Plastic deformation behavior is the ability of a material to undergo a permanent deformation without fracturing or breaking. FCC (face-centered cubic), BCC (body-centered cubic), and HCP (hexagonal close-packed) metals all have different crystal structures and therefore exhibit different plastic deformation behavior.
In FCC metals, plastic deformation occurs through the movement of dislocations within the crystal structure. The dislocations move easily due to the closely packed atomic arrangement, resulting in a high ductility and toughness. FCC metals are commonly used in applications that require high deformability, such as in electrical wiring, jewelry, and coins.
In BCC metals, plastic deformation occurs through the movement of edge dislocations. The arrangement of atoms in BCC metals creates a more complex structure, which makes it more difficult for dislocations to move and results in lower ductility and toughness. BCC metals are commonly used in applications that require high strength, such as in structural components of buildings and bridges.
In HCP metals, plastic deformation occurs through the movement of screw dislocations. HCP metals have a close-packed hexagonal structure, which makes dislocation movement more difficult than in FCC metals but easier than in BCC metals. HCP metals are used in a variety of applications, including in the aerospace and defense industries due to their high strength-to-weight ratios.
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A person hears the echo of his own sound from a distance hill after 2 seconds . How far is the person from the hill , if the speed of sound is 330 m/s?
Answer:
the distance between the person and the hill is 330 m.
Explanation:
Given;
speed of sound in air, v = 330m/s
time of sound travel, t = 2 s
The distance between the person and the hill is calculated as;
\(Distance = Speed \ \times \ Time\\\\Time \ of \ echo = \frac{2\ \times \ distance}{speed} \\\\distance = \frac{Time \ of \ echo \ \times \ speed}{2} \\\\distance = \frac{2 \ \times \ 330}{2} \\\\distance = 330 \ m\)
Therefore, the distance between the person and the hill is 330 m.
100 points,
The National Park Service sometimes creates controlled burns to mitigate wildfires. How does a controlled burn limit the spread of wildfires?(1 point)
A controlled burn is used to make a path that helps a spreading wildfire arrive at a source of water.
A controlled burn temporarily shuts down parks so people won’t start campfires.
A controlled burn helps to remove plants and vegetation around buildings so a wildfire won’t destroy them.
A controlled burn removes dead vegetation that might otherwise help a wildfire start and spread.
A controlled burn removes dead vegetation that might otherwise help a wildfire start and spread.
What is a controlled burns?The term controlled burn refers to setting up an area in which the fire is controlled in order to avoid wild fires. These are deliberately set up in order to avoid the bush from burning down.
Let us recall that a wild fire is able to blaze across a large causing damage to a buildings as well as life and other properties in the way of the fire and could cause huge looses including loss of habitat.
Thus, the National Park Service sometimes creates controlled burns to mitigate wildfires because a controlled burn removes dead vegetation that might otherwise help a wildfire start and spread.
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1. Napagyayaman ang kaalaman sa parabula bilang akdang
pampanitikan.
2. Nakabubuo ng sariling konsepto tungkol sa parabula at sa layunin nito
sa mambabasa.
3. Nabibigyang ng sariling kahulugan ang matatalinghagang pahayag.
Bago tayo dunako sa ating aralin ay nais ko munang subukin kung
masasagot mo ang ilang katanungan hinggil sa ating aralin.
Napagyayaman ang kaalaman sa parabula bilang akdang pampanitikan?
→ Ang parabula ay mahalagang maunawaan at mapahalagahan bilang akdang pampanitikan sapagkat ito ay mga salita ni Hesus na kanyang ginamit upang maiparating sa mga tao ang mensahe ng Ama para sa kaligtasan ng mga makasalanan. Hindi lang ito malaking parte ng akdang pampanitikan ngunit pati na rin sa Katolikong paniniwala at pananampalataya.
Nakabubuo ng sariling konsepto tungkol sa parabula at sa layunin nito sa mambabasa.
→ Ito ay tumutukoy sa isang kwento na Kong saan ay tao ang gumaganap at into at patungkol sa bibliya
\(#CarryOnLearning\)Donna sent her grandson a birthday present. The box weighed 0.875 kilograms and the present itself weighed 6,800 grams. a. What was the gross weight of the package in kilograms
The gross weight of the package in kilograms that Donna send to her grandson as birthday present is 7.675 kg.
The weight of the box in which Donna has sent the present (w1)= 0.875 kg. Now we know, 1 kg = 1000 grams . So , 0.875 kg = 0.875 * 1000 = 875 grams.
