There are two solutions does the equation have.
We have to given that;
The equation is,
⇒ 5x² + 3x + 8
Now, We can see that;
The degree of equation is, 2
Hence, There are two solution of the equation are possible.
Thus, There are two solutions does the equation have.
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answer this correctly and i will give brainliest
2x+3x Equals? Please help!!
Answer:
the answer is 5x
Step-by-step explanation:
Pls answer this 100 points if so
Answer:
(f) can you plz mark brainiest
Step-by-step explanation:
Tracey paid $155 for an item that was originally priced at $520. What percent of the original price did Tracey pay? Around to the nearest tenth of a percent
Tracey paid approximately 29.8% of the original price for the item.
To find the percentage of the original price that Tracey paid, we can use the formula:
Percentage = (Amount Paid / Original Price) * 100
Let's plug in the given values:
Percentage = (155 / 520) * 100
Percentage = 0.2980769230769231 * 100
Percentage ≈ 29.8%
So, Tracey paid approximately 29.8% of the original price for the item.
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One thing that many students think about when they register for classes at a university is how many textbooks they are going to have to buy for the class and how much the books are going to cost. To add to this, a lot of the students wonder if they are even going to use the books that they are required to buy. In fact, some students don’t buy books for their classes because they are convinced that they don’t really need them to achieve an acceptable grade.
This is exactly the line of thinking that textbook writers are afraid of—they want students to have to use their books to get good grades in their classes, and they want professors to think that students need their books so that they require them as part of their classes.
Even though textbooks have a definite value—they are available to students who use them when their professors are not—there is some debate on whether they are really needed as part of university classes.
Recently, a researcher conducted an experiment to address this question. In the experiment, the researcher compared two sections of his introductory statistics course, a course required for all liberal arts and sciences students. Students who were enrolled in the fall semester of the course were told that buying the textbook was optional, whereas students enrolled in the spring semester were told that buying the textbook was required. All 380 of the students (190 in the fall and 190 in the spring) completed the course, and they all took the final exam, which consisted of some calculations and several conceptual essay questions.
When the professor finished scoring the essays, he compared the final exam grades of both sections of the class. He found just what he thought he would—there were no differences in the scores on the exams between the section that thought the textbook was optional and the section that thought the textbook was required. The average grade for the fall semester was 84.3%, and for the spring semester it was 85.2%.
Based on this study, the researcher concluded that textbooks were not necessary or helpful for learning, since there were no differences in scores between the two sections.
No control or comparison group
No random assignment
Participant bias
Small sample size
Poor sample selection
Attrition or mortality
Experimenter bias
Confuse correlation with causality
DV is not reliable, precise or accurate
DV is not valid
DV is not objectively scored
Premature generalization of results
The study conducted by the researcher suffers from several limitations, including the absence of a control group, small sample size, participant bias, and experimenter bias. Furthermore, the sample selection is inadequate, as all the participants are students of one course in a single university.
Moreover, the study fails to account for extraneous variables that might affect the results. Therefore, that textbooks are not necessary or helpful for learning is premature and cannot be generalized to other courses or universities. T he study is flawed, and more research is needed to assess the effect of textbooks on learning.
The study conducted by the researcher suffers from several limitations. First, there is no control group, which makes it difficult to determine whether the results are due to the absence or presence of the textbook. Second, the sample size is small, which reduces the generalizability of the findings.
Third, there is participant bias, as some students might have bought the textbook even though it was optional, while others might not have bought it even though it was required. Fourth, there is experimenter bias, as the professor who scored the essays knew which section had the textbook and which did not.
Fifth, the sample selection is inadequate, as all the participants are students of one course in a single university. Moreover, the study fails to account for extraneous variables that might affect the results, such as the students' prior knowledge, motivation, and study habits.
Therefore, the textbooks are not necessary or helpful for learning is premature and cannot be generalized to other courses or universities. The study is flawed, and more research is needed to assess the effect of textbooks on learning.
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All 136 students in the Math Club went on a field trip. Some students rode in cars which hold 4
students each and some students rode in buses which hold 30 students each. How many of each type
of vehicle did they use if there were 8 vehicles total?
