Answer:
This is a category of physics dealing with the observable phenomena, and experimental aspects by investigation, and scientific testing to measure the properties of matter, and energy.
Answer:
Experimental physics is the category of disciplines and sub-disciplines in the field of physics that are concerned with the observation of physical phenomena and experiments.
I hope you helped^_^
Follow me for more answersTwo objects of the same mass are launched from the ground. object a has a launch angle of 45, while object b has a launch angle of 65. which object will fly the farthest
In this case, object b will fly farther than object a.
ANGLE MASSThe distance that an object flies depends on its initial velocity, launch angle, and the gravitational acceleration acting on it. All other things being equal, the object with the higher launch angle will fly farther. In this case, object b will fly farther than object a.
When an object is launched at an angle, it follows a parabolic path under the influence of gravity. The initial velocity of the object, the launch angle, and the gravitational acceleration all play a role in determining the shape and distance of this path.
The launch angle is the angle between the initial velocity of the object and the horizontal. For an object launched at an angle, the vertical component of its initial velocity determines the highest point it reaches, while the horizontal component determines how far it travels horizontally.
For two objects of the same mass, the one launched at a higher angle will have a greater vertical component of its initial velocity, and therefore will reach a higher maximum height. It will also have a smaller horizontal component of its initial velocity, meaning it will take longer to return to the ground. As a result, the object launched at a higher angle will travel a greater horizontal distance before hitting the ground.
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what is a Pulley why is it used
Answer:
A simple pulley is a wheel with a rope that allows you to pull one end and have it lift whatever is on the other end. A modern, common example of this is a crane, often used in construction.
Explanation:
What is electricity?
Answer:Electricity is the flow of electrons. All matter is made up of atoms, and an atom has a center, called a nucleus. When electrons are "lost" from an atom, the free movement of these electrons constitutes an electric current. Electricity is a basic part of nature and it is one of our most widely used forms of energy.
Explanation:
Answer:
Electricity is the set of physical phenomena associated with the presence and motion of matter that has a property of electric charge. Various common phenomena are related to electricity, including lightning, static electricity, electric heating, electric discharges and many others.a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.
Explanation:
Two students with masses of 40kg and 32 kg are sitting 22 m apart. What is the gravitational force of attraction between them?
I get 1.76 x 10^-10 Newton.
That's 0.000 000 000 176 Newton
Which is about 0.000 000 000 635 ounce of force pulling them together.
That's why we never notice it.
A sound wave travelling in water has a frequency of 100 Hz. The speed of sound in water is 1482 m/s. Calculate the wavelength of the wave
Select the correct answer. Which statement correctly describes protons? A. They have no charge and are present in the nucleus of an atom. B. They have a negative charge and travel around the nucleus of an atom. C. They have a positive charge and travel around the nucleus of an atom. D. They have a positive charge and are present in the nucleus of an atom along with the neutrons.
The statement "They have a positive charge and are present in the nucleus of an atom along with the neutrons" correctly describes protons.
What are protons?Protons are small particles that make up the nucleus of an atom. They carry a positive charge and have a mass of approximately 1 atomic mass unit. The number of protons within an atom's nucleus defines its atomic number and thus its identity as an element.
For instance, carbon atoms have 6 protons, and oxygen atoms have 8 protons. Protons are vital building blocks of all atoms and play a significant role in the chemical behavior and reactions of elements.
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give relation between potential work and time
Relation between work done and potential is a change in the potential energy associated with the force. The negative sign provides the convention that work done against a force field increases potential energy, while work done by the force field decreases potential energy.
A fire engine is moving at 40 m/s and sounding its
horn. A car in front of the fire engine is moving at
30 m/s, and a van in front of the car is stationary.
Which observer hears the fire engine's horn at a
higher pitch, the driver of the car or the driver of
the van?
The driver of the van will hear a higher pitch due to his higher relative velocity.
What is relative velocity?The relative velocity of an object is the velocity of the object with respect to a stationary observer.