Hence w1=875 grams is the weight of the box in which the present is there.
The weight of the present itself (w2)=6800 grams.
So, the gross weight of the package = w1+w2= 875 +6800 grams = 7675 grams.
So, the gross weight of the package ( the box+the gift) = 7675grams =7675 / 1000 = 7.675 kg.
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A m = 2.88kg mass starts from rest and slides a distance d down a frictionless θ = 34.7° incline. While sliding, it comes into contact with an unstressed spring of negligible mass, as shown in the figure below. The mass slides an additional 0.185m as it is brought momentarily to rest by compression of the spring (k = 409N/m). Calculate the initial separation d between the mass and the spring.
The initial separation d between the mass and the spring is 0.14m.
A m = 2.88kg mass starts from rest and slides a distance d down a frictionless θ = 34.7° incline. While sliding, it comes into contact with an unstressed spring of negligible mass. The mass slides an additional 0.185m as it is brought momentarily to rest by compression of the spring (k = 409N/m).
The initial separation d between the mass and the spring can be calculated using the equation:
d = (2*m*g*sin(θ)) / k
Substituting in the given values, we get:
d = (2*2.88kg*9.8m/s2*sin(34.7°)) / 409N/m
d = 0.14m
Therefore, the initial separation d between the mass and the spring is 0.14m.
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Please help me by 8:00!!! Thank you!!
Answer: Im sure its 1/A
Explanation:.
help please help!!!!!!!!
1. Electron
2. Neutron
3. Nucleus
4. Atom
5. Molecule
nancy is in her early 60s and nervous about growing old because she doesn’t want to be limited in her daily functioning or lose her memory or judgement. how might you reassure nancy about her fears?
I would like assure Nancy by telling her her Dementia is not inevitable; while 10% will develop dementia in their lifetime, less than half of people above age 84 will have it. So there is a 90% chance that Nancy might not lose her memory or judgement.
What is Dementia?Dementia is described as a general term for loss of memory, language, problem-solving and other thinking abilities that are severe enough to interfere with daily life.
Dementia is characterized by impairment of at least two brain functions, such as memory loss and judgement.
So there are high chances that Nancy might not lose her memory or judgement and normal functioning.
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what is the distance in mm between these minima if the diffraction pattern falls on a screen 1.2 m from the slit?
The distance in mm between these minima is 0.29 ×\(10^{-3}\) m
For first minima, m=1, Then,
\(a\sin \theta_1 = \lambda_1 \Rightarrow \sin\theta_1 = \frac{\lambda_1}{a} \Rightarrow \theta_1 = \sin^{-1}\left(\frac{589.1\times10^{-9}}{2.4\times 10^{-6}}\right) = 14.2^{\circ}\)
\(a\sin \theta_2 = \lambda_2 \Rightarrow \sin\theta_2 = \frac{\lambda_2}{a} \Rightarrow \theta_2 = \sin^{-1}\left(\frac{589.6\times10^{-9}}{2.4\times 10^{-6}}\right) = 14.22^{\circ}\)
Hence the required angle is , (14.22 - 14.2) = 0.02o
The distance between these two minima,
\(\Delta y = y_2 -y_1 = \frac{D}{a}\left( \lambda_2-\lambda_1\right) = \frac{1.4}{2.4\times 10^{-6}}\left(0.5\times 10^{-9} \right ) = 0.29\times 10^{-3} \hspace{2mm} m\)
This distance is best measured using a microscope.
The length of a particular path taken by an object between two points is its distance, such as the distance traveled through a maze. In some cases, such as when a ball is thrown straight up or the Earth completes an orbit, this can even be a closed distance along a closed curve that begins and ends at the same location. The mathematical term for this is the curve's arc length. It is also possible to signify the distance traveled: a "ahead" distance is positive and a "backward" distance is negative.
When building vehicles or mechanical gears, it can be helpful to take circular distance—the distance covered by a
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the switch in the circuit in fig. p7.1 has been open for a long time. at the switch is closed. a) determine and b) determine for c) how many milliseconds after the switch has been closed will equal 100 ma?
The question asks us to determine the time it takes for the current to equal 100 mA after the switch in the circuit has been closed.
