Examples of devices found at the network layer include routers and switches.
Routers and switches are two common devices found at the network layer. A router is a network device that forwards data packets between computer networks. It operates at the network layer of the OSI model and uses routing tables and protocols to determine the best path for data to take between networks. Switches, on the other hand, are used to connect devices within a network. They also operate at the network layer and use MAC addresses to determine the best path for data to take within the network. Both routers and switches play important roles in managing network traffic and ensuring that data is delivered efficiently and securely.
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Never operate electric tools outdoors or in wet conditions unless circuit is protected by what?.
Never operate electric tools outdoors or in wet conditions unless the circuit is protected by a ground fault circuit interrupter (GFCI).
When a number of electric entities are connected through various conductors is called a circuit.
Here,
A ground fault circuit interrupter (GFCI) helps to avoid the repercussion caused due to electric shocks. An individual receives a shock, the GFCI perceives this and cuts off the current before the individual can get any damage. it is usually installed where electrical circuits come into reference with water.
Thus, Never operate electric tools outdoors or in wet conditions unless the circuit is protected by a ground fault circuit interrupter (GFCI).
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Standards relating to technical drawing
Answer:
Borders, Dimensions Identified, Scale, Text Box with Date/Author/Title/Version Number
Explanation:
Technical drawings have many standards in order to maintain integrity and ensure that they can be used by engineers to produce what is mapped out in the drawing.
Every technical drawing needs to have borders and a text box with all information related to the drawing. This includes the date it was created, date it was updated, version number, title, and author.
Furthermore, each drawing should have necessary dimensions with a scale. At the same time, technical drawings should not be over-dimensioned or repetitive.
All of these things must be on a technical drawing to allow professional engineers to sign off on drawings.
A European apparel manufacturer has production facilities in Italy and China to serve its European market, where annual demand is for 1.9 million units. Demand is expected to stay at the same level over the foreseeable future. Each facility has a capacity of 1 million units per year. With the current exchange rates, the production and distribution cost from Italy is 10 euro per unit, whereas the production and distribution cost from China is 7 euro. Over each of the next three years, the Chinese currency could rise relative to the euro by 15 percent with a probability of 0.5 or drop by 5 percent with a probability of 0.5. An option being considered is to shut down 0.5 million units of capacity in Italy and move it to China at a one-time cost of 2 million euros. Assume a discount factor of 10 percent over the three years. Do you recommend this option?
very big question aa having i can't answer it
what executable programs in /usr/bin have names that are exactly two characters long and end in r, and what do they do?
A crontab file is a simple text file that provides a list of instructions that are meant to be run at specific times.
In Linux, FHS describes the contents of directories and how Operating System files are presented to users. The directory /bin houses executable software. The abbreviation for system binaries is s/bin. System binaries need root privileges to carry out particular operations. Binaries that are essential for both booting the system and recovering and restoring it can be found in /the bin. The system boot commands are likewise found in the /bin directory, but the primary distinction between the two is that /sbin applications can only be run by the root user. Examples include ifconfig, fdisk, fsck, root, halt, init, and grub. Simple text instructions are contained in the crontab file, which instructs the cron daemon what to do at predetermined intervals or periods.
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“Snow Cover Area change Analysis for Kabul Basin”
Summarize how GIS & Remote Sensing is incorporated in this study.
GIS
The full for GIS is : Geographic Information System.
The GIS is a system of mapping that is used to create, analyze, manage and map all the types of data.
It is a method capturing, checking as well as displaying all the data that is related to the position of the surface of earth.
Remote Sensing
Remote sensing is defined as a process where the various physical characteristics of an area are constantly monitored and detected by a process of measuring the reflection of the emitted radiations at ta distance.
The snow covered areas of the Kabul basin can be monitored and analyzed by using the process of GIS and remote sensing.
They provide a continuous source of information and data about snow covered peaks, the amount of snow to the authorities.
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What is the meaning of beauty and completeness? In relation to these what are the attributes a Muslim should adopt?
ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.
ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.
When choosing a respirator for your job, you must conduct a _____ test.
A) Fit B) Practice C) Breathing D) Weight?
Answer:
Fit test
Explanation:
it's on the automotive technology sight : )
Consider a regenerative gas-turbine power plant with two stages of compression and two stages of expansion. The overall pressure ratio of the cycle is 9. The air enters each stage of the compressor at 300 K and each stage of the turbine at 1200 K. Accounting for the variation of specific heats with temperature, determine the minimum mass flow rate of air needed to develop a net power output of 105 MW.
Answer: the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s
Explanation:
from the T-S diagram, we get the overall pressure ratio of the cycle is 9
Calculate the pressure ratio in each stage of compression and expansion. P1/P2 = P4/P3 = √9 = 3
P5/P6 = P7/P8 = √9 =3
get the properties of air from, "TABLE A-17 Ideal-gas properties of air", in the text book.
At temperature T1 =300K
Specific enthalpy of air h1 = 300.19 kJ/kg
Relative pressure pr1 = 1.3860
At temperature T5 = 1200 K
Specific enthalpy h5 = 1277.79 kJ/kg
Relative pressure pr5 = 238
Calculate the relative pressure at state 2
Pr2 = (P2/P1) Pr5
Pr2 =3 x 1.3860 = 4.158
get the two values of relative pressure between which the relative pressure at state 2 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.
Relative pressure pr = 4.153
The corresponding specific enthalpy h = 411.12 kJ/kg
Relative pressure pr = 4.522
The corresponding specific enthalpy h = 421.26 kJ/kg
Find the specific enthalpy of state 2 by the method of interpolation
(h2 - 411.12) / ( 421.26 - 411.12) =
(4.158 - 4.153) / (4.522 - 4.153 )
h2 - 411.12 = (421.26 - 411.12) ((4.158 - 4.153) / (4.522 - 4.153))
h2 - 411.12 = 0.137
h2 = 411.257kJ/kg
Calculate the relative pressure at state 6.
Pr6 = (P6/P5) Pr5
Pr6 = 1/3 x 238 = 79.33
Obtain the two values of relative pressure between which the relative pressure at state 6 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.
Relative pressure Pr = 75.29
The corresponding specific enthalpy h = 932.93 kJ/kg
Relative pressure pr = 82.05
The corresponding specific enthalpy h = 955.38 kJ/kg
Find the specific enthalpy of state 6 by the method of interpolation.
(h6 - 932.93) / ( 955.38 - 932.93) =
(79.33 - 75.29) / ( 82.05 - 75.29 )
(h6 - 932.93) = ( 955.38 - 932.93) ((79.33 - 75.29) / ( 82.05 - 75.29 )
h6 - 932.93 = 13.427
h6 = 946.357 kJ/kg
Calculate the total work input of the first and second stage compressors
(Wcomp)in = 2(h2 - h1 ) = 2( 411.257 - 300.19 )
= 222.134 kJ/kg
Calculate the total work output of the first and second stage turbines.
(Wturb)out = 2(h5 - h6) = 2( 1277.79 - 946.357 )
= 662.866 kJ/kg
Calculate the net work done
Wnet = (Wturb)out - (Wcomp)in
= 662.866 - 222.134
= 440.732 kJ/kg
Calculate the minimum mass flow rate of air required to generate a power output of 105 MW
W = m × Wnet
(105 x 10³) kW = m(440.732 kJ/kg)
m = (105 x 10³) / 440.732
m = 238.2 kg/s
therefore the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s
I think the proactive stance is a better attitude to promote than after-the-fact worrying! when planning a long week of sunbathing on the beach, what type of dna damage should sunbathers be aware of before hitting the beach? multiple choice
I completely agree that a proactive stance is crucial when it comes to sunbathing on the beach. Sun exposure can cause a variety of DNA damage, which can ultimately lead to skin cancer. The types of DNA damage that sunbathers should be aware of include:
1. UV-induced DNA damage: UV radiation from the sun can cause damage to the DNA in skin cells, leading to mutations that can increase the risk of skin cancer.
