Cheetah mothers perform a number of different behaviors. They and their cubs stay in one place for only four days, moving on before they leave too strong a smell behind in one area. They also expend time and energy teaching their cubs to hunt successfully. In one or two sentences, explain how these behaviors affect cheetah reproductive success.(2 points)

Answers

Answer 1

Answer:

Cheetah cubs are in danger from predators like lions and hyenas which can track their prey by scent and so the mother and her cubs leave an area when their scent is too strong so that they are not hunted and the cubs survive.

Mother Cheetahs also train their cubs to hunt so that they may get food for themselves which will ensure their survival as well thus showing that both of these practices can impact on reproductive success.


Related Questions

Scuba divers use compressed oxygen gas to go diving. The oxygen's volume decreases as pressure is increased to fit more in an oxygen tank. What Gas Law is being applied in this situation?

Charles Law


Gay-Luassac's Law


Boyle's Law


Newton's Law

Answers

I feel like it’s Boyle’s Law, correct me if I’m wrong .

Revision. Explain why a gap of a few cm should be left above the water surface when filling a cold car radiator.​

Answers

Car's radiator is in charge of regulating the engine's temperature. By moving heat away from the engine, it accomplishes this by continuously moving coolant throughout the system and thermostat.

Thus, Air blowing over the radiator then chills the coolant. Only when the engine is turned off will the car radiator be cold.

The radiator will warm up as the coolant flows through it while the engine is operating. This explains why the radiator in your automobile is cold when the engine is off yet warm when it is on.

Keep in mind that the radiator is merely one component of the cooling system. The thermostat, water pump, and other parts are included in the cooling system.

Thus, Car's radiator is in charge of regulating the engine's temperature. By moving heat away from the engine, it accomplishes this by continuously moving coolant throughout the system and thermostat.

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A photoelectric experiment indicates that violet light of wavelength 420 nm is the longest wavelength radiation that can cause photoemission of electrons from a particular multialkali photocathode surface.c. Given that the UV light of wavelength 300 nm has an intensity of 20 mW/cm2, if the emitted electrons are collected by applying a positive bias to the opposite electrode, what will be the photoelectric current density in mA cm-2 ?

Answers

The given information are not enough to determine the photoelectric current density

How to determine the photoelectric current density

From the question, we have the following parameters that can be used in our computation:

UV light of wavelength = 300 nmIntensity = 20 mW/cm²Violet light of wavelength = 420 nm (the longest)

The photoelectric current density can be calculated using:

J = n * e / t

Where

n is proportional to the intensity of the light (I) and the quantum efficiency (η) of the photocathode (η)

From the question, we do not have value for (η)

Hence, the photoelectric current density cannot be calculated

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A student hangs a slinky over the edge of a stairwell. The slinky is stretched so that it is just above the ground. The student sends a pulse down the slinking and measures the speed to be 18m/s. The student then vibrates the slinky with a frequency of 4.5 Hz and notices that 4 nodes produced. The end near the floor is an open end and the end where the student his holding the slinking is a fixed end.] How high is the stairwell?
a) Calculate the wavelength of the slinky. (4.0 m)
b) Draw a well labelled diagram of the situation. (because of one open end, there are 3.5 loops)
c) Calculate the height of the stairwell. (h = 7 wavelength quarters, 7/4λ = h, h = 7.0 m)

Answers

The drawing of the wave in the slinky shows the node and antinode

in the form of a standing wave pattern.

The correct responses;a) 4.0 metersb) Please find attached the drawing of the wave motion in the slinkyc) 7.0 m

Method used to arrive at the response above:Given parameters;

The speed of the wave pulse through the slinky, v = 18 m/s

The frequency with which the student vibrates the slinky, f = 4.5 Hz

Number of nodes in the slinky, n = 4 nodes

a) Wavelength of the slinky λ:

The wavelength of the slinky, λ, is given as follows;

\(\displaystyle \lambda = \mathbf{ \frac{v}{f}}\)

Therefore;

\(\displaystyle \lambda = \frac{18 \, m/s }{4.5 \, Hz} = \mathbf{4.0 \, m}\)

The wavelength of the wave formed on the slinky, λ = 4.0 meters

b) Drawing of a well labelled diagram of the situation:

