Discuss three types of valency

1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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The data the students could collect to confirm the type of reaction is the temperature before and after the reaction.

The system is the reaction vessel and the surroundings are the laboratory environment.

Chemical reactions are reactions in which new substances called products are formed from one or more substances that undergo chemical change called reactants.

During a chemical reaction, heat changes occur as the reactants form products. The heat changes that occur may involve the release of heat by the chemical system to the surroundings or the absorption of heat from the surrounding by the chemical system.

A reaction in which heat is absorbed will feel cold to touch and is called an endothermic reaction.

A reaction in which heat is released to the surroundings will feel hot to touch and is called an exothermic reaction.

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Answer:

Explanation:

ammonite

Answer:

Ammonite

Explanation:

These are some awesome fossils

Plz mark B R A I N L I E S T

Explanation:

Heat is transferred by conduction when adjacent atoms vibrate against one another or electrons move from one atom to another . Conduction is the most significant meanings of heat transfer within a solid or between solid objects informal contact.

To answer this question, we need to use the ideal gas law equation, which states that PV=nRT, where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the universal gas constant, and T is the temperature of the gas.

Assuming that the sample is at standard temperature and pressure (STP), which is 0 degrees Celsius and 1 atmosphere of pressure, we can use the molar volume of gas at STP, which is 22.4 liters per mole.
So, if we know the volume of the sample, we can calculate the number of moles of oxygen gas in the sample. Let's say the volume of the sample is 50 liters.
Using the formula, we can rearrange it to solve for n: n = PV/RT. Plugging in the values we have, we get:
n = (1 atm) x (50 L) / [(0.08206 L x atm/mol x K) x (273 K)]
Simplifying this, we get n = 1.83 moles of oxygen gas in the sample.
Therefore, there are about 1.83 moles of oxygen gas in the sample, assuming that it is at STP and has a volume of 50 liters.

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The number of moles in 6.0 × 10²⁴ atoms of oxygen is 5 moles (option D).

The number of moles in a substance can be calculated by dividing the number of atoms of the substance by Avogadro's number as follows:

no of moles = no of atoms ÷ 6.02 × 10²³

According to this question, a sample of oxygen gas is said to contain 6.0 × 10²⁴ atoms of oxygen. The number of moles in this substance can be calculated as follows:

no of moles = 6.0 × 10²⁴ atoms ÷ 6.02 × 10²³

no of moles = 1 × 10¹ = 10 moles of oxygen gas

10 ÷ 2 = 5 moles of oxygen atom

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We are given a speed of 1.02 mm/hr and we have to convert that speed into inches/day. To find the answer to our problem we can use a 2 steps conversion. First we can convert mm into inches and then the hr into days.

We know that there are 25.4 mm in 1 inch. So let's convert it.

25.4 mm = 1 inch

Speed = 1.02 mm/hr * 1 inch / (25.4 mm) = 0.04016 inch/hr

Speed = 0.04016 inch/hr

Then we know that there are 24 hours in 1 day.

24 hrs = 1 day

Speed = 0.04016 inch/hr * 24 hr/(1 day) = 0.964 inch/day

Speed = 0.964 inch/day

The speed of a slime mold in inches per day is 0.964.

Answer: Industrial processes including mining and manufacturing historically have been leading causes of soil pollution. Industrial areas typically have much higher levels of trace elements and organic contaminants. This is due to intentional and unintentional releases from industrial processes directly into the environment, including to the soil, adjacent water bodies, and the atmosphere.

Explanation:

I CANT DELETE THE ANSWER, SO HERE.

Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Answer:

+1

Explanation:

Na₂O₂

NOTE: the oxidation number of oxygen is always –2 except in peroxides where it is –1.

Thus, we can obtain the oxidation number of sodium (Na) in Na₂O₂ as illustrated below:

Na₂O₂ = 0 (oxidation number of ground state compound is zero)

2Na + 2O = 0

O = –1

2Na + 2(–1) = 0

2Na – 2 = 0

Collect like terms

2Na = 0 + 2

2Na = 2

Divide both side by 2

Na = 2/2

Na = +1

Thus, the oxidation number of sodium (Na) in Na₂O₂ is +1

The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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Answer: first option (or letter A): 20.3 g LizN

Explanation:

The question requires us to calculate the mass of Li3N produced when 1.75 moles of Li and excess of N2 are used in the following chemical reaction:

To solve this problem, we must consider the stoichiometry of the reaction to calculate the amount of moles of Li3N produced and then use the molar mass of Li3N (34.83 g/mol) to convert the number of moles in mass of Li3N.