Let's break down the problem into smaller steps to find the answer:
a) To determine the time it takes for the current to equal 100 mA after the switch is closed, we need to consider the circuit's components and their values. However, the question does not provide the values of the components in the circuit. Therefore, we cannot determine the exact time it takes for the current to reach 100 mA without this information. It is important to have the values of the resistors, capacitors, and other components in the circuit to make an accurate calculation. Without this information, we cannot provide a specific answer. b) Similarly, without the values of the components, we cannot determine the current in the circuit at any specific time after the switch is closed. The current in the circuit depends on the voltage supplied, the resistance in the circuit, and the capacitance, if present. Without knowing these values, we cannot provide a specific answer. c) Finally, the question asks how many milliseconds it will take for the current to equal 100 mA after the switch has been closed. As mentioned earlier, without the values of the components in the circuit, we cannot calculate the time it takes for the current to reach 100 mA accurately. In summary, without the values of the components in the circuit, we cannot provide a specific answer to determine the time it takes for the current to equal 100 mA after the switch has been closed. It is essential to have this information to make accurate calculations.About MillisecondsA milliseconds is a unit of time in the International System of Units which is equal to one thousandth of a second and 1000 microseconds. The units of 10 milliseconds may be called a centimeter, and one in 100 milliseconds is a decisecond, but these names are rarely used. Below are the order of numbers for the smaller units of time below the second. Starting from milliseconds, microseconds, nanoseconds, picoseconds, femtoseconds, attoseconds, zeptoseconds and each value is based on a reference for seconds. The researchers managed to measure the fastest unit of time, zeptosecond, which is faster than seconds and milliseconds. The size of a zeptosecond is 0.000000000000000000001 (zero point septillion or zero point billion trillion) seconds.
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A baseball is thrown at 50 m/s horizontally from a height of 3 m. How far will the ball travel before it reaches the ground?
Answer:
Approximately \(39 \; \rm m\), assuming that the gravitational field strength is \(g = 9.81\; \rm m\cdot s^{-2}\) and that the air resistance on this baseball is negligible.
Explanation:
Start by finding the duration \(t\) of the flight of this baseball.
The SUVAT equation \(h = (1/2)\, g\, t^{2} + v_{0} \, t\) relates \(t\) to initial height \(h\), initial vertical velocity \(v_{0}\), and gravitational acceleration \(g\). (This equation applies only if the air resistance on the baseball is negligible.)
The initial vertical velocity of this baseball would be \(v_{0} = 0\; \rm m\cdot s^{-1}\) since this ball was thrown horizontally. The equation becomes:
\(\begin{aligned}h &= \frac{1}{2}\, g\, t^{2} + v_{0} \, t \\ &= \frac{1}{2}\, g\, t^{2}\end{aligned}\).
Rearrange and solve for \(t\):
\(\begin{aligned}t^{2} &= \frac{2\, h}{g} \end{aligned}\).
\(\begin{aligned}t &= \sqrt{\frac{2\, h}{g}} && (\text{$t \ge 0$)} \end{aligned}\).
(So is the case for other free fall motions where the initial vertical velocity is \(0\).)
Substitute in \(g = 9.81\; \rm m\cdot s^{-2}\) and the initial height of the baseball \(h = 3\; \rm m\):
\(\begin{aligned}t &= \sqrt{\frac{2\, h}{g}} \\ &= \sqrt{\frac{3\; \rm m}{9.81\; \rm m\cdot s^{-2}}} \\ &\approx 0.782\; \rm s\end{aligned}\).
In other words, the baseball would have flown for approximately \(0.782\; \rm s\) before landing. If there is no air resistance on this baseball, the horizontal velocity of this baseball would be constant (\(50\; \rm m\cdot s^{-1}\) until the ball lands.) This baseball would have travelled a horizontal distance of approximately:
\(50\; \rm m \cdot s^{-1} \times 0.782\; \rm s \approx 39\; \rm m\).
Name 3 input components
Answer:
keyboards
mouse
scanner
Users can interact with a system or computer using input components, which are objects or elements. Three pictures of the input elements are shown below:
1. Keyboard
2. Mouse
3. Touchscreen
Keyboard: Text, commands, and other data are entered into a computer or other electronic device through the most commonly used input device, the keyboard. To enter characters and perform specific actions, users can press a variety of keys.
Another important input device is the mouse, which enables users to control a cursor on a computer screen. Users can navigate through the graphical user interface and interact with the software program by moving the mouse and pressing its buttons.
Users can interact directly with the display screen through a touchscreen, which is a user interface, by touching it with their fingers.
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(03.04 MC)
If the distance between two charged particles is doubled, the force between them changes by a factor of...