The attached drawing of the situation shows the wavelength of the

wave equal to the distance between three consecutive nodes, N

The number of loops = 3 complete loops + Half of a loop = 3.5 loops

c) To calculate for the height of the stairwell:

The length of the wavelength, λ = Length of two complete loops

Height of the stairwell = 3.5 loops

2 loops = λ

Therefore;

\(\displaystyle Height \ of \ stairwell = \frac{\lambda}{2 } \times 3.5 = \mathbf{1.75 \cdot \lambda}\)

Which gives;

Height of the stairwell, h = 1.75 × 4.0 m = 7.0 m

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A student hangs a slinky over the edge of a stairwell. The slinky is stretched so that it is just above

Select the correct answer. Physics is explicitly involved in studying which of these activities? A. the mixing of metals to form an alloy B. the metabolic functions of a living organism C. the motion of a spacecraft under gravitational influence D. the depletion of the atmospheric ozone layer due to pollutants E. the killing of cancerous cells by radiation therapy

Answers

Answer:  C. the motion of a spacecraft under gravitational influence.

Explanation:

A is Metallurgy, B is Biology, C is astro-physics, I am not sure what D is, but it's   safe to say it's not physics, E, micro-biology, and the study of radiation. C is the only one involving physics.

What is the period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth)?

Answers

When a mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth), the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

The period of revolution of a satellite with mass (m) that orbits the earth in a circular path of radius 7480 km (about 1100 km) above the surface of the earth) can be determined by using Kepler's third law which relates the period of revolution of a satellite to the average radius of its orbit.

Kepler's third law states that the square of the period of revolution of a satellite is proportional to the cube of the average radius of its orbit.

Mathematically, the law can be expressed as: T² = (4π² / GM) × R³Where T is the period of revolution, G is the gravitational constant, M is the mass of the earth, and R is the average radius of the orbit of the satellite.

To find the period of revolution of the given satellite, we can substitute the given values in the equation: R = 7480 km + 6370 km = 13850 kmM = 5.97 × 10²⁴ kgG = 6.67 × 10⁻¹¹ Nm²/kg²T² = (4π² / GM) × R³T² = (4π² / (6.67 × 10⁻¹¹ × 5.97 × 10²⁴)) × (13850 × 10³)³T² = 6.7182 × 10¹⁴ seconds²

Taking the square root of both sides, we get:T = 8.2079 × 10³ seconds

Therefore, the period of revolution of the given satellite is approximately 8207 seconds or 2.28 hours.

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3. Find the current enclosed by the loop (maybe using current density if you need a fraction of the total current). 4. Solve for the magnitude of the magnetic field 5. Double check the direction of the magnetic field using the right hand rule.

Answers

A magnetic field is a physical field that is produced by moving electric charges or by an intrinsic magnetic dipole such as a permanent magnet.

3. To find the current enclosed by the loop:

Identify the wire or wires that pass through the loop.

Determine the total current passing through those wires.

If the wire or wires have a uniform current density, use the formula I = J*A, where I is the current, J is the current density, and A is the area of the loop. If the current density is not uniform, integrate J over the area of the loop to find the total current.

4. To solve for the magnitude of the magnetic field:

Determine the distance between the wire or wires and the loop.

Use the formula for the magnetic field due to a current-carrying wire, B = (μ0I)/(2πr), where μ0 is the permeability of free space, I is the current in the wire, and r is the distance from the wire to the point where you want to calculate the magnetic field.

If there are multiple wires, calculate the magnetic field due to each wire and add them vectorially.

5. To double check the direction of the magnetic field using the right hand rule:

Point your right thumb in the direction of the current.

Curl your fingers around the wire in the direction of the magnetic field.

Your palm will then face in the direction of the magnetic field.

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what is thermodynamic?​

Answers

Answer:

Thermodynamics is a branch of physics which deals with the energy and work of a system. It was born in the 19th century as scientists were first discovering how to build and operate steam engines. Thermodynamics deals only with the large scale response of a system which we can observe and measure in experiment.

Answer:

thermodynamics is the branch of physics which deals with the study of heat and other forms energy and their mutual relationship(relation ship between them)

Explanation:

i hope this will help you :)

A force of 16 N is applied to a 5 kg block that is at rest on a smooth, horizontal surface. What is the velocity of the

block at time t = 5 seconds?​

Answers

Answer:

16m/s

Explanation:

Given the following data;

Force, F = 16N

Mass, m = 5kg

Time, t = 5 seconds.

