Compare this number based on the Avogadro's number finding the % error. Discuss why the % error is well over 100% and how that would be possible

Answer:

22.4 Liters at STP

Explanation:

General Rule => Any (ALL) gas will occupy 22.4 Liters at Standard Conditions (STP).

Answer:

D. Paper D, paper C, paper A, paper B

Explanation:

Please check the attached image for a diagram showing clearly the pH colour chart

pH measures how acidic or alkaline a solution is. The pH scale ranges from 1 - 14

Solutions with a pH less than 7 are acidic

Solutions with a pH equal to 7 are neutral

In the image, test papers D and C occur on the left, thus, they are acidic

Solutions with a pH greater than 7 are alkaline

pH test papers are used to test to test how acidic or alkaline a solution is

The number of moles of NaCl present in 276.50 mL of 1.55 M NaCl solution is 0.429 mol.

To find the number of moles of NaCl in a given solution, we can use the formula: moles of solute = concentration of solution x volume of solution We are given the following information:Concentration of solution = 1.55 MVolume of solution = 276.50 mL

To use this formula, we need to convert the volume of the solution from milliliters (mL) to liters (L).1 L = 1000 mLTherefore, 276.50 mL = 0.27650 LNow, we can substitute the given values in the formula and calculate the number of moles of NaCl present in the solution:moles of solute = concentration of solution x volume of solution= 1.55 M x 0.27650 L= 0.429 molTherefore, there are 0.429 moles of NaCl in 276.50 mL of 1.55 M NaCl solution. Hence, the correct option is 0.429.

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Answer: B) A model used to explain how or why a phenomenon occurs.

Explanation: Scientific theory explain through models will educate students more. they can learn in both audio visual ways and keep that situation in brain always. a model or a blue print is a better way of educating on scientific theory as the aim. material, observation and conclusion can be derived by actually viewing the phenomenon.

Answer: Id answer it but i think your copy and paste got corrupted!

Explanation:

Answer:

3.38 moles.

Explanation:

The following data were obtained from the question:

Mass of copper (Cu) = 215 g

Number of mole of copper (Cu) =...?

The number of mole of copper (Cu) in 215 g can be obtained as follow:

Mass of copper (Cu) = 215 g

Molar mass of copper (Cu) = 63.55 g/mol

Number of mole of copper (Cu) =...?

Mole = mass /Molar mass

Mole of Cu = 215/63.55

Mole of Cu = 3.38 moles

Therefore, 3.38 moles of copper (Cu) is present in the sample.

The moles of carbon atoms are there in 0.500 mole of C₂H₆ is:

c. 1.00 mole

To determine the number of moles of carbon atoms, we need to use the mole ratio between C₂H₆ and carbon atoms. The mole ratio is based on the balanced chemical equation, which shows the relationship between the number of moles of different elements or compounds.

In this case, the mole ratio between C₂H₆ and carbon atoms is 1:2. This means that for every 1 mole of C₂H₆, there are 2 moles of carbon atoms.

Using this mole ratio, we can set up a conversion factor to calculate the moles of carbon atoms:

0.500 mole C₂H₆ * (2 moles C / 1 mole C₂H₆)

By multiplying the given quantity (0.500 mole C₂H₆) by the conversion factor, we cancel out the mole unit for C₂H₆ and end up with the moles of carbon atoms.

Calculating this expression gives us:

0.500 mole C₂H₆ * (2 moles C / 1 mole C₂H₆) = 1.00 mole C

Therefore, there are 1.00 mole of carbon atoms in 0.500 mole of C₂H₆.

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Moles of Allura Red = stock volume x stock concentration

= 5.00/1000 x 1.90 x \(10^{-4}\) = 9.50 x \(10^{-7}\) mol

Volume of diluted solution = 100 mL = 0.100 L

The concentration of diluted solution = moles/volume

= 9.50 x\(10^{-7}\)/0.100 = 9.50 x \(10^{-6}\) M

Dilution is the process of reducing the concentration of a solute in a solution by simply adding more solvent to the solution, eg water. To dilute a solution, add solvent without adding solute. Dilution is the process of adding solvent to a solution to reduce the concentration of solutes.

Concentration is the process of removing solvent from a solution to increase the concentration of solutes in the solution. Dilution is the process of reducing the concentration of a solute in a solution usually by simply mixing the solute with more solvent. Add water to the solution. Diluting a solution means adding solvent without adding solute.