According to the chemical equation, 2 moles of Li3N are produced when 6 moles of Li are reacting. Thus, we can write:

6 mol Li ---------------------- 2 mol Li3N

1.75 mol Li ------------------ x

Solving for x, we'll have:

Therefore, 0.583 moles of Li3N are obtained from 1.75 moles of Li.

Now, considering the molar mass of Li3N (34.83 g/mol):

1 mol Li3N --------------- 34.83g Li3N

0.583 mol Li3N ------- y

Solving for y, we'll have that 0.583 moles of Li3N correspond to 20.3 g of this compound.

The best option to answer this question is the first one (or letter A): 20.3 g LizN.

Step 1: Write and balance the equation:

3 NaCl + Al(NO3)3 → AlCl3 + 3 NaNO3

Step 2: We need to find the limiting and excess reactant. For this, we need to look at the stoichiometric ratio between the reactants:

3 moles of NaCl reacts with 1 mole of Al(NO3)3.

Now we do a rule of 3 for both.

For 9 moles of NaCl:

3 moles of NaCl --- 1 mole of Al(NO3)3

9 moles of NaCl --- x mole of Al(NO3)3

3x = 9

x = 3 moles of Al(NO3)3

For 4 moles of Al(NO3)3:

3 moles of NaCl --- 1 mole of Al(NO3)3

x moles of NaCl --- 4 moles of Al(NO3)3

x = 12 moles of NaCl

As we can see, to react with 4 moles of Al(NO3)3 we should have 12 moles of NaCl, but we have just 9. So the NaCl is the limiting reactant and the excess reactant is Al(NO3)3.

Step 3: We need to look at the stoichiometric ratio between the limiting reactant (NaCl) and NaNO3:

3 moles of NaCl --- 3 moles of NaNO3

9 moles of NaCl --- x moles of NaNO3

x = 9 moles of NaNO3

Answer: The maximum amount of NaNO3 that was produced during the experiment is 9 moles.

Answer:

Explanation:

An acid is a substance that can donate protons (H+) to water when dissolved in it, resulting in an increase in the concentration of H+ ions in the solution.

When NaCl (sodium chloride) is dissolved in water, it dissociates into its individual ions, Na+ and Cl-. These ions do not donate protons to water, so NaCl does not form an acid when dissolved in water.

NO2 (nitrogen dioxide) is a neutral compound, it does not donate protons to water and does not form an acid when dissolved in water.

H2SO3 (sulfurous acid) is an acid, when dissolved in water, it donates protons to water and forms H+ ions and SO3- ions.

HCl (hydrochloric acid) is an acid, when dissolved in water it donates protons to water and forms H+ ions and Cl- ions.

So the answer is H2SO3 and HCl are the compounds that would form an acid when dissolved in water as an aqueous solution.

The calculate the age of the rock sample values, the age of the rock sample can be determined.

we can use the concept of radioactive decay and the ratio of 87Sr to 87Rb. Since 87Sr is a stable product of the beta decay of 87Rb, the increase in the ratio of 87Sr to 87Rb over time reflects the decay of 87Rb.

The ratio of 87Sr to 87Rb in ancient samples is given as 0.0205. This means that for every 0.0205 moles of 87Rb, there is one mole of 87Sr.

Since the half-life of 87Rb is 4.75×10^10 years, after each half-life, half of the 87Rb would have decayed into 87Sr. Therefore, the ratio of 87Sr to 87Rb increases by a factor of 2.

To determine the age of the rock sample, we can calculate the number of half-lives that have occurred based on the change in the ratio. The ratio of 0.0205 corresponds to 1 half-life, 0.041 corresponds to 2 half-lives, 0.082 corresponds to 3 half-lives, and so on.

By taking the logarithm of the ratio change and dividing it by the logarithm of 2 (since the ratio doubles with each half-life), we can find the number of half-lives.

Using this information, the age of the rock sample can be calculated as follows:

Age (in years) = number of half-lives × half-life of 87Rb

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Over-tilling and Over farming are the two processes that can harm the fertility of the soil.

