Draw a Lewis structure for nitric acid, HNO3 (the hydrogen atom is attached to one of the oxygen atoms) Include all three resonance hybrids by alternating the double bond among the three oxygen atoms. Draw moleculos by placing atoms on the grid , and connocting them with bonds_ Includo all nonbonding electrons_'

The erythrocytes in the hemolysis I lab are initially blind to the external saline solution.

The erythrocytes become blank to the external solution once the test solutions have been applied thanks to blank. As a result, blank takes place in an effort to achieve balance, finally leading to the lysis of the erythrocytes.

Red blood cells can occasionally be destroyed too quickly, before your body has a chance to replenish them. Hemolysis is the term used to describe the process of destroying red blood cells, including those that do so too soon. Hemolytic anemia is a disorder when there are insufficient red blood cells as a result of hemolysis.

A cell will increase volume if it is submerged in a hypotonic solution because there will be a net flow of water entering the cell. The solution is hypotonic to the cell if the concentration of solutes outside the cell is lower than inside the cell and the solutes cannot cross the membrane.

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Anaerobic fermentation is similar to aerobic respiration because of formation of glycolysis,ATP formation from carbohydrate etc.

Anaerobic cellular respiration and maturation create ATP in totally different ways, and the terms ought not be treated as equivalent words. Cell breath (both vigorous and anaerobic) utilizes profoundly diminished synthetic mixtures like NADH and FADH₂ (for instance created during glycolysis and the citrus extract cycle) to lay out an electrochemical slope (frequently a proton inclination) across a film. This outcomes in an electrical potential or particle fixation contrast across the layer

Anaerobic fermentation starts the same way as aerobic respiration and maturation. The initial step is still glycolysis, it actually makes 2 ATP from one carbohydrate particle. Be that as it may, rather than finishing with glycolysis, as aging does, anaerobic fermentation makes pyruvate and afterward progresses forward with a similar way as oxygen consuming breath.

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Answer:

the ratio of the distance travelled by the solute to the distance travelled by the solvent

Explanation:

It is used in chromatography to quantify the amount of retaration of a sample in a stationary phase relative to a mobile phase.

Answer:

The Resource Conservation and Recovery Act (RCRA; PL 94-580), the major federal law on waste disposal, was passed in 1976. Its primary goal was to "protect human health and the environment from the potential hazards of waste disposal." RCRA is also concerned with reducing the amount of waste generated, ensuring that wastes are managed properly, and conserving natural resources and energy. The RCRA regulates solid waste, hazardous waste, and underground storage tanks

Explanation:

Answer:

2Na + 2H2O → 2NaOH + H2

Explanation:

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the same for both the reactants and the products.

The half reactions are the reactions where the reduction and oxidation are shown at the same time.

These are also known as redox reactions.

Redox reactions, as the name tells, is the combination of two types of reaction, the reduction and the oxidation.

The reduction half reaction will show the reduction of either molecules, atoms, oxidation number or charges and the oxidation reaction will show the gain of the same.

In this equation where ClO is reacting to form Cl, is a part of reduction reaction.

This is because the Oxygen is getting detached from the chlorine and the deoxidation of chlorine can be seen.

The de-oxidation of chlorine will result in reduction of the molecule.

Thus the correct answer is option C, ClO + H₂O -> Cl + 2OH⁻ is the half reaction for the given equation.

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You test your hypothesis by completing an experiment.

We test our hypothesis by performing experiment or research because in an experiment, we test our hypothesis and collect data in order to draw a conclusion from it.

So we can conclude that you test your hypothesis by completing an experiment.

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The molar mass of the unknown gas is approximately 47.007 g/mol.

