consider the integral ∫01∫12x12f(x,y)dydx. sketch the region of integration and change the order of integration.

Step-by-step explanation:

101° = (6x + 5)° (by F angles)

Therefore 6x = 96 and x = 16.

Answer:

X=16

Step by Step explanation:

We want to know what x is

We would have to make an equation

REMEMBER: *Any 4 angles has to equal to 360 degrees*

Its pretty easy to remember

Triangles: All interior angles must add up to 180

4 angles shapes: All interior angles must add up to 360

If any shape has more than 4 angles, calculate how many angles there are and multiply them by 90

Okay so this “shape” has only 1 angle given And that would be 101

So we know right away that the angle vertical to it (angle 8) is also 101

Now we know two sides and since the other two unknown sides are vertical so they have to be equal, we really only have to focus on the 101 angle.

So we know that 2 ngles are 101

Thats all we need to know

make them equal

6x+5=101

Now sole and you would get 16

Answer: -14

Step-by-step explanation:

what is the question your trying to find, if you could repile to this so I can try to figure it out. (I'll be heading off soon)

(a)  Total urine volume is excreted during this time period is 442.34 mL.

(b) Equations for the velocity of urine is v = (-3 x \(V_t\) + 7.35) / 2.46 x \(10^{-5}\)

(a) To determine the total urine volume excreted during this time period, we need to integrate the flow rate function over the given time period. However, we are given two different equations for the flow rate for different ranges of time:

For t < 12 seconds, V = -0.306 x  \((t-7)^2\)  + 15

For 12 ≤ t < 26.7 seconds, V = -3 x \(V_t\)  + 7.35

To find the total urine volume, we need to first determine the time at which the flow rate changes from the first equation to the second.

We can do this by setting the two equations equal to each other and solving for t:

-0.306 x  \((t-7)^2\)  + 15 = -3 x \(V_t\) + 7.35

0.306 x  \((t-7)^2\) + 3 x \(V_t\)  = 7.65

0.306 x \((t-7)^2\) = 7.65 - 3 x \(V_t\)

\((t-7)^2\) = (7.65 - 3 x \(V_t\) ) / 0.306

t = 7 +/- \(\sqrt{((7.65 - 3 \times Vt) / 0.306)}\)

Since t < 12 for the first equation, we can ignore the negative root and use the positive root to find the time at which the flow rate changes:

t = 7 + \(\sqrt{((7.65 - 3 \times 12) / 0.306)}\)= 10.76 seconds

Now we can integrate each equation separately over their respective time ranges:

For 0 ≤ t < 10.76 seconds:

∫ V dt = ∫ (-0.306 x \((t-7)^2\) + 15) dt

= [-0.102 x \((t-7)^3\) + 15t] from t=0 to t=10.76

= 121.86 mL

For 10.76 ≤ t < 26.7 seconds:

∫ V dt = ∫ (-3 x \(V_t\) + 7.35) dt

= [-1.5 x \(V_t^2\) + 7.35t] from t=10.76 to t=26.7

= 320.48 mL

Therefore, the total urine volume excreted during this time period is:

121.86 mL + 320.48 mL = 442.34 mL

(b) To develop equations for the velocity of urine as it exits the body, we need to use the continuity equation, which states that the flow rate (V) is equal to the cross-sectional area (A) multiplied by the velocity (v):

V = A x v

We are given that the urethra has a diameter of 5.6 mm, which means the radius is 2.8 mm (or 0.0028 m).

The cross-sectional area can be calculated using the formula for the area of a circle:

A = π x \(r^2\)

A = 3.14 x \((0.0028)^2\)

A = 2.46 x   \(10^{-5}\) \(m^2\)

Now we can rearrange the continuity equation to solve for the velocity:

v = V / A

Substituting the given equations for V, we get:

For t < 12 seconds:

v = (-0.306 x \((t-7)^2\) + 15) / 2.46 x  \(10^{-5}\)

For 12 ≤ t < 26.7 seconds:

v = (-3 x  \(V_t\) + 7.35) / 2.46 x \(10^{-5}\)

Note that the velocity will be in units

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Question:-

The flow of urine from the bladder, through the urethra, and out of the body, is induced by increased pressure in the bladder resulting from muscle contractions around the bladder with simultaneous relaxation of the muscles in the urethra. The mean pressure in the bladder can be estimated using the velocity of urine as it exits the body. Assume that the bladder is about 5 cm above the external urethral orifice. (This height is different for males and females.) The flow rate of urine from the bladder can be approximately described with the following equations, where t is time in seconds, and V is flow rate in mL/s:

V = -0.306 X (t – 7)2 + 15 Osts 12

V = -3 X Vt 12 + 7.35 12 st < 26.7

(a) How much total urine volume is excreted during this time period?