Over-tilling refers to the exceeding levels of tilling and levelling the soil which adversely affects the quality of the soil. This is because tillage fractures the soil, it disrupts soil structure, accelerating surface runoff and soil erosion. Tilling of soil also reduces crop residue, which help cushion the force of pounding raindrops.

Without crop residue, soil particles become more easily dislodged, being moved or 'splashed' away. The splashed particles clog soil pores, effectively sealing off the soil's surface, resulting in poor water infiltration and hence subsequently affects the soil fertility.

Similarly, the main effect of over-farming is soil depletion. When crops are grown in the same place year after year, the soil becomes depleted of the nutrients that the plants need to grow. This can lead to lower yields and poorer quality crops. In extreme cases, it can lead to desertification.

So, these two are the processes that can harm soil fertility.

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Explanation:

A pure substance is a form of matter that has a constant composition and properties that are constant throughout the sample. Mixtures are physical combinations of two or more elements and/or compounds

Answer:

Its density decreases

Its volume increases

Explanation:

You notice that ice floats on water, this means that its density is less. The mass remains the same because you did not add or remove anything. But what causes the density to decrease then? For density to change, there needs to be a change in either the volume or the mass of the object. Density is calculate by mass/volume. Since the mass did not change, the volume must have. So in this case, the volume increases. Hence, this is what causes it to be less dense.  :)

Answer:

D.

Explanation:

brainliest pls

Answer:

i would say two

Explanation:

I did the math

Answer:

The Answer is 100.06c

Explanation:

GradPoint:)

Answer: The answer is incus

Sodium lauryl sulfate is a surfactant that help with the mixing of oil and water to clean the skin and hair by helping water to mix with oil and dirt so that they can be rinsed away or suspend poorly soluble ingredients in water.

Thus, ammonia lauryl sulfate serve as surfactore due to it's ability to lower the surface tension of water and ability to form micelles in water.

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The percent by mass of nitrogen in ammonia (NH3) is approximately 82.15%

Calculating the mass of nitrogen to the total mass of the compound and then expressing the result as a percentage will allow us to determine the percent by mass of nitrogen in NH3 (ammonia).

Ammonia's molecular structure, NH3, indicates that it is made up of one nitrogen atom (N) and three hydrogen atoms (H). We must take both the molar masses of nitrogen and ammonia into account when calculating the percent by mass of nitrogen.

Nitrogen's (N) molar mass is roughly 14.01 g/mol. The molar masses of nitrogen and hydrogen are added to determine the molar mass of ammonia (NH3). Since hydrogen's molar mass is around 1.01 g/mol, ammonia's molar mass is:

(3 mol H 1.01 g/mol) + (1 mol N 14.01 g/mol) = 17.03 g/mol = NH3.

Now, we can use the following formula to get the nitrogen content of ammonia in percent by mass:

(Mass of nitrogen / Mass of ammonia) / 100% is the percentage of nitrogen by mass.

Ammonia weighs 17.03 g/mol and contains 14.01 g/mol of nitrogen by mass. By entering these values, we obtain:

(14.01 g/mol / 17.03 g/mol) 100% 82.15 % of nitrogen by mass

Ammonia (NH3) has a nitrogen content that is roughly 82.15 percent by mass.

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Answer: 45 g HCl

Explanation:

1) solve for moles

moles = M X L = 5 x 0.250 =1.25 moles

2) stoichiometry to grams

1.25 x (36 g HCl/1 mole HCl) =45 g HCl

Answer:

C:RS₂ have the properties of both  R and S.

Explanation:

A compound formed between the two elements R and S to form RS₂ will have properties that reflects both R and S.

This is chemical change and the atoms combine will influence how the the product is formed.

Compounds are substances that are composed of two or more kinds of atoms joined together in a definite grouping.

Answer:

A. tissues are comprised of cells

Answer:

Meteorology

Explanation:

Meteorology focuses on Earth's atmosphere and, especially, how changes in the atmosphere affect weather and climate on Earth's surface.

To answer first we need to calculate the molar weight of this molecule (KBr):

For this we go to the periodic table and check the molar weight of potassium and bromine:

K: 39.098 g/mol

Br: 79.904 g/mol

So the molar weight of KBr is:

Now, we know that the solution is 0.955 M, this means that in 1000 ml there are 0.955 moles of KBr. So we calculate the number of moles in 92.7ml:

Now we use the molar weught to calculate the grams in the sample:

So the answer is 10.17g.