Answer:
They used 4 buses and 4 cars
Step-by-step explanation:
136/30= 4.5 (which means we can full 4 buses)
If we fill 4 buses : 4x30=120
We have 4 vehicles left and 16 students left too.
4x4= 16
We can fit every studens in the cars.
Here is a bank statement.
=
$
Responsible Bank
210 2nd Street
Anytown, MH 06930
Andre Person
1729 Euclid Ave
Anytown, MH 06930
Date
2017-10-03 Previous Balance
2017-10-05 Check Number 256
2017-10-06 ATM Deposit - Cash
2017-10-10 Wire Transfer
2017-10-17 Point of Sale - Grocery Store
2017-10-25 Funds Transfer from Savings
2017-10-28 Check Number 257
2017-10-29 Online Payment - Phone Services
Description
Checking Account Statement
Page: 1 of 1
Statement Period
2017-10-01 to 2017-11-01
Withdrawals Deposits
28.50
37.91
16.43
42.00
72.50
45.00
50.00
1. If we put withdrawals and deposits in the same column, how can they be represented?
2. Andre withdraws $40 to buy a music player. What is his new balance?
3. If Andre deposits $100 in this account, will he still be in debt? How do you know?
Account No.
1120635978
Balance
39.87
11.37
56.37
18.46
2.03
52.03
10.03
-62.47
The analysis of the bank statement thus, given below. Since the result is negative, this means that Andre would still have a negative balance after depositing $100, and therefore would still be in debt.
What is bank statement analysis?1. If we put withdrawals and deposits in the same column, they can be represented as positive and negative values in a single column. Deposits would be represented with positive values, and withdrawals would be represented with negative values.
2. Andre's new balance would be $16.37. We can calculate this by subtracting $40 (the withdrawal) from his previous balance of $56.37:
$56.37 - $40 = $16.37
3. If Andre deposits $100 in this account, he will no longer be in debt. We can calculate his new balance by adding his previous balance and the deposit, and then subtracting any withdrawals:
$56.37 + $100 = $156.37 (balance after the deposit)
$156.37 - $28.50 - $37.91 - $16.43 - $42.00 - $72.50 - $45.00 - $50.00 - $10.03 - $62.47 = -$49.47
Since the result is negative, this means that Andre would still have a negative balance after depositing $100, and therefore would still be in debt.
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What is the percent
increase from 70 to 77?
Percentage change = 10%
We can use the formula:
Percent change = \(\frac{New-Old}{Old}\) x 100
Percent change = \(\frac{77-70}{70}\)x100
Percent change = \(\frac{7}{70}\) x 100
Percent change = 0.1 x 100
Percent change = 10%
Answer: 53.9
Step-by-step explanation:
the cricketplayer class was created so that we can track different stats. it was designed to create a player, then add a match’s statistics, and report the stats.
The cricket Player class has been designed to keep track of the different stats.
This class was created with the aim of creating a player, incorporating a match's statistics, and finally displaying the stats.
Creating an object of the cricketPlayer class is the first step.The object can then be used to call the various member functions of the class.
The stats can be added by calling the appropriate member functions and providing the required data as parameters. Finally, the stats can be displayed by calling the member function that displays the stats.
The cricket Player class has the following member functions:
• setData() - This function is used to set the data members of the cricket Player class. It takes four parameters that represent the player's name, team name, the total number of runs scored, and the number of wickets taken by the player. The function then sets these values to the appropriate data members.
• displayData() - This function is used to display the data members of the cricket Player class. It displays the player's name, team name, the total number of runs scored, and the number of wickets taken by the player.
• addRuns() - This function is used to add runs to the total runs scored by the player. It takes a single parameter that represents the number of runs scored in a particular match. The function then adds this value to the total runs scored by the player.
• addWickets() - This function is used to add wickets to the total number of wickets taken by the player. It takes a single parameter that represents the number of wickets taken in a particular match. The function then adds this value to the total number of wickets taken by the player.
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A distribution of scores on a driver's license test forms is normally shaped. This is an example of a symmetrical distribution. True False
A distribution of scores on a driver's license test forms is normally shaped. This is an example of a symmetrical distribution is TRUE.
A symmetrical distribution is a distribution where there is an equal number of data points on both sides of the center point, in which the mean, mode, and median of a data set are all similar.