2. Oxidative DNA damage: The sun can also generate reactive oxygen species (ROS) that can damage DNA by causing breaks and other changes.
3. Thymine dimers: UV radiation can cause thymine dimers, which are abnormal bonds between adjacent thymine bases in DNA. These dimers can interfere with DNA replication and transcription and may lead to mutations.
4. Photoaging: The sun can also cause premature aging of the skin, which is characterized by wrinkles, dryness, and other signs of damage.
Therefore, it's essential to take proactive steps to protect your skin before and during sun exposure. This can include wearing protective clothing, applying sunscreen with a high SPF, seeking shade during peak sun hours, and staying hydrated. By being proactive, you can reduce your risk of DNA damage and protect your skin from the harmful effects of the sun.
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The internal loadings at a critical section along the steel drive shaft of a ship are calculated to be a torque of 2300 lb⋅ft, a bending moment of 1500 lb⋅ft, and an axial thrust of 2500 lb. If the yield points for tension and shear are σY= 100 ksi and τY = 50 ksi, respectively, determine the required diameter of the shaft using the maximum-shear-stress theory
Answer:
Explanation:
Given that:
Torque T = 2300 lb - ft
Bending moment M = 1500 lb - ft
axial thrust P = 2500 lb
yield points for tension σY= 100 ksi
yield points for shear τY = 50 ksi
Using maximum-shear-stress theory
\(\sigma_A = \dfrac{P}{A}+\dfrac{Mc}{I}\)
where;
\(A = \pi c^2\)
\(I = \dfrac{\pi}{4}c^4\)
\(\sigma_A = \dfrac{P}{\pi c^2}+\dfrac{Mc}{ \dfrac{\pi}{4}c^4}\)
\(\sigma_A = \dfrac{2500}{\pi c^2}+\dfrac{1500*12c}{ \dfrac{\pi}{4}c^4}\)
\(\sigma_A = \dfrac{2500}{\pi c^2}+\dfrac{72000c}{\pi c^3}}\)
\(\tau_A = \dfrac{T_c}{\tau}\)
where;
\(\tau = \dfrac{\pi c^4}{2}\)
\(\tau_A = \dfrac{T_c}{\dfrac{\pi c^4}{2}}\)
\(\tau_A = \dfrac{2300*12 c}{\dfrac{\pi c^4}{2}}\)
\(\tau_A = \dfrac{55200 }{\pi c^3}}\)
\(\sigma_{1,2} = \dfrac{\sigma_x+\sigma_y}{2} \pm \sqrt{\dfrac{(\sigma_x - \sigma_y)^2}{2}+ \tau_y^2}\)
\(\sigma_{1,2} = \dfrac{2500+72000}{2 \pi c ^3} \pm \sqrt{\dfrac{(2500 +72000)^2}{2 \pi c^3}+ \dfrac{55200}{\pi c^3}} \ \ \ \ \ ------(1)\)
Let say :
\(|\sigma_1 - \sigma_2| = \sigma_y\)
Then :
\(2\sqrt{( \dfrac{2500c + 72000}{2 \pi c^3})^2+ ( \dfrac{55200}{\pi c^3})^2 } = 100(10^3)\)
\((2500 c + 72000)^2 +(110400)^2 = 10000*10^6 \pi^2 c^6\)
\(6.25c^2 + 360c+ 17372.16-10,000\ \pi^2 c^6 =0\)
According to trial and error;
c = 0.75057 in
Replacing c into equation (1)
\(\sigma_{1,2} = \dfrac{2500+72000}{2 \pi (0.75057) ^3} \pm \sqrt{\dfrac{(2500 +72000)^2}{2 \pi (0.75057)^3}+ \dfrac{55200}{\pi (0.75057)^3}}\)
\(\sigma_{1,2} = \dfrac{2500+72000}{2 \pi (0.75057) ^3} + \sqrt{\dfrac{(2500 +72000)^2}{2 \pi (0.75057)^3}+ \dfrac{55200}{\pi (0.75057)^3}} \ \ \ OR \\ \\ \\ \sigma_{1,2} = \dfrac{2500+72000}{2 \pi (0.75057) ^3} - \sqrt{\dfrac{(2500 +72000)^2}{2 \pi (0.75057)^3}+ \dfrac{55200}{\pi (0.75057)^3}}\)
\(\sigma _1 = 22193 \ Psi\)
\(\sigma_2 = -77807 \ Psi\)
The required diameter d = 2c
d = 1.50 in or 0.125 ft
containers transporting more than 1000 pounds of non-bulk packages are required to be placarded on
Containers transporting more than 1000 pounds of non-bulk packages are required to be placarded on all four sides of the vehicle.
