Determine the type of investigation.


How does an iPod receive messages?


comparative

none is correct

experimental

descriptive

This indicates that for the solution vapor pressures to be increased to 1 atm, the temperature must be greater than the typical boiling point of the pure solvent.

No matter how much pressure is applied, a liquid will boil at its usual boiling point, meaning the temperature when the vapor pressure matches the standard air pressure at sea level (760 mm [29.92 inches] of mercury). A water's point of boiling at sea level is 100°C (212°F). When a substance changes from a liquid to a gas, that temperature is known as its boiling point. The liquid's vapor pressure has now reached equilibrium with the pressure being exerted on it. The term "normal boiling point" refers to the boiling point at 1 atmosphere of pressure.

The temperature at which solid-state molecular collisions can cause a liquid to develop is known as the melting point. Whereas liquids and gases are concerned with the boiling point. Some molecules on the liquid's surface are escaping as the molecules move around.

Also, as a result of this change, the temperature on the fusion curve—which corresponds to the pressure of 1 atm—declines. Overall, the result is that the solution is more flammable and has a higher boiling point than a pure solvent.

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Answer:

0.015 M

Explanation:

For a first order reaction;

ln[A] =ln[A]o - kt

[A] = final concentration

[A]o =initial concentration

k= rate constant

t= time taken

ln[A] =ln[A]o - kt

ln[A] = ln(0.0500) - 6.7 x 10-4 (30 × 60)

ln[A] = -2.9957 - 1.206

ln[A] = -4.202

e^ln[A] = e^(-4.202)

A= 0.015 M

Answer:

Empirical formula

Explanation:

The empirical formula of a compound is the simplest whole number ratio of atoms of each element in the compound. It is determined using data from experiments and therefore empirical.

Answer:

1

Explanation:

To determine the value of K (equilibrium constant) at 25 °C, we can use the Nernst equation, which relates the cell potential (E) to the equilibrium constant (K) and the standard cell potential (EºCell). The Nernst equation is given by:

E = EºCell - (RT / nF) * ln(K)

Where:

E = cell potential

EºCell = standard cell potential

R = gas constant (8.314 J/(mol·K))

T = temperature in Kelvin (25 °C = 298 K)

n = number of electrons transferred in the balanced redox equation

F = Faraday's constant (96,485 C/mol)

ln = natural logarithm

In this case, the given standard cell potential (EºCell) is -0.37 V.

The balanced redox equation for the cell reaction is:

Pt + Cr²+ -> Pt + Cr³+

Since there is no change in the oxidation state of Pt, no electrons are transferred in the reaction (n = 0).

Substituting the known values into the Nernst equation, we have:

E = -0.37 V - (8.314 J/(mol·K) * 298 K / (0 * 96,485 C/mol)) * ln(K)

E = -0.37 V

Since n = 0, the term (RT / nF) * ln(K) becomes 0, and we are left with:

-0.37 V = -0.37 V - 0

This implies that the value of K is 1, since any number raised to the power of 0 is equal to 1.

Therefore, the value of K at 25 °C for the given cell is 1.

The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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Answer:

Number of mole in HCL = 2.56 x 10⁻³ mol HCL

Explanation:

Given:

Volume of HCL = 25.62 ml

Molarity of HCL = 0.1 M

Find;

Number of mole in HCL

Computation:

Volume of HCL = 25.62 ml

Volume of HCL (in liter) = 25.62 / 1000

Volume of HCL (in liter) = 0.02562 L

Number of mole = Molarity x volume in liter

Number of mole in HCL = Volume of HCL (in liter) x Molarity of HCL

Number of mole in HCL = 0.02562 x 0.1

Number of mole in HCL = 0.002562

Number of mole in HCL = 2.56 x 10⁻³ mol HCL

Answer:

Dude this one is confusing because you are not giving the price of the object.

Explanation:

We must identify if AgBr is polar or non-polar.

In order to determine this we must use that

Now, we can see that the compound has 2 atoms: Ag and Br and they are different. So, the compound is polar.