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Answer:

hey here is the answer to your question.

Explanation:

1) Write a balanced equation for the reaction occurring. (*Iron occurs in a few different oxidation states, but I will assume we're referring to Fe(II) or Fe2+)

Fe + CuSO4 -> Cu + FeSO4

2) Calculate the number of moles of each reactant.

Fe: 1.924 g * (1 mol / 55.85 g) = 0.03455 mol Fe

CuSO4: 0.1363 L * (0.0750 mol / 1 L) = 0.01022 mol CuSO4

3) Determine the limiting reactant. Because we have fewer moles of copper(II) sulfate and are reacting both reactants in a 1:1 ratio, we will run out of copper(II) sulfate first, making it the limiting reactant.

4) Convert moles of the limiting reactant to moles and grams of product of interest.

0.01022 CuSO4 (1 mol Cu / 1 mol CuSO4 ) (63.55 g Cu / 1 mol Cu) = 0.6495 g Cu

There are 6 σ bonds and 3 π bonds in H₃C-CH₂-CH═CH-CH₂-C≡CH.

In the given chemical structure, σ (sigma) bonds are formed by the overlap of atomic orbitals in a head-to-head fashion. These bonds allow for the sharing of electrons between the atoms involved. Each single bond, whether between carbon and hydrogen or carbon and carbon, is a σ bond. Therefore, we count the number of single bonds to determine the number of σ bonds.

In this molecule, there are six single bonds: three between carbon and hydrogen  and three between carbon and carbon.Hence, there are 6 σ bonds in total.

In the given structure, there are three double bonds: one between carbon atoms (═), one between carbon and carbon (ch═ch), and one between carbon and carbon (c≡ch). Each double bond consists of one σ bond and one π bond.

Therefore, there are 6 σ bonds and 3 π bonds in the given chemical structure.

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The heat that is evolved in the process is 29.2 kJ of heat.

The first step in the process would be to obtain the limiting reactant of the system and then we would have that;

Number of moles of the SO2 = 0.5 * 15/0.082 * 310

= 0.295 moles

Number of moles of oxygen = masa/molar mass = 16 g/32 g/mol = 0.5 moles

If 2 moles of SO2 reacts with 1 mole of O2

0.295 moles of SO2 will react with 0.295 moles * 1/2

= 0.1475 moles

Hence the SO2 is the limiting reactant.

If 2 moles of SO2 produced 198 kJ .of heat

0.295 moles of SO2 will produce 0.295 moles * 198 kJ/2 moles

= 29.2 kJ of heat

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Answer:

A,B,E,F

Explanation:

The percentage of \(SiO_{2}\) in a sample weighing 7.69 g if 3.27 g of \(SiO_{2}\) have been recovered is option D) 67%.

To arrive at this answer, we can use the formula:
Percentage of \(SiO_{2}\) = (Mass of recovered \(SiO_{2}\) ÷ Mass of sample) x 100
Plugging in the values given in the question, we get:
Percentage of \(SiO_{2}\) = (3.27 g ÷ 7.69 g) x 100 = 42.5%
However, this is the percentage of \(SiO_{2}\) recovered, not the percentage of \(SiO_{2}\) in the original sample. To find the latter, we can use the fact that the mass of \(SiO_{2}\) in the original sample must be equal to the mass of \(SiO_{2}\) recovered:
Mass of \(SiO_{2}\) in original sample = Mass of \(SiO_{2}\) recovered
Let x be the percentage of \(SiO_{2}\) in the original sample. Then we can set up the equation:
x% of 7.69 g = 3.27 g
Solving for x, we get:
x = (3.27 g ÷ 7.69 g) x 100 = 42.5%
So the percentage of \(SiO_{2}\) in the original sample is 42.5%, which means that option A is incorrect.
To get the main answer, we need to calculate the percentage of the sample that is not \(SiO_{2}\):
Percentage of other substances = 100% - Percentage of \(SiO_{2}\)
Percentage of other substances = 100% - 42.5% = 57.5%
This means that the original sample was 57.5% other substances and 42.5% \(SiO_{2}\).
Now we can use this information to find the percentage of \(SiO_{2}\) in a sample weighing 7.69 g if 3.27 g of SiO2 have been recovered:
Percentage of \(SiO_{2}\) = (Mass of \(SiO_{2}\) in sample ÷ Sample mass) x 100
Let y be the mass of the sample that is not \(SiO_{2}\). Then we can set up the equation:
3.27 g = 0.425(7.69 g) + y
Solving for y, we get:
y = 7.69 g - 3.27 g/0.425 = 12.56 g
So the mass of the sample that is not \(SiO_{2}\) is 12.56 g.
Now we can calculate the mass of \(SiO_{2}\) in the original sample:
Mass of SiO2 in sample = 0.425(7.69 g) = 3.27 g
Since 3.27 g of \(SiO_{2}\) have been recovered, the mass of \(SiO_{2}\) in the remaining sample is:
3.27 g + 3.27 g = 6.54 g
Therefore, the percentage of \(SiO_{2}\) in the remaining sample is:
Percentage of \(SiO_{2}\) = (6.54 g ÷ 20.25 g) x 100 = 32.3%
This means that the sample weighing 7.69 g originally contained 42.5% \(SiO_{2}\) and the remaining sample after 3.27 g of \(SiO_{2}\) was recovered contains 32.3% \(SiO_{2}\).