What is the requirement for placarding containers transporting more than 1000 pounds of non-bulk packages?Containers transporting more than 1000 pounds of non-bulk packages are required to be placarded on all four sides of the vehicle.
Placards are large, diamond-shaped signs that communicate the type of hazardous material being transported.
They are used to alert emergency responders, other drivers, and the public about the potential hazards associated with the cargo. Placarding helps ensure safety and proper handling of the materials during transportation.
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where does the efficienty occur maximum? what will be a condition of maximum efficienty?
Answer:
The transformer will give the maximum efficiency when their copper loss is equal to the iron loss.
engineers can modify a system to eliminate nearly all false positives, but that action risks making the system prone to false negatives: failing to identify a dangerous situation true
Yes, that is correct. When engineers modify a system to eliminate nearly all false positives, they often do so by making the criteria for identifying a potential threat very strict. While this can reduce the number of false alarms, it also increases the risk of false negatives - situations where the system fails to identify a dangerous situation. This can be particularly dangerous in situations where the consequences of a missed threat could be catastrophic.
Therefore, it's important for engineers to carefully balance the risk of false positives and false negatives when designing and modifying systems.Yes, that is a true statement. In many systems, there is a tradeoff between sensitivity (the ability to detect all true positives) and specificity (the ability to avoid false positives). If engineers modify a system to eliminate nearly all false positives, it means that the system will only trigger an alarm or alert when it is highly certain that a dangerous situation is occurring. However, this also means that the system may miss some true positives and fail to identify a dangerous situationFor example, consider a security system that triggers an alarm when it detects motion in a restricted area. If the system is too sensitive, it may trigger false alarms due to environmental factors such as wind, shadows, or animals. To eliminate these false positives, engineers may adjust the system's sensitivity so that it only triggers an alarm when a person or object is detected. However, this may also mean that the system may miss some intruders who manage to avoid detection, resulting in false negatives.Thus, engineers must strike a balance between sensitivity and specificity based on the requirements and constraints of the system. In some cases, it may be necessary to accept a certain level of false positives or false negatives, while in other cases, it may be possible to minimize both.
Hi! Yes, it is true that engineers can modify a system to eliminate nearly all false positives, but doing so may increase the risk of the system being prone to false negatives, which means it could fail to identify a dangerous situation.
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in the 802.11a amendment, the unii-3 band is intended to be used for which of the following wlan applications?
IEEE 802.11a is an amendment to the 802.11 standard for wireless LANs.
Which of the following wlan applications?
They are used for home and small office networks that link together laptop computers, printers, smartphones, Web TVs and gaming devices with a wireless router, which links them to the internet.WLANs allow users to move around in a confined area while they are still connected to the network. In some instance wireless LAN technology is used to save costs and avoid laying cable, while in other cases, it is the only option for providing high-speed internet access to the public.Although the terms WLAN and Wi-Fi are used interchangeably, the two wireless technologies differ. Wireless LAN uses radio technology to connect nodes, while Wi-Fi is a type of WLAN.To learn more about wlan refers to:
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what is most delicious fod in the philippines?