ANSWER:

The compound is polar.

It is essential to consult a healthcare professional before taking any medication when experiencing indigestion or any other health condition, to ensure that the medication is safe and effective for the patient's specific needs.

It is not advisable to use drug S when a patient has indigestion problem because drug S may worsen the patient's condition or interact negatively with other medications they are taking. Indigestion is a common condition that occurs when there is an imbalance in the digestive system, causing discomfort, bloating, and nausea. Some drugs can exacerbate these symptoms by increasing the production of stomach acid or by irritating the lining of the digestive tract. Drug S may have side effects that include gastrointestinal disturbances, including stomach pain, nausea, and diarrhea. This can make indigestion symptoms worse and lead to further discomfort and distress for the patient. Additionally, drug S may interact negatively with other medications that the patient is taking, further worsening their indigestion. Therefore, it is essential to consult a healthcare professional before taking any medication when experiencing indigestion or any other health condition, to ensure that the medication is safe and effective for the patient's specific needs.

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The question requires us to calculate the amount of energy absorbed by the reaction, considering the molar enthalpy for oxygen gas (O2) and that 80.6 g of oxygen were reacting.

The following information was provided by the question:

Balanced chemical reaction:

Molar enthalpy of reaction for O2: +499.0 kJ/mol

Mass of O2 reacting: 80.6 g

To solve this problem, we need to calculate the amount of moles that corresponds to the mass of O2 given and then use this value and the molar enthalpy provided to calculate how much heat would be absorbed by the reaction.

First, we need the molar mass of O2. Knowing that the atomic mass of O is 15.99 u:

molar mass (O2) = (2 * 15.99) = 31.98 g/mol

Now, we use the molar mass to calculate the number of moles in 80.6 g of O2:

31.98 g O2 ------------------------ 1 mol O2

80.6 g O2 ------------------------- x

Solving for x, we'll have:

There are 2.52 moles of O2 reacting and next we need to calculate the amount of heat absorbed considering this.

The molar enthalpy of O2 tells us how much heat is abosrbed when 1 mol of O2 reacts. Thus, we can use it to calculate the amount of heat absorbed when 2.52 moles of O2 react:

1 mol O2 ----------------------- 499.0 kJ

2.52 mol O2 ----------------- y

Solving for y, we'll have:

Therefore, 1257.5 kJ of energy are absorbed when 80.6 g of O2 are reacting.

We can fill in the boxes to answer the question as it follows:

Answer: 1257.5

Units: kJ

Answer:

11 grams of atoms are in 0.35 moles of oxygen.

The resulting pH of the solution is 1.74(approx).

To solve this problem, we need to use the concept of acid-base equilibrium and the pH scale. The addition of sulfuric acid will increase the concentration of H+ ions in the solution, which will shift the equilibrium of the \(H_2S\)/HS- system. We can use the following equation to calculate the pH of the resulting solution:

Ka = [H+][HS-]/\(H_2S\)]

where Ka is the acid dissociation constant for \(H_2S\), [\(H_2S\)], [HS-], and [H+] are the concentrations of the \(H_2S\), HS-, and H+ ions, respectively.

First, we need to calculate the initial concentrations of\(H_2S\) and HS- in the solution:

[\(H_2S\)] = 0.505 M

[HS-] = 0.505 M

Next, we need to calculate the amount of H+ ions added to the solution by 1 mL of concentrated sulfuric acid. To do this, we can use the following equation:

[H+] = (n/V) = (18.4 mol/L) x (1x\(10^{-3}\) L) = 1.84 x\(10^{-2}\)mol

where n is the amount of sulfuric acid added in moles, V is the volume of the solution in liters, and 18.4 mol/L is the concentration of the sulfuric acid.