1/2
1/4
2
4
Answer:
1/4
Explanation:
If the distance between two charges is doubled, the attraction of repulsion between the two becomes weaker, and decreases to 1/4 of the original value.
16g 2g/cm3 what is the Volume
Answer:
V = 1.25E-7 cubic meter
A machine lifts a 35 kg object doing 6860 J worth of work. How much power is produced by the machine if it lifts the object in 4 seconds?
350 W
60025 W
27440 W
1715 W
Answer:
Explanation:
We need the power equation for this which is
P = Work/time
We have everything we need to solve this (the mass of the object is extra information):
P = 6860/4
P = 1715W
The process of a nucleus giving off radioactive particles to become more stable is called
Answer:
Radioactive Decay
Explanation:
In a location where the speed of sound is 340 m/s, a 2,000 Hz sound wave impinges on two slits 30 cm apart. (a) At what angle is the first-order maximum located? (b) If the sound wave is replaced by 3.40 cm microwaves, what slit separation gives the same angle for the first-order maximum? cm (c) If the slit separation is 1.00 m, what frequency of light gives the same first-order maximum angle? Hz
We get: sinθ = (1)(0.17)/0.3, which simplifies to θ = sin^-1(0.17/0.3) = 33.6°. In the values for m (1), λ (0.034 m), and θ (33.6°), we get: d = (1)(0.034)/sin(33.6°) = 0.063 m = 6.3 cm. The frequency of light that gives the same first-order maximum angle is 3.00 x 10^8 Hz, which is in the radio wave part of the electromagnetic spectrum.
(a) To find the angle of the first-order maximum, we can use the equation: sinθ = mλ/d, where θ is the angle of diffraction, m is the order of the maximum (in this case, m = 1), λ is the wavelength of the sound wave (in this case, λ = v/f = 340/2000 = 0.17 m), and d is the slit separation (d = 30 cm = 0.3 m). Plugging these values into the equation, we get: sinθ = (1)(0.17)/0.3, which simplifies to θ = sin^-1(0.17/0.3) = 33.6°.
(b) To find the slit separation that gives the same angle for the first-order maximum with 3.40 cm microwaves, we can use the same equation as in part (a), but with different values for λ and d. We want to solve for d, so we can rearrange the equation as: d = mλ/sinθ. Plugging in the values for m (1), λ (0.034 m), and θ (33.6°), we get: d = (1)(0.034)/sin(33.6°) = 0.063 m = 6.3 cm.
(c) To find the frequency of light that gives the same first-order maximum angle with a slit separation of 1.00 m, we can use the same equation as in parts (a) and (b), but with different values for λ and f. We want to solve for f, so we can rearrange the equation as: f = m*v/d. Plugging in the values for m (1), v (speed of light = 3.00 x 10^8 m/s), and d (1.00 m), we get: f = (1)(3.00 x 10^8)/1.00 = 3.00 x 10^8 Hz. So the frequency of light that gives the same first-order maximum angle is 3.00 x 10^8 Hz, which is in the radio wave part of the electromagnetic spectrum.
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Which of these best describes convection currents?Aextremely fastBunpredictableCslow-movingDeasily visible
The correct option is D, These best convection currents are easily visible.
Convection is a mode of heat transfer that occurs through the motion of fluids, such as gases or liquids. When there is a temperature difference between two fluid regions, hotter regions tend to expand and become less dense, causing them to rise and cooler regions to sink. This process creates a flow of fluid, which carries heat away from the hotter region and toward the cooler one.
Convection plays a vital role in many natural phenomena, such as weather patterns, ocean currents, and the movement of magma in the Earth's mantle. It is also used in various engineering applications, such as cooling, heating, and fluidized bed reactors.
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Complete Question:
Which of these best describes convection currents?
A. extremely fast
B. unpredictable
C. slow-moving
D. easily visible
The isotope of plutonium 238 Pu is used to make thermoelectric power sources for spacecraft. Suppose that a space probe was launched in 2012 with 2.0 kg of 238 Pu.
The space probe launched in 2012 with 2.0 kg of plutonium-238 (238Pu) is utilized for thermoelectric power sources in spacecraft.
Plutonium-238 (238Pu) is an isotope of plutonium that undergoes radioactive decay, emitting heat in the process.
This unique property makes it an ideal choice for generating power in space missions where sunlight is limited, such as deep space probes or missions to distant planets. The heat produced by the radioactive decay of 238Pu is converted into electricity using thermoelectric materials.