(b) Develop equations for the velocity of as it exits the body. Assume that the urethra is 5.6 mm in diameter.

Answer:

x=6/5

y=1/5

z=14/5

i think i  not 100% sure

(a) tangent line to the graph of f(x) = x^3 at the point (4,2).

(b) equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12).

(a) To find the equation of the tangent line to the graph of f(x) = x^3 at the point (4,2), we need to find the slope of the tangent line at that point. We can do this by taking the derivative of f(x) with respect to x and evaluating it at x = 4. The derivative of f(x) = x^3 is f'(x) = 3x^2. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Once we have the slope, we can use the point-slope form of a linear equation to write the equation of the tangent line.

(b) Similarly, to find the equation of the tangent line to the graph of f(x) = x^2 - x at the point (4,12), we differentiate f(x) to find the derivative f'(x). The derivative of f(x) = x^2 - x is f'(x) = 2x - 1. Evaluating f'(x) at x = 4 gives us the slope of the tangent line. Using the point-slope form, we can write the equation of the tangent line.

In both cases, the equations of the tangent lines will be in the form y = mx + b, where m is the slope and b is the y-intercept.

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Answer:

She will have a total of 17 pounds.

Step-by-step explanation:

You could simply put the question is slop intercept form to figure it out from there.

y = m(x) + b

y = 3(x) + 8

y = 3(3) + 8

y = 9 + 8

y = 17

Pls mark Brainliest with the crown

The quadratic functions are  x = 3y2 – 6y + 5, y + 3 = –2 x 2+ 5 , y = 2 x 2 – 8 x + 6, y = 5 x(x + 9) – 8, y – 2 x 2 = 3 x – 2 x 2 + 4

A quadratic function is defined as a function of a polynomial where the highest degree of any variable is 2.

It has a  standard form of;

ax² + bx + c = 0

Given that;

Hence, the functions are x = 3y2 – 6y + 5, y + 3 = –2 x 2+ 5 , y = 2 x 2 – 8 x + 6, y = 5 x(x + 9) – 8, y – 2 x 2 = 3 x – 2 x 2 + 4

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The complete question:

Select all of the following that are quadratic functions. x = 3y2 – 6y + 5, y + 3 = –2 x 2+ 5 , y = 2 x 2 – 8 x + 6, y= –7 x – 4, y – 3 x = 4 x 3 – x2 + 9, y = 5 x(x + 9) – 8, y – 2 x 2 = 3 x – 2 x 2 + 4

The volume of the tree stump is approximately calculated as: 2327.6 cubic inches.

First, we need to convert the circumference from inches to feet since the height is given in feet:

50 in ÷ 12 in/ft = 4.17 ft (rounded to two decimal places)

Now, we can use the formula for the volume of a cylinder:

V = πr²h

where r is the radius and h is the height. We can find the radius from the circumference:

C = 2πr

50 in = 2πr

r = 25/π in ≈ 7.96 in (rounded to two decimal places)

Now we can calculate the volume in cubic inches:

V = π(7.96 in)²(1.9 ft x 12 in/ft)

V ≈ 2327.6 cubic inches

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False. The average for our class on quiz 3 was 74%. That means that at least one student in our class scored exactly 74%.

It is possible that no student in the class scored exactly 74% on the quiz, even if the class average was 74%. The class average is calculated by adding up all the individual scores and dividing by the total number of students, so it is a measure of the central tendency of the scores. However, it doesn't necessarily mean that any individual score matches that average. It's possible that some students scored above 74%, while others scored below. So, it's not necessarily true that at least one student scored exactly 74%.

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The value of the quotient -3 1/6 ÷  -8 2/5 is 95/7

From the question, we have the following parameters that can be used in our computation:

Divide negative 3 and one-sixth ÷ negative 8 and two-fifths.