To solve this problem, we can use Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

Let's assume the molar mass of the unknown gas is M_2. According to the problem, the rate of effusion for argon (M_1) is 0.849 times that of the unknown gas:

Rate of argon (M_1) / Rate of unknown gas (M_2) = 0.849

By rearranging the equation, we get:

Rate of unknown gas (M_2) = Rate of argon (M_1) / 0.849

Since the molar mass of argon (M_1) is given as 39.948 g/mol, we can substitute the values into the equation:

Rate of unknown gas (M_2) = 39.948 g/mol / 0.849

Calculating this expression gives us the molar mass of the unknown gas:

M_2 = 47.007 g/mol

Therefore, the molar mass of the unknown gas is approximately 47.007 g/mol.

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The molar mass of the unknown gas is approximately 27.17 g/mol.

At a given temperature, the rate at which a gas effuses (passes through a small opening) can be determined by using Graham's Law of Effusion. Graham's Law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. In this case, we are comparing the effusion rates of an unknown gas and neon gas.

The given information states that the rate of effusion of the unknown gas is 0.849 times that of neon gas. Let's denote the rate of effusion of the unknown gas as r_unknown and the rate of effusion of neon gas as r_neon.

We can express this relationship mathematically as:

r_unknown = 0.849 * r_neon

Now, Graham's Law tells us that the rate of effusion is inversely proportional to the square root of the molar mass. Let's denote the molar mass of the unknown gas as M_unknown and the molar mass of neon gas as M_neon.

Using Graham's Law, we can write:

r_unknown / r_neon = sqrt(M_neon / M_unknown)

Since we know that r_unknown = 0.849 * r_neon, we can substitute this value into the equation:

0.849 * r_neon / r_neon = sqrt(M_neon / M_unknown)

Simplifying the equation:

0.849 = sqrt(M_neon / M_unknown)

To solve for M_unknown, we need to isolate it on one side of the equation. Squaring both sides of the equation, we get:

0.849^2 = M_neon / M_unknown

M_unknown = M_neon / 0.849^2

Now, the molar mass of neon gas (M_neon) is approximately 20.18 g/mol. Let's substitute this value into the equation:

M_unknown = 20.18 g/mol / 0.849^2

Calculating this value, we find:

M_unknown ≈ 27.17 g/mol

So, the molar mass of the unknown gas is approximately 27.17 g/mol.

Please note that the given information does not mention the temperature explicitly. However, the molar mass of a gas is constant at a given temperature. Therefore, we can use the given information to determine the molar mass of the unknown gas regardless of the temperature.

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a) the concentration of COCl₂ when the concentrations of both CO and

Cl₂ are 5.90 x 10-³ M is 8.13 x 10^(-3) M

b) When the equilibrium concentration of COC12 is 0.003 70 M,, the concentrations of CO and Cl₂ are approximately 0.0511 M, assuming they are equal.

To solve the given equilibrium problem, we can use the equilibrium constant expression and the stoichiometry of the reaction. The equilibrium constant expression for the decomposition of phosgene reaction is:

Kc = [CO][Cl₂] / [COCl₂]

where [CO], [Cl₂], and [COCl₂] are the concentrations of the respective species at equilibrium.

a. To find the concentration of COCl₂ when [CO] = [Cl₂] = 5.90 x 10^(-3) M, we can substitute the given values into the equilibrium constant expression:

4.282 x 10^(-2) = (5.90 x 10^(-3) M) * (5.90 x 10^(-3) M) / [COCl₂]

Simplifying the equation, we find:

[COCl₂] = (5.90 x 10^(-3) M) * (5.90 x 10^(-3) M) / (4.282 x 10^(-2))

[COCl₂] ≈ 8.13 x 10^(-3) M

b. When the equilibrium concentration of COCl₂ is 0.00370 M, and assuming [CO] = [Cl₂], we can use the equilibrium constant expression to find the concentrations of CO and Cl₂:

4.282 x 10^(-2) = ([CO])^2 / (0.00370 M)

Simplifying the equation, we find:

[CO] ≈ [Cl₂] ≈ √((4.282 x 10^(-2)) * (0.00370 M))

[CO] ≈ [Cl₂] ≈ 0.0511 M

Therefore, when the equilibrium concentration of COCl₂ is 0.00370 M, the concentrations of CO and Cl₂ are approximately 0.0511 M, assuming they are equal.