Now, we can calculate the new concentrations of \(H_2S\), HS-, and H+ ions in the solution:

[\(H_2S\)] = [\(H_2S\)]0 - [H+] = 0.505 - 1.84x\(10^{-2}\)= 0.486 M

[HS-] = [HS-]0 + [H+] = 0.505 + 1.84x\(10^{-2}\) = 0.524 M

[H+] = 1.84 x \(10^{-2}\)M

Finally, we can use the equation for Ka to calculate the pH of the resulting solution:

Ka = 1.1 x \(10^{-7}\)

[H+] x [HS-]/[\(H_2S\)] = Ka

pH = -log[H+]

Substituting the values, we get:

(1.84 x \(10^{-2}\)) x (0.524)/(0.486) = 1.98 x \(10^{-2}\)

pH = -log(1.98 x \(10^{-2}\)) = 1.74(approx)

Therefore, the resulting pH of the solution is 1.74(approx)

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Answer:

In the above reaction, sulfur dioxide and oxygen react together to form sulfur trioxide. This means that an increase in pressure would move the equilibrium to the right and result in more sulfur trioxide being formed. Pressure can only affect the position of equilibrium if there is a change in the total gas volume.

Answer:

Other forms of energy

Explanation:

none of the other answers could be correct.

Answer:

none of the other answers could be correct.

Explanation:

Answer:

(3rd option) Asexually reproduced offsprings have the same amount of genetic information as the parent, while sexually reproduced offsprings have half as much genetic information.

Explanation:

This is variation is caused as a result of both gamete production and fertilisation.

The structure for 2-methyl-3-propalhex-2-yne can be shown in the image attached.

We know that a compound is composed of atoms that can be found in the compound. For the organic compound, we can see that we can be able to obtain the structure of the compound from the structure.

The compound as we can see is  2-methyl-3-propalhex-2-yne. The structure of the compound must be able to include a double bond as we can clearly see from the image that is attached to this answer.

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Answer:

a

Explanation:

Answer:

A

Explanation:

The percent by mass of nitrogen in ammonia (NH3) is approximately 82.15%

Calculating the mass of nitrogen to the total mass of the compound and then expressing the result as a percentage will allow us to determine the percent by mass of nitrogen in NH3 (ammonia).

Ammonia's molecular structure, NH3, indicates that it is made up of one nitrogen atom (N) and three hydrogen atoms (H). We must take both the molar masses of nitrogen and ammonia into account when calculating the percent by mass of nitrogen.

Nitrogen's (N) molar mass is roughly 14.01 g/mol. The molar masses of nitrogen and hydrogen are added to determine the molar mass of ammonia (NH3). Since hydrogen's molar mass is around 1.01 g/mol, ammonia's molar mass is:

(3 mol H 1.01 g/mol) + (1 mol N 14.01 g/mol) = 17.03 g/mol = NH3.

Now, we can use the following formula to get the nitrogen content of ammonia in percent by mass:

(Mass of nitrogen / Mass of ammonia) / 100% is the percentage of nitrogen by mass.

Ammonia weighs 17.03 g/mol and contains 14.01 g/mol of nitrogen by mass. By entering these values, we obtain:

(14.01 g/mol / 17.03 g/mol) 100% 82.15 % of nitrogen by mass

Ammonia (NH3) has a nitrogen content that is roughly 82.15 percent by mass.

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Answer:

The second period starts with Lithium and Beryllium which have 3 and 4 electrons and hence the last electrons enter the level 2s and they have an electronic configuration of 1s22s1 and 1s22s2

The volume of carbon dioxide produced is approximately (d) 11.9 liters.

To determine the amount of carbon dioxide (C\(O_2\)) produced when 37.8 grams of carbon disulfide (C\(S_2\)) reacts with excess oxygen gas (\(O_2\)), we need to use stoichiometry and the given balanced chemical equation:

C\(S_2\)(l) + 3\(O_2\)(g) → C\(O_2\)(g) + 2S\(O_2\)(g)

First, we calculate the number of moles of C\(S_2\) using its molar mass:

Molar mass of (C\(S_2\)) = 12.01 g/mol (C) + 32.07 g/mol (S) × 2 = 76.14 g/mol

Number of moles of (C\(S_2\)) = mass / molar mass = 37.8 g / 76.14 g/mol ≈ 0.496 mol

From the balanced equation, we can see that the stoichiometric ratio between (C\(S_2\)) and C\(O_2\) is 1:1. Therefore, the number of moles of C\(O_2\) produced will also be 0.496 mol.