A normal distribution is a bell-shaped distribution that is symmetrical, with most of the data falling near the mean and progressively less toward the tails. When data are symmetrical, the mean and median values are similar, and the standard deviation can be used to compute the proportions of data within a range of values surrounding the mean.
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Jeremy stands so his shadow aligns with the shadow of a flag pole. Jeremy’s shadow is 8ft long, he is standing 16 ft from the flag pole, and he is 74in tall. How tall is the flag pole?
The flag pole to which Jeremy's shadow aligns with is 12.33 ft
How tall is the flag pole?Equate the ratio of Jeremy's shadow to flagpole
8 : 16 = 74 in : x
74 in = 6.16667
So,
8 : 16 = 6.16667 : x
8/16 = 6.16667 / x
cross product
8 × x = 16 × 6.16667
8x = 98.66672
divide both sides by 8
x = 98.66672 / 8
x = 12.33334
Therefore, the flag pole is approximately 12.33 ft long
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The grocery store has bulk pecans on sale, which is great since
you're planning on making 7 pecan pies for a wedding. How many
pounds of pecans should you buy?
First, determine what information you n
4 The grocery store has bulk pecans on sale, which is great since you're planning on making 7 pecan ples for a wedding. How many pounds of pecans should you buy? First, determine what information you
To determine how many pounds of pecans should be bought for making 7 pecan pies, you need to know the amount of pecans required for each pie.
The amount of pecans needed for each pecan pie depends on the recipe or the desired level of pecan density in the pie. Typically, a pecan pie recipe calls for around 1 to 1.5 cups of pecans. However, this can vary based on personal preference. To calculate the total amount of pecans needed for 7 pecan pies, you can multiply the number of pies (7) by the amount of pecans required for each pie.
Let's assume a conservative estimate of 1 cup of pecans per pie. Multiplying this by 7 pies gives us a total of 7 cups of pecans. However, to determine the weight in pounds, we need to convert cups to pounds. The weight of pecans can vary, but on average, 1 cup of pecans weighs approximately 4.4 ounces or 0.275 pounds. Therefore, to find the total weight of pecans needed, you would multiply the number of cups (7) by the average weight per cup (0.275 pounds). In this case, you should buy approximately 1.925 pounds of pecans for making 7 pecan pies.
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if i have an 84 in a class, and i get a 64 on a test, what is my grade?
Answer:
Depending on how many grades you have in the class already and how much the test is worth, the score will go down. It will not go below 64, but it will not be above 84.
a plant cell had 5.8 x 10^-6 m and width 2.9 x 10^-6 m. what is the ratio of the plants cells length to its width
The ratio of the plant cell's length to its width is 2:1 (5.8 x 10^-6 m to 2.9 x 10^-6 m).
To calculate the ratio of the plant cell's length to its width, we first need to find the length and width of the cell. The given data states that the length of the cell is 5.8 x 10^-6 m and the width is 2.9 x 10^-6 m. To calculate the ratio, we divide the length by the width. In this example, we divide 5.8 x 10^-6 m by 2.9 x 10^-6 m, which equals 2. Thus, the ratio of the plant cell's length to its width is 2:1.
length / width = 5.8 x 10^-6 m / 2.9 x 10^-6 m = 2
length : width = 5.8 x 10^-6 m : 2.9 x 10^-6 m = 2:1
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Need help to solve (show work) for this example. Virtual school not showing enough instructions. Find value of x
In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
diagram
Step 02:
circle:
arcs and angles:
\(x=\frac{1}{2}(53\degree\text{ + 83}\degree\text{\rparen =}\frac{1}{2}(136\degree)=68\degree\)The answer is:
x = 68°
(1) Find the volume in the first octant bounded by y^2=4−x and y=2z
(2) Find the volume bounded by z=x^2+y^2and z=4
the volume in the first octant bounded by\(y^2=4−x\) and y=2z is pi/36 sqrt(3).
(1) To find the volume in the first octant bounded by the surfaces \(y^2 = 4 - x\) and y = 2z, we can set up a triple integral in cylindrical coordinates.
First, we need to determine the bounds for our variables. Since we are working in the first octant, we know that 0 <= z, 0 <= theta <= pi/2, and 0 <= r.
