draw the circuit schematic of a 3-bit r-2r ladder dac and write down the output analog voltage in terms of digital binary word input combined with a dc reference voltage.

Answer:

Explanation:

You need something that relates distance to what the gravitational pull is. You can set up a complex sort of proportion. What you need is a number that is comparable to 9.81 or you can just use the Gravitational Force formula with a 4 tier fraction.

Givens

x = the additional distance toward outer space above the radius of the earth.

G is the gravitational constant.

m1 = the person's mass (which does not change no matter where you are).

m2 = the earth's mass

F1 = 588 N

F2 = 300 N

Formula

\(\frac{F1}{F2} = \frac{588 N}{300N}=\frac{\frac{Gm1*m2/}{6400^2} }{\frac{G*m1*m2}{(6400 + x)^2} }\)

Solution

G*m1*m2 all cancel. So what you get looks like this.

\(\frac{588}{300} = \frac{(6400 + x)^2}{6400^2}\)

Cross Multiply

588 * 6400^2 = 300*(6400+x)^2  Now all you need do is solve for x.

x will be in km.

588*40960000 = 300 * (40960000 + 12800x + x^2)

1.2288*10^10 + 3840000x + 300x^2  = 2.408448*10^10

300x^2 + 3840000x + 1.2288*10^10 = 2.408448 * 10^10  

Subtract 2.409448 * 10^10 from both sides.

300x^2 + 3840000x - 1,179648 * 10^10

Now use the quadratic formula

I'm guessing I should have converted this to meters because I'm getting ridiculous numbers. They are already large enough as you can see. The method is correct, even if the numbers are not.  

Answer:

B -- a single electron or one of two or more electrons in the outer shell of an atom that is responsible for the chemical properties of the atom.

Explanation:

Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

The electrons in the outermost shell available for bonding are known as valence electrons. Therefore, option (B) is correct.

Valence electrons can be described as the electrons occupying the valence shell or outermost shell of an atom while the electrons filled in the inner shell are known as core electrons. Lewis structures can be helpful to evaluate the valence electrons and know the nature of bonds.

Valence electrons can be filled in several electron shells and these electrons participate in the interaction between atoms and lead to the formation of bonds.

Only electrons filled in the outermost or valence shell can participate in the formation of a chemical bond and set the trend of the reactivity of the element. Valence electrons participate in bonding to achieve the noble gas configuration.

Therefore, valence electrons are the electrons in the outermost shell available for bonding.

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The reactance of a coil can be determined using the formula:

Reactance (X) = Impedance (Z) - Resistance (R)

Given that the resistance of the coil is 120 Ω and the impedance is 200 Ω, we can calculate the reactance using the above formula:

X = 200 Ω - 120 Ω

X = 80 Ω

Reactance is a property of an inductor (coil) that arises due to the presence of inductive elements such as inductance and frequency. It represents the opposition to the flow of alternating current (AC) in an inductor and is associated with the magnetic field generated by the coil. Reactance is measured in ohms (Ω) and can be further categorized into inductive reactance (XL) and capacitive reactance (XC), depending on the type of element present.

In this case, since we are given the impedance and resistance of the coil, we can directly calculate the reactance by subtracting the resistance from the impedance. It's important to note that impedance is the total opposition to the flow of AC and includes both resistance and reactance components. By subtracting the resistance, we isolate the reactance component.

The reactance of the coil is 80 Ω.

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Iron oxide cement produces bright-red and yellow colors in some sandstones.

The coloration in sandstones is often influenced by the presence of different minerals and pigments in the cement that binds the sediment grains together. Iron oxide, specifically hematite (Fe2O3) and goethite (FeO(OH)), is a common cementing material found in sandstones. When present in higher concentrations, these iron oxide minerals can impart bright-red and yellow hues to the sandstone.

The colors of iron oxide cement in sandstones are a result of the selective absorption and reflection of light. Hematite and goethite have specific light absorption properties that allow them to absorb certain wavelengths of light, particularly in the blue and green regions of the visible spectrum. As a result, the sandstone appears red or yellow, as these colors are the wavelengths of light that are not absorbed and are instead reflected or transmitted.