If a fire engine is moving at 40 m/s and sounding its horn. Also if A car in front of the fire engine is moving at 30 m/s, and a van in front of the car is stationary.
The relative velocity of the stationary van is calculated as;
Vv = -40m/s - 30 m/s = - 70 m/s
The driver of the van will hear a higher pitch since his combined relative velocity of both cars is 70 m/s.
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The efficiency of a motor is 15%. The student calculated the useful output energy transfer is 1.20J. Calculate the total input energy transfer.
Answer:
\(8.0\; \rm J\).
Explanation:
The efficiency of a machine is the ratio between the useful output and the energy input:
\(\begin{aligned}\text{efficiency} &= \frac{\text{useful output}}{\text{energy input}} \times 100\%\end{aligned}\)
Rearrange this equation to find energy input in terms of efficiency and useful output:
\(\displaystyle \text{energy input} = \frac{\text{useful output}}{\text{efficiency} / (100\%)}\).
Substitute in the values: \(\text{useful output} = 1.2\; \rm J\) and \(\text{efficiency} = 15\%\). Evaluate to find the value of \(\text{energy input}\):
\(\begin{aligned} \text{energy input} &= \frac{\text{useful output}}{\text{efficiency} / (100\%)} \\ &= \frac{1.20\; \rm J}{15\% / (100\%)} \\ &= 8.0\; \rm J\end{aligned}\).
(Rounded to two significant figures as in the value of efficiency.)
What angle is necessary to keep a 10 kg box motionless if the coefficient of static friction between the box and the ramp is 0.55?
a.33.4°
b.28.8°
c.56.6°
d.45.0°
The angle necessary to keep a 10 kg box motionless, given a coefficient of static friction of 0.55 between the box and the ramp, is 33.4°, which corresponds to Option A.
To determine the angle, we can use the relationship between the coefficient of static friction, the angle of the incline, and the gravitational force acting on the box. The maximum static friction force can be calculated using the formula:
Friction force = coefficient of static friction * Normal force
The Normal force can be found by decomposing the gravitational force acting on the box into components parallel and perpendicular to the incline. The perpendicular component (Normal force) is equal to the weight of the box (mass * gravitational acceleration).
Since the box is motionless, the friction force must be equal to the component of the gravitational force acting parallel to the incline:
Friction force = Component of weight parallel to incline
By substituting the given values and solving for the angle, we find:
coefficient of static friction = tan(angle)
angle = arctan(coefficient of static friction)
angle = arctan(0.55) ≈ 33.4°
Therefore, the correct answer is Option A, 33.4°.
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Question 2 (3 points)
Which of the following is the main difference between speed and velocity?
A)There is no difference between speed and velocity.
B)Velocity has both speed and direction.
C)There is no difference between speed and velocity.
D)Speed is constant.
If a person pushed on the door to the left of the handle, will they need to use more or less force than if they used the handle? explain why
If a person pushed on the door to the left of the handle, they would need to use less force than if they used the handle.
The reason for this is that the handle provides a mechanical advantage over pushing directly on the door. When the handle is used, the force applied to it is multiplied by the mechanical advantage, which is the ratio of the distance through which the handle moves to the distance through which the door moves.
For example, if the handle moves the door a distance of 2 cm and the door moves a distance of 5 cm when pushed directly on it, the mechanical advantage is 2:5, or 0.4. This means that for every 0.4 units of force applied to the handle, the door moves 1 unit.
On the other hand, if the person pushed directly on the door, the force applied to it would be the same as the force applied to the door, without any mechanical advantage. In this case, the door would move 5 cm, not 2 cm, for every unit of force applied to it.
Therefore, the person would need to use more force if they pushed directly on the door than if they used the handle, because they would have to apply the same amount of force over a greater distance to move the door the same distance.
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Which statement correctly describes the relationship between the volume of a gas and its temperature, in Kelvin, assuming pressure is held constant?
1. The relationship is inversely proportional; as temperature increases, volume decreases in the same way.
2. The relationship is directly proportional; as temperature increases, volume increases in the same way.
3. The relationship is inversely proportional; as temperature increases, volume increases in the same way.
4. The relationship is directly proportional; as temperature increases, volume decreases in the same way.
The relationship is directly proportional; as temperature increases, volume increases in the same way.