First of all, we would find the acceleration of the object.

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is given by the formula;

\( F = ma\)

Where;

F represents force.m represents the mass of an object.a represents acceleration.

Making acceleration (a) the subject, we have;

\(Acceleration, a = \frac{F}{m}\)

Substituting into the equation;

\(Acceleration, a = \frac{16}{5}\)

Acceleration, a = 3.2 m/s²

Now, to find velocity;

We would use the first equation of motion given by the formula;

\( V = U + at\)

Where;

V is the final velocity. U is the initial velocity. a is the acceleration. t is the time measured in seconds.

We know that acceleration due to gravity is 9.8m/s² and initial velocity (U) is 0 since the object is at rest.

Substituting into the equation, we have;

\( V = 0 + 3.2*5\)

\( V = 0 + 16\)

Velocity, V = 16m/s.

Plzz answer this correctly

Plzz answer this correctly

Answers

Answer:

C and E...................

A cheetah can accelerate to 60mph (26.8 m/s) in 2.90 seconds! How long will it take a cheetah to run 40 meters starting from rest? Please show work.​

Answers

Answer:

It will take 2.94 s to run 40 meters starting from rest.

Explanation:

Given that,

Initial speed of cheetah, u = 0

Final speed of cheetah, v = 26.8 m/s

Time, t = 2.9 s

We need to find how long will it take a cheetah to run 40 meters.

First finding acceleration of cheetah ,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{26.8-0}{2.9}\\\\a=9.24\ m/s^2\)

Let it will take t seconds. So, using second equation of motion to find it.

\(d=ut+\dfrac{1}{2}at^2\\\\40=0+\dfrac{1}{2}\times 9.24t^2\\\\40=0+4.62t^2\\\\t^2=\dfrac{40}{4.62}\\\\t=2.94\ s\)

So, it will take 2.94 s to run 40 meters starting from rest.

QUESTION 2
How do plants help in erosion control?
1.Plants roots hold the soil in place.

2.Plants are pretty and keep the neighborhood from being ugly.

3. Plants do not help in erosion control.

4. Plants allow the soil to float in the rainwater.

Answers

Answer:

1.Plants roots hold the soil in place.

What did Rutherford’s model of the atom include that Thomson’s model did not have?
a nucleus
energy levels
electron clouds
smaller particles

Answers

Answer:

Yes the answer is A.)  A Nucleus

Explanation:

I took the test

Rutherford’s model of the atom included a nucleus  that Thomson’s model did not have, therefore the correct option is A

What are atomic models?

There are some models that are used to explain the arrangements of subatomic particles inside the atom based on the atomic theory of atom are known as the atomic models.

There are many types of atomic models proposed in past based on their individual assumptions and the experimentations

There are mainly five most widely accepted atomic models

John Dalton's atomic model which based on the assumption that all the entities of the universe are made up of the fundamental particle that is an atom.

J.J. Thomson's model: Plum Pudding model explains the arrangement of subatomic particles by taking the example of plum pudding in which positive charge is distributed uniformly throughout and the negative charge particles are sprinkled on it in a random fashion.

Rutherford's model explained the existence of a nucleus inside the atom by using the alpha particle bombardment experiment on a thin sheet of gold.

Niels Bohr's model explained the revolving nature of the electrons in the different shells around the nucleus of the atom.

Erwin Schrodinger's model explains the arrangement of the subatomic particles as the electron Cloud Model also known as the Quantum Model.

Rutherford’s model of the atom included a nucleus  that Thomson’s model did not have, therefore the correct option is A

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Which of the following is the most appropriate description of an electric current?

Answers

Electric current is the flow of charge due to the potential difference between two terminals per unit time. It is denoted by I and its unit is amp. It can be mathematically expressed as I=Q/t.

If this isn’t what your looking for I need the options they gave you

A 1.35 kg block is pulled across a flat, frictionless floor with a 3.07 n force at 32.0 above horizontal. What is the acceleration of the block

Answers


1. Calculating the horizontal component of the applied force:
Horizontal component = 3.07 N * cos(32.0°)
Horizontal component ≈ 2.597 N

2. Calculating the acceleration of the block:
Acceleration = Horizontal component / Mass
Acceleration = 2.597 N / 1.35 kg
Acceleration ≈ 1.925 m/s²

Therefore, the acceleration of the block is approximately 1.925 m/s².