Now we can use the ideal gas law to calculate the volume of C\(O_2\) at the given temperature and pressure. The ideal gas law equation is:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

Converting the temperature from Celsius to Kelvin:

T(K) = 28.85°C + 273.15 = 302 K

Using the ideal gas law:

V = nRT / P = (0.496 mol) × (0.0821 L·atm/mol·K) × (302 K) / (1.02 atm) ≈ 11.9 L

The correct answer is 11.9 liters.

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The molecular mass of the gas, given that 2.63 g of the gas occupied 0.98 L at standard conditions of temperature and pressure is 60 g/mol

First, we shall obtain the mole of the gas. Details below:

PV = nRT

1 × 0.98 = n × 0.0821 × 273

0.98 = n × 22.4133

Divide both sides by 22.4133

n = 0.98 / 22.4133

n = 0.0437 mole

Finally, we shall obtain the molecular mass of the gas. This is shown below:

Molar mass = mass / mole

Molar mass of gas = 2.63 / 0.0437  

Molar mass of gas = 60 g/mol

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Answer:

its sodium hydroxide

Explanation:

The sample that uses the substance that Jacob and Natalie should use to make a cold pack that will do the best job of keeping food cool is sample 2, because it absorbs the most energy (option B).

Endothermic refers to a chemical reaction that absorbs heat energy from its surroundings. This ensures that the temperature of the surroundings is cool or has a lower temperature.

According to this question, Jacob and Natalie are asked by their science teacher to design a warming or cooling device. They make use of certain substances, however, sample 2 has the lowest final temperature of -4°C.

This shows that sample 2 absorbs the most energy, hence, would be the best for keeping the food cool.

The incomplete question is as follows:

Jacob and Natalie are asked by their science teacher to design a warming or cooling device. They decide to design a cold pack that can be used to help keep food cool. Jacob and Natalie read about different substances that can be used inside cold packs and learn that most cold packs use endothermic reactions to cool objects.

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The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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Answer:

increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object would make the oppositely charged objects attract each other more.

In order to determine the emperical formular for the hydrocarbon, we will follow the steps below:

• Moles of CO2- given that mass of CO2 = 20.5g

-Molecular Mass of CO2 = 44.01g/mole

Therefore, moles(n) = m/Mol.Mass= 20.5g/44.01g/mol = 0.466moles

• Moles of H2O - given that mass of H2O = 6.29g

-Molecula Mass of H2O = 18,01528 g/mol

Therefore,moles (n) = m/Mol.Mass = 6.29g/18.01528g/mol = 0.349moles

• Moles of Hydogen = ,0.349moles, H2O * 2Moles H /1mol H2O

=0.698 moles of hydogen

For C = 0.466moles/0.466moles = 1 * 4 = 4

For H = 0.698 moles/0.466moles = 1.49* 4= 5.99 = 6

Ratio is therefore C : H

4 : 6

is the same as 2: 3

Therefore , the emperical formula for the hydrocarbon = C2H3

In dynamic equilibrium conditions, the vapor pressure is unique, and the rate of vaporization and condensation are at equal rates. Thus, option b is accurate.

A dynamic equilibrium is a reaction state where the rate of the forward and the backward reaction are equal. In the above case, the vapourization and the condensation will occur simultaneously at the same rate.

The vapor pressure of the liquid to gas and vice versa has a distinctive value as the temperatures are different making the pressure change directly.

Therefore, option b. II and III are the correct options.

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Answer:

zero

Explanation:

Answer:

Zero.

Explanation:

The overall formal charge in CF4 is zero.