Charles's law states that at a constant pressure, the volume of fixed a mass of a gas is directly proportional to its absolute temperature or kelvin temperature.
Mathematically, this law can be written as follows;
\(V = kT\\\\where;\\k \ \ is \ a \ constant \\\\T \ is \ kelvin \ temperature\\\\V \ is \ the \ volume \ of \ the \ gas\)
This law explains the direct relationship between Volume of the gas and its Kelvin temperature. That is, as Temperature increases, the volume of the gas increases.
Thus, the correct statement is "The relationship is directly proportional; as temperature increases, volume increases in the same way".
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Answer:
The relationship is directly proportional; as temperature increases, volume increases in the same way.
Explanation:
I took the test.
NO LINKs PERIOD, FREQUENCY OR AMPLITUDE
1. Doesn't change period
2. More of this means more energy
3. Increases as a pendulum swings back and forth faster
4. Measured in cycles per second
5. Measured in meters or centimeters
6. This is decreases with smaller swing
7. If the frequency increases, this decreases
8. Measured in Hertz
9. Measured in seconds
10. if it swings back and forth slower, this decrease
11. As it dampens, this decreases
Answer:
AmplitudeAmplitude Frequency Frequency Amplitude Frequency Time peroidFrequency Time period Frequency Amplitude1. Which of the following is an example of projectile motion?
An elevator
Ajet taking off
O A football flying through the air
Dropping an aluminum can into the garbage
Answer:
A football flying through the air
Explanation:
when an object has projectile motion it is moving through the air
From the given options, the football flying through the air is the prime example of projectile motion. (option d)
Projectile motion refers to the motion of an object that is launched into the air and moves under the influence of gravity alone. It follows a curved path known as a projectile trajectory. Among the options provided, the example that best represents projectile motion is a football flying through the air.
When a football is kicked or thrown, it experiences an initial force that propels it forward. However, as soon as it leaves the kicker's or thrower's hand or foot, the only force acting on it is gravity. Gravity pulls the football downward, causing it to follow a curved path. The shape of the path depends on the angle at which the football is launched and its initial velocity.
During its flight, the football follows a parabolic trajectory, moving both horizontally and vertically. The horizontal component of its motion remains constant, while the vertical component experiences a downward acceleration due to gravity. This combination of horizontal and vertical motion creates the characteristic curved path of projectile motion.
Therefore, option (d) is correct.
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An object that is slowing down can be described as:______.
Answer: an object with much friction
Explanation:
I read about it good luck
You are an astronomer on planet tirth, which orbits a distant star. it has recently been accepted that tirth is spherical in shape, though no one knows its size. one day, you learn that on the equinox your sun is directly overhead in the city of tyene, located 750 kilometers due north of you. on the equinox, you go outside in alectown and observe that the altitude of your sun is 87.0 ∘.
Answer:
The circumference will be "43,200 km".
Explanation:
As you should be directly south of Tyene, this same angular distance among both yourself as well as the town of Tyene seems to be the distinction to be made throughout the height including its sun at two positions on a specified day.
The sun is therefore immediately overhead in Tyene, does have an altitude with respect to the horizon will be:
⇒ \(\Theta_r = 90^{\circ}\)
At the very same day on yourself location, the altitude of the sun will be:
⇒ \(\Theta_A=85^{\circ}\)
Therefore, a complete circle is 360 degrees. So the angular distinction will be somewhere between you as well as Tyene:
⇒ \(\frac{5}{360}\)
Therefore,
⇒ \(\frac{\Theta}{x}=\frac{360}{Circumference}\)
⇒ \(Circumference=\frac{360}{\Theta}\times x\)
If, \(\Theta = 5^{\circ}\)
\(x (separation) = 600 \ km\)
Now,
The circumference = \(\frac{360}{5}\times 600\)
= \(43,200 \ km\)
a boy sleading down a hill accelerates
alt 1.40m/s? If he started from rest, in what
In what distance would he reach a speed.
of 7s?