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The molar mass of the protein is 6.65 × 10³ g/mol.

The pressure that must be applied to the solution side to stop fluid movement when a semipermeable membrane separates a solution from pure water is defined as the osmotic pressure.

As we know the formula for osmotic pressure is given by,

P = CRT

⇒ C = P / RT

⇒ C = 0.117 atm / (0.0821 × 298)

⇒ C = 0.00478

Also,

Concentration (C) = Moles/Volume

⇒ C = (Mass/Molar mass) / Volume

⇒ C = (159 × 10⁻³/M) / 5 mL/1000

⇒  0.00478 = (159 × 10⁻³/M) / 5 mL/1000

⇒ M = 6.65 × 10³ g/mol

The given question is incomplete and the complete question is given below,

159.00 mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of solution. The osmotic pressure of this solution is measured to be 0.117 atm at 25.0 °C. Calculate the molar mass of the protein, R=0.0821 L.at m/K. Be sure your answer has the correct number of significant digits.

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The acid that will react with strontium hydroxide to produce strontium chloride in a neutralization reaction is hydrochloric acid (HCl).

When strontium hydroxide reacts with hydrochloric acid, the products formed are strontium chloride (SrCl2) and water (H2O). The chemical equation for the neutralization reaction is as follows:

Sr(OH)2 + 2HCl → SrCl2 + 2H2O

Here, Sr(OH)2 is the base (strontium hydroxide) and HCl is the acid that undergoes a neutralization reaction. The products formed are a salt (strontium chloride) and water.

Neutralization reactions are a type of chemical reaction that occurs when an acid reacts with a base to form a salt and water.

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Answer:

They fall slower.

Explanation:

moon's gravitation force is effected by the mass of the moon

but because the moon has less mass,

objects fall slower because it has less gravitation force

________________________________________________

Hope this helped.

Answer:

Particle density is the volumetric mass of the solid soil. It differs from bulk density because the volume used does not include pore spaces. Particle density represents the average density of all the minerals composing the soil.

Hope that helps

In scientific investigations, the effect of fertilizer on plant growth can be studied by examining various variables. Two key variables in this context are the presence or absence of fertilizer (independent variable) and the size or growth of the plant (dependent variable).

When investigating the effect of fertilizer on plant growth, the independent variable is the presence or absence of fertilizer. This variable is controlled by having two groups of plants: one group receiving fertilizer (experimental group) and another group without fertilizer (control group). By comparing the growth of these two groups, we can determine the impact of fertilizer on plant size.

The dependent variable, on the other hand, is the size or growth of the plant. This variable is measured or observed as the outcome of interest. In this case, it would be the height, weight, or overall size of the plants.

By systematically changing the independent variable (presence or absence of fertilizer), we can observe how it affects the dependent variable (plant growth). The experimental group receiving fertilizer is expected to show greater plant growth compared to the control group without fertilizer. This allows us to draw conclusions about the effect of fertilizer on plant growth.

However, it is important to note that the specific outcome may vary depending on other factors such as plant species, soil conditions, and environmental factors. Conducting a controlled experiment while considering these factors helps in obtaining more reliable results.

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For a volume of tissue, the Dose `D would be 1 × 10^6 [cm−2] × 0.0233 [cm2 g−1] × 1 [MeV] / 1.602 × 10^-13 [J MeV−1] × 1.0 [g] = 1.448 mGy]`. The condition that is necessary to make this calculation is to assume a tissue type because the value of the energy absorption coefficient varies with different tissue types.