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Answer:

D THEY ADAPT TO THE THICKER FUR AND EVOLVE.

Explanation:

Hydration of alkynes with h3o typically requires a mercury catalyst is a false statement.

Alkynes are first hydrated by the addition of the first water molecule. But this initial hydration event results in the formation of an enol, an alcohol joined to a vinyl carbon.

Enols instantly go through a particular kind of isomerization process termed tautomerization to create carbonyl groups, such as aldehydes or ketones. With the understanding that aldehydes occur on terminal alkyne carbons, this reaction is referred to as "enol-keto" tautomerization to make things straightforward.

Similar to hydration (adding water) of alkenes, hydration of alkynes necessitates the use of a potent acid, typically sulfuric acid with a mercuric sulfate catalyst.

Therefore,  Hydration of alkynes with h3o typically requires a mercury catalyst is a false statement.

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We need 65mL of the 11.6M stock hydrochloric acid to prepare 250mL of 3.0M HCl solution.

To calculate the volume of 11.6M stock hydrochloric acid needed to prepare 250mL of 3.0M HCl solution, we need to use the formula:
M1V1 = M2V2
where M1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, M2 is the desired concentration of the diluted solution, and V2 is the final volume of the diluted solution.
In this case, we know:
M1 = 11.6M
V1 = unknown (what we need to find)
M2 = 3.0M
V2 = 250mL
Plugging these values into the formula, we get:
11.6M x V1 = 3.0M x 250mL
To solve for V1, we can rearrange the formula:
V1 = (3.0M x 250mL) / 11.6M
V1 = 65mL (rounded to the nearest mL)

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Density is Mass per Volume

so

0,8765 g/ml = Mass of Benzene / 250 ml

Mass of Benzene = 219,125 gram

so 250 ml of benzene is equal to 219,125 gram

Answer:

I exist ;-;

Explanation:

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

\(Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2\)

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

\(m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2\)

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

\(m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu} \\\\m_{Cu}=0.380gCu\)

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

\(m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3} \\\\m_{AgNO_3}=2.03gAgNO_3\)

Best regards!

Answer:

4 moles of HCl will be required to produce 2 moles of H2.

Explanation:

A balanced chemical equation gives the stoichiometric ration of moles of reactants required to produce a certain number of moles of products. The ratio of moles of reactants to moles of products is known as the mole ratio and is constant for a given chemical reaction.

In the given balanced equation of reaction shown below:

Zn + 2HCl → ZnCl2 + H2

The mole ratio of HCl and H2 is 2:1. This means that in this reaction between Zinc metal and hydrochoric acid to produc zinc chloride and hydrogen gas, every two moles of hydrochloric acid used in the reaction will result in the production of one mole of hydrogen gas.

Therefore for two moles of H2 to be obtained from the reaction, twice the number of moles of HCl is required.

Moles of HCl required = 2 × 2 moles = 4 moles of HCl.

Shortest wavelength of light that can be emitted by a hydrogen atom is 95.0 nm

Emission is the transfer of electron from higher energy level to lower energy level.

Shortest wavelength is the transition with higher energy.

So,

The electron emits from \($n=5$\) to \($n=1$\) level.