The specific shades and intensity of red and yellow colors in sandstones can vary depending on factors such as the concentration of iron oxide minerals, grain size, and the presence of other minerals or impurities. Different geological processes and environmental conditions during the formation of sandstones can contribute to the variation in coloration.

The bright-red and yellow colors observed in some sandstones are typically caused by the presence of iron oxide cement, specifically hematite and goethite. The selective absorption and reflection of light by these minerals result in the sandstone appearing red or yellow. The exact coloration may vary based on factors such as the concentration of iron oxide, grain size, and geological processes involved in the sandstone's formation.

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The repulsion force between the two Arkon nuclei when the distance between them is 1x10⁻³μm is approximately 7.4x10⁻¹⁴N. The correct option is d. 7.4x10⁻¹⁴N.

The formula for repulsion force between two Arkon nuclei when the distance between them is given by Coulomb's law. Coulomb's law states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as F=kq1q2/r²,

Where F is the force, q1 and q2 are the charges, r is the distance between the charges, and k is the Coulomb's constant.The electric charge of one electron is 1.6x10⁻¹⁹C.

Therefore, the charge of the Arkon nucleus with 18 protons = 18(1.6x10⁻¹⁹) C = 2.88x10⁻₈⁸ CThe force between the two Arkon nuclei can be calculated using the formula above.

F=kq1q2/r²

Substituting the values we have;F = (9x10⁹)(2.88x10⁻¹⁸ C)2/(1x10⁻³ m)2F ≈ 7.4x10⁻¹⁴ N. Therefore, the repulsion force between the two Arkon nuclei when the distance between them is 1x10-3μm is approximately 7.4x10⁻¹⁴N. The correct option is d. 7.4x10⁻¹⁴N.

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Answer:

compacting

Explanation:

i don't think there is very much explanation, the snow falls and compacts the ice to become giant lol

the speed of the waves going past the pier is approximately 20.0 m/s.

The time it takes for a wave crest to move past a fixed point is known as the period of the wave, which is represented by the symbol T. The period is related to the frequency of the wave, which is the number of wave crests that pass a fixed point per unit time. The frequency is represented by the symbol f, and it is related to the period by the formula:

f = 1 / T

In this problem, the time it takes for the bobber to move from its highest point to its lowest point is given as 2.4 s. This time corresponds to the period of the wave, since it is the time it takes for one complete wave crest to pass the pier. Therefore, we can find the frequency of the wave using the formula above:

T = 2.4 s

f = 1 / T

= 1 / 2.4 s

= 0.4167 Hz

The distance between adjacent wave crests is given as 48 m. This distance is called the wavelength of the wave, which is represented by the symbol λ. The speed of the wave, represented by the symbol v, is related to the frequency and wavelength by the formula:

v = fλ

Substituting the values we found above, we get:

f = 0.4167 Hz

λ = 48 m

v = fλ

= 0.4167 Hz x 48 m

= 20.0 m/s

what is frequency?

Frequency refers to the number of occurrences of a repeating event per unit of time.

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Explanation:

Let thermal capacity of the vessel be C' J K-1

Heat energy given by hot water = 40 x 4.2 x (60 - 30) = 5040 J

Heat energy taken by cold water = 50 x 4.2 x (30 - 20) = 2100 J

Heat energy taken by vessel = C' x (30 - 20) = 10 C' J

If there is no loss of heat energy,

Heat energy given by hot water = Heat energy taken by cold water and vessel

or 5040 = 2100 + 10 C'

or 10 C' = 2940

or C'= 294 J K-1

Thus, thermal capacity of vessel = 294 J K-1.

When salt is introduced to water, the temperature at which freezing occurs is lowered.

A mixture of two or more substances is referred to as a solution. The solvent is the substance that dissolves the solute in a solution, while the solute is the substance that is dissolved. The solvent is usually a liquid, while the solute can be a solid, gas, or liquid. Salt is an example of a solid solute that can dissolve in a solvent such as water. The process of dissolving a solute in a solvent is called dissolution. The solute particles become surrounded by the solvent particles during dissolution, which prevents them from re-forming the solid. The amount of solute that can be dissolved in a given solvent at a particular temperature is known as its solubility. As we know, water has a freezing point of 0°C (32°F). The introduction of salt to water, on the other hand, will lower the freezing point. This is due to the solute (salt) causing disorder in the solvent (water) at the molecular level. The salt ions take up positions between water molecules, disrupting the hydrogen bonding network that holds the water molecules together.