In the context of the space probe launched in 2012, the 2.0 kg of 238Pu serves as the fuel for the thermoelectric power source.
The heat generated by the decay of the plutonium is harnessed to produce electricity through the Seebeck effect.
Thermocouples, made from two dissimilar materials, are used to create a temperature gradient. As the heat flows across the junction of the thermocouple, it creates a voltage difference that can be utilized to power the spacecraft's instruments, systems, and communication devices.
The use of 238Pu as a power source offers several advantages for space missions.
Unlike solar panels, which are dependent on sunlight, thermoelectric generators powered by plutonium-238 can operate in deep space or in regions where solar energy is insufficient.
This is particularly crucial for missions that venture beyond the orbit of Mars or explore dark, shadowed areas where sunlight is scarce.
Additionally, the longevity of 238Pu's decay heat allows for prolonged power generation, ensuring continuous operation and data transmission over long-duration missions.
Plutonium-238 (238Pu) is a scarce and highly valuable resource due to its applications in space exploration. It is primarily produced through the irradiation of neptunium-237 in nuclear reactors.
The production and handling of 238Pu require strict safety measures due to its high radioactivity. Furthermore, the dwindling global supply of 238Pu has posed challenges for future space missions relying on this isotope.
The development of alternative power sources and the search for innovative ways to produce and utilize plutonium-238 remain areas of active research in the field of space exploration.
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The properties of element 17 are most similar to which of the following elements?
Bromine
Sulfur
Argon
Lithium
Halogens are highly reactive nonmetal elements in group 17 of the periodic table. ... Halogens are among the most reactive of all elements. They have seven valence electrons, so they are very “eager” to gain one electron to have a full outer energy level.
4. A student has 500 identical, rectangular sheets of paper. The mass of 1.0m² of the paper is 0.080 kg. (2) Using a metre rule, she measures the length of one sheet of paper and its width. The length is 0.300 m and the width is 0.210m. (1) Calculate the mass of one sheet of paper.
mass of one sheet of paper is 0.00504 kg or 5.04g.
First we will find the surface area of a single sheet of paper
surface area = length ×width
surface area =0.3×0.21
surface area =0.063m²
now 0.063m² is the surface area of a single sheet of paper .
so now we will find number of papers required to form 1m² of area
which will be given by dividing 1m² by surface area of a single sheet
i.e.
number of sheets required = 1/0.063m²
number of sheets required =15.87
mass of one sheet = mass of 1 m^2 of paper / number of times narrower
mass of one sheet = 0.080 kg / 15.873
mass of one sheet = 0.00504 kg
mass of one sheet of paper is 0.00504 kg or 5.04g.
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A 1.5 kg ball is kicked with an initial velocity of 26 m/s at an angle of 30 degrees above the horizontal. How far did the ball go before returning to the ground? Answer in meters.
The maximum height travelled by the ball before returning to the ground is 8.62 m.
What is the maximum height travelled by the ball?
The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.
H = (u²sin²θ) / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (26² (sin 30)²) / (2 x 9.8)
H = 8.62 m
Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.
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looking at the image above, which example is creating a sound wave with the shortest wavelength?
"from the coordinates obtained in part b, find the slope of the position-time relationship for the bowling ball using the ""rise over run"" algortithm."View Available Hint(s) 0.40 s 2.5m 2.5m/s 0.40m/s Submit
To find the slope of the position-time relationship for the bowling ball using the "rise over run" algorithm, you'll first need the coordinates obtained in part b. The slope represents the rate of change of position with respect to time, and in this context, it is equal to the ball's velocity.
Using the "rise over run" algorithm, the slope (velocity) can be calculated by dividing the change in position (rise) by the change in time (run). In this case, the coordinates represent the position and time values, with the first coordinate being the initial position and time, and the second coordinate being the final position and time.
Assuming you have two coordinates (x1, y1) and (x2, y2), where x values represent time and y values represent position:
Slope = (y2 - y1) / (x2 - x1)
Once you have the coordinates from part b, plug the values into the formula above to calculate the slope. This will give you the velocity of the bowling ball, which represents the relationship between the position and time for the given motion.
For example, if the coordinates from part b are (0.4 s, 2.5 m) and (0.8 s, 5 m), the slope would be:
Slope = (5 m - 2.5 m) / (0.8 s - 0.4 s) = 2.5 m / 0.4 s = 6.25 m/s
In this example, the slope (velocity) of the position-time relationship for the bowling ball is 6.25 m/s.