Answer:
Well there are a lot of delicious food in the philppines but my most favorite is the Lechon, Adobo, Sisig, Chicken Curry, Crispy pata and Sinigang
When thrust faults occur, the region undergoing stress is subject to: Group of answer choices compression tension shearing No answer text provided.
When thrust faults occur, the region undergoing stress is subject to compression stress.
What is compression stress?Compressive stress is a force that causes a substance to deform in order to take up less space.
When thrust faults occur, the region undergoing stress is subject to compression stress. A substance is said to be under compression when it is subjected to compressive stress.
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A 50 g polymer sample was fractionated into six samples of different weights given in the table below. Estimate the number average and weight average molecular weights of the original sample. Would you classify the molecular weight distribution of the original sample as narrow or broad?
Molecular weight distribution is an important factor in the polymer’s physical properties. The molecular weight of a polymer, for example, influences its tensile strength, viscosity, and other properties. As a result, the average molecular weight and molecular weight distribution of a polymer must be determined before it can be used in any application.
A 50 g polymer sample was fractionated into six samples of different weights given in the table below. Estimate the number average and weight average molecular weights of the original sampleSo, let us first calculate the number average molecular weight and weight average molecular weight by using the formulae.Number average molecular weight is given by the formula, M_n = Σ(N_iM_i)/ΣN_iwhere N_i and M_i are the mole fraction and molecular weight of ith fraction of polymer respectively.From the table given above,ΣN_i = 1.0 (sum of all mole fractions of different fractions of polymers is always equal to 1)For Number average molecular weight, M_n = (4*10^20 * 2000 + 6*10^20 * 8000 + 10*10^20 * 20000 + 15*10^20 * 40000 + 18*10^20 * 80000 + 19*10^20 * 120000)/(4*10^20 + 6*10^20 + 10*10^20 + 15*10^20 + 18*10^20 + 19*10^20)M_n
= 1,207,527 g/molWeight average molecular weight is given by the formula, M_w =
Σ(N_iM_i^2)/Σ(N_iM_i)For Weight average molecular weight, M_w = (4*10^20 * 2000^2 + 6*10^20 * 8000^2 + 10*10^20 * 20000^2 + 15*10^20 * 40000^2 + 18*10^20 * 80000^2 + 19*10^20 * 120000^2)/(4*10^20 * 2000 + 6*10^20 * 8000 + 10*10^20 * 20000 + 15*10^20 * 40000 + 18*10^20 * 80000 + 19*10^20 * 120000)M_w = 2,715,479 g/molNow let us classify the molecular weight distribution of the original sample as narrow or broad.Now, Molecular weight distribution (Mw/Mn) = (2,715,479/1,207,527)Molecular weight distribution (Mw/Mn) = 2.25The distribution is broad since the molecular weight distribution of the original sample is greater than 1, which implies a broad range of molecular weights. This indicates that the polymer sample is made up of polymers with a wide range of molecular weights.
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A circular hoop sits in a stream of water, oriented perpendicular to the current. If the area of the hoop is doubled, the flux (volume of water per unit time) through it:___________
Answer:
The flux (volume of water per unit time) through the hoop will also double.
Explanation:
The flux = volume of water per unit time = flow rate of water through the hoop.
The Flow rate of water through the hoop is proportional to the area of the hoop, and the velocity of the water through the hoop.
This means that
Flow rate = AV
where A is the area of the hoop
V is the velocity of the water through the hoop
This flow rate = volume of water per unit time = Δv/Δt =Q
From all the above statements, we can say
Q = AV
From the equation, if we double the area, and the velocity of the stream of water through the hoop does not change, then, the volume of water per unit time will also double or we can say increases by a factor of 2
all electrical service distribution equipment is labeled with its maximum voltage and current ratings . select one: a. true b. false
The voltage range and current consumption at which an electrical device is intended to function are both disclosed in its rating. Normally, a rating plate that is attached to the device displays these figures, such as 230 volts, 3 amps.
Explain about the maximum voltage and current ratings?