Next, we need to find the equation for the upper and lower bounds of z in terms of r and theta. We can start with the equation \(y^2 = 4 - x\) and substitute y = 2z to get:
\((2z)^2 = 4 - x\)
\(4z^2 = 4 - x\)
\(x = 4 - 4z^2\)
We can then use this equation along with the equation z = y/2 to get the bounds for z:
\(0 < = z < = (4 - x)^(1/2)/2 = (4 - 4z^2)^(1/2)/2\)
Squaring both sides, we get:
\(0 < = z^2 < = (1 - z^2)/2\)
\(0 < = 2z^2 < = 1 - z^2\)
\(z^2 < = 1/3\)
So the bounds for z are:
\(0 < = z < = (1/3)^(1/2)\)
Finally, we can set up the triple integral in cylindrical coordinates:
V = ∫∫∫ r dz dtheta dr
with bounds:
0 <= r
0 <= theta <= pi/2
\(0 < = z < = (1/3)^(1/2)\)
and integrand:
r
So the volume in the first octant bounded by y^2=4−x and y=2z is:
V = ∫∫∫ r dz dtheta dr
= ∫ from 0 to\((1/3)^(1/2) ∫ from 0 to pi/2 ∫ from 0 to r r dz dtheta dr\)
= ∫ from 0 to\((1/3)^(1/2) ∫ from 0 to pi/2 r^2/2 dtheta dr\)
= ∫ from 0 to\((1/3)^(1/2) r^2 pi/4 dr\)
\(= pi/12 (1/3)^(3/2)\)
= pi/36 sqrt(3)
Therefore, the volume in the first octant bounded by\(y^2=4−x\) and y=2z is pi/36 sqrt(3).
(2) To find the volume bounded by z = x^2 + y^2 and z = 4, we can use a triple integral in cylindrical coordinates.
First, we need to determine the bounds for our variables. Since we are working in the region where z is bounded by \(z = x^2 + y^2\) and z = 4, we know that 0 <= z <= 4.
Next, we can rewrite the equation \(z = x^2 + y^2\) in cylindrical coordinates as \(z = r^2.\)
So the bounds for r and theta are:
0 <= r <= 2
0 <= theta <= 2pi
And the bounds for z are:
\(r^2 < = z < = 4\)
Finally, we can set up the triple integral in cylindrical coordinates:
V = ∫∫∫ r dz dtheta dr
with bounds:
0 <= r <= 2
0 <= theta <= 2pi
\(r^2 < = z < = 4\)
and integrand: 1
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Put the following equation of a line into slope-intercept form, simplifying all fractions. 3x−6y= −30
Answer: y = 1/2x + 5
Step-by-step explanation:
3x-6y= -30
Step 1: Subtract 3x to cancel it out and put it on the other side.
3x-6y= -30 -3x
- 3x
After doing that, the equation should look like this: -6y = -3x - 30
Step 2: Divide by -6 to get y alone
-6y/-6= (-3x - 30)/-6
Step 3: Solve
After dividing everything by -6, we get our answer!!
y = 1/2x + 5
*Slope-Intercept form will always end up being in the same format as y=mx+b
I hope this helps :))
x/8 -4 =7/16 x=
PLEASE HELP I WILL MARK BRAINLIEST
Answer:
Exact form: x = \(\frac{-64}{5}\)
Decimal form: x = -12.8
Mixed number form: x = -12\(\frac{4}{5}\)
Step-by-step explanation:
hope this helps :)
Answer:
x = - \(\frac{64}{5}\)
Step-by-step explanation:
Given
\(\frac{x}{8}\) - 4 = \(\frac{7}{16}\) x ( multiply through by 16 to clear the fractions )
2x - 64 = 7x ( subtract 2x from both sides )
- 64 = 5x ( divide both sides by 5 )
- \(\frac{64}{5}\) = x
when the perimeter of a regular polygon is divided by 5 the lenght of a side is 25 cm what is the perimeter
Answer:
125 cmStep-by-step explanation:
when the perimeter of a regular polygon is divided by 5 the lenght of a side is 25 cm what is the perimeter?