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The drop time can be calculated as follows: where y is the vertical height of the table and g is the
acceleration due to gravity. How did the calculated drop time compare to the average of your measured drop
times? Find the percent error using the following equation:
What factors might cause the differences?
Answer:
Tt can be calculated by copy
How are nuclear reactions used to meet the world’s energy needs?
A. Both fusion and fission are used to generate electricity, but more fission reactors than fusion reactors are in use.
B. Fission reactors are used to generate electricity, but fusion is not yet practical enough to be used.
C. Both fusion and fission are used to generate electricity, but more fusion reactors than fission reactors are in use.
D. Fusion reactors are used to generate electricity, but fission is not yet practical enough to be used.
Fission reactors are used to generate electricity, but fusion is not yet practical enough to be used.
What is a nuclear reaction?The term nuclear reaction has to do with a type of reaction in which there is a change in the nucleus of an atom. This leads to the release of a tremendous amount of energy.
Hence, the way in which nuclear reactions can be used to meet the world’s energy needs is that fission reactors are used to generate electricity, but fusion is not yet practical enough to be used.
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Thirteen resistors are connected across points A and B as shown in the figure. If all the resistors are
accurate to 2 significant figures, what is the equivalent resistance between points A and B?
The equivalent resistance between points A and B in the diagram is 22 Ω
How do I determine the equivalent resistance?We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:
Resistor 1 (R₁) = 6 ΩResistor 2 (R₂) = 6 ΩResistor 3 (R₃) = 6 ΩEquivalent resistance (Rₜ) = ?1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₜ = 1/6 + 1/6 + 1/6
1/Rₜ = 3/6
1/Rₜ = 1/2
Rₜ = 2 Ω
Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:
Resistor 1 (R₁) = Resistor 2 (R₂) = ... = Resistor (R₁₁) = 2 ΩEquivalent resistance (R) =?R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁
R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
R = 22Ω
Thus, we can conclude that the equivalent resistance is 22 Ω
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Is it speed, velocity, or acceleration of a football just after being kicked?
It is velocity of a football just after being kicked. Velocity is the speed and direction of an object, and it is a vector quantity, meaning it has both magnitude and direction.
When a football is kicked, it has a certain velocity in a particular direction, which can be measured using a speedometer or other measuring device. Acceleration, on the other hand, refers to the rate of change of velocity, so it would only be relevant if the football's velocity was changing after being kicked (for example, if it were slowing down due to air resistance or gravity).
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PLEASE HELP!! HURRYY
If a step down transformer has 220 V coming into the primary coil of 30 turns and 140 V is coming out of the second coil, how many turns in are in the secondary coil?
a.) 30
b.) 19
c.) 0.05
d.) 7
Answer:
We can use the formula for the transformer voltage ratio, which states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the output voltage to the input voltage:
Np/Ns = Vp/Vs
where Np is the number of turns in the primary coil, Ns is the number of turns in the secondary coil, Vp is the input voltage, and Vs is the output voltage.
We know that Vp = 220 V and Vs = 140 V, and we are trying to find Ns. We also know that Np = 30, since that is the number of turns in the primary coil. Substituting these values into the formula, we get:
30/Ns = 220/140
Simplifying the right side of the equation, we get:
30/Ns = 11/7
Cross-multiplying, we get:
11Ns = 210
Dividing both sides by 11, we get:
Ns = 19
Therefore, the answer is b.) 19.
Under certain circumstances, the grounded (neutral) conductors of a residential service ____ permitted to be sized smaller than the phase conductors.
Under certain circumstances, the grounded (neutral) conductors of a residential service are permitted to be sized smaller than the phase conductors.
What is conductors?
A material that easily permits the flow of electricity is referred to as an electrical conductor. Conductivity is the quality of conductors that enables them to conduct electricity.
Electric current is the name given to the movement of electrons through a conductor. Voltage is the amount of power necessary to cause that current to flow through the conductor.
What is phase ?
Phases are parts of a system that are mechanically separable from other parts of the system and are physically distinct from other parts of the system. types of substance. Solid, liquid, or gaseous phases can exist in a system. Strong atomic bonding and high viscosity, which produce a hard form in solids, are their distinguishing characteristics.
Therefore, Under certain circumstances, the grounded (neutral) conductors of a residential service are permitted to be sized smaller than the phase conductors.
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