Answer:
9.8
Explanation:
distance=vt
1.40*7=distance
What is the net force on an object with a mass of 2.5 kg if it accelerates at 6.4 m/s^2 when pushed?
ANSWER:
16 N
STEP-BY-STEP EXPLANATION:
The force is given by the multiplication of the mass and the acceleration, like this:
\(\begin{gathered} f=m\cdot a \\ m=2.5\text{ kg} \\ a=6.4\frac{m}{s^2} \end{gathered}\)We repalce and calculate the force, like this:
\(\begin{gathered} f=2.5\cdot6.4 \\ f=16\text{ N} \end{gathered}\)The force is 16 newtons
Answer Questions below
Answer:
When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.
1) V= 60 volt
Total resistance R = R₁ + R₂
= 20 + 10
= 30 Ω
2) Ohms law states that,
\(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)
3) Voltage around 10 Ω resistor,
V₂ = I R₂
= 2 * 10
= 20 volt
___________________________________________________
4) Total current = 1 A
5) Total voltage = 8 volt
6) Voltage around R₁ is V₁
R₁ = 2 Ω ; I = 1 A
V₁ = IR₁
= 1 * 2
= 2 volt
7) Resistance 2:
Total resistance = R
Total voltage = V = 8 volt
Total current = I = 1 A
\(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)
R = 8 Ω
R₁ + R₂ = 8 Ω
2 + R₂ = 8
R₂ = 8 - 2
R₂ = 6 Ω
8)Voltage around R₂:
\(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)
V₂ = 6 volt
9) Total R = 8 Ω
_________________________________________________
10) Total V = 12 volt
11) Total R = 8 + 8
= 16 Ω
12) Total current I,
\(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)
13) Voltage at each resistor:
V₁ = I*R₁
= 0.75 * 8
= 6 volt
V₂ = I*R₂
= 0.75 * 8
= 6 volt
_______________________________________________________
14) Total R = 40 + 20
= 60 Ω
15) To find V₁, first find total voltage.
I = 2 A ; R = 60 Ω
V = IR
= 2 * 60
= 120 V
V₁ + V₂ =V
V₁ + 80 = 120
V₁ = 120 - 80
V₁ = 40 volt
A stationary 0.325 kg steel ball begins rolling down a frictionless track from a height h as shown in the diagram. It completes a loop-the-loop of radius 1.20 m with a speed of 6.00 m/s at the top of the loop. What is the gravitational potential energy of the ball at the top of the loop?
The ball at the top of the loop has a gravitational potential energy of 7.55 J.
The kinetic energy of the ball at the top of the loop is equal to its gravitational potential energy before it begins to fall. The total energy of the ball is the sum of its kinetic and gravitational potential energies. We can calculate the gravitational potential energy of the ball at the top of the loop by using the equation given below; PE=mghwhere, m=mass, g=acceleration due to gravity, and h=height above the reference level. Substituting the values we get, PE=(0.325 kg)(9.8 m/s2)(2.4 m)=7.55 J. Therefore, the gravitational potential energy of the ball at the top of the loop is 7.55 J. A stationary steel ball of 0.325 kg rolling down the track from height h completes a loop of radius 1.20 m with a velocity of 6.00 m/s at the top of the loop. We need to calculate the gravitational potential energy of the ball at the top of the loop. The gravitational potential energy of an object is the energy it possesses due to its height above the reference level. The kinetic energy of the ball at the top of the loop is equal to its gravitational potential energy before it begins to fall. The total energy of the ball is the sum of its kinetic and gravitational potential energies. We can calculate the gravitational potential energy of the ball at the top of the loop by using the equation given below; PE=mghwhere, m=mass, g=acceleration due to gravity, and h=height above the reference level. Substituting the values we get, PE=(0.325 kg)(9.8 m/s²)(2.4 m)=7.55 J. Therefore, the gravitational potential energy of the ball at the top of the loop is 7.55 J.For more questions on gravitational potential energy
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could not find angular material core theme. most material components may not work as expected
When you see the error message "could not find angular material core theme. most material components may not work as expected," it means that the Angular Material theme is missing, and the application is having difficulty displaying Material components.