A Regular polygon is a polygon with all sides of equal length
so
25 * 5 = 125 cm
In the rainforest of Puerto Rico, I needed to measure the height of a really tall tree. I used a device to measure the angle of elevation from my line of sight to the top of a tree to be 31°. Find the height of the tree if my height is 6 feet and I was 275 feet from the tree
Answer:
Step-by-step explanation:
See image
The average score of students in the first group is 39, the second group is 32, and the third group is 43. If the numbers of students in the three groups are 24, 26, and 27, respectively, find the average score of all students.
The average score of all students, calculated by taking a weighted average based on the number of students in each group, is 38. The overall performance is slightly below the group averages.
The average score of students in the first, second, and third groups are 39, 32, and 43, respectively. There are 24 students in the first group, 26 students in the second group, and 27 students in the third group.
To find the average score of all students, we need to take a weighted average of the scores in each group, with the number of students in each group as the weights.
Here's how to do it: First, we calculate the total number of students:24 + 26 + 27 = 77. Then, we calculate the total score across all students: 39*24 + 32*26 + 43*27 = 936 + 832 + 1161 = 2929
Finally, we divide the total score by the total number of students to get the average score:2929/77 = 38. The average score of all students is 38.
This means that the overall performance of all the students is slightly below the average of the scores in each group.
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If the scale factor of the point X (-10,4) is 2/5. Then determine the coordinates of the dilated point X’.
A. (-4, 2.6)
B. (-4, 1.6)
C. (-4, 8)
D. (-4, 1.8)
The answer is C.
Can I get brainliest please
Answer:
(-4, 1.6)
Step-by-step explanation:
D. (-2, 0)
can you plz help
more than one answer
Help me with this Question Please.
Answer:
\(3 \times \frac{1}{3 } + \frac{1}{2} \times - 12( \frac{1}{3} ) = \frac{1}{3} \)
Let’s say you separated your candy into two bags. One bag for chocolate bars and one bag for everything else. In the chocolate bar bag there were the following; 10 dark chocolate, 23 milk chocolate, 14 chocolate with nuts and 3 white chocolate bars. If you reached into the bag without looking, what is the probability of getting a dark chocolate bar?
Answer:
10/50 or 1/5 or 20 % chance
Step-by-step explanation:
well to find this out we have to add all of the chocolates together
10+23+14+3
33+17
50
And then we divide the amount of dark chocolate by 50
And it will be 10/50 or 1/5
The first four terms of an arithmetic sequence are shown below.
1, 5, 9, 13,......
(a) Write down the nth term of the sequence (general formula).
(b) Calculate the 100th term of the sequence.
(c) Find the sum of the first 100 terms of the sequence.
Answer:
a) n = 4(n-1)+1
b) 397
c) 19900
Step-by-step explanation:
Divide.
(2x³ − 3x² + 5) ÷ (x − 4)
Answer: \frac{2x^3-3x^2+5}{x-4}
Step-by-step explanation:
a plumer charges $25 for a service call plus $50 per hour of service. write an equation in slope - intercept form for cost , c ,after h hours of service, what will be the total cost for 8 hours of work? 10 hours of work
The total cost for 10 hours of work would be 25 + 50(10) = 525.
What is cost?Cost is the monitorial associated with the purchase of production of food or service if can include the prices of material of which is over it and other expenses that are related to the production of the code of service cost is a major fraction of when deciding whether to purchase a product something as it is and indicator of the value of the product of sound service.
The marginal cost of producing 5 items can be calculated using the equation C(x)=1300+4x/10. The marginal cost is the cost associated with producing one additional item. To calculate the marginal cost, we can plug in x=5 into the equation.
The equation in slope-intercept form for cost, c, after h hours of service is c = 25 + 50h.
The total cost for 8 hours of work would be 25 + 50(8) = 425.
The total cost for 10 hours of work would be 25 + 50(10) = 525.
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What is the difference between midpoint and perpendicular bisector?
Answer:The midpoint can be any middle part of a line, and the perpendicular Bisector is can only be 90 degrees.
Find the median of the data.
31
44
38
32
The calculated median of the stem and leaf data is 32
How to find the median of the data.From the question, we have the following parameters that can be used in our computation:
The stem and leaf plot
By definition, the median of the data is calculated as
Median = The middle element of the stem
using the above as a guide, we have the following:
Middle = Stem 3 and Leaf 2
So, we have
Median = 32
Hence, the median of the data is 32
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