Express properly

So, we have the following representation

-3 1/6 ÷  -8 2/5

Cancel out the negatives

This gives

3 1/6 ÷  8 2/5

Express as improper fractions

19/6 ÷  42/5

Express as products

So, we have

19/6 x  5/42

Evaluate the products

19/1 x  5/7

So, we have

95/7

Hence, the quotient is 95/7

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Step-by-step explanation:

lateral surface area here = πrl

r = 10

l = √h²+r²= √ 24²+ 10² = 26

lateral surface area = 10 × 26 × π

= 260π in²

hope this will be helpful to you .

plz mark my answer as brainlist if you find it useful.

Answer:

The lateral area of cone is 260π in².

Step-by-step explanation:

\(\begin{gathered}\end{gathered}\)

\(\begin{gathered}\end{gathered}\)

\(\star{\underline{\boxed{\sf{\purple{\ell = \sqrt{{(r)}^{2} + {(h)}^{2}}}}}}}\)

\(\star{\underline{\boxed{\sf{\purple{La_{(Cone)}= \pi r\ell}}}}}\)

\(\begin{gathered}\end{gathered}\)

Finding the slant height of cone by substituting the values in the formula :

\(\begin{gathered} \qquad{\longrightarrow{\sf{\ell = \sqrt{{(r)}^{2} + {(h)}^{2}}}}}\\\\\qquad{\longrightarrow{\sf{\ell = \sqrt{{(10)}^{2} + {(24)}^{2}}}}}\\\\\qquad{\longrightarrow{\sf{\ell = \sqrt{{(10 \times 10)} + {(24 \times 24)}}}}}\\\\\quad{\longrightarrow{\sf{\ell = \sqrt{(100)+(576)}}}}\\\\\qquad{\longrightarrow{\sf{\ell = \sqrt{100 + 576}}}}\\\\\quad{\longrightarrow{\sf{\ell = \sqrt{676}}}}\\\\\quad{\longrightarrow{\sf{\ell = 26 \: in}}}\\\\\quad\star\underline{\boxed{\sf{\pink{\ell = 26 \: in}}}} \end{gathered}\)

Hence, the slant height of cone is 26 in.

\(\begin{gathered}\end{gathered}\)

Now, finding the lateral area of cone by substituting the values in the formula :

\(\begin{gathered} \qquad{\longrightarrow{\sf{La_{(Cone)} = \pi r \ell}}}\\\\\qquad{\longrightarrow{\sf{La_{(Cone)} = \pi \times 10 \times 26}}}\\\\\qquad{\longrightarrow{\sf{La_{(Cone)} = \pi \times 260}}}\\\\\qquad{\longrightarrow{\sf{La_{(Cone)} = 260\pi\: {in}^{2}}}}\\\\ \qquad{\star{\underline{\boxed{\sf{\pink{La_{(Cone)} = 260\pi \: {in}^{2}}}}}}}\end{gathered}\)

Therefore, the lateral area of cone is 260π in².

\(\rule{300}{2.5}\)

Answer:

\(6 * 7^3 = 2058\)

Step-by-step explanation:

Given

\(6 * 7^3\)

Required

Solve

App;y law of indices:

\(6 * 7^3 = 6 * 7*7*7\)

Multiply

\(6 * 7^3 = 2058\)

Answer:

9

Step-by-step explanation:

\(3 \frac{3}{4} + 5 \frac{1}{4} = 8 \frac{4}{4} = 9\)

\(\rule{300}{2}\\\dashrightarrow\large\textsf{\textbf{\underline{Given question:-}}}\)

      [refer to attachment for question]

\(\dashrightarrow\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\)

In order to find out how many miles Peter rode overall, we need to add the number of miles he rode on Monday + the number of miles he rode on Tuesday:-

Since the denominators match, we can just add the numerators and the whole parts:-

\(\bigstar\) Which results in

\(\boxed{\bold{9\:Miles}}\)

\(\rule{300}{1}\)

Answer:

\( \sqrt{9 } = 3 \)

Answer:

x = -1

Step-by-step explanation:

Answer: Your machine is fine.

In this problem, we are asked to find the probability that Lindsay was able to work out for 40 minutes straight at the gym.

To do this, we must take into account the probabilities of her getting either a stairmaster or a stationary bike, and the probability of being able to use it for 40 minutes straight given the equipment she gets.