A) Calculation of dose in mGy for a volume of tissue and fluence of 1 × 10^6 [cm−2] of an energy of 1 MeV

For this calculation, the required formula is:

`Dose = Fluence × Energy Absorption Coefficient`

The fluence given is:

1 × 10^6 [cm−2] of an energy of 1 MeV

The value of energy absorption coefficient varies according to the tissue. Therefore, we have to assume a tissue type.For example, for the tissue type of soft tissue, the value of the energy absorption coefficient is:

0.0233 [cm2 g−1]

Thus, Dose `D = 1 × 10^6 [cm−2] × 0.0233 [cm2 g−1] × 1 [MeV] / 1.602 × 10^-13 [J MeV−1] × 1.0 [g] = 1.448 mGy]`

B) Condition necessary to make this calculation and why?

The condition that is necessary to make this calculation is to assume a tissue type because the value of the energy absorption coefficient varies with different tissue types.

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Answer:  When an acid and a base are placed together, they react to neutralize the acid and base properties, producing a salt. The H(+) cation of the acid combines with the OH(-) anion of the base to form water. The compound formed by the cation of the base and the anion of the acid is called a salt.

Answer:

K = 351.3

Explanation:

The relationship between the Celsius scale and kelvin scale is;

K = 273 + C

Since the Celsius temperature = 78.3

The kelvin temperature is given as;

K = 273  + 78.3

K = 351.3

Answer:

nobel gases

Explanation:

nobel gases elements in the periodic table are least likely to combine with other elements

Answer:

1.3×10−39ms−1

Explanation:

Answer:

The second company job of $18 /hr is the better deal

Explanation:

We are told that;

-First job offers a salary of $30,000/yr

-Second job offers a salary of $18/hr.

Now, let's convert the salary of the second job to amount per year.

We are told that full-time work is 49hr/wk, 52 wk/yr.

Since we have 49 hrs in a week, then amount per week = 18 × 49 = $882 per week

Then amount per year = 882 × 52 = $45864 /yr

Thus, the second job pays $45864 /yr.

This is more than the first job. Thus, the second job is the better deal

Answer:

Based on the data in the table, which alarm produces sound waves with the greatest amplitude? Explain your answer.

this bit says based on the table but there is no table.

Explanation:

This reaction is also known as double decomposition reaction.

HCl + CaCO3 + MgCO3 → H2O + H2 + CO2 + CaCl2 + MgCl2

Answer:

0.24%

Explanation:

The following data were obtained from the question:

Measured value = 42.1 g

Actual value = 42 g

Percentage error =?

Percentage error can be obtained by using the following formula:

Percentage error = |Measured value – Actual value | / Actual value × 100

With the above formula, we can obtain the percentage error as follow:

Measured value = 42.1 g

Actual value = 42 g

Percentage error =?

Percentage error = |42.1 – 42| / 42 × 100

Percentage error = 0.1/42 × 100

Percentage error = 10/42

Percentage error = 0.24%

Therefore, the percentage error is 0.24%

The component that must also be present for translation to take place is Factor Polymerases and GTP Initiation. Correct answer: letter C.

Since, the factorial polymerases bind to the mRNA and initiate the translation process. GTP is also needed to provide the energy necessary to move the mRNA along the ribosome. Without these components, translation could not take place.

Is the process by which extracellular signals, such as hormones and growth factors, are converted into intracellular signals. This process begins with the binding of a signal molecule to a receptor on the surface of the cell.

This binding triggers a series of biochemical reactions and intracellular signaling pathways, leading to a cellular response, such as:

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The atomic symbol for the nuclide that decays by alpha emission to form lead-208 (Pb-208) is thorium-232 (Th-232)

Thorium-232 is a radioactive isotope that undergoes alpha decay, which involves the emission of an alpha particle consisting of two protons and two neutrons. Through alpha decay, thorium-232 loses an alpha particle and transforms into a different nuclide. In this case, the decay of thorium-232 leads to the formation of lead-208.

The atomic symbol for lead is Pb, and the number 208 represents the atomic mass of lead-208, which indicates the sum of protons and neutrons in the nucleus. Therefore, the atomic symbol for the nuclide undergoing alpha decay to form lead-208 is thorium-232 (Th-232).

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Answer:

Explanation:

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