As a result, more energy is needed to generate the hydrogen bonds that create ice. The freezing point of the saltwater solution is lowered as a result of this effect.

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The force opposing the motorcycle's motion must be less than 4,000 N and greater than zero since the motorcycle is gradually slowing down.

This means that there must be a force acting in the opposite direction of the motorcycle's motion that is reducing its speed. This force could be due to factors such as air resistance, friction between the wheels and the road, or the weight of the motorcycle and rider. However, it cannot be greater than 4,000 N as that would mean the motorcycle would be accelerating in the opposite direction. It is important to note that the force opposing the motorcycle's motion will vary depending on factors such as speed, terrain, and weather conditions.

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Answer:

I would like to attach options to the question above for clarity.

Jasmine is investigating the effect force has on the motion of an object. She predicts if she puts a strong force on pushing a bowling ball, it will travel a farther distance than when a weak force is applied. Is her prediction correct?

A. No, a weak or a strong force applied to the ball is unable to affect the motion of the ball.

B. No, the force applied to the bowling ball should be a strong force.

C. Yes, the force applied to the bowling ball affects the motion of the ball.

D. Yes, the ball will travel a longer distance when a weak force is applied.

The correct option is C (Yes, the force applied to the bowling ball affects the motion of the ball).

Explanation:

First, a force is any effort either push or pull that causes an object to undergo a change.

A bowling ball can remain at rest or in motion except a force acts on it. This brings us to the question above, the mass which affects force is not mentioned which means it is uniform or negligible. Recall that force = mass X acceleration. So the greater the force that is applied to the bowling ball the further distance it will travel. From the question, she applied a forward force (pushing), so the more force she applies the further the bowling ball will travel.

The estimated demand for Week 4 is 36.3

MAD(Mean Absolute Deviation) is used to calculate the average difference between forecast values and actual values. It calculates the deviation by taking the absolute value of the difference between actual and forecasted demand. The formula to calculate Mean Absolute Deviation is:

MAD= Sum of| Actual demand - Forecast demand | / number of periods

In the given table, the Actual demand is shown as B and the forecast demand is shown as F.

B Actual Forecast 11 40 41 35 38 3 38 35 33 30

Calculation of MAD:

Actual (B) Forecast (F) |B-F|11 40 29.041 35 5.043 38 0.053 3 35.054 38 3.055 35 0.056 33 3.057 30 3.058 0.0 30.0Total 103.0

The number of periods is 9 as shown in the table.

MAD= 103/9MAD= 11.44

Mean Squared Error (MSE) measures the average squared difference between the actual and forecasted values. The formula for MSE is:

MSE= Sum of (Actual demand - Forecast demand)^2 / number of periods.

Calculation of MSE:

Actual (B) Forecast (F) (B-F)^2 11 40 841 35 25 625 38 0 0 3 35 484 38 0 0 35 33 4 30 0 900Total 2854

The number of periods is 9 as shown in the table.

MSE= 2854/9MSE= 317.1

Therefore, the calculated MAD is 11.44 and MSE is 317.1.

Trend Projection formula is given by:

Y = a + bx

where Y is the estimated demand for a particular period.

a is the Y-intercept

b is the slope of the regression line x is the period number

In the given table, the Week number is shown as X and the Actual demand is shown as Y.

Week number Actual Demand 11 24 22 29

Using trend projection for Week 3, we can calculate the demand as follows:

Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*22 - 1*24)/(2*3 - 1*1) = 20/5 = 4

Intercept (a) = Σy/n - b(Σx/n) =(24+22)/2 - 4(2/2) = 23Y = a + bx = 23 + 4(3) = 35

Therefore, the estimated demand for Week 3 is 35.