To find the probability that Lindsay worked out for 40 minutes straight, we need to use the law of total probability. The probability of working out for 40 minutes straight can be expressed as:

P(40 minutes straight) = P(Stairmaster) * P(40 minutes straight | Stairmaster) + P(Bike) * P(40 minutes straight | Bike)

Plugging in the values given, we have:

P(40 minutes straight) = 0.20 * 0.10 + 0.80 * 0.50 = 0.22

So, the probability that Lindsay worked out for 40 minutes straight today is 0.22.

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To calculate how many months it will take to have four months of rent saved for a chosen rental property, we need specific information about the rental property's monthly rent.

To determine the number of months required to save four months of rent, we divide the total savings amount from Part 1 by the monthly rent of the chosen rental property. This will give us the number of months it will take to accumulate the equivalent of four months' rent. By knowing the specific monthly rent, we can divide the savings amount by the monthly rent and obtain the answer in terms of months. Please provide the monthly rent, and I will perform the calculation for you.

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Answer:

y = (3/4)x + (3/2)

Step-by-step explanation:

all points on that line

Step-by-step explanation:

form the quadratic equation

solve for x by the use of completing square method.

Answer:

33.

Step-by-step explanation:

Using PEMDAS, we would multiply 5 • 6 first, giving us 30. After this, we would complete the problem by adding 3. The end result is 33.

Answer:

33

Step-by-step explanation:

BODMAS rule

5×6+3

(5×6)+3

30+3

33

The value of b for the given function f(x) is found as b = -20.

We are given a function f(x) and we have to find the value of b for which f'(2) = 0.

Given function is f(x) = (2x³ + bx)g(x)

We have to find f'(2), so we will differentiate f(x) w.r.t x.

Here is the step-wise solution:f(x) = (2x + bx)g(x)

Differentiate w.r.t x using product rule:f'(x) = 6x²g(x) + 2x³g'(x) + bg(x)

Differentiate once more to get f''(x) = 12xg(x) + 12x²g'(x) + 2xg'(x) + bg'(x)

Differentiate to get f'''(x) = 24g(x) + 36xg'(x) + 14g'(x) + bg''(x)

Since we have to find f'(2), we will use the first derivative:

f'(x) = 6x²g(x) + 2x²g'(x) + bg(x)

f'(2) = 6(2)²g(2) + 2(2)³g'(2) + b*g(2)

f'(2) = 24g(2) + 16g'(2) + 4b

Now we know g(2) = 4 and g'(2) = -1.

So substituting these values in above equation:

f'(2) = 24*4 + 16*(-1) + 4b

= 96 - 16 + 4b

f'(2) = 80 + 4b

We want f'(2) = 0, so equating above equation to 0:

80 + 4b = 0

Solving for b:

b = -20

Therefore, for b = -20, f'(2) = 0.

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Answer: 7

Step-by-step explanation:

Answer: 7 or 5 because 7 is on the bottom but 5 is on the otherside which it looks like its the same value.

When the water is 7 meters high, it is changing height at a rate of about 0.019 meters per minute.

We need to use related rates and the volume formula for a cone.

V as the conical tank's water volume

h is the measurement of the conical tank's water level

The conical tank's base has a radius of r

The volume of a cone can be calculated using the formula: V = (1/3)πr²h.

Given that the base and height of the conical tank are equal, we can write r = h.

Differentiating the volume formula with respect to time t, we get:

dV/dt = (1/3)π(2rh dh/dt + r² dh/dt).

Since r = h, we can simplify the equation to:

dV/dt = (1/3)π(2h² dh/dt + h² dh/dt)

= (2/3)πh² dh/dt (Equation 1).

Assuming that the rate of water filling is 2 m/min, dh/dt must equal 2 m/min.

Finding dh/dt at h = 7 m is necessary because we want to know how quickly the water's height is changing.

Substituting the values into Equation 1:

2 = (2/3)π(7²) dh/dt

2 = (2/3)π(49) dh/dt

2 = (98/3)π dh/dt

dh/dt = 2 * (3/(98π))

dh/dt ≈ 0.019 m/min.

Therefore, When the water is 7 meters high, it is changing height at a rate of about 0.019 meters per minute.

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Answer:4320

Step-by-step explanation:8% interest =108% which is equivalent to x1.08

4000 x 1.08 = 4320