A trolley going down an inclined plane has an acceleration of 2cm/s^2 What will be its velocity
3s after the start.​

Answers

Answer:

\(V_{f}\) = 6 cm/s

Explanation:

Given:

Acceleration = a = 2 cm/s²

Time = t = 3s

Initial Velocity = \(V_{i}\) = 0 cm/s

Required:

Velocity = \(V_{f}\) = ?

Formula:

a = \(\frac{V_{f}-V_{i}}{t}\)

Solution:

2 = \(\frac{V_{f}-0}{3}\)

=> \(V_{f}\) = 2*3

=> \(V_{f}\) = 6 cm/s

1 x 1015 electrons are pushed through a 10 Ω wire in one minute. What is the voltage of the power source? (e = -1.602 x 10-19 C)

Answers

The voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.

Voltage of the power source

The voltage of the power source is determined from ohm's law as shown below;

V = IR

where;

I is currentR is resistanceV is voltage

But, I = Q/t

V = (Q/t)R

\(V = \frac{QR}{t} \\\\V = \frac{(1\times 10^{15} \times 1.602\times 10^{-19} \ C) \times \ 10 \ ohms}{1 \times 60\ s} \\\\V = 2.67 \times 10^{-5} \ V\)

Thus, the voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.

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Compare the force of gravity on a 81 kg mass on the Moon's surface with the force on the Earth's surface. Which force is greater? And by how much (F_Earth / F_Moon)? (Assume the mass of the Earth is 5.97 ✕ 1024 kg, the radius of the Earth is 6.38 ✕ 103 km, the mass of the Moon is 7.35 ✕ 1022 kg, and the radius of the Moon is 1.74 ✕ 103 km.)

Answers

Answer:

The force of gravity on an object depends on the mass of the object and the mass and distance of the celestial body it is on or near. The formula for the force of gravity is:

F = G * (m1 * m2) / r^2

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

To compare the force of gravity on an 81 kg mass on the Moon's surface with the force on the Earth's surface, we need to calculate each force using the above formula and then compare the results.

First, let's calculate the force of gravity on an 81 kg mass on the Earth's surface:

F_Earth = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 5.97 x 10^24 kg) / (6.38 x 10^6 m)^2

= 7.92 x 10^2 N

So the force of gravity on an 81 kg mass on the Earth's surface is 792 N.

Next, let's calculate the force of gravity on an 81 kg mass on the Moon's surface:

F_Moon = G * (m1 * m2) / r^2

= 6.67 x 10^-11 Nm^2/kg^2 * (81 kg * 7.35 x 10^22 kg) / (1.74 x 10^6 m)^2

= 1.32 x 10^3 N

So the force of gravity on an 81 kg mass on the Moon's surface is 1320 N.

Therefore, the force of gravity on the Moon's surface is greater than the force of gravity on the Earth's surface. The ratio of F_Earth to F_Moon is:

F_Earth / F_Moon = 792 N / 1320 N

= 0.6

So the force of gravity on the Moon's surface is about 60% of the force of gravity on the Earth's surface.

A typical electric refrigerator has a power rating of 500 Watts, which is the rate (J/s) at which electrical energy is supplied to do work needed to remove heat from the refrigerator. If the refrigerator releases heat to the room at a rate of 800 Watts, at what rate (in Watts) does it remove heat from inside of the refrigerator?

Answers

Answer:

The rate of heat removed from inside the refrigerator is 300 watts.

Explanation:

By the First Law of Thermodynamics and the definition of a Refrigeration Cycle, we have the following formula to determine the rate of heat removed from inside the refrigerator (\(\dot Q_{L}\)), in watts:

\(\dot Q_{L} = \dot Q_{H}-\dot W\) (1)

Where:

\(\dot Q_{H}\) - Rate of heat released to the room, in watts.

\(\dot W\) - Rate of electric energy needed by the refrigerator, in watts.