Using trend projection for Week 4, we can calculate the demand as follows:

Slope (b) = (nΣ(xy) - Σx Σy) / (nΣ(x^2) - (Σx)^2) =(2*29 - 1*24)/(2*5 - 1*1) = 34/9 = 3.78

Intercept (a) = Σy/n - b(Σx/n) =(24+22+29)/3 - 3.78(2.0) = 21.5Y = a + bx = 21.5 + 3.78(4) = 36.3

Therefore, the estimated demand for Week 4 is 36.3.

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Joshua’s study of the mental health of adolescents to fill in insufficient or incomplete information falls under the theoretical knowledge gap in practical research

Practical research is an approach that provides practical solutions to current problems or issues in society. It is an empirical or experimental investigation that employs scientific techniques to discover solutions to practical problems. In practical research, the knowledge gap occurs when the researchers cannot solve or provide explanations for real-world issues, which leads to an incomplete or insufficient understanding of the topic being investigated.

Knowledge gaps can occur in various forms and for various reasons, and identifying them is essential to conduct research to fill these gaps. In the research conducted by Joshua on the mental health of adolescents, he aims to fill the knowledge gap related to adolescents’ mental health by providing a comprehensive understanding of the subject matter.

The knowledge gap here is related to incomplete or insufficient information regarding the mental health of adolescents. Therefore, this type of knowledge gap is theoretical since it relates to the knowledge that is yet to be established or known. To conclude, Joshua's study of the mental health of adolescents falls under the theoretical knowledge gap in practical research.

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Answer:

The force of gravitational attraction between the satellite and Earth is \(2.587\times 10^{10}\) newtons.

Explanation:

Statement is incorrect. Correct statement is:

A satellite (\(m = 4.44\times 10^{9}\,kg\)) travels in orbit around the Earth at a distance of \(1.9\times 10^{6}\,m\) above Earth's surface. What is the force of gravitational attraction between the satellite and Earth?

The gravitational force experimented by the satellite (\(F\)), in newtons, is calculated by Newton's Law of Gravitation, whose equation is defined by following formula:

\(F = \frac{G\cdot m \cdot M}{R^{2}}\) (1)

Where:

\(G\) - Gravitational constant, in cubic meters per kilogram-square second.

\(m\) - Mass of the satellite, in kilograms.

\(M\) - Mass of the Earth, in kilograms.

\(R\) - Distance of the satellite with respect to the center of the Earth, measured in meters.

If we know that \(G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}\), \(m = 4.44\times 10^{9}\,kg\), \(M = 5.972\times 10^{24}\,kg\) and \(R = 8.271\times 10^{6}\,m\), then the force of gravitational attraction between the satellite and Earth is:

\(F = 2.587\times 10^{10}\,N\)

The force of gravitational attraction between the satellite and Earth is \(2.587\times 10^{10}\) newtons.

Answer:

4 hrs

Explanation:

40/10 = 4 hrs

Answer:

1. net force

2. Ist

3. velocity

4. accelerating

5. speed

6. friction

7. The ball will be accelerated faster by the eighth grader.

8.  Newton's third law,

d9. Newton's first law

Explanation:

Answer:

1 represents the electron flow

2 represents the load.

3 represents the voltage source.

4 represents the conductive path.

Explanation:

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

\( V = IR\)

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

In an electrical circuit, there are various symbols used to represent different parameters or quantities as shown in the image attached above and these includes;

a. 1 represents the electron flow. This is a representation of the direction of flow of current.

b. 2 represents the load. This is the electrical appliance such as an electronic bulb that is being powered by the electrical circuit.

c. 3 represents the voltage source. This is typically a battery cell that provides the required amount of voltage for the circuit.

d. 4 represents the conductive path. This is the conductor that carries current from one point to another in the circuit such as copper.

Answer:

11772 N

Explanation:

\(\boxed{w = mg}\)

w= weight

m= mass

g= acceleration due to gravity

The acceleration due to gravity on earth is 9.81m/s².

Substitute m= 1200 and g= 9.81 into the formula:

w= 1200(9.81)

w= 11772 N

Signals generated by transducers are normally of the order of microvolts to millivolts.

What are transducers?

Transducers are electrical components that transform energy from one form into another. They are electrical sensors that generate an electrical signal based on the quantity being assessed.