For products lacking a protective element at the VCC side, voltages up to the absolute maximum rated supply voltage (i.e., VEE+36V) can be delivered, independent of supply voltage. In general, the absolute maximum common-mode voltage is VEE-0.3V and VCC+0.3V.
The chip's maximum ratings are the harsh conditions to which it can be subjected for a brief period of time without suffering long-term harm. Long-term exposure to absolute maximum ratings may have an impact on a device's dependability.
(Krnt Rest) (Electrical engineering: Circuits, Electrical power) The greatest current that a fuse is rated to carry for an infinite duration without significantly degrading the fuse element is known as the current rating.
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solve for the unknown values in the circuit in figure 3-9, NEED ANSWERS ASAP
Answer:
25 V, 50V, 75V respectively.
I hope it will be useful.
where the nec does require listing, the equipment shall be installed and used in accordance with the ?
Where the NEC does require listing, the equipment shall be installed and used in accordance with the listing and labeling conditions specified in the instructions included in the listing or labeling.
In accordance with the listing, equipment should be installed and utilized. A listing is a formal document that lists the criteria and requirements that equipment must meet in order to be deemed safe and functional. A listing implies that an independent third-party organization has tested and validated the equipment to be safe for use. The National Electrical Code (NEC) requires that specific electrical equipment be listed or certified by an independent testing laboratory to ensure that it is safe and suitable for the intended purpose.This ensures that the equipment is properly installed, maintained, and operated for safety and effectiveness.
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The posted speed limit is the highest speed that you are
permitted to drive unless
Answer:
d
Explanation:
Which one of the following answer options are your employers responsibility
Where are your answer options?
Answer:
Implement a hazard communication program
Explanation: i took the quiz
suggestions for implementing self-monitoring strategies include: implementing self-monitoring strategies after the student has already learned to do the task; teaching the self-monitoring strategy to the student before implementing the strategy; and which of the following?
Another suggestion for implementing self-monitoring strategies is to provide ongoing feedback to the student regarding their performance. This can help the student to become more aware of their own performance and to adjust their behavior accordingly.
Feedback can take many forms, such as verbal praise, written comments, or visual cues, and should be provided consistently and in a timely manner. In addition, it can be helpful to involve the student in the development of the self-monitoring strategy, as this can increase their sense of ownership and motivation to use the strategy effectively.
Finally, it may be useful to provide additional support and scaffolding as the student learns to use the self-monitoring strategy, such as modeling, guided practice, or prompts, in order to ensure that the strategy is implemented correctly and effectively.
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The _ (set of values) of an attribute may represent an entity itself (e.g. an address of a person, a city in which a person is living, the phone number of a person).
The set of values of an attribute that represents an entity itself is known as a domain.
In a database, an attribute represents a characteristic or property of an entity. The domain of an attribute defines the set of values that the attribute can take. In some cases, the set of values of an attribute can represent an entity itself. For example, consider the attribute "address" of a person entity. The set of values for this attribute would be a domain that represents different addresses. Each value within the domain corresponds to a specific address, and the attribute itself represents the entity of an address.
Similarly, attributes like "city" or "phone number" can also have domains that represent the entities of cities or phone numbers, respectively. By defining appropriate domains for attributes, a database can accurately represent and store information about entities and their associated properties. Domains ensure that the values assigned to attributes adhere to the intended entities and provide meaningful and consistent data storage and retrieval
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How does the action of wind affect a rock’s appearance?
Answer:
Forces like wind and water break down rocks through the processes of weathering and erosion. ... Forces like wind and water move the rock pieces. They mix with matter like sand to become sediment. Weathering and erosion help shape Earth's surface.
Answer:
As an agent of erosion, the wind will quickly break the rock into different rock types.
Explanation:
How many loads can be connected in series per line in a control circuit in which a switch is use as to control the loads?