If we know that \(\dot Q_{H} = 800\,W\) and \(\dot W = 500\,W\), then the rate of heat removed from inside the refrigerator is:

\(\dot Q_{L} = \dot Q_{H}-\dot W\)

\(\dot Q_{L} = 300\,W\)

The rate of heat removed from inside the refrigerator is 300 watts.

Which of these ALL require direction?
Force, Time, Acceleration
Speed, Velocity, Distance
Displacement, Velocity, Force
Mass, Time, Speed

Answers

Answer:

i think it's either force or time

Explanation:

just a random guess, but i think one of those are right

If the acceleration vector of an object is directed parallel to the velocity vector, then Select one:
O a. the object is moving with a constant velocity.

O b. the object is turning.

O c. the object is at rest.

O d. the object is slowing down

O e. the object is speeding up.​

Answers

Answer:

a. The object is moving with a constant velocity.

A 4.0m wire carries a current of 7.0A toward +x direction. A magnetic force of 3.8e-6N acts on wire in the -y direction. a) Find the magnitude of the magnetic field producing the force. Answer in units of T

Answers

The magnitude of the magnetic field producing the magnetic force of 3.8 * \(10^{-6}\) N in the -y direction is 0.14 μ T

F = I L B sin θ

F = Magnetic force

I = Current

L = Length

B = Magnetic field

θ = Angle between wire and magnetic field

L = 4 m

I = 7 A

F = 3.8 * \(10^{-6}\) N

In a current carrying wire, the direction of magnetic field is perpendicular to he wire.

θ = 90°

B = F / I L sin θ

B = 3.8 * \(10^{-6}\) / 7 * 4 * sin 90°

B = 0.14 * \(10^{-6}\)  T

B = 0.14 μ T

Therefore, the magnitude of the magnetic field producing the force is 0.14 μ T

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what is the gravitational potential energy of each of the 2kg books in the image?

what is the gravitational potential energy of each of the 2kg books in the image?

Answers

Given data:

* The mass of the book is m = 2 kg.

* The height of book A is h_A = 1 m.

* The height of book B is h_B = 1.5 m.

* The height of book C is h_C = 2 m.

Solution:

(a). The gravitational potential energy of book A is,

\(U_A=\text{mgh}_A\)

where g is the acceleration due to gravity,

Substituting the known values,

\(\begin{gathered} U_A=2\times9.8\times1 \\ U_A=19.6\text{ J} \end{gathered}\)

Thus, the gravitational potential energy of book A is 19.6 J.

(b). The gravitational potential energy of book B is,

\(\begin{gathered} U_B=\text{mgh}_B \\ U_B=2\times9.8\times1.5 \\ U_B=29.4\text{ J} \end{gathered}\)

Thus, the gravitational potential energy of book B is 29.4 J.

(c). The gravitational potential energy of book C is,

\(\begin{gathered} U_C=\text{mgh}_C \\ U_C=2\times9.8\times2 \\ U_C=39.2\text{ J} \end{gathered}\)

Thus, the gravitational potential energy of book C is 39.2 J.

1 The displacement of a "spring + mass" system in simple harmonic motion on a frictional less surface can be described by the expression x = A cos(3rt/T). The spring constant is k and the mass is m. Describe the potential as well as the kinetic energies of the system at the following time instances. (a) At t = 0. [2] (b) At t = T. [2] (c) At t = T/6. [2] (d) At t= T/3. [2] (e) At t = T/2. [2]​

Answers

The potential and kinetic energy of the system at the following time instances is zero and maximum.

From the given,

The displacement of the system is, x = A cos(3πt/T)

1) At t =0, the displacement of the system is given by, x = cos(3π×0/T)= cos(0) = 1. The displacement is maximum at t=0. Hence, the potential energy is maximum and kinetic energy is zero.

2) At t=T, the displacement, x = cos(3πT/T)= cos(3π) = -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

3) At t = T/6, the displacement x = cos(3πT/6T)=cos(π/2)=0, the displacement is zero, and hence, both the potential and kinetic energy is zero.

4) At t=T/3, the displacement, x= cos(3πt/T)=cos(3πT/3)= -1. The displacement is minimum and hence, the potential energy is minimum and kinetic energy is maximum.

5) At t=T/2, the displacemetn x = cos(3πt/T) = cos(3πT/2T) = cos (3π/2)=0. Hence, both the potential and kinetic energy is zero.