A transducer is a device that transforms a physical quantity such as force, pressure, or temperature into an electrical signal. This electrical signal can then be amplified, filtered, or measured in other ways.

Some common examples of transducers include microphones, strain gauges, accelerometers, and thermocouples.

What are the signals generated by transducers?

The signals generated by transducers are normally of the order of microvolts to millivolts. The magnitude of the signal generated depends on the quantity being assessed, as well as the type and sensitivity of the transducer.

In order to use the signal generated by a transducer, it is usually necessary to amplify and filter the signal to remove noise and unwanted frequencies. This can be done using an amplifier or other signal processing equipment.

Overall, the signals generated by transducers are a crucial part of many electronic systems and are used in a wide variety of applications.

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The transfer function is Vc(s)/Vs(s) = (R + 1/(sC)) / (sL + R + 1/(sC)), the pole-zero map includes poles at -R/L and zeros at -1/(sC), the response to Vs(t) = u(t)V can be calculated using inverse Laplace transform techniques and the response to Vs(t) = o(t)V can also be determined using inverse Laplace transform techniques.

To find Vc(s)/Vs(s), we need to consider the given electrical system with components R, L, and C. By applying Kirchhoff's laws and solving for the output voltage Vc(s) and input voltage Vs(s) in the Laplace domain, we can derive the transfer function as (R + 1/(sC)) / (sL + R + 1/(sC)).

The pole-zero map provides insights into the stability and behavior of the system. In this case, the transfer function has poles at -R/L, indicating a time constant associated with the system's dynamics. The transfer function also has zeros at -1/(sC), which affect the frequency response characteristics.

To find the response to Vs(t) = u(t)V, where u(t) represents the unit step function, we can apply inverse Laplace transform techniques to the transfer function Vc(s)/Vs(s). This will yield the time-domain response of the system to a step input.

Similarly, to find the response to Vs(t) = o(t)V, where o(t) represents the unit impulse function, we can use inverse Laplace transform techniques on the transfer function Vc(s)/Vs(s). This will give us the time-domain response of the system to an impulse input.

By calculating the inverse Laplace transforms of the transfer functions in cases 3) and 4), we can obtain the time-domain responses of the electrical system to the respective inputs.

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(a) The magnitude of each of her forces of push against the two columns of rock is: 549.6 N.
(b)The fraction of her weight is supported by the frictional force on her shoes is: 1.12.

Given data
Mass of the rock climber = m = 50 kg
Coefficient of static friction between shoes and rock = μ₁ = 1.12
Coefficient of static friction between her back and the rock = μ₂ = 0.767

(a) To find the magnitude of each of her forces of push against the two columns of rock:

Force of push against the left column of rock = F₁
Force of push against the right column of rock = F₂

The maximum frictional force that can be exerted is given by,
Maximum frictional force = μmg
where,
μ = coefficient of static friction
m = mass of the object
g = acceleration due to gravity

In this problem, the object is a rock climber. Therefore, the maximum frictional force that can be exerted is given by,
F₁ = μ₁mg
F₂ = μ₂mg

where,
m = 50 kg
g = 9.8 m/s²

Now, substituting the values in the above equation, we get

F₁ = μ₁mg = 1.12 × 50 × 9.8 = 549.6 N
F₂ = μ₂mg = 0.767 × 50 × 9.8 = 376.93 N

Therefore, the magnitude of the force of push against the left column of rock is 549.6 N and that of the force of push against the right column of rock is 376.93 N.

(b) To find what fraction of her weight is supported by the frictional force on her shoes:

The weight of the rock climber is given by,

W = mg

where,

m = 50 kg

g = 9.8 m/s²

Now, substituting the values in the above equation, we get

W = mg = 50 × 9.8 = 490 N

The frictional force that is supported by her shoes is given by,

Fs = μ₁mg

where,

μ₁ = coefficient of static friction

m = mass of the object

g = acceleration due to gravity

In this problem, the object is a rock climber. Therefore, the maximum frictional force that can be exerted is given by,

Fs = μ₁mg = 1.12 × 50 × 9.8 = 549.6 N

Therefore, the fraction of her weight that is supported by the frictional force on her shoes is,

Fraction = Fs/W = 549.6/490 = 1.12

Therefore, the fraction of her weight that is supported by the frictional force on her shoes is 1.12.