How to resolve the issue?Here are some steps to resolve this issue:
1. You should first ensure that Angular Material has been installed in your application. You may use the following command to install Angular Material:ng add ("at" symbol)angular/material
2. Then, import the necessary styles in the styles.scss file to include the Angular Material theme.
Once you've completed these steps, restart your server and see if the error has been resolved. The Material Design components should now display correctly.
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A force of 30 N stretches a spring 0.73 m from equilibrium. What is the value of the spring constant? A) 41 N/m B) 22 N/mC) 34 N/m D) 46 N/m
if the voltage drop is less than 0.5 volts, then measure the voltage drop on the starter ground circuit.
If the voltage drop is less than 0.5 volts, then measure the voltage drop on the starter ground circuit.When troubleshooting electrical systems, it is important to identify potential issues with voltage drops.
A voltage drop occurs when there is a loss of voltage across a circuit or component due to resistance. If the voltage drop is less than 0.5 volts, it suggests that the circuit is functioning properly and there is minimal resistance.
In the case of the starter ground circuit, it is crucial for the starter motor to have a reliable ground connection to function efficiently. By measuring the voltage drop on the starter ground circuit, we can determine if there are any excessive resistances that might be hindering the starter motor's performance.
If the voltage drop on the starter ground circuit is greater than 0.5 volts, it indicates a potential problem with the ground connection. This could be due to corroded terminals, loose connections, or damaged wiring. In such cases, it is necessary to inspect and repair the ground circuit to ensure proper functioning of the starter motor.
To summarize, if the voltage drop is less than 0.5 volts, measuring the voltage drop on the starter ground circuit is necessary to ensure the ground connection is optimal. This helps in identifying any potential issues with excessive resistance and allows for appropriate troubleshooting and repairs if needed.
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Why cant Analog Thermometers measure temperature below 0 °C?
Answer:
Alcohol thermometers are used rather than mercury thermometers in very cold regions because alcohol has a lower freezing point than mercury.
A piece of metal has a mass of 60 g and a volume of 3 cm^3, what is the density of the metal..?
====================================================
Work Shown:
density = mass/volume
d = m/v
d = (60 grams)/(3 cubic cm)
d = (60/3) g per cm^3
d = 20 g per cm^3
d = 20 g/cm^3
This means that each cubic centimeter of material has about 20 grams of mass.
A cubic centimeter is a cube that has all sides each 1 cm.
The density of the piece of metal is equal to 20 g/cm³ when the mass is 60 g and a volume of 3 cm³ of metal.
What is the density?The density of a substance can be measured as the mass per unit volume of that substance. The average density is equal to the total mass of the substance divided by its total volume.
The formula for the density of the substance is represented as follows:
The density of material = Mass/Volume
The density of a material is an intrinsic property as it does not depend on its size and the S.I. unit of the density is Kg/m³. If the size of the substance increases, the mass increases as well but the density of the material remains the same.
Given, the mass of the metal, M = 60 g
The volume of the metal, V = 3cm³
The density of metal = M/V = 60 /3 = 20 g/cm³
Therefore, the density of a piece of metal is 20g/cm³.
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According to molecular orbital theory the highest energy molecular orbital that is occupied with electron is referred to as ____
a. degenerate. b. antibonding. c. the LCAO. d. the LUMO. e. the HOMO.
According to molecular orbital theory, the highest energy molecular orbital that is occupied with an electron is referred to as the **HOMO** (Highest Occupied Molecular Orbital).
Molecular orbital theory describes the behavior of electrons in molecules by constructing molecular orbitals from the combination of atomic orbitals. These molecular orbitals are energy levels that can be occupied by electrons. The HOMO represents the highest energy level among the molecular orbitals that contains electrons. It is the orbital with the highest energy among the occupied orbitals in a molecule.