The lowest state is:

\(n_1=1$\\\mathrm{n}_2=5$$\)

The Balmer-Rydberg equation is

\($$\begin{aligned}& \frac{1}{\lambda}=R_{\infty}\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right] \\& \mathrm{n}_2=5 \text { and } \mathrm{n}_1=1 \\& \mathrm{R}=1.097 \times 10^7 \mathrm{~m}^{-1}\end{aligned}$$\)

\(\frac{1}{\lambda}=R_{\infty}\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]$\\\\$\Rightarrow \frac{1}{\lambda}=1.097 \times 10^7 \mathrm{~m}^{-1}\left[\frac{1}{1^2}-\frac{1}{5^2}\right]$\\\\$\Rightarrow \frac{1}{\lambda}=1.097 \times 10^7 \mathrm{~m}^{-1} \times 0.96=10531200 \mathrm{~m}^{-1}$$\lambda\\\\=\frac{1}{10531200 \mathrm{~m}^{-1}}\\\\=9.50 \times 10^{-8} \mathrm{~m}$$\lambda\\\\=95.0 \times 10^{-9} \mathrm{~m}\\\\=\mathbf{9 5 . 0} \mathbf{n m}$\)

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What is the shortest wavelength of light that can be emitted by a hydrogen atom, if the electron is initially in the n=5 level? Give your answer accurate to three significant figures.

You can use a very simple formula for first order decay...

Fraction Remaining (FR) = 0.5n where n is the number of half lives that have elapsed.

In the current problem we want to find the FR, and we know n = 2 half lives elapsed (60 yr/30yr = 2)

FR = 0.52 = 0.25

Since we started with 5.0 g, and we have 0.25 (1/4) left, that would be 5.0 g x 0.25 = 1.25 g

Answer:

ngl ts ngl ts ts ngl...imma keep it a buck.96 ion got the answers kanye do.

Explanation:

Let's see that in the periodic table, we have the molar mass of every element. In this case, carbon has a molar mass of 12 g/mol and oxygen of 16 g/mol. The conversion from grams to moles is dividing the mass by the sum of the molar mass of the compound.

In this case, we have 1 atom of carbon and two atoms of oxygen. Doing the algebraic sum for each of them with their molar mass we're going to obtain:

So, 225 g of carbon dioxide will be:

So, finally, we have 5.11 moles in 225 grams of CO2.

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons.

An Arrhenius acid increases the number of\(H^+\) ions in the water.

According to the Arrhenius theory, a substance which has hydrogen atom and can easily give hydrogen ion or proton in its aqueous solution is called as Arrhenius acid.

For example, when hydrochloric acid is dissolved in water, it forms chloride ion (\(Cl^-\)) and hydronium ion (\(H_3O^+\)).

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For a  concentration of  is initially 0.150 M before it proceeds to equilibrium, the equilibrium concentration of B  is mathematically given as

x=3.0*10^{-7}m

Generally, the equation for the  change in Gibbs free energy   is mathematically given as

dG=-RTInK

Therefore

31.5*10*^{3}=-(8.314)(298)(ink)

K=3*10^(-6)

Eqution

A--->B

K=x/0.1-x

x=3.0*10^{-7}m

In conclusion, the equilibrium concentration

x=3.0*10^{-7}m

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Answer:

Enter your numerical answer to 1 decimal place. Do not include the units of "g". Question: Question 14 1 pts Consider the following reaction, where A and E are hypothetical elements. A+3E --> AE The atomic mass of A is 42.1 amu. The atomic mass of Eis 56.2 amu. If 42.6 g of A fully reacts, how many grams of AE, are expected to form?

The movement of chloride ions into the red blood cells (RBCs) in exchange for bicarbonate ions is known as the chloride shift or Hamburger phenomenon.

This occurs in the lungs and helps to regulate the pH of the blood. During gas exchange, oxygen diffuses into the bloodstream and carbon dioxide diffuses out of the bloodstream.

This increase in oxygen levels and decrease in carbon dioxide levels leads to a decrease in the production of bicarbonate ions in RBCs and an increase in the production of chloride ions.

The chloride ions then move into the RBCs to maintain electroneutrality, while bicarbonate ions move out of the RBCs into the plasma.

In tissues, the opposite process occurs, with bicarbonate ions moving into the RBCs and chloride ions moving out of the RBCs, helping to maintain pH homeostasis in the body.

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Answer:

Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume.

Explanation:

Hopefully that helped:/

Answer: Density, mass of a unit volume of a material substance. Hope this helps!