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According to current understanding, the first generation of stars differed from stars born today in their composition.

The first generation of stars, also known as Population III stars, were made up of mostly hydrogen and helium, with very little to no heavier elements.

This is because they formed from the gas and dust left over from the Big Bang, which was primarily hydrogen and helium.

In contrast, stars born today, also known as Population I stars, have a higher percentage of heavier elements, such as carbon, oxygen, and iron.

This is because they formed from gas and dust that has been enriched with heavier elements from previous generations of stars.

As stars age and die, they expel these heavier elements into the surrounding gas and dust, which then goes on to form new stars.

Therefore, the main difference between the first generation of stars and stars born today is their composition, with the first generation having a higher percentage of hydrogen and helium, and stars born today having a higher percentage of heavier elements.

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Answer:

For example, an earthquake of magnitude 5.5 releases about 32 times as much energy as an earthquake measuring 4.5. Another way to look at this is that it takes about 900 magnitude 4.5 earthquakes to equal the energy released in a single 6.5 earthquake.

Explanation:

Answer:

Frequency is the number of revolutions done per second. If one period is 30 seconds, then it takes 30 seconds to complete a single revolution.

So, how many revolutions occur in 1 second?  130

That’s your frequency. It should be obvious that this is the inverse of period.

On another note, angular frequency is the angular distance traveled per second, not revolutions. In a circle, each revolution is a full rotation about a circle, which is  2π

 (radians) Hence the angular frequency, given the above period, is the frequency multiplied by  2π

, since one revolution translates to  2π

 units of angular distance.

In summary, if we call  f

 the frequency (revolutions per second),  ω

 the angular frequency (radians per second) and  T

 your period (seconds per revolution), we have the following relations:

T=1f=2πω

ω=2πf=2πT

Explanation:

Answer:

792J

Explanation:

Use the formula Force × Distance

With 110 newtons being the force and 7.2 meters being the distance

Which gives 792 and work us measured in joules therefore its joules

Work done is the dot product of force and displacement. The work done on the box to push across the surface for 7.2 m by applying a force of 110 N is 792 J.

Force is an external agent acting on a body tp change it from the state of motion or rest.  Force is a vector quantity thus, it is characterized by a magnitude and direction.

When force acting on a body results in displacement of the body, it is said to be work done on the body. The work done on the body is the product of force and displacement.

W = F d.

Given the force acting on the box = 110 N

 displacement d = 7.2 m

Work done w = 110 N × 7.2 m

                       = 792 J.

Therefore, the work done on the box is 792 J.

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The speed of the cat when it slide off the table is 2.27 m/s

To obtain the answer to the given question, we'll begin by obtainig the time taken for the cat to strike the floor. This can be obtained as follow:

h = ½gt²

0.94 = ½ × 9.81 × t²

0.94 = 4.905 × t²

Divide both side by 4.905

t² = 0.94 / 4.905

Take the square root of both side

t = √(0.94 / 4.905)

t = 0.44 s

The speed of the cat can be obatined as illustrated below:

s = ut

1 = u × 0.44

Divide both sides by 0.44

u = 1 / 0.44

u = 2.27 m/s

Thus, we can conclude that the speed of the cat is 2.27 m/s

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The interaction of an attracting or repulsive force between two charged bodies is referred to as an electric force.

This force is comparable to other forces in that it strikes and affects a specific item, and it is simple to illustrate using Newton's law of motion. One of the forces acting on other bodies is the electric force.

Electric force is the interaction of any two charged bodies that is either repellant or attracting. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so. The list of additional forces that apply to objects includes the electric force.

The electrostatic force between the two electrons is one of repulsion since electrons are negatively charged and items with like charges repel one another.

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Answer:

It is in contact with two vertical rails which are joined at the top. The rails are without friction and resistance. There is a horizontal uniform magnetic field of magnitude B perpendicular to the plane of the ring and the rails.

Explanation:

Not sure if this is correct but pls give thanks anyway!