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) The graph in the figure shows the position of a particle as a function of time as it travels along the x-axis.
What is the average velocity of the particle between t = 2.0 s and t = 4.0 s?

Answers

The average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.

What is average velocity?

Average velocity is the rate of change of an object's position, expressed as a vector quantity that tells both the speed and direction of the object's motion.

The average velocity of the particle between t = 2.0 s and t = 4.0 s can be calculated by taking the difference in the x-position of the particle at t = 4.0 s and t = 2.0 s, and dividing it by the difference in the time.
The x-position of the particle at t = 2.0 s is 4 m and the x-position of the particle at t = 4.0 s is 8 m.
Therefore, the difference in the x-position is 8 m - 4 m = 4 m.
The difference in time is 4.0 s - 2.0 s = 2.0 s. Therefore, the average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.

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- Practice: A rectangular boat has a width of 5 cm, a length of 8 cm, and a mass of 150 g.
How far will the boat sink into liquid with a density of 1.2 g/mL? Check your answer.

Answers

Answer:

the boat will sink 3.125 cm

Explanation:

According to Archimedes principle of buoyance, the buoyant force exerted on the part of the boat immersed in the liquid must  be equal to the weight of the fluid that was displaced. And if the boat is floating, the boat's weight must equal that buoyance force:

Weight boat = Weight of liquid displaced

boat's mass x g = mass of liquid displaced x g

simplifying "g":

boat's mass = mass of liquid displaced

In the case of the boat, its mass = 150 gr, and the volume of its submerged part is: 5 cm x 8 cm x h  With "h" the unknown we need to find (amount the boat sunk into the liquid).

Then:

boat's mass = 150 grams

Recall that density = Mass/Volume  -->  mass = Volume x density

mass of liquid displaced = volume x density = 5x8xh cm^3 x 1.2 g/mL

Recall as well that 1 mL = 1 cm^3 therefore:

mass of liquid displaced = 40 h x 1.2 grams = 48 h grams

solving for "h" (which will come in cm):

150 = 48 h

then h = 150/48 = 3.125 cm


Select the correct answer from each drop-down menu.
Rocky metallic objects found between the orbits of Mars and Jupiter are(drop down). The largest known of these is(drop down).

Answers

Answer:

Blank 1 (asteroids)

Blank 2 (Ceres)

Explanation:

Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.

What are asteroids?

Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]

A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,

Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.

The correct option from the drop-down menu is asteroids and ceres.

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In what ways does ecotourism help living things in ecosystems?

Answers

Ecotourism has the potential to eliminate the requirement to hunt wildlife for a living. Ecotourism generates revenue by maintaining the rainforest; deforestation is discouraged because it reduces tourist revenue.

What role does ecotourism play in biodiversity conservation?

Ecotourism firms safeguard biodiversity by preserving animals in their natural habitats and preserving natural ecosystems in biosphere reserves, wildlife sanctuaries, and national parks.

Can tourism save the environment?

Ecotourism contributes to the preservation of a destination's ecological and biological diversity. For example, since Costa Rica's jungle is so popular with visitors, inhabitants work hard to protect it instead of attempting deforest it for a short-term profit.

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An insulated aluminium calorimeter with a mass of 154 g, contains 90 ml of water at a temperature of 80°C 10 g of ice at -20°C is added to the water and the mixture stirred until the ice has dissolved. What is the final temperature of the water? (specific heat aluminium = 880 JkgK¹)

Answers

The final temperature of the water is approximately 19.8°C.First, we need to calculate the heat lost by the water as it cools down from 80°C to the final temperature.

What formula is used?

We can use the formula: Q = m × c × ΔT where Q is the heat lost, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

The mass of water in the calorimeter is:

90 ml = 90 g

The heat lost by the water is:

Q1 = 90 g × 4.18 J/g°C × (80°C - T)

Q = m × Lf + m × c × ΔT

The mass of ice added to the water is 10 g. The heat gained by the ice is:

Q2 = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

where 334 J/g is the heat of fusion of water.

Since the calorimeter is insulated, we know that the heat lost by the water must equal the heat gained by the ice. Therefore:

Q1 = Q2

90 g × 4.18 J/g°C × (80°C - T) = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

Simplifying and solving for T, we get:

T = 19.8°C

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