The other options mentioned are:
a. Degenerate: This term refers to orbitals that have the same energy level.
b. Antibonding: Antibonding orbitals are formed when atomic orbitals combine out of phase, resulting in regions of electron density with reduced electron density between the nuclei.
c. LCAO: LCAO stands for Linear Combination of Atomic Orbitals, which is a method used to construct molecular orbitals.
d. LUMO: LUMO stands for Lowest Unoccupied Molecular Orbital, which represents the lowest energy level among the unoccupied orbitals in a molecule.
Among these options, the term that specifically refers to the highest energy molecular orbital occupied with an electron is the HOMO.
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What happens if there is no transformation of energy in the world ?
Answer:
If there were no transformation of energy in the world, everything would come to a standstill.
Explanation:
Energy is required for all processes and interactions to occur, including movement and chemical reactions. Without energy, matter would not be able to move or change in any way. This would mean that living organisms would not be able to survive, as they rely on energy to carry out metabolic processes and maintain their body's functions.
The sun would not shine, the wind would not blow and the water would not flow, as they are all driven by energy transformations. The weather would not change, and there would be no seasons. The temperature would not vary and the weather patterns would not change.
Machines and technology would not work, as they also rely on energy to operate. There would be no electricity, transportation, or communication. The economy would come to a standstill as all the industry, trade, and commerce would stop.
In short, without energy transformation, the world would be a static, lifeless place, and life as we know it would not be possible.
A 0.50-μF and a 1.4-μF capacitor (C1 and C2, respectively) are connected in series to a 6.0-V battery.
c) Calculate the potential difference across each capacitor assuming the two capacitors are in parallel.
d) Calculate the charge on each capacitor assuming the two capacitors are in parallel.
The potential to difference across each capacitor assuming the two capacitors are in parallel are;
p.d(0.50-μF) = 4.42Vp.d(1.4-μF) = 1.58VThe charge on each capacitor assuming the two capacitors are in parallel are:
Q(0.5-μF) = 0.58CQ(1.4-μF) = 1.64CCapacitors in series and parallel connectionsC) The potential difference, p.d for the capacitors connected in series are inversely proportional to the capacitance and are as follows;
p.d(0.50-μF) = (1.4)/(1.9) × 6 = 4.42Vp.d(1.4-μF) = (0.5)/(1.9) × 6 = 1.58VD) When the connection is parallel, the charge on each capacitor is shared as follows;
First, Total charge, Q = C(total) × V.
where, C(total) = (0.5×1.4)/(1.9) = 0.37-μF.
Q = 0.37 × 6Q = 2.22C
Hence, the charge is shared as follows;
Q(0.5-μF) = (0.5/1.9) × 2.22 = 0.58CQ(1.4-μF) = (1.4/1.9) × 2.22 = 1.64CRead more on capacitors in series and parallel;
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Impulsive vs. Long-Duration Flare The X-ray flux from an X5 impulsive flare can be approximated as 5x10-4e-2 W/m², t (hours) > 0 The X-ray flux from an X1 long-duration flare can be approximated as 1x10-4 e-t/3 W/m², t (hours) > 0 Calculate the total X-ray flux in J/m² for each flare. If the total fluxes are similar, which flare is more likely to signal the beginning of a significant space weather event? Why?
The X₅ impulsive flare has a total X-ray flux that is four times greater than the X1 long-duration flare.
How to calculate the valueThe total X-ray flux for the X5 impulsive flare is:
5x10-4e⁻² W/m² * 3600 s/hour * 1 hour
= 5.4 J/m²
The total X-ray flux for the X1 long-duration flare is:
1x10⁻⁴ e-t/3 W/m² * 3600 s/hour * 1 hour
= 1.2 J/m²
As you can see, the X₅ impulsive flare has a total X-ray flux that is four times greater than the X1 long-duration flare. Therefore, the X impulsive flare is more likely to signal the beginning of a significant space weather event.
The reason for this is that the X₅ impulsive flare is a much more powerful event. It releases a much larger amount of energy in a much shorter period of time.
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