -2a
7 +4a = 9 . . . . . . . . . add 2a
4a = 2 . . . . . . . . . subtract 7
a = 0.5 . . . . . . divide by 4
The value of a is 1/2.
__
Additional comment
The attached calculator output shows this value of 'a' satisfies the equation.
You are given the principal, the annual interest rate, and the compounding period Determine the value of the account at the end of the specified time period found to two decal places $6.000, 4% quarterly 2 years
The value of the account at the end of the 2-year period would be $6,497.14.
What is the value of the account?Given data:
Principal (P) = $6,000Annual interest rate (R) = 4% = 0.04Compounding period (n) = quarterly (4 times a year)Time period (t) = 2 yearsThe formula to calculate the value of the account with compound interest is \(A = P * (1 + R/n)^{n*t}\)
Substituting values:
\(A = 6000 * (1 + 0.04/4)^{4*2}\\A = 6000 * (1 + 0.01)^8\\A = 6000 * (1.01)^8\\A = 6,497.14023377\\A = 6,497.14\)
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The value of the account at the end of the specified time period, with a principal of $6,000, an annual interest rate of 4% compounded quarterly, and a time period of 2 years, is approximately $6489.60.
Given a principal amount of $6,000, an annual interest rate of 4% compounded quarterly, and a time period of 2 years, we need to determine the value of the account at the end of the specified time period.
To calculate the value of the account at the end of the specified time period, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A is the future value of the account,
P is the principal amount,
r is the annual interest rate (expressed as a decimal),
n is the number of compounding periods per year, and
t is the time period in years.
Given the values:
P = $6,000,
r = 0.04 (4% expressed as 0.04),
n = 4 (compounded quarterly), and
t = 2 years,
We can plug these values into the formula:
A = 6000(1 + 0.04/4)^(4*2)
Simplifying the equation:
A = 6000(1 + 0.01)^8
A = 6000(1.01)^8
A ≈ 6000(1.0816)
Evaluating the expression:
A ≈ $6489.60
Therefore, the value of the account at the end of the specified time period, with a principal of $6,000, an annual interest rate of 4% compounded quarterly, and a time period of 2 years, is approximately $6489.60.
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HELP PLSSS ASAP!!! HELP ASAP MATH! (BRAINLIST)
What is the measure, in degrees of an angle that represents 50/360 of a circle?
90º
50º
360º
310º
The measure, in degrees of an angle that represents 50/360 of a circle is 50 degrees.
What is a circle?A circle is a locus of a point that moves in a plane such that its distance from a fixed point is always constant.
As we know that a circle has a total of 360 degrees all the way around the center.
So, the measure, in degrees of an angle that represents 50/360 of a circle will be = 50/360 * 360 degrees.
the measure, in degrees of an angle that represents 50/360 of a circle will be = 50 degrees.
Therefore, the measure, in degrees of an angle that represents 50/360 of a circle is 50 degrees.
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The measure of the angle at the centre of the circle that represents 50/360 of a circle is 50°.
What is a circle?A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant; alternatively, it is the shape formed by all points in a plane that are at a set distance from a given point, the centre.
A complete circle has a 360° angle at the center of it, since the angle we need to calculate is represented by 50/360, therefore, the measure of the angle can be written as,
\(\theta = \dfrac{50}{360}\times 360^o = 50^o\)
thus, the measure of the angle at the centre of the circle that represents 50/360 of a circle is 50°.
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33.
60°
C
30°
A supplementary
neither
Are these angles complementary, supplementary or neither?
B
complementary
The angles shown in the figure are complementary angles.
What are angles?The construction of an angle is a type of geometric shape made by connecting two rays at their termini. Three letters that make up the shape of the angle can alternatively be used to symbolize the angle, with the middle letter indicating the location of the angle.
Given the angles,
60° and 30°
the sum of both angles is,
60° + 30° = 90°
The sum of two angles is 90° then the angles are known as complementary angles.
Hence the angles are complementary angles.
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A coach is buying snacks for 22 players at a soccer match. She pays a total of $77 to
buy each player a bottle of water and an energy bar. The price of one energy bar is $2.
Let w equal the price of a bottle of water. Write an equation that
represents the situation.
Answer: 22( w + 2 ) =77 and the amount of the water bottle would be 1.50
Step-by-step explanation: i dont know what to write??
Which equation represents the sentence, "The sum of twenty-four and p minus fifteen is q"?
A. 24 + p + 15 = q
B. 24 + p – 15 = q
C. p + q – 15 = 24
D. 15 + p = q – 24
Answer:
B is correct: also if u add C and D together there both different and if u added B and A correctly u would have got B as your answer.
Step-by-step explanation:
Solve the initial value problem dy COS + y sin x = 2x cosa x, dr y(0) = 5. [6 marks)
The solution to the initial value problem is y(x) = 3x sin x + 2x cos x.
To solve the initial value problem, we can use an integrating factor method. First, we rewrite the given equation as dy/dx + y tan x = 2x sin x. By comparing this form with the standard form of a linear first-order differential equation, we can determine the integrating factor. The integrating factor is given by exp(integral(tan x dx)), which simplifies to cos x.
Multiplying the entire equation by cos x, we get cos x dy/dx + y sin x = 2x sin x cos x. The left-hand side of the equation is now the derivative of (y cos x) with respect to x. Integrating both sides, we have ∫(y cos x) dx = ∫(2x sin x cos x) dx.
Integrating the right-hand side and simplifying, we get y(x) cos x = x sin^2(x) + C, where C is the constant of integration. To find the value of C, we use the initial condition y(0) = 5. Plugging in x = 0 and y = 5 into the equation, we get 5 cos 0 = 0 + C. Simplifying, we find C = 5.
Substituting C back into the equation, we have y(x) cos x = x sin^2(x) + 5. Dividing both sides by cos x, we obtain the final solution y(x) = (x sin^2(x) + 5) / cos x. Simplifying further, we get y(x) = 3x sin x + 2x cos x, which is the solution to the initial value problem.
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Answer:
5 > n + 10
8 x 7 < n
n/3 + 1
6 x 8 - 10 < n
n - 1 x n
n x -n + 7
a company manufactures batteries in batches of 15 and there is a 3% rate of defects. find the mean number of defects per batch. group of answer choices
0.45 will be the mean number of defects per batch.
Given,
The number of batches of batteries manufactured by a company = 15
The rate of defects in the batteries = 3%
We have to find the mean number of defects per batch;
Defects per Unit (DPU)
The average number of defects per unit of a product is measured by DPU. It can be calculated by dividing the overall number of flaws by the quantity of units. For instance, the DPU is equal to 2 if 30 units are created and a total of 60 flaws are discovered.
Here,
The mean number of defects per batch = Number of batches × Rate of defects
Mean number of defects = 15 × 3/100 = 0.45
That is,
The mean number of defects per batch is 0.45
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