Answer:45
Explanation:
because i am gay
Engine oil flows in a 15-cm-diameter horizontal tube with a velocity of 1.3 m/s, experiencing a pressure drop of 12 kPa. The pumping power required to overcome this pressure drop in W is
Given:Velocity of the engine oil, v = 1.3 m/s Diameter of the horizontal tube, D = 15 cm = 0.15 m Pressure drop, ΔP = 12 kPa.
We know that: Pumping power required = (Pressure drop × Volume flow rate) ÷ Efficiency Volume flow rate, Q = πD²/4 × vQ = π(0.15)²/4 × 1.3Q = 0.01335 m³/s= 13.35 L/s Substitute the values: Pumping power required = (12 kPa × 0.01335 m³/s) ÷ 0.70 Pumping power required = 226.9 W
Therefore, the pumping power required to overcome this pressure drop is 226.9 W (rounded off to the nearest tenth).Note: The efficiency value is not given. It is assumed as 0.70 (typical efficiency value of pumps).
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Installation a2 An insulated rigid tank initially contains 1.4-kg saturated liquid
water and water vapor at 200°C. At this state, 25 percent of the
volume is occupied by liquid water and the rest by vapor. Now an
electric resistor placed in the tank is turned on, and the tank is
observed to contain saturated water vapor after 20 min. Determine
(a) the volume of the tank, (b) the final temperature, and (c) the
electric power rating of the resistor
nd demo of reaper in Mahindra Yuvo 575 DI tractor
Answer:
Explanation:
It appears that you are trying to solve a problem involving an insulated rigid tank containing saturated liquid water and water vapor. To determine the volume of the tank, you will need to know the mass of the liquid water and the mass of the water vapor. The mass of the liquid water can be calculated by multiplying the mass of the water and vapor mixture by the fraction of the mixture that is liquid water (1.4 kg * 0.25 = 0.35 kg). The mass of the water vapor can be calculated by subtracting the mass of the liquid water from the total mass of the mixture (1.4 kg - 0.35 kg = 1.05 kg).
To determine the final temperature of the tank, you will need to know the amount of heat added to the tank by the electric resistor and the specific heat capacity of the water and water vapor mixture. The specific heat capacity is a measure of the amount of heat required to raise the temperature of a substance by a certain amount. The specific heat capacity of water is 4.186 J/g°C, and the specific heat capacity of water vapor is 2.080 J/g°C.
To determine the electric power rating of the resistor, you will need to know the amount of heat added to the tank by the resistor and the time over which the heat was added. The power rating of the resistor is equal to the amount of heat added to the tank divided by the time over which the heat was added.
I hope this helps clarify the problem and provide some guidance on how to solve it. If you have any further questions or need additional help, please don't hesitate to ask.
As an electrician on the job, you encounter an installation that is supposed to have ten 250-watt lamps on a 20 amp
circuit. The voltage is 120 volts to each lamp. Is this circuit adequate considering that the load is continuous and the
circuit can only be loaded to 80% of its rating? (You will see the calculation once you submit)
a Yes
b. No
check photo below
answer is yes
The watt is used to quantify the amount of power in a circuit. Yes the circuit is large enough to carry the load as the reason the above response is correct is as follows:
Number of 500-W lamp to be installed on the same circuit = 8
Circuit voltage, V = 227 V
Rating of circuit breaker on the circuit = 20-A
Allowable load for continuous use = 80% of the rating
What's the current equation for physics?The circuit is large enough to sustain the load and has an allowed current load greater than the total current flowing through it. The maximum continuous use current for the circuit is 16 A, or 80% of 20 A.
The current is flowing which can be calculated to use the electric current formula I=V/R. Ohm's Law serves as the foundation for what is known as the "current equation." I, V, and R are the variables that stand in for current, voltage, and resistance, respectively.
Current is calculated as the quantity of electrons passing through the cross section of a conductor in a second. Although they move in the same general direction, current and electrons move in different paths. In both directions, electrons can go from a negative to a positive potential.
Therefore, The watt is used to quantify the amount of power in a circuit.
Learn more about electrons on:
https://brainly.com/question/1255220
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